Answer:
N2O(g) + 3 H2O(l) ---------------> 2 NH3(g) + 2 O2(g)
Explanation:
If we look at the reaction stated in the question, we will notice that the option chosen in the answer is the reverse of that reaction.
One thing is clear, if a reaction is possible, then its reverse reaction is equally possible. The equilibrium position may shift towards the forward or reverse reaction based on the conditions of the reaction.
Hence if the reaction, 2NH3(g) + 2O2(g) → N2O(g) + 3H2O(l) is possible, then the reaction, N2O(g) + 3 H2O(l) ---------------> 2 NH3(g) + 2 O2(g) is also possible.
QUICK WILL MARK BRAINLIEST!!
Match each of the unknown ions to its appropriate description.
A− A) A nonmetal that gained one electron
B+ B) A metal that lost one electron
C2− C) A metal that lost two electrons
D2+ D) A nonmetal that gained two electrons
Answer:
c2-c
Explanation:
A mental that lost two electrons just joking I don't k ow but I think it ain't the first o e because of comment sense to the 5th power
Answer:
A and B
Explanation:
metal form ion by lossing elecron
non metal form ion by gaining electron
Question 7
How many molecules of water are in 0.042 Lof pure water (ignoring any temperature
effect)?
Express your answerin e-notation using as many decimal places as necessary
Example: 1,000,001 should be expressed as 1.000001e+6
Notes: Avogadro's constant = 6.02214076e+23 mol 1
Explanation:
Moles of 0.042 L of Pure water = 0.042 / 22.4
[tex]Moles \: of \: 0.042 L \: of \: Pure \: water \: = 1.87 \times {10}^{ - 3} [/tex]
[tex]Molecules \: in \: 0.042 L \: of \: Pure \: water \: = moles \times avogadro \: number[/tex]
Molecules in 0.042 L of Pure Water
= 1.126 * 10^21
BRAINLIeSt TO FIRST Which is a correct method used in a scientific experiment involving acid and base solutions? (2 points) Select one: a. Using a pH test strip to measure the oxygen content of a solution b. Adding an indicator to a solution to test its acidity c. Adjusting the recorded pH measurements to prove the hypothesis d. Measuring the pH of a test strip by dipping it into an indicator
Answer:
B, adding an indicator to a solution to test its acidity
Explanation:
Answer:
B - Adding an indicator to a solution to test its acidity
Explanation:
Took the test
What is the concentration of a dextrose solution prepared by diluting 16 mL of a 1.0 M dextrose solution to 25 mL using a 25 mL volumetric flask?
Answer:
0.64 M
Explanation:
Step 1: Given data
Initial concentration (C₁): 1.0 MInitial volume (V₁): 16 mLFinal concentration (C₂): ?Final volume (V₂): 25 mLStep 2: Calculate the final concentration of the dextrose solution
We want to prepare a diluted solution from a concentrated one. We can find the final concentration using the dilution rule.
C₁ × V₁ = C₂ × V₂
C₂ = C₁ × V₁ / V₂
C₂ = 1.0 M × 16 mL / 25 mL
C₂ = 0.64 M
In preparing quantitative solutions used in titration, one must use freshly boiled deionized water. Explain why.
Answer:
to prevent the chemical from reacting with ions present in water
Explanation:
water contains dissolved ions such as calcium from minerals and soluble rocks
If the components of a solution are in different states, which one is a solvent?
Answer:
The solvent is the substance which typically determines the physical state of the solution (solid, liquid or gas). The solute is the substance which is dissolved by the solvent.
g Consider the reaction when aqueous solutions of potassium hydroxide and ammonium bromide are combined. The net ionic equation for this reaction is:
Net ionic equation is calculated by the eliminating spectator ion. The net ionic products are potassium ion and bromine ion.
Net ionic equation:
It shows the ionic products of the products that has been precipitated by the dissociation of reactant in aquas solution.
Aqueous solutions of potassium hydroxide and ammonium bromide combined to form a precipitate KBr.
The dissociation reaction of
[tex]\bold {KBr(aq) \rightarrow K^+(aq) + Br^-(aq)}[/tex]
Aquas potassium hydroxide dissociates into potassium ion and bromine ion.
Therefore, the net ionic products are potassium ion and bromine ion.
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A sample of 23.2 g of nitrogen gas is reacted with
23.2 g of hydrogen gas to produce ammonia, NH3.
Using the balanced equation below, what is the
maximum amount, in moles, of ammonia that can be
produced?
N2 + 3H2
2NH3
IN
[?] moles NH3
Answer:
1.66 moles.
Explanation:
We'll begin by calculating the number of mole in 23.2 g of nitrogen gas, N2.
This is illustrated below:
Molar mass of N2 = 2x14 = 28 g/mol
Mass of N2 = 23.2 g
Mole of N2 =.?
Mole = mass /Molar mass
Mole of N2 = 23.2/28
Mole of N2 = 0.83 mole
Next, we shall determine the number of mole in 23.2 g of Hydrogen gas, H2.
This is illustrated below:
Molar mass of H2 = 2x1 = 2 g/mol
Mass of H2 = 23.2 g
Mole of H2 =?
Mole = mass /Molar mass
Mole of H2 = 23.2/2
Mole of H2 = 11.6 moles
Next, the balanced equation for the reaction. This is given below:
N2 + 3H2 —> 2NH3
From the balanced equation above,
1 mole of N2 reacted with 3 moles of H2 to produce 2 moles of NH3.
Next, we shall determine the limiting reactant. This can be obtained as follow:
From the balanced equation above,
1 mole of N2 reacted with 3 moles of H2.
Therefore, 0.83 moles will react with = (0.83 x 3) = 2.49 moles of H2.
From the calculations made above, we can see that only 2.49 moles out of 11.6 moles of H2 is required to react completely with 0.83 mole of N2.
Therefore, N2 is the limiting reactant.
Finally, we shall determine the maximum amount of NH3 produced from the reaction.
In this case, we shall use the limiting reactant because it will give the maximum yield of NH3 since all of it is consumed in the reaction.
The limiting reactant is N2 and the maximum amount of NH3 produced can be obtained as follow:
From the balanced equation above,
1 mole of N2 reacted to produce 2 moles of NH3.
Therefore, 0.83 mole of N2 will react to produce = (0.83 x 2) = 1.66 moles of NH3.
Therefore, the maximum amount of NH3 produced from the reaction is 1.66 moles.
Propyne can be converted to
propene by using H2+Lindlar's
catalyst ?
True
or False
Answer:
Propyne can be converted to
propene by using H2+Lindlar's
catalyst ?
True
or False
Propyne can be converted to
propene by using H2+Lindlar's
catalyst ?
True
or False
Propyne can be converted to
propene by using H2+Lindlar's
catalyst ?
True
or False
Propyne can be converted to
propene by using H2+Lindlar's
catalyst ?
True
or False
Propyne can be converted to
propene by using H2+Lindlar's
catalyst ?
True
or False
Propyne can be converted to
propene by using H2+Lindlar's
catalyst ?
True
or False
Propyne can be converted to
propene by using H2+Lindlar's
catalyst ?
True
or False
Propyne can be converted to
propene by using H2+Lindlar's
catalyst ?
True
or False
Explanation:
Propyne can be converted to
propene by using H2+Lindlar's
catalyst ?
True
or False
Propyne can be converted to
propene by using H2+Lindlar's
catalyst ?
True
or False
Propyne can be converted to
propene by using H2+Lindlar's
catalyst ?
True
or False
Propyne can be converted to
propene by using H2+Lindlar's
catalyst ?
True
or False
Propyne can be converted to
propene by using H2+Lindlar's
catalyst ?
True
or False
Propyne can be converted to
propene by using H2+Lindlar's
catalyst ?
True
or False
Propyne can be converted to
propene by using H2+Lindlar's
catalyst ?
True
or False
Propyne can be converted to
propene by using H2+Lindlar's
catalyst ?
True
or False
Propyne can be converted to
propene by using H2+Lindlar's
catalyst ?
True
or False
Propyne can be converted to
propene by using H2+Lindlar's
catalyst ?
True
or False
Propyne can be converted to
propene by using H2+Lindlar's
catalyst ?
True
or False
Propyne can be converted to
propene by using H2+Lindlar's
catalyst ?
True
or False
Propyne can be converted to
propene by using H2+Lindlar's
catalyst ?
True
or False
Propyne can be converted to
propene by using H2+Lindlar's
catalyst ?
True
or False
Propyne can be converted to
propene by using H2+Lindlar's
catalyst ?
True
or False
Propyne can be converted to
propene by using H2+Lindlar's
catalyst ?
True
or False
A scuba diver goes deeper underwater the diver must be aware that the increased pressure affects the human body be increasing the
Answer:
The amount of dissolved gases in the body. Have a good day! =)
Explanation:
is mass an intensive phsical property because it is dependent on the size of the sample
What is the maximum number of moles of nickel carbonate (NiCO3) that can form during the precipitation reaction
Answer:
The correct answer is : 0.025.
Explanation:
The precipitation reaction is as follows in this procedure:
NiSO4.6H20 (aq) + Na2CO3.10H2O (aq)⇒ NiCO3 (s) + Na2SO4 (aq) + 16H2O
So, the number of moles of reactants can be found by
number of moles : mass used/ molar mass
n (NiSO4×6H2O) = (6.57 g)/(262.84 g/mol) = 0.025 mol (for Ni)
n (Na2CO3×10H2O) = (7.15 g)/(286.14 g/mol) = 0.0250 mol (for CO3).
Thus, The maximum number of moles of NiCO3 that can form is 0.025 mol.
The combustion of 0.295 kg of propane produces 712 g of carbon dioxide. What is the percent yield of carbon dioxide? ( Make sure to balance equation) C3H8 (g)+ 029) à co2 g H200 0
a. 124%
b. 41 .4%
c. 80.5%
d. 0.805 %
Answer:
Option C. 80.5%
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
C3H8 + 5O2 —> 3CO2 + 4H2O
Next, we shall determine the mass of C3H8 that reacted and the mass of CO2 produced from the balanced equation.
This is illustrated below:
Molar mass of C3H8 = (3x12) + (8x1) = 36 + 8 = 44 g/mol
Mass of C3H8 from the balanced equation = 1 x 44 = 44 g
Molar mass of CO2 = 12 + (2x16) = 12 + 32 = 44 g/mol
Mass of CO2 from the balanced equation = 3 x 44 = 132 g
From the balanced equation above,
44 g of C3H8 reacted to produce 132 g of CO2.
Next, we shall determine the theoretical yield of CO2.
This can be obtained as shown below:
From the balanced equation above,
44 g of C3H8 reacted to produce 132 g of CO2.
Therefore, 0.295 kg (i.e 295 g) will react to produce = (295 x 132)/44 = 885 g of CO2.
Therefore, the theoretical yield of CO2 is 885 g.
Finally, we shall determine the percentage yield of CO2 as follow:
Actual yield of CO2 = 712 g
Theoretical yield of CO2 = 885 g
Percentage yield of CO2 =..?
Percentage yield = Actual yield /Theoretical yield x 100
Percentage yield of CO2 = 712/885 x 100
Percentage yield = 80.5%
Therefore, the percentage yield of CO2 is 80.5%.
From the following list of observations, choose the one that most clearly supports the conclusion that electrons have wave properties.
A) the emission spectrum of hydrogen
B) the photoelectric effect
C) the scattering of alpha particles by metal foil
D) diffraction
E) cathode "rays"
Answer:
diffraction
Explanation:
Louis de Broglie in 1924 proposed the idea of wave particle duality. In his proposition, matter could exhibit wavelike properties.
Electrons are generally regarded as particles. Electrons may also display wavelike properties such as diffraction patterns. Generally, diffraction is regarded as a property of waves.
Hence, electron diffraction effect owes to the wavelike nature of of electrons when they are passed near matter.
If 20.6 grams of ice at zero degrees Celsius completely change into liquid water at zero degrees Celsius, the enthalpy of phase change will be positive. TRUE FALSE
Answer:
True
Explanation:
According to naming rules, the types of compound that use prefixes in their names are ________.
Answer:
Covalent compounds.
Explanation:
Hello,
In this case, when forming chemical bonds in order to form compounds, we say that if electrons are shared, covalent compounds are to be formed and they usually have subscripts that need prefixes to be named, for instance phosphorous pentachloride (PCl5), dichlorine heptoxide (Cl2O7), carbon tetrachloride (CCl4) and many others.
Regards.
We study science to be able to answer questions about the world around us. Write down at least three questions
that you think might be answered by studying Earth and space science.
Answer:
1) If life exists in other planets
2) What type of living organisms exists on other planets
3) Predominant atoms/mixture/compound that exists on other planets
Explanation:
Earth and space science is the study of the earth, the space and other planets within the universe.
The following questions can be answered by studying earth and space science
1) If life exists in other planets
Over the years, there has been several reports suggesting this but a deep inquiry into this with scientific data can assist in putting the matter to rest.
2) What type of living organisms exists on other planets
If there is/are lives on other planets, what type of life/living organisms exist there. Are they plants? Are they animals? Or do we have a new classification for them?
3) Predominant atom/mixture/compound that exists on other planets
What is the most popular substance in each of these planets? The role of this substance in the survival of the planet or it's inhabitants also needs to be studied
Which particle j j Thomson discovered
Sir Joseph John Thomson OM PRS (18 December 1856 – 30 August 1940) was a British physicist and Nobel Laureate in Physics, credited with the discovery of the electron, the first subatomic particle to be discovered.
when bisecting an angle, one of the steps is to draw an arc centered on a point on a ray of the angle. in particular this angle is to be drawn on the interior of the angle, why must The Arc be drawn in the interior of the angle?
Answer:
the answer is c
Explanation:
Separate this redox reaction into its balanced component half‑reactions. Use the symbol e− for an electron. Cl2+2Li⟶2LiCl
Answer:
Cl₂ ⟶ 2Cl⁻ + 2e⁻ Oxidation
2Li + 2e⁻ ⟶ 2Li⁺ Reduction
Explanation:
The question requests to split the equation below into half equations;
Cl2+2Li⟶2LiCl
In redox chemistry, splitting into half equations simply means highlighting the reduction and oxidation reactions of the reaction.
Before proceeding, we hav to split the ionic compound; LiCl into it's component ions. So we have;
Cl₂ + 2Li ⟶ 2Li⁺Cl⁻
This leaves us with;
Cl₂ ⟶ 2Cl⁻ ............................... i
2Li ⟶ 2Li⁺ .............................. ii
Oxidation reactions can be identified by the increase in oxidation number and decrease in the case of reduction.
in reaction i, there is a decrease in oxidation number from 0 to -1. This is the reduction half equation,
in reaction ii, there is an increase in oxidation number from 0 to +1. This is the oxidation half equation
In terms of electrons, we have to even the charge;
Oxidation = Loss of electrons
Reduction = Gain of electrons
The half equations are given as;
Cl₂ ⟶ 2Cl⁻ + 2e⁻ Oxidation
2Li + 2e⁻ ⟶ 2Li⁺ Reduction
Separation of the redox reaction into its balanced component half-reactions is as follows;
Oxidation half-reaction;
2Li ⟶ Li²+ + 2e-Reduction half-reaction;
Cl2 + 2e- ⟶ 2Cl-By definition;
Oxidation is simply characterized by an increase in oxidation number of a reacting entity.
Reduction is simply characterized by a decrease in oxidation number of a reacting entity.
A reaction in which oxidation and reduction occur simultaneously is termed a Redox reaction as in the given reaction.
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Is it a spontaneous or non-spontaneous change?
During an exothermic chemical reaction, two moles of gaseous reactants are turned into four moles of gaseous products.
Spontaneous Non-spontaneous
During an endothermic chemical reaction, four moles of gaseous reactants are turned into two moles of gaseous products.
Spontaneous Non-spontaneous
A gas expands without absorbing or releasing heat.
Spontaneous Non-spontaneous
what cells form enamel?
Answer:enamel is formed by differentiated dental epithelial cells known as ameloblasts.
Explanation:
how does heat flow in air and ocean currents
Answer:
the transfer of heat energy within the atmosphere, hydrosphere, and the earth's surface and interior occurs as a result of radiation, convection, and conduction. ocean currents play a significant role in transferring this heat toward the poles.
Which statement explains why spontaneous generation is a mistaken idea? A. Living things do not need to reproduce. B. Living things are produced only by living things. C. Not all living things can maintain homeostasis. D.All living things exhibit binomial nomenclature.
Which species have the same electron arrangements?
I. O2-, F-. Ne
II. Li+, Na+, K+
III. S2-, Ar, K+
A. I and II only
B. I and III only
C. II and III only
D. I, II and III
Answer:
the answer will be B.1 and 3 only
Explanation:1. O2- means it has in total 10 electrons as atomic no of oxygen is 8
again F- has also 10 electrons as flourine has atomic no 9
and neon also has 10 electrons
incase of 3rd no S2- has 18 electrons as atomic no of sulfur is 16 as its an ion so it will take 2 more electrons
argon is an inert gas so it has 18 electrons and potassium has 19 electrons eliminating 1 we will 18
# incase of the second option lithium + contains 2 electrons and Na+ contains 10 and K+ contains 18 electrons so all of them are not same
ANS is 1 and 3 only(B.i and iii) only
thank u
Mass and energy are conserved Question 13 options: A) only in chemical changes. B) always in physical changes and sometimes in chemical changes. C) only in physical changes. D) in chemical changes and physical changes.
Answer:
D) in chemical changes and physical changes.
Explanation:
Mass and energy are conserved in chemical changes and physical changes. Therefore, option D is correct.
What is physical change ?Physical modifications are those that affect a chemical substance's form but not its chemical content. Physical changes may normally be used to separate compounds into chemical elements or simpler compounds, but they cannot be used to separate mixtures into their component compounds.
A change in physical attributes accompanies a physical change. Melting, turning into a gas, changing strength or durability, changing crystal structure or texture, and changing shape, size, color, volume, or density are a few examples of physical qualities.
In a physical change, the substance's shape or appearance changes, but the type of matter it contains stays the same. In contrast, when matter undergoes a chemical transformation, at least one new substance with novel features is created.
Thus, option D is correct.
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Gold atoms form small clusters containing a fixed number of atoms. What is the mass (in grams) of oneAu31 cluster
Answer:
[tex]m_{Au_{31}}=6106.07 g[/tex]
Explanation:
Hello,
In this case, since one gold atom has a mass of 196.97 g, for the given gold cluster that has 31 gold atoms, the mass will be:
[tex]m_{Au_{31}}=31*196.97g\\\\m_{Au_{31}}=6106.07 g[/tex]
Whereas we consider the mass of all the 31 gold atoms to compute the overall mass.
Best regards.
Answer:
The mass (in grams) of one Au31cluster = [tex]1.014*10^{-20}grams[/tex]Explanation:
Atomic mass of Au = 197u
So, mass of 1 Au31 cluster (in u)
[tex]= 197 * 31\\\\= 6107u[/tex]
So, mass of 1 Au31 cluster (in gram)
[tex]= 6107 * 1.66*10^{-24}\\\\= 1.014*10^{-20}grams[/tex]
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What areas of the work force can science be applied to?
Select all that apply
Answer:
1. the study of the structure, properties, and interactions of materials and the changes they undergo
2. the study of matter and energy and how they interact
3. the systematic study and analysis of facts
4. a process to test a proposed solution to a problem
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Until the 1600s, people who investigated problems related to our understanding of the natural world were called _____.
Click ca
Explanation:
Hydrogen was collected over water using the approach in the manual. The water temperature was 220C and the measured pressure inside the tube was determined to be 715mmHg. Use Appendix F in your lab manual to determine the pressure of the collected hydrogen gas.
Answer:
Pressure of hydrogen gas = 695.2 mmHg
Explanation:
Given:
Water temperature = 22°C
Pressure inside the tube = 715 mmHg
Find:
Pressure of hydrogen gas
Computation:
Using vapor pressure of water table
Water pressure at 22°C = 19.8 mmHg
Pressure inside the tube = Pressure of hydrogen gas + Water pressure at 22°C
715 = Pressure of hydrogen gas + 19.8
Pressure of hydrogen gas = 715 - 19.8
Pressure of hydrogen gas = 695.2 mmHg
Calculate the solubility at of AgCl in pure water and in a ).0010 M solution. You'll find data in the ALEKS Data tab. Round both of your answers to significant digits.
Answer:
1.34x10⁻⁵ mol / L is the solubility of AgCl
Explanation:
Ksp of AgCl is defined as:
AgCl(s) ⇄ Ag⁺(aq) + Cl⁻(aq)
If 0.010M of AgCl is added, some Ag⁺ and Cl⁻ will be produced until:
Ksp = [Ag⁺] [Cl⁻]
Ksp for AgCl = 1.8x10⁻¹⁰ (Taken from ALEKS Data tab):
Some Ag⁺ and Cl⁻ are produced, you can take this "some" as X:
[Ag⁺] = X
[Cl⁻] = X
Where X is the amount of AgCl that dissolvesin water. X = solubility:
Ksp = 1.8x10⁻¹⁰ = [Ag⁺] [Cl⁻]
1.8x10⁻¹⁰ = [X] [X]
1.8x10⁻¹⁰ = X²
X =
1.34x10⁻⁵ mol / L is the solubility of AgCl