To make some draperies, an interior decorator needs 12 1/4 yards of material for the den and 8 1/2 yards for the living room. If the material comes only in 21-yard bolts, how much will be left over after completing both sets of draperies?

Answers

Answer 1

Answer:

1/4 of a yard of material

Step-by-step explanation:

First, we must convert both 12 1/4 yards and 8 1/2 yards to quarters. Since 1/2 of a yard is equal to 2/4 of a yard, 8 1/2 yards will be equal to 8 2/4 yards. 8 yards + 12 yards = 20 yards, and 2/4 of a yard + 1/4 of a yard = 3/4 of a yard, so you get 20 3/4 of a yard to finish the draperies. To find the leftover material, do 21 yards - 20 3/4 yards = 1/4 of a yard of material. Hope this helps!


Related Questions

Find the area of the triangle whose vertices are (2, 3); (-1, 0); (2, -4)...
[Also show the steps of the solution]
Please answer correctly, it's really urgent!​

Answers

Answer:

Area = 14.5

Step-by-step explanation:

Let's label the given coordinates A, B, C;

Thus;

A = (2, 3)

B = (-1, 0)

C = (2, -4)

From the coordinate geometry formula, the formula for area of a triangle with 3 vertices is;

Area = [Ax(By - Cy) + Bx(Cy - Ay) + Cx(Ay - By)]/2

Area = [2(0 - (-4)) + (-1)(-4 - 3) + 2(3 - (-4))]/2

Area = 29/2

Area = 14.5

pls help me in these questions ​

Answers

Answer:

1=85

2=10

3=108

Step-by-step explanation:

Number 1: Calculate each angle...and you know a straight line is 180°. N the interior sum of a quadrilateral is always 360°.

Number2: Use corresponding, alternate and interior angles method. It will help

Number 3: It's just about solving the interior sum of the pentagon

Answer:

2. 10 degrees

3. 108 degrees

Step-by-step explanation:

sorry I reposted it because the previous answer was deleted and plz mark me as a brainliest.

Question 18 (5 points)
Determine the sum of the measures of the interior angles of a dodecagon (12-sided
polygon).
540°
1,800°
360°
2,160°

Answers

Answer:

its 540 bro

Step-by-step explanation:

Determine if the ordered pair (-1,-5) is a solution to the inequality y<_ -3/4x-1.

A.) No,because (-1,-5) is above the line
B.) Yes, because (-1,-5) is below the line
C.) No, because (-1,-5) is on the line
D.) Yes, because (-1,-5) is on the line

Answers

Answer:

the answer is B, comment if you need explanation

Step-by-step explanation:

The answer is B come in if you need an explanation

Can some help with this problem

Answers

Answer:

x+115=180 x=65

90+65+y=180 y=25

Step-by-step explanation:

Which of the following square root of the following number below? Check all that apply. 361

Answers

Answer:

strangely worded question....

[tex]361^{1/2} = \sqrt{361}[/tex]

Step-by-step explanation:

4 Answers:  B, C, D, and F

=========================================================

Explanation:

Notice how (19)^2 = 19*19 = 361

This shows that 19 is a square root of 361. We can say [tex]\sqrt{361} = \sqrt{19^2} = 19[/tex]

Similarly, (-19)^2 = (-19)*(-19) = 361. The two negatives cancel each other out. So that's why there are two solutions to [tex]x^2 = 361[/tex] which are x = 19 and x = -19.

So far that accounts for answer choices B and D.

-------------------------------------------

The other two answers are [tex]-361^{1/2}[/tex] and [tex]361^{1/2}[/tex] (choices C and F) because anything to the 1/2 power represents a square root.

[tex]x^{1/2} = \sqrt{x}[/tex]

anything to the 1/3 power is a cube root

[tex]x^{1/3} = \sqrt[3]{x}[/tex]

anything to the 1/4 power is a fourth root

[tex]x^{1/4} = \sqrt[4]{x}[/tex]

and so on.

-------------------------------------------

Side note: For choice C, the exponent is done first before we apply the negative. So technically we could say [tex]-1*(361)^{1/2}[/tex] for choice C to mean the same exact thing. If your teacher said [tex](-361)^{1/2}[/tex] then this would not be an answer because this results in a non-real number.

Solve The inequality

Answers

Answer:

D is the correct answer.

Please thank me

Step-by-step explanation:

You invest $4.000 in a savings account. The account pays 3% annual interest. How much money will be in the savings account after 9 years?

A) $4,938.29
B) $5,219.20
C) $5,124.33
D) $6,003.45​

Answers

Answer:

4000*0.03*9=1080

4000+1080=5080

umm but like thats not one of the answers sorry

Hope This Helps!!!

Step-by-step explanation:

4000*3% = 120

120*9= 1080

1080+4000=5080

If and are the zeroes of the polynomial 2x^2+3x+5 then the value of 1/alpha + 1/beta
Pls answer fast..I’ll mark the brainlest

Answers

Answer:

-4/15

Step-by-step explanation:

Mathematically, we know that;

alpha= -b/a and beta = c/a

a refers to the coefficient of the x^2 which is 2

b is the coefficient of x which is 3

c is the last number which is 5

alpha = -b/a = -3/2

beta = c/a = 5/2

1/alpha = -2/3

1/beta = 2/5

so we have the sum as;

-2/3 + 2/5

= -5(2) + 3(2)/15 = (-10 + 6)/15 = -4/15

Really struggling with these problems please help!
Solve.
[tex] \sqrt{10y + 24} - 3 = y + 1[/tex]

Answers

Answer:

[tex]y_1 = -2[/tex] and [tex]y_2 = 4[/tex]

Step-by-step explanation:

[tex] \sqrt{10y + 24} - 3 = y + 1[/tex]

Move the constant to the right-hand side and change their sign.

[tex] \sqrt{10y + 24} = y + 1 + 3 [/tex]

combine like terms

[tex] \sqrt{10y + 24} - 3 = y + 4[/tex]

Square both side to remove square brackets.

10y + 24 - 3 = y²+ 8y + 16

Move the expression to the left-hand side and change its sign.

10y + 24 - y² - 8y - 16 = 0

Combine like terms

10y - 8y + 24 - 16 - y² = 0

2y + 8 - y² = 0

Use commutative property to reorder the terms.

-y² + 2y + 8 = 0

Change the sign of expression.

y² -2y -8 = 0

split -2y

y² + 2y - 4y - 8 = 0

Factor out y from the first pair and -4 from the second equation.

y ( y + 2 ) - 4 ( y + 2 ) = 0

Factor out y+2 from the expression.

( y + 2 ) ( y - 4)

When the products and factors equals 0, at least one factor is 0.

y + 2 = 0

y - 4 = 0

Solve for y

y = -2

y = 4

When we plug the both solution as y we found that both is true solution of this equation.

This equation has two solutions which are -2 and 4.

Answer:

Solution given:

[tex] \sqrt{10y + 24} - 3 = y + 1[/tex]

keep the constant term in one side

[tex] \sqrt{10y + 24} =y+1+3[/tex]

solve possible one

[tex]\sqrt{10y+24}=y+4[/tex]

now

squaring both side

[tex](\sqrt{10y+24})²=(y+4)²[/tex]

10y+24=y²+8y+16

taking all term on one side

10y+24-y²-8y-16=0

solve like terms

8+2y-y²=0

doing middle term factorisation

8+4y-2y-y²=0

4(2+y)-y(2+y)=0

(2+y)(4-y)=0

either

y=-2

or

y=4

y=-2,4

a. 1.3
b. 9.6
c. 13
d. 1

Answers

Answer:      I believe the answer would be 1.3

           HOWEVER, if you do have to round to the nearest tenth then the answer would be 1

Step-by-step explanation:    

2x+7 = 12x - 6

(subtract 2x from both sides)

7 = 10x - 6

(add 6 to both sides)

13 = 10x

(divide 13/10)

1.3 = x

The a oranial price of a skate broad was reduced by 15 dollars .the new price is 49 dollars if p=the stakebroads oranail price in dollars what mathematical sentence expresses the information
a.49-p=15
b.15-p=49
c.15+p=49
d.p-15=49

Answers

Answer:

d. p - 15 = 49

Step-by-step explanation:

p = original price

The price was reduced by 15 dollars.

The new price is p - 15.

The new price is 49.

p - 15 = 49

Answer: d. p - 15 = 49

I need help plz help

Answers

answer is C. 252 ft^2

split the figure into two pieces and first figure out the rectangle (shown in turquoise).

If you multiply the width and length (18*6) you should get 108.

Then figure out the trapezoid (in magenta). the formula is (a+b)/2*h where a and b are the bases and h is the height. the bases are given, 6 and 18. to find the height, subtract the entire figure's height by 6, which is 18-6 and gives us 12. so the formula converted to this problem is (6+18)/2*12. simplify parenthesis and get 24/2*12. 24/2=12, so multiply 12*12. The area of the trapezoid is 144. Add the areas of both figures together and get 252.

Which point is a solution to the inequality shown in this graph

Answers

Answer: C. (0, -3)

Step-by-step explanation:

You don't even need to find the function, just mentally graph every point in the options on the graph.

If it land in the white area, it's not a solution.If it land in the blue area or on the line, it's a solution.

The line is not dotted, showing that the inequality is probably either ≥ or ≤, so points on the line do count as solution.

All current-carrying wires produce electromagnetic (EM) radiation, including the electrical wiring running into, through, and out of our homes. High frequency EM is thought to be a cause of cancer; the lower frequencies associated with household current are generally assumed to be harmless. The following table summarizes the probability distribution for cancer sufferers and their wiring configuration in the Denver area.

Leukemia Lymphoma Other Cancers
High Frequency wiring 0.242 0.047 0.079
Low frequency wiring 0.391 0.098 ???
(a) What is the missing probability (labelled ???) in the above table?

(b) What is the probability of having high frequency wiring among cancer suffers in the Denver area?

(c) Is the event "Having Leukemia" independent of the event "Having high frequency frequency wiring"? Explain.

Answers

Answer:

[tex]x = 0.143[/tex]

[tex]P(High\ |\ Cancer) = 0.215[/tex]

Not independent

Step-by-step explanation:

Given

See attachment for proper table

Solving (a): The missing probability

First, we add up the given probabilities

[tex]Sum = 0.242+0.047+0.079+0.391+0.098[/tex]

[tex]Sum = 0.857[/tex]

The total probability must add up to 1.

If the missing probability is x, then:

[tex]x + 0.857 = 1[/tex]

Collect like terms

[tex]x = -0.857 + 1[/tex]

[tex]x = 0.143[/tex]

Solving (b): P(High | Cancer)

This is calculated as:

[tex]P(High\ |\ Cancer) = \frac{n(High\ n\ Cancer)}{n(Cancer)}[/tex]

So, we have:

[tex]P(High\ |\ Cancer) = \frac{0.079}{0.242+0.047+0.079}[/tex]

[tex]P(High\ |\ Cancer) = \frac{0.079}{0.368}[/tex]

[tex]P(High\ |\ Cancer) = 0.215[/tex]

Solving (c): P(Leukemia) independent of P(High Wiring)

From the attached table

[tex]P(Leukemia\ n\ High\ Wiring) = 0.242[/tex]

[tex]P(Leukemia) = 0.242 + 0.391 =0.633[/tex]

[tex]P(High\ Wiring) = 0.242+0.047+0.079=0.368[/tex]

If both events are independent, then:

[tex]P(Leukemia\ n\ High\ Wiring) = P(Leukemia) * P(High\ Wiring)[/tex]

[tex]0.242 = 0.633 * 0.368[/tex]

[tex]0.242 \ne 0.232[/tex]

Since the above is an inequality, then the events are not independent

find f(-2)for f(x)=5*3^x

Answers

f ( - 2 ) = 5 × 3^( - 2 )

f ( - 2 ) = 5 × 1/9

f ( - 2 ) = 5/9

© Find the quotient of 3/8 and ,4/9
Give your answer as a fraction in its simplest form.

Answers

[tex] \frac{3}{8} \div \frac{4}{9} \\ = \frac{3}{8} \times \frac{9}{4} \\ = \frac{27}{32} [/tex]

Hope it helps!!!

Thanks!!!

Plis help me it’s for today

Answers

Answer:

Following are the solution to the given points:

Step-by-step explanation:

For question 1:

[tex]\to 3^{-4}= \frac{1}{3^4}=\frac{1}{81}=0.0123456789[/tex]

For question 2:

[tex]\to (-2)^{3}\cdot(-2)^{4}\cdot(-2)^{-1}=-8\cdot-16\cdot -\frac{1}{2}= 128\cdot -\frac{1}{2}=-64[/tex]

For question 3:

[tex]\to 7^{-4} \div 7^{-2}= \frac{1}{7^{4}} \div \frac{1}{7^{2}}=\frac{1}{7^{4}} \times \frac{7^{2}}{1}=\frac{1}{7^{2}} =\frac{1}{49} =0.0204081633[/tex]

For question 4:

[tex]\to [(-3)^{2}]^3= (-3)^{2\cdot 3}= (-3)^{6}=729[/tex]

For question 5:

[tex]\to [5 \cdot (-3)]^{2}= 25 \cdot 9=225[/tex]

For question 6:

[tex]\to [(10 \div 5)]^{3}= [(\frac{10}{5})]^{3}=[2]^{3}=8[/tex]

For question 7:

[tex]\to 10^6 \cdot 10^{-4} \cdot 10^2= 10^6 \cdot \frac{1}{10^{4}} \cdot 10^2= 10^2 \cdot 10^2=10^4=10,000[/tex]

For question 8:

[tex]\to (-4)^{-5}=\frac{1}{(-4)^{5}}=- \frac{1}{1,024}=-0.0009765625[/tex]

For question 9:

[tex]\to \frac{2^3}{2^4}= \frac{8}{16}=\frac{1}{2}=0.5[/tex]

For question 10:

[tex]\to (-6)^3 \cdot (-6)^5 \cdot (-6)^{-5}= (-6)^3 \cdot (-6)^5 \cdot \frac{1}{(-6)^{5}}= (-6)^3 =-216[/tex]

I forgot to label the triangle below! I just know that the cos A = 0.48. Based on this information, which angle should be marked A?

Answers

Answer:

angle 1

Step-by-step explanation:

Using the trigonometric mnemonic SOH CAH TOA, we know that cos or cosine is the ratio between the adjacent side and hypotenuse side.

This means that if cos A = 0.48, A is the measure of the angle which it's relative adjacent side divided by the hypotenuse of the triangle will be around 0.48.

Let's try angle 2, cos (angle 2) = adjacent / hypotenuse = 7.8 / 8.9 = 0.876404494382 ≈ 0.87 ≠ 0.48. Since the proportions are not equal, this angle cannot be the one marked as A.

Since angle 3 is a right angle, the adjacent could be either side so it cannot be correct. Thus angle 1 is correct.

If f(x) = 3x + 10 and g(x) = 2x - 4, find (f+g)(x).
O A. (f+g)(x) = -34 - 2x - 14
B. (f+ g)(x) = 3x - 2x + 14
O C. (f+ g)(x) = 5x + 6
D. (f+ g)(x) = 3x + 2x + 6

Help! I’m getting really confused which one it is

Answers

Answer:

O D

Step-by-step explanation:

f+g(x)

3x+10+2x-4

3x +2x+6

In ΔCDE, the measure of ∠E=90°, ED = 28, CE = 45, and DC = 53. What ratio represents the tangent of ∠C?

Answers

Answer:

3/5

Step-by-step explanation:

prependicular / hypotenuse

sin C=ED/CD

=3/5

8 Find the value of x a (22²)x is exponent of (22²) = 64​

Answers

Given:

Consider the given equation is:

[tex](2\cdot 2^2)^x=64[/tex]

To find:

The value of x.

Solution:

We have,

[tex](2\cdot 2^2)^x=64[/tex]

It can be written as:

[tex](2\cdot 4)^x=8\times 8[/tex]

[tex]8^x=8^2[/tex]

On comparing the exponents of both sides, we get

[tex]x=2[/tex]

Therefore, the value of x is 2.


Two
1 1 sides of trapezium are bound 60 cm & 77cm
outer sides are 25cm. & 26cm Find the
area of trapezium

Answers

Answer:

area ABEC

[tex]s =\frac{25 + 26 + 17}{2} = 34[/tex]

area ∆ BEC

[tex] = \sqrt{34 \times 9 \times 8 \times 17} [/tex]

[tex]17 \times 3 \times 2 \times 2 = 204cm ^{2} [/tex]

area ∆ BEC

[tex] = \frac{1}{2} \times 17 \times h = 204[/tex]

[tex]h = \: \frac{204 \times 2}{17} = 24[/tex]

[tex]area \: trap \: \: abcd \\ = \frac{1}{2}(60 + 77) \times 24 \\ = 137 \times 12 = 1644cm ^{2} [/tex]

Step-by-step explanation:

❣️Jess bragoli❣️

#keep learning!!

Which graph represents the solution of x2 + 9y2 ≤ 81 and y2 + 2 < x? On a coordinate plane, an ellipse has center (0, 0) and goes through (3, 0), (0, negative 9), (negative 3, 0), and (0, 9). A parabola opens to the right and goes through (6, 2), has vertex (2, 0), and goes through (6, negative 2). Everything inside of the ellipse and outside of the parabola is shaded. On a coordinate plane, an ellipse has center (0, 0) and goes through (3, 0), (0, negative 9), (negative 3, 0), and (0, 9). A parabola opens to the right and goes through (6, 2), has vertex (2, 0), and goes through (6, negative 2). Everything inside of the ellipse and inside of the parabola is shaded. On a coordinate plane, an ellipse has center (0, 0) and goes through (9, 0), (0, negative 3), (negative 9, 0) and (0, 3). A parabola opens to the right and goes through (6, 2), has vertex (2, 0), and goes through (6, negative 2). Everything inside of the ellipse and inside of the parabola is shaded. On a coordinate plane, an ellipse has center (0, 0) and goes through (9, 0), (0, negative 3), (negative 9, 0) and (0, 3). A parabola opens to the right and goes through (6, 2), has vertex (2, 0), and goes through (6, negative 2). Everything inside of the ellipse and outside of the parabola is shaded.

Answers

9514 1404 393

Answer:

  C

Step-by-step explanation:

The ellipse y-intercepts are ±3, the x-intercepts are ±9, eliminating choices A and B. The parabola is shaded inside, eliminating choice D.

The correct choice is the third one.

please tel me answer of under root 3+4i
without calculatot with steps

Answers

Hello,

[tex]Let's\ say \\\\z=\sqrt{3+4*i} =a+b*i\\\\z^2=3+4*i=(a+b*i)^2=a^2-b^2+2i*a*b\\\\\\if \ a\neq 0\\\left\{\begin{array}{ccc}a^2+b^2&=&3\\2ab=4\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}b=\dfrac{2}{a}\\a^2-(\dfrac{2}{a})^2=2\\\end{array}\right.\\\\\\a^4-4=3*a^2\\a^4-3a^2-4=0\\\\\Delta=(-3)^2-4*1*(-4)=25=5^2\\\\a^2=4\ or \ a^2=-1 (impossible)\\\\So:\\(a=2\ and\ b=1)\ or\ (a=-2\ and\ b=-1)\\[/tex]

Roots are thus 2+i and -2-i

There is an other using a geometrical formula (formule de Moivre)

Solve simultaneously

4X + 3y= 19
2X +5y= 20

Answers

answer

4

2

Step-by-step explanation:

4x+3y=19

4x=19-3y

4x=16

x=16/4

x=4

2x+5y=20

5y=20/2x

5y= 10

y=10/5

y=2

álgebra 1 solve -7 + 18(17h + 19)

Answers

Answer:  =360h+335

Step-by-step explanation:

Answer:

306h + 281

Step-by-step explanation:

-7 + 18(17h + 19)

-7 + 306h + 288

306h + 281

The angle of elevation of a tree at a distance of 10m from the foot of the tree is 43°. Find the height of the tree

Answers

Answer:

9.32m is the height of. the tree from the ground.

Can someone help me?

Answers

Answer:

C

Step-by-step explanation:

its asking for y, on the graph, the line is placed on point 4

write the equation of the line that passes through the points (1,6) and (9,-8). put your answer in fully reduced slope form, unless it is a vertical or horizontal line.

Answers

Answer:

Y = - 7/4 X + 31/4

Step-by-step explanation:

M = 14/-8 = - 7/4

6 = - 7/4 + B

24 = -7 + 4B

31 = 4B

B = 31/4

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