the radius and height of a cone are 8 cm and 15 cm respectively find its curved surface are

Answer:

To know which is better to pay.

Step-by-step explanation:

Good Luck

●✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎❀✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎●

Hi my lil bunny!

❧⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯☙

Answer : [tex]\boxed{(2x + 5 ) (2x - 5)}[/tex]

[tex]4x^2-25[/tex]

Rewrite [tex]4x^2[/tex] as [tex](2^x)^2[/tex].

[tex](2x)^2 - 5^2[/tex]

Rewrite [tex](2x)^2[/tex] as [tex]5^2[/tex].

[tex](2x)^2 - 5^2[/tex]

Since both terms are perfect squares, factor using the difference of squares formula, [tex]a^2 - b^2 = ( a + b ) ( a - b )[/tex] where [tex]a = 2x[/tex] and [tex]b = 5[/tex].

[tex](2x + 5 ) (2x - 5)[/tex]

❧⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯☙

●✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎❀✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎●

Have a great day/night!

❀*May*❀

Answer:

x² - 3x - 18 = 0

Step-by-step explanation:

x/3 - 6/x = 1

x²/3 - 6 = x

x² - 18 = 3x

x² - 3x - 18 = 0

Merhaba ;))

Answer:

4.952

#Başarılar

Answer:

Step-by-step explanation:

[tex]\begin{matrix}\space\space&2&3&8&9&\textbf{1}\\ -&1&8&9&3&\textbf{9}\end{matrix}\\\mathrm{The\:bottom\:number\:is\:larger\:than\:the\:upper\:number.\:\:\\Try\:to\:'borrow'\:a\:digit\:from\:the\:left.}\\\mathrm{Borrow\:}1\mathrm{\:from\:}9\mathrm{.\:\:The\:remainder\:is\:}8\\\begin{matrix}\space\space&\space\space&\space\space&\space\space&\textbf{8}&10\\ \space\space&2&3&8&\textbf{\linethrough{9}}&1\\ -&1&8&9&\textbf{3}&9\end{matrix}[/tex]

[tex]\begin{matrix}\space\space&\space\space&\space\space&\space\space&8&\textbf{11}\\ \space\space&2&3&8&\linethrough{9}&\textbf{\linethrough{1}}\\ -&1&8&9&3&\textbf{9}\end{matrix}[/tex]

[tex]\frac{\begin{matrix}\space\space&\space\space&\space\space&\space\space&\textbf{8}&11\\ \space\space&2&3&8&\textbf{\linethrough{9}}&\linethrough{1}\\ -&1&8&9&\textbf{3}&9\end{matrix}}{\begin{matrix}\space\space&\space\space&\space\space&\space\space&\textbf{5}&2\end{matrix}}[/tex]

[tex]\frac{\begin{matrix}\space\space&\space\space&\textbf{\space\space}&\space\space&8&11\\ \space\space&2&\textbf{3}&8&\linethrough{9}&\linethrough{1}\\ -&1&\textbf{8}&9&3&9\end{matrix}}{\begin{matrix}\space\space&\space\space&\textbf{\space\space}&\space\space&5&2\end{matrix}}[/tex]

[tex]\frac{\begin{matrix}\space\space&\textbf{1}&10&\space\space&8&11\\ \space\space&\textbf{\linethrough{2}}&3&8&\linethrough{9}&\linethrough{1}\\ -&\textbf{1}&8&9&3&9\end{matrix}}{\begin{matrix}\space\space&\textbf{\space\space}&\space\space&\space\space&5&2\end{matrix}}[/tex]

[tex]\frac{\begin{matrix}\space\space&1&\textbf{13}&\space\space&8&11\\ \space\space&\linethrough{2}&\textbf{\linethrough{3}}&8&\linethrough{9}&\linethrough{1}\\ -&1&\textbf{8}&9&3&9\end{matrix}}{\begin{matrix}\space\space&\space\space&\textbf{\space\space}&\space\space&5&2\end{matrix}}[/tex]

[tex]\frac{\begin{matrix}\space\space&1&\textbf{12}&10&8&11\\ \space\space&\linethrough{2}&\textbf{\linethrough{13}}&8&\linethrough{9}&\linethrough{1}\\ -&1&\textbf{8}&9&3&9\end{matrix}}{\begin{matrix}\space\space&\space\space&\textbf{\space\space}&\space\space&5&2\end{matrix}}[/tex]

[tex]\frac{\begin{matrix}\space\space&1&12&\textbf{18}&8&11\\ \space\space&\linethrough{2}&\linethrough{13}&\textbf{\linethrough{8}}&\linethrough{9}&\linethrough{1}\\ -&1&8&\textbf{9}&3&9\end{matrix}}{\begin{matrix}\space\space&\space\space&\space\space&\textbf{\space\space}&5&2\end{matrix}}[/tex]

[tex]\frac{\begin{matrix}\space\space&1&12&\textbf{18}&8&11\\ \space\space&\linethrough{2}&\linethrough{13}&\textbf{\linethrough{8}}&\linethrough{9}&\linethrough{1}\\ -&1&8&\textbf{9}&3&9\end{matrix}}{\begin{matrix}\space\space&\space\space&\space\space&\textbf{9}&5&2\end{matrix}}[/tex]

[tex]\frac{\begin{matrix}\space\space&1&\textbf{12}&18&8&11\\ \space\space&\linethrough{2}&\textbf{\linethrough{13}}&\linethrough{8}&\linethrough{9}&\linethrough{1}\\ -&1&\textbf{8}&9&3&9\end{matrix}}{\begin{matrix}\space\space&\space\space&\textbf{4}&9&5&2\end{matrix}}[/tex]

[tex]\frac{\begin{matrix}\space\space&\textbf{1}&12&18&8&11\\ \space\space&\textbf{\linethrough{2}}&\linethrough{13}&\linethrough{8}&\linethrough{9}&\linethrough{1}\\ -&\textbf{1}&8&9&3&9\end{matrix}}{\begin{matrix}\space\space&\textbf{0}&4&9&5&2\end{matrix}}\\\\=4952[/tex]

Answer:

7 1/5

Step-by-step explanation:

You said that she poured 1 1/5 pouches in each cup. There are 5 cups, so multiply 1 1/5 by 5.

(e.g)

1 1/5+1 1/5= 3 because 1+1=2 & 1/2+1/2=1 so you add them and get 3

Do that twice and you get 6

then you have 1 one more cup left so add 1+6=7 then add the half 7+1 1/2=7 1/2

Your Welcome

Answer:

105 ways

Step-by-step explanation:

Because the order of selection does not matter, we know that we will be using a combination instead of a permutation.

₁₅C₂ = 15! / (2! * 13!)

= 15 * 14 * ... * 2 * 1 / 2 * 1 * 13 * 12 * ... * 2 * 1

= 15 * 14 / 2 * 1 (The 13! cancels out)

= 105

Answer:

105 ways, because the order of selection does not matter, we know that we will be using a combination instead of a permutation.

The inequality expression is :

16 + 8B ≥ 50

Least amount that could be spent = $4500

The total number of rooms required should be atleast 50

Already booked = 16

Number of rooms per block = 8

If the number of blocks = B

Summing together :

Then we have :

16 + 8B ≥ 50

The leat additional amount to be spent:

(50 - 16) / 8

34/8 = 4.25

Least number of blocks, B = 5

Least amount = $900 * 5 = $4500

Learn more : https://brainly.com/question/15974141

Inequalities are used to represent unequal expressions.

Given that:

[tex]Room = 50[/tex] at least

[tex]Reserved = 16[/tex]

[tex]Rate = 8[/tex] per block

A. The inequality

Let the number of blocks be B.

"At least" means, greater than or equal to. So, we have:

[tex]Rate \times B + Reserved \ge 50[/tex]

Substitute known values

[tex]8 \times B + 16 \ge 50[/tex]

[tex]8B + 16 \ge 50[/tex]

So, the inequality that describes the scenario is:

[tex](b).\ 8B + 16 \ge 50[/tex]

B. The least amount

Solve for B in: [tex]8B + 16 \ge 50[/tex]

[tex]8B \ge 50 - 16[/tex]

[tex]8B \ge 34[/tex]

Divide both sides by 8

[tex]B \ge 4.25[/tex]

The number of blocks cannot be a decimal. So, we round 4.25 to the smallest integer greater than 4.25

This gives:

[tex]B \ge 5[/tex]

The least number of block is 5.

Given that:

[tex]Cost = \$900[/tex] per block

The least amount is calculated as follows:

[tex]Least = B \times Cost[/tex]

So, we have:

[tex]Least = 5 \times \$900[/tex]

[tex]Least = \$4500[/tex]

Hence, the least additional money is: $4500

Read more about inequalities at:

https://brainly.com/question/17675534

Answer:

15/28

Step-by-step explanation:

Answer:

y = 3 and x = - 5

Step-by-step explanation:

(a)

[tex]\frac{5-7y}{2+4y}[/tex] = [tex]\frac{-8}{7}[/tex] ( cross- multiply )

- 8(2 + 4y) = 7(5 - 7y) ← distribute parenthesis on both sides

- 16 - 32y = 35 - 49y ( add 49y to both sides )

- 16 + 17y = 35 ( add 16 to both sides )

17y = 51 ( divide both sides by 17 )

y = 3

-----------------------------------------------

(b)

x + 7 - [tex]\frac{8x}{3}[/tex] = [tex]\frac{17}{6}[/tex] - [tex]\frac{5x}{2}[/tex]

Multiply through by 6 to clear the fractions

6x + 42 - 16x = 17 - 15x

42 - 10x = 17 - 15x ( add 15x to both sides )

42 + 5x = 17 ( subtract 42 from both sides )

5x = - 25 ( divide both sides by 5 )

x = - 5

If the line goes downhill as you read from left to right, then the slope is negative.

The slope is positive when you go uphill, reading from left to right.

A slope of 0 means the line is completely horizontal or level

If the line is completely vertical, then the slope is undefined.

Answer:

c. 40°

Step-by-step explanation:

The information given has been illustrated in the figure drawn in the attachment below.

m<BAD = 50° (angle bisector theorem)

m<ADB = 90° (perpendicular bisector)

m<ABD = 180 - (m<BAD + m<ADB) (sum of angles in a triangle)

m<ABD = 180° - (90° + 50°)

= 180° - 140°

= 40°

B = 40°

Answer:

EF = 58 units

Step-by-step explanation:

Given:

DF = 9x - 39

DE = 47

EF = 3x + 10

Find:

EF

Computation:

DF = DE + EF

9x - 39 = 47 + 3x + 10

9x - 3x = 47 + 39 + 10

6x = 96

x = 16

EF = 3x + 10

EF = 3(16) + 10

EF = 58 units

Answer:

12,500 euro = 61,250 cedis

Step-by-step explanation:

1 euro = 4.9 cedis

12500 euro = 4.9 * 12500 cedis

12,500 euro = 61,250 cedis

49,400-20,000=29400

29400/24=1225 average miles per month

Answer:

To make a true equation, check your math to make sure that the values on each side of the equals sign are the same. Ensure that the numerical values on both sides of the "=" sign are the same to make a true equation. For example, 9 = 9 is a true equation. 5 + 4 = 9 is a true equation.You will be able to determine if an equation has one solution (which is when one variable equals one number), or if it has no solution (the two sides of the equation are not equal to each other) or infinite solutions (the two sides of the equation are identical).

1) multicropping

2)soilconservation

3)High carbon farming

4) clay particle

Hope it helps

Answer:

Rate of return = 16%

Step-by-step explanation:

The computation of the rate of the return is shown below:

Data provided in the question

Current value of the investment = $20,880 = C

Originally cost = $18,000 = O

N = Net earnings = C - O

= $20,880 - $18,000

= $2,880

Based on the above information, the rate of return is

[tex]= \frac{N}{O} \\\\ = \frac{\$2,880}{\$18,000}[/tex]

= 16%

Hence, the rate of return is 16%

Answer:

x > 7/3   or x < -11/3

Step-by-step explanation:

|3x + 2| > 9

There are two solutions, one positive and one negative, remembering to flip the inequality when taking the negative solutions

3x+2 > 9         or         3x+2 < -9

Subtract 2

3x+2-2 >9-2   or      3x+2-2 < -9-2

3x >7                           3x>-11

Divide by 3

3x/3 > 7/3                    3x/3 < -11/3

x > 7/3   or x < -11/3

Answer:

5 buses

Step-by-step explanation:

Total number of 6th graders going for the field trip = 184

Step 1

Divide the total number of students by 4

184/4 = 46

We have 46 groups of six graders.

Step 2

There needs to be one chaperone for every four students.

We have 46 groups of six graders

This means there is need for 1 chaperone per group

Hence, we have 46 chaperones

Step 3

Find total number of people going for the field trip

184 students + 46 chaperones

= 230 people

Step 4

If a bus can hold 50 people, how many buses will they need for the trip?

50 people = 1 bus

230 people = ??y

50 × y = 230

y = 230/50

y = 4.6 buses

Hence, 4.6 buses would be needed but since we can't have 0.6(part) of a bus figuratively, as buses come in whole numbers, we approximate to the nearest whole number

= 4.6 ≈ 5

Therefore, they would be needing 5 buses for the trip.

5 buses

Step-by-step explanation:

i got 10 out of 10

Answer: 23

Step-by-step explanation: he had 12 and 24 which makes 36

then he had 13 which means he gave 23 because adding them together gives the original amount

Answer:

X= 7

Step-by-step explanation:

This is the idea that any segment is the same length as itself (in this case, segment VO is the same length as segment VO). Think of a mirror reflecting an identical image of something in front of the mirror.

It might seem redundant to say VO = VO, but it's useful when you want to break up a figure into smaller more manageable pieces to do the proof.

The measure of angle MRS exists equivalent to the measure of the angle MRO or m∠MRS = m∠MRO.

It exists described as the four-sided polygon in geometry containing four edges and four corners.

∠MRS ≅ ∠MRO (given)

From the given figure, we get

∠MRS + ∠MRO = ∠SRO

∠MRS + ∠MRO = 180 (as SRO exists a straight line segment)

Given: ∠MRS exists congruent to ∠MRO

2∠MRS = 180 degree

∠MRS = 90 degree

∠MRO = 180 - 90 = 90 degree

m∠MRS = m∠MRO

Therefore, the measure of angle MRS exists equivalent to the measure of the angle MRO or m∠MRS = m∠MRO.

To learn more about quadrilateral

https://brainly.com/question/27891143

#SPJ2

==========================================

Explanation:

The two smaller circles have a height of h, so one circle has a height of h/2 = 0.5h

The radius of each smaller circle is (0.5h)/2 = 0.25h

Draw an xy axis. Place the bottom left corner of the rectangle at the origin (0,0)

The center of the lower smaller circle is at location (0.25h, 0.25h). Call this point A.

Let B be the center of the larger circle. It has coordinates (x,y). We don't know x, but we know that y = 0.5h since the center must be at the halfway point in terms of the height of this rectangle. So the larger circle has a radius of 0.5h

Draw a line segment connecting A and B. The length of this segment, call it d, is d = 0.5h + 0.25h = 0.75h. Note how I added the two radius values mentioned earlier.

-------------

Summarizing everything so far, we have

A = (0.25h, 0.25h)

B = (x, 0.5h)

d = 0.75h

The distance formula is then used

d = distance from A to B

d = length of segment AB

d = sqrt( (x1-x2)^2 + (y1-y2)^2 )

0.75h = sqrt( (0.25h - x)^2 + (0.25h - 0.5h)^2 )

(0.75h)^2 = (0.25h - x)^2 + (-0.25h)^2

0.5625h^2 = 0.0625h^2 - 0.5hx + x^2 + 0.0625h^2

x^2 - 0.5hx + 0.4375h^2 = 0

From here you use the quadratic formula to get x = 0.9571067811865h approximately (the other solution is ignored as it's negative). See the attached image below if you're curious what the quadratic formula steps would look like.

This x value is the x coordinate of point B, which is the center of the larger circle. This spans the horizontal distance from the left edge of the rectangle to the center of the larger circle. The remaining horizontal distance is h/2 as it is the radius of the larger circle.

Therefore,

w = 0.9571067811865h + 0.5h

w = 1.4571067811865h

-------------

We have turned w into a roughly equivalent expression that has an h in it, allowing us to find the ratio of h to w

h/w = h/(1.4571067811865h) = 1/1.4571067811865 = 0.68629150101527

When rounding to two decimal places, we get roughly 0.69

Answer:

18 values for n are possible.

Step-by-step explanation:

Given the quadratic polynomial:

[tex]$x^2 - mx + n$[/tex]

such that:

Roots are positive prime integers and

[tex]$m < 20$[/tex]

To find:

How many possible values of [tex]n[/tex] are there ?

Solution:

First of all, let us have a look at the sum and product of a quadratic equation.

If the quadratic equation is:

[tex]Ax^{2} +Bx+C[/tex]

and the roots are: [tex]\alpha[/tex] and [tex]\beta[/tex]

Then sum of roots, [tex]\alpha+\beta = -\frac{B}{A}[/tex]

Product of roots, [tex]\alpha \beta = \frac{C}{A}[/tex]

Comparing the given equation with standard equation, we get:

A = 1, B = -m and C = n

Sum of roots,  [tex]\alpha+\beta = -\frac{-m}{1} = m[/tex]

Product of roots, [tex]\alpha \beta = \frac{n}{1} = n[/tex]

We are given that [tex]m<20[/tex]  

[tex]\alpha[/tex] and [tex]\beta[/tex] are positive prime integers such that their sum is less than 20.

Let us have a look at some of the positive prime integers:

2, 3, 5, 7, 11, 13, 17, 23, 29, .....

Now, we have to choose two such prime integers from above list such that their sum is less than 20 and the roots can be repetitive as well.

So, possible combinations and possible value of [tex]n (= \alpha \times \beta)[/tex] are:

[tex]1.\ 2, 2\Rightarrow n = 2\times 2 = 4\\2.\ 2, 3 \Rightarrow n = 6\\3.\ 2, 5 \Rightarrow n = 10\\4.\ 2, 7\Rightarrow n = 14\\5.\ 2, 11 \Rightarrow n = 22\\6.\ 2, 13 \Rightarrow n = 26\\7.\ 2, 17 \Rightarrow n = 34\\8.\ 3, 3\Rightarrow n = 3\times 3 = 9\\9.\ 3, 5 \Rightarrow n = 15\\10.\ 3, 7 \Rightarrow n = 21\\[/tex]

[tex]11.\ 3, 11\Rightarrow n = 33\\12.\ 3, 13 \Rightarrow n = 39\\13.\ 5, 5 \Rightarrow n = 25\\14.\ 5, 7 \Rightarrow n = 35\\15.\ 5, 11 \Rightarrow n = 55\\16.\ 5, 13 \Rightarrow n = 65\\17.\ 7, 7 \Rightarrow n = 49\\18.\ 7, 11 \Rightarrow n = 77[/tex]

So,as shown above 18 values for n are possible.

Answer:

2+2+2=6

4+52-32+2=26

finally add 26+6=32

hi

40 students

30 read chemistry

20 read physics

so logical deduction is that 10 read chemistry and physics.  

So only 20 read only chemistry and only 10 read only physics.  

So read only chemistry is  20/40 = 1/2

Answer as a fraction =  1/2

Answer in decimal form = 0.5

Answer in percent form = 50%

All three represent the same idea, but in a different form.

=======================================================

Work Shown:

30 read chem, 20 read physics

30+20 = 50 read either one, but this is over 40, so 50-40 = 10 students must read both

From that,

30-10 = 20 read chem only

20-10 = 10 read physics only

This makes the venn diagram you see below

Divide the number of people who read chemistry only (20) over the total number of people (40). This gives 20/40 = 2/4 = 1/2

Then you would use your calculator to find 1/2 = 0.5 = 50%

hi my litler friend

[tex](x-5)^2=3\\(x-5)=+-\sqrt{3} \\\\x-5=\sqrt{3} \\x=5+\sqrt{3} \\\\x-5=-\sqrt{3} \\x=5-\sqrt{3} \\\\\\S=(5-\sqrt{3},5+\sqrt{3})\\[/tex]

if in doubt, let me know. I really like to help.

Exact solutions: [tex]x = 5+\sqrt{3} \ \text{ or } \ x = 5-\sqrt{3}[/tex]

Approximate solutions: [tex]x \approx 6.732051 \ \text{ or } \ x \approx 3.267949[/tex]

==================================================

Work Shown:

Apply the square root to both sides, then add 5 to both sides

Don't forget about the plus/minus so you can get two solutions.

[tex](x-5)^2 = 3\\\\\sqrt{(x-5)^2} = \sqrt{3}\\\\|x-5| = \sqrt{3}\\\\x-5 = \pm\sqrt{3}\\\\x-5+5 = \pm\sqrt{3}+5\\\\x = 5\pm\sqrt{3}\\\\x = 5+\sqrt{3} \ \text{ or } \ x = 5-\sqrt{3}\\\\x \approx 6.732051 \ \text{ or } \ x \approx 3.267949\\\\[/tex]

Use a calculator for the last step.

Answer:

B. ∠ABC

Step-by-step explanation:

When naming an angle using three points, the points should be given in order, with the vertex of the angle in the middle. B is the only option that has the letters in the right order.

∠CBA would also be a valid name for the angle, but that's not one of the options.

The diagram below shows what the problem is describing.

Rays BA and BC will form an angle named B. <ABC.

Therefore, the letter of the vertex will be in the middle of the three letters used in naming the angle.

The name of the angle formed by BA and BC is B. <ABC.

Learn more about naming of angles here:

https://brainly.com/question/19350659

Answer:

-32

Step-by-step explanation:

Negative plus negative = Negative

Just add those 2 together,

(-)18 + (-) 14

Which is -32

(-) 32 = -32