This interaction is not possible in nature because it violates a conservation law. Which quantity is not conserved?
p+ e-+ --> π+n+ve

Answer:

1. The day-to-day conditions of the atmosphere at a place with respect to elements like humidity, temperature, wind speed, rainfall, etc. is called the weather of that place.

2. Weather can be cloudy, sunny, rainy, stormy or clear. It is a part of the natural phenomenon which maintains the equilibrium in the atmosphere.

3. But conditions can be worse sometimes. When the atmospheric conditions are extreme or intense enough to cause property loss or life loss, such weather is termed as severe weather.

4. These also vary according to the altitudes, latitudes, and region and pressure differences. Tornadoes, cyclones, heavy rainfall, fog, winter storms come under this category. They are disastrous and hazardous. Proper disaster management and strategies are required to handle these conditions.

Recall that

v² - u² = 2 a ∆x

where u and v denote initial and final velocities, respectively; a is acceleration; and ∆x is the distance traveled.

Then we get

(18 m/s)² - (26 m/s)² = 2 a (52 m)

a = ((18 m/s)² - (26 m/s)²) / (104 m)

a ≈ -3.4 m/s²

Answer:

Is it only me who can't understand your question?

Pls give the full question ...

Hope you have a great day!

Answer:

1 m/s²

Explanation:

Let velocity at A be v,

Use d = v*t + at²2/2

From A to B,

6 = v(2) + a(2²)/2 = 2v + 2a, so

v + a = 3   (1)

From A to C,

6 + 10 = v(4) + a(4²)/2

16 = 4v + 8a  

or, v + 2a = 4   (2)

From (1) (2), get

a = 1 m/s²

Answer:

The time of travel and the distance between neighboring dots is always the same. So, the speed between neighboring dots is constant. This speed will be the same as the average speed in part F. hope it helps!

a. The electric field above the planar insulating sheet is Ej = (σ/ε₀)j

b. The electric field below the planar insulating sheet is -Ej = -(σ/ε₀)j

The electric field above the planar insulating sheet is Ej = (σ/ε₀)j

Using Gauss' law ε₀∫E.dA = q where

Now, ε₀∫E.dA = q

ε₀∫Ej.dAj = σA

ε₀∫EdA = σA

ε₀E∫dA = σA

ε₀EA = σA

ε₀E = σ

E = σ/ε₀

So, the electric field above the planar insulating sheet is Ej = (σ/ε₀)j

The electric field below the planar insulating sheet is -Ej = -(σ/ε₀)j

Using Gauss' law ε₀∫E.dA = q where

Now, ε₀∫E.dA = q

ε₀∫-Ej.-dAj = σA

ε₀∫EdA = σA

ε₀E∫dA = σA

ε₀EA = σA

ε₀E = σ

E = σ/ε₀

So, the electric field below the planar insulating sheet is -Ej = -(σ/ε₀)j

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The point A with the higher mass of 10kg will have the greatest moment of inertia.

This can be defined as the resistance of any physical object to a change in its velocity.

Masses which have the highest values and are further away form the axis of rotation have the greatest moment of inertia which was why point A was chosen as the most appropriate choice.

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(a) The work done in strecthing the spring is 122.5 N.

(b) The work done in compressing the spring is -122.5 N.

The work done in stretching a spring is positive since the applied force acts in the same direction as the displacement.

The work done in strecthing the spring is calculated as follows;

W = ¹/₂kx²

W = ¹/₂ x (5 x 10⁴) x (0.07)²

W = 122.5 N

The work done in compressing the spring is negative, since the applied force acts in opposite direction to the displacement of the spring.

The work done in compressing the spring is calculated as follows;

W = -¹/₂kx²

W = -¹/₂ x (5 x 10⁴) x (0.07)²

W = -122.5 N

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Answer:

y = 6.92[m]

Vf = 16.305[m/s]

Explanation:

To solve this problem we must use the following kinematics equations, where we must first find the final velocity.

[tex]v_{f}=v_{i}+(g*t)[/tex]

where:

Vi = initial velocity = 11.4[m/s]

Vf = final velocity [m/s]

t = time = 0.5[s]

g = gravity acceleration = 9.81[m/s^2}

Note: the positive sign in the equation above is because the acceleration of gravity goes in the direction of the motion of the rock.

Vf = 11.4 + (9.81*0.5)

Vf = 16.305 [m/s]

Now we can calculate how far the rock goes, using the following equation:

[tex]v_{f} ^{2}= v_{i} ^{2}+(2*g*y)\\v_{f} ^{2}- v_{i}^{2} = 2*g*y\\y = \frac{v_{f} ^{2}- v_{i}^{2}}{2*g} \\y = \frac{16.305^{2}-11.4^{2} }{2*9.81}\\ y=6.92[m][/tex]

Therefore the Rock will be (70 - 6.92) = 63.07 [m] above the water level

Answer:

V * ρB = WB        volume of ball * density of ball = weight of ball

V * ρW = Ww        volume of ball * density of water = buoyant force

ρB / ρW = WB / Ww = 80 / 20 = 4    water provides 20 N of buoyant force

ρB = 4 ρW = 4 gm/cm^3

ρW = 1000 kg / m^3 = 1 gm / cm^3

(1 gm/cm^3) = .001 kg / .000001 m^3 = 1000 kg/^3

ρW = 1 gm / cm^3

multiply by 9.8 or 980 to get weight densities

In this case

4 * 1000 kg/m^3 * 9.8 m/s^2 = 39200 N /m^3      weight density of ball

Answer:

zero

Explanation:

The work done is zero because the object has no displacement

Answer:

Explanation:

For example 1, there is no friction, so the acceleration in example 1 is:[tex]\sum F=F=100=ma \rightarrow a=\frac{100}{50}=2 ms^{-2}[/tex]

For example 2, there is a friction, so the acceleration in example 2 is:

[tex]\sum F=F-f=100-40 = 60 = ma\rightarrow a_{2}=\frac{60}{50}=1.2 ms^{-2}[/tex]

Here we can say that "according to Newton's 2nd Law, the box in example 2 has less acceleration than in the example 1". So, the claim is denied.  

From the question, the order of information processing from the shallowest to the deepest is;

The term information processing means the way in which we deal with information. It is the process by which information is encoded into our memory.

The following is the order of information processing from the shallowest to the deepest;

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Answer:

F = M a       fundamental Newton's equation

F = 3 kg * 3 m/s^2 = 9 kg m / s^2 = 9 Newtons

Explanation:

if we convert it into g/cm it'll be

2000 grams

Answer:

gfdvcfffddfgffffdrddgfddddghtscgvfrggxfhxdg

Answer:

-.57

Explanation:

Slope from the points (0,6) and (7,2)

2-6/7-0=-.57

Answer:

Yes. Yes. Yes

Explanation:

Answer Is yes

Answer:

The mitochondria, also known as the mitochondrion, is the organelle that produces energy in living organisms.

Explanation:

This organelle is found in Eukaryotic cells. This organelle converts energy into food molecules through a process known as cellular respiration.

I hope this helps you

:)

Answer:

GIVE ME BRAINLIEST!!!!!!!!!!

Why does Venus appear so bright to our eyes?

Venus is so bright because its thick clouds reflect most of the sunlight that reaches it (about 70%) back into space, and because it is the closest planet to Earth. Venus can often be seen within a few hours after sunset or before sunrise as the brightest object in the sky (other than the moon).

it is much larger than either Mercury or Mars

Mars, the fourth planet from the sun, is the second smallest planet in the solar system; only Mercury is smaller.

it gets closer to us than does any other planet

In other words, Mercury is closer to Earth, on average, than Venus is because it orbits the Sun more closely. Further, Mercury is the closest neighbor, on average, to each of the other seven planets in the solar system.

All of the items listed helps us understand why Venus is so bright.

Venus is so bright because its thick clouds reflect most of the sunlight that reaches it (about 70%) back into space, and because it is the closest planet to Earth. Venus can often be seen within a few hours after sunset or before sunrise as the brightest object in the sky (other than the moon).

its sulfuric acid cloud cover reflects almost 60% of the sunlight

Clouds. Venusian clouds are thick and are composed mainly (75–96%) of sulfuric acid droplets. These clouds obscure the surface of Venus from optical imaging, and reflect about 75% of the sunlight that falls on them. The geometric albedo, a common measure of reflectivity, is the highest of any planet in the Solar System

it lies closer to the Sun than we do, so sunlight is more intense there

When it is winter in the northern half of Earth, the southern hemisphere, tilted toward our Sun, has summer. During fall and spring, some locations on Earth experience similar, milder, condition.

Answer:

They create enormous amounts of sound energy, much like explosion. When an aircraft passes through air, it creates a series of pressure waves just like the waves created by the boat. As the speed of aircraft increases these waves are forced to compress.

Answer:

What happens when a plane passes the speed of sound?

Answer - You hear a loud BOOM then you cant hear it

How does it sound?

Answer - there is no sound

Is the sound super high since the wavelength is super low or maybe even non-existent?

Answer - When its about to break the sound barrier it makes a high pitched sound

How does it look and why does it look that way?

Answer - Its air you cant see it ;-;

How will it affect people on ground?

you will hear the sound and it might hurt but nothing else

Explanation:

The Final angular velocity of the sphere is : Half of its initial value ( W/2 )

Given that The kinetic energy of a rotating body ( K ) = 1/2 IW² --- ( 1 )

where : I = moment of inertia,  w = angular velocity

I = [tex]\frac{2}{5} MR^{2}[/tex]

Therefore equation ( 1 ) becomes

K = [tex]\frac{1}{5}MR^2W^2[/tex]   ----- ( 2 )

After doubling the radius

R' = 2R

K' = K

Mass = unchanged

therefore :

  [tex]\frac{1}{5}MR'^2W'^2 = \frac{1}{5}MR^2W^2[/tex]

= ( 2R )² W'² = R²W²

Resolving equation above

Hence : W' ( new angular velocity ) =  W / 2

In conclusion The Final angular velocity of the sphere is : Half of its initial value ( W / 2).

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Answer:

The current is   [tex]I  =  1.1434*10^{-5}}\  A[/tex]

Explanation:

From the question we are told that

   The radius of the kite string is  [tex]R =  2.02 mm =  0.00202 \ m[/tex]

   The  distance it extended upward is   [tex]D =  0.823 km = 823 \  m[/tex]

   The thickness of the water layer is [tex]d = 0.506 mm  =  0.000506 \  m[/tex]

   The resistivity is  [tex]\rho =  159\ \Omega  \cdot m[/tex]

   The potential  difference is  [tex]V  =   186 MV =  186 *10^{6} \  V[/tex]

Generally the cross sectional area of the water layer is mathematically represented as

      [tex]A =  \pi r^2[/tex]

Here  r is mathematically represented as

      [tex]r =  [(R + d ) - R][/tex]

=>   [tex]r =  [(0.00202 +  0.000506 ) - 0.00202][/tex]

=>  [tex]r =  0.000506[/tex]

=>     [tex]A = 3.142 *  [0.000506]^2 [/tex]  

=>     [tex]A = 8.0447*10^{-7}\ m^2 [/tex]  

Generally the resistance of the water is mathematically represented as

    [tex]R =  \frac{\rho  * D }{A}[/tex]

=>   [tex]R =  \frac{159  *823 }{8.0447*10^{-7}}[/tex]

=>   [tex]R = 1.62662 * 10^{11} \  \Omega  [/tex]

Generally the current is mathematically represented as

      [tex]I  =  \frac{V}{R}[/tex]

=>    [tex]I  =  \frac{186 *10^{6} }{1.62662 * 10^{11}}[/tex]

=>    [tex]I  =  1.1434*10^{-5}}\  A[/tex]

Answer:

The buoy will move upwards and downwards and well as left and right

Explanation:

As the wind is storing so had the capability to move the buoy in all directions as it is a light object despite being anchored down

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Answer:

50 V; step-down transformer

Explanation:

10,000 : 5,000 = 100 : V

V = 50 V

From 100 V change to 50 V, so it is a step-down transformer

The time needed for the block to travel from -A/2 to A/2 is mathematically given as

t=0.5sec

Generally, when the start point is the mean intial position and it goes from  A/2  down through the right goes through and fro back to the mean position, and this is after it must have gone through -A/2. Hence it has finished one cycle (0.1 sec.)

In conclusion, for an -A/2 to A/2 oscillation, then it will finish half-cycle given time period to be

t=1/2

t=0.5sec

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Answer:

D refraction

Explanation:

I had a question like this so and I got it right so I believe this is the correct answer

Answer:

Explanation:

so,average velocity =total displacement

total time taken

100m/4 =25

Answer:

v=10 m/s

Explanation:

Given that,

Speed of a drone is 8 m/s due East with respects to the wind

Speed of a drone 6 m/s due North with respect to the ground.

We need to find the speed of the drone with respect to the ground. Let v is the speed. It is given by the resultant of two speeds.

[tex]v=\sqrt{8^2+6^2} \\\\v=10\ m/s[/tex]

So, the speed of the drone with respect to the ground is 10 m/s.