The position x of a bowling ball rolling on a smooth floor as a function of time t is given by: x(t)=v0t+x0x(t)=v0t+x0, where v0=2.5m/sv0=2.5m/s and x0=−5.0mx0=−5.0m. The polynomial relationship between position and time for the bowling ball is _______________. O cubic O inverse exponential O quadratic linear

We choose the point midway between the two plates as the reference point for the electric potential energy to quantify energy stored.

The electric potential energy (PE) is a measure of the energy stored in an electric field. It is defined as the work done by an external agent to move a charged particle from one point in the electric field to another.

In the case of an electron at rest at a point midway between two plates, we can choose this location as the reference point for the electric potential energy. This means that the electric potential energy at this point is zero, and all other points in the electric field can be defined relative to this reference point.

The i and f subscripts indicate quantities evaluated in the initial and final states, respectively. So, (PE)_i indicates the electric potential energy of the electron in the initial state, when it is at rest at the reference point, and (PE)_f indicates the electric potential energy of the electron in the final state, after it has been moved by an external agent.

The electric potential energy can be calculated using the formula PE = qV, where q is the charge of the electron and V is the electric potential difference between the initial and final states. In this case, the electric potential difference between the two plates can be calculated using the equation V = Ed, where E is the electric field strength and d is the distance between the plates.

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The density of solvent is  2448 kg/m³.

Per unit area across which a force is spread, pressure is the force delivered perpendicularly to an object's surface. In comparison to the surrounding pressure, gauge pressure is the pressure. Pressure is expressed using a variety of units.

Pressure is expressed using a variety of units. Some of them come from dividing a force unit by an area unit; for example, the SI pressure unit, the pascal, is derived from this (Pa).

According to the question:

ρ × 10 × 12.5 = 306 × 10³

ρ = 2448 kg/m³

Hence, the density of solvent is  2448 kg/m³.

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The object is moving at a velocity of 5 m/s when it is at x = 8 m.

The velocity of an object with constant acceleration can be found using the equation:

v = v0 + at

where v0 is the initial velocity, a is the acceleration, and t is the time elapsed.

Given that the object has an acceleration of a = 4 m/s²

initial velocity of v0 = 1 m/s,

we can calculate the velocity at x = 8 m by solving for t and then substituting  into the velocity equation:

x = x0 + v0t + 0.5at^2

x = 7 m + 1 m/s * t + 0.5 * 4 m/s² * t^2

x = 8 m

Expanding and solving for t, we find:

t = (8 - 7 - 1 * t) / (0.5 * 4 * t^2)

t = 1 s

So the object has been moving for 1 second, and its velocity at x = 8 m is given by:

v = v0 + at

v = 1 m/s + 4 m/s² * 1 s

v = 5 m/s

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Sure, here's an example implementation of the ewma function in Python:

import numpy as np

def ewma(data, alpha):

   """

   Calculate the exponential weighted moving average of a given data array.

   Args:

   - data: a 1D numpy array containing the data points to be averaged.

   - alpha: a float between 0 and 1 representing the degree of weighting decrease.

            A higher value of alpha gives more weight to recent data points.

   Returns:

   - ewma: a 1D numpy array containing the exponentially weighted moving average of the input data.

   """

   # Initialize variables

   ewma = np.zeros_like(data)

   ewma[0] = data[0]

   for i in range(1, len(data)):

       ewma[i] = alpha * data[i] + (1 - alpha) * ewma[i-1]

   return ewma

To use this function, you can call it with your data array and the desired alpha value, like so:

data = np.array([1, 2, 3, 4, 5])

alpha = 0.5

result = ewma(data, alpha)

print(result)

This will output the exponential weighted moving average of the data array with the specified alpha value. You can change the value of alpha and the input data to generate different results.

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a. The distance separating two dust particles if each has a charge of +e and the Coulomb force is 2.5 × 10⁻³ m

b. The mass of one of the dust particles if this Coulomb force would accelerate it is  2.22 x 10⁻²³ kg.

What is force?

Force is a physical quantity that represents the interaction between two objects that cause changes in motion of the objects. Force can be defined as the push or pull effect on an object. It is a vector quantity, which means it has both magnitude and direction. The unit of force in the International System of Units (SI) is the Newton (N), which is defined as the force required to accelerate a mass of one kilogram at a rate of one meter per second squared.

a) The force between two charged particles can be calculated using Coulomb's law, which states that the force between two point charges is proportional to the product of the charges and inversely proportional to the square of the distance between them:

F = k × q1 × q2 / r²

where k is the Coulomb constant (8.99 x 10⁹ N m²/C²), q1 and q2 are the charges of the two particles, and r is the distance between them.

Given that the force between the two particles is 1.00 x 10⁻¹⁴ N and each particle has a charge of +e, we can rearrange the equation to solve for r:

r = [tex]$ \sqrt{\frac{k \times q_1 \times q_2 }{ F} }[/tex]

= [tex]$ \mathrm{ \sqrt{\frac{8.99 \times 10^2 N m^2/C^2 \times 2e^2 }{ 1.00 \times 10^{-14} N} } }[/tex]

= 2.5 × 10⁻³ m

b) To calculate the mass of one of the dust particles, we can use Newton's second law, which states that the net force acting on an object is equal to its mass times its acceleration:

F = m × a

where F is the force, m is the mass, and a is the acceleration. Given that the acceleration of the particle is 4.50 x 10⁸ m/s², we can rearrange the equation to solve for m:

m = F / a

[tex]$ \mathrm{= \frac{1.00 \times 10^{-14} N}{ 4.50 \times 10^8 m/s^2} }[/tex]

= 2.22 x 10⁻²³ kg

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(a) The x component of the electric force exerted by A on C is 2.29 x 10⁻⁷ N.

(b) The y component of the force exerted by A on C is  1.72 x 10⁻⁷ N.

(c) The magnitude of the force exerted by B on C is -3.96 x 10⁻⁷ N.

(d) The x component of the force exerted by B on C is -3.17 x 10⁻⁷ N.

(e) The y component of the force exerted by B on C is -2.38 x 10⁻⁷ N.

(f) The sum of two x components from parts (a) and (d) to obtain the resultant x component of the electric force acting on C is -0.88 x 10⁻⁷ N.

(g) The y component of the resultant force vector acting on C is -0.66 x 10⁻⁷ N.

(h) The magnitude of the net electric force on particle C is 1.01 x 10⁻⁷ N.

The electric force exerted by a particle on another particle can be calculated using Coulomb's Law, which states that the force between two point charges is given by:

F = k * q1 * q2 / r²

where k is the Coulomb constant (8.99 x 10⁹ Nm²/C²), q1 and q2 are the magnitudes of the charges, and r is the distance between the two particles.

(a) The x component of the electric force exerted by particle A on C can be found by considering the x direction only. The distance between A and C can be found using the Pythagorean theorem:

r = sqrt((4.00 m)² + (3.00 m)²) = 5.00 m

The electric force in the x direction can then be found as follows:

F_x = k * q1 * q3 / r² * cos(θ)

where q1 is the charge of particle A (3.24 x 10⁻⁴ C), q3 is the charge of particle C (1.01 x 10⁻⁴ C), and θ is the angle between the line connecting the two particles and the x-axis. Since the line is in the first quadrant, cos(θ) is positive:

θ = arctan(3.00 m / 4.00 m) = 0.93 radians

cos(θ) = cos(0.93) = 0.80

F_x = k * q1 * q3 / r² * cos(θ) = (8.99 x 10⁹ Nm²/C²) * (3.24 x 10⁻⁴ C) * (1.01 x 10⁻⁴ C) / (5.00 m)² * 0.80 = 2.29 x 10⁻⁷ N

(b) The y component of the force exerted by A on C can be found in a similar manner:

F_y = k * q1 * q3 / r² * sin(θ)

sin(θ) = sin(0.93) = 0.60

F_y = k * q1 * q3 / r² * sin(θ) = (8.99 x 10⁹ Nm²/C²) * (3.24 x 10⁻⁴ C) * (1.01 x 10⁻⁴ C) / (5.00 m)² * 0.60 = 1.72 x 10⁻⁷ N

(c) The magnitude of the force exerted by B on C can be found using Coulomb's Law:

F = k * q2 * q3 / r²

where q2 is the charge of particle B (-5.64 x 10⁻⁴ C) and r is the distance between the two particles:

r = sqrt((4.00 m)² + (3.00 m)²) = 5.00 m

F = k * q2 * q3 / r² = (8.99 x 10⁹ Nm²/C²) * (-5.64 x 10⁻⁴ C) * (1.01 x 10⁻⁴ C) / (5.00 m)²= -3.96 x 10⁻⁷ N

(d) The x component of the force exerted by B on C can be found by considering the x direction only:

F_x = k * q2 * q3 / r² * cos(θ)

where q2 is the charge of particle B (-5.64 x 10⁻⁴ C), q3 is the charge of particle C (1.01 x 10⁻⁴ C), and θ is the angle between the line connecting the two particles and the x-axis. Since the line is in the first quadrant, cos(θ) is positive:

θ = arctan(3.00 m / 4.00 m) = 0.93 radians

cos(θ) = cos(0.93) = 0.80

F_x = k * q2 * q3 / r² * cos(θ) = (8.99 x 10⁹ Nm²/C²) * (-5.64 x 10⁻⁴ C) * (1.01 x 10⁻⁴C) / (5.00 m)² * 0.80 = -3.17 x 10⁻⁷ N

(e) The y component of the force exerted by B on C can be found in a similar manner:

F_y = k * q2 * q3 / r² * sin(θ)

sin(θ) = sin(0.93) = 0.60

F_y = k * q2 * q3 / r² * sin(θ) = (8.99 x 10⁹ Nm²/C²) * (-5.64 x 10⁻⁴ C) * (1.01 x 10⁻⁴ C) / (5.00 m)² * 0.60 = -2.38 x 10⁻⁷ N

(f) The x component of the resultant force can be found by summing the x components from parts (a) and (d):

F_x_resultant = F_x(A on C) + F_x(B on C) = 2.29 x 10⁻⁷ N + (-3.17 x 10⁻⁷ N) = -0.88 x 10⁻⁷ N

(g) The y component of the resultant force can be found by summing the y components from parts (b) and (e):

F_y_resultant = F_y(A on C) + F_y(B on C) = 1.72 x 10⁻⁷ N + (-2.38 x 10⁻⁷ N) = -0.66 x 10⁻⁷ N

(h) The magnitude of the resultant force can be found using the Pythagorean theorem:

F_resultant = sqrt(F_x_resultant² + F_y_resultant²) = sqrt((-0.88 x 10⁻⁷ N)² + (-0.66 x 10⁻⁷ N)²) = 1.01 x 10⁻⁷ N

So the magnitude of the net electric force on particle C is 1.01 x 10⁻⁷ N.

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When you increase your vehicle's speed, you must also increase your following interval to compensate for limitations.

What is speed?

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A car traveling eastwards gains 1 m/s eastwards every second. The car is E: accelerating and C: changing its velocity.

A car traveling eastwards that gains 1 m/s of velocity every second is considered to be accelerating. This is because acceleration is defined as the rate of change of velocity. In this case, the velocity of the car is changing in the eastward direction, indicating that it is accelerating eastwards. It is also important to note that acceleration can be either positive or negative, depending on the direction of the velocity change.

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When a firm has transcended a production or selling orientation, and attempts to discover and satisfy its customer's needs and wants, the firm is customer-oriented.

A customer-oriented firm places the needs and wants of its customers at the forefront of all its decision-making processes. This approach goes beyond merely producing and selling products, as it takes into account the entire customer experience.

The focus is not just on meeting customer needs, but on anticipating and exceeding them. This involves collecting and analyzing customer data, regularly gathering feedback, and continuously improving the customer experience.

A customer-oriented culture also permeates all levels of the organization, from top management to front-line employees. The result is increased customer loyalty, higher sales and profits, and a stronger brand reputation. Ultimately, a customer-oriented approach helps a firm to establish a long-term, sustainable competitive advantage.

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Answer: The dielectric constant is the ratio of the capacitance formed by two plates with material between them to the capacitance of the same plates with air as the dielectric. For low megahertz, frequencies are less than are equal to 1,000 MHz.

Explanation:

Answer: approximately 18.854 Joules of work is required to put the bag of sugar on the shelf. where Force is the weight of the bag of sugar and Distance is the vertical distance lifted.

Explanation:

The wavelength of an NMR signal at 250 MHz is 1.2m and its energy is 1.67 x 10⁻²⁵ J.

Nuclear Magnetic Resonance (NMR) spectroscopy is a widely used technique in physics and chemistry for determining the chemical and physical properties of substances. The frequency of an NMR signal is related to the magnetic field strength and the magnetic properties of the nuclei being studied.

The wavelength of an NMR signal can be calculated using the equation:

λ = c/v

where c is the speed of light (3 x 10⁸ m/s) and v is the frequency of the signal (250 MHz).

λ = c / v

λ = 3 x 10⁸ m/s / (250 x 10⁶ Hz)

λ = 1.2 m

The energy of an NMR signal can be calculated using the equation:

E = hv

where h is Planck's constant (6.63 x 10⁻³⁴ J s) and v is the frequency of the signal.

E = h × v  

E = 6.63 x 10⁻³⁴ J s × (250 x 10⁶ Hz)

E = 1.67 x 10⁻²⁵ J

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The circuit of an electric bell consists of an electromagnet, a switch, and a source of power. When the switch is activated, the electromagnet is energized, creating a magnetic field. This magnetic field attracts a metal hammer, which strikes a bell and produces a ringing sound. When the switch is released, the circuit is broken, de-energizing the electromagnet and allowing the hammer to return to its original position. This process repeats each time the switch is activated.

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The vertical force induced in the tower by the cables by:

e) all of the above. All of the methods listed (a, b, c, and d) can be used to find the vertical force induced in the tower by the cables, and each method provides a different approach to finding the solution. The choice of method will depend on the complexity of the problem and the level of mathematical sophistication required for the solution.

The various methods listed (a, b, c, and d) all involve mathematical and physical principles that can be used to find the vertical force induced in the tower by the cables.

a) Product to pairs of vectors and projecting a resultant force from the tower: This method involves using vector dot products or cross products to find the projection of one vector onto another, which can then be used to find the magnitude and direction of the vertical force.

b) Cartesian vector analysis to the coplanar forces: This method involves finding the components of each cable force in a two-dimensional coordinate system, adding the components to find the resultant force, and then finding the direction cosine to determine the direction of the resultant force.

c) Applying Newton's second law of motion and the Pythagorean Theorem: This method involves using Newton's second law of motion (F = ma) to find the net force acting on the tower and then using the Pythagorean Theorem to find the magnitude and direction of the vertical force.

d) Force resolution: This method involves breaking down the cables' forces into their individual components, finding the net force in each direction, and then using vector addition to find the magnitude and direction of the vertical force.

Each method has its own advantages and disadvantages, and the choice of method will depend on the complexity of the problem, the level of mathematical sophistication required for the solution, and the desired level of accuracy.

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Answer: 0.497 J

Explanation:

Spring energy
Spring energy is stored in a compressible or stretchable object like a spring or rubber band.

The work done on a spring in changing its original length is converted to its elastic potential energy or spring energy.

Given -

The spring constant is k = 20N/m,

The initial stretch is x1 = 0.16m,

The additional stretch is x2 = 0.063m,

W = 0.5k (x1 + x2)^2 - 0.5k x1^2
W = 0.5 (20 N/m) (0.16m + 0.063m)^2
W = 0.497 J

Answer:

Explanation:

The work done by a force on an object is equal to the product of the magnitude of the force, the distance moved by the object in the direction of the force, and the cosine of the angle between the force and the direction of motion.

In this case, the worker pushes the crate horizontally, so the force and the direction of motion are in the same direction. Therefore, the angle between them is 0 degrees, and the cosine of the angle is 1.

The work done by the worker on the crate is then:

work = force x distance x cos(angle)

= 235 N x 3.3 m x cos(0)

= 773.5 J

So the work done by the worker is 773.5 Joules (J).

Hello,

Answer:

The work done by a force on an object is given by:

Work = Force x Distance x cos(theta)

where Force is the magnitude of the force applied, Distance is the displacement of the object, and theta is the angle between the force and displacement vectors. Since the worker is pushing horizontally on the crate, the angle between the force and displacement vectors is zero degrees, and cos(0) = 1.

So, the work done by the worker is:

Work = Force x Distance x cos(theta)

Work = 235 N x 3.3 m x cos(0)

Work = 773.5 J

Therefore, the work done by the worker on the crate is 773.5 J.

Good luck !

Since the total energy of the body is constant, we can write Epot + Ekin is 725 J

We can express the potential energy of the body as a function of its height, h, relative to some reference point:

Epot = m * g * h

where m is the mass of the body, g is the acceleration due to gravity, and h is the height of the body.

We can express the kinetic energy of the body as a function of its velocity, v:

Ekin = 0.5 * m * v^2

Since the total energy is constant, we can substitute Epot + Ekin = 725 J into the expressions for Epot and Ekin:

m * g * h + 0.5 * m * v^2 = 725 J

For a moment during the falling, both the potential energy and the kinetic energy can have any non-negative value, as long as their sum is equal to 725 J. So, there are infinitely many possible values for the potential energy and the kinetic energy during the falling. For example, one possible set of values could be:

Epot = 500 J

Ekin = 225 J

Another possible set of values could be:

Epot = 700 J

Ekin = 25 J

And so on.

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The turning effect is 5 N/m.

We have to note that the torque is the product of the force and the distance that it has turned. The torque can be used to describe the kind of force that can be able to provide a turning effect.

In this case for the question that we have here we know that;

Force =  25 Newton

Distance = 0.20 m

Torque = 0.20 m * 25 Newton

= 5 N/m

This is the force that would cause the pedal to be turned so that we can have the movement of the bicycle as shown above.

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A point charge placed in an electric field does experience a force due to the interaction of the electric field with the charge. At locations where the electric field is zero, the force on the point charge would be zero as well, as it would not experience any interaction with the field.

If the electric field strength is 1/(1.6 times 10^-19) N/C, the force on the point charge would be equal to the product of the electric field strength and the magnitude of the charge.

The direction of the force would depend on the sign of the charge - if it is positive, it would experience a force in the direction of the electric field, and if it is negative, it would experience a force in the opposite direction.

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The required cannonball hits the target with a velocity of 26.25 m/s.

The law of conservation of energy states that sum, when the object is in motion the sum of the initial energy, is equal to the sum of the final energy.

The velocity of the cannonball just before it hits the target can be determined using the law of conservation of energy, which states that the total energy of a system is constant.

The initial potential energy of the cannonball is given by:

PE(i) = mgh

PE(i) = 11 kg * 9.8 m/s^2 * 28 m

PE(i) = 3018.4 J

The final potential energy of the cannonball is given by:

PE(f) = mgh

PE(f) = 11 kg * 9.8 m/s^2 * 11 m

PE(f) = 1185.8J

The initial kinetic energy of the cannonball is given by:

KE(i) = 0.5 * m * v^2

KE(i) = 0.5 * 11 kg * 19 m/s^2

KE(i) = 1985.5 J

Since the total energy of the system is conserved, we have:

PE(i)l + KE(i) = PE_(f) + KE_(f)

3018.4 J + 1985.5  J = 1185.8 J + KE(f)

KE(f) = 3791.1 J

Finally, the velocity of the cannonball just before it hits the target can be calculated from its kinetic energy:

v^2 = 2 * KE / m

v^2 = 2 * 3791.1J / 11 kg

v = √(2 * 3791.1 J / 11 kg)

v = 26.25 m/s

So the cannonball hits the target with a velocity of 26.25 m/s.

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The actual amount of fuel needed for the 750 mile trip is 22.54 U.S. gallons.

Fuel is a material that is burned or used to produce energy. It can come in many forms, including gasoline, diesel, propane, wood, coal, natural gas, and oil. Fuel can be used to power engines to move vehicles, generate electricity, and heat homes and buildings. It is a necessity of modern life, as it is required to power many of the machines, appliances, and systems that make our lives easier. Without fuel, transportation, communication, and many other essential services would be impossible. Fuel is often divided into two categories, renewable and non-renewable.

The tourist mistakenly believes that she needs 18.75 gallons of fuel for a trip of 750 miles. This is calculated as follows:

750 miles/40 miles per gallon = 18.75 gallons

However, since the tourist is using a U.K. gallon, which is larger than a U.S. gallon, the actual amount of fuel needed is less. To do the conversion, we need to convert the 18.75 gallons to litres and then back to U.S. gallons:

18.75 U.K. gallons x 4.546090 litres/U.K. gallon = 85.22 litres

85.22 litres/3.785411.8 litres/U.S. gallon = 22.54 U.S. gallons

Therefore, the actual amount of fuel needed for the 750 mile trip is 22.54 U.S. gallons.

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The volume rate of flow is approximately 102.3 cm if a 5.7 diameter horizontal pipe gradually narrows to 3.6 cm.

To determine the volume rate of flow in a pipe, we can use the equation for the continuity of fluid flow:

[tex]A1 * v1 = A2 * v2[/tex]

where A1 and A2 are the cross-sectional areas of the two sections of the pipe and v1 and v2 are the velocities of the fluid in each section.

We can first convert the diameter measurements to cross-sectional areas:

[tex]A1 = (π / 4) * (5.7 cm)^2 = 40.2 cm^2A2 = (π / 4) * (3.6 cm)^2 = 10.1 cm^2[/tex]

Next, we can use the formula for the velocity of a fluid in a pipe:

[tex]v = (2 * ΔP / ρ)^0.5[/tex]

where ΔP is the pressure difference across the pipe, and ρ is the density of the fluid.

Using this formula, we can find the velocities in each section of the pipe:

[tex]v1 = (2 * (32.5 kPa - 0) / 1000 kg/m^3)^0.5 = 2.53 m/sv2 = (2 * (24.0 kPa - 0) / 1000 kg/m^3)^0.5 = 1.94 m/s[/tex]

Finally, using the continuity equation, we can find the volume rate of flow:

[tex]V = A1 * v1 = A2 * v2V = 40.2 cm^2 * 2.53 m/s = 10.1 cm^2 * 1.94 m/sV = 102.3 cm^3/s[/tex]

So, the volume rate of flow is approximately 102.3 cm

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5. The density here will be 60/150 = 0.4 g/cm³

The force of gravity, often known as gravitation, affects every material thing in the universe. The gravity force tends to draw any two items or particles with nonzero mass toward one another. From subatomic to galaxy clusters, gravity affects things of all sizes.

Gravitation seems to be the force in physics that draws two masses together. Unbelievably, every subatomic particle of matter with in cosmos attracts every other particle through gravity. The phrases attraction and gravity are sometimes used synonymously to refer to the attraction that exists between anything with mass or energy.

6) a. The weight of water causes this pressure .

b. As the weight of water increases the pressure increases too.

7) a. pascal (represented as Pa) can be used to measure pressure.

b. The number of particles increases.

c. The pressure will compress

8) The affect of drag on an object causes friction

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Answer:

Answer: Buoyant force = 19.6N. Water displaced = 0.065m³

Explanation:

The question says:

A ball of mass 2kg had a diameter of 50cm falls into a pool.

Calculate its buoyant force and volume of the water displaced.

According to Archimedes' principle, When a body is immersed fully or partially in a fluid, it experiences an upward force that is equal to the weight of the fluid displaced by it.

At the location of q a in the figure, given that q b = q c = q d = 4.9 nC , q = - 0.25 nC , and the square is 12 cm on a side. The magnitude of the electric field at the location of qa is 2.16 x [tex]10^{7}[/tex] N/C.

The electric field at a point due to a point charge is given by the formula:

E = k . q / r^2

where,

k = Coulomb's constant (8.99 x 10^9 Nm^2/C^2),

q = the charge producing the field,

r = the distance from the charge.

Let's call the side length of the square L. The charges qb, qc, and qd are located at the corners of the square, and are equidistant from the point where we want to calculate the electric field, so we can calculate the field due to each of them separately and then add them up.

The distance between the charges and the point of interest is L/√2. The electric field due to each charge can be calculated as:

E = k * 4.9 x 10^-9 C / (L/√2)^2 = k * 4.9 x 10^-9 C / (12/√2)^2 = k * 4.9 x 10^-9 C / (12/1.4142)^2

Adding the contributions from the three charges, the total electric field due to qb, qc, and qd is:

E = 3 * k * 4.9 x 10^-9 C / (12/1.4142)^2

Next, we need to calculate the contribution from the charge q. The electric field due to q can be calculated in the same way, but since q is negative, the direction of the field will be opposite to that due to the other charges:

Eq = - k * -0.25 x 10^-9 C / (L/√2)^2 = k * 0.25 x 10^-9 C / (12/√2)^2

Finally, the total electric field at the point is the sum of the contributions from all the charges:

Etotal = E + Eq = 3 * k * 4.9 x 10^-9 C / (12/1.4142)^2 + k * 0.25 x 10^-9 C / (12/√2)^2

So, the magnitude of the electric field at the location of qa is:

So the magnitude of the electric field at the location of qa is 2.16 x [tex]10^{7}[/tex] N/C.

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Answer:

Explanation:

when o2 increases, the co2 percentage drops. plants will die. because they needed CO2 for respiration. specially carbon cycle fell into verge.

The football Felipe throws to Lilah will go at a speed of 23 km/h.

The movement of an object in relation to another observer is known as its relative velocity. It is the pace at which one object's close location changes in reference to another object over time.

Felipe is riding his skateboard toward Lilah at 15 km/h. He throws a football to Lilah. The football is thrown at 8 km/h.

Then the velocity of the ball is given as,

v = 15 + 8

v = 23 km/h

The velocity of the ball will be 23 km / h.

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The kinetic energy is increased by the number of flights of steps that the rider will climb. The correct option is D.

The energy an object has as a result of motion is known as kinetic energy in physics. It is described as the effort required to move a mass-determined body from rest to the stated velocity. The body holds onto the kinetic energy it acquired during its acceleration until its speed changes.

Given that the engineers are testing the waterslide for the theme park.

As we can know that kinetic and potential energy are two energies which are converted from one to another. The potential energy is increased by increasing the height of the slide from the ground level.

If the potential energy is higher than the kinetic energy of the slider will also increase during the downward journey.

So by increasing the number of flights of steps that the rider will climb there will be more kinetic energy in the slide. The correct option is D.

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The thought is a significant issue facing by united states. In the capitalist economy, all the sectors are changing to private mode and labors facing competing issues.

In capitalist democracies, there are impossibly high hurdles that prevent the government from opposing capitalism. Although the concept of "one person, one vote" gives the impression that everyone has an equal voice, the state is actually a system of institutions that we may influence by casting the proper votes.

Instead, it is wanted to demonstrate that capitalists wield excessive political power through both the market and the state, and that this power comes mainly from the productive assets they own.

The wealth of the wealthy, however, has been financialized during the past 40 years. Due to this, they now have more access to money markets to leave political areas. Even if this gives capitalists more leverage to evade expropriation demands, I'll conclude on a positive note.

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