The projected worth (in millions of dollars) of a large company is modeled by the equation w = 221(1.06) t. The variable t represents the number of years since 2000. What is the projected annual percent of growth, and what should the company be worth in 2009?

Answer: The answer is 3.60 dollars.

Step-by-step explanation:

1 bottle = 10 cents

12 bottles = 120 cents

100 cents = 1 dollar

1 cent = 1/100

120 = 1/100 * 120 = 1.2 dollars

now

1 aluminium can = 5 cents

48 cans = 5*48 = 240 cents

240 cents = 1/100 * 240 = 2.4 dollars

so total = (1.2+2.4) dollars

= 3.6 dollars

Answer:

Rs. 2400

Step-by-step explanation:

.25(x -.1x) = 540

(x -.1x) = 2160

(.9x) = 2160

x = 2400

Step-by-step explanation:

hope this helps you 830.77

Hello,

In all reply x²'s coefficient is 1.

The polynom will be (x+i)(x-5)= x²+ix -5x-5i

Answer  C

Answer:

The dependent variable is the time taken to run 100 metres

Step-by-step explanation:

A dependent variable is simply one that is being measured or sometimes tested in an experiment.

Now, in this case, what is being determined is the time each group of participants will take to run a 100-meter race.

Thus, the dependent variable is the time each group of participants will take to run a 100-meter race.

Answer:19 You can use addition 12+7=19 19-7=12

Answer:

Tan A = [tex]\frac{21}{35}[/tex] = [tex]\frac{3}{5}[/tex] = .6

Step-by-step explanation:

SOH CAH TOA

Sin Ф = [tex]\frac{O}{H}[/tex]

Cos Ф = [tex]\frac{A}{H}[/tex]

Tan Ф = [tex]\frac{O}{A}[/tex]

Answer:

radius = 5

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

Here r² = 25 ( take the square root of both sides )

r = [tex]\sqrt{25}[/tex] = 5

ᴀɴsᴡᴇʀ:

1.Example, x²-25 can be factored as (x+5)(x-5).

2.This method is based on the pattern (a+b)(a-b)=a²-b², which can be verified by expanding the parentheses in (a+b)(a-b).

3.When an expression can be viewed as the difference of two perfect squares, i.e. a²-b², then we can factor it as (a+b)(a-b). For example, x²-25 can be factored as (x+5)(x-5).

ʜᴏᴘᴇ ɪᴛ ʜᴇʟᴘs!

☞︎︎︎ᴄᴀʀʀʏ ᴏɴ ʟᴇᴀʀɴɪɴɢ☜︎︎︎

Answer: ∠1 = 48°, ∠2 = 42°

Step-by-step explanation:

∠M = 90° = ∠1 + (3x)° = (2x + 20)° + (3x)°

2x + 20 + 3x = 90

2x + 3x = 90 - 20

5x = 70

x = 14

∠1 = 2x + 20 = 2(14) + 20 = 28 + 20 = 48°

∠2 = 3x = 3(14) = 42°

(I hope this is right :\)

c ans

...................

Hello,

Using Thalès 's theorem:

Let's h the height of the monument.

[tex]\dfrac{1}{h} =\dfrac{4.5}{78} \\\\h=\dfrac{78}{4.5} =\dfrac{156}{9} \approx{17.3\ (ft)}[/tex]

If you don't know what is the Thalès's theorem,

imagine that the similar triangles.

Answer:

[tex]180ft^{3}[/tex]

Step-by-step explanation:

Volume of a cone:

[tex]V=\pi r^{2} \frac{h}{3}[/tex]

Take [tex]\pi[/tex] as 3, as mentioned in the question

'r' is 'radius' ⇒ {diameter is given so divide by 2: 12/2 = 6}

'h' is 'height'

[tex]V=(3)(6)^{2} (\frac{5}{3} )[/tex]

[tex]V=(3)(36)(\frac{5}{3} )[/tex]

[tex]V=108(\frac{5}{3} )[/tex]

{multiply 108 with 5 and then divide the answer by 3}

[tex]V=108[/tex] × [tex]5[/tex]

[tex]V=540[/tex]

[tex]V=540/3[/tex]

[tex]V=180ft^{3}[/tex]

Answer: The cost for the two pairs of shoes is $13.33

Step-by-step explanation:

Since we have given that

Cost of pair of flip flops = $3.46

Cost of pair of slip on shoes = $9.87

We need to find the cost of two pairs of shoes.

Cost of two pairs of shoes = Cost of pair of flip flops + Cost of pair of slip on shoes

[tex]cost=3.46+9.87=13.33[/tex]

the cost for the two pairs of shoes is $13.33.

Answer:

I believe this would be the answer?

Step-by-step explanation:

{2, 3, 4, 6, 8, 9, 10, 12}

Answer:

[tex]x=7\text{ and } m\angle KLM = 34^\circ[/tex]

Step-by-step explanation:

We are given ethat KM and JN are parallel.

And we want to find the value of x.

Notice that ∠JKM and ∠LKM form a linear pair. Linear pairs total 180°. Therefore:

[tex]m\angle JKM + m\angle LKM = 180[/tex]

We know that ∠JKM measures (14x + 8). Substitute:

[tex](14x+8)+m\angle LKM =180[/tex]

Solve for ∠LKM:

[tex]m\angle LKM = 172-14x[/tex]

Next, since KM and JN are parallel, by the Corresponding Angles Theorem:

[tex]\angle JNM \cong \angle KML[/tex]

Since we know that ∠JNM measure (10x + 2), we can conclude that:

[tex]m\angle KML = 10x+2[/tex]

Next, recall that the three interior angles of a triangle must total 180°. Therefore:

[tex]m\angle KLM + m\angle LKM + m\angle KML = 180[/tex]

Substitute:

[tex](5x-1)+(172-14x)+(10x+2)=180[/tex]

Solve for x. Rewrite:

[tex](5x-14x+10x)+(-1+172+2)=180[/tex]

Combine like terms:

[tex](1x)+(173)=180[/tex]

Therefore:

[tex]x=7[/tex]

To find ∠KLM, substitute in 7 for x and evaluate. So:

[tex]m\angle KLM = 5(7) - 1 =34^\circ[/tex]

Answer:

112

Step-by-step explanation:

add both bases the multiply by the height

Answer:

112

13 + 15

= 28 ÷ 2

= 14 × 8

= 112

2 fewer than the quotient of a and 5

(x/5)-2

Hello,

here is the picture:

Slope (PR):

[tex]m=\dfrac{2-4}{6-2} =-\dfrac{1}{2} \\Slope\ of\ the\ perpendicular: -\dfrac{1}{\dfrac{-1}{2} } =2\\\\perpendicular\ is\ passing\ trought\ M(4,3): y-3=2(x-4)\\y=2x-5\\If\ y=0\ then\ x= \dfrac{5}{2} \\Q=( \dfrac{5}{2},0)\\[/tex]

Answer:

-1

Step-by-step explanation:

Replace x with -2

f(-2)=-(-2)^2+3

Solve.

f(-2)=-4+3

      =-1

I hope this helps!

Answer:

-1

Step-by-step explanation:

When you have f(x) =- x^2 +3 and want to find f(-2), it is basically asking you to calculate the function where x is -2. So if you plug in -2 for x you get:

-(-2)^2 + 3= f(-2)

-4+3= f(-2)

-1=f(-2)

Answer:

please mark me a brainliest

[tex] \frac{2.5 + 1.3 + 2.2 + x}{4} = 1.8[/tex]

[tex] \frac{6 + x}{4} = 1.8[/tex]

6 + X = 1.8 * 4

6 + X = 7.2

X = 7.2 - 6

X = 1.2

So therefore the value of X is 1.2

Step-by-step explanation:

Have a good day

Have a good day And I hope this will help

Answer:

1

Step-by-step explanation:

February is the only month that has 28 days

Answer:

[tex]12 \: months \: have \: 28 \: days \\ thank \: you[/tex]

Answer:

5

Step-by-step explanation:

The given is 3-4-5 special triangle so the missing side represented with x is 5

Answer:

a) 9

b)

[tex]1 \frac{1}{3} [/tex]

c) 15

Step-by-step explanation:

The first step is to cancel out the fraction's denominator if possible.

a)

[tex]15 \times \frac{3}{5} [/tex]

We can cancel the 5 out since 15 divided by 5 is 3. The answer that comes out is

[tex]3 \times \frac{3}{1} [/tex]

Since 3/1 is 3, we can now simplify the values:

[tex]3 \times 3 = 9[/tex]

b)

[tex]4 \times \frac{1}{3} [/tex]

4 is indivisible by three and gives a non-whole value. This is not what we need here.

Instead we should do the division rule and find the remainder.

In this case, 4 divided by 3 gives 1 with a remainder of 1.

[tex]4 \times \frac{1}{3} = \frac{4}{3} [/tex]

After we simplify the non-mixed fraction, we have to change it into a mixed fraction, which consists of a whole number and a fraction. We can split it into the following:

[tex] \frac{4}{3} = 1r1[/tex]

The r1 is just the remainder of the fraction. Since we cannot remove 1 from the remainder, we add it back into the fraction's denominator of 3. This gives:

[tex] \frac{4}{3} = 1 + \frac{1}{3} = 1 \frac{1}{3} [/tex]

c)

[tex] \frac{5}{2} \times 6[/tex]

For this part, we can cancel out 2 since 6 is divisible by 2. This gives:

[tex] \frac{5}{1} \times 3[/tex]

Since 5/1 is 5,

we can now solve part c:

[tex]5 \times 3 = 15[/tex]

Answer:

34 is greater than or equal to z which is greater than or equal to 30

Answer:

Yes

General Formulas and Concepts:

Algebra I

Step-by-step explanation:

When we plot (-2, -4) onto the graph, we can envision that the point is within the shaded region of the graphed line.

∴ (-2, -4) would be a solution.

Answer:

See Explanation

Step-by-step explanation:

If a Function is differentiable at a point c, it is also continuous at that point.

but be careful, to not assume that the inverse statement is true if a fuction is Continuous it doest not mean it is necessarily differentiable, it must satisfy the two conditions.

                                          And

If function is differentiable at a point x, then function must also be continuous at x. but The converse does not hold, a continuous function need not be differentiable.