the multimeter functions as an ammeter

The Multimeter Functions As An Ammeter

Answers

Answer 1

Answer: What?

Explanation:


Related Questions

Do this work if someone give correct answer I make her brainliest do this worksheet please

Answers

Sry,I only know the answer of q2

Chlorine is a non metal because it is bad conductor of heat and sodium is a metal because it is good conductor of heat.

The 3 ways in which metal is different from non metal are given below:

1)metal are good conductor of heat but nonmetal are bad conductor of heat.

2)metals are malleable but non metal aren't malleable.

3)metals are generally ductile but non metal aren't ductile.

Hope it will helpyou!

Answer:

Explanation:Chlorine is a non metal because it is bad conductor of heat and sodium is a metal because it is good conductor of heat.

The 3 ways in which metal is different from non metal are given below:

1)metal are good conductor of heat but nonmetal are bad conductor of heat.

2)metals are malleable but non metal aren't malleable.

3)metals are generally ductile but non metal aren't ductile

Which phrase describes blackbody radiation?
O A. Radiation that is absorbed by an object as it warms
O B. Light given off by an object based on its temperature
O C. Radiation that explains the wave model of light
O D. Light given off by an object based on its color

Answers

Answer:

b

Explanation:

The phrase that describes blackbody radiation is the radiation that is absorbed by an object as it warms.

What is blackbody radiation?

Blackbody radiation is a radiation produced by heated objects, particularly from a blackbody.

In physics, a blackbody, approximated by a hole in a hollow black sphere, absorbs all incident electromagnetic radiation and reflects none.

Therefore, the phrase that describes blackbody radiation is the radiation that is absorbed by an object as it warms.

Learn more about blackbody radiation at: https://brainly.com/question/13934832

#SPJ2

A girl delivering newspapers covers her route by traveling 3.00 blocks west, 4.00 blocks north, and then 6.00 blocks east. What is the total distance she travels?

Answers

Answer:

13 blocks

Explanation:

The total distance the student travels is 13 blocks.

 Distance is the length of path covered during the motion of a body.

 To find distance:

 Total distance  = Number of blocks to the west + number of blocks to the north + number of blocks to the east

 Total distance  = 3blocks + 4blocks + 6blocks  = 13blocks

What is the velocity of v2 if m1=82kg v1= 25 m/s m2=60kg?

Answers

Given :

[tex]m_1 = 82 \ kg\\\\v_1 = 257 m/s\\\\m_2 = 60 kg[/tex]

Let, us assume that momentum is conserved during the process.

To Find :

The velocity [tex]v_2[/tex] .

Solution :

Applying conservation of momentum :

Initial momentum = Final momentum

[tex]m_1v_1 = m_2v_2\\\\82\times 257=60\times v_2\\\\v_2 = \dfrac{82\times 257}{60}\ m/s\\\\v_2 = 351.23\ m/s[/tex]

Hence, this is the required solution.

If the scale model works as predicted, the final product is guaranteed to be flawless.
•True
•False

Answers

Answer: true

Explanation:

If the scale model was working as it was predicted to work, then the final product is expected to be flawless. It should be a reasonable product if the scale model is working. Our answer is the option True.

b. The coefficient of friction between the tires and the road is 0.850 and the mass of the car is
1.35x10' kg. Draw the free body diagram of this situation and determine the applied force
that caused the acceleration from part a. (2 law: Fnet-ma)
Given:
u
בנו
Samt
g=9.8 m/s^2
am
(from part a)
Unknown:
Fapp = ?
Equation:
Fnet=ma
Fapp- umg=ma
Solution:

Answers

Answer:

156.26N

Explanation:

The data needed are incomplete. Let the acceleration of the body be 3.5m/s²

Other given parameters

Mass = 1.35×10^1 = 13.5kg

coefficient of friction between the tires and the road = 0.850

Acceleration due to gravity = 9.8m/s²

According to Newton's second law:

Fnet = ma

Fnet = Fapp - Ff

Fapp is the applied force

Ff is the frictional force = umg

The equation becomes:

Fapp - Ff = ma

Fapp-umg = ma

Fapp - 0.85(13.5)(9.8) = 13.5(3.5)

Fapp - 109.0125 = 47.25

Fapp = 47.25+109.0125

Fapp = 156.2625N

Hence the applied force that caused the acceleration is 156.26N

Note that the acceleration of the car was assumed. Any value of acceleration can be used for the calculation.

A man is standing on the edge of a 20.0 m high cliff. He throws a rock horizontally with an initial velocity of 10.0 m/s.
a. How long does it take to reach the ground?
b. How far does the rock land from the base of the cliff?

Answers

Answer:

a. The rock takes 2.02 seconds to hit the ground

b. The rock lands at 20,2 m from the base of the cliff

Explanation:

Horizontal motion occurs when an object is thrown horizontally with an initial speed v from a height h above the ground. When it happens, the object moves through a curved path determined by gravity until it hits the ground.

The time taken by the object to hit the ground is calculated by:

[tex]\displaystyle t=\sqrt{\frac{2h}{g}}[/tex]

The range is defined as the maximum horizontal distance traveled by the object and it can be calculated as follows:

[tex]\displaystyle d=v.t[/tex]

The man is standing on the edge of the h=20 m cliff and throws a rock with a horizontal speed of v=10 m/s.

a,

The time taken by the rock to reach the ground is:

[tex]\displaystyle t=\sqrt{\frac{2*20}{9.8}}[/tex]

[tex]\displaystyle t=\sqrt{4.0816}[/tex]

t = 2.02 s

The rock takes 2.02 seconds to hit the ground

b.

The range is calculated now:

[tex]\displaystyle d=10\cdot 2.02[/tex]

d = 20.2 m

The rock lands at 20,2 m from the base of the cliff

A light bounces off the surface of a metal cup and shines in Harold’s eyes. Which best describes what is happening to the light waves in this scenario?

absorption
interference
refraction
reflection

Answers

Answer:

Reflection

Explanation:

Reflection is the change in direction of a wavefront at an interface between two different media so that the wavefront returns into the medium from which it originated. Common examples include the reflection of light, sound, and water waves.

Answer:

d

Explanation:

A tourist stands at the top of the Grand Canyon, holding a rock, overlooking the valley below. Find the final velocity, and displacement of the rock after 4.0 seconds give the three initial conditions listed below.
a. The rock is dropped vertically from rest
b. The rock is tossed vertically upward with 8.0 m/s of speed
c. The rock is tossed vertically downward with 8.0 m/s of speed TV TV

Answers

Answer:

a. Vf = 39.24 [m/s]

b. Vf = 31.24 [m/s]

c. Vf = 47.24 [m/s].

Explanation:

To solve this problem we can use the following equation of kinematics. We have to keep in mind that the gravitational acceleration acts downwards, therefore when the rock falls towards the abyss it has the same direction of the acceleration and that is why the gravitational acceleration has a positive sign in the equation.

[tex]v_{f}=v_{o}+g*t[/tex]

where:

Vf = final velocity [m/s]

Vo = initial velocity = 0 (when the rock is dropped)

g = gravitational acceleration = 9.81 [m/s²]

t = time = 4 [s]

a.

[tex]v_{f}=0+9.81*4\\v_{f}= 39.24 [m/s][/tex]

b.

In this particular situation, the acceleration will be taken as negative because the gravity is pointing in the opposite direction of the movement of the rock.

[tex]v_{f}=8-(9.81*4)\\v_{f}=-31.24[m/s][/tex]

The negative sign in the answer tells us that the rock no longer moves up instead it does downwards when 4 seconds have passed.

c.

[tex]v_{f}=8+(9.81*4)\\v_{f}=47.24[m/s][/tex]

The vocal cords in your throat _____________.

collapse
vibrate
compress

Answers

Answer:

vibrate

Explanation:

Vocal folds vibrate when excited by aerodynamic phenomena; they are not plucked like a guitar string. Air pressure from the lungs controls the open phase. The passing air column creates a trailing “Bernoulli effect,” which controls the close phase.

hope it helps!!

If a net force of 375N is acting on a crate and there is 65N of friction
created, what is the magnitude net force the crate experiences?
375N
65N
310N
440N

Answers

Answer:

310 N

Explanation:

The net force, I assume, is an applied force that is causing motion of the crate. However, frictional force opposes this motion, so the frictional force is in the opposite direction. Overall, we can create a net force equation of this crate as

Fnet= Force applied + Force of friction

Thus,

Fnet= 375N -65N (because friction is in the opposite direction)

Then solve to get that the net force while the crate is in motion is 310N.

what is the correct answer?

Answers

Answer:

3.2

Explanation:

I remember taking this quiz and I think that one is correct

Un cuerpo se lanza hacia arriba con 50 m/s . ¿A qué altura se encuentra cuando su rapidez es 20 m/s por segunda vez? (g = 10 m/s ^ 2) .

Answers

Answer:

105 m

Explanation:

Given that the initial velocity of the body, u= 50 m/s in upward direction.

Acceleration due to gravity, g= 10 m / [tex]s ^ 2[/tex] in the downward direction.

Let h be the height of the body when the velocity of the body is 20 m/s.

As the gravitational force acting in the downward direction, so taking it negative as

a= - 10 m/[tex]s ^ 2[/tex]  in the upward direction.

By using the equation of motion [tex]v^2=u^2+2as[/tex] ...(i)

Here, u= 50 m/s

v= 20 m/s

[tex]a=- 10 m/s^2[/tex]

s=h

Putting all the values in the equation (i), we have

[tex]20^2=50^2+2(-10)h \\\\400=2500-20h \\\\h=\frac{2500-400}{20} \\\\h=105 m[/tex]

Hence, the height of the body is 105 m.

When a 54.9-g tennis ball is served, it accelerates from rest to a speed of 45.1 m/s. The impact with the racket gives the ball a constant acceleration over a distance of 35.1 cm. What is the magnitude of the net force acting on the ball

Answers

Answer:

F = 159.07 N

Explanation:

Given that,

Mass of a tennis ball, m = 54.9 g = 0.0549 kg

It accelerates from rest to a speed of 45.1 m/s.

The impact with the racket gives the ball a constant acceleration over a distance of 35.1 cm = 0.351 m

We need to find the magnitude of net force acting on the ball.

Let a be the acceleration of the ball. Using third equation of motion to find it.

[tex]v^2-u^2=2ad\\\\a=\dfrac{v^2-u^2}{2d}\\\\a=\dfrac{(45.1)^2-(0)^2}{2\times 0.351}\\\\=2897.45\ m/s^2[/tex]

Net force,

F = ma

F = 0.0549 kg × 2897.45 m/s²

= 159.07 N

Hence, the net force acting on the ball is 159.07 N.

the great pyramid of khufu (giza, egypt) is about 140m tall. How much work would be required to raise an average - sized pyramid black (2.5 tons) to this height?

Answers

Omg I just had this ? But I forgot what I put

the kinetic energy of an object of mass in moving with a velocity of 5 MS -1 is 25j what will be its kinetic energy when its velocity is doubled what will be its kinetic energy when its velocity is increased three times. please answer fast I will mark brainly​

Answers

Answer:

When the speed is doubled, K = 100 J, when the speed is tripled, K = 225 J

Explanation:

Kinetic Energy

Is the type of energy an object has due to its speed. It's proportional to the square of the speed.

The equation for the kinetic energy is:

[tex]\displaystyle K=\frac{1}{2}mv^2[/tex]

Where:

m = mass of the object

v = speed at which the object moves

The kinetic energy is expressed in Joules (J)

The object has a kinetic energy of K=25 J when moving at v=5 m/s, thus the mass can be calculated by solving for m:

[tex]\displaystyle m=\frac{2K}{v^2}[/tex]

[tex]\displaystyle m=\frac{2*25}{5^2}=2[/tex]

m = 2 Kg

If the speed is doubled, v=10 m/s, the new kinetic energy is:

[tex]\displaystyle K=\frac{1}{2}2\cdot 10^2[/tex]

K = 100 J

If the speed is tripled, v=15 m/s, the new kinetic energy is:

[tex]\displaystyle K=\frac{1}{2}2\cdot 15^2[/tex]

K = 225 J

When the speed is doubled, K = 100 J, when the speed is tripled, K = 225 J

An object has a momentum of 56.59 kg*m/s and a velocity of 5.3 m/s. What 1 point
is the mass of the object? *

Answers

Answer:

10.68 kg

Explanation:

The mass of the object can be found by using the formula

[tex]m = \frac{p}{v} \\ [/tex]

p is the momentum

v is the velocity

From the question we have

[tex]m = \frac{56.59}{5.3} \\ = 10.677358...[/tex]

We have the final answer as

10.68 kg

Hope this helps you

A car is stopped for a traffic signal. When the light turns green, the car accelerates, increasing its speed from zero to 5.27 m/s in 0.833 s. What linear impulse and average force does a 69.8 kg passenger in the car experience

Answers

Answer:

See explanation

Explanation:

From Newton's law; the rate of change of momentum is proportional to the impressed force. Hence;

F.t = mv- mu

F= force

t= time

m= mass

V= final velocity

u = initial velocity

since u = 0, mv= 0

F= MV/t

F= 69.8 × 5.27/0.833

F= 442 N

Impulse = Ft= 442 × 0.833= 368 Ns

1
Suppose you ride a bicycle around the block, returning to your starting point.
At the end of your trip, your average velocity will be ..........
Positive
Negative
Zero

Answers

Answer:

zero

Explanation:

this is the answer

A cello string is 0.695 m long, and transmits waves at 204 m/s. What frequency does it produce? (Unit = Hz)​

Answers

Answer:

ν=293.53 Hz

Explanation:

ν= speed/λ

speed = 204 m/s

λ=0.695 m

v = 204 m/s * 1/0.695m

meters cancels out

1/s = Hz

v = 204/0.695 Hz

ν=293.53 Hz

please give thanks, click heart! :)

apparently it is wrong, but my work and online calculator says otherwise... possibly round your answer? I'm not sure then...

Answer:146.75

Explanation:

How much work is it to lift a 2.0 kg sack of potatoes vertically 6.5 m?

Answers

Answer:

Therefore, the work done to lift a 20 kg sack of potatoes of potatoes vertically 6.5 m is 1, 274 J.

A man is standing on the edge of a 20.0 m high cliff. He throws a rock horizontally with an initial velocity of 10.0 m/s.
a. How long does it take to reach the ground?
b. How far does the rock land from the base of the cliff?

Answers

Answer:

a. t = 2.02 s

b. d = 20.2 m

Explanation:

Horizontal Motion

If an object is thrown horizontally from a height h with a speed v, it describes a curved path ruled exclusively by gravity until it eventually hits the ground.

The time the object takes to hit the ground can be calculated as follows:

[tex]\displaystyle t=\sqrt{\frac{2h}{g}}[/tex]

The time does not depend on the initial speed.

The range or maximum horizontal distance traveled by the object can be calculated by the equation:

[tex]\displaystyle d=v.t[/tex]

The man standing on the edge of the h=20 m cliff throws a rock with an initial horizontal speed of v=10 m/s.

a.

The time taken by the rock to reach the ground is:

[tex]\displaystyle t=\sqrt{\frac{2*20}{9.8}}[/tex]

[tex]\displaystyle t=\sqrt{4.0816}[/tex]

t = 2.02 s

b.

The range is:

[tex]\displaystyle d=10\cdot 2.02[/tex]

d = 20.2 m

Hi can you help me with this please?

An eagle , initially at rest on the ground , lifts off vertically with a constant acceleration of 25 meters per square second . How long will it take the eagle to reach an altitude of 100 meters ?​

Answers

Answer:

4s

Explanation:

My assumption would be 4s since 25 going into 100 would be 4? hope that helped..

Which of these best defend defines whethera atomic fear contains over 30-year period b day-to-day conditions with the weather see long-term conditions of the atmosphere and the average

Answers

Answer: Climate

Explanation:

The climate is the constant condition of the atmosphere of a particular condition for a period of 30 years. It consider atmosphere for relatively long periods of time.

The averages of precipitation, humidity, wind speed, temperature, rainfall are considered while knowing the status of climate of a particular region or location.  Other parameters like fog, hail storms, and frost are also measured.

Uncle Harry weighs 750 N. What is his mass in kg?

Answers

Answer:

W = MG

750 = M * 10

M = 750/10

M = 75 kg

Answer:

76.479 Kilograms Force (kgf)

Explanation:

What is the kinetic energy of a 0.5 kg puppy that is running 1.5m/s

Answers

Answer: Well the answer is KE = 5.625E-7 i just don't know the units for it...

Hope this helps....... Stay safe and have a Merry Christmas!!!!!!!!!! :D

A 6 kg block is released from rest at the top of an incline, as shown above, and slides to the bottom. The incline is 1.97 m long, is inclined at an angle of 29.4°, and the coefficient of kinetic friction between the block and the incline is 0.21.
a. Calculate the normal force the incline puts on the block.

Answers

The net force on the block acting perpendicular to the incline is

F = n - w cos(29.4°) = 0

where n is the magnitude of the normal force and w = m g is the weight of the block.

The equation itself comes from splitting up the forces acting on the block into components pointing parallel or perpendicular to the incline. The only forces acting on the block in the perpendicular direction are the normal force and the perpendicular component of the block's weight.

Solve for n :

n = m g cos(29.4°)

n = (6 kg) (9.80 m/s²) cos(29.4°)

n ≈ 51.2 N

The moon has approximately 1/6th the
gravitational pull that the earth has. If something
has a mass of 60kg on Earth, what is its mass on
the moon?

Answers

Answer:

m = 60 [kg] (mass on the moon)

Explanation:

We must remember that the mass is conserved, that is, it remains the same regardless of where it is located.

The only variation is the weight, which is different from the mass. Weight is determined by means of the product of mass by gravitational acceleration.

Therefore the mass of 60 [kg] on Earth will be the same mass on the moon.


The temperature of boiling water cannot be measured by alcohol
thermometer.​

Answers

Answer:

It can be measured by using laboratory thermometer.

A ship is travelling due east at 30 km/hr and a boy runs across the deck
in a south west direction at 10 km/hr. Find the velocity of the boy
relative to sea.

Answers

Answer:

Vr = 20 [km/h]

Explanation:

In order to solve this problem, we have to add the relative velocities. We must remember that velocity is a vector, therefore it has magnitude and direction. We will take the sea as the reference measurement level.

Let's take the direction of the ship as positive. Therefore the boy moves in the opposite direction (Negative) to the reference level (the sea).

[tex]V_{r}=30-10\\V_{r}=20 [km/h][/tex]

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