Answer:
[tex]\mathbf{t_2 = 75.696 \ min}[/tex]
Explanation:
From the question:
The outer surface of a steel gear is to be hardened by increasing its carbon content
Given that :
Diffusion of heat temperature at [tex]T_1[/tex] 850 °C = 1123 K
Diffusion time [tex]t_1[/tex] = 10 min
diffusion after the carbon concentration at a position [tex]x_1[/tex] ( 1.0 mm) below the surface = 0.90 wt%
Preexponential = 1.1 × 10⁻⁶ m²/s
Activation Energy [tex]Q_d[/tex] = 87400 J/mol
We are to determine the time [tex]t_2[/tex] at 650 °C (923 K) to achieve the same diffusion result as at 850 °C (1123 K) for [tex]t_1[/tex] = 10 min
Considering Fick's second law for the condition of Constant surface concentration; we have:
[tex]\frac{Cx-C_0}{C_s-C_0} = 1-erf(\frac{x}{2\sqrt{Dt} } )[/tex] ------ equation (1)
where;
[tex]C_0 =[/tex] concentration of the diffusing solute atom before diffusion
[tex]C_s[/tex] = Constant surface concentration
[tex]C_x[/tex] = Concentration at depth x after time t
[tex]erf(\frac{x}{2\sqrt{Dt} } )[/tex] = Gaussian error function
At some desired specific concentration of solute [tex]C_1[/tex] in an alloy ; the left side of the above equation (1) thus becomes constant ;
i.e [tex]\frac{Cx-C_0}{C_s-C_0} = \mathbf{ constant}[/tex]
Then ; [tex]\frac{x}{2\sqrt{Dt} }[/tex] = constant
[tex]\frac{x^2}{Dt}[/tex] = constant
Dt = constant
Thus; [tex]D_1t_1 = D_2t_2[/tex]
Therefore, the time [tex]t_2[/tex] at 650°C([tex]T_2[/tex] = 923 K) required to produce the same diffusion on result as at 850°C ([tex]T_1[/tex] = 1123 K) for [tex]t_1[/tex] = 10 min is [tex]t_2 = \frac{D_1t_1}{D_2}[/tex]
We need to first determine the Diffusion coefficient at 1123 K and 923 K ( i.e [tex]D_1[/tex] and [tex]D_2[/tex])
At [tex]T_1[/tex] = 1123 K , Diffusion coefficient [tex]D_1[/tex] is calculated by the equation [tex]D_1 = D_0 exp ( - \frac{Q_d}{RT_1})[/tex] (equation from temperature dependence of the diffusion coefficient)
[tex]D_1 = 1.1 * 10^{-6} \ exp ( - \frac{87,400}{8.314*1123} )[/tex]
[tex]D_1 = 9.462*10^{-11} \ m^2/s[/tex]
[tex]D_2 = D_0 exp ( - \frac{Q_d}{RT_2})[/tex]
[tex]D_2 = 1.1 * 10^{-6} \ exp ( - \frac{87,400}{8.314*923} )[/tex]
[tex]D_2 = 1.25*10^{-11} m^2/s[/tex]
[tex]t_2 = \frac{ 9.462*10^{-11}*10}{ 1.25*10^{-11} }[/tex]
[tex]\mathbf{t_2 = 75.696 \ min}[/tex]
A sample of gas had a volume of 20.0 liters at 00C and 1520 torr. What would be the volume of this gas sample at 00C and 760 torr?
Answer:
40.0 L
Explanation:
Please see the step-by-step solution in the picture attached below.
Hope this answer can help you. Have a nice day!
What is enthalpy?
A. Enthalpy is the heat involved in a reaction.
B. Enthalpy is the temperature of a reaction.
C. Enthalpy is the mass involved in a reaction.
D. Enthalpy is the kinetic energy of a system.
Enthalpy is the heat involved in a reaction.
The enthalpy change is the sum of the internal energy and the product of volume and pressure. Enthalpy is the heat involved in a reaction. The correct option is A.
What is enthalpy?The enthalpy denotes the measurement of energy in a thermodynamic system. The amount of enthalpy equals to the total heat content of a system, equivalent to the system's internal energy plus the product of volume and pressure.
The enthalpy is described as a state function, which indicates that its value depends only on the state of the system and it is independent of the path by which this state has been reached.
The equation of the enthalpy of system is given as:
H = U + PV
Here the enthalpy is represented by the letter 'H'. It is a very important quantity as it gives how much heat or energy is present in the system.
Thus the correct option is A.
To know more about enthalpy, visit;
https://brainly.com/question/1657608
#SPJ7
When Fe2O3(s) reacts with H2(g) to form Fe(s) and H2O(g), 98.8 kJ of energy are absorbed for each mole of Fe2O3(s) that reacts. Write a balanced thermochemical equation for the reaction with an energy term in kJ as part of the equation. Note that the answer box for the energy term is case sensitive. Use the SMALLEST INTEGER coefficients possible and put the energy term in the last box on the appropriate side of the equation. If a box is not needed, leave it blank.
Answer:
Explanation:
Fe₂O₃(s) + 3H₂(g) = 2Fe (s) + 3H₂O - 98.8 kJ .
one mole of ferric oxide reacts with 3 mole of hydrogen to give 2 mole of iron and 3 mole of water . 98.8 kJ of heat is absorbed .
A solution is formed by mixing 15.2 g KOH into
1.200 kg water. Use the periodic table to find the
moles of solute.
Answer:
There are approximately [tex]0.271\; \rm mol[/tex] of formula units in that [tex]\rm 15.2\; g[/tex] of [tex]\rm KOH[/tex] (the solute of this solution.)
Explanation:
A solution includes two substances: the solute and the solvent. Note the solution here contains significantly more water than [tex]\rm KOH[/tex]. Hence, assume that water is the solvent (as it is in many other solutions.)
The (molar) formula mass of [tex]\rm KOH[/tex] is necessary for finding the number of moles of
One [tex]\rm K[/tex] atom, One [tex]\rm O[/tex] atom, andOne [tex]\rm H[/tex] atom.The formula mass of [tex]\rm KOH[/tex] will thus be the sum of:
The mass of one mole of [tex]\rm K[/tex] atoms, The mass of one mole of [tex]\rm O[/tex] atoms, andThe mass of one mole of [tex]\rm H[/tex] atoms.On the other hand, the mass (in grams) of one mole of atoms of an element is (numerically) the same as its relative atomic mass. The relative atomic mass data can be found on most modern periodic tables.
Relative atomic mass data from a modern periodic table:
[tex]\rm K[/tex]: [tex]39.098[/tex].[tex]\rm O[/tex]: [tex]15.999[/tex].[tex]\rm H[/tex]: [tex]1.008[/tex].For example, the relative atomic mass of [tex]\rm K[/tex] (potassium, atomic number [tex]19[/tex]) is [tex]39.098[/tex] (3 sig. fig.) Hence, the mass of one mole of
The formula mass of [tex]\rm KOH[/tex] is the sum of these three masses:
[tex]\begin{aligned}& M(\mathrm{KOH}) \\ &\approx 39.098 + 15.999 + 1.008 \\ &= 56.105\; \rm g \cdot mol^{-1}\end{aligned}[/tex].
The number of moles of [tex]\rm KOH[/tex] formula units in this [tex]15.2\; \rm g[/tex] sample would be:
[tex]\begin{aligned}n &= \frac{m(\mathrm{KOH})}{M(\mathrm{KOH})} \\ &\approx \frac{15.2\; \rm g}{56.105\; \rm g \cdot mol^{-1}} \approx 0.271\; \rm mol \end{aligned}[/tex].
Answer:
the answer is 0.271
Explanation:
got the right answer on edg 2020
Substituents on an aromatic ring can have several effects on electrophilic aromatic substitution reactions. Substituents can activate or deactivate the ring to substitution, donate or withdraw electrons inductively, donate or withdraw electrons through resonance, and direct substitution either to the ortho/para or to the meta positions.
1. From the following list, select the substituents that have the indicated property. The substituents are written as -XY, where X is the atom directly bound to the aromatic ring.
a. Activation of the ring towards substitution
i. -CF3
ii. -NO2
iii. -OCOCH3
iv. -NH2
Answer:
iv. -NH₂
Explanation:
The amine group is an activating substituent and provides an ortho-para orientation.
The free electrons in the nitrogen atom provide stabilization by resonance in the sigma complex if the attack by the electrophilic reactant occurs in the positions ortho or para with regards to the nitrogen atom.
Calculate the pH of 0.65 M H2SO4 (sulfuric acid) solution? (Ka2: 1.1x10-2)
Answer:
pH = 0.18
Explanation:
The sulfuric acid (H₂SO₄) has the following reactions in aqueous medium:
H₂SO₄ → HSO₄⁻ + H⁺
HSO₄⁻ ⇄ SO₄²⁻ + H⁺ Ka = 1.1x10⁻²
Where Ka is defined as Ka = [SO₄²⁻] [H⁺] / [HSO₄⁻] = 1.1x10⁻²
Based in the first reaction, [H⁺] = 0.65M and [HSO₄⁻] = 0.65M
In the second reaction, the two species are in equilibrium, thus, concentrations will be:
[H⁺] = 0.65M + X
[HSO₄⁻] = 0.65M - X
[SO₄²⁻] = X
Replacing in Ka formula:
1.1x10⁻² = [X] [0.65 + X] / [0.65M - X]
7.15x10⁻³ - 1.1x10⁻²X = 0.65X + X²
0 = X² + 0.661X - 7.15x10⁻³
Solving for X:
X = -0.67M → False solution. There is no negative concentrations.
X = 0.01065M → Right answer.
Thus [H⁺] = 0.65M + 0.01065M = 0.66065M
As pH = -log [H⁺];
pH = -log 0.66065M = 0.18
Which is the correct oxidation half reaction for the following reaction K2Cr2O7 + H2O + S à SO2 + KOH + Cr2O3
Answer:
[tex]S^0 \rightarrow S^{+4}+4e^-[/tex]
Explanation:
Hello,
In this case, for the reaction:
[tex]K_2Cr_2O_7 + H_2O + S \rightarrow SO_2 + KOH + Cr_2O_3[/tex]
We first must assign the oxidation state of each element:
[tex]K^{+1}_2Cr^{+6}_2O_7^{+2} + H_2^{+1}O^{-2} + S^0 \rightarrow S^{+4}O_2^{-2} + K^{+1}O^{-2}H^{+1} + Cr_2^{+3}O_3^{-2}[/tex]
Thus, we should remember that the oxidation half-reaction applies for the element undergoing an increase in its oxidation state, such case is sulfur, for which passes from 0 to +4 as shown below:
[tex]S^0 \rightarrow S^{+4}+4e^-[/tex]
It means, that four electrons were lost due to the effect of the strong oxidizing agent, potassium dichromate.
Best regards.
A student requires 2.00 L of 0.100 M NH4NO3 from a 1.75 M NH4NO3 stock solution. What is the correct way to get the solution?
Use M subscript i V subscript 1 equals M subscript f V subscript f..
Measure 114 mL of the 1.75 M solution, and dilute it to 1.00 L.
Measure 114 mL of the 1.75 M solution, and dilute it to 2.00 L.
Measure 8.75 mL of the 1.75 M solution, and dilute it to 2.00 L.
Measure 8.75 mL of the 0.100 M solution, and dilute it to 2.00 L.
Answer:
I believe its B
Explanation:
Answer:
B. Measure 114 mL of the 1.75 M solution, and dilute it to 2.00 L.
What role does wind play in mechanical weathering?
Which event most likely occurs at point k?
Answer:The answer is C melting.
Explanation:
Answer:melting
Explanation:
(14.1.50) 0.03 mol of helium are enclosed in a cylinder with a piston which maintains a constant pressure in the helium. Initially the helium is immersed in thermal bath with at 250K. Suddenly, the helium is removed from this thermal bath and plunged into a thermal bath at temperature 350K. Determine (a) the increase in the entropy of the helium. (Hint the entropy change for the helium is the same as if it had been taken through this temperature change by a reversible process.) (b) the increase in entropy of the universe. (Answer: 0.032 J/K)
Answer:
a) 0.210 j /k
b) 0.032 j/k
Explanation:
Find the attachment for solution
Write and balance the following equation: silver phosphate reacts with ammonium sulfide. The coefficient of the precipitate is
Answer:
Answer if yourself Kempner student.
Explanation:
xD
How many ng are there 5.27x10-13 kg
Answer:
This involves metric conversion and one can easily use dimensional analysis, assuming you know the conversion factors.
1 ng = 10-9 g, or put another way 109 ng = 1 g
1 kg = 103 g
5.27x10-13 kg x 1 g/1x10-3 kg x 1x109 ng/g = 5.27x10-1 ng = 0.527 ng
Looking at the individual steps and following the units, we have...
5.27x10-13 kg x 1 g/1x10-3 g = 5.27x10-10 g (kg cancel leaving g)
5.27x10-10 g x 1x109 ng/g = 5.27x10-1 ng = 0.527 ng (g cancel leaving ng)
Which of the following reactions best represents the reaction between H3PO4
and water?
A) H3PO4 + H2O ⇌ H2PO4
- + H2O
B) H3PO4 + H2O ⇌ H2PO4
- + H3O+
C) H3PO4 + 3 H2O → PO4 3- + 3 H2O
D) H3PO4 + 3 H2O → PO4 3- + 3 H3O+
Answer:
Option B, [tex]H3PO4 + H2O <==> H3O^+ + H2PO4^-[/tex]
Explanation:
In this reaction, a weak acid is reacting with water. Thus, water is this case will act as a proton acceptor or a base as well as an acid. Hence water will be amphiprotic for this chemical process and can donate as well accept as a proton. Now when weak acid such as phosphoric acid loses a hydrogen ion it forms a weak conjugate base ie. H2PO4^-. Water being a weak base shall accept the proton and forms hydronium ion i.e H3O^+
The dihydrogen phosphate ion reacts with water:
H2PO4^- + H2O <----> HPO4^2- + H3O^+
After some time a proton is again transferred to the H2O molecule to produce phosphate ion
HPO4^2- + H2O <----> H3O^+ + PO4^3-
How do limiting factors affect organisms in a community
Answer: Both biotic and abiotic limiting factors can limit organisms' ability to live or reproduce.
Explanation:
penn foster
Which of the two compounds, H_2NNH_2 and HNNH, has the strongest nitrogen-nitrogen bond, and which has the shorter nitrogen-nitrogen bond.
a. H_2NNH_2 has the strongest nitrogen-nitrogen bond and HNNH has the shorter nitrogen-nitrogen bond.
b. H_2NNH_2 has both the strongest nitrogen-nitrogen bond and the shorter nitrogen-nitrogen bond.
c. HNNH has the strongest nitrogen-nitrogen bond and H_2NNH_2 has the shorter nitrogen-nitrogen bond.
d. HNNH has both the strongest nitrogen-nitrogen bond and the shorter nitrogen-nitrogen bond.
Answer:
d. HNNH has both the strongest nitrogen-nitrogen bond and the shorter nitrogen-nitrogen bond.
Explanation:
The Lewis structure of HNNH comprises of a double bound between the two nitrogen atoms, therefore each nitrogen still carrying a lone pair of electron and a single bond between each nitrogen to it respective hydrogen.
Also for H_2NNH_2; there exists a single nitrogen to nitrogen bond because hydrogen is sharing two bonds already with the nitrogen; the nitrogen also possess a lone pair of electron and the last bond is a single bond between the nitrogen to nitrogen atom ( therefore obeying the octet rule).
The bond strength and bond angle is stronger and shorter in double bonds than single bonds, thus HNNH has both the strongest nitrogen-nitrogen bond and the shorter nitrogen-nitrogen bond.
Answer:
d. HNNH has both the strongest nitrogen-nitrogen bond and the shorter nitrogen-nitrogen bond.
Explanation:
The Lewis structure of HNNH comprises of a double bound between the two nitrogen atoms, therefore each nitrogen still carrying a lone pair of electron and a single bond between each nitrogen to it respective hydrogen.
Also for H_2NNH_2; there exists a single nitrogen to nitrogen bond because hydrogen is sharing two bonds already with the nitrogen; the nitrogen also possess a lone pair of electron and the last bond is a single bond between the nitrogen to nitrogen atom ( therefore obeying the octet rule).
The bond strength and bond angle is stronger and shorter in double bonds than single bonds, thus HNNH has both the strongest nitrogen-nitrogen bond and the shorter nitrogen-nitrogen bond.
Please help me
*science *
Answer: Solar energy
Explanation:
Solar energy because it has more clear and sunny skys
Hello there!
An alternative energy source that is best for Coalville is wind energy.
The first two options, solar power and hydroelectric power aren't very good options since solar power requires lots of sun and they only receive 70 days of sun. While, hydroelectric power isn't a good choice either since it is a small stream meaning very little water and not big enough to build a dam on.
Therefore, wind energy is the best idea since high wind speeds are good to spin the wind turbines. The faster the wind the more energy is produced. Coalville has an average windspeed of 20 mph which is quite fast so that will the best option.
A box sits on a table. An arrow labeled F subscript N points up. An arrow labeled F subscript g points down. An arrow labeled F subscript P points right. An arrow labeled A points left. The box is at rest on the table. Which force is represented by vector A? sliding friction rolling friction static friction fluid friction
Answer:
Static Friction
Explanation:
Answer:
The answer is Static Friction
Explanation:
what would be considered more dilute? sweet tea or unsweetened tea
Answer:
Unsweetened tea
Explanation:
A concentrated solution is a solution that has more of the solute in it than the solvent (water).
A diluted solution is a solution that has more solvent (water) than the solute.
From the above we can say that the sweet tea contains more of the tea than water i.e it is concentrated hence, the taste is sweet. On the other hand, we can say that the unsweetened tea contains more water than the tea i.e it is diluted hence, the unsweetened taste.
Which type of rock is Most likely to form because of high heat and pressure
Answer:
Metamorphic rock
Explanation:
Answer:
metamorphic
Explanation:
just took the test
Which statement best describes the formation of a solution?
A large amount of solute is dissolved in a smaller amount of solvent.
A small amount of solute is dissolved in a larger amount of solvent.
A small amount of solvent is dissolved in a larger amount of solute.
A large amount of solvent is dissolved in a larger amount of solute.
Answer:
A small amount of solute dissolved in a larger amount of solvent.
Take this analogy to help you understand, if you were to put a teaspoon of sugar in a liter of water it would dissolve, but if you put a sack of sugar in it it would not dissolve! The solute is what is being dissolved and the solvent is what dissolves the solute, so that eliminates some of the options.
What is the unit volume in mL
Answer:
4.35 mL
Explanation:
The water line falls halfway inbetween the 4.4 and 4.3 mark.
The number halfway between 4.3 and 4.4 is 4.35.
Therefore, the volume of the liquid in the graduated cylinder is 4.35 mL.
Metal plating is done by passing a current through a metal solution. For example, an item can become gold plated by attaching the item to a power source and submerging it into an Au³⁺ solution. The item itself serves as the cathode, at which the Au³⁺ ions are reduced to Au(s). A piece of solid gold is used as the anode and is also connected to the power source, thus completing the circuit. What mass of gold is produced when 15.1 A of current are passed through a gold solution for 31.0 min?
Answer:
172 g
Explanation:
Let's consider the reduction of Au³⁺ to Au.
Au³⁺(aq) + 3 e⁻ → Au(s)
In order to find the mass of gold produced, we will use the following relations.
1 min = 60 s1 A = 1 C/sThe charge of 1 mole of electrons is 96,468 C (Faraday's constant).1 mole of Au is deposited when 3 moles of electrons circulate.The molar mass of Au is 196.97 g/mol.The mass of gold produced when 15.1 A of current are passed through a gold solution for 31.0 min is:
[tex]31.0min \times \frac{60s}{1min} \times \frac{15.1C}{s} \times \frac{1mole^{-} }{96,468C} \times \frac{3molAu}{1mole^{-} } \times \frac{196.97gAu}{1molAu} = 172 gAu[/tex]
Can you please help me?
Answer:
60 moles of NaF
Explanation:
The balanced equation for the reaction is given below:
Al(NO3)3 + 3NaF —> 3NaNO3 + AlF3
From the balanced equation above,
3 moles of NaF reacted to produce 1 mole of AlF3.
Therefore, Xmol of NaF will react to produce 20 moles of AlF3 i.e
Xmol of NaF = 3 x 20
Xmol of NaF = 60 moles
Therefore, 60 moles of NaF are required to produce 20 moles of AlF3.
Which represents the self-ionization of water at 25°C?
O A. H2O + H20 = 2H2 + O2
OB.
H2O + H2O = H2O2 + H2
O C.
H2O + H2O = 4H+ + 202-
OD.
H2O + H20 = H30+ + OH-
Answer:
D
Explanation:
H2O + H20 = H30+ + OH-
Given the potential energy diagram representing a reaction below, which numbered interval represents the heat of reaction?
Answer:
2
Explanation:
Heat of reaction is usually the difference of heat of products and heat of reactions. The difference here is represented by the letter 2.
The potential energy diagram has been representing the heat of reaction at interval 2.
The heat of reaction has been defined as the difference in the heat of product and reactant. The potential energy has been the stored energy of the compounds.
Potential Energy Diagram:In the given potential energy curve, the heat of reaction has been found to be the increase in potential energy. There has been an increment in the energy at interval 2.
Thus, the potential energy diagram has been representing the heat of reaction at interval 2.
For more information about potential energy, refer to the link:
https://brainly.com/question/21288807
Identify the outer electron configurations for the (a) alkali metals, (b) alkaline earth metals, (c) halogens, (d) noble gases. (a) Alkali metal: ns,1 ns2, ns2np1, ns2np2, ns2np3, ns2np4, ns2np5, ns2np6. (b) Alkaline earth metals: ns1, ns2, ns2np1, ns2np2, ns2np3, ns2np4, ns2np5, ns2np6. (c) Halogens: ns1, ns2, ns2np1, ns2np2, ns2np3, ns2np4, ns2np5, ns2np6. (d) Noble gases: ns1, ns2, ns2np1, ns2np2, ns2np3, ns2np4, ns2np5, ns2np6.
Answer:
Explanation:
Alkali metals ------ outermost orbit containing one electron
ns²np¹
Alkaline metals -------- outermost orbit containing two electron
ns²np²
halogens --------------- outermost orbit containing seven electron
ns²np⁵
noble gas --------------- outermost orbit containing eight electron
ns²np⁶.
What Science and Math jobs are expected to have much faster than average growth? Check all that apply.
1.Natural Sciences Managers
2.Zoologists and Wildlife Biologists
3.Medical Scientists
4.Food Science Technicians
5 .Biochemists and Biophysicists
6.Mathematical Technicians
Answer:
3.Medical Scientists
5.Biochemists and Biophysicists
Explanation:
Science and Math jobs are expected to have much faster than average growth. Medical Scientists and Biochemists and Biophysicists is correct.
What is biochemist ?Scientists with biochemistry training are known as biochemists. They research the chemistry of living things, including chemical reactions and changes. Biochemists research DNA, proteins, and cellular components. A portmanteau of "biological chemist" is the term "biochemist."
The study of biochemistry focuses on the chemistry of living things. It is a lab-based science that combines chemistry and biology.
Biochemists investigate the makeup, chemistry, and chemical processes of the compounds found in living things in order to understand how they work and how to manipulate them.
Thus, option 3 and 5 both are correct.
To learn more about biochemist follow the link;
https://brainly.com/question/18524947
#SPJ5
3. Consider the transport of galactose across a semi-permeable membrane from the extracellular space ([galactose] = 2 mM) to the cytosol ([galactose] = 10 mM) under biochemically standard conditions. (R = 0.08206 L atm/mol K = 8.314 J/mol K) (15 pts.) If ATP hydrolysis liberates 30.5 kJ/mol at standard conditions, approximately how many grams of ATP (507.2 g/mol) would be required to transport 260 g of galactose from the extracellular space to the cytosol?
Answer:
15.63.
Explanation:
So, from the question, we are given the following parameters or data or information for solving this particular Question and they are;
(1). "semi-permeable membrane from the extracellular space ([galactose] = 2 mM) to the cytosol ([galactose] = 10 mM) under biochemically standard conditions. (R = 0.08206 L atm/mol K = 8.314 J/mol K) (15 pts.) "
(2). "If ATP hydrolysis liberates 30.5 kJ/mol at standard conditions".
(3). " (507.2 g/mol) would be required to transport 260 g of galactose from the extracellular space to the cytosol"
Step one: determine the difference to transport of galactose from extracellular space to cytosol.
This can be done by using the formula below:
Ratio = intracellular/ extracellular.
=> 10/2 = 5 mM.
Step two: so, from statement (2) and (3), the if 507.2 g/mol ATP = 30.5 kJ/mol, then 260 g/mol = ???
Therefore, 260 × 30.5 / 507.2 = 15.63 is the energy required.
what is the full form of DNA
Answer:
Deoxyribose Nucleic Acid
Answer:
The Full form of DNA is Deoxyribonucleic acid. Deoxy means lack of an oxygen atom, Ribo means ribose sugar, Nucleic is found in the nucleus of cell and Acid contains negatively charged phosphate ion which is acidic.