Three hikers take three different paths to the top of a mountain, Paths 1, 2, and 3. The hikers are all the same height and weight.

When all of the hikers are at the finish point at the top of the mountain, which hiker will have the greatest amount of gravitational potential energy?

A)The gravitational potential energy is the same for all of the hikers.
B)The hiker who took Path 1
C)The hiker who took Path 2
D)The hiker who took Path 3

Answer:

Explanation:

Given

Force = 8N

Direction = N50°E

Required

x component of the Force

Fx = F cos theta

Fx = 8cos 50°

Fx = 8(0.6428)

Fx = 5.1423N

Hence the x component of the force is 5.1423N

Answer:

D

Explanation:

Magnetic domains are always present in ferromagnetic materials due to the way the atoms bond to form the material. However, when a ferromagnetic material is in the unmagnetized condition, the magnetic domains are randomly oriented so that the magnetic field strength in the piece of material is zero.

Answer:

D. magnetic fields of atoms being aligned with each other

Explanation:

Answer:

340m/s

Explanation:

Given parameters:

Wavelength  = 2m

Frequency   = 170Hz

Unknown:

Velocity of the wave  = ?

Solution:

The velocity of the wave is the product of frequency and wavelength of the wave;

          V  = F λ

V is the velocity

 F is the frequency

λ is the wavelength

  Insert the parameters and solve;

          V = 2  x 170 = 340m/s

The velocity of the wave with the given wavelength and frequency is 340m/s.

Given the data in the question;

Velocity; [tex]v =\ ?[/tex]

To determine the velocity of the wave, we use the expression for the relations between wavelength, frequency and speed.

[tex]\lambda = \frac{v}{f}[/tex]

Where [tex]\lambda[/tex] is wavelength, f is frequency and v is speed.

We substitute our given values into the equation

[tex]2m = \frac{v}{170s^{-1}}\\\\v = 2m * 170s^{-1}\\\\v = 340m/s[/tex]

Therefore, the velocity of the wave with the given wavelength and frequency is 340m/s.

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Answer:

I think white is the colour of star A.

Answer:

yellow

Explanation:

Answer:

A planet's orbital speed changes, depending on how far it is from the Sun. The closer a planet is to the Sun, the stronger the Sun's gravitational pull on it, and the faster the planet moves.

Explanation: hope that helps :)

A maritime polar air mass has relatively higher moisture and is relatively cooler than the tropical air mass.

Maritime polar (mP) is cold but moist due to its origination over the oceans. The desert region air masses (hot and dry) are designated by ‘cT’ for ‘continental tropical’. As these air masses move around the earth they can begin to acquire additional attributes.

The continental Tropical (cT) air mass originates in arid or desert regions in the middle or lower latitudes, principally during the summer season. It is strongly heated in general, but its moisture content is very low.

Continental tropical air masses are extremely hot and dry. Arctic, Antarctic, and polar air masses are cold. The qualities of arctic air are developed over ice and snow-covered ground. Arctic air is deeply cold, colder than polar air masses

Maritime Polar (mP) air masses develop over the polar areas of both the Northern and the Southern hemispheres. They generally contain considerably more moisture than the cP air masses. As they move inland in middle and high latitudes, heavy precipitation may occur.

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Answer: -.80m/s

Explanation:

Answer:

Weight of the box? 980 N

Value of the normal force? 630 N

Acceleration of the box? 7.5 m/s^2

Explanation:

I got the answer right

Answer:

The potential is  [tex]V_A = 9600 \ V[/tex]

Explanation:

From the question we are told that  

   The  magnitude of the charge is  [tex]q_1 = 4 \mu C = 4*10^{-6} \ C[/tex]

   The position of the charge is  [tex]x = + 3.0 \ m[/tex]

   The magnitude of the second charge is  [tex]q_2 = -2.0 \mu C = -2.0 *10^{-6} \ C[/tex]

   The position is  [tex]y_1 = - 1.0 \ m[/tex]

     The position of point A is  [tex]y_2 = + 4.0 \ m[/tex]  

Generally the electric potential  at A due to the first charge is mathematically represented as

         [tex]V_a = \frac{k * q_1 }{r_1 }[/tex]

Here k is the coulombs constant with value [tex]k = 9*10^{9} \ \ kg\cdot m^3\cdot s^{-4} \cdot A^{-2}[/tex]

        [tex]r_1[/tex]  is the distance between first charge and a which is mathematically represented as

         [tex]r_1 = \sqrt{x^2 + y_2 ^2 }[/tex]

=>      [tex]r_1 = \sqrt{3^2 + 4 ^2 }[/tex]    

=>      [tex]r_1 = 5 \ m[/tex]    

So

           [tex]V_a = \frac{9*10^9 * 4*10^{-6} }{5 }[/tex]

      [tex]V_a = 7200 \ V[/tex]

Generally the electric potential  at A due to the second charge is mathematically represented as

         [tex]V_b = \frac{k * q_2 }{r_2 }[/tex]

Here k is the coulombs constant with value [tex]k = 9*10^{9} \ \ kg\cdot m^3\cdot s^{-4} \cdot A^{-2}[/tex]

        [tex]r_2[/tex]  is the distance between second charge and a which is mathematically represented as

         [tex]r_2 = y_2 - y[/tex]

=>      [tex]r _2 = 4.0 - (-1.0)[/tex]    

=>      [tex]r = 5 \ m[/tex]    

So

           [tex]V_a = \frac{9*10^9 * -2*10^{-6} }{5 }[/tex]

      [tex]V_a = -3600 \ V[/tex]

So the net potential difference at point A  due to the charges is mathematically represented as

       [tex]V_n = V_a + V_b[/tex]

=>     [tex]V_n = 7200 - 3600[/tex]

=>     [tex]V_n = 3600 V[/tex]

Generally the net potential difference at the origin due to both charges is mathematically represented as

     [tex]V_N = V_c + V_d[/tex]

Here  

      [tex]V_c = \frac{k * q_1 }{x}[/tex]

=>   [tex]V_c = \frac{9*10^9 * 4*10^{-6} }{3}[/tex]

=>   [tex]V_c = 12000 V[/tex]

and

              [tex]V_d= \frac{k * q_2 }{y}[/tex]

=>   [tex]V_c = \frac{9*10^9 * -2*10^{-6} }{1}[/tex]

=>   [tex]V_c =- 18000 V[/tex]

Generally the net potential difference at the origin is  

       [tex]V_N = 12000 - 18000[/tex]

=>     [tex]V_N = -6000[/tex]

Generally the potential difference at A relative to zero at the origin is mathematically evaluated as

         [tex]V_A = V_n - V_N[/tex]

=>      [tex]V_A = 3600 - (-6000)[/tex]

=>      [tex]V_A = 9600 \ V[/tex]

Answer:

this is in the middle of the wheel and helps it rotate it is an axle

Answer:

His third law states that for every action (force) in nature there is an equal and opposite reaction. Explanation:

Answer:

His third law states that for every action (force) in nature there is an equal and opposite reaction

Explanation:

In other words, if object A exerts a force on object B, then object B also exerts an equal and opposite force on object A. Notice that the forces are exerted on different objects.

Answer:

The object takes approximately 1.180 seconds to complete one horizontal circle.  

Explanation:

From statement we know that the object is experimenting an Uniform Circular Motion, in which acceleration ([tex]a[/tex]), measured in meters per square second, is entirely centripetal and is expressed as:

[tex]a = \frac{4\pi^{2}\cdot R}{T^{2}}[/tex] (1)

Where:

[tex]T[/tex] - Period of rotation, measured in seconds.

[tex]R[/tex] - Radius of rotation, measured in meters.

If we know that [tex]a = 26.36\,\frac{m}{s^{2}}[/tex] and [tex]R = 0.93\,m[/tex], then the time taken by the object to complete one revolution is:

[tex]T^{2} = \frac{4\pi^{2}\cdot R}{a}[/tex]

[tex]T = 2\pi\cdot \sqrt{\frac{R}{a} }[/tex]

[tex]T = 2\pi\cdot \sqrt{\frac{0.93\,m}{26.36\,\frac{m}{s^{2}} } }[/tex]

[tex]T \approx 1.180\,s[/tex]

The object takes approximately 1.180 seconds to complete one horizontal circle.  

Answer: Use the x/t = v formula!!! x is distance, t is time, and v is velocity. you just need to do 40 / 5 = 8 and 100 / 15 = 6.66

Answer:

The acceleration is 8 m/s²

Explanation:

The given parameters are;

The initial velocity, u = 2 m/s

The final velocity, v = 6 m/s

The distance the acceleration took place, s = 2 m

The acceleration, a, can be found from the following kinematic equation;

v² = u² + 2·a·s

By substituting the values, we have;

6² = 2² + 2 × a × 2

6² - 2² = 2 × a × 2

32 = 4·a

a = 32/4 = 8 m/s²

The acceleration, a, of the given motion = 8 m/s².

Answer: So if the steady easterly wind of 19 m/s begins to blow more than the 10 m/s it just needs more wind and direction So the resultant has to be 29 m/s east.

Answer:

When same-sized team members are placed on each side of the rope, the sizes of the arrows on both sides remain the same.

Explanation:

This is the answer on Plato

Answer:

When same-sized team members are placed on each side of the rope, the sizes of the arrows on both sides remain the same.

Explanation:

Answer:

increase distance

Explanation:

Inclined planes make it easier to move objects to a higher elevation. The sloping surface of the inclined plane supports part of the weight of the object as it moves up the slope. As a result, it takes less force to move the object uphill.

Answer:

Hello your answer would be increase of distance

Explanation:

I know that because than you would have to go upward with the object.

Answer:

Exercise 1;

The centripetal acceleration is approximately 94.52 m/s²

Explanation:

1) The given parameters are;

The diameter of the circle = 8 cm = 0.08 m

The radius of the circle = Diameter/2 = 0.08/2 = 0.04 m

The speed of motion = 7 km/h = 1.944444 m/s

The centripetal acceleration = v²/r = 1.944444²/0.04 ≈ 94.52 m/s²

The centripetal acceleration ≈ 94.52 m/s²

Gravitational potential energy is the energy stored in an object as the result of its vertical position or height. It can be calculated as its weight times the height. This is:

[tex]\boxed{U_g=W\cdot h=mgh}[/tex]

Where:

Evaluating:

[tex]U_g = (0.145\;kg)(9.8\;m/s^2)(2.50\;m)\\\\\boxed{U_g=3.5525\;J}[/tex]

R/ The ball has 3.5525 J of potential energy.

Answer:

the time comes eventually.

Explanation:

ur body just be giving up

Answer:

e

Explanation:

e

Answer: mass

Explanation:

i remember my teacher saying it lol

A rifle recoils from firing a bullet. The speed of the rifle’s recoil is small compared to the speed of the bullet because the rifle has a great deal more mass than the bullet.

Mass is a numerical measure of inertia, which is a basic feature of all matter. It is, in effect, a body of matter's resistance to a change in speed or position caused by the application of a force.

In the International System of Units (SI), the kilogram is the unit of mass.

A rifle recoils from firing a bullet. The speed of the rifle’s recoil is small compared to the speed of the bullet because the rifle has a great deal more mass than the bullet.

Hence d is the correct option.

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Answer:

His initial velocity (speed) must be 64.16 m/s.

Explanation:

Horizontal Motion

When an object is horizontally launched at a speed v from a height h, the maximum horizontal distance (also called Range) traveled by the object can be calculated as follows:

[tex]\displaystyle d=v\cdot\sqrt{\frac {2h}{g}}[/tex]

Our daredevil is attempting to clear a river d=420 m wide with his motorcycle from a cliff h=210 m high. We need to find the speed needed to safely reach the opposite edge of the river.

From the above equation, we solve for v:

Speed:

[tex]\displaystyle v=d\cdot\sqrt{\frac {g}{2h}}[/tex]

[tex]\displaystyle v=420\cdot\sqrt{\frac {9.8}{2\cdot 210}}[/tex]

[tex]\displaystyle v=420\cdot\sqrt{\frac {9.8}{420}}[/tex]

v = 64.16 m/s

His initial velocity (speed) must be 64.16 m/s.

Answer:

Option D (On the...............dominate) would be the right approach.

Explanation:

The Gravitational constant (G) will be:

= [tex]6.67\times 10^{-11}[/tex]

The Coulomb's law constant (K) will be:

= [tex]9\times 10^9[/tex]

⇒ [tex]\frac{f_e}{f_g}\sim 10^{42}[/tex]

The latter three choices aren't connected to either the situation mentioned in the clarification segment elsewhere here.

The statement that provides evidence that there must be at least two types of electrical charge, but that there is only one type of mass is that on the scale of the solar system, electric forces cancel out and gravitational forces dominate.

The examples that provides conclusive evidence of is option d because the Gravitational constant is (G)=6.67*10-11 while the Coulomb's law constant(K)=9*109.

The interaction between charged objects is regarded as a non-contact force that acts over some distance of separation.

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