The longest pipe found in most medium-size pipe organs is 2.40 m (7.87 ft) long. What is the frequency of the note corresponding to the fundamental mode if the pipe is open at one end and closed at the other

Answer:

E) the energy stored will quadrupled

Explanation:

The correct question is

A parallel plate capacitor consists of two square parallel plates separated by a distance d. If i double the potential across the plates, while keeping everything else constant, what happens to the energy stored in the capacitor?

A) There will be 1/4 of the energy stored

B) There will be 1/2 of the energy stored

C) The energy stored will remain constant

D) The energy stored will double

E) the energy stored will quadruple

The initial energy stored in the capacitor [tex]E_{i}[/tex] = [tex]\frac{1}{2}CV^{2}[/tex]

where C is the capacitance

V is the potential difference

If I double this voltage, while holding every other parameters constant, the new energy stored will be

[tex]E_{n}[/tex] = [tex]\frac{1}{2}C(2V)^{2}[/tex] = [tex]\frac{4}{2}CV^{2}[/tex]

[tex]E_{n}[/tex] = [tex]2CV^{2}[/tex]

dividing new energy stored by the initial energy stored, we have

[tex]E_{n}/E_{i}[/tex] = [tex]2CV^{2}[/tex] ÷ [tex]\frac{1}{2}CV^{2}[/tex] = 4

the energy stored will be quadrupled.

Answer:

18.83m/s

Explanation:

In the first 11meters, we can calculate the Kinectic energy since we know that

the floor is frictionless then work done by the horizontal force= Kinectic energy gain by the block in the first 11m.

Then Kinetic Energy = wordone

But work done= Force × distance

Kinetic Energy=(225×11)= 2475J

In the next 10.0 m the coefficient of friction is 0.20, the Kinectic energy has equal value to the difference in workdone by both the horizontal and frictional force

K.E= (Force× distance) - ( mass × gravity× coefficient of friction × distance at 10 m)

K.E= [(225×10)-(.20× 9.8×10× 24)]

K.E= 2250-470.4

= 1779.6J

The addition of the Kinectic energy above give us the total Kinectic energy experience by the crate.

Total Kinectic energy= 1779.6+2475

= 4254.6J

the final speed of the crate after being pulled these 21.0 m?

Total distance= 11m + 10m = 21 m

Then the final speed can be calculated from the total Kinectic energy, since we know that

K.E= 0.5mv^2

V= √(2K.E/m)

= √(2×4254.6)/24

Final speed v = √354.55

Final speed v= 18.83m/s

Therefore, the final speed of the crate after being pulled these 21.0 m is 18.83m/s

Answer:

The gauge pressure in Pascals inside a honey droplet is 416 Pa

Explanation:

Given;

diameter of the honey droplet, D = 0.1 cm

radius of the honey droplet, R = 0.05 cm = 0.0005 m

surface tension of honey, γ = 0.052 N/m

Apply Laplace's law for a spherical membrane with two surfaces

Gauge pressure =  P₁ - P₀ = 2 (2γ / r)

Where;

P₀ is the atmospheric pressure

Gauge pressure = 4γ / r

Gauge pressure = 4 (0.052) / (0.0005)

Gauge pressure = 416 Pa

Therefore, the gauge pressure in Pascals inside a honey droplet is 416 Pa

Answer:

D. The object splitting into two parts to form two organisms.

Explanation:

The splitting of cell of an organism actually shoes if it's Alive or not .

The splitting can be either mitosis or meosis for either plant or animal.

But for the fact that it's has cell membrane shoes it's either a plant or an animal.

So the splitting will confirm it's alive.

Answer:

D the correct answer is D

Explanation:

I took the test and was going to pick c but changed my mind

Answer:

7.92 × 10^8 M

A radio wave sent from the surface of the earth reflects from the surface of the moon and returns to the earth. The elapsed time between the generation of the wave and the detection of the reflected wave is 2.6444s. then the distance from the surface of the earth to the surface of the moon would be 3.9632×10⁸ meters.

It can be understood in terms of the distance between any two similar successive points across any wave for example wavelength can be calculated by measuring the distance between any two successive crests.

As given in the problem A radio wave sent from the surface of the earth reflects from the surface of the moon and returns to the earth. The elapsed time between the generation of the wave and the detection of the reflected wave is 2.6444s

the given speed of the light is 2.9979 ×10⁸ m/s

As we know that

Distance =speed ×time

Distance = 2.9979 ×10⁸× 2.6444

               =7.92644× 10⁸

This is the total distance covered by both ways from the moon to earth

The actual distance of the moon from earth would be half of this distance

Thus, the distance from the surface of the earth to the surface of the moon would be 3.9632×10⁸ meters.

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Answer:

0.0129 m

Explanation:

ΔL = FL / (EA)

where ΔL is the deflection,

F is the force,

L is the initial length,

E is Young's modulus,

and A is the cross sectional area.

F = mg = 100 kg × 9.8 m/s² = 9800 N

A = 4.0 mm² × (1 m / 1000 mm)² = 4×10⁻⁶ m²

ΔL = (9800 N) (1.0 m) / ((1.9×10¹¹ Pa) (4×10⁻⁶ m²))

ΔL = 0.0129 m

Answer:

the correct amount

Explanation:

The pan balance has two pans . When the elevator is accelerating upward , the apparent weight of both objects placed on either pan increase . The net effect is that they cancel out the effect of accelerating elevator . Hence the apparent weight of salt remains same as and equal to its real weight.

In case of spring balance,  its apparent weight would have increased . Its apparent weight would have measured more than its true weight.

Answer:

(1): Similarities Both thermometers are used to measure temperature and both of them use mercury,Differences Clinical thermometer is used to measure human body temperature whereas laboratory thermometer is used to measure temperature of other object which has higher temperature than human body temperature

(2)Examples of conductors include metals, aqueous solutions of salts, Examples of insulators include plastics, Styrofoam, paper, rubber, glass and dry air.

(3)Air acts as insulator of heat. This layer prevents our body heat to escape in the surroundings. More layers of thin clothes will allow more air to get trapped and as a result we will not feel cold. So wearing more layers of clothing during winter keeps us warmer than wearing just one thick piece of clothing

Explanation:

Answer:

The  values is  [tex]f_b =14.9 \ beats/s[/tex]

Explanation:

From the question we are told that

   The  speed of the fire engine is  [tex]v = 5\ m/s[/tex]

    The frequency of the tone is  [tex]f = 500 \ Hz[/tex]

    The speed of sound in air is [tex]v_s = 340 \ m/s[/tex]

The  beat frequency is mathematically represented as

     [tex]f_b = f_a - f[/tex]

Where  [tex]f_a[/tex] is the frequency of sound heard by the people in the fire engine and is is mathematically evaluated as

   [tex]f_a = [\frac{v_s + v }{v_s -v} ]* f[/tex]

substituting values

  [tex]f_a = [\frac{340 + 5 }{340 -5} ]* 500[/tex]

  [tex]f_a = 514.9 \ Hz[/tex]

Thus  

      [tex]f_b =514.9 - 500[/tex]

      [tex]f_b =14.9 \ beats/s[/tex]

Answer:

aaawwwwwwwsssaaaasasss

Explanation:

We need to add 28.97 and 45.876.

Here, the first no is 28.97 and other no is 45.876

Here, 28.97 is the least precise value and 45.876 is most precise.

28.97 + 45.876 = 74.846

We need to write the final answer such that there is two digit after the decimal. So, 28.97 + 45.876 = 74.85 because 6 is more than 5 i.e. we add 1 to 4.

Answer:

 28.97

+ 45.876

 74.846

Explanation:

Because 28.97 has only two decimal places, round off the answer to two decimal places: 74.85.

Answer:

Independent Variable: Choice of preservative

Dependent Variable: Time it took to brown

Controlled Variables/Constants: Climate, Size of apple slices, and amount of preservative on each slice

Control: Apple Slices without preservatives on them

Repeated Trials: One?

Explanation:

Answer:

option B is correct

Explanation:

in geocentric model earth is at the center of the universe and sun,moon star etc orbited the earth  thats why option B is correct

Speed, weight, and time between impact and stopping all are the factors that affect force.

A force is an influence in physics that can change the motion of an object. A force can cause a mass object to change its velocity, or accelerate.

Intuitively, force can be described as a push or a pull. A force is a vector quantity because it has both magnitude and direction.

The magnitude of a force expresses its strength. The magnitude of a force is expressed in Newtons, the SI unit of force.

One Newton is the force that can cause an object weighing one kilogram to move one meter per second.

The mass of the objects and the coefficient of friction between them are the two factors. The angle between them is also important.

Thus, these are some factors affecting strength of force.

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Answer:

True

Explanation:

Without proper development during the critical period, the growth of some life skills may be severely delayed or stunted.

the answer wil be 2.36+3.38+0.355+1.06=7.155

Explanation:

The pressure of hurricane which is high decreases gradually as we move higher . The pressure is maximum at the surface . Hence the relative air pressure is higher at the surface and low at the top . Like wise the pressure is low at the center and keeps on increasing when we move outside . Hence the answer is pressure is high at surface and low aloft.

Answer:

The average velocity of an object is its total displacement divided by the total time taken. In other words, it is the rate at which an object changes its position from one place to another. Average velocity is a vector quantity. The SI unit is meters per second.

hope this helps you

Answer:

displacement divided by time

Explanation:

Explanation:

Pressure = force / area

P = 55 N / (0.55 m × 0.45 m)

P = 220 Pa

Answer:

a) Hmax =   10.86 m

b) Rx = 48.64 m

c) Rx¹ = 36.48m

Explanation:

Given that Ф = 50°

v₀ = 22 m/s

a)

hmax = v₀²sin²Ф / 2g

hmax = 22² × sin²50  / 2 × 9.8

hmax =   14.49 m

Hmax = 75% of hmax

Hmax = 0.75 × 14.49

Hmax = 10.86 m

the maximum height reached by the ball during its first parabolic arc is 10.86 m

b)

Rx = v₀²sin2Ф / g

Rx = 22² × sin 100  / 9.8

Rx = 48.64 m

the distance between the launch point to where the ball lands the first time is 48.64 m

c)

Rx¹ = 75% 0f Rx

Rx¹ = 0.75 × 48.64

Rx¹ = 36.48m

the distance between the launch point to where the ball lands the second time is 36.48m  

Answer: -1   or -4/4

Explanation:

4/4  simplifies to 1   and the opposite of 1 is -1.

Answer:

4.5%

Explanation:

efficiency = energy out / energy in

e = 9.3×10⁴ J / 2.06×10⁶ J

e = 0.045

Answer:

The  value is  [tex]d = 0.000125 \ m[/tex]

Explanation:

From the question we are told that

   The  wavelength is  [tex]\lambda = 500 \ nm = 500 *10^{-9 } \ m[/tex]

    The  distance is of  the screen is  [tex]D = 2.0 \ m[/tex]

    The  width of the fifth dark spot is [tex]y = 4.00 \ cm = 0.04 \ m[/tex]

Generally the width of a fringe is mathematically represented as

           [tex]y = \frac{ n * \lambda * D }{d }[/tex]

=>        [tex]0.04 = \frac{ 5 * 500 *10^{-9} * 2 }{d}[/tex]

=>        [tex]d = \frac{ 5 * 500 *10^{-9} * 2 }{0.04}[/tex]

=>        [tex]d = 0.000125 \ m[/tex]

Answer:

The value of fraction of energy is [tex]2.23\times10^{-11}[/tex]

The value of fraction of energy is [tex]7.53\times10^{-5}[/tex]

Explanation:

Given that,

Charge = q

Acceleration = a

The rate at which energy is emitted from an accelerating charge

[tex]\dfrac{dE}{dt}=\dfrac{q^2a^2}{6\pi\epsilon c^3}[/tex]....(I)

We know that,

Acceleration for circular motion is

[tex]a=\dfrac{v^2}{r}[/tex]....(II)

The kinetic energy is

[tex]K.E=\dfrac{1}{2}mv^2[/tex]

[tex]v^2=\dfrac{2(K.E)}{m}[/tex]

Put the value of v in equation (II)

[tex]a=\dfrac{2(K.E)}{mr}[/tex]

Put the value of a in equation (I)

[tex]\dfrac{dE}{dt}=\dfrac{q^2(\dfrac{2(K.E)}{mr})^2}{6\pi\epsilon c^3}[/tex]

[tex]\dfrac{dE}{dt}=\dfrac{q^24(K.E)^2}{6\pi\epsilon c^3\times m^2 r^2}[/tex]

[tex]\dfrac{\dfrac{dE}{dt}}{K.E}=\dfrac{q^24(K.E)}{6\pi\epsilon c^3\times m^2 r^2}[/tex]

Suppose that,

[tex]\dfrac{\dfrac{dE}{dt}}{K.E}=R[/tex]

So,

[tex]R=\dfrac{q^2\times4(K.E)}{6\pi\epsilon c^3\times m^2 r^2}[/tex]....(III)

(a). For proton,

We need to calculate the fraction of its energy does it radiate per second

Using equation (III)

[tex]R=\dfrac{4\times(1.6\times10^{-19})^2\times5.0\times1.6\times10^{-19}\times10^{6}\times6\times10^{9}}{(3\times10^{8})^3\times(1.67\times10^{-27})^2\times(0.540)^2}[/tex]

[tex]R=2.23\times10^{-11}[/tex]

(b). For electron,

We need to calculate the fraction of its energy does it radiate per second

Using equation (III)

[tex]R=\dfrac{4\times(1.6\times10^{-19})^2\times5.0\times1.6\times10^{-19}\times10^{6}\times6\times10^{9}}{(3\times10^{8})^3\times(9.1\times10^{-31})^2\times(0.540)^2}[/tex]

[tex]R=0.0000753[/tex]

Hence, The value of fraction of energy is [tex]2.23\times10^{-11}[/tex]

The value of fraction of energy is [tex]7.53\times10^{-5}[/tex]

Answer:

e see that the distances are different, the only way that the two beams of light approach simultaneously is that event 2 (farthest) occurs first than event 1

Explanation:

This is an ejercise in special relativity, where the speed of light is constant.

Let's carefully analyze the approach, we see the two events at the same time.

The closest event time is

       c = (x₁-300) / t

       t = (x₁-300) / c

The time for the other event is

       t = (x₂- 600) / c

since they tell us that we see the events simultaneously, we can equalize

        (x₁ -300) / c = (x₂ -600) / c

         x₁ = x₂ - 300

We see that the distances are different, the only way that the two beams of light approach simultaneously is that event 2 (farthest) occurs first than event 1

Complete question:

A certain organ pipe, open at both ends, produces a fundamental frequency of 293 Hz in air. If the pipe is filled with helium at the same temperature, what fundamental frequency fHe will it produce? Take the molar mass of air to be 28.97 g/mol and the molar mass of helium to be 4.00 g/mol. Now consider a pipe that is stopped (i.e., closed at one end) but still has a fundamental frequency of 293 Hz in air. How does your answer to first question, fHe, change?

Answer:

The fundamental frequency that helium produced is 788.6 Hz.

Since the fundamental frequency of air in closed pipe is still the same value as open pipe, the fundamental frequency of helium will not change.

Explanation:

The speed of sound in pipe when filled with air is given by;

[tex]v = \sqrt{\frac{\gamma RT}{M} }[/tex]

Where;

γ = 1.4

R = 8.31 J/mol.K

M = 0.02897 kg/mol

T = 20°C = 293 K

[tex]v_{air} = \sqrt{\frac{1.4* 8.31*293}{0.02897} } = 343 \ m/s[/tex]

The speed of sound in pipe when filled with helium is given by

[tex]v_{He} = \sqrt{\frac{1.4* 8.31*293}{0.004} } =923.14 \ m/s[/tex]

Now, determine the fundamental frequency Helium will it produce

v = fλ

[tex]\frac{V_{air}}{F_o{air}} = \frac{V_{He}}{F_o{He}}\\\\F_o{He} = \frac{F_o{air}*V_{He}}{V_{air}} \\\\F_o{He} = \frac{(293)*(923.14)}{343}\\\\F_o{He} = 788.6 \ Hz[/tex]

Since the fundamental frequency of air in closed pipe is still the same value as open pipe, the fundamental frequency of helium will not change.

Answer:

v = 17.71 m / s

Explanation:

We can work this exercise with the kinematics equations. In general the body is released so that its initial velocity is zero, the acceleration of the acceleration of gravity

                v² = v₀² - 2 g (y -y₀)

                v² = 0 - 2g (y -y₀)

when it hits the stone the height is zero and part of the height of the seagull I

              v² = 2g y₀

              v = Ra (2g i)

let's calculate

              v =√ (2 9.8 16)

              v = 17.71 m / s

Answer:

4.167m/sec

Explanation:

1km=1000m

1.5km=1500m

1min=60sec

6min=360sec

In 360sec they travel 1500m

In 1 sec they travel=1500m/360

1sec=4.167m

Answer:

T' = 2T

Explanation:

The time period of a simple pendulum is given by the relation as follows :

[tex]T=2\pi \sqrt{\dfrac{l}{g}}[/tex]

l is length of the pendulum

g is acceleration due to gravity

If the length is increased four time, new length is l' = 4l

So,

New time period is :

[tex]T'=2\pi \sqrt{\dfrac{l'}{g}}\\\\T'=2\pi \sqrt{\dfrac{4l}{g}}\\\\T'=2\times 2\pi \sqrt{\dfrac{l}{g}}\\\\T'=2\times T[/tex]

So, the new time period is 2 times of the initial time period.