The x vector component of a displacement vector has a magnitude of 146 m and points along the negative x axis. The y vector component has a magnitude of 113 m and points along the negative y axis. Find (a) the magnitude and (b) direction of . Specify the direction as a positive angle with respect to the negative x axis.

Answer:

The maximum intensity, if it changes with distance, the correct answer is a

Explanation:

After reading your extensive writing on the phenomenon of interference, I see that your question is not very related to it

In the interference experiments the amplitude of the radiation is given by the sum of the intensity of a point of the two waves coming from the slits,

           I =[tex]I_{max }[/tex] cos² ([tex]\frac{\pi \ d \ sin \theta}{\lambda}[/tex])  sinx / x

           x = [tex]\frac{\pi \ a \ sin \theta }{ \lambda }[/tex]

where d is the separation between the slits and a the width of each slit.

Therefore, we can see that the intensity of the radiation is redistributed in space in lines approximately the same intensity, second factor is due to the diffraction of each slit, this is generally small for the central part of the interference pattern

therefore the interference pattern is made up of lines of equal intensity.

The maximum intensity, if it changes with distance, in general for energy conservation the intensity must decrease with distance, therefore the correct answer is a

Answer:

I don't really know

Explanation:

I really wanted to help you, but then I realized i didnt know how to

The initial speed of the bullet = v₁= 511.07 m/s

Given

17.4 g bullet

5506 g wooden

The velocity of the block+bullet :1.61 m/s

Required

The initial speed

Solution

Momentum

m₁v₁+m₂v₂=m₁v₁'+m₂v₂'

v₂=0 ⇒block at rest

v₁'=v₂'=1.61 m/s

the equation becomes :

m₁v₁=(m₁+m₂)v'

17.4v₁=(17.4+5506)1.61

v₁= 511.07 m/s

This question is incomplete, the complete question is;

A 1800 kg hybrid vehicle operates on ethanol and is equipped with a multipurpose motorgenerator-flywheel. When the vehicle slows or stops, 50% of the kinetic energy is recovered as electrical energy in the battery. When the IC engine is used to recharge the battery, there is a 25% efficiency of converting chemical energy in the fuel to electrical energy stored in the battery. The vehicle slows from 70 miles per hour to 20 miles per hour. Calculate: (A) Electrical energy recovered in the battery in [kJ] (B) Mass of fuel needed to store same amount of energy in the battery in [kg]

Answer:

a) Electrical energy recovered in the battery is 404.6895 kJ

b) Mass of fuel needed to store same amount of energy in the battery is 0.0606 kg

Explanation:

Given that;

Initial speed of the vehicle V = 70 miles per hour = 31.293 m/s

Final speed of the vehicle u = 20 miles per hour = 8.941 m/s

mass of vehicle m = 1800 kg

Noe, change in kinetic energy of the vehicle will be;

[tex]E_{kinetic}[/tex] = [tex]\frac{1}{2}[/tex]m( v² - u² )

we substitute

=  [tex]\frac{1}{2}[/tex] × 1800( (31.293)² - (8.941)² )

= 900( 979.2518 - 79.9414)

= 900 × 899.3104

=  809379.36 J

[tex]E_{kinetic}[/tex] = 809.379 kJ

now, Electrical energy recovered in the battery when the vehicle slows will be;

[tex]E_{battery}[/tex] = 50% × [tex]E_{kinetic}[/tex]

[tex]E_{battery}[/tex] = 50/100 × 809.379 kJ

[tex]E_{battery}[/tex] =  404.6895 kJ

Therefore, Electrical energy recovered in the battery is 404.6895 kJ

b)

For this electrical energy to be obtained from fuel, the chemical energy required will be;

[tex]E_{chemical}[/tex] =  [tex]E_{battery}[/tex] / 25%

[tex]E_{chemical}[/tex] =  404.6895 kJ / 0.25

[tex]E_{chemical}[/tex]  = 1618.758 kJ  

Heat energy released per mass of ethanol combustion

(Lower heating value of ethanol) is 26.7kJ/g

Now, the mass of fuel needed to generate  1618.758 kJ will be;

[tex]m_{fuel}[/tex] = 1618.758 kJ / 26.7kJ/g

[tex]m_{fuel}[/tex] = 60.63 g

[tex]m_{fuel}[/tex] = 0.0606 kg

Therefore, Mass of fuel needed to store same amount of energy in the battery is 0.0606 kg

Answer: [tex]r = \sqrt{\frac{p}{4pil}}[/tex]

Explanation:

[tex]l = \frac{p}{4pir^2} \\4pir^2l=p\\r^2 = \frac{p}{4pil} \\r = \sqrt{\frac{p}{4pil}}[/tex]

Answer:

a) The final pressure is 1.68 atm.

b) The work done by the gas is 305.3 J.

Explanation:

a) The final pressure of an isothermal expansion is given by:

[tex] T = \frac{PV}{nR} [/tex]

[tex] T_{i} = T_{f} [/tex]

[tex] \frac{P_{i}V_{i}}{nR} = \frac{P_{f}V_{f}}{nR} [/tex]

Where:

[tex]P_{i}[/tex]: is the initial pressure = 5.79 atm

[tex]P_{f}[/tex]: is the final pressure =?

[tex]V_{i}[/tex]: is the initial volume = 420 cm³

[tex]V_{f}[/tex]: is the final volume = 1450 cm³

n: is the number of moles of the gas

R: is the gas constant

[tex] P_{f} = \frac{P_{i}V_{i}}{V_{f}} = \frac{5.79 atm*420 cm^{3}}{1450 cm^{3}} = 1.68 atm [/tex]

Hence, the final pressure is 1.68 atm.

b) The work done by the isothermal expansion is:

[tex] W = P_{i}V_{i}ln(\frac{V_{f}}{V_{i}}) = 5.79 atm*\frac{101325 Pa}{1 atm}*420 cm^{3}*\frac{1 m^{3}}{(100 cm)^{3}}ln(\frac{1450 cm^{3}}{420 cm^{3}}) = 305.3 J [/tex]

Therefore, the work done by the gas is 305.3 J.

I hope it helps you!        

Answer:

The added mass will mean a longer period of oscillation.

Explanation:

The period of oscillation here is given by the formula;

T = 2π√(m/k)

Where m is mass and k is spring constant

From the equation of oscillation period above, it's obvious that when we increase the mass, the oscillation period will also increase.

Thus, the added mass will mean a longer period of oscillation.

Answer:

the speed of the electron from charge q1 is 7.17×10⁶ m/s

Explanation:

Given the data in the question;

the potential at the center of the two charges will be;

V = k( q1/(d/2) + q2/(d/2)

so we substitute

V = (9×10⁹)( (3.95×10⁻⁹/(0.39/2) + 1.80×10⁻⁹/(0.39/2)

V = 265.4 V

the potential at a distance of 10 cm from the charges will be

V = k( q1/(d1) + q2/(d2)

(d1 = 10cm = 0.1m and d2 = 39cm - 10cm = 29cm = 0.29m )

V' = (9×10⁹)( (3.95×10⁻⁹/0.1 + 1.80×10⁻⁹/0.29

V' = 411.4 V

Now, from the conservation of energy the speed of the electron from charge q1 will be;

E = ( V' - V) qe

1/2mv² = ( V' - V) qe

v² = [( V' - V) qe] / 1/2m

v =√ ([( V' - V) qe] / 1/2m)

v =√ ([2( V' - V) qe] / m)

we substitute

v =√ (2[( 411.4  - 265.4) 1.6×10⁻¹⁹] / 9.1×10³¹)

v = 7.17×10⁶ m/s

Therefore, the speed of the electron from charge q1 is 7.17×10⁶ m/s

Answer:

k = 7.84 N/m

Explanation:

We are given;

Mass hanging object; m = 0.2 kg

Extension; Δx = 0.25 m

Now, formula for the force is;

F = k•Δx

Where k is the spring constant

Since we have mass, then F = W = mg = 0.2 × 9.8 = 1.96 N

Thus;

1.96 = k × 0.25

k = 1.96/0.25

k = 7.84 N/m

s=600 m

t=12 s

s=0.5*a*t² (initial speed V0=0)

a=(2*s)/t²

a=(2*600)/12²

a≈8.33 m/s²

L= s(t2=12s)-s(t1=11s) -> (distance during the twelfth second)

L=0.5*a*(t2²-t1²)

L=0.5*((2*s)/t²)*(t2²-t1²)

L=0.5*((2*600)/12²)*(12²-11²)

L ≈ 95.83 m

Answer:

3.19*10^-24

Explanation:

the equation to find momentum is p=mv so you just multiply the mass times velocity

An electron has a mass of 9.1x10⁻³¹ kilograms. if it is traveling at a speed of 3.5x10⁶ meters/seconds then its momentum would be  3.185 ×10⁻²⁴ kgm/s.

It can be defined as the product of the mass and the speed of the particle, it represents the combined effect of mass and the speed of any particle, and the momentum of any particle is expressed in Kg m/s unit.

As given in the problem an electron has a mass of 9.1x10⁻³¹ kilograms. if it is traveling at a speed of 3.5x10⁶ meters/seconds then its momentum would be

the momentum of the electrons = mass of the electron×velocity of the electron

                                                   = 9.1x10⁻³¹ × 3.5x10⁶

                                                   = 3.185 ×10⁻²⁴ kgm/s

Thus, the momentum of the electron would be 3.185 ×10⁻²⁴ kgm/s.

To learn more about momentum from here, refer to the link;

brainly.com/question/17662202

#SPJ2

Answer:

chinawares are wrapped by paper while packaging to reduce the chances of the wares breaking when falling

Answer:

Please see below as the answer is self-explanatory.

Explanation:

Answer:

The Force that resists the motion of one object moving relative to another is Friction. Kinetic Friction Resists the motion of Moving objects, while Static friction keeps the objects from moving.

Answer:

The calculation that you then need to do is 25000 x 0.0136 = 340. You must not forget the units of speed, which here are metres per second, or m/s. Your final answer is 340 m/s.

Answer:

Endothermic, because energy is absorbed (A)

Explanation:

The reaction that take place in the instant cold pack causes the surroundings around it, including the bag that contains it. When the bag loses heat to the cold pack, the cold pack absorbs the heat, thereby causing the environment (the bag) to be cold.

Explanation:

1.

We use the equation

h = [tex]\frac{gt^2}{2}[/tex], where

h is the height traveled,

g is the acceleration due to gravity and

t is the time taken to reach height h.

We can now calculate t to be

[tex]\sqrt{\frac{2*1.2 m}{9.81 m/s^2} }[/tex]

= 0.495 s

Let v be the initial velocity of the player.

The player deaccelarates from v m/s to 0 m/s in 0.495 s at the rate of 9.81 m/s^2.

v = 9.81 m/s^2 x 0.495 s = 4.85 m/s

2.

The player takes 0.3 s to increase his velocity from 0 m/s to 4.85 m/s. So his average accelaration is

4.85 m/s / 0.3 s = 16.2 m/s^2

Answer:

particles

Explanation:

in liquids, particle are close together

Answer:

the principle of conservation of energy cannot be violated.

the correct one is: The total power is equal to the sum of the powers dissipated by the resistors.

Explanation:

The power in an electric circuit is given by

         P == I V

In a circuit with several components (resistors) the power dissipated is the current by the voltage in each resistance, by the principle of conservation of energy the current in each resistance is the same if the circuit is in series and the current is the same if The circuit is in parallel, but cannot be greater than the current supplied by the power source.

Therefore, the power dissipated by the entire circuit is the sum of the power dissipated by each part, since the principle of conservation of energy cannot be violated.

When reviewing the answers, the correct one is: The total power is equal to the sum of the powers dissipated by the resistors.

Answer and Explanation:

(a) The fre-body diagrams for each block is shown below. In the block of mass 3.60 kg, there are 3 forces acting on it: horizontal force due to the rope ([tex]F_{t}[/tex]), vertical gravitational force ([tex]F_{g}[/tex]) and vertical normal force ([tex]F_{n}[/tex]), due to the surface. Since there is no vertical movement, [tex]F_{g}[/tex] and [tex]F_{n}[/tex] cancels it out. So, for this block, net force is horizontal due to the rope [tex]F_{t}[/tex].

The block of mass m is hanging from the pulley, so there is the force of the rope ([tex]F_{t}[/tex]) and the gravitational force ([tex]F_{g}[/tex]). Both are vertical, because there is no surface "holding" block m.

(b) Since both blocks are attached to each other, the acceleration will be the same. To calculate it, we use the Second Law of Motion:

[tex]F_{r}=m.a[/tex]

[tex]a=\frac{F_{r}}{m}[/tex]

[tex]a=\frac{18.8}{3.6}[/tex]

a = 5.22

The acceleration of either block is 5.22 m/s².

(c) Block m has 2 forces acting on it: tension and gravitational force. Gravitational force is the force of attraction the Earth does over an object. It is calculated as the product of mass and gravitational acceleration, which has magnitude g = 9.8 m/s².

Suppose positive referential is going up. To determine mass:

[tex]F_{r}=m.a[/tex]

[tex]F_{t}-F_{g}=m.a[/tex]

[tex]F_{t}-m.g=m.a[/tex]

[tex]18.8-9.8m=5.22m[/tex]

[tex]15.02m=18.8[/tex]

m = 1.25

Block m has 1.25 kg.

(d) Gravitational force is also called weight. So, as described above: [tex]F_{g}=m.g[/tex].

The weight for the hanging block is

[tex]F_{g}=1.25*9.8[/tex]

[tex]F_{g}=[/tex] 12.25 N

Comparing tension and weight:

[tex]\frac{12.25}{18.8}[/tex] ≈ 0.65

We can see that, weight of the hanging block is almost 0.65 times smaller than the tension on the rope.

Answer:

Option 10. 169.118 J/KgºC

Explanation:

From the question given above, the following data were obtained:

Change in temperature (ΔT) = 20 °C

Heat (Q) absorbed = 1.61 KJ

Mass of metal bar = 476 g

Specific heat capacity (C) of metal bar =?

Next, we shall convert 1.61 KJ to joule (J). This can be obtained as follow:

1 kJ = 1000 J

Therefore,

1.61 KJ = 1.61 KJ × 1000 J / 1 kJ

1.61 KJ = 1610 J

Next, we shall convert 476 g to Kg. This can be obtained as follow:

1000 g = 1 Kg

Therefore,

476 g = 476 g × 1 Kg / 1000 g

476 g = 0.476 Kg

Finally, we shall determine the specific heat capacity of the metal bar. This can be obtained as follow:

Change in temperature (ΔT) = 20 °C

Heat (Q) absorbed = 1610 J

Mass of metal bar = 0.476 Kg

Specific heat capacity (C) of metal bar =?

Q = MCΔT

1610 = 0.476 × C × 20

1610 = 9.52 × C

Divide both side by 9.52

C = 1610 / 9.52

C = 169.118 J/KgºC

Thus, the specific heat capacity of the metal bar is 169.118 J/KgºC

Answer:

F = 75 N

Explanation:

Given that,

Mass of a sculpture, m = 150 kg

The acceleration of the sculpture, a = 0.5 m/s²

We need to find the force with which the curator pushes the sculpture.

F = ma

Substitute all the values of m and a in it.

F = 150 kg × 0.5 m/s²

= 75 N

So, the required force with which the curator pushes the sculpture is 75 N.

Answer:

Explanation:

The electron has a negative charge. Proton is positive and neutron is neutral.

Answer:

you would be better off if the car bounced backwards

Explanation:

because if the hood was dismembered than you have a high chance of very bad injury but if it is just bounced back you would have less chance of getting hurt if properly sitting and seat belted.

Answer:

Explanation:

During the first .8 s , the elevator is under acceleration . It starts from initial velocity u = 0 , final velocity v = 1.2 m /s , time = .8 s

v = u + at

1.2 = 0 +  .8 a

a = 1.2 / .8

= 1.5 m /s²

During the acceleration in upward direction , let reaction force of ground on man be R .

Net force on man = R - mg

Applying Newton's 2 nd law

R - mg = ma

R = m ( g + a )

= 72 ( 9.8 + 1.5 )

= 813.6 N .

This reaction force will be measured by spring scale , so reading of spring scale will be 813.6 N .

Answer:

Its the sum of the potential energy and the kinetic energy

Answer:

Ri = 0.8 Ω

V= 2.55 V

Explanation:

      [tex]I_{1} = \frac{V}{R_{i} + 4.3 \Omega } = 0.500 A (1)[/tex]

      [tex]I_{2} = \frac{V}{R_{i} + 9.4 \Omega} } = 0.250 A (2)[/tex]

       [tex]\frac{R_{i} + 9.4 \Omega}{R_{i} + 4.3 \Omega} = \frac{I_{1} }{I_{2}} = 2 (3)[/tex]

        ⇒  V = 2.55 V (emf of the battery)

Answer:

20 m/s. have a great day

Answer:

since v decreased by 20m/s in 5 sec, a = -4 m/s^2

assuming the 3 seconds started at t=0,

s = 30t - 2t^2

s(3) = 30(3) - 2(9) = 72m

Answer:

If A + B = C for the vector equation then substituting for B gives

A + (-A) = C = 0

The only thing that can be said about "C" is that it has zero magnitude.