In linear equation, 48720 is the tread life covered under the warranty.
What in mathematics is a linear equation?
An algebraic equation with simply a constant and a first-order (linear) term, such as y=mx+b, where m is the slope and b is the y-intercept, is known as a linear equation. Sometimes, the aforementioned is referred to as a "linear equation of two variables," where x and y are the variables.
1) µ = 60,000 and σ = 6000 miles.
P ( X >= 55000 ) = 1 - P ( X < 55000 )
Standardizing the value
Z = ( X - μ)/σ
Z = ( 55000 - 60000 ) / 6000
Z = -0.83
P((X - μ)/σ > ( 55000 - 60000)/6000
P ( Z > -0.83 )
P ( X >= 55000 ) = 1 - P ( Z < -0.83 )
P ( X >= 55000 ) = 1 - 0.2033
P ( X >= 55000 ) = 0.7967
Part v) What proportion of the tires will need to be replaced under warranty?
X ~ N ( μ = 60000 , σ = 6000 )
P ( X < 52000 )
Standardizing the value
Z = ( X - μ)/σ
Z = ( 52000 - 60000 ) / 6000
Z = -1.33
P((X - μ)/σ > ( 55000 - 60000)/6000
P ( X < 52000 ) = P ( Z < -1.33 )
P ( X < 52000 ) = 0.0918
Part c) If you buy 36 tires, what is the probability that the average life of your 36 tires will exceed 61,000?
X ~ N ( μ = 60000 , σ = 6000 )
P ( X > 61000 ) = 1 - P ( X < 61000 )
Standardizing the value
Z = ( X - μ)/(σ/√n)
Z = (61000 - 60000)/(6000/√36)
Z = 1
P(( X - μ)/(σ/√n) > (61000 - 60000)/(6000/√36)
P ( Z > 1 )
P ( X > 61000 ) = 1 - P ( Z < 1 )
P ( X > 61000 ) = 1 - 0.8413
P ( X > 61000 ) = 0.1587
Part d) The manufacturer is willing to replace only 3% of its tires under a warranty program involving tread life. Find the tread life covered under the warranty.
P ( Z < ? ) = 3% = 0.03
Looking for the probability 0.03 in standard normal table to find the critical value Z
Z = - 1.88
Z = (X - μ)/σ
- 1.88 = ( X - 60000)/6000
X = 48720
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2.35 [5] <$2.9> For the following code: Ibu $t0,($t1) sw $t0,($t2) Assume that the register $t1 contains the address 0x10000000 and the data at address is 0x11223344. 2.35.1 [5] <$2.3, 2.9> What value is stored in 0x10000004 on a big-endian machine? 2.35.2 [5] <$2.3, 2.9> What value is stored in 0x10000004 on a little-endian machine?
The value stored in 0x10000004 on a big-endian machine is given by 0x00000011.
The word "endianness" refers to the arrangement of bytes as they are stored in computer memory. Endianness is classified as big or little depending on which value is stored first.
The "big end" (the most important item in the sequence) is put first and at the lowest storage address in a big-endian order. The "small end" (the least important item in the sequence) is put first in a little-endian order.
(1)In Big-endian Machine, first byte of multi-byte data will be stored first(at lower memory address)
Address Data
0x10000000 0x11
0x10000001 0x22
0x10000002 0x33
0x10000003 0x44
---------------------------------------------------------------------
lbu $t0, 0($t1)
Load unsigned byte in Register $t0 at address 0x10000000
Here byte at address 0x10000000 is 0x11
$t0 = 0x00000011
----------------------------------------------------
sw $t0, 0($t2)
Store a word(4 bytes) from Register $t0 to memory address 0x10000004
value stored in 0x10000004 is 0x00000011
--------------------------------------------------------------------------------
(2)In Little-endian Machine, last byte of multi-byte data will be stored first(at lower memory address)
Address Data
0x10000000 0x44
0x10000001 0x33
0x10000002 0x22
0x10000003 0x11
---------------------------------------------------------------------
lbu $t0, 0($t1)
Load unsigned byte in Register $t0 at address 0x10000000
Here byte at address 0x10000000 is 0x44
$t0 = 0x00000044
----------------------------------------------------
sw $t0, 0($t2)
Store a word(4 bytes) from Register $t0 to memory address 0x10000004
value stored in 0x10000004 is 0x00000044.
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When I first look at an equation, HOW DO I KNOW which method to use to solve it?
for example:
-4(7j+2) = 10
What do I look for (by looking at it) to know if I should start to solve it by distributing, or just use division?
Please help! I am really confused. Thank you
Answer:
j = - 9/14
Step-by-step explanation:
-4(7j+2) = 10
Distributing First
-28j - 8 = 10
Try to get the variable on one side.
-28j = 18
Divide both sides by -28
j = -18/28 = - 9/14
3 Tell whether each statement is True or False.
A 20° angle and a 70° angle can be
composed into a 90° angle.
b. Three 50° angles compose an angle
that measures 350⁰.
c. A 15° angle and a 60° angle compose
an angle that measures 75°.
d. Four 50° angles can be composed
into a 200° angle.
True False
True
True
True
4 Look at the drawing of a hand fan at the right. The
False
False
Fal
d. True. The sum of four 50° angles is 200°, so they can compose a 200° angle.
what is a geometric sequence?
A geometric sequence is a sequence of numbers in which each term after the first is found by multiplying the previous term by a fixed constant called the common ratio. The common ratio is denoted by the letter r.
The general formula for a geometric sequence is:a₁, a₁r, a₁r², a₁r³, ...
a. False. The sum of a 20° angle and a 70° angle is 90°, so they can compose a 90° angle.
b. False. The sum of three 50° angles is 150°, so they cannot compose an angle that measures 350⁰.
c. False. The sum of a 15° angle and a 60° angle is 75°, so they can compose an angle that measures 75°.
Therefore, d. True. The sum of four 50° angles is 200°, so they can compose a 200° angle.
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. If h> 3 and h - 2g= 0, which of
the following must be true?
A. g> 2.5
B. g> 1.5
C. g <0.5
D. g <1.5
E. g>2
By linear equality , g >1.5 is must be true.
What are equality and inequality along a line?
Equal (=) is the symbol used in linear equations. Example. Using the inequality symbols (>,, is greater than or equal to, and is less than or equal to), linear inequalities are expressed.
x - 5 > 3x - 10 is an illustration of a linear inequality. As the larger than symbol is employed in this inequality, the LHS is strictly greater than the RHS. After being solved, the inequality appears as 2x 5 x (5/2).
If h> 3 and h - 2g= 0
H=2g
2g>3
g >1.5
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f(s) = 3s + 2
p(s) = s^3+ 4s
Find (f • p)(-5)
The value of (f • p)(-5) is 1885 when functions are given as f(s) = 3s + 2 and p(s) = s³+ 4s.
What is function?In mathematics, a function is a relation between a set of inputs and a set of possible outputs with the property that each input is related to exactly one output. It is often represented by an equation or formula, and can be visualized as a graph. Functions are widely used in various areas of mathematics, science, engineering, and other fields to model real-world phenomena and solve problems.
Here,
f(s) = 3s + 2
p(s) = s³+ 4s
To find (f • p)(-5), we need to first find f(-5) and p(-5), and then multiply them together. To find f(-5), we substitute -5 into the function f(s) and simplify:
f(-5) = 3(-5) + 2
= -13
To find p(-5), we substitute -5 into the function p(s) and simplify:
p(-5) = (-5)³ + 4(-5)
= -125 - 20
= -145
Now we can multiply f(-5) and p(-5) together to find (f • p)(-5):
(f • p)(-5) = f(-5) * p(-5)
= (-13) * (-145)
= 1885
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Consider the system described below with input f(t) and output y(t). Determine if the system is linear or nonlinear. Show all work. dy +3 +3ty(t)=1² f(t) dt 5. By direct integration find the Laplace transform of the signal shown. f (t) 1+6) t(s)
The system described above is nonlinear because it contains a term with y(t) multiplied by t. The Laplace transform of f(t) is (6/s²)+(1/s).
If we substitute y1(t) and y2(t) into the equation and add them together, we get:
dy1/dt + 3 + 3ty1(t) = 1² f(t) dt dy2/dt + 3 + 3ty2(t) = 1² f(t) dt
Then we can add these two equations together to get:
d(y1+y2)/dt + 3 + 3t*(y1+y2)(t) = 2*1² f(t) dt
This is not equal to the original equation with y(t), which means that the system is nonlinear.
To find the Laplace transform of f(t), we can use the formula:
L{f(at+b)} = (1/a) ×F(s-b/a)
where F(s) is the Laplace transform of f(t). In this case, we have:
f(t) = (1+6t)
So we can rewrite this as:
f(t) = (6×t+1)
Now we can use the formula to find the Laplace transform:
L{(6×t+1)} = (6/s²)+(1/s)
Therefore, the Laplace transform of f(t) is (6/s²)+(1/s).
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1. In the figure below, solve for the missing side (seems harder then it should be)
A.7
B.8
C.9
D.10
Answer:
1. a square plus b square is c square where c is the hypotenuse.
so 1. 7^2 + 6^2 = c^2
49+36=c^2
85=c^2
the square root of 85 is c
9.22 is c
all the other questions are blurry :OO
Step-by-step explanation:
Total of 18 students 5 students prefer country. what is the probability?
Answer:
27.78%
Step-by-step explanation:
We know
Total of 18 students 5 students prefer country.
What is the probability?
5/18 = 27.78%
So, the answer is 27.78%
In a group of rectangles, the length of each rectangle is twice the width. Is this an additive or multiplicative relationship? Explain your reasoning.
Answer:
Multiplicative
Step-by-step explanation:
If the area of the first rectangle is l*w, the area of the second would be 2w*w. The area is multiplied by 2 and the relationship is therefore multiplicative.
5 Mrs. Newsome bought a piece of fabric 142 centimeters long to make a quilt for her son's bedroom. She bought a piece of fabric 2 meters long for curtains. How could Mrs. Newsome find the total length, in centimeters, of both pieces of fabric? Multiply 2 by 2,000, then add 142. Add 2 and 142, then multiply by 100. Divide 142 by 100, then add 2,000. O Multiply 2 by 100, then add 142. B C
Answer:
Step-by-step explanation:
To find the total length of both pieces of fabric in centimeters, we need to add the length of the first piece of fabric (142 cm) and the length of the second piece of fabric (2 meters).
However, we need to make sure that the units are consistent before we add the lengths. We can convert the length of the second piece of fabric from meters to centimeters by multiplying by 100. Therefore, the total length in centimeters is:
142 cm + 2 meters * 100 cm/meter = 142 cm + 200 cm = 342 cm
The option that correctly gives the answer is "Multiply 2 by 100, then add 142" (Option C).
PLEASE ASAP!!Graph the line 4x+5y=20
Step-by-step explanation:
Might be a little easier to visualize if yo re-arrange it into y = mx + b form:
4x+ 5y = 20
5y = -4x + 20
y = - 4/5 x + 4 y-axis intercept at y = 4
x axis intercept is found by:
0 = -4/5 x + 4
- 4 = -4/5 x
x = 5
So===> plot the two intercept points ( 0,4) and ( 5,0) and connect the dots
Can the binomial distribution be approximated by a normal distribution? n = 31, p = 0.9 Explain why or why not.
Therefore, we can use the normal distribution with mean 27.9 and standard deviation 1.67 to approximate the binomial distribution with n = 31 and p = 0.9.
What is binomial distribution?The binomial distribution is characterized by two parameters: the number of trials, denoted by n, and the probability of success on each trial, denoted by p. The probability of obtaining exactly k successes in n trials is given by the binomial probability mass function:
P(k) = (n choose k) * [tex]p^{k}[/tex] * [tex](1-p)^{(n-k)}[/tex],
where (n choose k) is the binomial coefficient, which represents the number of ways to choose k items from a set of n distinct items.
Given by the question.
Yes, the binomial distribution with n = 31 and p = 0.9 can be approximated by a normal distribution.
The conditions for a binomial distribution to be approximated by a normal distribution are as follows:
n*p >= 10
n*(1-p) >= 10
In this case, n = 31 and p = 0.9, so:
np = 310.9 = 27.9 >= 10
n*(1-p) = 31*0.1 = 3.1 >= 10
Condition 1 is satisfied, but condition 2 is not. Therefore, it is recommended to use a correction factor to improve the approximation.
The correction factor is given by:
[tex]\sqrt[2]{np(1-p)}[/tex]
Substituting the values, we get:
[tex]\sqrt[2]{310.90.1}[/tex]= 1.67
The corrected values for mean and standard deviation are:
mean = np = 310.9 = 27.9
standard deviation = [tex]\sqrt[2]{np(1-p)}[/tex] = 1.67
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a
21 units squared
b
27.6 units squared
c
32.2 units squared
d
42 units squared
The area of the right triangle given in this problem is given as follows:
21 units squared -> Option A.
How to obtain the area of a triangle?To calculate the area of a triangle, you can use the formula presented as follows:
Area = (1/2) x base x height
In which the parameters are given as follows:
"base" is the length of the side of the triangle that is perpendicular to the height."height" is the length of the perpendicular line segment from the base to the opposite vertex.For a right triangle, we can consider one side to be the base and the other side to be the height, hence the parameters are given as follows:
Base of 7 units.Height of 6 units.Hence the area of the triangle is given as follows:
A = 0.5 x 7 x 6 = 21 units squared.
Missing InformationThe complete problem is defined as follows:
"Calculate the area of the given triangle".
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Find the Z-score for each of the following IQ scores
90 160(Einstein's IQ)
Answer:
z=3.75
Step-by-step explanation:
HELP ASAP PLEASE! A yard plan includes a rectangular garden that is surrounded by bricks. In the drawing, the garden is 7 inches by 4 inches. The length and width of the actual garden will be 35 times larger than the length and width in the drawing.
What is the perimeter of the drawing? Show your work.
What is the perimeter of the actual garden? Show your work.
What is the effect on the perimeter of the garden with the dimensions are multiplied by 35? Show your work.
The perimeter of the garden in the drawing is 22 inches and the perimeter of the actual garden is 770 inches
The perimeter of the drawingThe perimeter of the garden in the drawing is calculated as
Perimeter of garden in drawing = 2(length + width)
So, we have
Perimeter of garden in drawing = 2(7 inches + 4 inches)
Evaluate
Perimeter of garden in drawing = 22 inches
So the perimeter of the garden in the drawing is 22 inches.
The perimeter of the actual gardenFor the perimeter of the actual garden, we have
Perimeter of actual garden = 22 inches * 35
Perimeter of actual garden = 770 inches
The effect on the perimeterWe can see that the perimeter of the actual garden is 35 times larger than the perimeter of the garden in the drawing.
This makes sense since the length and width of the actual garden are 35 times larger than the length and width in the drawing, so the perimeter (which is the sum of the lengths of all four sides) would also be 35 times larger.
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LetY1,Y2,Yn denote a random sample of size n from a population whose density is given by f(y)={αyα−1θα,0≤y≤θ0,elsewhere,where α>0 is a known, fixed value, but θ is unknown. Consider the estimator ˆθ=max(Y1,Y2,...Yn).(a) Show that ˆθ is a biased estimator for θ.(b) Find a multiple of ˆθ that is an unbiased estimator of θ.(c) Derive MSE(ˆθ).
(a) θ is a biased estimator for θ.
(b) (α+1)Y/α is an unbiased estimator of θ.
(c) MSE(θ) = αθ^2/[(α+1)^2(α+2)]
(a) To show that θ is a biased estimator for θ, we need to show that E(θ) ≠ θ.
Using the definition of the maximum function, we have
P(θ ≤ y) = P(Y1 ≤ y, Y2 ≤ y, ..., Yn ≤ y) = (F(y))^n
where F(y) is the cumulative distribution function of Y.
Differentiating both sides with respect to y, we get:
f(θ) = n(F(θ))^(n-1)f(θ)
Simplifying, we get
F(θ) = (1/n)^(1/(n-1))
Using this result, we can find the expected value of θ
E(θ) = ∫₀^∞ θf(θ)dθ = ∫₀^θ θαθ^α-1dθ = αθ/(α+1)
Thus, E(θ) ≠ θ, which means that θ is a biased estimator for θ.
(b) To find a multiple of θ that is an unbiased estimator of θ, we can use the method of moments.
We know that the population mean of Y is
μ = ∫₀^θ yf(y)dy = αθ/(α+1)
The sample mean is
Y = (Y1+Y2+...+Yn)/n
Equating these two expressions and solving for θ, we get
θ = (α+1)Y/α
Thus, (α+1)Y/α is an unbiased estimator of θ.
(c) The mean squared error (MSE) of θ can be written as
MSE(θ) = E[(θ - θ)^2]
Expanding the square and using the linearity of expectation, we have
MSE(θ) = E[θ^2] - 2θE[θ] + E[θ]^2
We already know that E[θ] = αθ/(α+1).
To find E[θ^2], we can use the fact that θ = max(Y1,Y2,...Yn)
P(θ ≤ y) = P(Y1 ≤ y, Y2 ≤ y, ..., Yn ≤ y) = (F(y))^n
Differentiating both sides with respect to y, we get
f(θ) = n(F(θ))^(n-1)f(θ)
Using this result, we can find E[θ^2]
E[θ^2] = ∫₀^∞ θ^2f(θ)dθ = ∫₀^θ θ^2αθ^α-1dθ = αθ^2/(α+2)
Substituting these expressions into the MSE formula, we get
MSE(θ) = αθ^2/(α+2) - 2θ(αθ/(α+1)) + (αθ/(α+1))^2
Simplifying, we get
MSE(θ) = αθ^2/[(α+1)^2(α+2)]
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Question 4 X Suppose that starting today, you make deposits at the beginning of each quarterly period for the next 40 years. The first deposit is for 400, but you decrease the size of each deposit by 1% from the previous deposit. Using an nominal annual interest rate of 8% compounded quarterly, find the future value (i.e. the value at the end of 40 years) of these deposits. Give your answer as a decimal rounded to two places (i.e. X.XX).
if we make quarterly deposits and invest them at an nominal annual interest rate of 8% compounded quarterly for 40 years, we will have $143,004.54 at the end of the 40 years.
The first step in solving this problem is to calculate the amount of each quarterly deposit. We know that the first deposit is $400, and each subsequent deposit decreases by 1% from the previous deposit. This means that each deposit is 99% of the previous deposit. To calculate the size of each deposit, we can use the following formula:
deposit_ n = deposit_(n-1) * 0.99
Using this formula, we can calculate the size of each quarterly deposit as follows:
deposit_1 = $400
deposit_2 = deposit_1 * 0.99 = $396.00
deposit_3 = deposit_2 * 0.99 = $392.04
deposit_4 = deposit_3 * 0.99 = $388.12
...
We can continue this pattern for 40 years (160 quarters) to find the size of each quarterly deposit.
Next, we need to calculate the future value of these deposits using an nominal annual interest rate of 8% compounded quarterly. We can use the formula for compound interest to calculate the future value:
[tex]FV = PV * (1 + r/n)^(n*t)[/tex]
where FV is the future value, PV is the present value (which is zero since we are starting with deposits), r is the nominal annual interest rate (8%), n is the number of times the interest is compounded per year (4 since we are compounding quarterly), and t is the number of years (40).
We can substitute the values into the formula and solve for FV:
[tex]FV = $400 * (1 + 0.08/4)^(440) + $396.00 * (1 + 0.08/4)^(439) + $392.04 * (1 + 0.08/4)^(4*38) + ... + $1.64 * (1 + 0.08/4)^4[/tex]
After solving this equation, we get a future value of $143,004.54, rounded to two decimal places. This means that if we make quarterly deposits and invest them at an nominal annual interest rate of 8% compounded quarterly for 40 years, we will have $143,004.54 at the end of the 40 years.
This calculation highlights the power of compound interest over long periods of time. By making regular contributions and earning interest on those contributions, our investment grows exponentially over time. It also shows the importance of starting early and consistently contributing to an investment over time in order to achieve long-term financial goals.
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Assuming boys and girls are equally likely, find the probability of a couple's last child being a baby boy. They have a total of 3 children not including the last child in question and all were boys before the last child was born.
Express your answer as a percentage rounded to the nearest hundredth without the % sign.
Answer:
Step-by-step explanation:
The probability of a baby being a boy or a girl is 1/2 or 50% each. Since the couple has already had three boys, the probability of the fourth child being a boy or a girl is still 1/2 or 50%, as the gender of each child is independent of the others. Therefore, the probability of the couple's last child being a baby boy is 50%.
The required probability of a couple having a baby boy when their third child is born is 1/2 / 50%.
What is probability?probability is the ratio of the number of favorable outcomes and the total number of possible outcomes. The chance that a particular event (or set of events) will occur expressed on a linear scale from 0 (impossibility) to 1 (certainty), also expressed as a percentage between 0 and 100%.
Given:
Assuming boys and girls are equally likely.
The first two children were both boys
According to given question we have
The probability of having a baby girl is an independent probability.
The first two children were both boys
So, it is not related to the previous child.
So required probability = 1/2 / 50%
Therefore, the required probability of a couple having a baby boy when their third child is born is 1/2 / 50%.
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Question 20
There were 750 shirts in a box. 20% of them were pink and 18% were green. The
remaining shirts were either yellow or black. If there were 85 more black shirts than
yellow shirts, what was the total number of black and green shirts in the box?
Answer:
410 Black and Green shirts
Step-by-step explanation:
150 shirts were pink
135 shirts were green
so knowing this we can set up the equation 2x+85=465
there were 275 black shirts in the box
and 190 yellow shirts
therefore there were 410 Black and Green shirts in the box
The area of a trapezium is 156cm2, the parallel sides are 17cm and 35cm respectively. What is the height of the trapezium
Answer:
6 cm
Step-by-step explanation:
You want the height of a trapezium with bases 17 cm, 35 cm and area 156 cm².
Area formulaThe formula for the are of a trapezium is ...
A = 1/2(b1 +b2)h
Filling in the given values, we have ...
156 = 1/2(17 +35)h = 26h
6 = h . . . . . . . . . . divide by 26
The height of the trapezium is 6 cm.
Answer:
6cm
Step-by-step explanation:
To find:-
The height of the trapezium.Answer:-
We are here given that the area of the trapezium is 156cm² and two of the parallel sides are 17cm and 35cm .We are interested in finding out the height of the trapezium.
The area of the trapezium is given by the formula,
[tex]:\implies \sf Area =\dfrac{1}{2}\times (s_1+s_1)\times h \\[/tex]
where s1 and s2 are the || sides of the trapezium and h is the height of the trapezium.
Now on substituting the respective values in the given formula, we have;
[tex]:\implies \sf 156cm^2 =\dfrac{1}{2} (17cm+35cm)\times h \\[/tex]
[tex]:\implies \sf 156cm^2(2) = 52cm (h) \\[/tex]
[tex]:\implies \sf h =\dfrac{156(2)}{52} cm\\[/tex]
[tex]:\implies \sf \pink{ height = 6 cm }\\[/tex]
Hence the height of the trapezium is 6cm .
Help pleaseeeeeeeeee!
Answer:
y = 0.8x
Step-by-step explanation:
machine fills 24 jars in 30 seconds , then
fills 1 jar in [tex]\frac{24}{30}[/tex] = 0.8 seconds
thus number of jars filled in x seconds is
y = 0.8x
Solve the following problems.
Given: AABC, DE AC,
BD DC, mZ1=m22,
mZBDC= 100°
Find: m< A, m< b , m
The value of the angles in the triangle are:
∠A = 60°, ∠B = 80° and ∠C = 40°
How to find the value of m∠A, m∠B, m∠C in the triangle?
We are given that BD = DC
Thus, ∠DBC = ∠BCD ---- 1 (angle in isosceles triangle)
We also have ∠BDC = 100°
In ΔBDC
∠BDC + ∠DBC + ∠BCD = 180° (sum of angles of triangle is 180°)
Using 1:
∠BDC + 2∠DBC = 180°
100° + 2∠DBC = 180°
2∠DBC = 180 - 100
2∠DBC = 80
∠DBC = 80/2
∠DBC = 40°
∠DBC = ∠BCD = ∠2 = 40°
Thus, ∠C = 40°
We are given that m∠1 = m∠2
Thus, ∠1 = ∠2 = 40°
Now, ∠BDC + ∠BDA = 180° (Linear pair)
100° + ∠BDA = 180°
∠BDA = 180 - 100
∠BDA = 80°
In ΔABD
∠ABD + ∠BDA + ∠BAD = 180° (sum of angles of triangle is 180°)
∠1 + ∠BDA + ∠BAD = 180°
40° + 80° + ∠BAD = 180°
120° + ∠BAD = 180°
∠BAD = 60°
So, ∠A = 60°
∠B = ∠1 + ∠2 = 40° + 40° = 80°
Therefore, ∠A = 60°, ∠B = 80° and ∠C = 40°
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Complete Question
m∠1=m∠2
D∈
AC
, BD = DC
m∠BDC = 100°
Find: m∠A, m∠B, m∠C
PLEASE HELP MEE with all four questionsss
Therefore, the distance between the 90 degree angle and the hypotenuse is approximately 0.829 units.
What is triangle?A triangle is a two-dimensional geometric shape that is formed by three straight line segments that connect to form three angles. It is one of the most basic shapes in geometry and has a wide range of applications in mathematics, science, engineering, and everyday life. Triangles can be classified by the length of their sides (equilateral, isosceles, or scalene) and by the size of their angles (acute, right, or obtuse). The study of triangles is an important part of geometry, and their properties and relationships are used in many areas of mathematics and science.
Here,
1. To find HF, we can use the angle bisector theorem, which states that if a line bisects an angle of a triangle, then it divides the opposite side into two segments that are proportional to the adjacent sides. Let's denote the length of HF as x. Then, by the angle bisector theorem, we have:
JF/FH = JG/HG
Substituting the given values, we get:
15/x = 18/21
Simplifying and solving for x, we get:
x = 15 * 21 / 18
x = 17.5
Therefore, HF is 17.5 cm.
2. Let's denote the length of the hypotenuse as h and the length of the leg opposite the 18-unit perpendicular as a. We can then use the Pythagorean theorem to write:
h² = a² + 18²
We are told that the hypotenuse is divided into segments of length x and 6 units, so we can write:
h = x + 6
Substituting this expression into the first equation, we get:
(x + 6)² = a² + 18²
We are also told that the leg adjacent to the angle opposite the 4-unit segment is divided into segments of length 4 and (a - 4), so we can write:
a = 4 + (a - 4)
Simplifying this equation, we get:
a = a
Now we can substitute this expression for a into the previous equation and solve for x:
(x + 6)² = (4 + (a - 4))² + 18²
Expanding and simplifying, we get:
x² + 12x - 36 = 0
Using the quadratic formula, we get:
x = (-12 ± √(12² - 4(1)(-36))) / (2(1))
x = (-12 ± √(288)) / 2
x = -6 ± 6√(2)
Since the length of a segment cannot be negative, we take the positive root:
x = -6 + 6sqrt(2)
x ≈ 1.46
Therefore, the value of x is approximately 1.46 units.
3. Let's denote the length of the hypotenuse as h and the length of the leg adjacent to the angle opposite the 9-unit perpendicular as b. We can then use the Pythagorean theorem to write:
h² = b² + 9²
We are told that the hypotenuse is divided into segments of length x and 6 units, so we can write:
h = x + 6
Substituting this expression into the first equation, we get:
(x + 6)² = b² + 9²
Expanding and simplifying, we get:
x² + 12x - b² = 27
We also know that the length of the leg opposite the 9-unit perpendicular is:
a = √(h² - 9²)
= √((x + 6)² - 9²)
= √(x² + 12x + 27)
Now we can use the fact that the tangent of the angle opposite the 9-unit perpendicular is equal to the ratio of the lengths of the opposite and adjacent sides:
tan(θ) = a / b
Substituting the expressions for a and b, we get:
tan(θ) = √(x² + 12x + 27) / (x + 6)
We also know that the tangent of the angle theta is equal to the ratio of the length of the opposite side to the length of the adjacent side:
tan(θ) = 9 / b
Substituting the expression for b, we get:
tan(θ) = 9 / √(h² - 9²)
Substituting the expression for h, we get:
tan(θ) = 9 / √((x + 6)² - 9²)
Since the tangent function is the same for equal angles, we can set these two expressions for the tangent equal to each other:
√(x² + 12x + 27) / (x + 6) = 9 / √((x + 6)² - 9²)
Squaring both sides, we get:
(x² + 12x + 27) / (x + 6)² = 81 / ((x + 6)² - 81)
Cross-multiplying and simplifying, we get:
x⁴ + 36x³ + 297x² - 1458x - 2916 = 0
Using a numerical method such as the Newton-Raphson method or the bisection method, we can find the approximate solution to this equation:
x ≈ 9.449
Therefore, the value of x is approximately 9.449 units.
4. Let's denote the length of the hypotenuse as h and the length of the leg adjacent to the angle opposite the distance we want to find as b. We can use the Pythagorean theorem to write:
h² = b² + d²
We are told that the hypotenuse is divided into segments of length 9 and 4 units, so we can write:
h = 9 + 4 = 13
Substituting this expression into the first equation, we get:
13² = b² + d²
Simplifying and solving for d, we get:
d = √(13² - b²)
Now, we need to find the value of b. We know that the hypotenuse is divided into segments of length 9 and 4 units, so we can use similar triangles to write:
b / 4 = 9 / 13
Simplifying and solving for b, we get:
b = 36 / 13
Substituting this expression for b into the equation we found earlier for d, we get:
d = √(13² - (36/13)²)
Simplifying and finding a common denominator, we get:
d =√ (169*13 - 36²) / 13²
Simplifying further, we get:
d = √(169169 - 3636) / 169
Calculating this expression, we get:
d ≈ 0.829
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5/9=
1/14=
12/13=
2/13=
9/11=
9/17=
To round each fraction
Answer:
Step-by-step explanation:
1. Rounded to 0.56
2. Rounded
6TH GRADE MATH PLS HELP TYSM
Answer:
m = 1
Step-by-step explanation:
Slope = rise/run or (y2 - y1) / (x2 - x1)
Pick 2 points (-1,0) (0,1)
We see the y increase by 1 and the x increase by 1, so the slope is
m = 1
A company rents storage sheds shaped like rectangular prisms. Each shed is 11 feet long, 7 feet wide, and 12 feet tall. The rental cost is $3 per cubic foot. How much does it cost to rent one shed?
The cost to rent one shed of the rectangular prism shaped shed is $2772.
What is area?The size of a section on a surface is determined by its area. Surface area refers to the area of an open surface or the border of a three-dimensional object, whereas the area of a plane region or plane area refers to the area of a shape or planar lamina.
What is a prism?A rectangular prism is a polyhedron in geometry that has two parallel and congruent sides. It also goes by the name cuboid. Six faces, each with a rectangle form and twelve edges, make up a rectangular prism. It is referred to as a prism because of the extent of its cross-section.
Volume of prism= BH
where B= area of base and H= height
B= 11*7 = 77 feet²
H= 12 feet
Volume= 77*12=924 cubic feet
Cost =$3 per cubic foot
Total cost= 3*924= $2772
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Question 2 (2 points) ✓ Saved
In the news, you hear "tuition is expected to increase by 12% next year." If tuition
this year was $5,500 per year, what will it be next year?
660
6160
4840
Cannot be solved.
Answer: 6,160
Step-by-step explanation:
Immediately, without even doing any math, the only logical answer would be 6160. This is because the current tuition is 5,500 and it is increasing so the answer cannot be lower.
However, mathematically you can prove this by turning 12% into a decimal and multiplying it by 5,500. 12% could be converted to .12 and because it is increasing you must add 1, or 100%, since that is what it started with. 5,500 x 1.12 = 6,160.
Consider the quadratic function f(x) = x2 – 5x + 12. Which statements are true about the function and its graph? Select three options. The value of f(–10) = 82 The graph of the function is a parabola. The graph of the function opens down. The graph contains the point (20, –8). The graph contains the point (0, 0).
The true statements are:
The graph of the function is a parabola.
The graph contains the point (0, 0).
The graph does not contain the point (20, -8).
How to deal with quadratic equation?The quadratic function is f(x) = x^2 - 5x + 12. Here are the statements that are true:
The value of f(-10) = 82:
To find f(-10), we substitute -10 for x in the function:
[tex]$$f(-10) = (-10)^2 - 5(-10) + 12 = 100 + 50 + 12 = 162$$[/tex]
Therefore, the statement "The value of f(-10) = 82" is false.
The graph of the function is a parabola:
Since the highest power of x in the function is 2, the graph of the function will be a parabola. Therefore, the statement "The graph of the function is a parabola" is true.
The graph of the function opens down:
The coefficient of [tex]$x^2$[/tex] in the function is positive (+1), which means the parabola opens upwards. Therefore, the statement "The graph of the function opens down" is false.
The graph contains the point (20, –8):
To see whether the point (20, -8) is on the graph of the function, we substitute x=20 into the function:
[tex]$$f(20) = (20)^2 - 5(20) + 12 = 400 - 100 + 12 = 312$$[/tex]
Since the y-coordinate of the point (20, -8) is not equal to 312, the statement "The graph contains the point (20, –8)" is false.
The graph contains the point (0, 0):
To see whether the point (0, 0) is on the graph of the function, we substitute x=0 into the function:
[tex]$$f(0) = (0)^2 - 5(0) + 12 = 12$$[/tex]
Since the y-coordinate of the point (0, 0) is equal to 12, the statement "The graph contains the point (0, 0)" is true.
Therefore, the true statements are:
The graph of the function is a parabola.
The graph contains the point (0, 0).
The graph does not contain the point (20, -8).
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Determine whether each of these functions from
Z
to
Z
is one-to-one (i.e., injective). (3 pts in total) (a)
f(n)=n−3
(b)
f(n)=n 2
−1
(c)
f(n)=n 5
The function f(n) = n - 3 maps distinct integers to distinct integers, and thus is injective.
(a) The function f(n) = n - 3 is one-to-one (injective). To prove this, suppose that f(a) = f(b) for some integers a and b. Then, we have a - 3 = b - 3, which implies a = b. Therefore, the function f(n) = n - 3 maps distinct integers to distinct integers, and thus is injective.
(b) The function f(n) = n^2 - 1 is not one-to-one (not injective). To see this, note that f(1) = f(-1) = 0, so different inputs map to the same output. In general, for any positive integer k, we have f(k) = f(-k), since (k^2 - 1) = ((-k)^2 - 1). Therefore, the function f(n) = n^2 - 1 is not injective.
(c) The function f(n) = n^5 is one-to-one (injective). To prove this, suppose that f(a) = f(b) for some integers a and b. Then, we have a^5 = b^5, which implies a = b (since the fifth root of a non-zero real number is unique). Therefore, the function f(n) = n^5 maps distinct integers to distinct integers, and thus is injective.
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10% of the cars in my neighborhood are red, and the rest of the cars in the neighborhood are silver. We'll call "seeing a red car" a success, and "seeing a silver car" a failure for the purposes of this problem.
Suppose that I watch 3 cars pass my house and that I become interested in the probability that exactly one of the three cars is red.
Apply the binomial formula to find the probability that exactly one of the three cars is red. Be sure to clearly state the values of n, x, and p in this case.
Answer:
In this scenario, we have:
n = 3 (since we are watching 3 cars)
x = 1 (since we are interested in the probability of exactly one car being red)
p = 0.1 (since the probability of a car being red is 10%, or 0.1)
The binomial formula for calculating the probability of exactly x successes in n independent trials with a probability of success p is:
P(x) = (nCx) * p^x * (1-p)^(n-x)
where nCx is the binomial coefficient, which can be calculated as:
nCx = n! / (x! * (n-x)!)
Using these values and the binomial formula, we can calculate the probability of exactly one of the three cars being red as:
P(1) = (3C1) * 0.1^1 * (1-0.1)^(3-1)
= (3) * 0.1 * 0.81
= 0.243
Therefore, the probability of exactly one of the three cars being red is 0.243.