There are 750 identical plastic chips numbered 1 through 750 in a box. What is the probability of reaching into the box and randomly drawing a chip number that is smaller than 627

Answers

Answer 1

Answer:

0.8358 = 83.58% probability of reaching into the box and randomly drawing a chip number that is smaller than 627

Step-by-step explanation:

Uniform probability distribution:

An uniform distribution has two bounds, a and b.

The probability of finding a value of at lower than x is:

[tex]P(X < x) = \frac{x - a}{b - a}[/tex]

There are 750 identical plastic chips numbered 1 through 750 in a box

This means that [tex]a = 1, b = 750[/tex]

What is the probability of reaching into the box and randomly drawing a chip number that is smaller than 627?

[tex]P(X < x) = \frac{627 - 1}{750 - 1} = 0.8358[/tex]

0.8358 = 83.58% probability of reaching into the box and randomly drawing a chip number that is smaller than 627


Related Questions

what percentage is the following 3 upon 4 of 3 upon 8​

Answers

Step-by-step explanation:

the answer is in the image above

Step-by-step explanation:

3/4×3/8

9/32

9/32×100

~28%

PLEASE HELP ME WITH THIS ONE QUESTION
If Linda is at the store and can buy any two fruits (the store sells apples, oranges, pears, bananas, and kiwis), how many combinations of fruit can she choose?
A) 25
B) 3
C) 10
D) 15

Answers

Answer:

option C

Step-by-step explanation:

Total number of items = 5

Number of items to choose = 2

Therefore, the number of combinations is

                                                       [tex]5C_2 = \frac{5 \times 4}{1 \times 2} = 10[/tex]

pls help! show your work!
(3sqrt4)/(3sqrt5)

Answers

Answer:

3sqaure root 100/5

Step-by-step explanation:

It would look like this picture Below

help with algebra 1 equation pls help

Answers

Answer:

b.    [tex] \blue{k = \dfrac{l - 14j}{3}} [/tex]

Step-by-step explanation:

[tex] l = 14j + 3k [/tex]

Switch sides.

[tex] 14j + 3k = l [/tex]

Subtract 14j from both sides.

[tex] 3k = l - 14j [/tex]

Divide both sides by 3.

[tex] \blue{k = \dfrac{l - 14j}{3}} [/tex]

PLEASE HELP! I'm lost. :(

In 2005, 1,475,623 students heading to college took the SAT. The distribution of scores in the math section of the SAT follows a normal distribution with mean
µ = 520 and population standard deviation = 115.

What math SAT score is 1.5 standard deviations above the mean? Round answer to a whole number.

Answers

Answer:

A math SAT score of 693 is 1.5 standard deviations above the mean

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean µ = 520 and population standard deviation = 115.

This means that [tex]\mu = 520, \sigma = 115[/tex]

What math SAT score is 1.5 standard deviations above the mean?

This is X when [tex]Z = 1.5[/tex]. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]1.5 = \frac{X - 520}{115}[/tex]

[tex]X - 520 = 1.5*115[/tex]

[tex]X = 693[/tex]

A math SAT score of 693 is 1.5 standard deviations above the mean

A cube with side lengths of 4 cm has a density of 3 grams/cubic centimeters. The mass of the cube is _____ grams?

Answers

9514 1404 393

Answer:

  21 1/3 grams

Step-by-step explanation:

The mass is the product of the volume and the density. The volume of a cube is the cube of its edge dimension.

  M = Vρ

  M = (4 cm)³×(3 g/cm³) = 64/3 g

The mass of the cube is 64/3 = 21 1/3 grams.

d= (r+c)t
how do i solve for t?

Answers

Answer:

[tex] { \tt{d = (r + c)t}}[/tex]

Divide ( r+c ) on both sides:

[tex]{ \tt{t = { \frac{d}{(r + c)} }}}[/tex]

Answer:

d / ( r + c) = t

Step-by-step explanation:

d = ( r + c ) t

Divide each side by ( r + c)

d / (r + c ) = ( r + c ) t / ( r + c)

d / ( r + c) = t

CollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollege

Answers

CollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollege

CollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollege

Mass of a proton: 1.007825 units
Mass of a neutron: 1.008665 units
Calculate the mass Defect of 214 N has actual mass of 14.0031 u.

Answers

Given:-

mass of proton = 1.007825 umass of neuron = 2.008625 u .Actual mass = 14.0031 u

To find:-

The mass defect.

Answer:-

Mass defect arises when the mass of the atom differs from the sum of masses of nucleons . As we know that the nucleus of an atom is made up of neutrons(n) and protons (p) , and the total mass of a atom is the mass of nucleons ( protons and neutrons ) as electrons have mass very low as compared to that of n or p .

If we denote mass number by [tex]\green{A}[/tex] , then ;

[tex]\implies A = n_{\rm neutrons} + n_{\rm protons} [/tex]

Let [tex] Z[/tex] be the atomic number, then ;

[tex]\implies n_p = Z [/tex]

So, the number of neutrons will be;

[tex]\implies n_n = (A-Z) [/tex]

Therefore total mass would be ;

[tex]\implies M = m_pZ +m_n (A-Z) [/tex]

Then the mass defect would be ,

[tex]\implies\underline{\underline{\green{ \Delta M = [Zm_p + (A-Z)m_n - M ] }}} [/tex]

where ,

[tex]Z [/tex] = atomic number[tex] A[/tex] = mass number[tex] m_p [/tex] = mass of a proton[tex] m_n [/tex] = mass of a neutron

_______________________________________

Now we know that the Atomic number of Nitrogen is 7(Z) and its mass number is 14(A) .

Now substitute the respective values,

[tex]\implies \Delta M = 7(1.007825) + (14-7)1.008665 - 14.0031 \\ [/tex]

[tex]\implies \Delta M = 7.054775 + 7(1.008665) - 14.00 31 [/tex]

[tex]\implies \Delta M = 7.054775 + 7.060655 - 14.0031 [/tex]

[tex]\implies \Delta M = 14.11543 - 14.0031 [/tex]

[tex]\implies \underline{\underline{\green{ \Delta M = 0.11233 \ u }}}[/tex]

Hence the mass defect is 0.11233 u .

Also this mass defect appears as energy which is responsible for the binding of nucleons together.

and we are done!

How much is 13,200 feet in miles

Answers

Answer:

2.5 miles

Step-by-step explanation:

Which best explains whether or not ABC = LMN?

Answers

Answer:

If I've done it right the answer should be A, the figures are congruent because a 270 rotation about the origin a d a reflection of the x-axis

For the following right triangle find the side length x

Answers

Step-by-step explanation:

everything can be found in the picture

Answer:

x=15

Step-by-step explanation:

Hi there!

We're given a right triangle with the measures of the 2 legs (sides that make up the right angle). We're also given the measure of the hypotenuse (the side opposite to the right angle) as x

We need to find x

The Pythagorean Theorem states that if a and b are the legs and c is the hypotenuse, then a²+b²=c²

Let's label the values of a, b, and c to avoid any confusion first

a=12

b=9

c=x

now substitute into the theorem

12²+9²=x²

raise everything to the second power

144+81=x²

add 144 and 81 together

225=x²

take the square root of 225

15=x (note: -15=x is technically also an answer, but since lengths cannot be negative, it's an extraneous solution in this case)

Therefore, the side length of x is 15

Hope this helps! :)

What is the length of each leg of the triangle below?
459
22
90°
45
O A. 11.12
B. 1
C. 15
D. 11
ET
F. 22

Answers

Answer:

option A

Step-by-step explanation:

since the given triangle is an isosceles triangle it's two remaining sides are equal

let the length of missing side be x

using pythagoras theorem

a^2 + b^2 = c^2

x^2 + x^2 = 22^2

2x^2 = 484

x^2 = 484/2

x = [tex]\sqrt{242}[/tex]

x = [tex]11\sqrt{2}[/tex]

According to records, the amount of precipitation in a certain city on a November day has a mean of inches, with a standard deviation of inches. What is the probability that the mean daily precipitation will be inches or less for a random sample of November days (taken over many years)

Answers

Answer:

The probability that the mean daily precipitation will be of X inches or less for a random sample of n November days is the p-value of [tex]Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex], in which [tex]\mu[/tex] is mean amount of inches of rain and [tex]\sigma[/tex] is the standard deviation.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question:

Mean [tex]\mu[/tex], standard deviation [tex]\sigma[/tex]

n days:

This means that [tex]s = \frac{\sigma}{\sqrt{n}}[/tex]

Applying the Central Limit Theorem to the z-score formula.

[tex]Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

What is the probability that the mean daily precipitation will be of X inches or less for a random sample of November days?

The probability that the mean daily precipitation will be of X inches or less for a random sample of n November days is the p-value of [tex]Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex], in which [tex]\mu[/tex] is mean amount of inches of rain and [tex]\sigma[/tex] is the standard deviation.

Rafael ate one-fourth of a pizza and Rocco ate one-third of it. What fraction of the pizza did they eat?

They ate

Answers

Answer:

7/12

Step-by-step explanation:

They ate  1/4  and 1/3

1/4 +1/3

Get a common denominator

1/4 *3/3 + 1/3 *4/4

3/12 + 4/12

7/12

When traveling to work, Cherise averages 60 miles per hour.Because of heavy traffic in the evening, she averages only 40 miles per hour. If the distance from home to work is 80 miles, how much longer does it take Cherise to make the drive home?

Answers

Answer:  40 minutes

============================================================

Explanation:

The distance traveled is d = 80 miles.

When going to work, her speed is r = 60 mph. She takes t = d/r = 80/60 = 4/3 hours which converts to 80 minutes. Multiply by 60 to go from hours to minutes.

Notice how the '80' shows up twice (in "80 miles" and "80 minutes"). This is because traveling 60 mph is the same as traveling 1 mile per minute.

-----------------

Now as she's coming home, her speed becomes r = 40 and she takes t = d/r = 80/40 = 2 hours = 120 minutes.

The difference in time values is 120 - 80 = 40 minutes.

Her commute back home takes 40 more minutes compared to the morning drive to work.

A cyclist travels 3 miles in 15 minutes and then a further 7 miles in 25 minutes without stopping.
Calculate the cyclist's average speed in mph.

Answers

Answer:

v = 15 mph

Step-by-step explanation:

Given that,

A cyclist travels 3 miles in 15 minutes and then a further 7 miles in 25 minutes without stopping.

Total distance, d = 3 + 7 = 10 miles

Total time, t = 15 + 25 = 40 minutes = 0.6667 hours

Average speed,

[tex]v=\dfrac{d}{t}[/tex]

Put all the value,

[tex]v=\dfrac{10}{0.6667}\\\\= $$14.99\ mph[/tex]

or

v = 15 mph

So, the required average speed is equal to 15 mph.

Nikki grows 20 tomato plants.
She measures their heights to the nearest centimeter and writes them down.
15 14 12 17 18
11 16 14 21 19
10 16 16 13 17
9 15 20 19 9
Complete the frequency table.

Answers

Answer:

I found answer

Step-by-step explanation:

1) 9

2) 12

3)15

4)20

Please answer the following.

Answers

Answer:

[tex] \sqrt{4 \times 5 + \sqrt{4 \times 9} } [/tex]

The ratio of girls to boys in a particular classroom is 4:3. What fraction of the total number of students are boys?

The ratio of boys to the total number of students in a particular classroom is

Answers

Answer:

3:7

Step-by-step explanation:

We know that there are 4 girls and 3 boys and 4+3=7.

please help me look at the photo!

Answers

First of all multiply both sides by the power of 3 to cancel out the cube roots.

So you will be left out with:

X+4 > -x

Now simplify:

4 > -x-x

4> -2x

4/-2 > -2x/-2

-2 > x

Final answer:

It’s C , x < -2

Good luck and best of wishes!!

in which quadrant or axis will the poit lie if...​

Answers

Step-by-step explanation:

a.fourth quadrent

b.third quadrent.

21(2-y)+12y=44 find y​

Answers

Answer: y= -2/9
Explanation:
21(2-y)+12y=44
42-21y+12y=44
42-9y=44
-9y=2
y=-2/9

Answer:

[tex]\textbf{HELLO!!}[/tex]

[tex]21\left(2-y\right)+12y=44[/tex]

[tex]42-21y+12y=44[/tex]

[tex]~add ~similar\:elements[/tex]

[tex]42-9y=44[/tex]

[tex]Subtract~42~from~both~sides[/tex]

[tex]42-9y-42=44-42[/tex]

[tex]-9y=2[/tex]

[tex]Divide\:both\:sides\:by\:}-9[/tex]

[tex]\frac{-9y}{-9}=\frac{2}{-9}[/tex]

[tex]y=-\frac{2}{9}[/tex]

----------------------

hope it helps...

have a great day!

A pile of 15 boxes is 3 metres high. What is the depth of each box?
5 m
0.002 km
200 cm
200 mm

pls help

Answers

A I seen it on the test

Jordan has more than 25 coins in his collection.
Which inequality shows the number of coins in Jordan's collection?

Answers

Answer:

x + 25 is an expression, not an inequality.

Jordan has more than 25 coins, so this means that the > symbol will be used.

The answer with this symbol is B. x>25.

Step-by-step explanation:


A jet travels 5192 miles against a jetstream in 8 hours and 6072 miles with the jetstream in the same amount of time. What
is the rate of the jet in still air and what is the rate of the jetstream?

Answers

the answer is in the picture

What is cos(A)? please explain

Answers

Answer:

cos(A) = adjacent side / hypotenuse

= 4/5

Answer:

[tex] \small \sf \: cos ( A ) = \green{ \frac{ 4}{ 5}} \\ [/tex]

Step-by-step explanation:

[tex] \small \sf \: cos ( A ) = \frac{ adjacent \: side }{ Hypotenuse} \\ [/tex]

Where, we have given

adjacent side is 4 Hypotenuse is 5

substitute the values that are given

[tex] \small \sf \: cos ( A ) = \green{ \frac{ 4}{ 5}} \\ [/tex]

Part 3: The Space Inside! 1. Find the volume of the shipping box using the two methods and show your work: 2. Using the volume formula

3. Explain how both methods provide the same measurement of volume for the shipping box.

Answers

9514 1404 393

Answer:

  36 9/16 cubic feet

Step-by-step explanation:

1.

Volume formula

  V = LWH

  V = (3 3/4 ft)(3 ft)(3 1/4 ft) = (15/4)(3)(13/4) ft³ = 585/16 ft³

  V = 36 9/16 ft³ . . . the volume of the shipping box

__

Packing cubes

Each cube measures 1/4 ft on a side. In terms of cubes, the dimensions of the box are ...

  3 3/4 ft = 15/4 ft = 15×(1/4 ft)   ⇒   15 cubes

  3 ft = 12/4 ft = 12×(1/4 ft)   ⇒   12 cubes

  3 1/4 ft = 13/4 ft = 13×(1/4 ft)   ⇒   13 cubes

This means 15 cubes can be lined up along the bottom front of the box. 12 such lines can make one layer of cubes covering the bottom of the box, and 13 such layers will fill the box.

The total number of cubes in the box is ...

  15 × 12× 13 = 2340 . . . . fish food cubes

Each cube has a volume of (1/4 ft)³ = 1/64 ft³, so the volume of the shipping box is ...

  (2340 cubes)×(1/64 ft³/cube) = 2340/64 ft³

  = 36 9/16 ft³ . . . shipping box volume

__

2.

Using the volume formula, the volume is 36 9/16 ft³

Using the packing cubes method, the volume is 36 9/16 ft³

__

3.

If you consider the math used in the packing cubes method, you see it looks like ...

  V = (15)(12)(13) × (1/64 ft³)

  = (15)(12)(13)×(1/4 ft)³ = (15×1/4 ft)(12×1/4 ft)(13×1/4 ft)

  = (3 3/4 ft)(3 ft)(3 1/4 ft)

  = LWH

That is, the "packing cubes method" is simply a rearrangement of the volume formula product using the commutative and associative properties of multiplication. The same numbers are used to compute the product, but in a different order. Hence the result must be the same.

On a coordinate plane, a line goes through (negative 3, negative 3) and (negative 1, 5). What is the equation of the line parallel to the given line with an x-intercept of 4?

Answers

y = mx + c

m = gradient

gradient of line:
[5 - (-3)]/[(-1) - (-3)]
= 8/2
= 4

y = mx + c
subsitute (4, 0)
0 = (4)(4) + c
0 = 16 + c
c = -16

equation of the line:

y = 4x - 16

hope this helped :)



Answer:

4, -16

Step-by-step explanation:

according to a salad recipe each serving requires 4 teaspoons of vegetable oil and 12 teaspoons of vinegar. if 14 teaspoons of vegetable oil were used how many teaspoons of vinegar should be used

Answers

Answer:

42 teaspoons of vinegar

Step-by-step explanation:

Given

[tex]x \to vegertable[/tex]

[tex]y \to vinegar[/tex]

[tex]x : y = 4 :12[/tex]

Required

Find y when [tex]x = 14[/tex]

[tex]x : y = 4 :12[/tex] implies that:

[tex]14 : y = 4 : 12[/tex]

Express as fraction

[tex]\frac{y}{14} = \frac{12}{4}[/tex]

[tex]\frac{y}{14} = 3[/tex]

Multiply by 3

[tex]y = 14* 3[/tex]

[tex]y = 42[/tex]

Other Questions
Enter your answer and show all the steps that you use to solve this problem in the space provided.Solve,4x + 6 < -6 Which topic is best suited for a formal discussion?the contents of a new textbookthe weekend plans of your friendsthe best places to shop online for new shoesthe best cookbooks for learning to make Thai food Leading up to the french and indian war the british were This year, Sigma Inc. generated $639,000 income from its routine business operations. In addition, the corporation sold the following assets, all of which were held for more than 12 months: Initial Basis Acc. Depr Sale PriceMarketable securities $144,000 0 $64,000Production equipment 93,000 $76,000 30,000 Business realty: Land 165,000 0 180,000Building 200,000 58,300 210,000Required:a. Compute Sigmas taxable income assuming that it used the straight-line method to calculate depreciation on the building and has no nonrecaptured.b. Recompute taxable income assuming that Sigma sold the securities for $150,000 rather than $64,000. Having a strong perceptual set may result in which of the following? A. Accurate interpretation of sensory informationB. Biased perception based on assumptionsC. A reliance on bottom-up processingD. Careful attention to all sensory stimuliE. Formations of perceptions that conflict with the perceptual set Evaluate expressions- if A=4 and B=9 what is the value of the following expression 20/a+7bA.28B.33C.68D.108 To find the quotient of multiply 3 by AYUDA PORFAVOR. Cuntas regiones hay en la zona andina del Per? A) 5 regiones andinas. B) 3 regiones andinas C) 8 regiones andinas. D) 6 regiones andinas. Find the measure of "theta". Round all answers to the nearest tenth. how can I solve this question ? wick method should I use ? Here are the first three terms of a different sequence.139Write down two numbers that could be the 4th term and the 5th term of this sequence.Give the rule you have used to get your numbers.please helpp Is this question biased or unbiased?"Why is drinking fruit juice good for you?" discrib an occasion when someone you know abused his or her authority Answer the following questions. who was the speaker sold into the chimney sweeping business by Ortega Company manufactures computer hard drives. The market for hard drives is very competitive. The current market price for a computer hard drive is $54. Ortega would like a profit of $14 per drive. What target cost Ortega should set to accomplish this objective I NEED HELP ASAP PLESSEEEWhat is the relation between the variables in the equationY/x^2= 10?a. x varies directly with the square of yb. y squared varies inversely with xC. y varies directly with x squaredy varies inversely with x squaredd. 7. You have 1.5x1024 atoms of iron. How many moles do you have? Read the following stanza from "Loveliest of Trees, the Cherry Now," by A. E.Housman.Now, of my threescore years and ten,Twenty will not come again,And take from seventy springs a score,It only leaves me fifty more.What tone does the poet create through his word choice in this stanza?A. JoyfulO B. ComfortingO C. ReflectiveD. UnkindPREVIOUS Es para hoy, ayuda por favor PLEASE HELPwhat is the amount of an investment $10,000 compounded quarterly for 3 years at a rate of 4 percent?