The Washington High key club is selling brownies and chocolate chip cookies to raise money. Their table only has room for 100 baked goods. Previous bake sells has taught them to plan to bake at most 30 brownies and at least 50 cookies. Write and graph a system of inequalities to represent the possible number of baked goods.

Answer: Yes

Step-by-step explanation:

A: 12 minutesAnswer to B: 36 minutesAnswer to C:

Answer:

20% of the invited people did not attend

Step-by-step explanation:

5 out of 25 people invited didn't attend Glen's party. That means the following:

[tex]\frac{5}{25}[/tex]  people didn't come which simplifies to  [tex]\frac{1}{5}[/tex]

Multiply [tex]\frac{1}{5}[/tex] by the giant one [tex]\frac{20}{20}[/tex] so the denominator is 100 which is the denominator used to find percentages.

You end up with [tex]\frac{20}{100}[/tex]

[tex]\frac{20}{100}[/tex] = 20%

20% is the percentage of the people whom Glen invited did not attend the party.

To find the percentage of people who did not attend the party, we will divide the number of people who did not attend (5) by the total number of people invited (25), and then multiply by 100.

Percentage = (Number of people not attended / Total number of people invited) × 100

Percentage = (5 / 25) × 100

Percentage = 20%

So, 20% of the people whom Glen invited did not attend the party.

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Answer:

4 pounds

Step-by-step explanation:

when you match it on the graph it corresponds to 4

steps

match 18 which is in between 16 and 20 to the weight and you will see it moves and is correspondence to 4

Answer:

help please, i’m struggling on this

Let

[tex]\displaystyle y(x) = \sum_{n=0}^\infty a_nx^n = a_0 + a_1x + a_2x^2 + \cdots[/tex]

Differentiating twice gives

[tex]\displaystyle y'(x) = \sum_{n=1}^\infty na_nx^{n-1} = \sum_{n=0}^\infty (n+1) a_{n+1} x^n = a_1 + 2a_2x + 3a_3x^2 + \cdots[/tex]

[tex]\displaystyle y''(x) = \sum_{n=2}^\infty n (n-1) a_nx^{n-2} = \sum_{n=0}^\infty (n+2) (n+1) a_{n+2} x^n[/tex]

When x = 0, we observe that y(0) = a₀ and y'(0) = a₁ can act as initial conditions.

Substitute these into the given differential equation:

[tex]\displaystyle \sum_{n=0}^\infty (n+2)(n+1) a_{n+2} x^n - \sum_{n=0}^\infty a_nx^n = 0[/tex]

[tex]\displaystyle \sum_{n=0}^\infty \bigg((n+2)(n+1) a_{n+2} - a_n\bigg) x^n = 0[/tex]

Then the coefficients in the power series solution are governed by the recurrence relation,

[tex]\begin{cases}a_0 = y(0) \\ a_1 = y'(0) \\\\ a_{n+2} = \dfrac{a_n}{(n+2)(n+1)} & \text{for }n\ge0\end{cases}[/tex]

Since the n-th coefficient depends on the (n - 2)-th coefficient, we split n into two cases.

• If n is even, then n = 2k for some integer k ≥ 0. Then

[tex]k=0 \implies n=0 \implies a_0 = a_0[/tex]

[tex]k=1 \implies n=2 \implies a_2 = \dfrac{a_0}{2\cdot1}[/tex]

[tex]k=2 \implies n=4 \implies a_4 = \dfrac{a_2}{4\cdot3} = \dfrac{a_0}{4\cdot3\cdot2\cdot1}[/tex]

[tex]k=3 \implies n=6 \implies a_6 = \dfrac{a_4}{6\cdot5} = \dfrac{a_0}{6\cdot5\cdot4\cdot3\cdot2\cdot1}[/tex]

It should be easy enough to see that

[tex]a_{n=2k} = \dfrac{a_0}{(2k)!}[/tex]

• If n is odd, then n = 2k + 1 for some k ≥ 0. Then

[tex]k = 0 \implies n=1 \implies a_1 = a_1[/tex]

[tex]k = 1 \implies n=3 \implies a_3 = \dfrac{a_1}{3\cdot2}[/tex]

[tex]k = 2 \implies n=5 \implies a_5 = \dfrac{a_3}{5\cdot4} = \dfrac{a_1}{5\cdot4\cdot3\cdot2}[/tex]

[tex]k=3 \implies n=7 \implies a_7=\dfrac{a_5}{7\cdot6} = \dfrac{a_1}{7\cdot6\cdot5\cdot4\cdot3\cdot2}[/tex]

so that

[tex]a_{n=2k+1} = \dfrac{a_1}{(2k+1)!}[/tex]

So, the overall series solution is

[tex]\displaystyle y(x) = \sum_{n=0}^\infty a_nx^n = \sum_{k=0}^\infty \left(a_{2k}x^{2k} + a_{2k+1}x^{2k+1}\right)[/tex]

[tex]\boxed{\displaystyle y(x) = a_0 \sum_{k=0}^\infty \frac{x^{2k}}{(2k)!} + a_1 \sum_{k=0}^\infty \frac{x^{2k+1}}{(2k+1)!}}[/tex]

Answer:

[tex]f(x) = \left \{ {{x + 3} \quad \text{if} \ -3 \leq x < -1\atop {5} \quad \text{if} \ -1 \leq x \leq1} \right.[/tex]

Step-by-step explanation:

You can find the first function if you know the general form of a line:

[tex]y = mx + b[/tex]

where [tex]m[/tex] is the slope and [tex]b[/tex] the intercept point with the [tex]y[/tex]-axis.

So in the first case the slope is 1 because the next formula

[tex]m = \frac{\Delta y}{\Delta x} = \frac{y_2 - y_1}{x_2 - x_1} = \frac{2-0}{-1+3} = 1[/tex]

And you can find the interception point if extend the line, then in our case is  3.

So the function is:

[tex]f(x) = x + 5[/tex]

In the other case is constant function that's mean that the function has the next form

[tex]f(x) = k[/tex]

Where [tex]k[/tex] is a constant.

So you only have to observe what is the value for each point in the interval, in this occasion is 5.

So the final answer is:

[tex]f(x) = \left \{ {{x + 3} \quad \text{if} \ -3 \leq x < -1\atop {5} \quad \text{if} \ -1 \leq x \leq1} \right.[/tex]

Answer:

i think 9900

Step-by-step explanation:

225x20 = 4500

180x30 = 5400

5400+4500 = 9900

Answer:

7.9000000÷96

=0.0822916667

Answer:

the answer is c

Step-by-step explanation:

u welcome

The value of r in terms of other variables in the given right triangle using the Pythagoras theorem can be shown as r = √(t² - s²).

According to the Pythagoras Theorem, in a right triangle, the square of the hypotenuse is equal to the sum of the squares of the legs.

In the question, we are shown a right triangle with the hypotenuse as t, and the legs as r and s.

We are asked to solve for r in terms of other variables.

By Pythagoras theorem in the given right triangle, we can say that:

r² + s² = t², which is the required equation.

To solve for r in terms of other variables, we do as follows:

r² + s² = t²,

or, r² + s² - s² = t² - s² {Subtracting s² from both sides of the equation},

or, r² = t² - s² {Simplifying},

or, r = √(t² - s²) {Square rooting both sides of the equation}.

Thus, the value of r in terms of other variables in the given right triangle using the Pythagoras theorem can be shown as r = √(t² - s²).

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Check the picture below.

Answer:

then z is a factor of x??? huh??

Answer:

-23 over 10

Step-by-step explanation:

Hope this helped :)

Answer:

253/20

Step-by-step explanation:

(−2 1/5) × (−5 3/4) =

1. change both mixed numerals into fractions.

= -11/5 × (-23/4)

2. Since both numbers are negative, the product is positive. Multiply both numerators together. Multiply both denominators together.

= 253/20

253 is the product of 2 prime numbers, 11 and 23. 20 is the product of 2² and 5. There are no common factors in the numerator and denominator, so this fraction cannot be reduced.

Answer: 253/20

Check the picture below.

Answer:

the answer is 24.23 $ thats what i got

Answer:

A. 2.11 and  B. 26.39+2.11=28.50

Step-by-step eplanation:

Answer:

(c) The effect of a larger sample size on the margin of error is that the margin of error will increase.

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

it is the opposite of A, which is true, as |-8| = 8

Answer:

$12.70

Step-by-step explanation:

8 x .25 = 2

2 x 2.55 = 5.10

1 x 2.45 = 2.45

1 x 3.15 = 3.15

__________

2 + 5.10 + 2.45 + 3.15 = 12.70 = $12.70

Answer:

they spent $15.85 in all.

Step-by-step explanation:

2.00 banana 5.10 bread 2.45 oj and 3.15 egg, add it all.

Answer:

3,280/38650 x 100% = 8%

[tex]\int {12x+5} \, dx[/tex]

For this problem, let's first apply the intergral sum rule.

[tex]\int {12x+5} \, dx = \int{12x} \, dx + \int{5}x \,dx[/tex]

Then, we'll use the reverse power rule on each of these integrals.

[tex]\int{12x} \,dx = 6x^2+C[/tex]

[tex]\int{5} \,dx = 5x+C[/tex]

So the indefinite integral of [tex]\int{12x+5} \,dx[/tex] is [tex]6x^2+5x+C[/tex].

Remember that we need our constant of integration, [tex]C[/tex], because of if we take the derivative of a constant, it'll be 0.

Hope this helps!

Hi there!

[tex]\int\limits {12x+5} \, dx[/tex]

Recall the following rules:

[tex]\int\limits {x^n} \, dx = \frac{x^{n+1}}{n+1}[/tex]

Use this rule to evaluate. Remember to include the constant:

[tex]\int\limits {12x+5} \, dx = \frac{12x^{1+1}}{1+1} + 5x +C[/tex]

[tex]\int\limits {12x+5} \, dx = 6x^2 + 5x + C[/tex]

Answer:

32 muffins

Step-by-step explanation:

one cup of milk will make 32 muffins

you can set up a proportion of milk/muffins = milk/muffins

let 'x' = number of muffins made from one cup of milk

5/8 ÷ 20 = 1 ÷ x

cross-multiply to get 5x = 20(8)

5x = 160

x = 32

Answer:

2. d. 0.0008

3. b. 0.07

4. c. thousandths

5. c. 0.005

=5/3   =−1

Once in standard form, identify a, b, and c from the original equation and plug them into the quadratic formula.

Using the probability concept, it is found that there is a [tex]\mathbf{\frac{1}{k}}[/tex] probability that “Relaxation Through Mathematics” is first to review.

A probability is given by the number of desired outcomes divided by the number of total outcomes.

In this problem:

The probability is:

[tex]p = \frac{D}{T} = \frac{1}{k}[/tex]

A similar problem is given at https://brainly.com/question/24483829

This is the answer which is not right because this is for points...

Answer:

Step-by-step explanation:

No . B'  (reflection of B) and C' (reflection of C) are in the right position,  but D' should be at  (4, 1) and A' should be at (-2,-4).

Answer:2422728

Step-by-step explanation: