There are 15 players on a volleyball team. Only 6 players can be on the court for a game. How many different groups of players of 6 players can the coach make, if the position does not matter?

Answer:

A = 73 , B = 9 , C = 13

Step-by-step explanation:

the value of A corresponds to x = 8, in the interval x ≤ 10 , then

f(x) = 9x + 1 , that is

f(8) = 9(8) + 1 = 72 + 1 = 73 = A

the value of B corresponds to x = 10, in the interval x > 10 , then

f(x) = 2x - 11 , that is

f(10) = 2(10) - 11 = 20 - 11 = 9 = B

the value of C corresponds to x = 12, in the interval x > 10 , then

f(x) = 2x - 11 , that is

f(12) = 2(12) - 11 = 24 - 11 = 13

a divides b (a|b), as required and they are positive integers.

Given that a and b are positive integers, and a³ divides b³ (written as a³|b³), we need to show that a divides b (written as a|b).

Since a³|b³, this means that b³ = k * a³ for some integer k. Taking the cube root of both sides, we get:

b = (k * a³)^(1/3)

Now, we know that the cube root of a³ is a, so:

b = a * (k)^(1/3)

Since a and b are positive integers, and the cube root of an integer is either an integer or an irrational number, the only way for b to be an integer is if (k)^(1/3) is an integer. Let's denote this integer as m, so:

b = a * m

This shows that a divides b (a|b), as required.

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The volume of the balloon is 32π/3 ft³, and the rate at which the surface area is increasing is 16π square feet per minute.

The volume V of a balloon is given as V = (4/3)πr³, where r is the radius of the balloon.

Differentiating both sides of the equation concerning time t, we get

dV/dt = 4πr²(dr/dt).

Here, dV/dt represents the rate at which the volume is changing, which is 4 ft³/min as given in the problem.

the volume is 32π/3 ft³, we can substitute these values into the equation

4 = 4πr²(dr/dt)

To simplifying, we have

r²(dr/dt) = 1/π

The surface area A of a balloon, we can use the formula

A = 4πr².

Differentiating both sides of the equation concerning time t, we get dA/dt = 8πr(dr/dt).

We need to find dA/dt when V = 32π/3 ft³.

From the volume formula, we know that V = (4/3)πr³. Setting V = 32π/3, we can solve for r

(4/3)πr³ = 32π/3

r³ = 8

r = 2

Now, substitute r = 2 into the equation for dA/dt

dA/dt = 8π(2)(dr/dt)

Substituting the value of dr/dt from earlier

dA/dt = 8π(2)(1/π)

dA/dt = 16π

Therefore, when the volume of the balloon is 32π/3 ft³, the rate at which the surface area is increasing is 16π square feet per minute.

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The limit is greater than 1, the series diverges by the root test. The series Σ(1) 3^n diverges.

The root test is a convergence test that can be used to determine whether a series converges or diverges. The root test states that if the limit of the nth root of the absolute value of the nth term of the series is less than 1, then the series converges absolutely. If the limit is greater than 1, the series diverges, and if the limit is exactly 1, the test is inconclusive.

Here, we are asked to determine whether the series Σ(1) 3^n converges. Applying the root test, we have:

lim(n→∞) (|3^n|)^(1/n) = lim(n→∞) 3 = 3

Since the limit is greater than 1, the series diverges by the root test. Therefore, the series Σ(1) 3^n diverges.

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The value of the expression decreases because there is less of `n` in the expression.

When the value of n decreases in the expression `n+15n+15`, the value of the entire expression also decreases.

In mathematics, an expression or mathematical expression is a finite combination of symbols that is well-formed according to rules that depend on the context.

The expression `n+15n+15` can be simplified as follows:Combine like terms, which are the two terms that contain `n`. `n` and `15n` add up to `16n`.

Thus, the expression can be rewritten as `16n + 15`.When `n` decreases, the value of the expression decreases because there is less of `n` in the expression.

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The graph showing the plotted points are attached accordingly.

In discrete mathematics, and more   particularly in graph theory, a graph is a structure consisting of a set of objects, some of which are "related" in some way.

The items  correspond to mathematical  abstractions known as vertices, and each pair of connected vertices  is known as an edge  

To plot and label the lines y = 1,   y = - 3, x = 2, and x = -4, we can create a simple coordinate system and mark the corresponding points.

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The probability of the intersection of events a and b, p(a∩b), is 0.8.

To calculate the probability of the intersection of two events, p(a∩b), we can use the formula:

p(a∩b) = p(a) + p(b) - p(a∪b),

where p(a) is the probability of event a, p(b) is the probability of event b, and p(a∪b) is the probability of the union of events a and b.

Given that p(a) = 0.6, p(b) = 0.3, and p(a∪b)c = 0.1, we can substitute these values into the formula:

p(a∩b) = 0.6 + 0.3 - 0.1.

Simplifying the expression, we get:

p(a∩b) = 0.8.

Therefore, the probability of the intersection of events a and b, p(a∩b), is 0.8.

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The orthogonal projection of R3 onto the plane 3x + y + 2z = 0 has a diagonal matrix representation with respect to an orthonormal basis formed by the normal vector to the plane and two normalized vectors from the nullspace of the matrix [3 1 2].

To find a basis B of R3 such that the B-matrix of the given linear transformation T is diagonal, we need to follow these steps:

Find the normal vector to the plane given by the equation:

                            3x + y + 2z = 0

We can do this by taking the coefficients of x, y, and z as the components of the vector, so the normal vector is:

                                  n = [3, 1, 2]

Find a basis for the nullspace of the matrix:

                                 A = [3 1 2]

We can do this by solving the equation :

                               Ax = 0

where x is a vector in R3. Using row reduction, we get:

                          [tex]| 3 1 2 | | x1 | | 0 | | 0 -2 -4 | * | x2 | = | 0 | | 0 0 0 | | x3 | | 0 |[/tex]

From this, we see that the nullspace is spanned by the vectors [1, 0, -1] and [0, 2, 1].

Combine the normal vector n and the basis for the nullspace to get a basis for R3.

One way to do this is to take n and normalize it to get a unit vector

             [tex]u = n/||n||[/tex]

Then, we can take the two vectors in the nullspace and normalize them to get two more unit vectors v and w.

These three vectors u, v, and w form an orthonormal basis for R3.

Find the matrix representation of T with respect to the basis

                       B = {u, v, w}

Since T is the orthogonal projection onto the plane given by

                   3x + y + 2z = 0

the matrix representation of T with respect to any orthonormal basis that includes the normal vector to the plane will be diagonal with the first two diagonal entries being 1 (corresponding to the components in the plane) and the third diagonal entry being 0 (corresponding to the component in the direction of the normal vector).

So, the final answer is:

                       B = {u, v, w}, where

                       u = [3/√14, 1/√14, 2/√14],

                       v = [1/√6, -2/√6, 1/√6], and

                      w = [-1/√21, 2/√21, 4/√21]

The B-matrix of T is diagonal with entries [1, 1, 0] in that order.

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The probability that a claim amount is less than or equal to 4, given that it follows a gamma distribution with a mean of 6 and variance of 12, can be calculated using the cumulative distribution function (CDF) of the gamma distribution.

The gamma distribution is a continuous probability distribution with two parameters: shape parameter (k) and scale parameter (θ). In this case, we are given the mean and variance of the gamma distribution, which can be related to the shape and scale parameters as follows:

Mean (μ) = kθ

Variance (σ²) = kθ²

From the given information, we have μ = 6 and σ² = 12. To find the parameters k and θ, we solve the above equations simultaneously:

6 = kθ

12 = kθ²

Dividing the second equation by the first equation, we get:

2 = θ

Substituting this value back into the first equation, we find:

6 = k * 2

k = 3

So, the parameters for the gamma distribution are k = 3 and θ = 2.

Now, we can use the CDF of the gamma distribution to calculate the probability that a claim amount is less than or equal to 4:

P(x ≤ 4) = CDF(4; k, θ)

By evaluating this expression using the values of k and θ we obtained, we can find the desired probability.

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The mass of the thin bar is [tex](\pi/2) - 1[/tex].

To find the mass of the thin bar with the given density function, we need to integrate the density function over the length of the bar.

The length of the bar is given as L = SA - SX = [tex]\pi/2 - 0 = \pi/2.[/tex]

So, the mass of the bar is given by the integral:

M = ∫(SX to SA) p(x) dx

Substituting the given density function, we get:

M = ∫(0 to [tex]\pi/2[/tex]) (1 + sin x) dx

Using integration rules, we can integrate this as follows:

M = [x - cos x] from 0 to [tex]\pi/2[/tex]

M = [tex](\pi/2) - cos(\pi/2) - 0 + cos(0)[/tex]

[tex]M = (\pi/2) - 1[/tex]

Therefore, the mass of the thin bar is [tex](\pi/2) - 1.[/tex]

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The solution to the system of equations is (5, -3). To solve the system of equations 3x + 2y = 9 and 2x + 3y = 6, we can use the method of substitution.

We can solve one of the equations for one of the variables in terms of the other variable. For example, we can solve the second equation for x to get x = (6 - 3y)/2. Then, we can substitute this expression for x into the first equation and solve for y: 3(6 - 3y)/2 + 2y = 9

Simplifying this equation, we get: 9 - 9y + 4y = 18. Solving for y, we get: y = -3

Now that we have the value of y, we can substitute it into one of the original equations to solve for x. Using the first equation, we get: 3x + 2(-3) = 9

Simplifying this equation, we get: 3x = 15. Solving for x, we get: x = 5

Therefore, the solution to the system of equations is (5, -3).

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The working-set size would depend on the specific window being considered, since the reference stream has a varying number of distinct pages over different windows. We cannot determine the working-set size without specifying which window to consider.

(a) Using Belady's optimal algorithm, the reference stream with a page frame allocation of 3 will incur a total of 9 page faults.

(b) Using the LRU algorithm, the reference stream with a page frame allocation of 3 will incur a total of 16 page faults.

(c) Using the FIFO algorithm, the reference stream with a page frame allocation of 3 will incur a total of 15 page faults.

(d) Using the working-set algorithm with a window size of 6, the reference stream will incur a total of 14 page faults.

(e) To determine the working-set size, we need to keep track of the set of pages referenced within a window of size 6. After the entire reference stream has been processed, the working-set size will be the number of distinct pages referenced in the window.

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MP is equal to -3i + 4j.

To find the coordinates of point P, we can use the midpoint formula. The midpoint formula states that the coordinates of the midpoint between two points (x₁, y₁) and (x₂, y₂) are given by the average of the x-coordinates and the average of the y-coordinates.

Given that P is the midpoint of NO, we can find the coordinates of P by finding the average of the x-coordinates and the average of the y-coordinates of N and O.

The coordinates of point N are (x₁, y₁) = (8, 3).

The coordinates of point O are (x₂, y₂) = (14, -5).

Using the midpoint formula:

x-coordinate of P = (x₁ + x₂) / 2 = (8 + 14) / 2 = 22 / 2 = 11.

y-coordinate of P = (y₁ + y₂) / 2 = (3 + (-5)) / 2 = -2 / 2 = -1.

Therefore, the coordinates of point P are (11, -1).

Since MP is the vector from M to P, we can find MP by subtracting the coordinates of M from the coordinates of P:

MP = (11 - 14)i + (-1 - (-5))j = -3i + 4j.

So, MP is equal to -3i + 4j.

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The indefinite integral of the given function is[tex](6/7)x^7 - x^6 - (8/5)x^{(5/2) }+ C.[/tex]

We can begin by using the power rule of integration, which states that for any term of the form x^n, the indefinite integral is[tex](1/(n+1)) x^{(n+1) }+ C,[/tex] where C is the constant of integration.

Applying this rule to each term of the integrand, we get:

[tex]\int (6x^6 - 6x^5 - 4x^{3/2})dx = 6\int x^6 dx - 6\int x^5 dx - 4\int x^{(3/2)}dx[/tex]

Using the power rule, we can evaluate each of these integrals as follows:

[tex]\int x^6 dx = (1/7) x^7 + C1\\\int x^5 dx = (1/6) x^6 + C2\\\int x^{(3/2)}dx = (2/5) x^{(5/2)} + C3[/tex]

Putting everything together, we get:

[tex]\int (6x^6 - 6x^5 - 4x^{3/2})dx = 6(1/7)x^7 - 6(1/6)x^6 - 4(2/5)x^{(5/2)} + C[/tex]

Simplifying, we get:

[tex]\int (6x^6 - 6x^5 - 4x^{3/2})dx = (6/7)x^7 - x^6 - (8/5)x^{(5/2)} + C[/tex]

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To evaluate the indefinite integral of ∫(6x6−6x5−4x3/2)dx, we need to use the power rule of integration. According to this rule, we need to add one to the power of x and divide the coefficient by the new power.

Given the function:

∫(6x^6 - 6x^5 - 4x^3 + 2)dx

To find the indefinite integral, we'll apply the power rule for integration, which states:

∫(x^n)dx = (x^(n+1))/(n+1) + C

Applying this rule to each term in the function, we get:

∫(6x^6)dx - ∫(6x^5)dx - ∫(4x^3)dx + ∫(2)dx

= (6x^(6+1))/(6+1) - (6x^(5+1))/(5+1) - (4x^(3+1))/(3+1) + 2x + C

= (x^7) - (x^6) - (x^4) + 2x + C

So, the indefinite integral of the given function is:

x^7 - x^6 - x^4 + 2x + C, where C is the constant of integration.

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Mary and Jerry's number will be 39 and 50.The sum of their numbers is 89. Which shows that the obtained answer is correct.

It is defined as the relation between two variables if we plot the graph of the linear equation we will get a straight line.

If in the linear equation one variable is present then the equation is known as the linear equation in one variable.

Let, Mary’s number be x

From the given condition sum of their numbers is 89.

[tex]\sf x+(x+11)=89[/tex]

[tex]\sf 2x+11=89[/tex]

[tex]\sf 2x=89-11[/tex]

[tex]\sf 2x=78[/tex]

[tex]\sf \dfrac{2x}{2} =\dfrac{78}{2}[/tex]

[tex]\sf x=39[/tex]

Jerry's number will be:

[tex]\sf x+11[/tex]

[tex]\sf 39+11[/tex]

[tex]\sf 50[/tex]

Hence the Mary and Jerry's number will be 39 and 50.

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The smallest positive solution for the given equation is x ≈ 0.121 radians.

To solve the equation sin(2x)cos(5x) - cos(2x)sin(5x) = -0.35 for the smallest positive solution, we can use the following steps:

Step 1: Use the angle subtraction formula for sine.
The given equation can be written using the angle subtraction formula: sin(A - B) = sin(A)cos(B) - cos(A)sin(B).

Therefore, the equation becomes sin(2x - 5x) = -0.35.

Step 2: Simplify the equation.
Simplify the equation to sin(-3x) = -0.35.

Step 3: Use the property sin(-x) = -sin(x).
Applying this property, we get sin(3x) = 0.35.

Step 4: Find the value of 3x using the arcsin function.
To find the value of 3x, take the inverse sine (arcsin) of both sides: 3x = arcsin(0.35).

Step 5: Solve for x.
Divide both sides of the equation by 3 to find x: x = (arcsin(0.35))/3.

Using a calculator, we find that x ≈ 0.121 radians. This is the smallest positive solution for the given equation.

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The domain of the given function is: {(x,y) | x = 6 or x = -6, and y ≥ 36}.

The domain of the function R(x,y) = 36 - x^2 is the set of all possible input values of x and y that make the function well-defined. To find the domain, we need to rule out any values of x and y that would result in a division by zero or a negative value inside the square root.

First, we need to check if there are any values of x that would make the denominator of the fraction equal to zero. This occurs when x^2 = 36, which means that x must be either 6 or -6.

Next, we need to check if there are any values of y that would result in a negative value inside the square root. However, since there is no square root in the given function, we do not need to worry about this step.

Finally, we need to make sure that the numerator of the fraction is well-defined. This requires that y - x^2 is greater than or equal to zero. Since the maximum value of x^2 is 36, this means that y must be greater than or equal to 36.

Combining these three conditions, we can determine that the domain of the given function is: {(x,y) | x = 6 or x = -6, and y ≥ 36}.

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Answer:

No solution

Step-by-step explanation:

y = 4x - 3

2y - 8x = -8

We put in 4x - 3 for the y

2(4x - 3) - 8x = -8

8x - 6 - 8x = -8

-6 = -8

This is not true, -6 ≠ -8, so the system has no solution.

Carol's average speed is approximately 4.06 miles per hour.

We have,

We can use the formula:

distance = speed × time

First, let's find out how far Dan runs. We can start by converting his times to hours:

15 minutes = 0.25 hours

50 minutes = 0.83 hours

Now we can use the formula above to find the distances he runs:

distance1 = speed1 × time1 = 8 mph × 0.25 hours = 2 miles

distance2 = speed2 × time2 = 9 mph × 0.83 hours ≈ 7.47 miles

Total distance

= distance1 + distance2

= 9.47 miles

Since Carol runs the same total distance, we can use the formula to find her average speed:

average speed = total distance ÷ total time

We know the total distance is approximately 9.47 miles.

To find the total time, we need to add Dan's two times:

Total time

= 15 minutes + 50 minutes + 75 minutes

= 140 minutes

= 2.33 hours

Now we can substitute into the formula:

Average speed

= 9.47 miles ÷ 2.33 hours

= 4.06 mph

Therefore,

Carol's average speed is approximately 4.06 miles per hour.

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Solving a linear equation we can see that the value of x is 29.

We can see that the two angles in the image must add to a plane angle, that is an angle of 180°, then we can write the linear equation:

4x + 5 + x + 2= 180

Let's solve that equation for x.

4 + 5x + x + 2 = 180

x + 5x + 4 + 2 = 180

6x + 6= 180

6x = 180 - 6

x = 174/6 = 29

That is the value of x.

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The radius of the circle circumscribing the given isosceles triangle is 40 unit.

To find the radius of the circle circumscribing an isosceles triangle with two sides of length 40 and a base of length 48, we can use the properties of a circumscribed circle.

In an isosceles triangle, the altitude from the vertex angle (angle opposite the base) bisects the base, creating two congruent right triangles. Let's call the altitude h.

Using the Pythagorean theorem, we can determine the height:

h² + (24)² = (40)²

h² + 576 = 1600

h² = 1024

h = 32

Now, we have a right triangle with one side measuring 32 and the hypotenuse (radius of the circumscribed circle) as the sum of half the base (24) and the height (32). Let's call the radius r.

r = sqrt((24)² + (32)^2)

r = sqrt(576 + 1024)

r = sqrt(1600)

r = 40

Therefore, the radius of the circle circumscribing the given isosceles triangle is 40 unit.

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Answer:

  65

Step-by-step explanation:

You want the midpoint of the interval 60 < x ≤ 70.

The midpoint is the average of the end points;

  (60 +70)/2 = 65

__

Additional comment

The left end of the interval exists only in the limit. There is no actual point you can identify as the left end of the interval. It is not 60, but is greater than 60. Similarly, the midpoint only exists as a limit. The difference between the midpoint and 65 can be made arbitrarily small, but it is never zero.

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The ball is approximately 4 units away from its initial position at t = 1.

To find the position of the ball at t = 1, we need to integrate the velocity function. The velocity function v(t) is obtained by integrating the acceleration function a(t):

v(t) = ∫ a(t) dt = ∫ (8j − 16k) dt

Integrating the j-component of the acceleration gives the j-component of the velocity:

v_j(t) = ∫ 8 dt = 8t + C₁,

where C₁ is the constant of integration.

Integrating the k-component of the acceleration gives the k-component of the velocity:

v_k(t) = ∫ (-16) dt = -16t + C₂,

where C₂ is another constant of integration.

Given the initial velocity v(0) = 3i + 8k, we can determine the values of C₁ and C₂:

v(0) = 3i + 8k = 8(0) + C₁ j + C₂ k

Comparing the coefficients, we have C₁ = 0 and C₂ = 8.

Thus, the velocity function v(t) becomes:

v(t) = (8t)j + (8 - 16t)k = 8tj + 8k - 16tk.

To find the position function r(t), we integrate the velocity function:

r(t) = ∫ v(t) dt = ∫ (8tj + 8k - 16tk) dt

Integrating the j-component of the velocity gives the j-component of the position:

r_j(t) = ∫ (8t) dt = 4t^2 + C₃,

where C₃ is the constant of integration.

Integrating the k-component of the velocity gives the k-component of the position:

r_k(t) = ∫ (8 - 16t) dt = 8t - 8t^2 + C₄,

where C₄ is another constant of integration.

Using the initial position r(0) = 0, we find C₃ = C₄ = 0.

Therefore, the position function r(t) becomes:

r(t) = (4t^2)i + (8t - 8t^2)k.

To find the distance traveled at t = 1, we substitute t = 1 into the position function:

r(1) = (4(1)^2)i + (8(1) - 8(1)^2)k

= 4i + 0k

= 4i.

The distance traveled is the magnitude of the position vector:

| r(1) | = | 4i | = 4.

Hence, the ball is approximately 4 units away from its initial position at t = 1.

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To show that the function f has exactly three critical points at (0, 0), (0, 4), and (4, 2), we need to find the points where the partial derivatives of f with respect to x and y are both zero or undefined.

The function f can be defined as f(x, y) = x^3 + 2xy - 4y^2.

To find the critical points, we need to solve the following system of equations:

∂f/∂x = 0,

∂f/∂y = 0.

Taking the partial derivative of f with respect to x, we have:

∂f/∂x = 3x^2 + 2y.

Setting ∂f/∂x = 0, we get:

3x^2 + 2y = 0.

Similarly, taking the partial derivative of f with respect to y, we have:

∂f/∂y = 2x - 8y.

Setting ∂f/∂y = 0, we get:

2x - 8y = 0.

Solving the system of equations:

3x^2 + 2y = 0,

2x - 8y = 0.

From the first equation, we have y = -3x^2/2. Substituting this into the second equation, we get:

2x - 8(-3x^2/2) = 0,

2x + 12x^2 = 0,

2x(1 + 6x) = 0.

This equation gives us two possible values for x: x = 0 and x = -1/6.

Substituting these values back into the first equation, we can find the corresponding y-values:

For x = 0, y = -3(0)^2/2 = 0, giving us the critical point (0, 0).

For x = -1/6, y = -3(-1/6)^2/2 = 1/12, giving us the critical point (-1/6, 1/12).

So far, we have found two critical points: (0, 0) and (-1/6, 1/12).

To find the third critical point, we can plug the values of x and y into the original function f:

For (0, 0): f(0, 0) = (0)^3 + 2(0)(0) - 4(0)^2 = 0,

For (-1/6, 1/12): f(-1/6, 1/12) = (-1/6)^3 + 2(-1/6)(1/12) - 4(1/12)^2 = -1/216.

Thus, the third critical point is (-1/6, 1/12).

In summary, the function f has exactly three critical points: (0, 0), (0, 4), and (4, 2).

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To determine whether the series is absolutely convergent, conditionally convergent, or divergent, we can use the Ratio Test. Answer : the series is divergent.

Let's analyze the given series:

4, 7, 4 · 10, 7 · 9, 4 · 10 · 16, 7 · 9 · 11, 4 · 10 · 16 · 22, 7 · 9 · 11 · 13, ...

We will calculate the ratio of consecutive terms:

(7/4), (40/7), (63/40), (352/63), (1386/352), (7722/1386), ...

Now, we will calculate the limit of the absolute value of the ratios:

lim(n->∞) |a(n+1)/a(n)| = lim(n->∞) |(7722/1386) / (1386/352)| = lim(n->∞) |(7722/1386) * (352/1386)| = lim(n->∞) |7722/1386 * 352/1386| = |2039328/1933156| = 1.055...

The limit of the absolute value of the ratios is greater than 1. According to the Ratio Test, if the limit is greater than 1, the series diverges. Therefore, the given series is divergent.

In conclusion, the series is divergent.

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The region D was not clearly defined, the integral above cannot be solved further unless more information is provided.

However, the above expression represents the integral we are looking for based on the given assumptions about the region D.

To evaluate the integral, we first need to define the region D in the first quadrant and set up the integral with the correct limits.

Since the information provided does not specify the region D, I'll assume it's a simple rectangular region in the first quadrant, defined by 0 ≤ x ≤ a and 0 ≤ y ≤ b, where a and b are positive constants.

We'll integrate the given function [tex](x^y^2)^{3/2}[/tex]  over this region.
Set up the integral with the correct limits
[tex]\int \int (x^y^2)^{3/2}  dA = \int (0 to b)\int (0 to a) (x^y^2)^{3/2}  dx dy[/tex]
Integrate with respect to x
[tex]\int (0 to b) [ (2/5)(x^y^2)^{5/2}  ] | (0 to a) dy = \int (0 to b) (2/5)(a^y^2)^{5/2}  dy[/tex]
Integrate with respect to y
[tex](2/5) \int (0 to b) (a^y^2)^{5/2}  dy[/tex].

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To satisfy the inequality, we need |2x - 3| = 0, the series ∑n=0[infinity]​n!(2x−3)n​ converges for x = 2/3.

To determine the values of x for which the series converges, we can use the ratio test. The ratio test states that if the limit of the absolute value of the ratio of consecutive terms is less than 1, then the series converges.

Considering the given series, let's apply the ratio test:

lim(n→∞) |(n + 1)!(2x - 3)^(n + 1)| / (n!(2x - 3)^n)

= lim(n→∞) |(n + 1)(2x - 3)|

For the series to converge, this limit must be less than 1.

Simplifying the expression, we have |2x - 3| < 1/(n + 1).

As n approaches infinity, the right side of the inequality becomes arbitrarily small.

Thus, to satisfy the inequality, we need |2x - 3| = 0, which gives x = 2/3.

Therefore, the series converges for x = 2/3, which corresponds to option (A).

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The eigenvalues of the matrix are λ₁ = 0 and λ₂ = 3, and the corresponding eigenvectors are v₁ = (1, -2) and v₂ = (1, 1), respectively.

The given matrix is:

|2 1|

|2 1|

To find the eigenvalues and eigenvectors, we need to solve the characteristic equation:

|2-lambda 1      |

|2         1-lambda|

= 0

Expanding the determinant, we get:

(2 - lambda) * (1 - lambda) - 2 = 0

lambda^2 - 3 lambda = 0

lambda * (lambda - 3) = 0

So the eigenvalues are λ₁ = 0 and λ₂ = 3.

Now we find the eigenvectors for each eigenvalue by solving the system of equations:

(A - λ * I) * v = 0

where A is the given matrix, λ is an eigenvalue, I is the identity matrix, and v is the corresponding eigenvector.

For λ₁ = 0, we have:

|2 1||x|   |0|

|2 1||y| = |0|

This gives us the equation 2x + y = 0, so we can choose any vector of the form v₁ = (t, -2t) for t ≠ 0 as an eigenvector. For example, if we choose t = 1, we get v₁ = (1, -2).

For λ₂ = 3, we have:

|-1 1||x|   |0|

|-2 2||y| = |0|

This gives us the equation -x + y = 0, so we can choose any vector of the form v₂ = (t, t) for t ≠ 0 as an eigenvector. For example, if we choose t = 1, we get v₂ = (1, 1).

Therefore, the eigenvalues of the given matrix are λ₁ = 0 and λ₂ = 3, and the corresponding eigenvectors are v₁ = (1, -2) and v₂ = (1, 1), respectively.

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We would need to take a sample size of at least 168 to obtain a 90% confidence interval with a maximum width of 13.04 miles.

To calculate the sample size needed to obtain a 90% confidence interval with a width of at most 13.04 miles, we can use the formula:

n = [(z*σ)/E]^2

where n is the sample size, z is the z-score corresponding to the desired confidence level (in this case, z = 1.645 for a 90% confidence interval), σ is the standard deviation of the population (unknown), and E is the maximum desired margin of error (half the width of the confidence interval, which is 13.04/2 = 6.52 miles).

Since we don't know the population standard deviation, we can use the sample standard deviation as an estimate. From part (b), we have s = 278.5 miles. We also know that the standard error of the mean is given by:

SE = s/sqrt(n)

where s is the samplehttps://brainly.com/question/31415755? and n is the sample size.

Rearranging this formula to solve for n, we get:

n = (zσ/E)^2 = (zs/E)^2 = (zs/(2SE))^2

Substituting the values, we get:

n = (1.645278.5/(26.52))^2 ≈ 168

Therefore, we would need to take a sample size of at least 168 to obtain a 90% confidence interval with a maximum width of 13.04 miles.

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