The path of a projectile launched from a 20-ft-tall tower is modeled by the equation y = -5x2 + 40x + 20. What is the maximum height, in meters
reached by the projectile?

The Path Of A Projectile Launched From A 20-ft-tall Tower Is Modeled By The Equation Y = -5x2 + 40x +

Answers

Answer 1

Answer:

30.49 m

Step-by-step explanation:

To obtain the maximum height, we solve for the value x when dy/dx = 0.

Since, y = -5x² + 40x + 20

dy/dx = d[-5x² + 40x + 20]/dx

dy/dx = -10x + 40

Since dy/dx = 0,

-10x + 40 = 0

-10x = -40

x = -40/-10

x = 4

Substituting x = 4 into the equation for y, we have

y = -5x² + 40x + 20

y = -5(4)² + 40(4) + 20

y = -5(16) + 160 + 20

y = -80 + 160 + 20

y = 80 + 20

y = 100 ft

Since y is in feet, we convert to meters.

Since 1 m = 3.28 ft, 100 ft = 100 ft × 1 m/3.28 ft = 30.49 m

So, the maximum height, in meters  reached by the projectile is 30.49 m


Related Questions

Jim is designing a seesaw for a children’s park. The seesaw should make an angle of 45 degrees with the ground, and the maximum height to which it should rise is 1 meter, as shown below: What is the maximum length of the seesaw? Choices: A) 1 meter B) 1.4 meters C) 2 meters D) 0.5 meters

Answers

Answer:

B) 1.4

Step-by-step explanation:

The sine of an angle is equal to the ratio of the opposite side to the hypotenuse.

sin(B)=opp/hyp

The maximum length of the seesaw is 1.4 meters

Trigonometric ratio

Trigonometric ratio is used to show the relationship between the sides and angles of a right angled triangle.

Let h represent the length of the seesaw, hence using trigonometric ratio:

sin(45) = 1 / h

h = 1.4 meters

The maximum length of the seesaw is 1.4 meters

Find out more on Trigonometric ratio at: https://brainly.com/question/1201366

Help plsssssss ,it would mean a lot thankyou

Answers

Answer:

Part 1;

(0, 0)

Part 2;

(0, 2.5)

Step-by-step explanation:

Part 1

The given system of inequalities is presented as follows;

f(x) < x + 4; f(x) > -x - 3; and f(x) < 5

We check each of the points as follows;

The point (0, 0) in the inequality f(x) < x + 4, gives;

f(0) < 0 + 4

f(0) = 0 < (is less than) 0 + 4 = 4

Therefore, (0, 0) is a solution of the inequality f(x) < x + 4

The point (0, 0) in the inequality f(x) > -x - 3, gives;

f(0) < -0 - 3

f(0) = 0 > (is larger than) -0 - 3 = -3

Therefore, (0, 0) is a solution of the inequality f(x) > -x - 3

The point (0, 0) in the inequality f(x) < 5, gives;

f(0) < 5

f(0) = 0 < (is less than) 5

Therefore, (0, 0) is a solution of the inequality f(x) < 5

The point (-6, 0) in the inequality f(x) > -x - 3, gives;

f(-6) = -6 - 3 = 3

The point (-6, 0) with y = 0 < (is less than) f(-6) = 3, therefore (-6, 0) is not a solution to (not included in the graph of) the inequality f(x) > -x - 3 and therefore to the system of inequalities because at x = -6, the values of f(x) > -x - 3 are larger than 3

The point (-3, 4) in the inequality f(x) < x + 4, gives;

f(-3) = -3 + 4 = 1

The point (-3, 4) with y = 4 < (is larger than) f(-2) = 1, therefore (-3, 4) is not a solution to (not included in the graph of) the inequality f(x) < x + 4  and therefore to the system of inequalities because at x = -3, the values of f(x) < x + 4 are less than 1

The point (4, 6) is not a solution to (not included in the graph of) the inequality f(x) < 5  and therefore to the system of inequalities because f(x) is larger than 5 for all x

Therefore, the point which is part of the solution set of the system of inequalities is (0, 0)

Part 2

The given system of inequalities are, f(x) ≥ 2·x + 2; f(x) ≤ -4·x + 3; and f(x) ≤ 6·x + 5

Plotting the given system of inequalities on MS Excel the point which is part of the solution is given by points which are within the triangular intersection area of the three inequalities, with coordinates, (1/6, 7/3), (-3/4, 1/2), and (-1/5, 19/5)

Therefore, the points, (0, 0), (-2.5, 0) are not solutions because, the y-value of the solution area are all higher than the line y = 0

The point (0. 6.5) is not a solution because the points in the triangular solution area all have x-values lesser than x = 6.5

The point which is part of the solution by examination is the point (0, 2.5) which is a point between the lines y = 19/5 = 3.8, y = 1/2, x = -3/4, and x = 1/6.

A matrix derived from a system of linear equations (each written in standard form with the constant term on the right) is the ---Select--- matrix of the system.

Answers

Answer:

augmented

Step-by-step explanation:

In the field of linear algebra, the augmented matrix is defined as the matrix that is [tex]\text{obtained by appending}[/tex] the given columns of any two given matrices, that is usually for the [tex]\text{purpose of performing the same elementary row operations on each of the given matrices. }[/tex]

Here, each row forms an equation having a constant and the column have the  coefficients for the single variable.

Thus an augmented matrix is obtained from a system of linear equation in matrix.

Given 2n-1 x 8^n = 2048, find the value n.​

Answers

The answer is 4.00029833

Which equation has no solution?

Answers

Answer:

Step-by-step explanation:

Jazmine they are asking about the absolute value signs,   see how that first one has a negative 6 for the solution?  well the absolute value of the other side of that equal sign will never be a negative 6  ,  see now?  so that first answer has no solution  :)

lines b and c are parallel. no links.

Answers

Answer:

Value of x:

[tex]{ \tt{(13x + 9) + (5x + 9) = 180 \degree}} \\ { \tt{18x + 18 = 180 }} \\ { \tt{18x = 162}} \\ { \tt{x = 9}} \\ [/tex]

Angle m‹6:

[tex]{ \boxed{ \tt{m \angle6 = (5x + 9) \degree}}} \\ { \tt{m \angle6 = (5 \times 9) + 9}} \\ { \tt{m \angle6 = 54 \degree}}[/tex]

Answer:

B. 54 degrees

Step-by-step explanation:

Set up an equation that equals 180 degrees because a line is 180 degrees:

(13x+9)+(5x+9)=180

Solve for x:

x=9

Substitute 9 in 5x+9:

5(9)+9

Solve.

54

Since angle 6 is complementary, it is the same as the 7th angle.

So the answer is B, 54 degrees.

Hope this helps!

need a help!!!
I need the answer only for the c part

Please help!!
Please answer correctly​

Answers

Step-by-step explanation:

316 days when you get the idea the most important thing is that the people who are looking for the right reasons why you

Consider this system of equations. Which shows the second equation written in slope-intercept form? y = 3 x minus 2. 10 (x + three-fifths) = 2 y y = 5 x + StartFraction 3 Over 10 EndFraction

Answers

Answer:

[tex]y = 5x + 3[/tex]

Step-by-step explanation:

Given

[tex]y = 3x - 2[/tex]

[tex]10(x + \frac{3}{5}) = 2y[/tex]

Required

The second equation in slope intercept form

We have:

[tex]10(x + \frac{3}{5}) = 2y[/tex]

Divide both sides by 2

[tex]5(x + \frac{3}{5}) = y[/tex]

Open bracket

[tex]5x + 3 = y[/tex]

Rewrite as:

[tex]y = 5x + 3[/tex]

Hence, the equation in slope intercept form is: [tex]y = 5x + 3[/tex]

Answer: I agree with the other person

Step-by-step explanation:

Complete the transformations below. Then enter the final coordinates of the figure.

A" (,)
B" (,)
C" (,)
HELP! PLZ.

Answers

Answer:

Step-by-step explanation:

If a point (x, y) is translated by 4 units horizontally right and 1 unit upwards, coordinates of the image point will be,

(x, y) → (x + 4. y + 1)

Therefore, vertices of the image triangle ABC will be,

A(2, 2) → A'(2+4, 2+1)

           → A'(6, 3)

B(5, -1) → B'(5+4, -1+1)

           → B'(9, 0)

C(1, -2) → C'(1+4, -2+1)

           → C'(5, -1)

Then reflected across y-axis.

Rule for the reflection across y-axis will be,

(x, y) → (-x, y)

A'(6, 3) → A"(-6, 3)

B'(9, 0) → B"(-9, 0)

C'(5, -1) → C"(-5, -1)

Answer:

A"(-6, 3)

B"(-9, 0)

C"(-5, -1)

Step-by-step explanation:

Question 7 of 10 What is the slope of the line shown below? A. 2 B.-2 C.4 D.-4​

Answers

Answer:

C. 4

Step-by-step explanation:

Use the slope formula y2-y1 / x2-x1

6+2/3-1

8/2

4

So, the answer is C. 4.

C.4 you need to use the formula for slope

Find the distance between A (2,0,-1) and B (3,1,4) and find the mid-point of line segment AB."

Answers

Step-by-step explanation:

To Find :-

Distance between the two points .

Solution :-

Using Distance Formula ,

> d = √{ ( 2-3)² + (0-1)² + (-1-4)² }

> d = √{ (-1)² + (-1)² + (-5)² }

> d = √{ 1 + 1 + 25 }

> d = √26 .

Using midpoint formula ,

> m = ( 2+3/2 , 0+1/2 , -1+4/3 )

> m = ( 5/2 , 1/2 , -3/3 )

> m = ( 2.5 , 0.5 , -1 )

I dont understand what to do here, can somebody help, please? 4.2 / 6 = ____ tenths / 6 4.2 / 6 ____ tenths

Answers

Answer:

sei lá, pergunta pra tua mãe

Which is the best estimate for 6.3×10 to the second power times 9.9×10 to the 3rd power written in scientific notation

Answers

Answer:

in scientific notation, the expression can be written as 6.237 x 10⁶

Step-by-step explanation:

Given;

6.3×10 to the second power times 9.9×10 to the 3rd power

Using scientific notation, it can be interpreted as;

[tex](6.3 \times 10^2) \times (9.9 \times 10^3)[/tex]

This can be simplified as;

[tex](6.3 \times 10^2) \times (9.9 \times 10^3) = (6.3\times 9.9)\times 10^{2+3}\\\\= 62.37\times 10^5 = 6.237\times 10^6[/tex]

Therefore, in scientific notation, the expression can be written as 6.237 x 10⁶

What is best buy £3.99 5kg or 3.2kg £2. 60?​

Answers

Answer:

I would say 5 kg because you get more kg with a little bit more money added

Find the value of x. PLEASE HELP ASAP

Answers

Hi there!

[tex]\large\boxed{A. \text{ } 7}[/tex]

The following trapezoidal theorem states that:

Middle segment = average of top and bottom side

Thus:

M = 1/2(b1 + b2)

21 - x = 1/2(17 + 11)

Solve:

21 - x = 1/2(28)

21 - x = 14

Subtract 21 from both sides:

-x = 14 - 21

-x = -7

Multiply both sides by -1:

x = 7

A certain forest covers an area of 3600km^2. Suppose that each year this area decreases by 6%. What will the area be after 8 years?

Answers

Answer:

= 1728km2

Step-by-step explanation:

From the formula A = PRT/100%

Where; A is final

P is initial

T is time taken

R is the rate

Therefore A = 3600 × (6/100) × 8

= 1728km2

modrater give answer


if 27x = 45263514282 than find the value of 200x ​

Answers

═══════ღ❦ღ══╮

[tex]\boxed{ \sf{Answer}} [/tex]

↦ First find the value of x

[tex]27x = 45263514282 \\ x = \frac{45263514282}{27} \\ x = 1676426454.89[/tex]

↦ Now, find the value of 200x

[tex]x = 1676426454.89 \\ 200x = 200 \times 1676426454.89 \\ 200x = 335285290978[/tex]

ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ

꧁❣ ʀᴀɪɴʙᴏᴡˢᵃˡᵗ2²2² ࿐

Given that,

→ 27x = 45263514282

Then we have,

To find the required value of 200x.

Before that,

find the required value of x.

→ 27x = 45263514282

→ x = 45263514282/27

→ [x = 1676426454.89]

Now we can,

Solve for the value of 200x.

→ 200x

→ 200 × (x)

→ 200 × (1676426454.89)

→ 335285290978

Hence, 200x is 335285290978.

how much does 1/64 stand for

Answers

Answer:

1/64 is 0.015625 in decimals

what is the slope of the line shown below? (enter your answer as a decimal if necessary.)

Answers

Answer: The slope is 2 -Please mark brainliest

1. Find the X and Y values of each point

X1: 1

X2: -1

Y1: 3

Y2: -1

2. Subtract X1 from X2 and Y1 from Y2

Y: -1-3=-4

X: -1-1=-2

3. Divide the X value by the Y value

-4/-2=2

The slope of the line shown on the coordinate plane is 2.

Answer:

2

Step-by-step explanation:

(X1,Y1)=(1,3)

(X2,y2)=(-1,-1)

slope(m)=y2-y1/x2-x1

= -1-3/-1-1

= -4/-2

= 2

1.8 divided by 1,008 I have to have it by tomorrow please help ! And also I have to show all the work so please help me

Answers

Answer:

Step-by-step explanation:

1,008/1.8=10,080/18

18)10080(560

     90

    -

   ----------

      108

      108

     -

   ------------

           0

 ---------------

If the volume of a cubical room is 2700 cm^3 . Find its length

Answers

Step-by-step explanation:

If the volume of a cubical room is 2700 cm³ .

l³=2700

l=3 (100)⅓


[tex]find \: the \: volume \: of \: cylinder \\ \\ radius \: = 4 \: cm \\ \\ height \: = \: 10 \: cm \: \\ \\ [/tex]

Answers

the volume is 502.6

the volume of a cylinder is V= (pi)(radius squared)(height)

in this case it would be pi times 4^2 times 10, which is 502.6 :)

A salesman receives a salary of 250 a month. To this is added 5/4% of the sales that he makes. what is his pay for a month in which he makes 1500 in sales. ​

Answers

Answer: $268.75

Step-by-step explanation:

First, find the amount he earned from his sales:

5/4% = 1.25% =0.0125

1500(0.0125) = $18.75

Next, add that to his monthly salary:

$250 + $18.75 = $268.75

find area of the figure
thanks for any help

Answers

Answer:

8050 m²

Step-by-step explanation:

We can divide the diagram up into two components: a rectangle with a width of 60 m and a height of 80 m, and a triangle with a base of 130 m (190 - 60) and a height of 50 m (80 - 30).

The area of the rectangle:

A = lw

A = 60 m (80 m)

A = 4800 m²

The area of the triangle:

A = 1/2 b*h

A = 1/2 (130 m) (50 m)

A = 1/2 (6500 m²)

A = 3250 m²

Now, we can add the areas of the two separate components:

A = 4800 m² + 3250 m²

A = 8050 m²

The answer is 8050m^2

Solve for x. Round to the nearest tenth of a degree, if necessary.

Answers

Answer:

x ≈ 60.6°

Step-by-step explanation:

Using the tangent ratio in the right triangle

tan x = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{IJ}{HI}[/tex] = [tex]\frac{3.9}{2.2}[/tex] , then

x = [tex]tan^{-1}[/tex] ([tex]\frac{3.9}{2.2}[/tex] ) ≈ 60.6° ( to the nearest tenth )

the ratio of 10:25 in its simplest form?

Answers

Answer:

2:5

Step-by-step explanation:

10:25 = 10/25 = 2/5 = 2:5

Answer:

2:5

Step-by-step explanation:

divide both of them by 5

10 divided by 5 is 2

25 divided by 5 is 5

expand: 4(w - 2)
(with the steps)​

Answers

Answer:

4w-8

Step-by-step explanation:

4(w-2)

(4*w)-(4*2)

4w-8

Answer:

4w-8

Step-by-step explanation:

4(w - 2)

Distribute

4*w - 4*2

4w-8

A7. Charlie sales wristbands to earn extra money. She charges $7 per wristband for material and $2.00 per hour to make
unique gifts. How much would two wristbands cost together if one takes her an hour and a half to make one and two
hours to make the other one?

Answers

Answer:

$21

Step-by-step explanation:

Find the cost of the wristband that took an hour and a half to make:

2(1.5) + 7

= 10

Find the cost of the one that took 2 hours to make:

2(2) + 7

= 11

Add together the prices:

10 + 11

= 21

So, it will cost $21

Which relation is a function?

Answers

Answer:

the function is the solution is done using the operation

a function is where there is only one output for every input. so when you plug in an x value, you should be getting only one y value.

it’s not the first one because you can see there are two points at (-1,0)
it’s not the second one because you can see there are two points at (0,0)
it’s not the fourth one because again there are two points at (-2,0) and (2,0)

it’s the third one because there is only one y value for every x value.

family of solutions of the second-order DE y y 0. Find a solution of the second-order IVP consisting of this differential equation and the given initial conditions. 12. y(1) 0, y(1) e

Answers

Answer:

[tex]y = \frac{1}{2}e^x -\frac{1}{2} e^{2-x}[/tex]

Step-by-step explanation:

Given

[tex]y=c_1e^x +c_2e^{-x[/tex]

[tex]y(1) = 0[/tex]

[tex]y'(1) =e[/tex]

Required

The solution

Differentiate [tex]y=c_1e^x +c_2e^{-x[/tex]

[tex]y' = c_1e^x - c_2e^{-x}[/tex]

Next, we solve for c1 and c2

[tex]y(1) = 0[/tex] implies that; x = 1 and y = 0

So, we have:

[tex]y=c_1e^x +c_2e^{-x[/tex]

[tex]0 = c_1 * e^1 + c_2 * e^{-1}[/tex]

[tex]0 = c_1 e + \frac{1}{e}c_2[/tex] --- (1)

[tex]y'(1) =e[/tex] implies that: x = 1 and y' = e

So, we have:

[tex]y' = c_1e^x - c_2e^{-x}[/tex]

[tex]e = c_1 * e^1 - c_2 * e^{-1}[/tex]

[tex]e = c_1 e - \frac{1}{e}c_2[/tex] --- (2)

Add (1) and (2)

[tex]0 + e = c_1e + c_1e + \frac{1}{e}c_2 - \frac{1}{e}c_2[/tex]

[tex]e = 2c_1e[/tex]

Divide both sided by e

[tex]1 = 2c_1[/tex]

Divide both sides by 2

[tex]c_1 = \frac{1}{2}[/tex]

Substitute [tex]c_1 = \frac{1}{2}[/tex] in [tex]0 = c_1 e + \frac{1}{e}c_2[/tex]

[tex]0 = \frac{1}{2} e+ \frac{1}{e}c_2[/tex]

Rewrite as:

[tex]\frac{1}{e}c_2 = -\frac{1}{2} e[/tex]

Multiply both sides by e

[tex]c_2 = -\frac{1}{2} e^2[/tex]

So, we have:

[tex]y=c_1e^x +c_2e^{-x[/tex]

[tex]y = \frac{1}{2}e^x -\frac{1}{2} e^2 * e^{-x}[/tex]

[tex]y = \frac{1}{2}e^x -\frac{1}{2} e^{2-x}[/tex]

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