The perimeter of a rectangular swimming pool is 56 meters. The width is 4 meters less than the length. What is the width of the swimming pool? 4 meters 4 meters 8 meters 8 meters 12 meters 12 meters 24 meters

Answer:

[tex]A(-3,2)\: B(-1,-2)\: C(1,3)[/tex]

[tex]A=1/2[x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)][/tex]

[tex]=1/2[-3(-2-3)(+1(3-2)+1(2-(-2))][/tex]

[tex]=1/2(15+1+4)[/tex]

[tex]=1/2(20)[/tex]

[tex]=10[/tex]

[tex]ANSWER: 10 ~units^{2}[/tex]

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hope it helps...

have a great day!!

The area of triangle with vertices A(-3,2), B(1,-2), and c(1,3) is 12 units^2.

The area of a triangle is defined as the total space occupied by the three sides of a triangle in a 2-dimensional plane. The basic formula for the area of a triangle is equal to half the product of its base and height, i.e., A = 1/2 × b × h.

The green line represents the height of the triangle = 4 units

The red line represents the base of the triangle = 6 units

Area of the triangle = 1/2 x 6 x 4 = 12 units^2

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Answer:

Greatest common factor = [2x - 5][x + 2]

Step-by-step explanation:

Given equation:

2x² - x - 10

Find:

Greatest common factor

Computation;

⇔ 2x² - x - 10

By splitting mid term

⇔ 2x² - [5 - 4]x - 10

Multiply by 'x'

⇔ 2x² - 5x + 4x - 10

taking x and 2  as common

⇔ x[2x - 5] + 2[2x - 5]

taking [2x - 5]  as common

⇔ [2x - 5][x + 2]

Greatest common factor = [2x - 5][x + 2]

Answer:

A. Cos S

Step-by-step explanation:

Recall: SOH CAH TOA

Sin W = Opp/Hyp

Opposite = 4

Hypotenuse = 5

Sin W = 4/5

Let's find the ratio for each option given to determine which gives us the same ratio as Sin W.

Option A: Cos S

Cos S = Adj/Hyp = 4/5

Option B: tan W

Tan W = Opp/Adj = 4/3

Option C: cos W

Cos W = Adj/Hyp = 3/5

Option D: sin S

Sin S = Opp/Hyp = 3/5

✔️Thus, sin W = cos S = 4/5

The correct option is A

Answer:

I think 1500 but u may need some else to be sure

Answer:

7

Step-by-step explanation:

trio meaning 3 quartet (quart) 4

Answer:

f(x)=(x+1)(x+2)(x+3)(x+4)+2019

f(x)=(x2+5x+4)(x2+5x+6)+2019

Suppose that y=x2+5x

Hence we have f(y)f(y)=(y+4)(y+6)+2019=y2+10y+24+2019=y2+10y+25+2018=(y+5)2+2018≥2018[∵(y+5)2≥0,∀y∈R]

and therefore…. min (f(x))=2018

ANSWER = 2018

Step-by-step explanation:

hope that helps >3

Answer:

2018

Step-by-step explanation:

By grouping the first, last and two middle terms, we get ([tex]x^{2}[/tex]+5x+4)([tex]x^{2}[/tex]+5x+6) + 2019. This can then be simplified to ([tex]x^{2}[/tex]+5x+2)^2 - 1 + 2019 Noting that squares are nonnegative, and verifying that [tex]x^{2}[/tex] + 5x + 5 = 0 for some real x, the answer is 2018.

Answer:

B. On the horizontal number line, -2.5 is located to the left of zero and 2.5 is located to the right of zero

B.

Hope this helps <33!

Answer:

[tex]{ \bf{c(g) = 5g + 3}} \\ { \bf{c(6) = 5(6) + 3}} \\ { \boxed{ \tt{c(6) = 33}}}[/tex]

Answer:

Step-by-step explanation:

Equation for the total volume of the bucket has been given as,

V = 4 + 2t

Here V = Total volume

t = elapsed time

Table for the input-output values,

t        0         1         2        3        4

V       4         6        8        10      12

Therefore, line passing through the given points in the table will be the graph for the equation.

Answer:

a=1

Step-by-step explanation:

Hopefully this helps :)

The equation of the parabola is: y = (x - 2)² - 2. Finding the value of A

The vertex of the parabola is at (2,-2). Since the parabola opens upward, the equation of the parabola will be of the form:

y = A(x - 2)² - 2

We can plug the point (3,-1) into this equation to find the value of A.

-1 = A(3 - 2)² - 2

Simplifying the right side of the equation, we get:

-1 = A - 2

Adding 2 to both sides of the equation, we get:

1 = A

Therefore, the value of A is 1.

Writing the equation of the parabola

The equation of the parabola is:

y = (x - 2)² - 2

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Step-by-step explanation:

hope it helps you.........

Answer:

[tex]here \: is \: your \: solution : - \\ \\ here \: is \: a \: right \: traingle \: with \\ \\ base \: = 52 \: units \\ \\ hypotenuse \: = 65 \: units \\ \\ perpendicular \: = {?} \\ \\ we \: need \: to \: find \: perpendicular \\ \\ by \: using \: pythagorus \: theorem : - \\ \\ perpendicular ^{2} \: = base ^{2} + perpendicular ^{2} \: \\ \\ perpendicular^{2} \: = 65 {}^{2} - 52 {}^{2} \\ \\ perpendicular {}^{2} = (4225 - 2704) \\ \\ perpendicular {}^{2} = 1521 \\ \\ perpendicular = \sqrt{1521} \\ \\ perpendicular = 39 \: units \: \\ \\ hope \: it \: helps \: you \: [/tex]

Answer:

super find out how many of

Step-by-step explanation:

final answer is 4 91 1 6 this is square root of 10

The property of math they are learning is the distributive property

Answer: -3, 4

Step-by-step explanation:

x · y = -12

x + y = 1 ⇒ y = 1 - x

Bring the y-value(1 - x) into x · y = -12:

[tex]x(1 - x) = -12 \\x-x^{2}=-12\\-x^{2}+x+12=0\\-(x^{2}-x-12)=0\\(x+3)(x-4)=0\\x=-3,x=4[/tex]

Bring the x-values into y = 1 - x and see if the values multiply to -12:

x = -3 ⇒ 1 - (-3) = 4 ⇒ 4 * -3 = -12

x = 4 ⇒ 1 -4 = -3 ⇒ -3 * 4 = -12

Answer:

[tex]b=80[/tex]°

Step-by-step explanation:

The central angles theorem states that the measure of an angle whose vertex is the center of the circle is equivalent to the arc surrounding it. One can apply this here by stating that the measure of the arc surrounding the (90) degree angle is (90) degrees.

The total degree measure of a circle is (360). Thus one can form an equation and solve it to find the measure of the arc surrounding the angle (b). Call the arc surrounding angle (b); ([tex]b_1[/tex]).

[tex](b_1)+(90)+(110)=360[/tex]

Simplify,

[tex]b_1+200=360[/tex]

Inverse operations,

[tex]b_1+200=360[/tex]

[tex]b_1=160[/tex]

The peripheral angles theorem states that if the vertex of an angle formed between a tangent and a chord, is on the circumference (outer edge) of a circle, then the measure of the angle is equal to half of the measure of the surrouding arc. Please note that a chord is a line segment in a circle that intersects the circle in two points. A tangent is a line segment that intersects a circle at one point. One can apply this here by stating the following,

[tex]b=\frac{b_1}{2}[/tex]

Substitute,

[tex]b=\frac{160}{2}[/tex]

Solve,

[tex]b=80[/tex]

We are given:

aᵇ = bᵃ

b = 2a

Finding (a+b):

Finding a:

replacing b by 2a in the first equation, we get:

(a²)ᵃ = (2a)ᵃ

(a²)ᵃ = 2ᵃ * aᵃ

a²ᵃ / aᵃ = 2ᵃ                  [dividing both sides by aᵃ]

aᵃ = 2ᵃ                          [because xᵃ / xᵇ = xᵃ⁻ᵇ]

a = 2                             [raising both sides to 1/a]

Finding b:

We are given that b = 2a

now that we know what a equals, we will plug that value here

b = 2(2)

b = 4

Finding a+b:

We found that a = 2, b = 4

a + b = 2 + 4 = 6

Answer:

401 a week

Step-by-step explanation: Fred earns $5.15 dollars plus a tip of $195  if he works for 40 hours the equation would be x=ab+c  X is the week, A is the money per hour, B is the amount of hours and C is the tip   X= 5.15(40)+195       5.15 times 40 is 206 then 206+195 is 401 which is your answer

Answer:

A. 55%

Step-by-step explanation:

First we should make these into fractions

A. 33/60

B. 36/78

C. 40/89

D. 24/59

these are the fractions, The question wants us to pick the Park with the Greatest Percentage, Not The Greatest Amount, so Lets look at these fractions A. 33/60 Is 55%   B. 36/78 is  46% .   C. 40/89 is 44%   D. 24/59 is about 40%

I also remember doing this on a quiz!!

Answer:

2. increasing when x > 0

the result of root is a positive number

and since there is no value of neg number in roots so it's increasing when x>0

plus in zero it self has a positive number (0,8)

but u cannot find either it's increasing or decreasing in zero bcoz in first derivative test

when x =0

y= not defined

Answer:

Step-by-step explanation:

2x=4y+8

divide by 2

x=2y+4

and x-2y=4

or x=2y+4

so both the equations represent the same line.

Vertical ship up three and two to the right and the square root will flip

so options I is wrong

II is right

III is right

IV is wrong

THUS THE ANSWER IS OPTION II III

4

Hey there!

[tex]\mathsf{x^2 - 11 = 25}[/tex]

[tex]\large\textsf{ADD 11 to BOTH SIDES}[/tex]

[tex]\mathsf{x^2 - 11 + 11 = 25 + 11}[/tex]

[tex]\large\textsf{CANCEL out: -11 + 11 because that gives you 0}[/tex]

[tex]\large\textsf{KEEP: 25 + 11 because that helps solve for the x-value}[/tex]

[tex]\mathsf{25 + 11 = \bf 36}[/tex]

[tex]\large\textsf{NEW EQUATION: }\mathsf{x^2=36}[/tex]

[tex]\large\textsf{Take the square root of the number (36)}[/tex]

[tex]\mathsf{x = \pm \sqrt{36}}[/tex]

[tex]\mathsf{\pm = \boxed{\bf plus-or-minus}}[/tex]

[tex]\mathsf{x = \sqrt{-36}\rightarrow \bf -6}[/tex]

[tex]\large\textsf{or}[/tex]

[tex]\mathsf{x = \sqrt{36} = \bf 6}[/tex]

[tex]\boxed{\boxed{\huge\textsf{Answer: \bf x = 6 or x = -6}}}\huge\checkmark[/tex]

[tex]\large\text{Good luck on your assignment and enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

x² - 11 = 25

Add 11 to both sides.

x² - 11 + 11 = 25 + 11

Cancle out the 11 because when we add -11 to 11 that gives 0. On other side add 25 and 11 we get 36.

x² = 36

Take the square root of both sides of the equation and remember to use both positive and negative roots.

√x² = ± √36

x = ± 6

Write the solutions, one with a+ sign and one with a- sign.

[tex] x_1 = 6[/tex]

[tex]x_2 = -6[/tex]

This equation has two solutions which are :-

[tex] x_1 = 6[/tex]and [tex]x_2 = -6[/tex]

Answer:

Relation

Explanation:

The definition of a relation is just a set of ordered pairs.

A function is a relation in which each domain element is paired with exactly one range element.  

It can't be a function because if it is a vertical line, then the x-value is the same for the whole line.

I hope that helps a bit

Answer:

[tex]Area = \frac{1}{2} * AC * D[/tex]

Step-by-step explanation:

From the complete question, we have:

Length D to be perpendicular to side AC

So, the area of the triangle is:

[tex]Area = \frac{1}{2} * Base * Height[/tex]

Since:

Length D is perpendicular to side AC

Then:

[tex]Base = AC[/tex]

[tex]Heigjt =D[/tex]

So:

[tex]Area = \frac{1}{2} * AC * D[/tex]

the answer is in the picture above

Answer:

No

Step-by-step explanation:

One is used as an enlargement of the object drawn. The image formed can either be smaller or bigger.

Answer:

x^2-2x-3+6=0

(x-2x)-(3x+6)=0

x(x-2)-3(x-2)=0

(x-3)(x-2)=0

x-3=0 or x-2=0

x=3or x=2