The medical director of a company looks at the medical records of all 50 employees and finds that the mean systolic blood pressure for these employees is 126.07. The value of 126.07 is symbolized by _____.

a) The resonance frequency (ω) is 2 rad/s.

b) The amplitude of the oscillations at time t = 100 can be found using the formula A = (F0/m) / √((ω^2 - ωr^2)^2 + (2ζωr)^2), where ωr is the resonance frequency. However, since ω is chosen to be precisely the resonance frequency, the denominator becomes 0 and the amplitude becomes undefined.

a) To find the resonance frequency (ω), we use the formula ω = √(k/m), where k is the spring constant and m is the mass. In this case, k = 20 and m = 5, so ω = √(20/5) = 2 rad/s.

b) The amplitude of the oscillations at time t = 100 can be found using the formula A = (F0/m) / √((ω^2 - ωr^2)^2 + (2ζωr)^2), where F0 is the amplitude of the driving force, ωr is the resonance frequency, and ζ is the damping ratio. However, in this system, it is mentioned that there is no damping (ζ = 0).

When ω is precisely equal to ωr, the denominator of the formula becomes 0. This means that the amplitude at time t = 100 is undefined, as dividing by 0 is not possible. Therefore, we cannot determine the amplitude of the oscillations at t = 100 in this scenario.

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The standard error for this problem is 0.016.

To calculate the standard error for this problem, we first need to find the proportion of non-scientists who answered yes and the proportion of scientists who answered yes.

For non-scientists:
Number who answered yes = 0.37 * 2002 = 740.74
Proportion who answered yes = 740.74 / 2002 = 0.369

For scientists:
Number who answered yes = 0.88 * 3748 = 3298.24
Proportion who answered yes = 3298.24 / 3748 = 0.879

Next, we can calculate the standard error using the formula:
SE = sqrt[(p1 * (1-p1) / n1) + (p2 * (1-p2) / n2)]

where p1 and p2 are the proportions we just calculated, and n1 and n2 are the sample sizes for each group.
SE = sqrt[(0.369 * (1-0.369) / 2002) + (0.879 * (1-0.879) / 3748)]
SE = 0.016

So, the standard error for this problem is 0.016.

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Parker should build the playhouse with a height of 1.59 meters, which is equivalent to 159 centimeters.

Parker is planning to build a playhouse for his sister. The scaled model below gives the reduced measures for width and height. The width of the playhouse is 22 centimeters and the height is 10 centimeters. Not drawn to scale The yard space is large enough to have a playhouse that has a width of 3.5 meters.

If Parker wants to keep the playhouse in proportion to the model, he should use the following cross multiplication of the proportion to find the height: `3.5/22 = 3.5x/h`.

First, the given proportions should be simplified. We will cross-multiply the given proportions:`22h = 3.5 × 10``22h = 35

`Divide both sides by 22 to solve for h:`h = 35/22

`The final answer is `h = 1.59 meters`. Parker should build the playhouse with a height of 1.59 meters, which is equivalent to 159 centimeters.

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The interval of t-values that traces the lower half of the unit circle (in the counter-clockwise direction) is π ≤ t ≤ 2π.

To find the interval of t-values that traces the lower half of the unit circle, we need to determine the range of t-values that corresponds to the angles in the lower half of the unit circle. In the unit circle, the coordinates of a point on the circle can be represented as [tex](cos(t),sin(t))[/tex] where t represents the angle in radians.

For the lower half of the unit circle, the y-coordinate [tex]sin(t)[/tex]  is negative, indicating a downward direction. Since sin(t) is negative for angles greater than π  less than or equal to 2π, the interval of t-values that traces the lower half of the unit circle is π ≤ t ≤ 2π.

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1 gallon is equivalent to 3.785 liters, so 5 liters is equivalent to approximately 1.32 gallons.

Here,

In math, two values are equivalent if they have the same numerical value or represent the same amount or quantity. For example, the fractions 1/2 and 2/4 are equivalent because they represent the same amount or quantity (one-half of a whole).

Similarly, the expressions 3x and 6x/2 are equivalent because they have the same numerical value (both simplify to 3x). In general, we can say that two values are equivalent if they can be transformed or manipulated in a mathematically valid way to obtain the same result.

In the given question,

In math, two values are equivalent if they have the same numerical value or represent the same amount or quantity. For example, the fractions 1/2 and 2/4 are equivalent because they represent the same amount

The customary unit that a measurement of 5 liters could be converted to is gallons.

1 gallon is equivalent to 3.785 liters, so 5 liters is equivalent to approximately 1.32 gallons.

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complete question;

Which customary unit could a measurement of 5 liters be converted to?

gallons

ounces

pounds

feet

The proportion of the variation in the dependent variable y that is explained by the estimated regression equation is measured by the coefficient of determination, R-squared.

In simple linear regression, the coefficient of determination (R-squared) is used to measure the proportion of the variation in the dependent variable (y) that is explained by the estimated regression equation. It is calculated as the ratio of the explained variation to the total variation. Mathematically, it can be represented as:

R-squared = Explained variation / Total variation

where, explained variation is the sum of squares of the regression (SSR) and total variation is the sum of squares of the residuals (SSE). Therefore, R-squared can also be written as:

R-squared = SSR / (SSR + SSE)

The value of R-squared ranges from 0 to 1, where a value of 1 indicates that all the variation in the dependent variable is explained by the regression equation. A higher value of R-squared indicates a better fit of the regression line to the data.

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Answer:

B bags, but there are 25 jelly beans in each bag and 60 in a tin, so the number of jelly beans, J = 25B + 60T

Step-by-step explanation:

.

The number next in the sequence is 216 and 343 respectively.

The sequence is an arrangement of numbers in a particular or successive order. It is also a set of logical steps carried out in order.

How to determine this

Here, the First term = 1 = [tex]1^{3}[/tex]

Second term = 8 = [tex]2^{3}[/tex]

Third term = 27 = [tex]3^{3}[/tex]

Fourth term = 64 = [tex]4^{3}[/tex]

Fifth term = 125 = [tex]5^{3}[/tex]

Therefore nth term = [tex]n^{3}[/tex]

To find the sixth term

6th term = [tex]6^{3}[/tex] = 6 * 6 * 6= 216

To find the seventh term ,7th term = [tex]7^{3}[/tex]= 7 * 7 * 7= 343

Therefore, the next pattern is 1,8.27,64,125,216,343

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There are a couple of ways to approach this problem, but one common method is to use multiplication.

If there are 275 houses in one village, then the total number of people living in that village is:

275 houses x 1 household / house = 275 households

Assuming that each household has an average of 3 people (which is just an estimate), then the total number of people living in one village is:

275 households x 3 people / household = 825 people

To find the total number of people living in three such villages, we can multiply the number of people in one village by 3:

825 people / village x 3 villages = 2475 people

Therefore, there are approximately 2475 people living in three villages with 275 houses each.

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The equation representing the situation is:

5 + 2.25m = 38.75

Let's break down the equation step by step.

Jazmin's ride home consists of two components: an initial cost of $5 to pick her up and a variable cost based on the distance traveled, which is $2.25 for every mile to her final destination.

To represent the total cost of the ride, we add the initial cost to the variable cost. The variable cost is calculated by multiplying the rate of $2.25 per mile by the number of miles traveled, represented by the variable 'm'.

Therefore, the equation becomes:

Total Cost = Initial Cost + Variable Cost

38.75 = 5 + 2.25m

This equation states that the total cost of Jazmin's ride home, which is $38.75, is equal to the initial cost of $5 plus the variable cost of $2.25 multiplied by the number of miles traveled, denoted by 'm'.

By solving this equation, we can find the value of 'm', which represents the number of miles to Jazmin's home.

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The value of the given integral over the curve C is ∞.

To compute the given double integral over the curve C: x^4 y^4 = 1, we need to parameterize the curve and evaluate the integral accordingly.

The curve C can be parameterized as follows:

x = t

y = t^(-1/4), where t > 0

To find the bounds of integration for t, we solve the equation x^4 y^4 = 1:

(t^4)(t^(-1))^4 = 1

t^4 * t^(-4/4) = 1

t^4 * t^(-1) = 1

t^3 = 1

t = 1

So the bounds of integration for t are from 1 to infinity.

Now we can express the given integral in terms of t:

∫∫C x^2 dx y^2 dy = ∫∫C (t^2)(t^(-1/2))^2 (dx/dt)(dy/dt) dt

Substituting the parameterization and differentiating:

= ∫∫C t^2 t^(-1/2)^2 (1)(-1/4t^(-5/4)) dt

= ∫∫C t^(2 - 1/2 - 5/2) dt

= ∫∫C t^(9/2) dt

Now we integrate with respect to t:

= ∫[1,∞] t^(9/2 + 1) / (9/2 + 1) dt

= ∫[1,∞] t^(11/2) / (11/2) dt

= (2/11) ∫[1,∞] t^(11/2) dt

= (2/11) [t^(13/2) / (13/2)] |[1,∞]

= (2/11) [(2/13) (∞^(13/2) - 1^(13/2))]

= (4/143) (∞ - 1)

= ∞

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The slope for the regression equation for predicting Y from X is 30/10, which simplifies to 3.

The slope of the regression equation for predicting Y from X can be calculated using the formula: slope = SP/SSX. In the given set of 15 pairs of X and Y scores, the values of SSX, SSY, and SP are given as 10, 40, and 30, respectively.

Therefore, the slope can be calculated as 30/10, which simplifies to 3. This means that for every one-unit increase in X, the predicted value of Y increases by 3 units.

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The inner circumference of Tom's tambourine is approximately 47.1 centimeters.
In summary, the inner circumference of Tom's tambourine is approximately 47.1 centimeters.

The circumference of a circle can be calculated using the formula C = πd, where C is the circumference and d is the diameter. Given that the diameter of the inner ring is 15 centimeters, we can calculate the inner circumference as follows:
C = π * 15
C ≈ 3.14 * 15
C ≈ 47.1 centimeter
Therefore, the inner circumference of Tom's tambourine is approximately 47.1 centimeters when using the value of 3.14 for π.

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The period of a simple pendulum is 1 s on Earth. when brought to a planet where g is one-tenth that on earth, its period becomes (d) 1/√10 s.

The period of a simple pendulum is given by the equation T = 2π√(L/g), where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity.

On Earth, the period is 1 s, which means that 1 = 2π√(L/gEarth).

When the same pendulum is taken to a planet where g is one-tenth that on Earth, the equation becomes T = 2π√(L/(g/10)).

We want to find the new period, so we can solve for T: T = 2π√(L/(g/10)) = 2π√(10L/g).

We know that the length of the pendulum does not change, so we can substitute L from the first equation into the second equation: T = 2π√(10/gEarth).

We can simplify this equation by dividing the numerator and denominator of the square root by gEarth:

T = 2π√(10/gEarth) * (√gEarth/√gEarth) = 2π√(10gEarth/gEarth^2) = 2π√(10/9.81) s.

Therefore, the answer is (d) 1/√10 s.

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The value of derivative dx/dt = 12t³ and dy/dt = 4-2t.

To find the derivatives of x and y as functions of t, we'll calculate dx/dt and dy/dt.

For x=3t⁴, the derivative dx/dt is 12t³. For y=4t-t², the derivative dy/dt is 4-2t.

Now, let's break down the steps in the explanation:
1. Identify the functions x and y: x=3t⁴, y=4t-t².
2. Calculate the derivative of x with respect to t:
  dx/dt = d(3t⁴)/dt = 3 * d(t⁴)/dt = 3 * (4t³) = 12t³.
3. Calculate the derivative of y with respect to t:
  dy/dt = d(4t-t²)/dt = d(4t)/dt - d(t²)/dt = 4 - 2t.
4. Write the final derivatives: dx/dt = 12t³, dy/dt = 4-2t.

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The series diverges when x = -2.

The given series is:

∑n=2^∞ (−2)ln(2) = ∑n=2^∞ ln(2^(-2))

We can write this as a power series in x by setting x = -2:

∑n=2^∞ ln(2^(-2))x^n

The interval of convergence of this power series can be found using the ratio test:

lim┬(n→∞)⁡|((ln(2^(-2))x^(n+1))/ln(2^(-2))x^n)| = |x|

The series will converge if |x| < 1, and diverge if |x| > 1. Therefore, the interval of convergence is -1 < x < 1.

Substituting x = -2, we get:

-1 < -2 < 1

This is not true, so the series diverges when x = -2.

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Factoring a polynomial involves expressing it as the product of two or more factors. In this case, the polynomial is 4x^2 + 12x - 6.

Here's how Joe and Hope went about factoring the polynomial:

Joe: Joe wrote down the polynomial and tried to factor it using a common factoring technique. He tried to factor out the greatest common factor (GCF), which is 4. He then tried to factor the remaining term, which is 12x - 6, using the difference of squares method. He obtained the factors (2x + 3)(2x - 3).

Hope: Hope also wrote down the polynomial and tried to factor it using a common factoring technique. She tried to factor out the GCF, which is 4. She then tried to factor the remaining term, which is 12x - 6, using the difference of squares method. She obtained the factors (2x + 6)(2x - 3).

Therefore, both Joe and Hope made some errors in their factoring attempts. Joe obtained the incorrect factors (2x + 3)(2x - 3), while Hope obtained the incorrect factors (2x + 6)(2x - 3).

To factor the polynomial completely, we need to find the correct factors. The correct factors are (x + 3)(x - 3), which can be verified by multiplying out the factors and simplifying.

Therefore, neither Joe nor Hope correctly factored the polynomial 4x^2 + 12x - 6.

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The exact length of the curve is (4/3)(21^(3/4) - 1) units

To find the length of the curve given by x = 3t^2, y = 4t^3, where 0 ≤ t ≤ 5, we need to use the formula:

L = ∫[a,b]sqrt(dx/dt)^2 + (dy/dt)^2 dt

where a and b are the values of t that correspond to the endpoints of the curve.

First, let's find dx/dt and dy/dt:

dx/dt = 6t

dy/dt = 12t^2

Then, we can compute the integrand:

sqrt(dx/dt)^2 + (dy/dt)^2 = sqrt((6t)^2 + (12t^2)^2) = sqrt(36t^2 + 144t^4)

So, the length of the curve is:

L = ∫[0,5]sqrt(36t^2 + 144t^4) dt

We can simplify this integral by factoring out 6t^2 from the square root:

L = ∫[0,5]6t^2sqrt(1 + 4t^2) dt

To evaluate this integral, we can use the substitution u = 1 + 4t^2, du/dt = 8t, dt = du/8t:

L = ∫[1,21]3/4sqrt(u) du

Now, we can use the power rule of integration to evaluate the integral:

L = (4/3)(u^(3/4))/3/4|[1,21]

L = (4/3)(21^(3/4) - 1^(3/4))

L = (4/3)(21^(3/4) - 1)

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.

Answer:

The derivative of the function is:

dy/dx = 9x(3x^2 + 5x + 1)^(1/2) + (15/2)(3x^2 + 5x + 1)^(1/2)

Step-by-step explanation:

To find the derivative of the function, we can use the chain rule and the power rule:

Let y = (3x^2 + 5x + 1)^(3/2)

Then, we have:

dy/dx = (3/2)(3x^2 + 5x + 1)^(1/2) (6x + 5)

Simplifying this expression, we get:

dy/dx = 9x(3x^2 + 5x + 1)^(1/2) + (15/2)(3x^2 + 5x + 1)^(1/2)

Therefore, the derivative of the function is:

dy/dx = 9x(3x^2 + 5x + 1)^(1/2) + (15/2)(3x^2 + 5x + 1)^(1/2)

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The one-sided (right side) confidence interval expression for an 85% confidence interval for the population mean is:

[tex]x + 1.04σ/√n < μ\\[/tex]

For a one-sided (right side) confidence interval for the mean of a normal population, the general expression is:

[tex]x + zασ/√n < μ\\[/tex]

where x is the sample mean, zα is the z-score for the desired level of confidence (with area α to the right of it under the standard normal distribution), σ is the population standard deviation, and n is the sample size.

To find the value of a that results in an 85% confidence interval, we need to find the z-score that corresponds to the area to the right of it being 0.15 (since it's a one-sided right-tailed interval).

Using a standard normal distribution table or calculator, we find that the z-score corresponding to a right-tail area of 0.15 is approximately 1.04.

Therefore, the one-sided (right side) confidence interval expression for an 85% confidence interval for the population mean is:

[tex]x + 1.04σ/√n < μ[/tex]

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Answer:

15.0

Step-by-step explanation:

1

When the error terms have a constant variance, a plot of the residuals versus the independent variable x has a pattern that b. Funnels in

When the error terms have a constant variance, a plot of the residuals (the differences between the observed values and the predicted values) versus the independent variable x often exhibits a funnel-shaped pattern that narrows as the values of x increase or decrease.

This funneling pattern is a characteristic of heteroscedasticity, which refers to the unequal dispersion of the error terms across the range of the independent variable. In other words, the variability of the residuals changes systematically with the values of x.

The funneling pattern occurs because as the values of x increase or decrease, the spread of the residuals tends to increase as well. This can happen when the relationship between the independent variable and the dependent variable is nonlinear or when there are other factors influencing the variability of the residuals.

On a scatterplot of residuals versus x, the points may initially fan out, indicating increasing variability. However, as x continues to increase or decrease, the points start to converge and form a narrower funnel shape, indicating decreasing variability.

This funneling pattern suggests that the assumption of constant variance (homoscedasticity) in a regression model is violated. It is important to address heteroscedasticity to ensure accurate statistical inference and model validity.

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Answer:

The answer to your problem is, B. (-1,3)

Step-by-step explanation:

( My guess why you have put it a question is because you do not know why it is incorrect let me explain )

The coordinates that are given the intersection is: ( -1, 3 )

Being the answer.

Here the equations of the system of equations are:

-x+y=4

6x+y= -3

Put it on a coordinate plane ( In picture )

Thus the answer to your problem is, B. (-1,3)

Picture ↓

In quadrant II, if cosθ=-12/13, then cscθ=-13/5 and cotθ=5/12.

In quadrant II, if secθ=-5/3, then cotθ=-3/5 and sinθ=4/5.

(a) The terminal side of θ lies in quadrant III. (b) The terminal side of θ lies in quadrant IV.

Since cosθ is negative in quadrant II, sinθ will be positive. Using the Pythagorean identity sin^2θ + cos^2θ = 1 and the fact that cosθ=-12/13, we can solve for sinθ to get sinθ=5/13. Therefore, cscθ=1/sinθ=-13/5 and cotθ=cosθ/sinθ=-12/5.

Similarly, since secθ is negative in quadrant II, cosθ will be negative. Using the Pythagorean identity cos^2θ + sin^2θ = 1 and the fact that secθ=-5/3, we can solve for cosθ to get cosθ=-3/5. Therefore, sinθ is positive and sinθ=√(1-cos^2θ)=4/5. Thus, cotθ=cosθ/sinθ=-3/5.

(a) Since sinθ<0 and cotθ<0, we know that sinθ is negative in quadrant III and cotθ is negative in quadrant II and IV. Therefore, the terminal side of θ can only lie in quadrant III or IV. To determine which quadrant it lies in, we can look at the signs of both sinθ and cotθ. Since both are negative in quadrant III and only cotθ is negative in quadrant IV, we conclude that the terminal side of θ lies in quadrant III.

(b) Since cosθ>0 and cscθ<0, we know that cosθ is positive in quadrant I and IV, and cscθ is negative in quadrant III and IV. Therefore, the terminal side of θ can only lie in quadrant III or IV. To determine which quadrant it lies in, we can look at the signs of both cosθ and cscθ. Since both are negative in quadrant III and only cscθ is negative in quadrant IV, we conclude that the terminal side of θ lies in quadrant IV.

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x  1   2  3 4 5

y 16 12 8 4 0

This is the table which shows exponential decay

Exponential decay is characterized by a decreasing pattern where the values decrease rapidly at first and then gradually approach zero.

In exponential decay, the y-values decrease exponentially as the x-values increase.

Among the given tables, the table that shows exponential decay is:

x  1   2  3 4 5

y 16 12 8 4 0

In this table, as x increases from 1 to 5, the corresponding y-values decrease rapidly and approach zero.

This pattern indicates exponential decay.

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We have shown that if f: R -> R is a differentiable Lipschitz continuous function, then f(0) is a bounded function.

As f is a Lipschitz continuous function, there exists a constant L such that:

|f(x) - f(y)| <= L|x-y| for all x, y in R.

Since f is differentiable, it follows from the mean value theorem that for any x in R, there exists a point c between 0 and x such that:

f(x) - f(0) = xf'(c)

Taking the absolute value of both sides of this equation and using the Lipschitz continuity of f, we obtain:

|f(x) - f(0)| = |xf'(c)| <= L|x-0| = L|x|

Therefore, we have shown that for any x in R, |f(x) - f(0)| <= L|x|. This implies that f(0) is a bounded function, since for any fixed value of L, there exists a constant M = L|x| such that |f(0)| <= M for all x in R.

In conclusion, we have shown that if f: R -> R is a differentiable Lipschitz continuous function, then f(0) is a bounded function.

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For a larger input size of 320,000 elements, it will take 240 ms to sort each half and 24 ms to merge the sorted halves, resulting in a total time of 264 ms.

The given information describes the time required for sorting and merging operations on two different input sizes. For 80,000 elements, it takes 18 ms to sort each half, resulting in a total of 36 ms for sorting. Merging the two sorted halves with 80,000 numbers in each takes 40 - 18 = 22 ms.

When the input size is doubled to 320,000 elements, the sorting time for each half increases to 240 ms, as it scales linearly with the input size. The merging time, however, remains constant at 4 ms since the size of the sorted halves being merged is the same.

Thus, the total time for sorting and merging 320,000 elements is the sum of the sorting time (240 ms) and the merging time (4 ms), resulting in a total of 264 ms.

Therefore, based on the given information, the total time required for sorting and merging 320,000 elements is 264 ms.

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To find the area of the hub cap, we need to use the formula for the circumference of a circle and solve for the radius, then use the formula for the area of a circle.

The formula for circumference of a circle is: C = 2πr where C is the circumference and r is the radius. We know that the circumference of the hub cap is 82.46 centimeters. So we can substitute this value into the formula:82.46 = 2πr To solve for r, we need to isolate it on one side of the equation.

We can do this by dividing both sides by 2π:82.46 / 2π ≈ 13.123r ≈ 13.123Now that we have the radius, we can use the formula for the area of a circle: A = πr²Substituting in the value of the radius we just found: A ≈ π(13.123)²A ≈ π(171.85)A ≈ 539.24So the area of the hub cap is approximately 539.24 square centimeters.

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In all cases, the p-value is less than the significance level of 0.05, so we reject the null hypothesis and conclude that there is evidence to support the alternative hypothesis. The probability of observing a sample proportion as extreme or more extreme than the one observed, assuming the null hypothesis is true, is very low.

To compute the p-value, we first need to calculate the test statistic z-score using the sample proportion and the null hypothesis.

a. x = 51; n = 100

The sample proportion is p-hat = x/n = 51/100 = 0.51

The test statistic is z = (p-hat - p0) / sqrt(p0(1-p0)/n) = (0.51 - 0.59) / sqrt(0.59(1-0.59)/100) = -2.41

Using a standard normal distribution table, we find that the p-value is 0.0081.

b. x = 138; n = 276

The sample proportion is p-hat = x/n = 138/276 = 0.50

The test statistic is z = (p-hat - p0) / sqrt(p0(1-p0)/n) = (0.50 - 0.59) / sqrt(0.59(1-0.59)/276) = -3.27

Using a standard normal distribution table, we find that the p-value is 0.0005.c. p¯p¯ = 0.54; n = 53

The test statistic is z = (p-hat - p0) / sqrt(p0(1-p0)/n) = (0.54 - 0.59) / sqrt(0.59(1-0.59)/53) = -1.62

Using a standard normal distribution table, we find that the p-value is 0.0526.d. p¯p¯ = 0.54; n = 425

The test statistic is z = (p-hat - p0) / sqrt(p0(1-p0)/n) = (0.54 - 0.59) / sqrt(0.59(1-0.59)/425) = -4.42

Using a standard normal distribution table, we find that the p-value is 0.000004.

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The curvature κ(t) is given by |6 / (2 + 3t²)³|.

To find the curvature κ(t) for the given parametric equations x = 9 + t² and y = 3 + t³, we need to use the formula:

κ(t) = |(x'y'' - y'x'') / (x'² + y'²)^(3/2)|

where x' and y' represent the first derivatives with respect to t, and x'' and y'' represent the second derivatives with respect to t.

Let's find the derivatives first:

Given:

x = 9 + t²

y = 3 + t³

First derivatives:

x' = 2t

y' = 3t²

Second derivatives:

x'' = 2

y'' = 6t

Now, we can substitute these values into the curvature formula:

κ(t) = |(x'y'' - y'x'') / (x'²+ y'²)^(3/2)|

= |((2t)(6t) - (3t²)(2)) / ((2t)² + (3t²)²)^(3/2)|

= |(12t² - 6t²) / (4t² + 9t[tex]x^{4}[/tex])^(3/2)|

= |(6t²) / (t²(4 + 9t²))^(3/2)|

= |(6t²) / (t²(√(4 + 9t²)))³|

= |(6t²) / (t² * (2 + 3t²))³|

= |6 / (2 + 3t²)³|

Therefore, the curvature κ(t) is given by |6 / (2 + 3t²)³|.

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