the waves with the longest wavelengths in the electromagnetic spectrum are

When a man pushes a box across a floor, as he increases the force he applies horizontally to the box, then the kinetic friction remains the same.

To find the answer, we need to know about friction.

Thus, we can conclude that, kinetic friction remains the same when we increase the applied force.

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As a guy pushes a box across a floor, the kinetic friction stays constant no matter how much force is applied on the box horizontally.

We must understand friction if we are to find the solution.

We can therefore draw the conclusion that kinetic friction does not change as the applied force is increased.

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Answer: A

Explanation:

The smallest perimeter of the rectangle is of value 150 cm.

Given:

The area of the rectangle, A = 1350 cm²

Calculation:

Let the length of the rectangle be 'x'

      the breadth of the rectangle be 'y'

We know that the area of a rectangle is given as:

A = (x) × (y)  

Applying values in the above equation we get:

xy = 1350 cm²

Factorizing the value of 1350, the possible values of length and breadth of the rectangle is as listed below:

x (cm)         y (cm)

1350      ×       1

675       ×       2

450       ×       3

270       ×       5

225       ×       6

150        ×       9

135        ×       10

90         ×       15

75         ×        18

54         ×        25

50         ×        27

45         ×        30         (least possible value)

Thus, the smallest perimeter of the rectangle can be calculated as:

P = 2 (x + y)

  = 2 (45 + 30)

  = 150 cm

Therefore, the smallest perimeter that the rectangle will have is 150 cm.

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Energy in should always be equal to energy out. This is a False statement.

- Energy In: Energy put into the body in form of calories from food like fats, carbohydrates and proteins.

- Energy Out: Energy burn for basic functions of the body like beating of the heart during physical movements.

When we consume more energy but does not consume it upto its potential, the body keeps storing the excess amount of energy as body fat. Maintaining a balance between Energy In and Energy Out is important to live a healthy lifestyle since the disbalance creates problems to the body.

It is easier to accurately measure change in energy than to measure the amount of energy present.

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The work done by the pushing force is 200 J; option B.

The work done in an inclined plane is given by the formula below:

Force, F = mgsinθ + ma

where a = 0

Work done = 80 * 5 * sin 30°

Work done = 200 J

In conclusion, work done is the product of force and distance.

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The resultant magnitude and direction of the vectors are as follows:

The resultant magnitude and direction of the vectors are as follows:

A. A = √(5.7² + 3.4²)

A = 6.6

θ = tan⁻¹(3.4/5.7)

θ = 30.8° from the x-axis

B. B = √{(-10)² + (-3²)}

B 10.4

θ = tan⁻¹(3/10) + 180

θ = 16.7° + 180°

θ = 196.7° from the x-axis

C. C = √{(12)² + (-20²)}

C = 23.3

θ = 360° - tan⁻¹(20/12)

θ = 300° from the x-axis

D. D = √{(-30)² + (27²)}

D = 40.4

θ = 180 - tan⁻¹(27/30)

θ = 138° from the x-axis

E. E = √{(48)² + (12²)}

E = 49.5

θ = 360° - tan⁻¹(12/48)

θ = 346° from the x-axis

In conclusion, the resultant of the vectors and direction are obtained using the resultant vector formula.

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b) internal energy drives plate motion

Lithospheric plates are part of a planetary scale thermal convection system. The energy source for plate tectonics is Earth’s internal heat while the forces moving the plates are the “ridge push” and “slab pull” gravity forces.

A tectonic plate (also called lithospheric plate) is a massive, irregularly shaped slab of solid rock, generally composed of both continental and oceanic lithosphere.

The motion of tectonic plates is driven by convection in the mantle. Convection: The process of heat transfer from one part of a fluid to another part by the actual movement of the particles of the fluid is called convection. Liquid and gases are heated by the process of convection.

In simple terms, convection is the idea that dense, cold things sink, and buoyant, warm things rise. In the earth the cold sinking things are slabs (subducting plates) and the warm things are plumes, or just rising material from deeper in the mantle.

hence , correct option is b) internal

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Several short trips taken from a cold start can use ...twice... as much fuel as a longer multi-purpose trip covering the same distance when the engine is warm.

In cold weather, properly designed gasoline aids in engine starting, while in hot weather, it helps prevent vapor lock. In order to meet the requirements of a modern engine, the fuel must have the volatility for which the engine's fuel system was built and an antiknock quality strong enough to prevent knock during routine operation.

During the intake phase, the air and fuel are combined before being introduced into the cylinder. The spark ignites the fuel-air mixture after the piston compresses it, resulting in combustion. During the power stroke, the piston is propelled by the expansion of the combustion gases.

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The tidal volume which typically maintains normal oxygenation and elimination of carbon dioxide is 8 to 10 ml/kg of body mass.

Tidal volume refers the amount of air that moves in and out of the lungs in one respiratory cycle.

During a respiratory cycle, oxygen moves into the lungs and the tissues during inhalation, while carbon dioxide moves out of the lungs during exhalation.

The continuous outward movement of carbon dioxide and inward movement of oxygen ensures that the body maintains homeostasis and internal or tissue respiration continues.

The normal tidal volume is about 500 ml per inspiration or 7 ml/kg of body mass.

However, for normal oxygenation and elimination of carbon dioxide, a tidal volume of about 8 to 10 ml/kg of body mass is required.

In conclusion, the tidal volume is a measure of the amount of air flow in the lungs for each respiratory cycle.

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The time taken for the athlete to finish the race is 20 s (Option A)

Power is simply defined as the rate at which work is done. It can be expressed mathematically as

Power (P) = work (W) / time (t)

But

Work = weight × distance

Therefore,

Power = (weight × distance ) / time

Power = (weight × distance ) / time

5400 = (539 × 200) / t

5400 = 107800 / t

Cross multiply

5400 × t = 107800

Divide both side by 5400

t = 107800 / 5400

t = 20 s

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The work done delivered by the Carnot engine is 93.75 J.

Solution:

[tex]T_c = 260 K\\ T_h = 320K\\ Q_h = 500J[/tex]

As we know that Carnot engine is ideal, the efficiency depends only on the temperature of the reservoirs(in kelvin scale):

[tex]n = 1 - \frac{T_c}{T_h} \\n = 1 - \frac{260}{320}[/tex]

[tex]n = 1- 0.8125\\n = 0.1875[/tex]

Also, we know that the work done is equal to product of efficiency and heat at hot reservoir:

[tex]W = n\times Q_h\\W = 0.1875 \times 500\\W = 93.75 J[/tex]

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Answer:if youre looking for the weight of the thermas in genral it should be 500n

Explanation:using the formula w=mg

w=500x10

giving us 500 newtons which is the weight.

A new CFD method for determination of translational is RANS simulations

Using numerical analysis and data structures, the field of computational fluid dynamics (CFD) studies and resolves issues involving fluid flows. The computations necessary to model the fluid's free-stream flow and its interactions with surfaces constrained by boundary conditions (both liquids and gases) are done on computers. Better answers can be found using high-speed supercomputers, which are frequently needed to address the most challenging issues.

Five prominent CFD methods -

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Answer:

Virgo will be the highest zodiac constellations at night.

Earth's magnetic field and molten metallic outer core creates barrier to stop Sun's radiation to strip away our atmosphere.

As we know that inside the earth there are several layers of the earth. The outer one is the Earth's crust which is all the ground we have , then we have the mantle that consist upper and lower crust. And then after we have outer and inner crust.

The outer core is made of molten material that consist of mainly iron and other ferrous metals. The core is important for many reasons-

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The way to perform the experiment is illustrated below.

Place each straw tightly without deforming the roundness of the straw into the corner of the set square.

Measure the distance from the corner of the set square to where the straw touches the set square using the 30 cm ruler. This will be the radius of each straw.

Multiply this radius by 2 in order to obtain the diameter of each straw.

Sum the diameter of each of the 10 straws.

Divide this sum by 10 to obtain the average value for the diameter of a straw.

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The threshold frequency for sodium metal is

5.49 x 10^14 s-1

Given:

photon with frequency = 6.66 × 10^14 s−1

kinetic energy = 7.74 × 10−20 j

To Find:

threshold frequency

Solution: The threshold frequency is defined as the minimum frequency of incident radiation below which the photoelectric emission is not possible completely. irrespective of the intensity of incident radiation

We know, relation between threshold frequency, kinetic energy and frequency s given by :

K.E = hv - hvo

Here h is plank's constant and vo, is threshold frequency.

Putting all these value in above equation we get:

7.74 x 10^-20 = (6.66 × 10^14-vo) x 6.626 x 10^-34

vo = 5.49 x 10^14 s^-1

Hence, the threshold frequency for sodium metal is 5.49 x 10^14 s-1

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The ball is travelling faster when the two objects hits the level ground below.

The time of motion of the objects depends on height and initial velocity of projection of the objects.

The stone has no initial vertical velocity while the ball has initial vertical velocity.

Thus, the ball is travelling faster when the two objects hits the level ground below.

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The steps which enhance strengths and address limitations as a coach include:

This is referred to a professional who gives special training about a particular subject or topic.

It is best to identify weakness and work towards improvement through determination and consistency.

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Answer: Increases, decreases

Explanation:

As the volume of a chamber decreases the pressure inside the chamber increases. As the volume increases the pressure decreases

The amount of work done during the lifting process is 4465.125 J and our average power will be 42.525 W.

Given:

Depth of the well, h = 22.5m

Mass of heavy-duty steel chain, M = 17.9 kg

The combined mass of the water and bucket, m = 11.3 kg

time taken to raise the bucket out of the water, T = 1.75 min = 105 s

Calculation:

Consider that the center of mass of the steel chain is at the midpoint of the depth of the well.

Now, the work done during the lifting process can be calculated as:

W.D = (Work done in lifting bucket filled with water) + (work done to lift    

                                                                                              the steel chain)

W.D = mgh + Mg (h/2)      -( 1 )

where g is the acceleration due to gravity

Applying values in the above equation we get:

W.D = mgh + Mg (h/2)

       = (11.3 kg)(9.8 m/s²)(22.5 m) + (17.9 kg)(9.8 m/s²)(22.5 m / 2)

       = 2491.65 + 1973.475

       = 4465.125 J

We know that the average power is given as:

P_avg = W.D / T     - ( 2 )

where W.D is the work done during the lifting process

            T is the time taken to raise the bucket out of the well

Applying values in the above equation, we get:

P_avg = W.D / T

           = (4465.125 J)/(105 s)

           = 42.525 W

Therefore, the amount of work done during the lifting process is 4465.125 J and our average power will be 42.525 W.  

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sorry for the late reply back I have been working on this project for a year now so it will not care if we can get the best of him and also has a full one of the most common misconceptions is that Africa is one large country and its followers are known as Sikhs and is the last survivor from the whole family and the fearful of all that is a metaphor of joy organised by the way I have

The change in potential along a path from C to D due to a small charged sphere is 900 V.

Given:

Charge, Q = 3 nC = 3 × 10⁻⁹ C

Distance between the sphere and point C, r₁ = 0.02 m

Distance between the sphere and point D, r₂ = 0.06 m

Calculation:

We know that the electric potential is given as:

V = k Q/r   - (1)

where, V is the electric potential

            k is Coulomb's force constant

            Qis the charge on the  sphere

            r is the  separation distance

The electric potential at point C due to charged sphere can be given as:

V₁ = k Q/r₁

   = (9×10⁹ Nm²/C²) [(3 × 10⁻⁹ C)/(0.02 m)]

   = 1350 V

The electric potential at point D due to charged sphere can be given as:

V₂ = k Q/r₂

   = (9×10⁹ Nm²/C²) [(3 × 10⁻⁹ C)/(0.06 m)]

   = 450 V

Now, the change in potential along the path from C to D can be calculated as:

ΔV = V₂ - V₁

     = 450 V - 1350 V

     = -900 V

The negative sign indicates that the work is done against the electric field in moving the charge from C to D.

Therefore, the change in potential along a path from C to D is 900 V against the direction of the electric field.

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[tex] {\qquad\qquad\huge\underline{{\sf Answer}}} [/tex]

Here we go ~

[tex]\qquad \sf  \dashrightarrow \:E = \dfrac{hc}{\lambda} [/tex]

here,

____________________________________

[tex]\qquad \sf  \dashrightarrow \: E = \cfrac{1.99 \times 10 {}^{ - 25} }{7 \times 10 {}^{ - 12} } [/tex]

[tex]\qquad \sf  \dashrightarrow \: E= \cfrac{1.99}{7} \times 10 {}^{ (- 25 + 12)} { } [/tex]

[tex]\qquad \sf  \dashrightarrow \:E= 0.284 \times 10 { }^{ - 13} [/tex]

[tex]\qquad \sf  \dashrightarrow \: E= 2.84 \times 10 { }^{ - 14\:\; } J\: \: [/tex]

so, correct choice is A

The substance, if eliminated, that would completely prevent the greenhouse effect from occurring on earth is fossil fuels (option C).

Greenhouse effect is the process by which a planet is warmed by its atmosphere.

Greenhouse effect is caused by greenhouse gases that deplete the ozone layer.

Fossil fuels, when burned, will release greenhouse gases such as carbon etc. to the atmosphere.

Therefore, the substance, if eliminated, that would completely prevent the greenhouse effect from occurring on earth is fossil fuels.

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If a star appears to move relative to other stars over a one-year period, this motion is due to the star's true space motion.

What is the proper motion of stars?

Proper motion is the angular change in position of a star across our line of sight, measured in arc seconds per year, and symbolized with the letter  μ.

Proper motion is generally measured by measuring the movement of the image of a star with respect to more distant background stars over that time period.

Here we are told that star appears to move relative to other stars over 1 year period.

So we know that,

True space motion is the annual apparent motion of a star across the sky.

True Space Motion is Combination of radial velocity, proper motion, and distance.

Hence,

If a star appears to move relative to other stars over a one-year period, this motion is due to the star's true space motion.

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Water bends in the same direction irrespective of the charge of the rod placed near it is because water is dipole- that hydrogen is positively charged and oxygen is negatively charged and thus either of the particle is attracted by the charged rod.

The reason behind it:

As a neutral substance, water has an equal number of positive and negative charges. The negatively charged electrons migrate away from the negatively charged rod and the positively charged protons move toward the rod when the negatively charged rod is placed closer to the water. Water then adheres to the rod. Protons migrate away from the positively charged rod, just as they do when it is moved closer to the water, while electrons flow in its direction. As a result, the water and rod form a relationship.

The partial +ve charge on H is drawn to the -ve charged rod when it is installed, which causes the water stream to bend in the direction of the charged rod.

The partial -ve charge on O is drawn to the +ve rod when it is installed, causing the water stream to bend in the direction of the rod.

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The thicker wire has one-fourth the resistance of the thinner wire.

The characteristic of a substance that prevents the flow of current is known as resistance. The free electrons begin to move in a specific direction when a voltage is applied across the conductor. These electrons collide with atoms or molecules as they move, creating heat in the process. These atoms or molecules prevent free electrons from moving through a substance. Resistance is represented by the symbol R.

Specific resistance is another name for resistivity. A substance with certain dimensions, such as one meter in length and a cross-sectional area of one square meter, has a resistance that is represented by its resistivity. Resistivity or specific resistance is represented by ρ.

The relation between resistance R and resistivity ρ is given as:

                                              R = ρL/A

where,

R = resistance of the conductor

ρ =  resistivity of the material

L = length of the conductor

A = cross-sectional area of the conductor

Given,

r₁ = 2r₂

L₁ = L₂

where

r₁ = radius of the first conductor

r₂ = radius of the second conductor

L₁ = length of the first conductor

L₂ = length of the second conductor

To find

R₁/R₂ =?  (the ratio of R₁ and R₂)

If the radius is twice the other then the area will become,

A₁ = π r₁²

A₂ = π r₂²

A₁ = π (2r₂)²

   = 4π r₂²

Therefore,

A₁ = 4 A₂

Now put the values in the formula,

R = ρL/A

R₁/R₂ = ρ L₁ A₂/  ρ L₂ A₁

R₁/R₂ = L A₂/ L (4A₂)

R₁/R₂ = 1/4

R₁ = R₂/4

Hence, the thicker wire with twice the radius of the thin wire has one-fourth the resistance of the thinner wire.

I understand the question you are looking for is this:

How do the resistances of two conducting wires compare if they have the same length, but one is twice the radius of the other?

(a) The thicker wire has half the resistance of the thinner wire

(b) The resistance is the same in both wires

(c) The thicker wire has one-fourth the resistance of the thinner wire

(d) The thicker wire has twice the resistance of the thinner wire.

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The rate of change of the current in the larger inductor is 0.3mA/s.

To find the answer, we need to know about the relation between the emf and inductance.

Thus, we can conclude that the rate of change of the current in the larger inductor is 0.3mA/s.

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A. The average force exerted on the ball during the serve is 57 N

B. The resistive force, given the data is -1125 N

F = ma

F = 0.057 × 1000

F = 57 N

F = m(v – u) / t

F = 3000(5 – 20) / 40

F = -1125 N

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