Answer:
Laterite is your correct answer
Explanation:
Well i took the quiz and made a %100 meaning i am correct.
The laterite soil is found in warm, humid climates
What are Laterite soil?A variety of rocks weathered under highly oxidising and leaching circumstances to form laterite soil, which is present in the soil layer and is rich in iron oxide.
Given data ,
Let the soil be represented as A
Now , the soil is found in warm, humid climates
The laterite soil is is rich in iron and aluminium, are assumed to have developed in hot, humid tropical climes. Because to the substantial concentration of iron oxide, nearly all laterites have a rusty-red colour.
They develop as a result of prolonged, intensive erosion of the underlying rock material, which most frequently takes place during periods of high temperatures and heavy precipitation that alternate with periods of dry weather.
Hence , Laterite is the type of soil is found in warm, humid climates.
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How bones do humans have ??
Answer:
206
Explanation:
The axial skeleton, comprising the spine, chest and head, contains 80 bones. The appendicular skeleton, comprising the arms and legs, including the shoulder and pelvic girdles, contains 126 bones, bringing the total for the entire skeleton to 206 bones.
A fully grown adult features 26 bones in the spine, whereas a child can have 34.
Answer:
The human body is made up of 206 bones
whenever velocity increases the kinetic energy will ?
Answer:
It will increase.
Explanation:
Because kinetic energy is proportional to the square of the velocity, when velocity is doubled, kinetic energy is quadrupled. Kinetic energy K=mv^2/2
A 12-kg sled is moving at a speed of 3.0 m/s. At which of the following speeds will the sled have twice as much kinetic energy?
What does "the following" mean ?
Kinetic energy is directly proportional to speed² .
So kinetic energy doubles if the speed is increased by √2 .
(3 m/s) · (√2) = 4.243 m/s
HELP FAST
How did the lab activities help you answer the lesson question, "How do atmospheric conditions influence weather patterns?" What did you learn from conducting this lab?
Answer:
not enough
Explanation:
information given
Answer:
Sample Response: In the lab, I discovered the air pressure, air temperature, and relative humidity conditions that create snow, rain, thunderstorms, fog, and clear skies. I learned that low-pressure areas usually experience snowy, rainy, and stormy weather, and that high-pressure areas usually experience either foggy or sunny weather. Knowing how these atmospheric conditions influence weather help weather forecasters predict weather patterns through maps and other information.
(Sorry this was not fast enough )
A student in your class whom you kind-of like asks you come to watch a meteor shower. What exactly are you being invited to? a. something your mom would not approve of, involving streams of dirty water b. the closest approach of an active bright comet to the Earth c. a once-in-a-lifetime experience at the end of which you will be completely covered with dust particles from space d. watching the left-over dirt from a comet burn up by friction as the pieces hit the Earth's atmosphere e. something quite dangerous where you are likely to be hit when many larger rocks fall from above Submit Your Answer
Answer:D. Watching the left-over dirt from a comet burn up by friction as the pieces hit the Earth's atmosphere
Explanation: A meteor shower is giant rocks moving across the sky
There must be an invitation for d. watching the left-over dirt from a comet burn up by friction as the pieces hit the Earth's atmosphere
What is a Meteor showers ?
Meteor showers occur when dust or particles from asteroids or comets enter Earth's atmosphere at very high speed. When they hit the atmosphere, meteors rub against air particles and create friction, heating the meteors. The heat vaporizes most meteors, creating what we call shooting stars
hence correct option will be D) Watching the left-over dirt from a comet burn up by friction as the pieces hit the Earth's atmosphere
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Sheila weighs 60 kg and is riding a bike. Her momentum on the bike is 340 kg • m/s. The bike hits a rock, which stops it completely and throws Sheila forward onto the pavement. If there is no net force on the system, what is Sheila's velocity immediately after she is thrown from the bike? 1.8 m/s 2.0 m/s 5.0 m/s 5.7 m/s
Answer:
v₂ = 5.7 m/s
Explanation:
We will apply the law of conservation of momentum here:
[tex]Total\ Initial\ Momentum = m_{1}v_{1} + m_{2}v_{2}\\[/tex]
where,
Total Initial Momentum = 340 kg.m/s
m₁ = mass of bike
v₁ = final speed of bike = 0 m/s
m₂ = mass of Sheila = 60 kg
v₂ = final speed of Sheila = ?
Therefore,
[tex]340\ kg.m/s = m_{1}(0\ m/s) + (60\ kg)v_{2}\\v_{2} = \frac{340\ kg.m/s}{60\ kg}\\\\[/tex]
v₂ = 5.7 m/s
Answer:
5.7 I got it right on edg 2021
Explanation:
Perform an experiment in which you compress a bar of steel 0.004 mm. Write
this measurement in scientific notation.
O A. 4.0 x 103 mm
O B. 4.0 x 104 mm
C. 4.0 x 10-4 mm
O D. 4.0 x 103 mm
Which may result from an increase in friction?
decreased traction
increased speed
reduced wear and tear
generation of heat
Answer:
The Answer is B: to provide traction so that slipping does not occur
Explanation:
if it is wrong please correct me
Does anybody know the formula needed to calculate distance given the values for mass, power, and time?
Answer:
Joules/second^2=(Newton×meter)/second^2.
Solving for mass: Kg= (second^3/ meter^2).
In an example food chain, mice only eat plants, and then snakes eat the mice. These snakes are examples of consumers.
a Quaternary
b Primary
c Secondary
d Tertiary
hiii pls help i’ll give brainliest thank you
Answer:
friction force
Explanation:
friction forces a force that opposed the relative motion of two bodies in contact or when sliding
An electric motor turns a flywheel through a drive belt that joins a pulley on the motor and a pulley that is rigidly attached to the flywheel. The flywheel is a solid disk with a mass of 70.5 kg and a diameter of 1.25 m. It turns on a frictionless axle. Its pulley has much smaller mass and a radius of 0.230 m. If the tension in the upper (taut) segment of the belt is 165 N, and the flywheel has a clockwise angular acceleration of 1.67 rad/s2, find the tension in the lower (slack) segment of the belt.
Answer:
The tension on the slack segment of the belt is 65 N
Explanation:
The given parameters are;
The mass of the solid disk = 70.5 kg
The diameter of the flywheel disk, D = 1.25 m
The radius of the pulley = 0.230 m
If the tension in the upper segment of the belt = 165 N
The angular acceleration of the flywheel = 1.67 rad/s²
The moment of inertia of a circular disc, I = 1/2·M·r²
The radius of the flywheel, r = D/2 = (1.25 m)/2 = 0.625 m
The moment of inertia of the flywheel, I = 1/2 × 70.5 kg × (0.625 m)² = 13.7695312 m²·kg
The moment of inertia, I = 13.7695312 m²·kg
Torque, τ = Moment of Inertia, I × Angular acceleration, α
Torque, τ = I × α
τ = 13.7695312 m²·kg × 1.67 rad/s² = 22.9951171 N·m ≈ 23 N·m
The torque applied from the pulley side is given as follows;
Let [tex]T_{slk}[/tex] represent the tension on the slack segment of the belts, we have;
23 N·m = (165 N - [tex]T_{slk}[/tex]) × 0.230 m
∴ 165 N - [tex]T_{slk}[/tex] = 23 N·m/0.230 m = 100 N
[tex]T_{slk}[/tex] = 165 N - 100 N = 65 N
The tension on the slack segment of the belt, [tex]T_{slk}[/tex] = 65 N
The tension on the slack segment of the belt is 65 N
What is flywheel?flywheel, heavy wheel attached to a rotating shaft so as to smooth out delivery of power from a motor to a machine. The inertia of the flywheel opposes and moderates fluctuations in the speed of the engine and stores the excess energy for intermittent use.
The given parameters are;
The mass of the solid disk = 70.5 kg
The diameter of the flywheel disk, D = 1.25 m
The radius of the pulley = 0.230 m
If the tension in the upper segment of the belt = 165 N
The angular acceleration of the flywheel = 1.67 rad/s²
The moment of inertia of a circular disc, I = 1/2·M·r²
The radius of the flywheel, r = D/2 = (1.25 m)/2 = 0.625 m
Now we will calculate tension on the slack side
The moment of inertia of the flywheel,
[tex]I = \dfrac{1}{2} \times 70.5 kg \times (0.625 m)^2 = 13.7695312 \ m^2 \ kg[/tex]
The moment of inertia, I = 13.7695312 m²·kg
Torque, τ = Moment of Inertia, I × Angular acceleration, α
Torque, τ = I × α
τ = [tex]13.7695312 \times 1.67 = 22.9951171 Nm = 23 Nm[/tex]
The torque applied from the pulley side is given as follows;
Let represent the tension on the slack segment of the belts, we have;
23 N·m = (165 N - ) × 0.230 m
∴ 165 N - = 23 N·m/0.230 m = 100 N
= 165 N - 100 N = 65 N
The tension on the slack segment of the belt, = 65 N
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A 12 kg object has a velocity of 37.5 m/s. What is its momentum
Answer:
Solution:
Explanation:
Here, mass of body ( m)=12kg.
velocity (v)=37.5 m/s. momentum = mass× velocity = 12kg×37.5m/s =450kgm/s ans.
what happens to our bodies if we do not eat nutritious meals? give three reasons.
3 things that happen to our body when we don't eat nutritious meals:
1. It can lead to bad eating habits that may cause obesity or diabetes
2. It can also cause heart disease and cancer
3. it can also make you more tired, and may contribute to stress.
Poor nutrition can contribute to stress, tiredness and our capacity to work, and over time. It can contribute to the risk of developing some illnesses and other health problems such as being overweight or obese.
Hope this helps; have a great day!
Three equal charge 1.8*10^-8 each are located at the corner of an equilateral triangle ABC side 10cm.calculate the electric potential due to these charge at the mid point of AB
Answer:
If all these three charges are positive with a magnitude of [tex]1.8 \times 10^{-8}\; \rm C[/tex] each, the electric potential at the midpoint of segment [tex]\rm AB[/tex] would be approximately [tex]8.3 \times 10^{3}\; \rm V[/tex].
Explanation:
Convert the unit of the length of each side of this triangle to meters: [tex]10\; \rm cm = 0.10\; \rm m[/tex].
Distance between the midpoint of [tex]\rm AB[/tex] and each of the three charges:
[tex]d({\rm A}) = 0.050\; \rm m[/tex].[tex]d({\rm B}) = 0.050\; \rm m[/tex].[tex]d({\rm C}) = \sqrt{3} \times (0.050\; \rm m)[/tex].Let [tex]k[/tex] denote Coulomb's constant ([tex]k \approx 8.99 \times 10^{9}\; \rm N \cdot m^{2} \cdot C^{-2}[/tex].)
Electric potential due to the charge at [tex]\rm A[/tex]: [tex]\displaystyle \frac{k\, q}{d({\rm A})}[/tex].
Electric potential due to the charge at [tex]\rm B[/tex]: [tex]\displaystyle \frac{k\, q}{d({\rm B})}[/tex].
Electric potential due to the charge at [tex]\rm A[/tex]: [tex]\displaystyle \frac{k\, q}{d({\rm C})}[/tex].
While forces are vectors, electric potentials are scalars. When more than one electric fields are superposed over one another, the resultant electric potential at some point would be the scalar sum of the electric potential at that position due to each of these fields.
Hence, the electric field at the midpoint of [tex]\rm AB[/tex] due to all these three charges would be:
[tex]\begin{aligned}& \frac{k\, q}{d({\rm A})} + \frac{k\, q}{d({\rm B})} + \frac{k\, q}{d({\rm C})} \\ &= k\, \left(\frac{q}{d({\rm A})} + \frac{q}{d({\rm B})} + \frac{q}{d({\rm C})}\right) \\ &\approx 8.99 \times 10^{9}\; \rm N \cdot m^{2} \cdot C^{-2} \\ & \quad \quad \times \left(\frac{1.8 \times 10^{-8} \; \rm C}{0.050\; \rm m} + \frac{1.8 \times 10^{-8} \; \rm C}{0.050\; \rm m} + \frac{1.8 \times 10^{-8} \; \rm C}{\sqrt{3} \times (0.050\; \rm m)}\right) \\ &\approx 8.3 \times 10^{3}\; \rm V\end{aligned}[/tex].
Write a paragraph describe the desert biome
Answer:
The desert biome is an ecosystem that forms due to the low level of rainfall it receives each year. Deserts cover about 20% of the Earth. There are four major types of desert in this biome - hot and dry, semiarid, coastal, and cold. They are all able to inhabit plant and animal life that are able to survive there. Although the daytime temperatures of the desert biome are very hot, they can get very cold at night. The Sahara Desert is the largest desert in the desert biome. It covers over 300 million square miles.
Explanation:
Answer all of these questions and you will get the brainlist
3. What happens when you get a large number of magnetic domains aligned?
a strong magnet
a weak magnet
a non-magnetic material
HELP!!!!!!!!
When a large number of magnetic domains are aligned, a strong magnet produces more magnetic attraction compared to a weak magnet and non-magnetic material.
What is magnetic induction?
Magnetic induction occurs when a magnetic field is used to magnetize another object.
This process occurs when the magnetic domains are aligned in the same direction, which causes the object become magnetized in that direction, thereby forming a magnet.
Thus, when a large number of magnetic domains are aligned, a strong magnet produces more magnetic attraction compared to a weak magnet and non-magnetic material.
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A disk 7.90 cm in radius rotates at a constant rate of 1 190 rev/min about its central axis. (a) Determine its angular speed. 124.58 Correct: Your answer is correct. rad/s (b) Determine the tangential speed at a point 2.98 cm from its center. 3.71 Correct: Your answer is correct. m/s (c) Determine the radial acceleration of a point on the rim. magnitude 1.23 Correct: Your answer is correct. km/s2 direction toward the center Correct: Your answer is correct. (d) Determine the total distance a point on the rim moves in 2.06 s. 20.28 Correct: Your answer is correct. m
Answer:
[tex]124.62\ \text{rad/s}[/tex]
[tex]3.71\ \text{m/s}[/tex]
[tex]1.23\ \text{km/s}^2[/tex]
[tex]20.28\ \text{m}[/tex]
Explanation:
r = Radius of disk = 7.9 cm
N = Number of revolution per minute = 1190 rev/minute
Angular speed is given by
[tex]\omega=N\dfrac{2\pi}{60}\\\Rightarrow \omega=1190\times \dfrac{2\pi}{60}\\\Rightarrow \omega=124.62\ \text{rad/s}[/tex]
The angular speed is [tex]124.62\ \text{rad/s}[/tex]
r = 2.98 cm
Tangential speed is given by
[tex]v=r\omega\\\Rightarrow v=2.98\times 10^{-2}\times 124.62\\\Rightarrow v=3.71\ \text{m/s}[/tex]
Tangential speed at the required point is [tex]3.71\ \text{m/s}[/tex]
Radial acceleration is given by
[tex]a=\omega^2r\\\Rightarrow a=124.62^2\times 7.9\times 10^{-2}\\\Rightarrow a=1226.88\approx 1.23\ \text{km/s}^2[/tex]
The radial acceleration is [tex]1.23\ \text{km/s}^2[/tex].
t = Time = 2.06 s
Distance traveled is given by
[tex]d=vt\\\Rightarrow d=\omega rt\\\Rightarrow d=124.62\times 7.9\times 10^{-2}\times 2.06\\\Rightarrow d=20.28\ \text{m}[/tex]
The total distance a point on the rim moves in the required time is [tex]20.28\ \text{m}[/tex].
A 80-kilogram rack star performs a workout preparing for a pole vault competition. The athlete starts from a rest on a horizontal surface and uniformly accelerates towards the bar at a top speed of 8.0 meters per second. The athlete sticks the pole into the ground and travels a vertical height of 5.7 meters and just clears the bar. Calculate the work done by friction by the athlete during the vault
Answer:
athlete W = 2560 J
roce W_{fr} = - 2560 J
Explanation:
For this exercise we can use the relationship between work and kinetic energy
W = ΔK
W = K_f -K₀
as the bearing of rest its v₀ = 0 and the final velocity is v = 8 m / s
athlete's job is
W = ½ m [tex]v_{f}^2[/tex] - 0
let's calculate
W = ½ 80 8²
W = 2560 J
For the work of the friction force let us use that since the athlete goes at constant speed, they relate it to zero, therefore the forces are in equilibrium
∑F = 0
F- fr = 0
F = fr
Therefore, the magnitude of the friction force is equal to the force applied by the athlete, as the friction force always has the opposite direction to the movement, its work is
W_{fr} = - W_{atlete}
W_{fr} = - 2560 J
A weight - lifter lifts a bell weighing 2 000 N and holds it in the air for 5 seconds. Has he done any work? Explain your answer.
Answer:
No, he hasn't done any work.
Explanation:
In this scenario, the weightlifter hasn't done any work because even though he lifted the bell for a specific period of time, he didn't cover any distance.
Mathematically, work done is given by the formula;
Work done = force * distance
[tex] W = F * d[/tex]
Where,
W is the work done
F represents the force acting on a body.
d represents the distance covered by the body.
Power can be defined as the energy required to do work per unit time.
Mathematically, it is given by the formula;
[tex] Power = \frac {Energy}{time} [/tex]
work and power!!
____is the measure of how much work, energy, or power is used or converted properly. Efficiency C Power b Newton d. Horsepower
Answer:
Efficiency
Explanation:
A penguin swimming underwater goes 20 meters in 5 seconds. What is its average speed?
Answer:
4 meters per second
Explanation:
A stone of mass 0.2kg is thrown vertically upwards from the ground with a velocity of 20m/s. Find the maximum height attained by the stone
Answer: 20.4 m
Explanation: speed v upward is v = vo -gt.
When maximum height v = 0, vo -gt = 0 and
T = vo / g = 20 m/s / 9.81 m/s² = 2.04 s
Now height y = vot -0.5 gt^2 = 20,4 m
This is possible to solve using
Conservation of energy Ek= Ep
0.5mv² = mgh. And h = v²/2g. Results same
Will most likely cause the formation of a Mountain
A. Divergent boundary
B. Convergent boundary
C. Transform boundary
Answer:
Convergent boundaries. When two plates collide and one is pushed over the other, forming a mountain.
PLZ HELP ILL GIVE BRAINLIEST
Answer:
x10 - 6 +(8+6-4)= 10
10m -10x y0
An object carries a +15.5 µC charge. It is 0.525 m from a -7.25 µC charge. What is the magnitude of the electric force on the object?
Answer:
the force of attraction between the two charges is 3.55 N.
Explanation:
Given;
first charge carried by the object, q₁ = 15.5 µC
second charge carried by the q₂ = -7.25 µC
distance between the two charges, r = 0.525 m
The force of attraction between the two charges is calculated as;
[tex]F = \frac{kq_1q_2}{r^2} \\\\F = \frac{(9\times 10^9)(15\times 10^{-6})(7.25\times 10^{-6})}{(0.525)^2} \\\\F = 3.55 \ N[/tex]
Therefore, the force of attraction between the two charges is 3.55 N.
which of the following is the best definition for homestasis
A property of cells, tissues, and organisms that allows the maintenance and regulation of the stability and constancy needed to function properly. Homeostasis is a healthy state that is maintained by the constant adjustment of biochemical and physiological pathways.
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how do you find the focal length of an lens experimentally
Answer:
Place the convex lens on a 'V' stand. . ii) Light a candle and take it far away from the lens along the principal axis. iii) Adjust the screen on the other side of the lens to get a clear image on it. iv) Measure the distance between the 'V' stand and the screen which gives a rough idea of the focal length of the lens.
Which stretch focuses on stretching the glutes and hamstrings while laying on your back?
Question 4 options:
Knee to hip
Bent knee
Knee to Chest
Chest flies
tyyyyyyyy
Answer:
knee to chest
Explanation:
I took the test
Answer:
C. Knee to chest.