through which material does the light travel the fastest?

Answer:

The Peltier coefficient is a measure of the amount of heat carried by electrons or holes

Explanation:

Answer:

The Peltier coefficient is a measure of the amount of heat carried by electrons or holes.

Explanation:

Answer:

Inner planets rotate slowly and so they take more time to complete a rotation. Whereas, outer planets rotate faster and so they take less time to complete a rotation.

Explanation:

The inner planets are the ones that are much closer to the sun and as such they have much smaller orbits around them and take much less time to circle around it. These planets are much smaller, which enables them rotate slowly, so they take more time to complete a rotation..

Whereas, the outer planets differ from the inner planets in that they are much further from the sun and so take much more time for them to be able to make a single circle around the su and also, because they are much bigger, it takes them much more time to spin around their own axis, thus Outer planets rotate faster, so they take less time to complete a rotation

Answer:

B. fjords

explanation :

Fjords were created by glaciers. In the Earth's last ice age, glaciers covered just about everything. Glaciers move very slowly over time, and can greatly alter the landscape once they have moved through an area. This process is called glaciation.The fjords are one of the glaciers that existed in the past. They are one of the many glacial relief forms that can give us a insight into the size and power of the glaciers.

Answer:

B. fjords

I hope this helps

Answer:

Explanation:

To find the distance covered by the car after it applied brakes, we use 3rd equation of motion.

2as = Vf² - Vi²

s = (Vf² - Vi²)/2a

1.

We have:

Vi = Initial Velocity = 5 m/s

Vf = Final Velocity = 0 m/s    (Since, car finally stops)

a = deceleration = - 2 m/s²

s = distance covered by the car = ?

Therefore,

s = [(0 m/s)² - (5 m/s)²]/2(- 2 m/s²)

s = 6.25 m

2.

We have:

Vi = Initial Velocity = 10 m/s

Vf = Final Velocity = 0 m/s    (Since, car finally stops)

a = deceleration = - 2 m/s²

s = distance covered by the car = ?

Therefore,

s = [(0 m/s)² - (10 m/s)²]/2(- 2 m/s²)

s = 25 m

Hence, the distance traveled by the car is affected by the initial speed in accordance with a direct relationship.

Answer:

to create the particle the speed must be greater than 2.25 10⁸ m / s

Explanation:

In this exercise we must use the relation of the index of refraction with the speed of light in a vacuum and a material medium

           n = c / v

where c is the speed of light in the vacuum, v the speed of light in the material medium and n the ratio of rafraccio

in this case they give us that the medium matter water them that has a refractive index of

              n = 1,333

we clear

          v = c / n

let's calculate

           v = 3 10⁸ / 1,333

           v = 2.25 10⁸ m / s

to create the particle the speed must be greater than 2.25 10⁸ m / s

Answer:

Explanation:

Message will travel through the fibre at the speed of 3 x 10⁸ m /s which is also the speed of light .

a ) Time for a message to travel from US to France by using glass fibre  link

time  = distance / speed

= 6000 x 1000 / 3 x 10⁸

= .02 s .

b )

22000 miles = 1.6 x 22000

= 35200 km

Time for a message to travel from US to France by using a satellite link

time = distance / velocity

 distance = 2 x √ ( 35200² + 3000² )

=  2 x 35327 km

= .7 x 10⁸ m .

time = .7 x 10⁸ / 3 x 10⁸

= .233 s

c )

Difference of time = .233 - .02

= .213 which is more than 1/6 s for which effect of hearing stays in the brain , which is called persistence of vision .  So they will be heard as different sounds.

Answer:

B. the number of field lines on the source charge

Explanation:

As we know that electric flux is defined as the number of electric field lines passing through a given area.

So here  electric flux due to a point charge "q" is given by

so here we know that flux depends on the magnitude of charge and hence we can say that number of filed lines originating from a point charge will depends on the magnitude of the charge.

The factor indicates the amount of charge on the source charge is the number of field lines on the source charge.

The electric flux is defined as the number of electric field lines passing through a given area.

The electric flux due to a point charge q is given by the number of filed lines through particular closed area.

We know that flux depends on the magnitude of charge and number of field lines starting from a point charge will depends on the magnitude of the charge.

Thus, the correct option is B.

Learn more about electric flux.

https://brainly.com/question/14544020

#SPJ2

Answer:

Explanation:

For a person suffering from nearsightedness, far point is 3.5 m . That means , an object beyond 3.5 m will not be clearly visible by the person . Ray of light coming from 3.5 m will be focussed on retina . For an object to be visible from infinity , ray of light coming from infinity should appear to be coming from 3.5 m . In other words , the object placed at infinity should form a virtual  image at 3.5 m . This can be done by concave lens.

u = ∝ ;  v  = 3.5

Using lens formula

[tex]\frac{1}{v} -\frac{1}{u} = \frac{1}{f}[/tex]

[tex]\frac{1}{-3.5} -0 = \frac{1}{f}[/tex]

f = - 3.5 m .

Answer:

The final velocity of the bullet is 9 m/s.

Explanation:

We have,

Mass of a bullet is, m = 0.05 kg

Mass of wooden block is, M = 5 kg

Initial speed of bullet, v = 909 m/s

The bullet embeds itself in the block which flies off its stand. Let V is the final velocity of the bullet. The this case, momentum of the system remains conserved. So,

[tex]mv=(m+M)V\\\\V=\dfrac{mv}{m+M}\\\\V=\dfrac{0.05\times 909}{0.050+5}\\\\V=9\ m/s[/tex]

So, the final velocity of the bullet is 9 m/s.

Answer: Silver

Explanation:Silver has ahigh thermal conductivity of 429 watts/meter-k. Stainless steel on the other hand, has low thermal conductivity of 160 watts/meter-k.

Please rate 5 stars and vote as brainliest:)

(^o^)(^o^)(^o^)(^o^)(^o^)(^o^)(^o^)(^o^)(^o^)(^o^)

Answer:

A.)

Explanation:

The answer is food chain A, as plants produce their own food using photosynthesis, therefore making them producers.  

A grasshopper then eats this grass, making it a consumer as it is obtaining its energy from the producer.  It is then eaten by a fish and a human.  This chain accurately describe the flow of energy in an ecosystem, as it goes, producer, consumer, consumer, consumer

Hope this helps a little

Answer:

sorry

Explanation:

patulong

Answer:

a

The force experience by the two spheres is [tex]F_1 = 1.44*10^4 N[/tex]

This force is attractive cause the charge are unlike charges

b

The force experienced by the two spheres is  [tex]F_2 = 3.24*10^{3} \ N[/tex]

The force is repulsive because the two charges are like charges

Explanation:

From the question we are told that

   The charge on the first sphere is  [tex]q_1 = -20.0 \mu C = 20 *10^{-6} C[/tex]

    The charge on the second sphere is  [tex]q_2 = 50 \mu C = 50*10^{-6} C[/tex]

      The distance of separation is [tex]d = 2.50 \ cm = \frac{2.50}{100} = 0.025 \ m[/tex]

The electrostatic force experienced by the two spheres is mathematically represented as

                  [tex]F_1 = \frac{k q_1 q_2}{d^2}[/tex]

Now k is the coulomb’s constant with a value of  [tex]k = 9*10^9 N \cdot m^2 /C^2[/tex]

   So

              [tex]F_1 = \frac{9*10^9 * 20 *10^{-6} * 50*10^{-6}}{0.025}[/tex]

              [tex]F_1 = 1.44*10^4 N[/tex]

When the sphere are brought together the charge on each sphere would be the average of the total charge and this can be mathematically evaluated as

            [tex]q = \frac{q_1 + q_2 }{2}[/tex]

            [tex]q = \frac{(-20 + 50)*10^{-6} }{2}[/tex]

            [tex]q = 15 \mu C[/tex]

So when they are seperated the electrostatic force experienced is  

         [tex]F_2 = \frac{kq^2}{d^2}[/tex]

         [tex]F_2 = \frac{ 9*10^9 * (15 *10^{-6})}{0.025}[/tex]

         [tex]F_2 = 3.24*10^{3} \ N[/tex]

Explanation:

the gravity force obeys the inverse square law because according to the newtons law of gravitaion the force of the gravitation is directly proportional to the product of masses ... In this way it depends upon the masses directly.We donot notice any gravitational force because we have very small masses as compared to the plantery universe and the solar system ... due to there greater masses they exert a large force and thus by increasing the distance the force of attraction varies inversely to the force of gravitation...thus gravitional force is a variable quantity ..............varies inversely to the square of distance between the to bodies...

          F ∝1/r2

Answer:

Answer is C                                

Explanation:

I just did it E2020

A free body diagram with three force vectors, the first pointing south labeled F Subscript g Baseline, the second pointing northeast labeled F Subscript T Baseline and the third pointing northwest labeled F Subscript T. Thus option C is correct.

Free body diagram is defined as a drawing of an interesting object with all of its surroundings removed and the forces at work on the subject's body clearly depicted.

It is also defined as a diagram that reduces the loads and moments acting on a component or system of components.

Free body diagrams are streamlined depictions of an object and the force vectors operating on it in a problem. Since the diagram will depict this body without its surroundings, it is "free" of its environment.

Thus, a free body diagram with three force vectors, the first pointing south labeled F Subscript g Baseline, the second pointing northeast labeled F Subscript T Baseline and the third pointing northwest labeled F Subscript T. Thus option C is correct.

To, learn more about free body diagram, refer to the link below:

https://brainly.com/question/24087893

#SPJ5

i think photons with shorter wavelengths have larger speed.

I apologise if its incorrect.

Answer:

energy

Explanation:

Answer:

the tension in the cable is [tex]\mathbf{F = \frac{\pi E_o v^2r^2}{2d^2}}[/tex]

the work done by the cable is [tex]\mathbf{W= \frac{\pi E_ov^2r^2}{4d}}[/tex]

Explanation:

A)

If we have two circular plate supported by a cable at a fixed distance, then the electric field formed between the two plate of the capacitor can be represented by the equation.

[tex]\mathbf{E = \frac{voltage \ \ V}{distance \ \ d}}[/tex]

However; the net electric field i.e the sum of the electric filed produced is represented as:

[tex]\mathbf{E' = \frac{E}{2}} \\ \\ \mathbf{E' = \frac{V}{2d}}[/tex]

So, if we assume that the lower plate and the upper plate possess the charge +q and -q respectively. Then, the tension of the cable which is the same as Force F can be written as:

[tex]\mathbf{F = q* E'}[/tex]

[tex]\mathbf{F = \frac{q*v}{2d}}[/tex] -----    equation (1)

Also ; we know that

[tex]\mathbf{C = \frac{q}{v}= \frac{E_oA}{d}}[/tex]

[tex]\mathbf{\frac{q}{v}= \frac{E_o \pi r^2}{d}} \ \ \ \ \ \mathbf{since \ A = \pi r^2}[/tex]

[tex]\mathbf{{q}= \frac{\pi E_o {v} r^2}{d}}[/tex]    -----   equation (2)

Replacing equation 3 into equation (2); we have:

[tex]\mathbf{F = \frac{\pi E_o vr^2}{d}* \frac{v}{2d}}[/tex]

[tex]\mathbf{F = \frac{\pi E_o v^2r^2}{2d^2}}[/tex]

Therefore,  the tension in the cable is [tex]\mathbf{F = \frac{\pi E_o v^2r^2}{2d^2}}[/tex]

B)

Assume that the upper plate is displaced by dz in an upward direction ; Then we can express the workdone by the tension as :

[tex]\mathbf{dW = T *dz} \\ \\ \mathbf{dW = F*dz} \\ \\ \mathbf{dW = \frac{\pi E_o v^2r^2}{2z^2}dz }[/tex]

The net workdone to raise the plate from separation d to 2d is:

[tex]\mathbf{W = \int\limits^{2d}_{2zd} {dw} = \frac{\pi E_ov^2r^2}{2} \int\limits^{2d}_d \frac{dz}{z^2} }[/tex]

[tex]\mathbf{W= \frac{\pi E_ov^2r^2}{2} [-\frac{1}{z}]^{2d}_d }[/tex]

[tex]\mathbf{W= - \frac{\pi E_ov^2r^2}{2} [\frac{1}{2d}-\frac{1}{d}]}[/tex]

[tex]\mathbf{W= - \frac{\pi E_ov^2r^2}{2} [\frac{-1}{2d}]}[/tex]

[tex]\mathbf{W= \frac{\pi E_ov^2r^2}{4d}}[/tex]

the work done by the cable is [tex]\mathbf{W= \frac{\pi E_ov^2r^2}{4d}}[/tex]

C) To calculate the energy stored in the Electrical energy Capacitor before the top plate is raised ; we have:

[tex]\mathbf{U_i = \frac{1}{2}Cv^2} \\ \\ \mathbf{U_i = \frac{1}{2}(\frac{E_oA}{d})v^2} \\ \\ \mathbf{U_i = \frac{1}{2}(\frac{E_o \pi r^2}{d})v^2} \\ \\ \mathbf{U_i = \frac{E_o \pi r^2 v^2}{2d}} }[/tex]

D) The energy stored in the plate after the  the top plate was raised is as follows:  

[tex]\mathbf{U_f = \frac{1}{2}C'v^2} \\ \\ \mathbf{U_f = \frac{1}{2}(\frac{E_oA}{2d})v^2} \\ \\ \mathbf{U_f = \frac{1}{2}(\frac{E_o \pi r^2}{2d})v^2} \\ \\ \mathbf{U_f = \frac{E_o \pi r^2 v^2}{4d}} }[/tex]

E) Yes,  work done by the cable equal to the change in the stored electrical energy. The Difference in energy stored before and after the top plate is raised:

[tex]\mathbf{U_i-U_f} = \mathbf{\frac{E_o \pi r^2 v^2}{2d}} }} - \mathbf {\frac{E_o \pi r^2 v^2}{4d}} }}[/tex]

[tex]\mathbf{U_i-U_f}= \mathbf {\frac{E_o \pi r^2 v^2}{4d}} }}[/tex]

Thus;

b)The work done in separating the plates is equal to the magnitude of the energy change in the plates. This does not mean that the work done is equal to the change in the energy stored in the plates.

Answer:

a. The free body diagram for this object has been attached. It shows all the forces acting on the body at rest, including the friction force in the opposite direction to sliding of the object (assume it's left to right).

b. Since the object is in contact with the surface, there is a normal force acting on both of them and is equal to the weight exerted by each. This perpendicular force is defined by Newton's second law of motion.

c. The force of friction always acts in a direction opposite to the direction of motion of the body. F = mg ('a' for acceleration is replaced by 'g' gravity because acceleration in this case is just gravity).

Hope that answers the question, have a great day!

Answer:

the speed of 0.10 sphere when it is moved to 0.20 kg  to the left is :   [tex]3.3337*10^{-5} \ m/s[/tex]

Explanation:

Using the expression of the Change in  Gravitational Potential Energy:

[tex]U= -(\frac{ Gm_1m_2 }{r_2} - \frac{ Gm_1m_2 }{r_1}) \\ \\ U=Gm_1m_2 (\frac{ 1 }{r_2} - \frac{ 1 }{r_1})[/tex]

So when the sphere exerts just 10 kg mass; the change in the gravitational potential energy is :

[tex]U_1=Gm_1m_2 (\frac{ 1 }{r_2} - \frac{ 1 }{r_1})[/tex]

[tex]U_1=6.67*10^{-11}*0.1 \ kg*10 \ kg(\frac{ 1 }{0.6 \ m} - \frac{ 1 }{0.8 \ m})[/tex]

[tex]U_1 = 2.778*10^{-11} J[/tex]

the change in the gravitational potential energy  when the sphere exerts just 5 kg mass is ;

[tex]U_2=Gm_1m_2 (\frac{ 1 }{r_2} - \frac{ 1 }{r_1})[/tex]

[tex]U_2=6.67*10^{-11}*0.1 \ kg*5 \ kg(\frac{ 1 }{0.4 \ m} - \frac{ 1 }{0.2 \ m})[/tex]

[tex]U_2 = -8.335*10^{-11} J[/tex]

The net total change is:

[tex]U_{total } = U_1 +U_2[/tex]

[tex]U_{total} = 2.778*10^{-11} + (-8.335*10^{-11})[/tex]

[tex]U_{total} = -5.557*10^{-11}[/tex]

We all know that for there to be a balance ;loss of gravitational potential energy must be equal to the gain in kinetic energy .

SO;

K.E =  [tex]5.557*10^{-11}[/tex]

[tex]\frac{1}{2}mv^2 = 5.557*10^{-11}[/tex]

[tex]v^2 = \frac{2*5.557*10^{-11} \ J}{m_1}[/tex]

[tex]v=\sqrt{ \frac{2*5.557*10^{-11} \ J}{0. 1 \kg}[/tex]

v = [tex]3.3337*10^{-5} \ m/s[/tex]

Thus, the speed of 0.10 sphere when it is moved to 0.20 kg  to the left is :   [tex]3.3337*10^{-5} \ m/s[/tex]

The speed of 0.10 sphere when it is moved to 0.20 kg  to the left is :3.3337 *10^-5 m/s

The speed of any object is defined as the movement of any object with respect to the time.

By using the expression of the Change in  Gravitational Potential Energy:

[tex]U=-Gm_1m_2(\dfrac{1}{r_2}-\dfrac{1}{r_1})[/tex][tex]U_2=-Gm_1m_2(\dfrac{1}{r_2}-\dfrac{1}{r_1})[/tex]

So when the sphere exerts just 10 kg mass; the change in the gravitational potential energy is :

[tex]U_1=-Gm_1m_2(\dfrac{1}{r_2}-\dfrac{1}{r_1})[/tex]

[tex]U_1=- 6.67\times 10^{-11}\times 0.1\times 10(\dfrac{1}{0.6}-\dfrac{1}{0.8})[/tex]

[tex]U_1=2.778\times 10^{-11][/tex]

The change in the gravitational potential energy  when the sphere exerts just 5 kg mass is ;

[tex]U_2=-Gm_1m_2(\dfrac{1}{r_2}-\dfrac{1}{r_1})[/tex]

[tex]U_2=- 6.67\times 10^{-11}\times 0.1\times 5(\dfrac{1}{0.4}-\dfrac{1}{0.2})[/tex]

[tex]U_2=-8.335\times 10^{-11}\ J[/tex]

The net total change is:

[tex]U_{total}=U_1+U_2[/tex]

[tex]U_{total}=2.778\times 10^{-11}+(-8.335\times 10^{-11})[/tex]

[tex]U_{tot\leq al}=-5.557\times 10^{-11}[/tex]

We all know that for there to be a balance ;loss of gravitational potential energy must be equal to the gain in kinetic energy .

SO;

[tex]\rm KE=5.557\times 10^{-11}[/tex]

[tex]\dfrac{1}{2}mv^2=5.557\times 10^{-11}[/tex]

[tex]v^2=\dfrac{2\times 5.557\times 10^{-11}}{m}[/tex]

[tex]v=\sqrt{\dfrac{2\times 5.557\times 10^{-11}}{m}}[/tex]

[tex]v=3.337\times 10^{-5}\ \frac{m}{s}[/tex]

Thus, the speed of 0.10 sphere when it is moved to 0.20 kg  to the left is : [tex]v=3.337\times 10^{-5}\ \frac{m}{s}[/tex]

To know more about speed follow

https://brainly.com/question/4931057

Answer:

The time interval is  [tex]t = 6.667 \ s[/tex]

Explanation:

From the question we are told that

    The acceleration of the car is  [tex]a = 3 m/s^2[/tex]

     The velocity of the car is  [tex]v= 20.0 \ m/s[/tex]

The final velocity of the car can be mathematically represented as

       [tex]v =u + at[/tex]

Now since the car start from rest  u = 0 So

      [tex]v = 0 + at[/tex]

       [tex]v = at[/tex]

substituting values

       [tex]20 = 3 t[/tex]

       [tex]t = \frac{20}{3}[/tex]

        [tex]t = 6.667 \ s[/tex]

Answer:

a. A list of the names of each student present today. (microstate)

b. The number of students in attendance. (macrostate)

Explanation:

You can fins the answer to this question by comparing the situation of the problem with a system of molecules with discrete energy.

Without importance of which molecules have a specific energy, but rather, what is the total amount of energy, you can get for different configurations of energy the same amount of the total energy. If different configurations of the energies of the molecules give you the same total energy of the system, you say that the macrostate is the same. In the case of the classroom, it does not matter how are distributed the students in the class, the total number of students is always the same. The macrostate is the same for what ever organization of the students in the class.

If you would interested in the energy of each molecules, you will obtain different configurations. In the case of the classroom. The names of the student will define a microstate because in this case there are many configurations.

a. A list of the names of each student present today. (microstate)

b. The number of students in attendance. (macrostate)

Answer: Carbon dioxide (CO2), Carbon monoxide (CO), Methane (CH4)

Explanation:

After every 3 to 4 months

Answer:500 W

Explanation:

Given

When length is L power dissipated is [tex]100\ W[/tex]

Potential difference applied is [tex]200\ V[/tex]

Resistance of wire is directly proportional to length of wire

Suppose initially Resistance is R

When L changes to [tex]2L[/tex]

Resistance changes to [tex]2R[/tex]

Initial Power dissipated is [tex]P_o=\frac{V^2}{R}[/tex]

For 2 R resistance and same voltage, Power dissipated is

[tex]P_1=\frac{V^2}{(2R)}[/tex]

So [tex]P_1=\frac{1}{2}\times \frac{V^2}{R}[/tex]

[tex]P_1=\frac{P_o}{2}[/tex]

So [tex]P_1=\frac{1000}{2}[/tex]

[tex]P_1=500\ W[/tex]

Answer:

[tex]L_{B}[/tex] / [tex]L_{A}[/tex] = [tex]\frac{5mvl}{mvl}[/tex]= 5

Explanation:

Find the given attachment

The definitions of angular momentum allow to find the result for the relationship between the two angular moments is:

           [tex]\frac{L_B}{L_A} = 5[/tex]  

The angular momentum is the vector product of momentum and  vector position.

       L = r x p

Where the bold letters indicate vectors, r is the position vector and p the moment. In the body that is in a rotation can be written as a function of the moment of inertia and the angular velocity.

      L = I w

Linear and angular variables are related.

       v = w L

We substitute

         L = I v L

The moment of inertia of a disk with respect to its center is:

        I = ½ m r²

Let's write the angular momentum for each disk.

Disc A

          [tex]L_A[/tex] = ½ [tex]m_A r^2 v_A L_A[/tex]  

Disc B

           [tex]L_B[/tex] = ½ [tex]m_B r^2 v_B L_B[/tex]  

They indicate that the mass of disk A is m and that of disk b is 20m, the length of the string is l for disk A and l / 4 for disk B.

We substitute

           [tex]L_A[/tex]  = ½ m r² v l

           [tex]L_B[/tex]  = ½ (20m) r² v ( [tex]\frac{l}{4}[/tex] )

The relationship between the angular moments is

          [tex]\frac{L_B}{L_A} = \frac{20m \frac{l}{4} }{m l}\\ \frac{L_B}{L_A} = 5[/tex]  

Consequently using the definitions of angular momentum we can find the result for the relationship between the two angular moments is:

           [tex]\frac{L_B}{L_A} = 5[/tex]

Learn more here:  brainly.com/question/25303285

Answer:

a)   r = (0.6 i- 2039 j ^ + 0.102 k⁾ m  and b) vₓ = 30.0 m / s , v_{y} = 2.04 10⁵ m / s   c) v_{z}  = 1.02 10⁻¹m / s

Explanation:

a) To find the position of the particle at a given moment we must know the approximation of the body, use Newton's second law to find the acceleration

         Fe + Fm = m a

         a = (Fe + Fm) / m

the electric force is

         Fe = q E   k ^

         Fe = 4.25 10-4 60 k ^

         Fe = 2.55 10-2 k ^

the magnetic force is

         Fm = q v x B

         Fm = 4.25 10⁻⁴  [tex]\left[\begin{array}{ccc}i&j&k\\30&0&0\\0&0&49\end{array}\right][/tex]

         fm = 4.25 10⁻⁴ (-j ^ 30 4)

         fm 0 = ^ -5,10 10⁻² j

We look for every component of acceleration

X axis

      aₓ = 0

there is no force

Axis y

      ay = -5.10 10²/5 10⁻⁵ j ^

      ay = -1.02 107 j ^ / s2

z axis

      az = 2.55 10⁻² / 5 10⁻⁵ k ^

      az = 5.1 10² k ^ m / s²

Having the acceleration in each axis we can encocoar the position using kinematics

X axis

the initial velocity is vo = 30 m / s and an initial position xo = 0

           x = vo t + ½ aₓ t₂2

           x = 30 0.02 + 0

           x = 0.6m

Axis y

acceleration is ay = -1.02 10⁷ m / s², a starting position of i = 1m

           y = I + go t + ½ ay t²

           y = 1 + 0 + ½ (-1.02 10⁷) 0.02²

           y = 1 - 2.04 10³

           y = -2039 m j ^

z axis

acceleration is aza = 5.1 10² m / s², the position and initial speed are zero

          z = zo + v₀ t + ½ az t²

          z = 0 + 0 + ½ 5.1 10² 0.02²

          z = 1.02 10⁻¹ m k ^

therefore the position of the bodies is

   r = (0.6 i- 2039 j ^ + 0.102 k⁾ m

b) x axis

 since there is no acceleration the speed remains constant

          vₓ = 30.0 m / s

Axis y

  let's use the equation v = v₀ + [tex]a_{y}[/tex] t

         [tex]v_{y}[/tex] = 0 + -1.02 10⁷ 0.02

          v_{y} = 2.04 10⁵ m / s

z axis

          v_{z} = vo + az t

          v_{z} = 0 + 5.1 10² 0.02

          v_{z}  = 1.02 10⁻¹m / s

A) The coordinates of the particle in  x,  y and z axis is written as  :

( 0.6 i - 2039 j + 0.102 k )m   ( i.e. x = 0.6,  y = 2039,  z = 0.102 )

B) The speed of the particle at t = 0.0200 s

A ) Determine the coordinates of the particle in  x, y and z axis

applying Newton's second law ;  a = ( Fe + Fm ) / m

where :  Fe = 2.55 * 10⁻² k

The magnetic force ( Fm ) = qv * B  = [tex]\left[\begin{array}{ccc}i&j&k\\30&0&0\\0&0&49\end{array}\right][/tex]

∴ Fm = 0

Acceleration in each axis ( x , y and z )

Ax = 0  because there is no force

Ay =  - 1.02 * 10⁷  j/s²

Az =   5.1 * 10² km/s²

i) For the x- axis

x =  Vot  +  ½ * Ax * t²

Vo = 30 m/s

t = 0.02

Ax = 0

∴ x - coordinate of the particle = 0.6m

ii) For the y-axis

y = I + Vo*t + ½ *Ay* t²

y = - 2039 m

iii) For the z-axis

 z = zo + v₀* t + ½ * Az* t²

 z = 0.102 m .

B ) Determine the speed of the particle in all three axis

Vx = 30 m/s

Vy = v₀ + Ay *  t

     = 30 + - 1.02 * 10⁷ * 0.020

     = 2.04 * 10⁵ m/s

Vz =  Vo + Az* t

    = 1.02 * 10⁻¹

Hence we can conclude that The coordinates of the particle in  x,  y and z axis is written as  : ( 0.6 i - 2039 j + 0.102 k )m   ( i.e. x = 0.6,  y = 2039,  z = 0.102 )The speed of the particle at t = 0.0200 s

Learn more : https://brainly.com/question/19915685

Answer:

These two forces are called action and reaction forces

Explanation:

Answer:

They are used in icy conditions.

Explanation:

They can also go over grassy plains and mucky swamps.

Answer: the expression of the mechanical energy for under damped system is;

x(t)=Ae−γ/2tcos⁡(ωdt+ϕ), where ωd=ω02−γ2/4

γ = damping rate, and

ω0 = the angular frequency of the oscillator without damping.

Explanation:

The physical situation in mechanical energy defined through out the world has three possible results depending on the value of a (which is a constant value), which depends on the value of what is under our radical. This expression can either be positive, negative, or equal to zero which will result in overdamping, underdamping, and critical damping, as the case may be.

γ2 >4ω²0 This is the Over Damped case. Here, the system returns to equilibrium by exponentially decaying towards zero, and the system will not pass that equilibrium position more than once.

γ² < 4ω²0 this is the Under Damped case. Here, the system moves back and forth as it slowly returns to equilibrium and the amplitude of the system decreases over time.

Finally, γ² = 4ω²0

This is the Critically Damped case. Here, the system returns to equilibrium very fast without moving back and forth and without passing the equilibrium position at all.

Answer:

a) ΔS = 14.46 J/k

b) ΔS = 70.76 J/k

Explanation:

The general formula to calculate the entropy change accompanied with a process is:

ΔS = ΔQ/T

where,

ΔS = entropy change for the process

ΔQ = Heat Transfer during the process

T = Absolute Temperature during the process

a)

In this case the heat transfer will be given as:

ΔQ = (ΔHfus)(N)

where,

ΔHfus = Molar Heat of Fusion of Tin = 7.029 KJ/mol

N = No. of moles of tin = 1 mol

Therefore,

ΔQ = (7.029 KJ/mol)(1 mol)

ΔQ = 7.029 KJ = 7029 J

and the absolute temperature is:

T = 213°C +273 = 486 k

using these values in the entropy formula, we get:

ΔS = 7029 J/486 k

ΔS = 14.46 J/k

b)

In this case the heat transfer will be given as:

ΔQ = (ΔHvap)(N)

where,

ΔHvap = Molar Heat of Vaporization of Carbon Dioxide = 15.326 KJ/mol

N = No. of moles of Carbon Dioxide = 1 mol

Therefore,

ΔQ = (15.326 KJ/mol)(1 mol)

ΔQ = 15.326 KJ = 15326 J

and the absolute temperature is:

T = 216.6 k

using these values in the entropy formula, we get:

ΔS = 15326 J/216.6 k

ΔS = 70.76 J/k