the term applied to the chemistry of the body​

Answers

Answer 1

Answer:

Biochemistry

Explanation:

Hope this helps :)

Answer 2

Answer:

Biochemistry

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Related Questions

a 1-w, 350-ω resistor is connected to 24 v. Is this resistor operating within its power rating?

Answers

Answer:

No.

Explanation:

[tex]P_r[/tex] = Power rating = 1 W

R = Resistance = [tex]350\ \Omega[/tex]

V = Voltage = [tex]24\ \text{V}[/tex]

Power is given by

[tex]P=\dfrac{V^2}{R}\\\Rightarrow P=\dfrac{24^2}{350}\\\Rightarrow P=1.65\ \text{W}[/tex]

[tex]1.65\ \text{W}>1\ \text{W}[/tex]

So

[tex]P>P_r[/tex]

Hence, the resistor is not operating within its power rating.

A lake is fed by a polluted stream and a sewage outfall. The stream and sewage wastes have a decay rate coefficient (k) of 0.5/day (1st order units). Assuming complete mixing and no other water losses or gains, what is the steady-state pollutant concentration as mg/L in the lake? Incoming Stream: C = 10 mg/L, Q = 40 m^3/s Sewage Outfall: C = 100 ppm, Q = 0.5 m^3/s Lake: V= 200 m^3

Answers

Solution :

Given :

k = 0.5 per day

[tex]$C_s = 10 \ mg/L \ ; \ \ Q_s= 40 \ m^3/s$[/tex]

[tex]$C_{sw} = 100 \ ppm \ ; \ \ Q_{sw}= 0.5 \ m^3/s$[/tex]

Volume, V [tex]$= 200 \ m^3$[/tex]

Now, input rate = output rate + KCV ------------- (1)

Input rate  [tex]$= Q_s C_s + Q_{sw}C_{sw}$[/tex]

                [tex]$=(40 \times 10) + (0.5\times 100)$[/tex]

                [tex]$= 2 \times 10^5 \ mg/s$[/tex]

The output rate [tex]$= Q_m C_{m}$[/tex]

                          = ( 40 + 0.5 ) x C x 1000

                          [tex]$=40.5 \times 10^3 \ C \ mg/s$[/tex]

Decay rate = KCV

∴[tex]$KCV =\frac{0.5/d \times C \ \times 200 \times 1000}{24 \times 3600}$[/tex]

            = 1.16 C mg/s

Substituting all values in (1)

[tex]$2 \times 10^5 = 40.5 \times 10^3 \ C+ 1.16 C$[/tex]

C = 4.93 mg/L

For a soil, cohesion is 15 kN/sq.M, unit weight is 20 kN/cu.M and the factor of safety is 1.5 along with stability number of 0.05. The safe maximum height of slope is *

Answers

Answer:

10 m

Explanation:

The Soil Cohesion is the force that holds together molecules or like particles within a soil.

The unit weight of a soil mass is the ratio of the total weight of soil to the total volume of soil.

The stability number (Sn) is given by the formula:

[tex]S_n=\frac{C_m}{\gamma *H}[/tex]

Given that:

Cohesion = C = 15 kN/m², Factor of safety = FOS = 1.5, unit weight = γ = 20 kN/m³, H = maximum height, Sn = 0.05. Hence:

[tex]C_m=\frac{C}{FOS}\\\\S_n=\frac{C}{\gamma *FOS *H}\\\\H= \frac{C}{\gamma *FOS *S_n}\\\\Substituting:\\\\H=\frac{15}{20*1.5*0.05} \\\\H=10\ m[/tex]

In order to avoid slipping in the shop, your footwear should ___________.
A) Be brand-new
B) Have steel toes
C) Not have shoestrings
D) Have proper tread

(This is for my Automotive class by the way)

Answers

D.) have proper tread :)

In order to avoid slipping in the shop, your footwear should have proper tread. The correct option is D.

What is slipping?

Slipping is an action of falling or sliding down due to a lack of friction between the surfaces. This occurs when both surfaces coming into contact are smooth or frictionless.

During rainy seasons, due to rain everywhere the chances of slipping increase, the slippers slip on mud or water. Vehicles also slip down on roads.

To avoid slipping, wear proper shoes. The shoes that have a good grip are less to slip. The tires are given with tread, which increases the grip on the road. Tread-on shoes or slippers are also good. Wear tread full shoes. It can avoid slipping and accidents.

Thus, the correct option is D. Have proper tread.

To learn more about slipping, refer to the link:

https://brainly.com/question/6327886

#SPJ2

Determine the design moment strength for a W21x73 steel beam with a simple span of 18 ft when lateral bracing for the compression flange is provided at the ends only (i.e., Lb

Answers

This question is incomplete, the complete question is;

Determine the design moment strength (ϕMn) for a W21x73 steel beam with a simple span of 18 ft when lateral bracing for the compression flange is provided at the ends only (i.e., Lb = 18 ft). Report the result in kip-ft.

Use Fy=50 ksi and assume Cb=1.0 (if needed).

Answer: the design moment strength for the W21x73 steel beam is 566.25 f-ft

Explanation:

Given that;

section  W 21 x 73 steel beam;

now from the steel table table for this section;

Zx = Sx = 151 in³

also given that; fy = 50 ksi and Cb = 1.0

QMn = 0.9 × Fy × Zx

so we substitute

QMn = 0.9 × 50 × 151

QMn = 6795 k-inch

we know that;

12inch equals 1 foot

so

QMn = 6795 k-inch / 12

QMn = 566.25 f-ft

Therefore the design moment strength for the W21x73 steel beam is 566.25 f-ft

A journeyman electrician with 16 years experience on-the-job was removing metal fish
tape from a hole at the base of a metal light pole. It was raining during the course of the
work. The fish tape became energized, electrocuting him. What could have been done to
prevent this accident? Select all that apply.

Answers

Explanation:

1. Ensure all circuits are de-energized before beginning work (29 CFR 1926.416(a)(3)).

2. Controls to be deactivated during the course of work on energized or de-energized

equipment or circuits must be tagged (29 CFR 1926.417(a)).

3. Employees must be instructed to recognize and avoid unsafe conditions associated with

their work (29 CFR 1926.21(b)(2)).


A gas stream (A) of 15.0 mol% H2, and the balance N2, is to be mixed with another gas stream
(B) containing 40.0 mol% H2, and the balance N2, to produce 100 kg/h of a 25 mol% H2, and the
balance N2 gas stream (C).
(a) Draw and fully label a flowchart of the mixing process.
(b) Calculate the average molecular weight of the product stream (C).
(c) Calculate the molar flow rates of the product stream (C) in kmol/h.
(d) Calculate the required flow rates of the feed mixtures A and B in kmol/h.

Answers

Answer:

A gas stream and other points are discussed below in details.

Explanation:

The method flow chart is displayed above.

B)Mole fraction of H2 in stream C=25%=0.25

Mole fraction of N2 in steams C=1-Mole fraction of H2=1-0.25=0.75

Average molecular weight of stream C=Mole fraction of H2*Molecular weight of H2+ Mole fraction of N2*Molecular weight of N2=0.25*2 kg/kmol+0.75*28 kg/kmol=21.5 kg/kmol

C) Mass flow rate of product C=100 kg/h

Molar flow rate of product C=Mass flow rate /Molecular weight=100 kg/h/21.5 kg/kmol=4.6512 kmol/h

D) Apply overall mole balance

Mole in=Mole out

Mole in=Mole of A+Mole of B=A+B

Let mole of A=A kmol/h

Mole of B=B kmol/h

Mole out=Mole of C stream=4.6512 kmol/h

A+B=4.6512 eq.1

Apply hydrogen mole balance

Mole of H2 in=Mole of H2 in A stream+ Mole of H2 in B stream=0.15 A+0.4 B

Mole of H2 out=Mole of H2 in C stream=0.25*4.6512=1.1628 kmol/h

1.1628 =0.15 A+0.4 B eq.2

Multiply eq.1 by 0.15

0.69768=0.15 A+0.15 B eq.3

Subtract eq.3 from eq.2

0.25 B=0.46512

B=1.86048 kmol/h

Substitute in eq1.

A=4.6512-1.86048=2.79042 kmol/h

Molar flow rate of A=2.79042 kmol/h

A molar flow rate of B=1.86048 kmol/h

What is a shop air compressor

Answers

Answer:

need more information about the question

5. (20 points) Identify and resolve (via forwarding) all the data hazards in the MIPS pipeline for the following sequence of MIPS instructions. Insert pipeline bubbles as necessary if forwarding cannot completely solve the data hazards. You may use multi-cycle pipeline representation to show the forwarding and bubbles. sub $4, $1, $3 sw $4, 0($2) lw $1, 0($2) add $1, $3, $4

Answers

Answer:

a

Explanation:

A fruit juice is being heated in an indirect heat exchanger using steam as a heating medium. The product flows through the heat exchanger at a rate of 1000 kg/h and the inlet temperature is 30 oC. Determine the quantity of steam required to heat the product to 100 oC when only latent heat of vaporization (2230.2 kJ/kg) from steam at 110oC is used for heating. The specific heat of the product is 4 kJ/(kg oC).

Answers

Answer:

The appropriate response will be "125.55 kg/hr".

Explanation:

The given values are:

Rate of heat exchanger,

m = 1000 kg/h

Inlet temperature,

T = 30°C

Specific heat,

[tex]c_p[/tex] = 4 kJ/(kg°C)

Now,

The heat taken by juice from steam will be:

⇒ [tex]Q=mc_p(\Delta T)[/tex]

On substituting the values, we get

⇒     [tex]=1000\times 4(100-30)[/tex]

⇒     [tex]=280000 \ kJ/hr[/tex]

The heat given by the steam to juice will be:

⇒ [tex]Q=m\times L[/tex]

On substituting the values, we get

⇒     [tex]=m\times 125.55[/tex]

On equating both the heat values, we get

⇒ [tex]280000=m\times 2230.2[/tex]

⇒         [tex]m=\frac{280000}{2230.2}[/tex]

⇒         [tex]m=125.55 kg/hr[/tex]

Ideal gas helium flows through the inlet of an isentropic nozzle with a velocity of 25 m/s, and the exit flow is at 100 kPa, 300 K, and has a velocity of 250 m/s. a. Determine the inlet temperature. b. Determine the inlet pressure. c. Determine the area ratio between inlet and exit

Answers

Answer:

a. The inlet temperature is approximately 305.232 K

b. The inlet pressure is approximately 452.0108 kPa

c. The area ratio between the inlet and exit is approximately 2.2509

Explanation:

a. From the energy equation related to the question, we have;

[tex]C_p \cdot (T_i - T_e) = \dfrac{1}{2} \cdot \left (v_e^2 - v_1^2 \right)[/tex]

Where;

[tex]C_p[/tex] = The specific heat capacity for helium = 5.913 kJ/(kg·K)

[tex]T_i[/tex] = The inlet temperature

[tex]T_e[/tex] = The exit temperature = 300 K

[tex]v_i[/tex] = The inlet velocity = 25 m/s

[tex]v_e[/tex] = The exit velocity = 250 m/s

Therefore, we have;

[tex]T_i= \dfrac{ \dfrac{1}{2} \cdot \left (v_e^2 - v_1^2 \right)}{C_p} + T_e = \dfrac{ \dfrac{1}{2} \times \left (250^2 - 25^2 \right)}{5.913 \times 1000} + 300 \approx 305.232[/tex]

The inlet temperature = [tex]T_i[/tex] ≈ 305.232 K

b. From the following equation for the critical pressure, for helium, we have;

[tex]\dfrac{P_c}{P_i} = \left (\dfrac{2}{n + 1} \right ) ^{\dfrac{n}{n - 1} } = 0.487[/tex]

Where;

[tex]P_c[/tex] = The critical pressure = 2.26 atm for helim

[tex]P_i[/tex] = The inlet pressure

n = The polytropic constant

We have;

[tex]\dfrac{2.26 \ atm}{P_i} = 0.487[/tex]

[tex]\therefore P_i = \dfrac{2.26 \ atm}{0.487} \approx 4.641 \ atm[/tex]

The inlet pressure, [tex]P_i[/tex] ≈ 4.641 atm ≈ 452.0108 kPa

c. The inlet to exit pressure ratio is given as follows;

[tex]P_e = \dfrac{A_i \times T_e \times v_i}{A_e \times T_i \times v_e} \times P_i[/tex]

Therefore, we have;

[tex]\dfrac{A_i}{A_e} = \dfrac{P_e \times T_i \times v_e}{ T_e \times v_i \times P_i} = \dfrac{100 \times 305.232 \times 250}{ 300 \times 25 \times 452.0108} = 2.2509[/tex]

The area ratio between the inlet and exit, [tex]A_i/A_e[/tex] ≈ 2.2509.

15 kg of ice at 0°C is heated to water of temperature 20°C. What is the amount of heat required if the specific latent heat of ice fusion is 335 kJ/kg and the specific heat capacity of water is 4.19kJ/kg/°C?

Answers

Answer:

6282 kJ

Explanation:

Given that:

The mass (m) = 15 kg

The specific latent heat of ice fusion [tex]h_{fg}_{ice}[/tex] = 335 kJ/kg

The specific heat capacity of water = 4.19 kJ/kg.c

The initial temperature of the ice [tex]T_i[/tex]= 0° C

The final temperature of the water [tex]T_f[/tex] = 20° C

To find the needed amount of heat to convert 0° C ice to 20° C of water.

To do that, we need to find the latent heat required for the phase change from 0° C ice to 0° C water, then the heat required to convert  0° C water to 20° C water.

Heat required = [tex]m \times h_{fg}_{ice}+ m \times c_{water} \times \Delta T[/tex]

Heat required = (15 × 335) + (15 × 4.19) × (20 - 0)

Heat required = 5025 + 62.85 × 20

Heat required = 5025 + 1257

Heat required = 6282 kJ

Which is a better hydraulic cross section for an open channel: one with a small or a large hydraulic radius?

Answers

Hydraulic radius is caused by pressurized hydrogen air so that should mean the answer is hydraulic radius

Which process made making copies of technical drawings easier?
In the nineteenth century, the process of ___________
helped professionals quickly create copies of technical drawings.

Answers

Answer:

The Process of printing

Explanation:

hope this helps :)

discuss 7 habits of highly effective people and how important are ethics in today's society​

Answers

Answer:

Explanation:

The 7 Habits of Highly Effective People, is a book written and first published in 1989. It is a business and self-help book that was written by Stephen Covey. The seven habits include

Being proactive

Starting anything with the end in mind

First things first

Always thinking towards a win-win situation

Seeking initially to understand, then going on to want to be understood

Synergize, and lastly

Growing

Which one of the following skills is a software engineer specializing in system support expected to possess?

ability to correct system maintenance issues
ability to direct traffic between devices
ability to develop user programming
ability to recommend system upgrades

Answers

Answer:

A. Ability to correct system maintenance issues

Explanation:

As a systems engineer, you will be responsible for a range of tasks, including management of IT systems, working with software developers to design and document new system architecture, and testing and implementing processes to improve the efficacy of existing systems.

a-ability to correct system maintenance issues

A heat exchanger is used to recover waste heat from an industrial furnace and use it to heat pressurized water. The heat exchanger consists of a tube bank with a square 10 x 10 array of thin-walled smooth tubes (total of 100 tubes). The tubes are aligned in-line with a transverse pitch, ST = 50 mm. Each tube is 25 mm in diameter and 4 m long. Water passes through each tube at a flow rate of 0.025 kg s-1, so the total flow rate through all 100 tubes is 2.5 kg s-1. The exhaust gas is in cross-flow over the tubes, with an upstream velocity of 5.0 m s-1 and total flow rate of 2.25 kg s-1. The exhaust gas has properties similar to air. The inlet temperatures of the water and exhaust gas are 300 K and 800 K, respectively. (a) What is the overall heat transfer coefficient between the water and the gas? (b) What are fluid outlet temperatures? As a first approximation, assume the water flow through the tubes is fully developed and turbulent, with an estimated bulk mean temperature of 350 K. Use a mean temperature of 600 K and properties of air to represent the exhaust gases. Please comment on the accuracy of these assumptions after you obtain your results, but you do not need to repeat any calculations.

Answers

Answer:

Explanation:

ok this is as test dont cheat i d

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