The perimeter of a rectangle is 99 ft, and the length is twice the width. what are its dimensions?

Answers

Answer 1

The dimension of the length and width of the rectangle with the given perimeter are 33ft and 16.5ft respectively.

What are the dimensions of the rectangle?

Perimeter of rectangle is expressed as;

P = 2( l + w )

Given that;

Perimeter P = 99ftLet width w = xLength l = 2x

We substitute into the formular above.

P = 2( l + w )

99ft = 2( x + 2x )

99ft = 2x + 4x

99ft = 6x

x = 99ft/6

x = 16.5ft

Width = x = 16.5ft

Length = 2x = 2( 16.5ft ) = 33ft

Therefore, the dimension of the length and width of the rectangle with the given perimeter are 33ft and 16.5ft respectively.

Learn more about rectangles here: https://brainly.com/question/27612962

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Value of [tex]\boldsymbol{DG}[/tex] in a triangle [tex]DFG[/tex] is equal to [tex]\boldsymbol{21}[/tex] inches. To understand the calculations, check below.

Define similar triangles.

Two triangles are said to be similar if their sides are proportional and their angles are equal.

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Answers

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Answers

Answer:

17 meters x 20 meters

Step-by-step explanation:

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Answer:

Step-by-step explanation:

Givens

Let the width = w

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Formula

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P = 74

Solution

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I really really need help

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Step-by-step explanation:

you can use any two points on the graph but I used the easiest one. It doesn't matter it will give the same result

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