the volume of one mole of a substance is 22.4 L at STP for all what​

Answer:

Explanation:

B

Answer:

The answer to the question is orbit

Answer:

This is False.

Explanation:

Acid=0-6

Neutral=7

Base=8-14

Answer:

approximately 15.1 grams.

Explanation:

The key to chemistry is to change everything to moles. Then when you have the answer in moles change the answer back to grams, liters, or whatever you want.

change 25 grams of potassium chlorate to moles.

calculate the gram molecular mass of potassium chlorate.

Chlorate is Cl with 3 oxygens. ate = saturated. Chlorine has seven valance electrons when it is saturated six of these electrons are used by oxygen ( 2 electrons per oxygen) leaving only 1 electron.

1 K x 39 grams/mole

+1 Cl x 35.4 grams/ mole

+3 O x 16 grams/ mole

= 122.4 grams / mole Potassium Chlorate

25

122.4

= moles.

2.05 moles of Potassium Chlorate.

There is a 1:1 mole ratio. 1 mole of Potassium Chlorate will produce 1 mole of Potassium Chloride.

2.05 moles of Potassium Chlorate will produce 2.05 moles of Potassium Chloride.

Find the gram molecular mass of Potassium Chloride.

1 K x 39 = 39

+1 Cl x 35.4 = 35.4

= 74.4 grams / mole.

2.05 moles x 74.4 grams/ mole = 15.2 grams

Hope it helps :)

Answer:

9.79g of O2

Explanation:

So this question you are trying to go from g of KCLO3 to grams of oxygen. There is no direct conversion so you have to utilize multiple process.

[tex]25.0g KCLO3 * \frac{1mol KCLO3}{122.55 gKCLO3} * \frac{3mol O2}{2 mol KCLO3} * \frac{32.00g O2}{1mol O2}[/tex]

=9.79 g of O2

So first you go from g of KCLO3 to moles of KCLO3  by using molar mass of KCLO3. Then you use mol:mol ratio from balanced equation to go to moles of O2, and finally use molar mass of O2 to go to grams of O2.

Answer: Removing Products, Adding Products, Changes in Volume and Pressure, and Changes in Temperature

Answer:

1.00 mol

71.0g P4 0 10          1mol p4 0 10              4 moles H3 PO4

____________  x  ___________    x     ______________

      1                     283.886g P4 0 10           1mol P4 0 10

= 1.00 moles H3 PO4

1.00 moles of H₃PO₄ are produced

Given:

Mass of P₄O₁₀ = 71.0 g

To find:

Moles of H₃PO₄ = ?

Balanced chemical reaction:

P₄O₁₀(s) + H₂O(l) → H₃PO₄(aq)

Molar mass of P₄O₁₀ = 283.866 g or 284 g

Number of moles is defined as given mass over molar mass.

[tex]\text{Moles of } H_3PO_4= \frac{71.0 g P_4O_{10}}{1} \times \frac{1 mol P_4O_{10}}{283.886 g P_4O_{10}} \times \frac{4 moles H_3PO_4}{1 mol P_4O_{10}} \\\\\text{Moles of } H_3PO_4= 1.00 mol[/tex]

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Answer:

Complete ionic equation

Explanation:

For every reaction, we could write the molecular equation as well as the ionic equation. The net ionic equation only shows the reaction of the main ions that take part in the reaction. It does not show the reaction of spectator ions.

In order to write the complete ionic equation for any reaction, we must observe the following steps;

We have to start by writing a balanced molecular equation for that particular reaction. Secondly, we split up the soluble strong electrolytes solutions into their constituent ions. It is necessary to indicate the correct formula and charge for each ion participating in the reaction. The individual stoichiometric coefficients of each ion is used toindicate the correct number of all the participating ions. All compounds formed during the reaction are noted with the appropriate symbols (s) for solid, (l) for liquid, or (g) for gaseous respectively.

Explanation:

B. sound waves can diffract.

....,........

2

Explanation:

50/50 chance of getting correct

Answer:

yes ,it is a physical change

Explanation:

because physical change can be reversed which means that boiling water can be reversed back

Answer:refer to the image below

Answer:

5000 nL

Explanation:

Answer: 5000 nL

Explanation:

When it is tilted away from the Sun, it is winter in the northern hemisphere. In between we have autumn and spring. The day that the Earth's North Pole is tilted closest to the sun is called the summer solstice. This is the longest day (most daylight hours) of the year for people living in the northern hemisphere.

Answer:

13,200 mL

Explanation:

multiply by 1000 to go from L to mL

Simulating Earth's gravity in space would be challenging, but it is possible to create artificial gravity using centrifugal force. Centrifugal force is the outward force experienced by an object that is moving in a circle.

An unobservable force that draws things together. Anyone remains on the ground thanks to Earth's gravity, which also causes objects to fall.

One way to create artificial gravity in space is by building a rotating space station. The station would consist of two main parts: a central hub and a rotating section.

The hub would contain the crew quarters, life support systems, and other essential components, while the rotating section would be attached to the hub via a set of cables or other structures.

The rotating section would be set spinning, creating centrifugal force that would push the crew towards the outer rim of the section. This force would create a sensation of gravity that would be similar to that experienced on Earth.

Thus, by rotating a spacecraft, it is possible to create a centrifugal force that mimics the gravitational force of Earth.

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Answer:

a. 1.01 molar solution

Explanation:

Now we have to recall the formula;

n= CV

Where

n= number of moles of magnesium oxide

C= concentration of magnesium oxide solution = ???

V= volume of magnesium oxide solution= 365 ml

But;

n= m/M

Where;

m= given mass of magnesium oxide= 14.2 g

M= molar mass of magnesium oxide= 40.3044 g/mol

Substituting values;

14.2g/40.3044 g/mol = C×365/1000

0.3523= 0.365 C

C= 0.3523/0.365

C= 0.965

C= 1.00 molar (approx)

Answer:

Option A. 1.01 molar solution

Explanation:

Step 1:

Data obtained from the question. This include the following:

Mass of MgO = 14.92g

Volume of solution = 365mL

Molarity of solution =.?

Step 2:

Determination of the number of mole present in 14.92g of MgO.

This is illustrated below:

Mass of MgO = 14.92g

Molar mass of MgO = 24.3 + 16 = 40.3g/mol

Number of mole MgO =...?

Mole = Mass /Molar Mass

Number of mole of MgO = 14.92/40.3 = 0.370 mole

Step 3:

Determination of the molarity of the solution.

This can be obtained as follow:

Mole of MgO = 0.370 mole

Volume = 365mL = 365/1000 = 0.365L

Molarity =..?

Molarity = mole /Volume

Molarity = 0.370/0.365

Molarity = 1.01M

Answer:

Toxicity is how much something can harm you, like poison. A quick example of this is rat poison. You can put it in traps to kill rats, but if you ingest it it'll also kill you. Also, tide pods are perhaps a more relevant example.

Answer:

-1, -4

Explanation:

[tex]x^2+4x+5=0[/tex]

Factoring, you get:

[tex](x+4)(x+1)=0[/tex]

To find what x can be, you need to realize what could make this equation true. To set the left side equal to 0, either one of the terms in parentheses must be equal to 0. To do that, x must be the negative of the other term, so that they can cancel each other out. Therefore, x is -4 and -1. Hope this helps!

Answer:

-1,-4

Explanation:

Answer:

It does this by using a thermal conductor (usually metal) to carry heat away from the processor into fins that expose a high amount of surface area to moving air. This allows the air to be heated, thus cooling the heat sink and the processor as well.

Answer:

= 2.33 L

Explanation:

V1/T1 = V2/T2

V1 = 3.0 L

T1 = 78 + 273

   = 351 K

At s.t.p the temperature is 273 K and pressure is 1 atm.

V2 = ?

T2 = 273 K

V2 = V1T2/T1

    = (3.0 ×273)/351

    = 2.33 L

Explanation:

ik it is confusing but that is what i got

Answer:

Thanks

Explanation:

Answer:

c

Explanation:

took it

Answer:

One mole of SnO2

Explanation:

SnO2(s) + 2H2(g) ------> Sn(s) + 2H2O(l)

In every question that has to do with stoichiometry, the balanced reaction equation is the first step towards obtaining the correct answer because it serves as a guide in solving the question.

From the balanced reaction equation, we have

1 mole of SnO2 reacts with 2 moles of hydrogen gas to yield two moles of water.

The balanced reaction equation represents one mole of SnO2.

Hence the answer.

Answer:smoke

Explanation:smoke is a gas

Answer:

Both are only physical changes

Explanation:

Sediment settling to the bottom of a muddy puddle is a physical change and a puddle freezing into ice on a cold night is also a physical change. Both are only physical changes.

Physical changes are those changes in which substance changes physical properties only. Properties like temperature, pressure, shape, color, size, state (solid, liquid and gas). These changes are temporary in nature. In physical change no new substances formed. It is reversible change. Sediment settling to the bottom of a muddy puddle is a physical change and a puddle freezing into ice on a cold night is also a physical change. Both are only physical changes.  

Chemical change are those changes in which substance changes chemical composition. These changes are permanent changes. In chemical change new substances formed and in chemical change substances can not get back into its original form. It is irreversible change. Sediment settling to the bottom of a muddy puddle and a puddle freezing into ice on a cold night both are not chemical changes as there is no new substances formed.

Thus, from the above conclusion we can say that Sediment settling to the bottom of a muddy puddle and a puddle freezing into ice on a cold night both are only physical changes.

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Answer: The gas would occupy volume of 221 ml at STP

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

[tex]\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex]

where,

[tex]P_1[/tex] = initial pressure of gas = 720 torr

[tex]P_2[/tex] = final pressure of gas = 760 torr (at STP)

[tex]V_1[/tex] = initial volume of gas = 250 ml

[tex]V_2[/tex] = final volume of gas = ?

[tex]T_1[/tex] = initial temperature of gas = [tex]20^oC=273+20=293K[/tex]

[tex]T_2[/tex] = final temperature of gas = [tex]273K[/tex]   (at STP)

Now put all the given values in the above equation, we get:

[tex]\frac{720\times 250}{293}=\frac{760\times V_2}{273}[/tex]

[tex]V_2=221ml[/tex]

The gas would occupy volume of 221 ml at STP

Answer:

ants and flys

Explanation:

26.3 grams of calcium carbonate must be decomposed to produce 5.00 L of carbon dioxide at 901 mmHg and [tex]0^0C[/tex]

Explanation:

According to ideal gas equation:

[tex]PV=nRT[/tex]

P = pressure of gas = 901 mm Hg = 1.18 atm   (760 mm Hg = 1 atm)

V = Volume of gas = 5.00 L

n = number of moles = ?

R = gas constant =[tex]0.0821Latm/Kmol[/tex]

T =temperature =[tex]0^0C=(0+273)K=273K[/tex]

[tex]n=\frac{PV}{RT}[/tex]

[tex]n=\frac{1.18atm\times 5.00L}{0.0821L atm/K mol\times 273K}=0.263moles[/tex]

The chemical reaction for the decomposition of calcium carbonate follows the equation:

[tex]CaCO_3(s)\rightleftharpoons CaO(s)+CO_2(g)[/tex]

According to stoichiometry:

1 mole of carbon dioxide is produced by = 1 mole of calcium carbonate

Thus 0.263 moles of carbon dioxide is produced by = [tex]\frac{1}{1}\times 0.263=0.263[/tex] moles of calcium carbonate

Mass of calcium carbonate=[tex]moles\times {\text {Molar mass}}=0.263mol\times 100g/mol=26.3g[/tex]

26.3 grams of calcium carbonate must be decomposed to produce 5.00 L of carbon dioxide at 901 mmHg and [tex]0^0C[/tex]