Answer:
Rubber Mallet
Explanation:
It is the most common types of hammers, it has a rubber head that allows a soft bang. They are used on sheet metal, woodworking, and filling. A rubber mallet is soft enough to force it without damaging the plasterboard.
100 POINTS!!!! PLZZ HELPPP 3. A jar made of 3/16 inch thick glass has an inside radius of 3.00 inches and total height of 6.00 inches (including the bottom thickness of glass). The glass has a density of 165 lb/ft3. The jar is placed in water with a density of 62.5 lb/ft3.
a. Assume the jar sits upright in the water without tipping over. How far will the empty jar sink into the water?
i. What is the volume of the glass shell of the jar? Precision 0.00
ii. What is the weight of the jar? Precision 0.00
iii. What is the weight of water the empty jar will displace? Precision 0.00
iv. What is the volume of water the empty jar will displace? Precision 0.00
v. How far will the empty jar sink?
Answer:
its only 50 points
Explanation:
If you have power steering and you are able to __________, you should have your vehicle checked out by a qualified technician.
Answer: drive
Explanation:
The best word that would fit this sentence is drive. A vehicle owner should know how to drive, and they can get their vehicle checked by a qualified technician. The best word that would fit this sentence is drive. If you have power steering and you are able to drive, you should have your vehicle checked by a qualified technician.
The profile height of the tire sidewall (from bead to tread) is 117 mm.
The height of the rim is 381 mm.
What is the total height of the rim and tire together?
Answer:
498 mm
Explanation:
The height of the tire sidewall is ; 117 mm
The height of the rim of the tire is: 381 mm
Total height of the rim and tire together is : 117 + 381 = 498 mm
Which of the following is an example of a product concept?
a new idea for a flying car
a convertible jacket/poncho that can transform into a floatation device
O a prototype of a self-propelled flying jetpack
O a new idea for a laptop software program
Answer:
A convertible jacket/poncho that can transform into a floatation device
Explanation:
A product concept normally on the assumption that it will attract customers to select the product due to its better qualities, features and performances.
A product concept is important because it will makes it necessary for a marketer to meet the demands and the wishes of users by delivering the best product.
Any help is appreciated <3
Answer:
forwarder
Explanation:
Select the correct answer. Jennifer, a construction manager at a construction firm, has to hire several contractors and subcontractors for a new project. She negotiates and finalizes contracts with the selected contractors and subcontractors. Which responsibility of a construction manager does Jennifer portray? A. project planning B. time management C. contract administration D. quality management
Answer:
C. Contract Administration
Explanation:
I got the answer correct on the quiz
Name the four ways in which heat is transferred from a diesel engine
Answer:
hope this helps!
Explanation:
Who can tell me how to time travel.
Answer:
speed, and using light
Explanation:
Which option identifies the step represented in the following scenario?
The team requests bids from a vendor to offer alternatives to raw materials that are too expensive for the proposed
price of the tablet.
solve the problem
define the problem
evaluate the problem
communicate the solution
Answer:
Solve the problem
Explanation:
The statement is : The team requests bids from a vendor to offer alternatives to raw materials that are too expensive for the proposed
price of the tablet.
The team wanted vendors to submit bids so that it can choose an alternative to raw materials to replace those that were expensive as compared to previous proposed price of a tablet. This is a process of solving the problem to identify a better solution.
What is the output of the following program fragment. Choose appropriate data-types of variables to match output.
i=7;j=8;k=9;
printf(“%d”,(i+10)%k/j);
Answer:
1
Explanation:
Given :
i=7;j=8;k=9;
printf(“%d”,(i+10)%k/j);
The printf function only displays the result
%d - is used for the display format
However, the actual calculation is in the expression: (i+10)%k/j
Given the variables :
i = 7 ;
j = 8 ;
k = 9 ;
(i + 10) = (7 + 10) = 17
(i + 10) % k = 17 % 9
% = remainder value after division
17 % 9 = (17 / 9) = 1 remainder 8
17 % 9 = 8
Hence,
(i + 10) % k = 8
(i + 10) % k / j
j = 8
8 / 8
= 1
QUESTION:
How does the G73 rough profile turning cycle differ from the other rough turn and face
cycles? The G73 cycle
write a trigonometry table
Explanation:
Trigonometric table :-
[tex]\begin{gathered}\begin{gathered}\begin{array}{ |c |c|c|c|c|c|} \bf\angle A & \bf{0}^{ \circ} & \bf{30}^{ \circ} & \bf{45}^{ \circ} & \bf{60}^{ \circ} & \bf{90}^{ \circ} \\ \\ \rm sin A & 0 & \dfrac{1}{2}& \dfrac{1}{ \sqrt{2} } & \dfrac{ \sqrt{3} }{2} &1 \\ \\ \rm cos \: A & 1 & \dfrac{ \sqrt{3} }{2}& \dfrac{1}{ \sqrt{2} } & \dfrac{1}{2} &0 \\ \\ \rm tan A & 0 & \dfrac{1}{ \sqrt{3} }& 1 & \sqrt{3} & \rm Not \: De fined \\ \\ \rm cosec A & \rm Not \: De fined & 2& \sqrt{2} & \dfrac{2}{ \sqrt{3} } &1 \\ \\ \rm sec A & 1 & \dfrac{2}{ \sqrt{3} }& \sqrt{2} & 2 & \rm Not \: De fined \\ \\ \rm cot A & \rm Not \: De fined & \sqrt{3} & 1 & \dfrac{1}{ \sqrt{3} } & 0 \end{array}\end{gathered}\end{gathered}[/tex]
Explanation:
[tex]\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\sf Trigonometry\: Table \\ \begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\boxed{\begin{array}{ |c |c|c|c|c|c|} \bf\angle A & \bf{0}^{ \circ} & \bf{30}^{ \circ} & \bf{45}^{ \circ} & \bf{60}^{ \circ} & \bf{90}^{ \circ} \\ \\ \rm sin A & 0 & \dfrac{1}{2}& \dfrac{1}{ \sqrt{2} } & \dfrac{ \sqrt{3}}{2} &1 \\ \\ \rm cos \: A & 1 & \dfrac{ \sqrt{3} }{2}& \dfrac{1}{ \sqrt{2} } & \dfrac{1}{2} &0 \\ \\ \rm tan A & 0 & \dfrac{1}{ \sqrt{3} }&1 & \sqrt{3} & \rm \infty \\ \\ \rm cosec A & \rm \infty & 2& \sqrt{2} & \dfrac{2}{ \sqrt{3} } &1 \\ \\ \rm sec A & 1 & \dfrac{2}{ \sqrt{3} }& \sqrt{2} & 2 & \rm \infty \\ \\ \rm cot A & \rm \infty & \sqrt{3} & 1 & \dfrac{1}{ \sqrt{3} } & 0\end{array}}}\end{gathered}\end{gathered}\end{gathered} \end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}[/tex]
Trigonometric table :-
[tex]\begin{gathered}\begin{gathered}\begin{array}{ |c |c|c|c|c|c|} \bf\angle A & \bf{0}^{ \circ} & \bf{30}^{ \circ} & \bf{45}^{ \circ} & \bf{60}^{ \circ} & \bf{90}^{ \circ} \\ \\ \rm sin A & 0 & \dfrac{1}{2}& \dfrac{1}{ \sqrt{2} } & \dfrac{ \sqrt{3} }{2} &1 \\ \\ \rm cos \: A & 1 & \dfrac{ \sqrt{3} }{2}& \dfrac{1}{ \sqrt{2} } & \dfrac{1}{2} &0 \\ \\ \rm tan A & 0 & \dfrac{1}{ \sqrt{3} }& 1 & \sqrt{3} & \rm Not \: De fined \\ \\ \rm cosec A & \rm Not \: De fined & 2& \sqrt{2} & \dfrac{2}{ \sqrt{3} } &1 \\ \\ \rm sec A & 1 & \dfrac{2}{ \sqrt{3} }& \sqrt{2} & 2 & \rm Not \: De fined \\ \\ \rm cot A & \rm Not \: De fined & \sqrt{3} & 1 & \dfrac{1}{ \sqrt{3} } & 0 \end{array}\end{gathered}\end{gathered}[/tex]