To cover the house roof, as we only need 6,750 shingles and we have 7,200 shingles available.
What are arithmetic operations ?
Arithmetic operations are basic mathematical operations used to perform calculations involving numbers. The four basic arithmetic operations are:
Addition: This operation involves combining two or more numbers to get a total or sum. The symbol used for addition is "+".Subtraction: This operation involves finding the difference between two numbers. The symbol used for subtraction is "-".Multiplication: This operation involves finding the product of two or more numbers. The symbol used for multiplication is "×" or "*".Division: This operation involves dividing a number into equal parts or finding how many times one number fits into another. The symbol used for division is "÷" or "/".According to the question:
To determine the amount of shingles needed to cover the roof of the house, we can use the fact that every 2 yards requires 3 shingles. Therefore, for 4500 yards, we need to divide by 2 and then multiply by 3 to get the total number of shingles needed.
(4500 yards) / (2 yards/2) * (3 shingles/2 yards) = 6,750 shingles
Since we have 60 boxes that contain 120 shingles each, we can calculate the total number of shingles we have:
60 boxes * 120 shingles per box = 7,200 shingles
Therefore, we have more than enough shingles to cover the roof, as we only need 6,750 shingles and we have 7,200 shingles available.
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a delivery truck driver charges a fixed base price of $6 for 2 miles. after 2 miles, he charges an additional $2 for every mile after 6 miles he charges an additional $4 for every mile
The analysis of the relationship in the question and the graph of the relationship indicates that the cost of the delivery truck between 1 mile and 2 miles is a constant, therefore;
The cost of the delivery truck between 1 mile and 2 miles is constant.What is the graph of a dataset?The graph of a dataset displays the relationship, between the variables in the dataset. It is a visual representation of the connection between the variables.
The fixed base price of the delivery truck for (the first) 2 miles = $6
The additional amount the delivery truck charges after 2 miles = $2 per mile
The additional amount charged by the delivery truck after 6 miles = $4 per mile
The part of the question obtained from a similar question posted on the website, includes;
The description of the cost of the delivery truck between 1 mile and 2 milesThe cost of the delivery truck, between 1 mile and 2 miles based on the graph is an horizontal line.
The horizontal line of a graph, indicates that the relationship between the input and output is a constant, such that the output of the relationship, within the interval of the horizontal line is a constant. The correct option is therefore;
b). The cost of the delivery truck between 1 mile and 2 miles is constant
The possible question options includes;
a) More information is required to determine the cost of the delivery truck between 1 mile and 2 miles
b) The cost of the delivery truck between 1 mile and 2 miles, is constant
c) The cost of the delivery truck is decreasing between 1 mile and 2 miles
d) The cost of the delivery truck is increasing between 1 mile and 2 miles
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The area of the intersection of a circle and a triangle is 45% of the area of their union. The area of the triangle outside the circle is 40% of the area of their union. What percentage of the circle lies outside the triangle?
Answer:
Percentage of the circle that lies outside the triangle = 15%
Step-by-step explanation:
Given,
The area of the intersection of circle and triangle is 45% of the area of the union.
The area of the triangle outside of the circle is 40% of the area of their union.
Required to find,
The percentage of the circle lies outside the triangle
Let us take 'C' as the area of the circle and 'T' as the area of the triangle.
The union of the area of the circle and triangle = C∪T
Let CUT be A
and the percentage of the circle that lies outside the triangle be 'x'
The intersection of the area of the circle and triangle = C∩T
Area of the triangle outside the circle = T - C
Area of the circle outside the triangle = C - T
Given,
C∩T = 45% of CUT = 45% of A
T - C = 40% of CUT = 40% of A
We know that,
The union of the area of the circle and triangle = Area of The intersection of the area of the circle and triangle + Area of the triangle outside the circle + Area of the circle outside the triangle
(CUT) = (C∩T) + (T - C) + (C - T)
[tex]A = 45\%A + 40\%A + x\%A[/tex]
[tex]A = (85+x)\% A[/tex]
[tex]85 +x = 100[/tex]
∴ [tex]x = 15[/tex]
Percentage of the circle that lies outside the triangle = 15%
Create a random triangle,
ABC . Record the lengths of its sides.
The triangle ABC with the given dimensions:AB = 10, BC = 6, CA = 90 are constructed.
Explain about the side-side-side congruence?You may determine the third angle by deducting the first two angles from 180 if you know the angles of one SSS triangle and another SSS triangle.Triangles that have corresponding sides with the same measurements are subject to the SSS hypothesis. A triangle with sides of 3, 4, & 5 and a triangle with sides of 4, 3, and 5 are two examples. SSS triangles—triangles whose values of all three sides coincide also with parameters of the second triangle—are also known as SSS triangles.The dimension of the triangle ABC are:
AB = 10
BC = 6
CA = 90
Thus, the triangle with the given dimensions are constructed.
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Create a trigonometric function that models the ocean tide..
Explain why you chose your function type. Show work for any values not already outlined above.
Answer:
One possible function that models the ocean tide is:
h(t) = A sin(ωt + φ) + B
where:
h(t) represents the height of the tide (in meters) at time t (in hours)
A is the amplitude of the tide (in meters)
ω is the angular frequency of the tide (in radians per hour)
φ is the phase shift of the tide (in radians)
B is the mean sea level (in meters)
This function is a sinusoidal function, which is a common type of function used to model periodic phenomena. The sine function has a natural connection to circles and periodic motion, making it a good choice for modeling the regular rise and fall of ocean tides.
The amplitude A represents the maximum height of the tide above the mean sea level, while B represents the mean sea level. The angular frequency ω determines the rate at which the tide oscillates, with one full cycle (i.e., a high tide and a low tide) occurring every 12 hours. The phase shift φ determines the starting point of the tide cycle, with a value of zero indicating that the tide is at its highest point at time t=0.
To determine specific values for A, ω, φ, and B, we would need to gather data on the tide height at various times and locations. However, typical values for these parameters might be:
1. A = 2 meters (representing a relatively large tidal range)
2. ω = π/6 radians per hour (corresponding to a 12-hour period)
3. φ = 0 radians (assuming that high tide occurs at t=0)
4. B = 0 meters (assuming a mean sea level of zero)
Using these values, we can write the equation for the tide as:
h(t) = 2 sin(π/6 t)
We can evaluate this equation for various values of t to get the height of the tide at different times. For example, at t=0 (the start of the cycle), we have:
h(0) = 2 sin(0) = 0
indicating that the tide is at its lowest point. At t=6 (halfway through the cycle), we have:
h(6) = 2 sin(π/2) = 2
indicating that the tide is at its highest point. We can also graph the function to visualize the rise and fall of the tide over time:
Tide Graph
Overall, this function provides a simple and effective way to model the ocean tide using trigonometric functions.
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please help me with 4 math questions
Using linear negative association, According to the all four parts correct options are D ;A ;D ;D respectively
What is linear negative association?The slope of a line expresses a great deal about the linear relationship between two variables. If the slope is negative, there is a negative linear relationship, which means that as one variable increases, the other variable decreases. If the slope is zero, one increases while the other remains constant.
The first answer to the question is option D
The second answer to the question must be option A
Option D must be chosen for the third question.
Option D must be selected for Question 4.
Solution:
1.
square of 3 is 9
3 to the power of negative 2 is 1/ 9
cube of 3 is 27
3 to the negative power 3 is 1/27
2.
cylinder volume =πr²h
Given value
pi =3.14
r=5
h=10
Volume=3.14×5²×10
cylinder volume =785m³
3.
When a point is rotated 90 degrees anticlockwise about the origin, it becomes the point (x,y) (-y,x).
The coordinates of Point N are (4, 3)
N' will be the new coordinates (-3, 4)
As a result, the y-coordinate of N' is 4.
4.
Option D must be selected for Question 4.
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10. What is the total surface area of the drawing?
A. 549 km²
B. 256 km²
C. 564 km²
D. 265 km²
Justin purchased his dream car worth 18500 on a finance for 4 years. He was offered 6% interest rate.assuming no other chargers and no tax,we want to find his monthly installment.
Answer:
To calculate Justin's monthly installment, we need to use the formula for calculating the monthly payment for a loan:
P = (r * A) / (1 - (1 + r)^(-n))
where P is the monthly payment, r is the monthly interest rate, A is the loan amount, and n is the total number of payments (in months).
In this case, A = 18500, r = 0.06/12 = 0.005 (since the annual interest rate is 6%, we divide by 12 to get the monthly rate), and n = 4*12 = 48 (since the loan is for 4 years, or 48 months).
Plugging in these values, we get:
P = (0.005 * 18500) / (1 - (1 + 0.005)^(-48))
P ≈ $432.85
Therefore, Justin's monthly installment would be approximately $432.85
PLEASE HELPPP ME MATH
The coordinates of the image of point D that ensures that the triangles are congruent is (-2, 2)
How to determine the coordinates of point DGiven the triangle ABC and the incomplete triangle DEF
From the triangle transformation of points B and C, we can see that
The points of the triangle ABC are translated to the left by 6 units and downward by 4 units
Mathematically, this can be represented as
(x, y) = (x - 6, y - 4)
Given that
A = (4, 6)
So, we have
D = (4 - 6, 6 - 4)
Evaluate the difference
D = (-2, 2)
Hence, the position is (-2, 2)
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An aquarium of height 1.5 feet is to have a volume of 12ft^3. Let x denote the length of the base and y the width.
a) Express y as a function of x.
b) Express the total number S of square feet of glass needed as a function of x.
The aquarium has six rectangular faces, four of which are identical (two sides and two ends), and two of which are identical to each other but different from the others (top and bottom).
What is the needed as a function?a) We can use the formula for the volume of a rectangular prism, which is given by V = lwh, where l is the length, w is the width, and h is the height. In this case, we have [tex]V = 12 ft^3 and h = 1.5 ft[/tex] . We want to express y as a function of x, so we need to eliminate w from the equation.
We can rearrange the equation for the volume to get [tex]w = V/(lh)[/tex] , and substitute in h [tex]= 1.5 ft[/tex] :
[tex]w = V/(1.5lx)[/tex]
Now we can substitute y for w to get:
[tex]y = V/(1.5lx)[/tex]
b) To find the total surface area, we need to find the area of each face and add them up.
The area of one of the identical sides or ends is lw, so the total area of these four faces is:
[tex]4lw = 4xy[/tex]
The area of the top and bottom faces is lx, so the total area of these two faces is:
[tex]2lx[/tex]
Therefore, the total surface area S is given by:
[tex]S = 4xy + 2lx[/tex]
We can express y in terms of x using the equation from part a):
[tex]y = V/(1.5lx)[/tex]
Substituting this into the expression for S, we get:
[tex]S = 4x(V/(1.5lx)) + 2lx[/tex]
Simplifying, we get:
[tex]S = (8/3)V/x + 2lx[/tex]
So the total surface area S is a function of x, and we can use this equation to find the value of S for any given value of x.
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What is the solution of
O x≤-3 or 2
Ox<-3 or 2
O-3≤x≤2
or x > 7
O-3 7
x²+x-6
<0?
X-7 50₂
Answer:
[-3, 7].
Step-by-step explanation:
do i need to explain all that?
Answer:
The inequality can be rewritten as x-7 ≤ 50, which we can solve by adding 7 to both sides to get x ≤ 57.
Step-by-step explanation:
It seems like there are multiple questions combined in this one prompt. I will break them down and provide solutions for each one.
Solution for O x≤-3 or 2 Ox<-3 or 2 O-3≤x≤2 or x > 7:
To find the solution for this inequality, we need to solve each part separately and then combine the solutions using the union (OR) operation.
a) x ≤ -3: This part is already solved for x. The solution is x ≤ -3.
b) 2x < -3: We divide both sides by 2 to isolate x and get x < -3/2.
c) 2 ≤ x ≤ -3: This is not possible as there is no number that is both greater than or equal to 2 and less than or equal to -3.
d) x > 7: This part is already solved for x. The solution is x > 7.
The solution to the entire inequality is the union of these solutions: x ≤ -3 OR x < -3/2 OR x > 7.
Solution for x²+x-6 < 0
To solve this quadratic inequality, we can factor it as (x-2)(x+3) < 0 and use the sign chart method.
We create a sign chart for the expression (x-2)(x+3) and test the sign of the expression in each interval
-3 2
---|-------|---
- +
(x-2) - 0 + +
(x+3) - - - 0 +
-------------
- + - 0 +
The sign chart tells us that the expression is negative when x is between -3 and 2. Therefore, the solution to the inequality is -3 < x < 2.
Solution for x-7 ≤ 50₂
It seems like the expression "50₂" is intended to represent the number 50 in base 2 (binary). To convert this number to base 10 (decimal), we can write 50₂ as
50₂ = 12^5 + 12^4 + 02^3 + 02^2 + 12^1 + 02^0 = 32 + 16 + 2 = 50
Therefore, the inequality can be rewritten as x-7 ≤ 50, which we can solve by adding 7 to both sides to get x ≤ 57.
A regular hexagon is inscribed into a circle. Find the length of the side of the hexagon, if the radius of the circle is 12 cm.
A. 20 cm
B. 18 cm
C. 16 cm
D. 12 cm
E. None of these
The length of the side of the hexagon is 12 cm and option d is the correct answer.
What is a regular polygon?A regular polygon is a closed shape made up of straight line segments with sides and angles that are all of the same length. For instance, a regular hexagon is a polygon having six equal-length sides and six equal-sized angles. Regular polygons have a variety of intriguing characteristics. For instance, their diagonals (lines connecting non-adjacent vertices) all intersect at a single point, and their centre of symmetry is located at the centre of the polygon's circumscribed circle (the circle that passes through all of the polygon's vertices).
Given that, regular hexagon is inscribed into a circle.
The radius of a circle enclosing a regular hexagon is the same as the length of the hexagon's sides.
Hence, the length of the side of the hexagon is 12 cm and option d is the correct answer.
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A company makes wax candles shaped like rectangular prisms. Each candle is 4 cm long, 3 cm wide, and 10 cm tall. If the company used 4080^3 cm of wax, how many candles did they make?
Answer:
87
Step-by-step explanation:
87
What is the equation of the circle in the standard (x, y) coordinate plane that has a radius of 4 units and the same center as the circle determined by x^2 + y^2 - 6y + 4=0?
A. x² + y^2 = -4
B. (x+3)^2 + y^2 = 16
C. (x-3)^2 + y^2 = 16
D. x^2 + (y+3)^2 = 16
E. x^2 + (y-3)^2 = 16
Answer:
E. x² + (y - 3)² = 16
Step-by-step explanation:
The equation of a circle in the standard (x, y) coordinate plane with center (h, k) and radius r is given by:
[tex]\boxed{(x - h)^2 + (y - k)^2 = r^2}[/tex]
To find the equation of the circle with a radius of 4 units and the same center as the circle determined by x² + y² - 6y + 4 = 0, we need to first write the equation of the second circle in the standard form.
We can complete the square for y to rewrite this equation in standard form. To do this move the constant to the right side of the equation:
[tex]\implies x^2 + y^2 - 6y + 4 = 0[/tex]
[tex]\implies x^2 + y^2 - 6y = -4[/tex]
Add the square of half the coefficient of the term in y to both sides of the equation:
[tex]\implies x^2 + y^2 - 6y +\left(\dfrac{-6}{2}\right)^2= -4+\left(\dfrac{-6}{2}\right)^2[/tex]
[tex]\implies x^2 + y^2 - 6y +9= -4+9[/tex]
[tex]\implies x^2 + y^2 - 6y +9=5[/tex]
Factor the perfect square trinomial in y:
[tex]\implies x^2+(y-3)^2=5[/tex]
[tex]\implies (x-0)^2 + (y-3)^2=5[/tex]
So the center of this circle is (0, 3) and its radius is √5 units.
Since the new circle has the same center, its center is also (0, 3).
We know its radius is 4 units, so we can write the equation of the new circle as:
[tex]\implies (x - 0)^2 + (y - 3)^2 = 4^2[/tex]
[tex]\implies x^2 + (y - 3)^2 = 16[/tex]
Therefore, the equation of the circle in the standard (x, y) coordinate plane with a radius of 4 units and the same center as the circle determined by x² + y² - 6y + 4 = 0 is x² + (y - 3)² = 16.
To find:-
The equation of circle which has a radius of 4units and same centre as determined by x² + y² - 6y + 4 = 0.Answer:-
The given equation of the circle is ,
[tex]\implies x^2+y^2-6y + 4 = 0 \\[/tex]
Firstly complete the square for y in LHS of the equation as ,
[tex]\implies x^2 + y^2 -2(3)y + 4 = 0 \\[/tex]
Add and subtract 3² ,
[tex]\implies x^2 +\{ y^2 - 2(3)(y) + 3^2 \} -3^2 + 4 = 0 \\[/tex]
The term inside the curly brackets is in the form of a²-2ab+b² , which is the whole square of "a-b" . So we may rewrite it as ,
[tex]\implies x^2 + (y-3)^2 -9 + 4 = 0 \\[/tex]
[tex]\implies x^2 + (y-3)^2 - 5 = 0 \\[/tex]
[tex]\implies x^2 + (y-3)^2 = 5\\[/tex]
can be further rewritten as,
[tex]\implies (x-0)^2 + (y-3)^2 = \sqrt5^2\\[/tex]
now recall the standard equation of circle which is ,
[tex]\implies (x-h)^2 + (y-k)^2 = r^2 \\[/tex]
where,
(h,k) is the centre.r is the radius.So on comparing to the standard form, we have;
[tex]\implies \rm{Centre} = (0,3)\\[/tex]
Now we are given that the radius of second circle is 4units . On substituting the respective values, again in the standard equation of circle, we get;
[tex]\implies (x-h)^2 + (y-k)^2 = r^2 \\[/tex]
[tex]\implies (x-0)^2 + (y-3)^2 = 4^2 \\[/tex]
[tex]\implies \underline{\underline{\red{ x^2 + (y-3)^2 = 16}}}\\[/tex]
and we are done!
Check them all Determine if the conditions are met for constructing a confidence interval for the population mean in each of the following settings.
a. How much time do students at your school spend on the Internet? You collect data from the members of your AP Statistics class and calculate the mean amount of time that these students spent on the Internet yesterday.
b. Is the real-estate market heating up? To estimate the mean sales price, a realtor in a large city randomly selected home sales from the previous months in her city. These sales prices are displayed in the boxplot.
Conditions for constructing a confidence interval for the population mean are met in first scenario. Conditions are generally met for population mean sales price, but potential outliers and non-normality need to be checked.
Yes, the conditions are met for constructing a confidence interval for the population mean in first scenario. The sample is randomly selected and independent, and we can also assume that the sample size is sufficiently large due to the Central Limit Theorem.
The sample comes from a normal population, or use a t-distribution if the sample size is small and the population standard deviation is unknown.
Yes, the conditions are generally met for constructing a confidence interval for the population mean sales price. We can assume that the sample is randomly selected and independent, and we can also assume that the sample size is sufficiently large due to the Central Limit Theorem.
However, we may want to check for these issues and consider using a non-parametric method, such as a confidence interval based on the median or the bootstrap, if there are concerns.
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3
1 point
Find the area of the composite figure below:
16.4 cm
5.5 cm
7 cm
The area of the composite figure is 159.9 cm²
Calculating the area of the composite figureFrom the question, we are to determine the area of the given composite figure
In the given diagram, the area of the composite figure = Area of triangle + Area of rectangle
First, we will calculate the area of the triangle
Area of triangle = 1/2 × base × height
Thus,
Area of the triangle = 1/2 × 16.4 × 5.5
Area of the triangle = 45.1 cm²
Calculating the area of the rectangle
Area of rectangle = Length × Width
Thus,
Area of the rectangle = 16.4 × 7
Area of the rectangle = 114.8 cm²
Therefore,
The area of the composite figure = 45.1 cm² + 114.8 cm²
The area of the composite figure = 159.9 cm²
Hence, the area is 159.9 cm²
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Write the equation for a parabola with a focus at (2,2) and a directrix at x=8
Answer:
(y - 2)² = -12(x - 5)
Step-by-step explanation:
A parabola is a locus of points, which are equidistant from the focus and directrix;
Generic cartesian equation of a parabola:
y² = 4ax, where the:
Focus, S, is: (a, 0)
Directrix, d, is: x = -a
a > 0
Put simply, a is the horinzontal difference between the directrix and the vertex or between the vertex and focus;
Always a good idea to do a quick drawing of the graph;
We are the told the focus, F, is: (2, 2) and directrix, d, is: x = 8;
First thing to note, the vertex, or turning point will be in line with the focus vertically, i.e. they will share the same y-coordinate;
Horizonatally, it will be halfway between the focus and the directrix, i.e. halfway between 8 and 2;
Therefore, the vertex will be will be (5, 2);
We can also work out a:
a = 8 - 5 = 5 - 2
a = 3
Substituting this value of a into the generic cartesian equation:
y² = 4(3)x
y² = 12x
The focus and directrix will be:
S: (3, 0)
d: x = -3
Next thing to note, a parabola curves away from the directrix;
In this case, the directrix is x = 8, so the vertex will be the right-most point on the parabola, it will curve off to the left and the focus will also be to the left;
What we want to do is compare with y² = 12x;
This parabola, has a vertex (0, 0), which is the left-most point that curves off to the right and a focus also to the right;
Since we know the formula of this parabola, if we figure out how to transform it into the one in the question, we can find out it's equation;
What we should recognise first is that the parabola in the question is reflected in the y-axis, compared to y² = 12x;
So we apply the transformation that corresponds to this, i.e. use the f(-x) rule:
y² = 12(-x)
y² = -12x
Now the two graphs will have the same shape and orientation;
The focus and directrix will also be affected:
S: (-3, 0)
d: x = 3
Now, the only remaining difference would be the coordinates of the focus and directrix of the two graphs;
The focus of the graph in the question is 5 units to the right and 2 units upwards compared to the focus of y² = -12x;
The directrix is 5 units to the right of that of y² = -12x;
So we apply a translation transformation of 5 units right and 2 units up, like so:
(y - 2)² = -12(x - 5)
Replace y with (y - 2) to translate up 2 units;
Replace x with (x - 5) to translate 5 units right.
We know have a parabola with focus, (2, 2), directrix, x = 8 and vertex, (5, 2), i.e. the parabola in the question;
Hence, the equation of the parabola in the question is:
(y - 2)² = -12(x - 5)
It might seem a bit long and complicated to begin with, but can be done very quickly if you can get used to it.
Ben knows that a line passes through the point (-3, 8) and has a slope of -3/4, but he needs to find the equation of the line. Therefore, he should substitute 8 for Response area and he should substitute -3 for Response area, and he should substitute -3/4 for Response area into the Point-Slope Formula. He will need to Response area and simplify before solving for y = mx + b form.
Answer:
y = -3/4 + 10 1/4
Step-by-step explanation:
y = mx + b
We are given the slope -3/4.
y = -3/4x + b To find the b we will use the point (-3,8) We will use -3 for x and 8 for y and then solve for b
8 = -3/4 (-3) + b
8 = -9/4 + b Add 9/4 to both sides
8 + 9/4 = -9/4 + 9/4 + b
41/4 = b or 10 1/4 = b
Helping in the name of Jesus.
xfind the volume v of the solid obtained by rotating the region bounded by the given curves about the specified line. y
The volume of the solid obtained by rotating the region bounded by the curves y = x and y = √x about the line x = 6 is (128π/15) - (13π/3), or approximately 3.013 cubic units.
To find the volume of the solid obtained by rotating the region bounded by the curves y = x and y = √x about the line x = 6, we can use the method of cylindrical shells.
First, we need to determine the limits of integration. Since the curves intersect at (0,0) and (1,1), we can integrate with respect to y from 0 to 1.
The radius of each cylindrical shell is the distance from the line x = 6 to the curve y = x or y = √x. We can express this distance as r = 6 - x or r = 6 - y^2, depending on which curve we are using.
The height of each cylindrical shell is the difference between the two curves at the given y-value. This is given by h = y - √x for y = x, and h = y^2 - x for y = √x.
Therefore, the volume of the solid is:
V = ∫(2πrh) dy from 0 to 1
Substituting r and h, we get:
V = ∫(2π(6 - x)(y - √x)) dy from 0 to 1 (for y = x)
V = ∫(2π(6 - y^2)(y^2 - x)) dy from 0 to 1 (for y = √x)
Evaluating these integrals using u-substitution and simplifying, we get:
V = (128π/15) - (13π/3)
Therefore, the volume of the solid is (128π/15) - (13π/3), or approximately 3.013 cubic units
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_____The given question is incomplete, the complete question is given below:
Find the volume V of the solid obtained by rotating the region bounded by the given curves about the specified in y = x, y = sqrt(x) ; about x = 6
Petra has a jar full of marbles. It has 30 blue marbles and 70 red marbles. She randomly chooses one marble, replaces it and then chooses a second marble. What is the probability Petra chose two blue marbles? What is the probability Petra chose two red marbles?
6. Deepa's age is three times that of her brother Devan. After 2 years Deepa's age would
be two times that of Devan. How old are they now?
Answer:
Devan's age = 2 years.
Deepa's age = 6 years.
Step-by-step explanation:
Framing and solving algebraic equation:Present age:
Let the present age of Devan = x
Present age of Deepa = 3x
After 2 years:
Age of Devan = x + 2
Age of Deepa = 3x + 2
Deepa's age = 2* Devan's age
3x + 2 = 2 *(x + 2)
3x + 2 = 2x + 2*2 {Use distributive property}
3x + 2 = 2x + 4
Subtract '2' from both sides,
3x = 2x + 4 - 2
3x = 2x + 2
Subtract '2x' from both sides,
3x - 2x = 2
x = 2
Devan's age = 2 years.
Deepa's age = 3*2
= 6 years
Change this mixed number to an improper fraction. Use the / key to enter a fraction e.g. half = 1/2
No spam links, please.
Answer:
35/8
Step-by-step explanation:
A mixed fraction in the form [tex]a \dfrac{b}{c}[/tex] can be converted to an improper fraction using the following calculation:
[tex]a \dfrac{b}{c} = \dfrac{(a \times b) + b}{c}[/tex]
Here we have the improper fraction [tex]4 \dfrac{3}{8}[/tex]
Using the technique described
[tex]4 \dfrac{3}{8} = \dfrac{4 \times 8 + 3}{8} = \dfrac{32+ 3}{8} = \dfrac{35}{8}[/tex]
Ans: 35/8
Bria is a customer who would like to display her collection of soap carvings on top of her bookcase. The collection needs an area of 300 square inches. What should b equal for the top of the bookcase to have the correct area? Round your answer to the nearest tenth of an inch.
help me pls D;
please !!!!
In linear equatiοn, the bοοkcase shοuld be apprοximately 12.2 inches in οrder tο give Bria's sοap carving cοllectiοn a 300-square-inch area.
What in mathematics is a linear equatiοn?An algebraic equatiοn with simply a cοnstant and a first-οrder (linear) term, such as y=mx+b, where m is the slοpe and b is the y-intercept, is knοwn as a linear equatiοn.
Sοmetimes, the afοrementiοned is referred tο as a "linear equatiοn οf twο variables," where x and y are the variables. Equatiοns with variables οf pοwer 1 are referred tο as linear equatiοns. One example with οnly οne variable is where ax+b = 0, where a and b are real values and x is the variable.
the bοοkcase's tοp is rectangular, with length "L" and width "b". Because the area οf a rectangle is the prοduct οf its length and width, we get:
L * b = 300
Tο find "b," we can rearrange the equatiοn as fοllοws:
b = 300 / L
L ≈ 2b
When we plug this intο the equatiοn abοve, we get:
b = 300 / (2b) (2b)
Tο simplify, we have:
b² = 150
When we take the square rοοt οf bοth sides, we get:
b ≈ 12.2
We have, rοunded tο the nearest tenth οf an inch:
b ≈ 12.2 inches
the width οf the tοp οf the bοοkcase shοuld be apprοximately 12.2 inches in οrder tο give Bria's sοap carving cοllectiοn a 300-square-inch area.
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The Venn diagram here shows the cardinality of each set. Use this to find the cardinality of the given set.
cardinality of the given set n(A'∩B') is 19
Define Venn DiagramIn a Venn diagram, circles are used to represent connections between objects or small groups of objects. Circles that overlap have some properties, but circles that do not overlap do not have properties. Venn diagrams are very useful for showing how two concepts are related and different graphically.
This Venn diagram illustrates the relationship between the subsequent set of integers.
Whereas the other set comprises the numbers in the 5x table from 1 to 25, the first set only contains even numbers from 1 to 25.
The intersection component demonstrates that 10 and 20 are both multiples of 5 from 1 to 25 and even integers.
Complement of A =14+5+12+7=38
Complement of B=7+4+3+9+12+7=42
n(A'∩B')=19
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What gravitational force does the moon produce on the Earth if their centers are 3.88x108 m apart and the moon has a mass of 7.34x1022 kg?
The gravitational force that the moon produces on the Earth is approximately 1.99x10²⁰ N.
What is Newton's law of gravitation?Every particle in the universe attracts every other particle with a force that is proportional to the product of their masses and inversely proportional to the square of the distance between their centers, according to Newton's rule of universal gravitation.
We can use Newton's law of gravitation to solve this problem:
[tex]$F = G \frac{m_1 m_2}{r^2}$[/tex]
where F is the gravitational force, G is the gravitational constant, [tex]$m_1$[/tex] and [tex]$m_2$[/tex] are the masses of the two objects, and r is the distance between their centers.
Plugging in the given values, we get:
[tex]$F = (6.674\times10^{-11} \text{ N}\cdot\text{m}^2/\text{kg}^2) \frac{(7.34\times10^{22} \text{ kg})(5.97\times10^{24} \text{ kg})}{(3.88\times10^8 \text{ m})^2}$[/tex]
Simplifying the expression, we get:
[tex]$F \approx 1.99\times10^{20} \text{ N}$[/tex]
Therefore, the gravitational force that the moon produces on the Earth is approximately 1.99x10²⁰ N.
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Barry spent 1/4 of his monthly salary for rent and 1/7 of his monthly salary for his utility bill. If $1411 was left, what was his monthly salary?
Answer: $2,324
Step-by-step explanation:
Let his salary be x.
He spent 1/4 of his salary, or x/4, and 1/7 of his salary, or x/7.
His salary was x. He spent x/4 and x/7, so we subtract those two amounts from his salary.
x - x/4 - x/7 is the amount he still has. He still has $1411. We equate the two and have an equation.
x - x/4 - x/7 = 1411
x/1 - x/4 - x/7 = 1411
We need to combine the three fractions on the left side, so we need to use a common denominator. The least common multiple of 1, 4, and 7 is 28, so 28 is the LCD.
28x/28 - 7x/28- 4x/28= 1411
17x/28= 1411
Multiply both sides by 28.
17x = 39,508
Divide both sides by 17.
x = 2,324
Check:
1/4 of his salary is 2,324/4 = 581
1/7 of his salary is 2,324/7 = 332
Now we subtract 581 and 332 from 2,324
2324 - 581 - 332 = 1411 which is what the problem stated.
Our answer $2,324 is correct.
The result of adding 15 to x and dividing the answer by 4 is the same as taking x from 80. a Express this statement as an algebraic equation. b Hence find the value of x.
Answer:
(15+x)÷4 = 80-x
by criss cross we'll get:
15+x = 4(80-x)
15+x = 320-4x
x+4x=320-15
5x = 305
x = 61
(pls help need answer by 10pm) Given that AC = DC and BC = CE, how do you write a two column proof to prove that angle A equals angle D?
Answer:
look at the explanation
Step-by-step explanation:
okay so here if AC is equals to DC and BC is equals to CE then AB is equals to DE as well hence, angle A would be equals to angle D.
The second reason that prove that angle A is a angle D is that angle A and angle D are alternate angles
I am also in ninth grade so do recheck yourself
the car drives at an average speed of 106 km per hour for 2 hours for 45 minutes at which constant speed must the car drive to travel the same distance in 2 hours 35 minutes
The car must drive at a constant speed of approximately 112.89 km/hr to cover the same distance in 2 hours 35 minutes.
What is the formula for Time?The formula for time is: time = distance / speed
where "distance" is the distance traveled by an object, and "speed" is the rate at which the object is moving.This formula can be used to calculate the time taken by an object to travel a certain distance at a constant speed, or to calculate the speed or distance if the other two variables are known.
What is the formula for Speed?The formula for speed is: speed = distance / time
where "distance" is the distance traveled by an object and "time" is the duration of travel.
This formula can be used to calculate the speed of an object if the distance it has traveled and the time it took to travel that distance are known. It can also be used to calculate the distance traveled by an object if its speed and the time it traveled at that speed are known.
In the given question,
Let's first calculate the distance traveled in 2 hours 45 minutes (2.75 hours) at an average speed of 106 km/hr.
distance = speed × time
distance = 106 × 2.75
distance = 291.5 km
Now, we need to find at which constant speed the car must drive to cover the same distance in 2 hours 35 minutes (2.5833 hours). Let's call this speed "x".
distance = speed × time
291.5 = x × 2.5833
x = 291.5 / 2.5833
x ≈ 112.89 km/hr
Therefore, the car must drive at a constant speed of approximately 112.89 km/hr to cover the same distance in 2 hours 35 minutes.
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The histogram below shows the average number of days per year in 117 Oklahoma cities where the high temperature was greater than 90 degrees Fahrenheit. Which is an accurate comparison? The mean is likely greater than the median because the data is skewed to the right.
The accurate comparison shown by Histogram is that the mean is likely greater than the median because the data is skewed to the right. So, the correct option is A).
The histogram shows a right-skewed distribution, with a tail extending to the right of the peak. This indicates that there are a few cities with very high values that are pulling the mean to the right. In a right-skewed distribution, the mean is always greater than the median. This is because the mean is sensitive to extreme values and the median is not.
Therefore, option A is the accurate comparison. Option B is incorrect because the data is not skewed to the left. Option C is incorrect because the median is always less than the mean in a right-skewed distribution. Option D is also incorrect because the median is always less than the mean in a left-skewed distribution. The correct answer is A).
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_____The given question is incomplete, the complete question is given below:
3 4 5 8 9 10
The histogram below shows the average number of days per year in 117 Oklahoma cities where the high temperature was greater than 90 degrees Fahrenheit.
Which is an accurate comparison?
A The mean is likely greater than the median because the data is skewed to the right.
B The mean is likely greater than the median because the data is skewed to the left.
C The median is likely greater than the mean because the data is skewed to the right.
D The median is likely greater than the mean because the data is skewed to the left.
The windows to a Tudor-style home create many types of quadrilaterals. Use the picture of the window below to answer the following questions.
Please help me I will give literally anything
a. Determine which type of quadrilaterals you see. Name these quadrilaterals using the labeled vertices.
b. What properties of quadrilaterals would you have to know to identify the parallelograms in the picture? Be specific as to each type of parallelogram by using the properties between sides, angles, or diagonals for each.
Answer:
I'd be happy to help!
a. From the picture of the window, we can identify the following quadrilaterals:
Rectangle: ABCD (all angles are right angles and opposite sides are parallel and congruent)
Parallelogram: EFGH (opposite sides are parallel and congruent)
Trapezoid: BCGH (at least one pair of opposite sides are parallel)
b. To identify the parallelograms in the picture, we would need to know the following properties of parallelograms:
Opposite sides are parallel and congruent
Opposite angles are congruent
Diagonals bisect each other
Using these properties, we can identify the following parallelograms in the picture:
Parallelogram EFGH: Opposite sides EF and GH are parallel and congruent, and opposite sides EG and FH are also parallel and congruent. Additionally, angles E and G are congruent, and angles F and H are congruent.
Rectangle ABCD: Opposite sides AB and CD are parallel and congruent, and opposite sides AD and BC are also parallel and congruent. Additionally, angles A and C are congruent, and angles B and D are congruent. The diagonals AC and BD bisect each other, meaning that they intersect at their midpoints.
Step-by-step explanation: