) The square plates of a 5000-pF parallel-plate capacitor measure 50 mm by 50 mm and are separated by a dielectric that is 0.23 mm thickand totally fills the region between the plates. The voltage rating (the maximum safe voltage) of the capacitor is 400 V. What is the maximum energy that can be stored in this capacitor without damaging it

A book is sitting on a desk is due to the Gravitational force of Earth Gravity so D. the downward force the Earth pulls on the book.

The force of attraction between all masses that is objects in the universe, especially the attraction of the Earth's mass for bodies near its surface.

Einstein said that the shape of spacetime is responsible for the rise of force that we experience as gravity. A concentration of mass, such as the Earth or sun, bends space around it like a rock bends the flow of a river.

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Answer:

Not D, every substance in existence has mass and is made from it in any given form.

B and C

Explanation:

The statements which are true about photons are:

Discussion:

The photon is a type of elementary particle. It is the quantum of the electromagnetic field including electromagnetic radiation such as light and radio waves, and the force carrier for the electromagnetic force.

Additionally, Photons are massless, so they always move at the speed of light in vacuum, 3 × 10⁸ m/s.

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Answer:

74 N to the right

Explanation:

the forces are going in opposite horizontal directions, meaning that they are directly opposing each other. this means that you can subtract the force applied in the direction that is greater from the direction that is less to get the net force for the greater direction

this means 182 N - 108 N = 74 N to the right

In a game of tug of war the magnitude and direction of the net horizontal force on the rope is 74 N.

A force in physics is an effect that has the power to alter an object's motion. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.

In a game of tug of war, a rope is pulled by a force of 182 N to the right and by a force of 108 N to the left. The magnitude and direction of the net horizontal force on the rope is,

F = 182 - 108

F = 74 N

The magnitude and direction of the net horizontal force on the rope is  74 N.

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Answer:

P = 180 [w]

Explanation:

To solve this problem we must use ohm's law, which is defined by the following formula.

V = I*R & P = V*I

where:

V = voltage = 200[volts]

I = current [amp]

R = resistance [ohm]

P = power [watts]

Since the bulbs are connected in series, the powers should be summed

P = 60 + 60 + 60

P = 180 [watts]

Now we can calculate the current

I = 180/200

I = 0.9[amp]

Attached is an image where we see the three bulbs connected in series, in the circuit we see that the current is the same for all the elements connected to the circuit.

And the power is defined by P = V*I

we know that the voltage is equal to 200[V], therefore

P = 200*0.9

P = 180 [w]

Answer:

T₂ is greater than T₁ by an amount independent of velocity

Explanation:

This is an exercise on Newton's second law

for block of mass m1

            T₁ = m₁ a

for block of mass m²

            T₂ = m₂ a

as it indicates that m₂> m₁

the tension T₂> T₁ also we see that in this equation there is no dependence with the velocity, but with the acceleration

the voltage difference does not depend on the speed of the vehicles

When reviewing the answers, the correct one is B

    T₂ is greater than T₁ by an amount independent of velocity

Answer:

B.  a hearing by a federal court of appeals

If any state tribunal decides a federal question and the litigant has no further remedy within the state court system, a hearing by a federal court of appeals.

Oral argument in the court of appeals is a prearranged conversation between the judges and the appellate attorneys that focuses on the legal principles at issue. Each party has a limited amount of time usually around 15 minutes to make their case to the judge.

If a litigant loses in a federal court of appeals or in the highest court of a state, they may ask the supreme court to reconsider the case by filing a petition.

Only when a case concerns an extremely significant legal concept or when two or more federal appellate courts have disagreed on how to interpret a statute will the court normally consent to consider it. Additionally, there are a few rare instances where the Supreme Court is mandated by the law to consider an appeal.

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Answer:

Both light and sound can be described in terms of wave forms with physical characteristics like amplitude, wavelength, and timbre. Wavelength and frequency are inversely related so that longer waves have lower frequencies, and shorter waves have higher frequencies

The ability of both to cause interference is the resemblance between sound waves and light waves.

While sound waves are mechanical, light waves are electromagnetic. Unlike sound waves, which are longitudinal, light waves are transverse. Light waves can go across a vacuum. Since sound waves need a physical medium to go through, they cannot move in a vacuum.

Both sound and light waves adhere to the rule of reflection, which states that the angle of incidence and angle of reflection are equal. Therefore, choice 2 is the right one. While light waves are transverse, sound waves are longitudinal.

In that, they both have an amplitude, a wavelength, a period, and a frequency, light, and sound waves are comparable to one another.

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Answer: Force of magnitude 20.22lbf to the right at angle 8.5°

Explanation: The image named "Untitled" below shows the forces acting on the cart.

The second image, "Untitled2", demonstrate the vector diagram of the forces acting on the kart, in which:

f is force forward

f(left) is pull to the left

f(R) is the resulting force necessary for the kart to move

The drag force is not draw on the vector diagram because its value is already part of the force forward.

As we can see, the diagram forms a right triangle with f(R) as hypotenuse.

Using Pytagorean Theorem:

[tex][f(R)]^{2}=f^{2}+[f(left)]^{2}[/tex]

[tex][f(R)]^{2}=20^{2}+3^{2}[/tex]

[tex][f(R)]^{2}=409[/tex]

[tex]f(R)=\sqrt{409}[/tex]

f(R) = 20.22

Force forward equals 20.22lbf to the right.

The angle formed form the forward direction and the resulting force is

[tex]cos\theta=\frac{20}{20.22}[/tex]

cosθ = 0.989

θ = cos⁻¹(0.989)

θ = 8.5°

The forward force is to the right at angle 8.5° and magnitude 20.22lbf.

Answer:

The tiger will land at 3.71 meters from the base of the rock

Explanation:

Horizontal Motion

When an object is thrown horizontally with a speed vo from a height h, the range or maximum horizontal distance traveled by the object can be calculated as follows:

[tex]\displaystyle d=v\cdot\sqrt{\frac {2h}{g}}[/tex]

The tiger leaps from a height of h=7.5 m with a speed of v=3 m/s. Substituting the values into the formula:

[tex]\displaystyle d=3\cdot\sqrt{\frac {2\cdot 7.5}{9.8}}=3.71\ m[/tex]

The tiger will land at 3.71 meters from the base of the rock

Answer:

(a) E = 3.6 x 10³ N/C = 3.6 KN/C

(b) ΔV = 1044 Volts

(c) K.E = 1.67 x 10⁻¹⁶ J

(d) Vf = 4.47 x 10⁵ m/s

(e) a = 3.45 x 10¹¹ m/s²

(f) F = 5.76 x 10⁻¹⁶ N

(g) E = 3.6 x 10³ N/C = 3.6 KN/C  

(h)  Both values are same in part (h) and (a)

Explanation:

(a)

Electric field between oppositely charged plates is given as follows:

E = σ/ε₀

where,

E = Electric Field Intensity = ?

σ = surface charge density = 32 nC/m² = 3.2 x 10⁻⁸ C/m²

ε₀ = Permittivity of free space = 8.85 x 10⁻¹² C²/N.m²

Therefore,

E = (3.2 x 10⁻⁸ C/m²)/(8.85 x 10⁻¹² C²/N.m²)

E = 3.6 x 10³ N/C = 3.6 KN/C

(b)

E = ΔV/r

ΔV = Er

where,

r = distance between plates = 29 cm = 0.29 m

ΔV = Potential Difference = ?

ΔV = (3.6 x 10³)(0.29)

V = 1044 Volts

(c)

Kinetic Energy of Proton = Work done on Proton

K.E = F r

but,  F = E q

K.E = E q r

where,

q = charge on proton = 1.6 x 10⁻¹⁹ C

Therefore,

K.E = (3600 N/C)(1.6 x 10⁻¹⁹ C)(0.29 m)

K.E = 1.67 x 10⁻¹⁶ J

(d)

K.E = (1/2)m(Vf² - Vi²)

where,

m = mass of proton = 1.67 x 10⁻²⁷ kg

Vf = Final Velocity = ?

Vi = Initial Velocity = 0 m/s

Therefore,

1.67 x 10⁻¹⁶ J = (1/2)(1.67 x 10⁻²⁷ kg)(Vf² - (0 m/s)²]

Vf² = (1.67 x 10⁻¹⁶ J)(2)/(1.67 x 10⁻²⁷ kg)

Vf = √(20 x 10¹⁰ m²/s²)

Vf = 4.47 x 10⁵ m/s

(e)

2as = Vf² - Vi²

2(a)(0.29 m) = (4.47 x 10⁵ m/s)² - (0 m/s)²

a = (20 x 10¹⁰ m²/s²)/0.58 m

a = 3.45 x 10¹¹ m/s²

(f)

F = ma

F = (1.67 x 10⁻²⁷ kg)(3.45 x 10¹¹ m/s²)

F = 5.76 x 10⁻¹⁶ N

(g)

E = F/q

E = (5.76 x 10⁻¹⁶ N)/(1.6 x 10⁻¹⁹ C)

E = 3.6 x 10³ N/C = 3.6 KN/C

(h)

Both values are same in part (h) and (a)

Answer:

28230 joules

Explanation:

becasue yes

Answer: Yes

Explanation: Because Electromagnetic waves form a continuous spectrum and all types of electromagnetic wave travel at the same velocity through a vacuum (space) or air. The waves that form the electromagnetic spectrum are grouped in terms of their wavelength and their frequency.

Answer: B. 15.2s

Explanation: 600/39.5 = about 15.2

Answer:

your answer is wavelength

Explanation:

the the highest service part of a weight is called the crest and the lowest part is the trough the vertical distance between the crest and the trough is the waist height the horizontal disc distance between two adjacent Crest or troughs is known as wavelengths

Answer:

0.75 meters per second; north

Explanation:

speed (velocity)= distance/time

15 meters= distance

20 seconds= time

15/20= 0.75 meters per second; north

Hope this helps!

Answer:

The total surface area of the seven little spheres is 1.91 times the total surface area of the bigger sphere.

Explanation:

Volume of a Sphere

The volume of a sphere of radius r is given by:

[tex]\displaystyle V=\frac{4}{3}\cdot \pi\cdot r^3[/tex]

The volume of each little sphere is:

[tex]\displaystyle V_l=\frac{4}{3}\cdot \pi\cdot 2^3[/tex]

[tex]V_l=33.51\ mm^3[/tex]

When the seven little spheres coalesce, they form a single bigger sphere of volume:

[tex]V_b=7*V_l=234.57\ mm^3[/tex]

Knowing the volume, we can find the radius rb by solving the formula for r:

[tex]\displaystyle V_b=\frac{4}{3}\cdot \pi\cdot r_b^3[/tex]

Multiplying by 3:

[tex]3V_b=4\cdot \pi\cdot r_b^3[/tex]

Dividing by 4π:

[tex]\displaystyle \frac{3V_b}{4\cdot \pi}= r_b^3[/tex]

Taking the cubic root:

[tex]\displaystyle r_b=\sqrt[3]{\frac{3V_b}{4\cdot \pi}}[/tex]

Substituting:

[tex]\displaystyle r_b=\sqrt[3]{\frac{3*234.57}{4\cdot \pi}}[/tex]

[tex]r_b=3.83\ mm[/tex]

The surface area of the seven little spheres is:

[tex]A_l=7*(4\pi r^2)=7*(4\pi 2^2)=351.86\ mm^2[/tex]

The surface area of the bigger sphere is:

[tex]A_b=4\pi r_b^2=4\pi (3.83)^2=184.33\ mm^2[/tex]

The ratio between them is:

[tex]\displaystyle \frac{351.86\ mm^2}{184.33\ mm^2}=1.91[/tex]

The total surface area of the seven little spheres is 1.91 times the total surface area of the bigger sphere.

Answer:

Motion map #3

Explanation:

because with velocity negative the arrows have to be the same size in the reverse direction.

Complete Question

A number 14 copper wire has a diameter of 1.628 mm. Calculate the resistance of a 37.0 m long piece of such wire.

(Use 1.72×10-8 ?m for the resistivity of copper.)

For safety, the National Electrical Code limits the allowable amount of current which such a wire may carry. When used in indoor wiring, the limit is 15.0 A for rubber insulated wire of that size. How much power would be dissipated in the wire of the above problem when carrying the maximum allowable current?

What would be the voltage between the ends of the wire in the above problem?

What is the current density in the wire when it is carrying the maximum allowable current? (Current density is the current in the wire divided by the cross sectional area of the wire.)

What is the drift velocity of the electrons when the wire is carrying the maximum allowable current?

(The density of electrons in copper is 8.47×1028 m-3.)

Answer:

a

 [tex]R =0.3057 \ \Omega [/tex]

b

 [tex]P  = 68.78 \ W  [/tex]

c

 [tex]V  = 4.5855 \ V[/tex]  

d

 [tex]J  =   7.205 *10^{6}\ A/m^2 [/tex]

e

 [tex]v_d  =  0.0005316 \ m/s[/tex]

Explanation:

From the question we are told that

   The resistivity of copper is  [tex]\rho =  1.72* 10^{-8} \  \Omega \cdot m[/tex]

   The  current limit is  [tex]I  =  15 \ A[/tex]

     The diameter is  [tex]d= 1.628 mm= 0.001628 \ m[/tex]

    The length of the wire is  [tex]l  =  37.0 m[/tex]

    The density of electron is  [tex]n  =   8.47*10^{28} m^{-3}[/tex]

Generally the radius is mathematically represented as

       [tex]r =  \frac{d}{2}[/tex]

=>     [tex]r =  \frac{0.001628}{2}[/tex]

=>     [tex]r =0.000814 \ m [/tex]

Generally the resistance is mathematically represented as

          [tex]R =  \frac{\rho  *  l }{A}[/tex]

Here A is the area which is mathematically represented as    

      [tex]A = 3.142 *   (0.00081)^2[/tex]

=>   [tex]A = 2.082 *10^{-6}\ m^2 [/tex]  

=>    [tex]R =  \frac{1.72* 10^{-8}  *  37.0  }{2.082 *10^{-6}}[/tex]

=>    [tex]R =0.3057 \ \Omega [/tex]

Generally the power dissipated is mathematically represented as

       [tex]P  =  I^2 R[/tex]

=>   [tex]P  =  (15)^2 *  0.3057 [/tex]

=>   [tex]P  = 68.78 \ W  [/tex]

Generally the voltage is mathematically represented as  

     [tex]V  =  I  * R[/tex]    

=>    [tex]V  =  15 * 0.3057[/tex]  

=>    [tex]V  = 4.5855 \ V[/tex]  

Generally the charge density is mathematically represented as

      [tex]J  =  \frac{I}{A}[/tex]

=>   [tex]J  =  \frac{15}{2.082 *10^{-6}}[/tex]

=>     [tex]J  =   7.205 *10^{6}\ A/m^2 [/tex]

Generally the drift velocity is mathematically represented as

     [tex]v_d  =  \frac{I}{ n  *  A *  e}[/tex]

Here e is the charge on an electron with value  [tex]e =  1.60 *10^{-19} \  C[/tex]

So

         [tex]v_d  =  \frac{15}{ 8.47*10^{28}  * 2.082 *10^{-6} *  1.60 *10^{-19} }[/tex]

 =>  [tex]v_d  =  \frac{15}{ 8.47*10^{28}  * 2.082 *10^{-6} *  1.60 *10^{-19} }[/tex]

 =>  [tex]v_d  =  0.0005316 \ m/s[/tex]

Answer:

5.5 is the correct answer

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Answer:

The total force on the cart is:  

F = F(applied) - F(friction) = (18 N) - (15 N) = 3.0 N  

The acceleration of the cart is:  

a = (change in velocity)/(time) = (1.0 m/s)/(5.0 s) = 0.20 m/s^2  

Using F = ma, the mass of the cart is:  

m = F/a = (3.0 N)/(0.20 m/s^2) = 15 kg

Answer: The answer is a

Explanation:

Answer:

Mass

axis

distance

intertia

Answer:

D. an ellipse with the Sun at one focus

Explanation:

Based on Kepler's work, the orbit of a planet around the Sun is an ellipse with the Sun at one focus.

Hence according to Kepler's first law of planetary motion, the orbit of a planet around the Sun is an ellipse with the Sun at one focus.

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Answer: 30.641

Explanation: If you get the ave which is 38.0 then the vi which is 7.359

38.0-7.359=30.641/0.0 which is 30.641

Answer:

Well we all know that bread and cake taste different. We do this on purpose.

Explanation:

When we make cake we add plenty of sugar to make it the delectable dessert we all know and love while when making bread we focus more on the corn starch and yeast's.

Answer:

The  dimension is  [tex]D =  L ^{2} T^{-1}[/tex]

Explanation:

From the question we are told that

     [tex]J  =  -D \frac{dn}{dx}[/tex]

Here  [tex][J] = \frac{1}{L^2 T}[/tex]

       [tex][n] =\frac{1}{L^3}[/tex]

        [tex][x] = L[/tex]

So

    [tex]\frac{1}{L^2 T} =  -D \frac{d(\frac{1}{L^3})}{d[L]}[/tex]

Given that the dimension represent the unites of  n and  x then the differential  will not effect on them

So

[tex]\frac{1}{L^2 T} =  -D \frac{(\frac{1}{L^3})}{[L]}[/tex]

=>   [tex]D =  \frac{L^{-2} T^{-1} * L }{L^{-3}}[/tex]

=>   [tex]D =  L ^{2} T^{-1}[/tex]

+500   because North is postiive direction

-300 because if you see it as a graph, left side is negative

-800 because South is downward

500-300-800 = -600

displacement is a vector, meaning it has both DIRECTION and magnitude

(literally the only physics problem i can easily solve lol)

Answer:

[tex]\mid D \mid = 424.26\ m[/tex]

Explanation:

Displacement

Suppose a moving object starts from point A and travels through a determined path to point B. The distance is the sum of all the partial distances traveled, and the displacement is the vector directed from A to B.

The path of the person is shown in the image below. Note the 500 m due north and the 800 m due south produce a distance of 300 m due south. The displacement vector D is the resultant of the whole movement.

To find the magnitude of the displacement, we need to calculate the hypotenuse of a triangle of sides 300 m (already described) and 300 m, marked in red.

The magnitude of D is:

[tex]\mid D \mid = \sqrt{300^2+300^2}[/tex]

[tex]\mid D \mid = \sqrt{90000+90000}[/tex]

[tex]\mid D \mid = \sqrt{180000}[/tex]

[tex]\mid D \mid = 424.26\ m[/tex]

Answer:

90

Explanation:

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