triangle has area 16 m ^2
. List all the possible positive integers that could
represent the lengths of its base and height.

By adding the weight of the triangle, the weight of the circle heavier than that of the square.

The linear equation that results from examining the weights will contain the following parameters.

Let t stand for the triangle.

Let c stand for the circle.

Let's use the shape square.

left side of the equation = 6s + 3t

right side of the equation = 3s + 3c

equating both sides

6s + 3t = 3s + 3c

6s - 3s + 3t = 3s + 3c

3s + 3t = 3c

3(s + t) = 3c

dividing all through by 3

s + t = c

10 + t = c

Because of the resulting equation, we can conclude that the the circle is weightier than the square by the weight of the triangle

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Answer:

A 1 in 4 chance or a probability of 0.25

Step-by-step explanation:

There is only 3 months that start with J and 12 months in a year so simplify 3/12 you get 1/4 or 0.25

Answer:

Step-by-step explanation:

i have no idea

Answer:

x = 55

Step-by-step explanation:

Since the sides of the shape are parallel, AngleC and AngleD will add up to 180° (see "parallel lines cut by a transversal" or maybe you have learned a big pile of parallelogram theorems)

Use this relationship to set up an equation.

2x + 20 + 50 = 180

combine like terms

2x + 70 = 180

subtract 70

2x = 110

divide by 2

x = 110/2

x = 55

x is 55

Answer:

The value of x is 55°

Step-by-step explanation:

Since we know that opposite angles of a parallelogram are equal

The sum of any two adjacent angles is supplementary. This means, ∠A + ∠B = 180°, ∠B + ∠C = 180°, ∠C + ∠D = 180°, and ∠D + ∠A = 180.

So,

∠C + ∠D = 180°

(2x + 20)° + 50° = 180°

2x + 70° = 180°

2x + 70° - 70° = 180° - 70°

2x = 110°

2x/2 = 110°

x = 55°

Thus, The value of x is 55°

The sale price of the item is given by the equation A = $ 26.40

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the sale price of the item be represented as A

Now , the equation will be

The original price of the item = $ 33

An item on sale costs 80% of the original price

So , the sale price of the item A = 80 % x original price of the item

Substituting the values in the equation , we get

The sale price of the item A = ( 80 / 100 ) x 33

The sale price of the item A = 0.80 x 33

The sale price of the item A = $ 26.40

Therefore , the value of A is $ 26.40

Hence , the sale price is $ 26.40

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On solving the provided question we cans ay that -  order when writing it on the number line: = -1.25, -0.75, 0.25, 1.5, 2

A number line is a visual representation of real numbers used in introductory mathematics. It is an image of a magnitude line. On the number line, each point represents a real number, and each real number is taken to represent a point. Increments on a number line are separated by equal distances. You can only respond to the numbers on a line in the manner indicated by those numbers. How the number is utilized is determined by the question that goes with it. B: Make a point.

The numbers on the number line must be

[tex]6/3 = 2\\-3/4 = -0.75\\1.5 = 1.5\\0.25 = 0.25\\-5.4 = -1.25\\[/tex]

In ascending order, t

[tex]-1.25 = -5/4\\-0.75 = -3/4\\0.25\\1.5\\2 = 6/3[/tex]

order when writing it on the number line:

-1.25, -0.75, 0.25, 1.5, 2

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Answer:

(0.5, 3)

Step-by-step explanation:

Just entered it into a desmos graphing calculator online

Answer:2009#73

Step-by-step explanation:

3939+373

Ie,ek

The graph of the system of linear equations is attached with the answer.

The general equation of a straight line is -

y = mx + c

{m} - slope.

{c} - intercept along the y - axis.

Given is the system of linear equations as given -

- 2x + y = 10

x + 2y = 5

The given system of linear equations is -

- 2x + y = 10

x + 2y = 5

Refer to the graph of the system of linear functions attached. The point (-3, 4) is the solution set of this system of equation.

Therefore, the graph of the system of linear equations is attached with the answer.

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Answer:

11

Step-by-step explanation:

Based on the given conditions, formulate: 25 - 14

Calculate the sum or difference: 11

get the result: 11

Answer:

Elliot = 16 years old

Miya = 10 years old

Cara = 25 years old

Step-by-step explanation:

Define the variables:

The average age of Elliot, Miya and Cara is 4 years more than the average age of Elliot and Miya:

[tex]\implies \dfrac{x+y+z}{3}=\dfrac{x+y}{2}+4[/tex]

[tex]\implies \dfrac{x+y+z}{3}=\dfrac{x+y+8}{2}[/tex]

[tex]\implies 2(x+y+z)=3(x+y+8)[/tex]

[tex]\implies 2x+2y+2z=3x+3y+24[/tex]

[tex]\implies 2z=x+y+24[/tex]

[tex]\implies x=2z-y-24[/tex]

Cara is 9 years older than Elliot:

[tex]\implies z = x + 9[/tex]

Four years ago, Elliot was double the age of Miya:

[tex]\implies (x - 4) = 2(y - 4)[/tex]

[tex]\implies x - 4 = 2y-8[/tex]

[tex]\implies x +4 = 2y[/tex]

[tex]\implies y=\dfrac{1}{2}x +2[/tex]

Substitute the equations for z and y into the equation for x and solve for x:

[tex]\implies x=2z-y-24[/tex]

[tex]\implies x=2(x+9)-\left(\dfrac{1}{2}x +2\right)-24[/tex]

[tex]\implies x=\dfrac{3}{2}x-8[/tex]

[tex]\implies \dfrac{1}{2}x=8[/tex]

[tex]\implies x=16[/tex]

Substitute the found value of x into the equation for z and solve for z:

[tex]\implies z = 16 + 9[/tex]

[tex]\implies z = 25[/tex]

Substitute the found value of x into the equation for y and solve for y:

[tex]\implies y=\dfrac{1}{2}(16) +2[/tex]

[tex]\implies y=8+2[/tex]

[tex]\implies y=10[/tex]

Therefore, the ages of Elliot, Miya and Cara are:

In the right triangle in the figure the value of x is solved to be 4.5

Using SOH CAH TOA for the right triangle

Sin = opposite / hypotenuse - SOH

Cos = adjacent / hypotenuse - CAH

Tan = opposite / adjacent - TOA

The figures show that

hypotenuse = 6

adjacent = x

given angle = 41 degrees

The value of x will be calculated using cos, CAH let the angle be y

cos y = adjacent / hypotenuse

cos 41 = x / 6

x = 6 * cos 41

x = 4.528

x = 4.5

Hence the value of x is 4.5

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Answer:

157[tex]ft^{3}[/tex]

Step-by-step explanation:

Volume =  the area of the base times the height.

Area of a circle = [tex]\pi[/tex][tex]r^{2}[/tex]

a = [tex]\pi[/tex][tex](5^{2})[/tex]   I am going to use 3.14 for [tex]\pi[/tex]

a = 3.14(25)

a = 15.7

Volume = 15.7 x 10 = 157

Answer:

785 ft२

Step-by-step explanation:

volume =3.13*5२*10

=3.14*25*10

=785 ft२

1] Answer: y = -[tex]\frac{1}{2}[/tex]x + 3

Step-by-step explanation:

➜ This line is going down from the top left to the bottom right, so it will have a negative slope.

➜ Using rise over run, we get a slope of -2/4. This simplifies to -1/2.

➜ The line intercepts the y-axis at 3.

2] Answer: y = 3x

Step-by-step explanation:

➜ This line is going down from the bottom left to the top right, so it will have a positive slope.

➜ Using rise over run, we get a slope of 3/1. This simplifies to 3.

➜ The line intercepts the y-axis at 0.

3] Answer: y = x - 4

Step-by-step explanation:

➜ This line is going down from the top left to the bottom right, so it will have a negative slope.

➜ Using rise over run, we get a slope of 2/2. This simplifies to 1.

➜ The line intercepts the y-axis at -4.

Answer:

each box contain 8 x 9 = 72

The linear equation in this case is . The [tex]$3 x^2+4 x+4=0$[/tex] answer is [tex]x=-\frac{2}{3}+i \frac{2 \sqrt{2}}{3}, x=-\frac{2}{3}-i \frac{2 \sqrt{2}}{3}[/tex] and [tex]$3 y^2+2 x+4=0: \quad$[/tex]: quadratic [tex](h, k)=(-2,0), p=-\frac {1} {6}[/tex] , is the solution.

[tex]$3 x^2+4 x+4=0 \quad: \quad x=-\frac{2}{3}+i \frac{2 \sqrt{2}}{3}, x=-\frac{2}{3}-i \frac{2 \sqrt{2}}{3}$[/tex]

[tex]$3 x^2+4 x+4=0$[/tex]

Apply the quadratic formula to the problem. [tex]$x_{1,2}=\frac{-4 \pm \sqrt{4^2-4 \cdot 3 \cdot 4}}{2 \cdot 3}$[/tex]

Simplify [tex]$\sqrt{4^2-4 \cdot 3 \cdot 4}: \quad 4 \sqrt{2} i$\\[/tex]

[tex]$x_{1,2}=\frac{-4 \pm 4 \sqrt{2} i}{2 \cdot 3}$[/tex]

Distinguish the answers

[tex]x_1=\frac{-4+4 \sqrt{2} i}{2 \cdot 3}, x_2=\frac{-4-4 \sqrt{2} i}{2 \cdot 3}\\x=\frac{-4+4 \sqrt{2} i}{2 \cdot 3}: \quad-\frac{2}{3}+i \frac{2 \sqrt{2}}{3}\\x=\frac{-4-4 \sqrt{2} i}{2 \cdot 3}: \quad-\frac{2}{3}-i \frac{2 \sqrt{2}}{3}[/tex]

The following are the quadratic equation's solutions:

[tex]x=-\frac{2}{3}+i \frac{2 \sqrt{2}}{3}, x=-\frac{2}{3}-i \frac{2 \sqrt{2}}{3}[/tex]

2) [tex]$3 y^2+2 x+4=0: \quad$[/tex] A parabola with a focal length of and a vertex at (h,k)=(-2, 0) [tex]$|p|=\frac{1}{6}$[/tex]

[tex]$3 y^2+2 x+4=0$[/tex]

[tex]$4 p(x-h)=(y-k)^2$[/tex] is the common formula for a right-to-left parabola with a vertex at (h, k) and a focal length of |p|.

Rewrite [tex]$3 y^2+2 x+4=0$[/tex]  using the proper form: [tex]$4\left(-\frac{1}{6}\right)(x-(-2))=(y-0)^2$[/tex]

The following are characteristics of parabolas:

[tex](h, k)=(-2,0), p=-\frac {1} {6}[/tex]

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1a) An equation that gives the width `y` of the book, if it has `x`-hundred pages printed on bond paper is; y = ¹/₂ + ¹/₄x

1b) Ledger paper has a thickness of 2/5 in. per `100` pages, the equation is; y = ¹/₂ + ²/₅x

2) The equation will be; y = ²/₃ +¹/₄x

1) We are told that the front cover and the back cover have a thickness of 1/4 inches and they also have a thickness of 1/4 inch. Thus;

The addition of both gives to the book thickness of;

1/4 + 1/4 = 1/2 inch, despite how many pages the book  has.

We are told that for every hundred pages, a thickness of 1/4 inch is added to the book, then the equation is:

y = ¹/₂ + ¹/₄x

where;

y is the width of the book in inches.

x is every hundred pages printed on bond paper.

1b) If ledger paper has a thickness of 2/5 in. per 100 pages, then the equation is now;

y = ¹/₂ + ²/₅x

2) If both front and back covers now, have a thickness of 1/3 inches instead of 1/4 inches each, then the equation will be;

y = 2(1/3) +¹/₄x

y = ²/₃ +¹/₄x

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The nearest integer that is a solution, gotten through graphing of the quadratic function x² + 2x - 2 = 5, is x = -4

Quadratic equations when plotted on a graph follows a parabolic path.

To plot the functions there will be table of values that is used in making the graph. The table of values is solved as follows

x² + 2x - 2 = 5 rearranging the equation will result to x² + 2x - 7 = 0

For x = -20,  y = (-20)² + 2 * -20 - 7 = 353

For x = 0,  y = (0)² + 2 * 0 - 7 = -7

For x = 20,  y = (20)² + 2 * 20 - 7 = 433

x      y

-20  353

0      -7

20    433

The graph is plotted and attached. From the graph the solution is

x = -3.828, to the nearest integer = -4

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A) The linear equation is:

y = (3/4)*x + 3

B) The sets with only positive elements are:

A general linear equation can be written as:

y = a*x + b

Where a is the slope and b is the y-intercept.

Here, we do know that the y-intercept of the linear equation is (0, 3), then we know that b = 3.

Then the line is something like:

y = a*x + 3

We also know that the line passes through (-4, 0), then we can replace these values in the equation above to get:

0 = a*-4 + 3

4a = 3

a = 3/4

Then the linear equation is:

y = (3/4)*x + 3

The sets where all the numbers are positive are:

{x| x ∈ N}

Where N is the set of the natural numbers, these are all the integers equal to or larger than 1, so all are positives.

{y| 0 < y < 1}

There we can see that y must be larger than zero, so all the elements are positive.

{y| 3 ≤ y ≤22}

Here the elements are between 3 and 22, so all of these are positve.

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7½

7×2+1/2

14+1/2

15/2

12½

12×2+1/2

24+1/2

25/2

Answer:

75%

Step-by-step explanation:

To find the percent of change that Target marks the shoes up for, you need to calculate the difference between the cost of the shoes to Target and the price at which they sell it to the public, and then divide that difference by the cost of the shoes to Target. Finally, you need to multiply the result by 100 to express the answer as a percentage.

Using this formula, the percent of change that Target marks the shoes up for is:

(35 - 20) / 20 * 100 = 15 / 20 * 100 = 0.75 * 100 = 75%

This means that Target marks the shoes up by 75% of their cost.

The solution to the equation log₇343 = 3 is 7³ = 343

An equation is used to show the relationship between numbers and variables.

The logarithm can be defined as the exponent that raises a base to get a particular number. The law of logarithm states:

logₓm = n is the same as xⁿ = m

Given the equation:

log₇343 = 3

Applying the law of logarithm gives:

7³ = 343

The solution to the equation is 7³ = 343

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4.8

Divide 250 by 2 which is 125 then do 600 divided by 125. Then your answer should be 4.8.

From the exponential function, the average rate of change from year 1 to year 4 is 62.43, the average rate of change from year 5 to year 8 is 67.57 and the rate of change per year is 65

An exponential function is a type of function that involves a variable in an exponent. It is of the form f(x) = a⋅b^x where a and b are constants and b > 0, b ≠ 1. The input to the function, x, is the exponent that the base, b, is raised to. The output, f(x), is the result of raising the base to the exponent.

In this problem, we have to calculate the rate of increase per year.

Data;

rate = 2%

P = 3000

The exponential growth can be calculated by;

A = P(1 + r)ⁿ

In year 1

A = 3000(1 + 0.02)¹

A = 3060

In year 4

A = 3000(1 + 0.02)⁴

A = 3247.3

a)

The average rate of change from year 1 to year 4 will be

A = [3000(1 + 0.02)⁴ - 3000(1 + 0.02)¹] / 4 - 1

A = 62.43

The average rate of change from year 1 to year 4 is 62.43

b)

The average rate of change from year 5 to year 8 is calculated as

A = [3000(1 + 0.02)⁸ - 3000(1 + 0.02)⁵] / 8 - 5

A = 67.57

C)

The rate of change increase can be calculated as;

A = [3000(1 + 0.02)⁸ - 3000(1 + 0.02)¹] / 8 - 1

A =65

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Answer:

1 unit to the left, 3 units down

Step-by-step explanation:

Take any point: I will take D. In order to get to D', you need to travel 1 unit along the x-axis towards the left, then 3 until along the y-axis downwards. The same applies for any other point.

The value inside the square root should be greater than or equal to zero. Then the domain of the function will be [7, ∞).

A function is an assertion, concept, or principle that establishes an association between two variables. Functions may be found throughout mathematics and are essential for the development of significant links.

The domain means all the possible values of x and the range means all the possible values of y.

The function is given below.

f(x) = √x

The function after the transformation, then we have

f(x) = √(x - 7) + 2

The value inside the square root should be greater than or equal to zero. Then the domain of the function will be given as,

x - 7 ≥ 0

x ≥ 7

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The unit rate is 18 commercials per hour.

A division is a process of splitting a specific amount into equal parts.

On Saturday morning, Wendy watched one and a half hours of her favorite shows on television.

During the shows there were 27 commercials.

We need to find the unit rate of commercials per hour.

To find this we have to divide 27 by number of hours

27/[tex]1\frac{1}{2}[/tex]

Convert [tex]1\frac{1}{2}[/tex] to improper fraction

27/(3/2)

When whole number is divided by fraction, the denominator is multiplied with whole number

27×2/3

54/3

18

Hence, the unit rate is 18 commercials per hour.

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Answer:18 commercials per hour

Step-by-step explanation:

Answer:

(-∞, 1] or {x|x<=1}

Step-by-step explanation: