Answer:
The correct answer is: Sweden
I just submitted my test with this question on it and it said the right answer was Sweden. When you look at the graphs the one with the most dark blue has the most supporters. Sweden has the most dark blue.
Hope this is helpful, please mark me Brainliest if i got it right :)
Explanation:
What are some uses of radioactive dating?
HELPP PLEASEEEE!!!
Answer:
Radioactive dating is a method of dating rocks and minerals using radioactive isotopes. This method is useful for igneous and metamorphic rocks, which cannot be dated by the stratigraphic correlation method used for sedimentary rocks. Over 300 naturally-occurring isotopes are known.
To gain an understanding of mixture and the concept of separate of mixture,prepare an article to help feeding mother in your community to find the element of iron in iron-fortified breakfast cereal flakes .through this article the mother should be able to see how the iron compenent of this mixture (cereal) retains its properties and can thus be separated by physical means
Answer:
you ask questions that are too hard!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!1
Explanation:
Magnetic field lines appear _____.
A farthest apart at the poles where the magnetic field is strongest
B closest together at the poles where the magnetic field is weakest
C closest together at the poles where the magnetic field is strongest
D farthest apart at the poles where the magnetic field is weakest
Answer:
A
Explanation:
A farthest apart at the poles where the magnetic field is strongest
A buffer that contains 0.34 M of an acid, HA and 0.37 M of its conjugate base A-, has a pH of 3.26. What is the pH after 0.032 mol of HCl are added to 0.71 L of the solution
Answer: pH ≈ 3.186
Explanation:
[tex]p^{H} &=p^{k a}+\left[\frac{A^{-}}{H A}\right] \\3.26 &=p^{k a}+ \log \frac{0.37}{0.34} \\3.26 &=p^{k a}+\log\ 1.089 \\3.26 &=p^{k e}+0.037 \\p^{k a} &=3.26-0.1105 \\p^{k a} &=3.1495[/tex]
[tex]$0.34 \frac{\mathrm{mol}}{2} \times 0.71 \mathrm{~L}=0.2414 \ {\mathrm{mol} \rightarrow HA \\\\[/tex]
[tex]$0.37 \frac{\mathrm{mol}}{2} \times 0.71 \mathrm{~L}=0.2627 \ {\mathrm{mol} \rightarrow A^{-} \\\\[/tex]
[tex]$0.2414-0.032 \mathrm{mol}=0.2094 \mathrm{\ mol} \ HA[/tex]
[tex]$0.2627+0.032 \mathrm{mol}=0.2947 \mathrm{\ mol} \ A^{-}[/tex]
[tex]\begin{aligned}&p H=3.1495+\log\frac{0.2627}{0.2414} \\&p H=3.1495+0.0367 \\&p H=3.186\end{aligned}[/tex]
Therefore, the pH after 0.032 mol of HCl are added to 0.71 L of the solution is approximately 3.186