three-fifths of a number increased by ten

Answer:

C. 47 deg

Step-by-step explanation:

m<A = 180 - 94 - 39 = 47

m<D = m<A = 47

Answer:

3/8

Step-by-step explanation:

Both measurements should be in same measure.So convert m to cm

2.4m = 2.4 * 100 = 240.0 = 240 cm

[tex]\frac{90}{240}=\frac{9}{24}=\frac{3}{8}[/tex]

9514 1404 393

Answer:

  A, C

Step-by-step explanation:

A: -3 -(-8) = -3 +8 = 5

B: -2 -3 = -5

C: 1 -(-4) = 1 +4 = 5

D: 7 -(-2) = 7 +2 = 9

__

Differences A and C are 5.

Answer: A: -3- (-8)

B:1 -(-4)

Step-by-step explanation:

in A your subtracting them in B your adding them

Answer:

I can graph stuff in different ways. but place share the mentioned tables. the data is missing.

will edit this placeholder answer asap when you show wich data to graph

Answer: 144

Step-by-step explanation:

If 1 pound is 16 ounces then you have to do 9 X 16

9x16 = 144

Therefore the answer is 144 ounces

Hope this helped!

Answer:

Coefficient of determination, R²

Step-by-step explanation:

The proportion of variation of the dependent variable that can be explained by the regression line is defined by the coefficient of determination, R².

In the scenario described above, the proportion of variation in the number of minutes of activity per day(dependent variable) that can be explained by age, hours of sleep and minutes spent on social media (independent variables) which forms the regression line is 0.45 (45%) is the coefficient of determination while (1 - 0.45) = 0.55 is due to other factors.

Answer: 2/3x-y=19/3

Step-by-step explanation:

Points are useless since we already know the point slope form and we can just simply that

y+1=2/3(x-8)

y+1=2/3x-16/3

y=2/3x-19/3

2/3x-y=19/3

F(1) is saying the value of x is 1

Look at the graph where x is 1 and find the y value of where the line is.

At x = 1, the line is at y = 1 ( there is actually a dot showing you the location.

The answer is 1

Answer:

Event 4 (0%), Event 2 (45%), Event 3 (80%), Event 1 (100%)

Step-by-step explanation:

Answer:

I am not to sure how the actual grade was calculated, maybe there are some other factors to it, but from the three grades you got, the weighted total is 70.2%, if we add the weighted average of 68 on the exam (with the weight being 20%), we get 83.3%.

Answer:

5x+4y=24

Step-by-step explanation:

So Ax+By=C is the standard form equation of a line.

y=mx+b (in which m is the slope and b is the y-intercept) is the equation that most people start off with.

Since the line intersects the y-axis at (0,6), the y-intercept is 6.

So, we can substitute 6 with b, which is y=mx+6.

Now, we can find the slope (m) by either inserting a known point (x,y) or using rise/run. Either way, you get the slope as -5/4 because we go five units DOWN and four units RIGHT from (0,6), one known point, to (4,1), another known point.

The y=mx+b equation becomes: y=(-5/4)x+6.

Now, we subtract (-5/4)x on both sides to get (5/4)x+y=6

Multiply 4 on both sides because standard form requires no fractions or decimals.

The final answer is 5x+4y=24.

That's your answer, fully simplified!

Answer:

asap!!

For the following geometric sequence, find the recursive formula.

(-80,20,-5...)

Step-by-step explanation:

asap!!

For the following geometric sequence, find the recursive formula.

(-80,20,-5...)

Answer:

z(max)  = 2350

x₁  =  18          x₂  =  10

Step-by-step explanation:

                             Vol (ft³)         W (p)    Income ($)

Cargo A  (x₁)             50              200          75

Cargo B  (x₂)            10               360          100

Max load limit       1000            7200

Objective Function

z  =  75*x₁   +  100*x₂

Constraints:

Volume constraint:

50*x₁  +  10*x₂  ≤ 1000

Weight constraint:

200*x₁  +  360*x₂  ≤ 7200

Model:

z  =   75*x₁   +  100*x₂       to maximize

Subject to:

50*x₁  +  10*x₂  ≤ 1000

200*x₁  +  360*x₂  ≤ 7200

x₁  ≥  0        x₂  ≥ 0    x₁  and x₂  integers

After 6 iterations with an on-line solver optimal solution is:

z(max)  = 2350

x₁  =  18          x₂  =  10

Step-by-step explanation:

how many people in the party please ?

Answer:

Its speed is 14 mph.

Step-by-step explanation:

Given that regarding racer called The Whirlwind, its poster says that in 1/20 hour it covers 7/10 mile, to determine what is the Whirlwind’s speed in miles per hour the following calculation must be performed:

1/20 x 60 = 0.05 x 60 = 3 minutes

7/10 = 0.7

Therefore, every 3 minutes the Whirlwind travels 0.7 miles.

60/3 = 20

0.7 x 20 = 14

Thus, in an hour it travels 14 miles, with which its speed is 14 mph.

Answer:

A is is correct since the interquatile or a is 15 since 15 plus 15 equals 30 and 20 plus 20 equals 40

B is incorrect since the interquare are not both 30

C is incorrect since both interquatiles are wrong

D is incorrect since the standrard devations are off

Answer:

Step-by-step explanation:

1.4 m = 1.4 * 100 = 140.0  = 140 cm

Answer:

[tex]Width = 59[/tex]

Step-by-step explanation:

Given

The above data

Required

The class width

To do this, we simply calculate the difference between the class limits of any one of the classes.

Taking 1187–1246 as a point of reference, the class width is:

[tex]Width = 1246 - 1187[/tex]

[tex]Width = 59[/tex]

Answer:

show the graphs?

Step-by-step explanation:

Answer:

[tex]x=2+\sqrt{21}\\\\x=2-\sqrt{21}[/tex]

Step-by-step explanation:

One is given the following equation;

[tex]x^2-4x-9=29[/tex]

The problem asks one to find the roots of the equation. The roots of a quadratic equation are the (x-coordinate) of the points where the graph of the equation intersects the x-axis. In essence, the zeros of the equation, these values can be found using the quadratic formula. In order to do this, one has to ensure that one side of the equation is solved for (0) and in standard form. This can be done with inverse operations;

[tex]x^2-4x-9=29[/tex]

[tex]x^2-4x-38=0[/tex]

This equation is now in standard form. The standard form of a quadratic equation complies with the following format;

[tex]ax^2+bx+c[/tex]

The quadratic formula uses the coefficients of the quadratic equation to find the zeros this equation is as follows,

[tex]\frac{-b(+-)\sqrt{b^2-4ac}}{2a}[/tex]

Substitute the coefficients of the given equation in and solve for the roots;

[tex]\frac{-(-4)(+-)\sqrt{(-4)^2-4(1)(-38)}}{2(1)}[/tex]

Simplify,

[tex]\frac{-(-4)(+-)\sqrt{(-4)^2-4(1)(-38)}}{2(1)}\\\\=\frac{4(+-)\sqrt{16+152}}{2}\\\\=\frac{4(+-)\sqrt{168}}{2}\\\\=\frac{4(+-)2\sqrt{21}}{2}\\\\=2(+-)\sqrt{21}[/tex]

Therefore, the following statement can be made;

[tex]x=2+\sqrt{21}\\\\x=2-\sqrt{21}[/tex]

9514 1404 393

Answer:

  D

Step-by-step explanation:

The sine function is negative only for angles greater than 180°. This eliminates choice B.

The sine function is periodic with a period of 360°, eliminating choices A and C.

The only viable choice is D, which is the correct one.

Answer:

The equation of line d is [tex]y + 8 = 6(x + 3)[/tex]

Step-by-step explanation:

Equation of a line:

The equation of a line, in point-slope form, is given by:

[tex]y - y_0 = m(x - x_0)[/tex]

In which the slope is m and the point is [tex](x_0,y_0)[/tex]

Perpendicular lines:

If two lines are perpendicular, the multiplication of their slopes is -1.

Perpendicular to y=-1/6x+5

Slope of - 1/6, so:

[tex]-\frac{1}{6}m = -1[/tex]

[tex]m = 6[/tex]

So

[tex]y - y_0 = 6(x - x_0)[/tex]

Passes through the point (-3,-8).

This means that [tex]x_0 = -3, y_0 = -8[/tex]. So

[tex]y - y_0 = 6(x - x_0)[/tex]

[tex]y - (-8) = 6(x - (-3))[/tex]

[tex]y + 8 = 6(x + 3)[/tex]

mass = force / area

this is second law of motion ( Newton's 2nd law)

[tex]\longrightarrow{\blue{ m = \frac{F}{a} }}[/tex] 

[tex]\large\mathfrak{{\pmb{\underline{\red{Explanation}}{\red{:}}}}}[/tex]

F = ma

➺ m = [tex]\frac{F}{a} [/tex]

where,

F = Force

m = mass

a = acceleration

"F = ma" is Newton's second law of motion, which states that force is equal to mass times acceleration.

The SI unit of force is newton, symbol N.

[tex]\bold{ \green{ \star{ \orange{Mystique35}}}}⋆[/tex]

Answer:

In explanation

Please let me know if something doesn't make sense.

Step-by-step explanation:

a)

*This relation is not reflexive.

0 is an integer and (0,0) is not in the relation because 0(0)>0 is not true.

*This relation is symmetric because if a(b)>0 then b(a)>0 since multiplication is commutative.

*This relation is transitive.

Assume a(b)>0 and b(c)>0.

Note: This means not a,b, or c can be zero.

Therefore we have abbc>0.

Since b^2 is positive then ac is positive.

Since a(c)>0, then (a,c) is in R provided (a,b) and (b,c) is in R.

*The relation is not antisymmretric.

(3,2) and (2,3) are in R but 3 doesn't equal 2.

b)

*This relation is reflective.

Since a^2=a^2 for any a, then (a,a) is in R.

*The relation is symmetric.

If a^2=b^2, then b^2=a^2.

*The relation is transitive.

If a^2=b^2 and b^2=c^2, then a^2=c^2.

*The relation is not antisymmretric.

(1,-1) and (-1,1) is in the relation but-1 doesn't equal 1.

c)

*The relation is reflexive.

a/a=1 for any a in the naturals.

*The relation is not symmetric.

Wile 4/2 is an integer, 2/4 is not.

*The relation is transitive.

If a/b=z and b/c=y where z and y are integers, then a=bz and b=cy.

This means a=cyz. This implies a/c=yz.

Since the product of integers is an integer, then (a,c) is in the relation provided (a,b) and (b,c) are in the relation.

*The relation is antisymmretric.

Assume (a,b) is an R. (Note: a,b are natural numbers.) This means a/b is an integer. This also means a is either greater than or equal to b. If b is less than a, then (b,a) is not in R. If a=b, then (b,a) is in R. (Note: b/a=1 since b=a)

Answer:

The 98% confidence interval to estimate the proportion of watermelon seeds that germinate is (0.4443, 0.6557). This means that we are 98% sure that the true proportion of all watermalong seeds of the company that germinate is between these two values, which means that there is good evidence that the proportion is below the 70% standard.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which

z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].

Once a week for 12 weeks, he purchases a pack of 10 watermelon seeds to act as his sample. He plants the seeds in a greenhouse with good soil to maintain a consistent temperature and watering routine. He finds that the germination rate for the company's watermelon seeds is 55%.

This means that [tex]n = 12*10 = 120, \pi = 0.55[/tex]

98% confidence level

So [tex]\alpha = 0.02[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.02}{2} = 0.99[/tex], so [tex]Z = 2.327[/tex].

The lower limit of this interval is:

[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.55 - 2.327\sqrt{\frac{0.55*0.45}{120}} = 0.4443[/tex]

The upper limit of this interval is:

[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.55 + 2.327\sqrt{\frac{0.55*0.45}{120}} = 0.6557[/tex]

The 98% confidence interval to estimate the proportion of watermelon seeds that germinate is (0.4443, 0.6557). This means that we are 98% sure that the true proportion of all watermalong seeds of the company that germinate is between these two values, which means that there is good evidence that the proportion is below the 70% standard.

Step-by-step explanation:

[tex] \frac{1}{3 } \times \frac{30}{1} = 10 \\ \\ \frac{10}{1} \times \frac{5}{6} = 8.33 \\ \\ \frac{833}{100} \times \frac{6}{10} = 4.998 \\ \\ \frac{4998}{1000} \times \frac{12}{1} = 59.976[/tex]

Hope this might help you (•.•) :)