Answer:
ecosystem; hurricanes and tornadoes; catastrophic events.; Fooding; moving water; soil
Explanation:
After using the word bank to fill in the blanks in the passage, the passage reads;
"The organisms and environments that make up a community called an ecosystem are constantly changing. Sudden and violent events, such as hurricanes and tornadoes that often cause these changes are called catastrophic events. Fooding results when rainfall exceeds the holding capacity of a drainage system. The energy of the fast-moving water and the layers of sediment carried by it can uproot or bury plants, reshape the soil and destroy roads and buildings."
A granite monument has a volume of 25,365.4 cm. The density of granite is 2.7 g/cms. Use this information to calculate the mass of the monument to the nearest tenth. The mass of the granite monument is
Answer:
m = 68,486,6 g is the answer.
Explanation:
To calculate mass you use formula:
m= V*r
To avoid remembering this formula you can see the type of unit on each given variable. We can see that we have g/cm^3 and cm^3. If we multiply them, we negate cm^3 and cm^3 and we are left with g which is unit for mass.
Hope I helped! ☺
Plz answer quick this is science
An evacuated long tube contains a coin and a feather. If both objects fall together starting from the top of the tube, it is expected that: If this experiment is repeated at a place 2000 kilometers above the sea-level, the acceleration due to gravity gexp is expected to :
Answer:
gexp = 3.65 m/s²
Explanation:
The value of acceleration due to gravity changes with the altitude. The following formula gives the value of acceleration due to gravity at some altitude from the sea level:
gexp = g(1 - 2h/Re)
where,
gexp = expected value of g at altitude = ?
g = acceleration due to gravity at sea level = 9.8 m/s²
h = altitude = 2000 km = 2 x 10⁶ m
Re = Radius of Earth = 6.37 x 10⁶ m
Therefore,
gexp = (9.8 m/s²)(1 - 2*2 x 10⁶ m/6.37 x 10⁶ m)
gexp = 3.65 m/s²
A whale swims at a constant speed of 8 m/s for 17 s. What distance did the whale travel in km?
Answer:
0.136 kmExplanation:
whale speed = 8 m/s for 17 sec.
find distance traveled in km
distance = velocity x time
= 8 m/sec. x 17 sec.
= 136 meters x 1 km
1000 meters
= 0.136 km
A construction worker drops a brick off a high scaffold. If the brick lands 5.0 s later, how fast was the brick travelling the instant before hitting the ground?
Answer:
The brick was traveling at 49 m/s the instant before hitting the ground.
Explanation:
When an object is dropped from rest in a free-falling motion, it falls with a constant acceleration called the acceleration of gravity, which value is [tex]g = 9.8 m/s^2[/tex].
The final velocity of a free-falling object after a time t is given by:
[tex]vf=g.t[/tex]
The distance traveled by a dropped object is:
[tex]\displaystyle y=\frac{gt^2}{2}[/tex]
The brick takes 5 seconds to land from the high scaffold. The speed at which it lands is:
[tex]vf=9.8\cdot 5[/tex]
vf=49 m/s
The brick was traveling at 49 m/s the instant before hitting the ground.
A car accelerates from 2 m/s to 5 m/s in 1.8 seconds. What is the acceleration of the car?
Answer:
5-2 / 1.8 = 1.66m/s
Explanation:
acceleration = vf-vi / t
vf= 5m/s
vi= 2m/s
t= 1.8 s
Modern isotopic counting is done by ___.
A. Microscope
B. Accelerator mass spectrometer
C. Balance
D. Scanning electron microscope
Accelerator mass spectrometers are used in modern isotope counting.
So, option B. is correct.
Define isotopes.Isotopes are two or even more kinds of atoms with the same atomic masses but differing nucleon numbers leading to varying numbers of neutrons within their nuclei.
Accelerator mass spectrometry would be a type of mass spectrometry in which ions are accelerated to extremely high kinetic energy before being analyzed for mass.
Accelerator mass spectrometers are used in modern isotope counting.
Option B. is correct.
Find out more information about isotope here:
https://brainly.com/question/11904263?referrer=searchResults
why do some objects fall faster than others?
Answer:
Weight and Mass !!!!!!
Explanation:
Galileo discovered that objects that are more dense, or have more mass, fall at a faster rate than less dense objects, due to this air resistance. A feather and brick dropped together. Air resistance causes the feather to fall more slowly.
A baseball traveling at a velocity of 35 m/s has a mass of
0.15 kg. What is the kinetic energy of the baseball?
Answer:
35 m/s = v KE= 1/2 m x v^2. 89= m x 1224
89 J = KE 89 = 1/2 (m) x (35)^2. m = 0.15 kg.
a soccer player kicks a ball with an initial velocity of 10 meters per second at an angle of 30 degrees
Answer:
Did you make a diagram?
Make your hypotenuse 10 and the base angle 30°
find the length of the adjacent side using
10cos30°
Explanation:
Answer:
A soccer player kicks a ball with an initial velocity of 10.0 meters per second at an angle of 30.0° above the horizontal. The magnitude of the horizontal component ofthe ball's initial velocity is which of the following?
9.8 m/s
0.50 m/s
15 m/s
7.4 m/s
Explanation:
Define kinetic energy and thermal energy. Describe what happens to each as the temperature of a substances increases.
Answer:
All matter is made up of particles that are constantly moving. The motion of the particles results in kinetic energy. The part of total internal energy that can be transferred is thermal energy. As temperature increases, the particles in a substance move faster and have greater kinetic and thermal energy.
Explanation:
Which of the following would be considered a lever?
a screw cap
a seesaw
an axe
a windmill
Answer:
A seesaw
Explanation:
Answer:
a seesaw
Explanation:
I need help guyssss plssss
Answer:
Cd(NO3)2 + Na2S --> CdS + 2 NaNO3
Explanation:
A bowling ball is rolling down the lane at a constant velocity of 7.5 m/s. If the bowling ball travels 18 m down the entire lane, how long does it take for the ball to reach the end?
Answer:
The answer is 2.4 sExplanation:
To find how long it took the ball to reach the end we use the formula
[tex]t= \frac{d}{v} \\ [/tex]
where
t is the time
d is the distance
v is the velocity
From the question
d = 18 m
v = 7.5 m/s
We have
[tex]t = \frac{18}{7.5} \\ [/tex]
We have the final answer as
2.4 sHope this helps you
a kid throws a ball from a tower 45 meters tall how fast is the ball going when it hits the ground?
Answer:
29.69 m/s
Explanation:
From the question given above, the following data were obtained:
Height (h) = 45 m
Velocity (v) =...?
Next, we shall determine the time taken for the ball to get to the ground. This can be obtained as follow:
Height (h) = 45 m
Acceleration due to gravity (g) = 9.8 m/s²
Time (t) =?
h = ½gt²
45 = ½ × 9.8 × t²
45 = 4.9 × t²
Divide both side by 4.9
t² = 45/4.9
Take the square root of both side
t = √(45/4.9)
t = 3.03 s
Finally, we shall determine the velocity with which the ball hits the ground. This is illustrated below:
Initial velocity (u) = 0 m/s
Acceleration due to gravity (g) = 9.8 m/s²
Time (t) = 3.03 s
Final velocity (v) =.?
v = u + gt
v = 0 + (9.8 × 3.03)
v = 0 + 29.694
v = 29.694 ≈ 29.69 m/s
Therefore, the ball hits the ground with a velocity of 29.69 m/s.
To determine the amplitude of a wave you need to know the
How long will it take to travel 84 miles if
you are traveling at a constant 70 miles
per hour?
quick omg ‼️ please
Answer:
The answer is 1.2 hoursExplanation:
To find the time taken given the velocity and distance covered we use the formula
[tex]t = \frac{d}{v} \\ [/tex]
where
t is the time
d is the distance covered
v is the velocity
From the question
d = 84 mi
v = 70 mi/h
We have
[tex]d = \frac{84}{70} = \frac{6}{5} \\ [/tex]
We have the final answer as
1.2 hoursHope this helps you
from problem 2,suppose another boy, boy C pulls the heavy cabinet with 5N of force in the same direction with boy A
1. what will be the net foece on the cabinet?
2. will the cabinet move?
3. in what direction will the cabinet move?
Answer:
Searching in Google I found that in problem 2 were two boys pulling the heavy cabinet, a Boy A pulling in the left direction with 10 N of force, and a boy B pulling in the right direction with 5 N.
1. F = 10 N
2. Yes, it will move.
3. It will move to the left direction of the cabinet (same direction as the boys A and C).
Explanation:
Searching in Google I found that in problem 2 were two boys pulling the heavy cabinet, a Boy A pulling in the left direction with 10 N of force, and a boy B pulling in the right direction with 5 N.
1. Hence, if another boy (C) pull in the same direction as the boy A with 5 N of force, we have:
[tex] \Sigma F = F_{A} + F_{C} - F_{B} [/tex]
[tex] \Sigma F = 10 N + 5 N - 5 N = 10 N [/tex]
The net force on the cabinet is 10 N.
2. Yes, the cabinet will move. From point 1 we can deduce that the cabinet will move since the net force on the cabinet is different from zero (10 N).
3. The direction of the motion is the same as the Boys A and C, that is to say, to the left of the cabinet.
I hope it helps you!
The net force acting on an object, is the vector sum of all the forces acting on it
The correct values for the forces acting on the cabinet are;
1. The net force on the cabinet is 10 N
2. Yes, the cabinet will move
3. The cabinet will move in the direction of boy A and boy C
The reason the above values are correct are as follows:
Question: The possible missing part of the question is; In problem 2 boy A is pulling a heavy cabinet with [tex]F_A[/tex] = 10 N force, and boy B is pulling the same cabinet at the same time and in opposite direction with a force of [tex]F_B[/tex] = 5 N
The known parameter:
The force with which boy C pulls the heavy cabinet = 5 N
The direction in which boy C pulls the cabinet = The same direction as boy A
Question 1. The net force on the cabinet, [tex]F_{NET}[/tex] is given as follows;
Taking the direction of the force of boy A as the positive direction, we have;
[tex]\overset \longrightarrow {F_A}[/tex] = 10 N
[tex]\overset \longrightarrow {F_B}[/tex] = - 5 N
[tex]\overset \longrightarrow {F_C}[/tex] = 5 N
[tex]\overset \longrightarrow {F_{NET}}[/tex] = [tex]\overset \longrightarrow {F_A}[/tex] + [tex]\overset \longrightarrow {F_B}[/tex] + [tex]\overset \longrightarrow {F_C}[/tex]
[tex]\overset \longrightarrow {F_{NET}}[/tex] = 10 N + (-5 N) + 5 N = 10 N
The net force on the cabinet, [tex]\overset \longrightarrow {F_{NET}}[/tex] = 10 N
Question 2. Yes: Given that there is a net force acting on the cabinet, according to Newton's first law of motion, in the absence of friction force, the cabinet will move in the direction of the net force of 10 Newton
Question 3. The cabinet will move in the direction of the net fore
The direction of the net force is the direction boy A and boy C are pulling the cabinet
Therefore, the cabinet will move in the direction boy A and boy C are pulling the heavy cabinet
Learn more about addition of forces here:
https://brainly.com/question/2080520
I need help for this displacement question.
Answer:
577656.0
Explanation:
Determine the launch speed of a horizontally launched projectile that lands 26.3 meters from the base of a 19.3-meter high cliff and takes 5 seconds to land.
Answer:
The launch speed is approximately 13.28 m/s
Explanation:
The given parameters are;
The distance from the base of the cliff the projectile lands = 26.3 meters
The height of the cliff, s = 19.3 meters
The time it takes the projectile to land = 5 seconds
The direction of the projectile = Horizontal
The vertical motion of the projectile is given as follows;
19.3 = 1/2 × g × t² = 1/2 × 9.81 × t²
t = √(2 × 19.3/9.81) ≈ 1.98 seconds
Therefore, the time it takes to land ≈ 1.98 seconds
The launch (horizontal) speed = (The horizontal distance)/(Horizontal time)
The launch (horizontal) speed = 26.3/1.98 ≈ 13.28 m/s.
The launch speed of a horizontally launched projectile is equal to 13.22 m/s.
Given the following data:
Time = 5 seconds.Height = 19.3 metersHorizontal distance = 26.3 meters.To determine the launch speed of a horizontally launched projectile:
First of all, we would calculate the time it took the projectile to land at the base of the cliff by using the maximum height formula:
[tex]H = \frac{1}{2} gt^2[/tex]
Making t the subject of formula, we have:
[tex]t=\sqrt{\frac{2H}{g} }[/tex]
Substituting the given parameters into the formula, we have;
[tex]t=\sqrt{\frac{2\times 19.3}{9.8} }\\\\t=\sqrt{\frac{38.6}{9.8} }\\\\t=\sqrt{3.94}[/tex]
Time, t = 1.99 seconds
Next, we would determine the launch speed by using the formula:
[tex]Horizontal\;speed = \frac{horizontal\;distance}{time} \\\\Horizontal\;speed = \frac{26.3}{1.99}[/tex]
Horizontal speed = 13.22 m/s
Read more: https://brainly.com/question/17742679
Acceleration is a vector quantity. When an object is said to have a negative acceleration, does it always mean that the object is slowing down? OTrue OFalse
HElP ME PLEASSEEEE ITS URGENT!!!
Answer:
1. states
2. kinetic theory
3.particles cqlled atoms
4.motion
5.collide
thats all I remember
what are three properties of magnets
If you push on an object with 10 N to the right and your friend pushes with 20 N to the left, what direction will the object move?
Answer:
The answer is left
Explanation:
because 20N is greater Then 10N
A piece of wood is measured to have 2 cm x 5 cm x 3 cm of volume. Its mass is 20.0 g. What is its density?
Answer:
[tex]\boxed {\tt \frac{2}{3} \ or \ 0.666666667 \ g/cm^3}[/tex]
Explanation:
Density can be found by dividing the mass by the volume.
[tex]d=\frac{m}{v}[/tex]
The mass is 20 grams.
We have to find the volume.
To find the volume, multiply the length by the width by the height. V= l*w*h l= 2 cm, w= 5 cm, h= 3 cmV= 2 cm * 5 cm * 3 cm = 30 cm³[tex]m= 20 \ g\\v= 30 \ cm^3[/tex]
Substitute the values into the formula.
[tex]d=\frac{20 \ g}{30 \ cm^3}[/tex]
Divide.
[tex]d=\frac{2}{3} \ g/cm^3[/tex]
[tex]d= 0.666666667 \ g/cm^3[/tex]
The density is 2/3 grams per cubic centimeter.
Which statement best describes the general movement of air masses?
A.
They move from areas of high humidity to areas of low humidity.
B.
They move from areas of high altitude to areas of low altitude.
C.
They move from areas of low temperature to areas of high temperature.
D.
They move from areas of high pressure to areas of low pressure.
Answer:
d
Explanation:
i looked it up
which one is deposition plz help
1. Your wet hair dries after a few minutes
2. The mirror gets fogged up when you breathe on it
3. Liquid glass cools and hardens
Deposition is when a gaseous state changes to solid state by escaping liquid state. So I think it is 3. Liquid glass cools and hardens
The real advantage to hydrostatic weighing is that it __________.
A.
can be done anywhere with no equipment
B.
gives one of the most accurate measurements of body fat
C.
uses calipers to measure body fat
The real advantage to hydrostatic weighing is that it gives one of the most accurate measurements of body fat.
It should be noted that the real advantage to hydrostatic weighing is that it gives one of the most accurate measurements of body fat.
What is Hydrostatic weighing,?Hydrostatic weighing can be regarded as underwater weighing which is very good and accurate ways to measure body fat.
Therefore, option B is correct.
Learn more about Hydrostatic weighing at;
https://brainly.com/question/2189911
3.2 Section Review 1. What are the units of energy and what do they mean? 2. What is work in physics and what is the relationship between work and energy? 3. How can you increase an object’s potential or kinetic energy? 4. What happens to the kinetic and potential energy of a ball as it falls toward the ground? 5. Explain what it means to say energy is conserved.
Answer:
thanks
Explanation:
23 14
2. Calculate: You can use trigonometry to find the initial horizontal and vertical components of the ball's
velocity. Take out your calculator now. Click Reset, and turn off Show velocity vector and Show velocity
components. Set Vinitial to 50.0 m/s and 8 to 60.0 degrees.
A.
To calculate vy, multiply Vinitial by the cosine of the angle: V = Viral · cos(O):
B. To calculate vy, multiply Vmisial by the sine of the angle: v, = Vinitial sin(C):
C. Turn on Show velocity components. Were you correct?
Answer:
(A). The horizontal initial velocity is 25 m/s.
(B). The vertical initial velocity is 43.3 m/s.
(C). The velocity component is
[tex]u_{x}=u\cos\theta[/tex]
[tex]u_{y}=u\sin\theta[/tex]
Explanation:
Given that,
Initial velocity = 50.0 m/s
Angle = 60°
We need to calculate the component of velocity
Using formula of component
(A). Horizontal initial velocity
[tex]\cos\theta=\dfrac{u_{x}}{u}[/tex]
Put the value in to the formula
[tex]\cos60=\dfrac{u_{x}}{50}[/tex]
[tex]u_{x}=50\times\cos60[/tex]
[tex]u_{x}=25\ m/s[/tex]
(B). Vertical initial velocity
[tex]\sin\theta=\dfrac{u_{y}}{u}[/tex]
Put the value in to the formula
[tex]\sin60=\dfrac{u_{y}}{50}[/tex]
[tex]u_{y}=50\times\sin60[/tex]
[tex]u_{y}=43.3\ m/s[/tex]
The velocity component is
[tex]u_{x}=u\cos\theta[/tex]
[tex]u_{y}=u\sin\theta[/tex]
Hence, (A). The horizontal initial velocity is 25 m/s.
(B). The vertical initial velocity is 43.3 m/s.
(C). The velocity component is
[tex]u_{x}=u\cos\theta[/tex]
[tex]u_{y}=u\sin\theta[/tex]