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Answer:

We're like children who move away from their parents - then back,

HUMANS LOVE to travel. Mentally or physically, they escape to other places. They crave adventure. They seek the unknown. They want to see new places, learn new things, enjoy new experiences and then return home to the familiar, the predictable, the secure, before taking off again on their travels.

This departure-return behaviour has its origins, perhaps, in the early exploratory behaviour of the child. Research has shown that children who are "securely attached" to their parents, sure of their affection and protection, and who know that their parents will respond to their needs, are more independent, adventurous and exploratory in their play and behaviour.

Observations of infants show that from the safe base of having a parent present and available, the infant dares to move away a short distance and then return to the parent, to move a little further and return, until in incremental and amazingly measurable distances it explores the environment that surrounds it and has the courage to move beyond it.

This may be the first symbolic travel: the first departure, the first expedition and the possible beginning of the travel bug for those for whom their initial independent voyaging was successful.

With these first independent steps away from the parental presence lies the atavistic or recurring wish to reach out beyond the current confines of space and relationship

and see what is further away. And yet further again to see what is not visible, what is around the next corner, in the next room and eventually on

the other side of our geographical or psychological world. This is a human need. It is why we have uncovered our world, travelled its length, hiked to the top of its mountains and the depth of its oceans. It is why we became discontent with exploring our own plant but had to move beyond it into the unknown. It is why, as poet TS Eliot reminds us, we will "not cease from exploration".

It is our nature to travel. It is our joy to travel. It is our paradoxical psychological disposition to wish for the contradictory conditions of stability and change: to stay and to go, to be and to explore, to rest and to travel unceasingly.

Travel is more than going somewhere. It is a psychological event. It requires motivation and imagination. It begins in childhood with faltering first steps and with imagination fired by the tales of "long, long ago in a faraway land".

We emerge from these fantasies of childhood determined to cross the oceans, to find those faraway lands, the characters they containand the magic they hold. Determined to find the adventures they promise and the prospect of returning home triumphant with trophies having vanquished all fear, overcome all obstacles and live happily eve after.

Answer:

to see the world and experience new things. it opens your mind and you can meet more people. you have a new view on the world after seeing it from other places, not only new views on the world but new cultures, and languages.

Explanation:

Answer:

5m

Explanation:

Whenever Two or more than two waves get to the same point/place, and they arrive at the same time, then there will be "superimposition" onto one another. Then there would be corresponding of each disturbance to a Amplitude or force, and since these disturbance maintain same line, "THEN THE RESULTING WAVE WILL BE THE ADDITION OF THE AMPLITUDE"

Superposition can be explained as the action that takes place as a result of two waves occupying same point.

To find the waves at this point, then " THE AMPLITUDE WILL BE ADDED TOGETHER"

Given:

Amplitude of first wave= 2.5m

Amplitude of second wave= 2.5m

The resulting wave will have an amplitude of(2.5m + 2.5m)=5.0m

Hence, The resulting wave has an amplitude of 5.0m

Answer:

The answer is below

Explanation:

A vector quantity is a quantity that has both magnitude and direction. The magnitude of a vector is the length of that vector.

The magnitude of a vector a with a x component of x and y component of y is given by the formula:

[tex]|a|=\sqrt{x^2+y^2}[/tex]

Given that the vector has a magnitude of √8, the x component is 2 and the y component = y. Hence:

[tex]\sqrt{8}=\sqrt{2^2+y^2}\\\\squaring\ both\ sides:\\\\8=4 + y^2\\\\y^2=8-4\\\\y^2=4\\\\square\ root\ of\ both\ sides:\\\\y=\sqrt{4} \\\\y=\pm 2\\\\y=+2\ or\ y=-2[/tex]

Answer:

Explanation:

The potential energy of a body can be found by using the formula

PE = mgh

where

m is the mass

h is the height

g is the acceleration due to gravity which is 10 m/s²

From the question we have

PE = 1.5 × 10 × 0.22

We have the final answer as

Hope this helps you

Answer:

[tex]a=2.4\ m/s^2[/tex]

Explanation:

Given that,

Initial speed of a car, u = 13 m/s

Final speed of a car, v = 25 m/s

Time, t = 5 s

We need to find the acceleration of the car during this 5.0 second time interval. Let a is the acceleration. It can be calculated as :

[tex]a=\dfrac{v-u}{t}\\\\a=\dfrac{25-13}{5}\\\\=2.4\ m/s^2[/tex]

So, the acceleration of the car is [tex]2.4\ m/s^2[/tex].

Explanation:

Ribosomes are not quite the same as different organelles since they have no layer around them that isolates them from different organelles, they comprise of two subunits, and when they are creating sure proteins they can become film bound to the endoplasmic reticulum, however they can likewise be free drifting while at the same time performing

Answer:

0.5625 Joules

Explanation:

The equation to calculate kinetic energy is:

[tex]KE = \frac{1}{2}mv^2[/tex]

So, plug in all given info and calculate:

[tex]KE = \frac{1}{2}(0.5)(1.5)^2 = 0.5625J[/tex]

And that's your answer! :)

Answer:

10m/s

Explanation:

Answer:

3500joules of work

Explanation:

Work done = Force×,distance

Given

Focrce= mass ,× acceleration = 140×10 = 1400N

Distance moved = 2.5m

Workdone = 1400×2.5

Work done = 140×25

Workdone = 3500Joules

Answer:

25J

Explanation:

Given parameters:

Mass of the dog  = 10kg

Speed of the dog  = 5m/s

Unknown:

The minimum energy required to stop the dog  = ?

Solution:

The dog is moving with a kinetic energy and to stop the dog, an equal amount of kinetic energy generated must be applied to the dog.

 To find the kinetic energy;

        K.E  = [tex]\frac{1}{2}[/tex] m v²

m is the mass

v is the velocity

Now insert the parameters and solve;

      K.E  =  [tex]\frac{1}{2}[/tex]  x 10 x 5  = 25J

Answer:

The donkey might be dead

Answer: 321.027 m/s

Explanation:

First let´s analyze the vertical problem:

Always when an object is above the ground and nothing is holding it (like the bullet after being fired) the gravitational force will start acting on it.

Then the vertical acceleration of the bullet will be the gravitational acceleration, we can write this as:

a(t) = -g

Where g = 9.8m/s^2

and the negative sign is because this acceleration pulls the bullet downwards.

To get the vertical velocity we need to integrate over time, this will lead to:

v(t) = (-9.8m/s^2)*t + v0

where v0 is the initial vertical velocity, as the bullet is fired horizontally, there is no initial vertical velocity, then we have v0 = 0m/s

And the velocity equation is:

v(t) = (-9.8m/s^2)*t

Now for the vertical position, we need to integrate again, to get:

p(t)  =(1/2)*(-9.8m/s^2)*t^2 + p0

Where p0 is the initial vertical position, in this case, is 1.9 meters above the ground, then p0 = 1.9m

And the vertical position equation will be:

p(t) = (1/2)*(-9.8m/s^2)*t^2 + 1.9 m

Now we want to find the time such that the vertical position is equal to zero, this will mean that the bullet it the ground.

p(t) = 0m = (1/2)*(-9.8m/s^2)*t^2 + 1.9 m

    (1/2)*(9.8m/s^2)*t^2 = 1.9m

    (4.9m/s^2)*t^2 = 1.9m

                  t = √(1.9m/(4.9m/s^2)) = 0.623 seconds.

This means that the bullet will travel for 0.623 seconds before hitting the ground.

Now we also can ignore the air friction for the horizontal motion, then we can assume that the horizontal speed does not change.

Then we can use the relationship:

Distance = speed*time

We know that:

time = 0.623 seconds

distance = 200m

now we can replace that in the equation to find the horizontal speed.

200m = speed*0.623s

200m/0.623s = speed = 321.027 m/s

Answer:

the SI unit of work or energy, equal to the work done by a force of one newton when its point of application moves one meter in the direction of action of the force, equivalent to one 3600th of a watt-hour.

Explanation:

Joule, unit of work or energy in the International System of Units (SI); it is equal to the work done by a force of one newton acting through one metre. Named in honour of the English physicist James Prescott Joule, it equals 107 ergs, or approximately 0.7377 foot-pounds.

Answer:

Explanation:

a gravitational field is the region of space surrounding a body in which another body experiences a force of gravitational attraction.

The formula is: weight/mass = gravitational field strength. On Earth the gravitational field strength is 10 N/kg.

an example of how you can use it if you need to find the gravitational force from earth.

Explanation:

id : 237 514 2470

pass : frmCV5

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I am boy :)

Answer:

a. s = 0.96 m

b. s = 2.15 m

Explanation:

a.

The relationship between the linear displacement and the angular displacement is given as follows:

[tex]s = r\theta[/tex]

where,

s = linear distance covered = ?

r = radius of wheel = (6 in)(0.0254 m/1 in) = 0.1524 m

θ = angular displacement = (1 rev)(2π rad/1 rev) = 2π rad

Therefore,

[tex]s = (0.1524\ m) 2\pi[/tex]

s = 0.96 m

b.

Assuming, we have to find linear displacement here, as well:

[tex]s = r\theta[/tex]

where,

s = linear distance covered = ?

r = radius of wheel = (13.5 in)(0.0254 m/1 in) = 0.3429 m

θ = angular displacement = (1 rev)(2π rad/1 rev) = 2π rad

Therefore,

[tex]s = (0.3429 \ m) 2\pi[/tex]

s = 2.15 m

Answer:

v₃ = 2 [m/s]

Explanation:

To solve such problems we must use the principle of conservation of momentum. That is, the linear momentum is conserved before and after the collision.

P = m*v

where:

P = linear momentum [kg*m/s]

m = mass [kg]

v = velocity [m/s]

The momentum is conserved before and after the collision, in this way we can obtain the following equation.

[tex](m_{1}*v_{1})+(m_{2}*v_{2})=(m_{1}+m_{2})*v_{3}[/tex]

where:

m₁ = mass of the cart moving = 4 [kg]

v₁ =  velocity of the cart moving before the collision = 3 [m/s]

m₂ = mass of the cart initially at rest = 2 [kg]

v₂ = velocity of the cart at rest = 0

v₃ = velocity of the two carts combined (carts stick together) after the collision [m/s]

[tex](4*3)+(2*0)=(4+2)*v_{3}\\v_{3}=12/6\\v_{3}=2[m/s][/tex]

can tigger sudden mass movement

Answer:

69.44kJ

Explanation:

Kinetic energy is expressed as;

KE = 1/2mv^2

m is the mass = 500kg

v is the velocity

Get the velocity;

v = displacement/time

velocity = 2000/120

velcoity = 16.7m/s

Gt the kinetic energy

KE = 1/2 * 500 * 16.7²

KE = 250*277.78

KE = 69,444.4Joules

Since 1000J = 1kJ

69,444.4Joules = 69,444.4/1000

69,444.4Joules = 69.44kJ

Hence the Secretariat's average kinetic energy is  69.44kJ

Answer:C 69.0kJ

Explanation:

Answer:

It is that kind of permeable membrane that allows certain molecules to pass through. Not every molecules can pass through it

Explanation:

1: 15m

2: 56m/s

3: 34.5m

Sorry if these are incorrect.

Answer:

Anything in an experiment that remains unchanged.

Explanation:

An example could be the temperature of the laboratory room. If there is something that has an effect on an experiment that is not variable, it is a constant. Another constant could be, say, if you were doing calculations with the same amount and kind of fluid throughout the experiment, then that fluid would also be a constant.

I believe the correct answer is atmosphere (D).

Answer:

D) atmosphere

Explanation:

but the correct answer is troposhare

Answer:

4.9949

Explanation:

M = 3 kg

P.E = 147 joules

G = 9.81 ms^-2

H = ?

P.E = MGH

147 = 3 x 9.81 x H

147 = 29.43H

147/29.43 = 29.43H/29.43

4.9949 = H

:. H = 4.9949

Answer:

The time taken to reach the maximum height is 3.20 seconds

Explanation:

The given parameters are;

The initial height from which the volcano erupts the lava bomb = 64.4 m

The initial upward velocity of the lava bomb = 31.4 m/s

The acceleration due to gravity, g = 9.8 m/s²

The time it takes the lava bomb to reach its maximum height, t, is given by the following kinematic equation as follows;

v = u - g·t

Where;

v = The final velocity  = 0 m/s at maximum height

u = The initial velocity = 31.4 m/s

g = The acceleration due to gravity = 9.8 m/s²

t = The time taken to reach the maximum height

Substituting the values gives;

0 = 31.4 - 9.8 × t

∴ 31.4 = 9.8 × t

t = 31.4/9.8  ≈ 3.204

The time taken to reach the maximum height rounded to three significant figures = t ≈ 3.20 seconds

Answer:

Dead sea is full of salt.

Explanation:

The water of the Dead Sea is full of salt, which makes it much denser and heavier than freshwater. If you swim in it, you float very easily.

When salt is dissolved in water, for example sea water, dissolved salt adds to the mass of the water and makes the water denser than it would be without salt. Because objects float better on a dense surface, they float better on salt water than fresh water.

Answer:

The correct option is;

b. 7.94 m

Explanation:

The given parameters of the jump of the long jumper are;

The angle above the horizontal with which the long jumper leaves the ground, θ = 20.0°

The speed with which the long jumper leaves the ground, u = 11.0 m/s

The furthest horizontal distance the long jumper jumps, given that the motion is equivalent to that of a particle, is given by the formula for the range, R, of a projectile motion as follows;

[tex]R = \dfrac{u^2 \times sin \left (2 \cdot \theta \right )}{g}[/tex]

Where;

g = The acceleration due to gravity ≈ 9.8 m/s²

u = The initial velocity of the long-jumper = 11.0 m/s

θ = The angle of the direction above the horizontal the long-jumper jumps = 20.0°

Plugging in the values, gives;

[tex]R = \dfrac{(11.0 \ m/s)^2 \times sin \left (2 \times 20.0 ^{\circ} \right )}{9.8} = \dfrac{121 \ m^2/s^2 \times sin \left (40.0 ^{\circ} \right )}{9.8 \ m/s^2} \approx 7.94 \ m[/tex]

How far the long-jumper goes = The range, R, of the projectile motion ≈ 7.94 m.

Answer:

Although the weight is given and we are asked for the weight, the odd wording of the question implies that we are being asked for the gravitational force on the backpack.

If it is gravitational force that is being requested, then the correct answer is A) 41.16 Newtons.

If it is actual weight being asked for, then none of the answers are correct, as the weight of 4.2 kg is given in the question, and does not match any of the answers.

Answer:

Q = 2250 Coulombs

Explanation:

We are given;

Current: I = 2.5 A

Time: t = 15 minutes = 15 × 60 seconds = 900 s

Now formula for the amount of charge through the circuit is given by:

Q = It

Thus;

Q = 2.5 × 900

Q = 2250 Coulombs

Answer:

it's 220 J

the second one