The worth of the car after it is paid off 5 years later given the rate of exponential depreciation is $32,842.34.
What is the worth of the car?When the car declines in value, it means that the car is depreciating. The formula that can be used to determine the value of the car with the depreciationn rate is:
FV = P (1 - r)^n
FV = Future value P = Present value R = rate of decline N = number of years$42,000 x (1 - 0.048)^5 = $32,842.34
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Find the measure of the missing angle
The two angles form a straight line and need to equal 180 degrees
180 - 61 = 119
The missing angle is 119 degrees
The school band sells carnations on Valentine's Day for $3 each. It buys the carnations from a florist for $0.50 each, plus a $15 delivery charge. When will the cost of the carnations be equal to the revenue from selling them? How many carnations does it need to sell to reach this point?
The cost of the carnations will be equal to the revenue when it has sold
_______ carnations. It will reach this point after it sells ______carnations.
Answer:
6 carnations
Step-by-step explanation:
0.5x +15 = 3x
x = 6
answer the question with true or false:
Answer:
true
Step-by-step explanation:
please helpppppppppppppppp ?
Answer: (x + 4)(x + 4)
x² + 8x + 16
x² + 4x + 4x + 16
Step-by-step explanation:
See the image below.
There are 6 orange marbles, 2 red marbles, 3 white marbles, and 4 green marbles in a bag. Once a marble is drawn, it IS replaced. Find the probability of selecting 2 orange marbles in a row P(orange, orange). Write your answer as a simplified fraction
The probability of selecting two orange marbles with replacement is 36/169.
Data;
Orange= 6Red = 2Green = 4Probability with replacementSince after each draw, the orange marble is replaced.
The total number of marbles in the bag is
6+3+4 = 13
And the number of orange marbles is 6.
For the first selection, the probability of selecting one orange is
[tex]P = \frac{6}{13}[/tex]
After drawn and replaced, the probability of selecting another marble is
[tex]P = \frac{6}{13}[/tex]
And the probability of selecting two orange marbles with replacement is
[tex]P = \frac{6}{13} * \frac{6}{13} = \frac{36}{169}[/tex]
The probability of selecting two orange marbles with replacement is 36/169.
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Which table does NOT represent a linear function?
Hey there!
Linear functions have a continuous change.
Let's check these tables and see if we can tell linear functions from non-linear functions.
The first one is
x values: -1, 0, 1, 2- we add 1 each time
y values: 8, 5, 2, -1- we subtract 3 each time
[tex]\rule{200}{2}[/tex]
Let's try the next one:
x values: -1, 0, 1, 2- we add 1 each time
y values: 5, 10, 15, 20- we add 5 each time
[tex]\rule{200}{2}[/tex]
Let's try the third one:
x values: -1, 0, 1, 2- we add 1 each timey values: 15, 18, 20, 21- we add 3, then 2, then 1..
So this table doesn't represent a linear function.
Let's check the fourth one:
x values: -1, 0, 1, 2- we add 1 each time
y values: 1, 2, 3, 4- we add 1 each time
Thus, Option C is the right option.
Hope everything is clear.
Let me know if you have any questions!
Always remember: Knowledge is power!
Copare use <,>, or =
Answer:
0.125 = ⅛
Step-by-step explanation:
Both are equal.......
The figure below is composed of eight circles, seven small circles and one large circle containing them all. Neighboring circles only share one point, and two regions between the smaller circles have been shaded. Each small circle has a radius of 5 cm.
The figure below is composed of eight circles, seven small circles and one large circle containing them all. Neighboring circles only share one point, and two regions between the smaller circles have been shaded. Each small circle has a radius of 5 cm.
Find the perimeter of the shape shown below.
perimeter = turn of the figure
P = 6 + 3 + 4 + 4 + 3 + 6 + 3 + 4 + 3 = 36
the triangle has 2 équal sides => isosceles
and 1 angle is 60° so the triangle is equilateral
Is the function in this table linear or nonlinear and why?
The question is in the attachment!!
[tex] \qquad\quad\hookrightarrow{\sf { 1000(e-1)}}[/tex]
Solution:[tex] \begin{aligned}&\longrightarrow \int_{0} ^{1000} {e}^{ - |x| }dx = \sum_{k = 0}^{999} \int_{k}^{k + 1}e ^{x - |x| }dx \\ \\ &\longrightarrow\int_{0} ^{1000} {e}^{ - |x| }dx = \sum_{k = 0}^{999} \int_{k}^{k + 1}e^{x - k}dx \\\\&\longrightarrow\int_{0} ^{1000} {e}^{ - |x| }dx = \sum_{k = 0}^{999}e^{x - k \big |_{k}^ {k + 1}} \\ \\& \longrightarrow\int_{0} ^{1000} {e}^{ - |x| }dx = \sum_{k = 0}^ {999}(e - 1)\\\\&\longrightarrow\int_{0} ^{1000} {e}^{ - |x| }dx = 1000(e - 1)\end{aligned}[/tex]
find the HCF of
[tex]5x {}^{2} - 125,x {}^{2} + 25and - 10x[/tex]
Answer:
Step-by-step explanation:
5x^2 - 125 factors into 5 (x^2 - 25)
x^2 - 25 factors into (x + 5)(x - 5)
So the answer to this part is 5(x + 5)(x - 5)
x^2 - 10x + 25 factors into
(x - 5)(x - 5)
So the HCF is (x - 5)
helppppppppp meee too simplify this
Answer:
30,976
Step-by-step explanation:
=}.
[tex](11 {}^{3} \times 4 { }^{2} \binom{}{11 {}^{2} } ) {}^{2} [/tex]
=}.
[tex](11 \times 4 {}^{2} ) {}^{2} [/tex]
=}.
[tex]121 \times (4 {}^{2} ) {}^{2} [/tex]
=}.
[tex]121 \times 256[/tex]
=}. 30,976
Answer:
Answer given above
Step-by-step explanation:
11^2 * 4^4
help me please lease
Answer:
m = 4
Step-by-step explanation:
(80, 40) and (90, 80)
40/10= 4
Answer:
4
Step-by-step explanation:
choose two points
I chose (80,40) and (90,80)
(80-40)÷(90-80)
40/10
4
The graph below represents the result of a survey in which a number of students
reported how many letters were in their last names.
How many students have a name that's longer than 8
letters?
Answer:
2
Step-by-step explanation:
One we student has 9 letters and another has 10 letters
3 shapes are combined to form a composite figure. a semicircle is on the bottom, and then a small rectangle connects the semicircle to a triangle. how can you decompose the composite figure to determine its area? as three triangles and a circle as two triangles, a rectangle, and a circle as a triangle, a pentagon, and a semicircle as a triangle, a rectangle, and a semicircle
Answer:
(d) as a triangle, a rectangle, and a semicircle
Step-by-step explanation:
The description of the shape tells you how to decompose it. The shape is described as a semicircle, a rectangle, and a triangle. The appropriate decomposition is ...
as a triangle, a rectangle, and a semicircle
Answer:
d
Step-by-step explanation:
The half-life of a radioactive substance is the time it takes for a quantity of the substance to decay to half of the initial amount. The half-life of the radioactive gas radon is approximately 2.8 days. The initial amount of radon used in an experiment is 74 grams. If N represents the number of grams of radon remaining t days after the start of the experiment,
a. Write an equation that gives Nin terms of t.
b. how much gas radon approximately remains after 2.8 days?
c. approximately when will the amount of radon remaining be 10 grams?
Step-by-step walkthrough:
a.
Well a standard half-life equation looks like this.
[tex]N = N_0 * (\frac{1}{2})^{t/p[/tex]
[tex]N_0[/tex] is the starting amount of parent element.
[tex]N[/tex] is the end amount of parent element
[tex]t[/tex] is the time elapsed
[tex]p[/tex] is a half-life decay period
We know that the starting amount is 74g, and the period for a half-life is 2.8 days.
Therefore you can create a function based off of the original equation, just sub in the values you already know.
[tex]N(t) = 74g * (\frac{1}{2})^{t/2.8days[/tex]
b.
This is easy now that we have already made the function. Here we just reuse it, but plug in 2.8 days.
[tex]N(t) = 74g * (\frac{1}{2})^{t/2.8days} = N(2.8days) = 74g * (\frac{1}{2})^{2.8days/2.8days}\\= 74g * \frac{1}{2} = 37g[/tex]
c.
Now we just gotta do some algebra. Use the original function but this time, replace [tex]N(t)[/tex] with 10g and solve algebraically.
[tex]10g = 74g * (\frac{1}{2})^{t/2.8days}\\\\\frac{10g}{74g} = (\frac{1}{2})^{t/2.8days}[/tex]
Take the log of both sides.
[tex]log(\frac{5}{37}) = log((\frac{1}{2})^{t/2.8days})[/tex]
Use the exponent rule for log laws that, [tex]log(b^x) = x*log(b)[/tex]
[tex]log(\frac{5}{37}) = \frac{t}{2.8days} * log(\frac{1}{2})[/tex]
[tex]\frac{log(\frac{5}{37})}{log(\frac{1}{2})} = \frac{t}{2.8days}[/tex]
[tex]2.8 * \frac{log(\frac{5}{37})}{log(\frac{1}{2})} = t[/tex]
slap that in your calculator and you get
[tex]t = 8.1 days[/tex]
HELP PLEASE
Find the area of the irregular figure.
5 in.
4 in
A = [ ? ]in.?
5 in.
9 in.
12 in.
4 in
5 in.
Answer:
Area of a rectangle
A = lw
Given AB and AC are lines that are tangent to the circle with
the measure of angle BAC = 40°, what is the measure of angle BDC?
Answer:
C
Step-by-step explanation:
Givens
You are given 2 tangent lines.
You are also given a 4 sided figure.
All 4 sided figures have 360 degrees
A radius meets a tangent at 90 degrees
Formula
<BDA + <DCA + <BCA + <BDC = 360
Solution
90 + 90 +40 + <BDC = 360 Combine
220 + <BDC = 360 Subtract 220 from both sides
220- 220 +BDC =360 - 220
<BDC = 140
Answer: C
What is the volume of this figure?
Enter your answer in the box.
ft³
Answer:
96
Step-by-step explanation:
L=6
W=2
H=8
LxWxH=8x6x2=96
8x6=48
48x2=96
Answer:
76
Step-by-step explanation:
the answer is 76 because I took the test
Leah invests money in an account paying simple interest. She invests $180 and no money is added or removed from the investment. After one year, she has $192.60. What is the simple percent interest per year?
The final statement is: The rate of interest is 7% and simple interest is $12.60
What Is Simple Interest?Simple interest is an interest charge that borrowers pay lenders for a loan. It is calculated using the principal only and does not include compounding interest. Simple interest relates not just to certain loans. It's also the type of interest that banks pay customers on their savings accounts.
Given here: Principal =$180 And amount after one year=$192.60
Therefore simple interest= 192.60-180
=12.60
∴12.60=180×r×1/100
r=7%
Hence, The rate of interest is 7% and simple interest is $12.60
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#SPJ1
Solve Systems of Equations Using the Substitution Method
6x - y= -4
2x + 2y = 15
I genuinely do not understand this concept at all, it would be AMAZING, if you could explain this as well.
Thanks, all.
Answer:
x= ½, y= 7
Step-by-step explanation:
[tex]\textcolor{steelblue}{\text{\textcircled{1} Label the equations}}[/tex]
6x -y= -4 -----(1)
2x +2y= 15 -----(2)
[tex]\textcolor{steelblue}{\text{\textcircled{2} Make y the subject of formula}}[/tex]
We could also make x the subject of formula in one equation, however the equation can be easily rearranged so that the coefficient of y is 1. This can be done by moving the y term to the right hand side of the equation, and the rest to the left. Note that each time you bring a term or constant over to the other side of the equation, its sign changes (e.g. positive to negative).
From (1):
6x +4= y
y= 6x +4 -----(3)
Label the equation as equation (3) so we can refer to it easily later.
[tex]\textcolor{steelblue}{\text{\textcircled{3} Substitute (3) into (2)}}[/tex]
Now that we have an equation of y that is written in terms of x, we can replace all the y in equation (2) so that the whole equation is only in terms of x.
Subst. (3) into (2):
2x +2(6x +4)= 15
Expand:
2x +12x +8= 15
Simplify:
14x +8= 15
14x= 15 -8
14x= 7
x= 7 ÷14
x= ½
[tex]\textcolor{steelblue}{\text{\textcircled{4} Find y}}[/tex]
Substitute x= ½ into (3):
y= 6(½) +4
y= 3 +4
y= 7
Which quadratic function in vertex form can be represented by the graph that has a vertex at negative 4. . 5. and passes through the point negative 7. . 11. ?
Answer:
the annswer is 4155 because its in formal information
Step-by-step explanation:
the annswer is 4155 because its in formal information
Tickets at a particular movie theater have different rates for adults and children. On Tuesday the theater sold 4 adult tickets and 9 child tickets for $88. The next day, the theater sold 7 adult tickets and 5 children tickets for $111. What is the price for the adult ticket and the price for the child ticket?
Answer:
Adult Ticket = $13.00, Children Ticket = $4.00
Step-by-step explanation:
13*4=52, 4*9=36, 52+36=88
13*7=91, 4*5=20, 91+20=111
help please
What is the surface area of a cube with an edge of 5 cm?
Answer:
150 cm^2
Step-by-step explanation:
A cube has 6 surfaces
Each surface square = 5 by 5
So.....
5 x 5 (or 25) times 6
25 x 6 = 150
Hope this helps!
marks obtained by the students are 12,16,14,13,19 and x . If their average marks is 15. find the value of x.
step by step
process by process
needed answer
making them as a brainlists
Answer:
x = 16
Step-by-step explanation:
Given:
Number of students = 6Average mark = 15Therefore, total marks = 15 × 6 = 90
To find the value of x, add up the individual marks:
12 + 16 + 14 + 13 + 19 + x = 74 + x
Now equate this to the total number of marks found previously:
74 + x = 90
Solve for x:
⇒ 74 + x - 74 = 90 - 74
⇒ x = 16
Therefore, the value of x is 16.
I need help please!!!!!!
Answer:
432 feet^2
Step-by-step explanation:
If we fill in the edges, it'll be 24x8, since 16+2 is 18, and 20+2(2) is 24. 24x18 is 432. Brainliest please.
A chocolatier is creating chocolate truffles in the shape spheres. The truffles will be solid chocolate and have a radius of 2.5 cm. How much should each truffle weigh if chocolate weighs 0.71 grams per cubic centimeter? (round to the nearest tenth, if necessary)
The truffles will have a volume of [Answer] cubic centimeters and will weigh a total of [Answer] grams.
Answer: Volume: 65.4 Weight: 46.4
Step-by-step explanation:
Density describes mass per unit volume. The weight of each of the considered chocolate truffle is 46.47 grams approx.
What is density?Density is like rate. It tells you how much of a thing is available for each unit other thing which contains the first thing.
Density = (Total amount available)/(total space which contains that amount)
We're given that:
The chocolate weighs 0.71 grams per cubic centimeter. This is density of the considered chocolate, as it is telling that 0.71 grams of chocolate is available per cubic cm.The chocolate truffles are in shape of sphere with radius 2.5 cmVolume of each chocolate truffle = volume of sphere with radius 2.5 cm
= [tex]\dfrac{4}{3} \pi (2.5)^3 \approx 65.45 \: \rm cm^3[/tex]
One cubic cm has 0.71 grams weight,
so one truffle, which has 65.45 cubic cm of chocolate, will weigh approx[tex]0.71 \times 65.45 \approx 46.47 \: \rm g[/tex]
Thus, the weight of each of the considered chocolate truffle is 46.47 grams approx.
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Estimate the difference.
Answer:
498. 498/6 = 83.
Step-by-step explanation:
Answer number 10 please. Thank you.