The location of a particle is measured with an uncertainty of 0.13 nm. One tries to simultaneously measure the velocity of this particle. What is the minimum uncertainty in the velocity measurement. The mass of the particle is 1.745×10-27 kg

Answers

Answer 1

Answer:

The minimum uncertainty in the velocity is 232.57 m/s.

Explanation:

Given that,

Location of a particle with uncertainty = 0.13 nm

Mass of particle [tex]m=1,745\times10^{-27}\ kg[/tex]

We need  to calculate the minimum uncertainty in the velocity

Using heisenberg's uncertainty principle,

[tex]\Delta x\cdot \Delta p\geq \dfrac{h}{4\pi}[/tex]

[tex]\Delta x\cdot m\Delta v \geq \dfrac{h}{4\pi}[/tex]

[tex]\Delta v=\dfrac{h}{4\pi\times m\Delta x}[/tex]

Put the value into the formula

[tex]\Delta v=\dfrac{6.63\times10^{-34}}{4\pi\times 1.745\times10^{-27}\times0.13\times10^{-9}}[/tex]

[tex]\Delta v= 232.57\ m/s[/tex]

Hence, The minimum uncertainty in the velocity is 232.57 m/s.


Related Questions

The potential energy U of an object of mass m that is separated by a distance R from an object of mass M is given by U= -GMm/RA. What is the kinetic energy K of the satellite?Express your answer in terms of the potential energy .
B. Find an expression for the square of the orbital period.

Answers

Answer:

A)  K = ½ U / r , B)     T² = (4π² / G M) r³

Explanation:

A) It asks us for the kinetic energy of the satellite and they give us the relation of the potential synergy

         U = - G M m / r

the force can be found from this expression

          F = - dU / dr

          F = - G M m / r²

The kinetic energy is given by the formula

          K = ½ m v²

let's use Newton's second law

        F = m a

        G M m / r² = m a

where the acceleration is centripetal

        a = v² / r

         G M r² = v² / r

         v² = G M r³

we substitute the expression for the kinetic energy

         K = ½ m v²

         K = ½ m G M r³

in terms of potential energy is

         K = ½ (G M m r²) 1 / r

         K = ½ U / r

B) The period of the orbit

         

We write Newton's second law

            G M m / r² = m a

            a = v² / r

           

in a circular orbit the speed of the velocity is constant

            v = d / t

           

the longitude of the orbit is

             d = 2π r

            v = 2π r / T

we substitute

            G Mm / r² = m (2πr / T)² / r

            G M / r³ = 4π² / T²

            T² = (4π² / G M) r³

(A) The kinetic energy of satellite in terms of potential energy is,

       K =  1/2 U / R.

(B)  The expression for the square of the orbital period is,

         T² = (4π² / G M) R³

Given data:

The potential energy of object is, U.

The mass of object is, m.

The distance from the other object of mass M is, R.

A.

The kinetic energy of the satellite and they give us the relation of the potential synergy,

U = - G M m / R

And the force can be found from this expression

F = - dU / dR

F = - G M m / R²

The kinetic energy is given by the formula

K = 1/2 m v²

Now use Newton's second law

F = m a

G M m / R² = m a

where the acceleration is centripetal

a = v² / R

G M R² = v² / R

v² = G M R³

we substitute the expression for the kinetic energy

K = 1/2 m v²

K = 1/2 m G M R³

in terms of potential energy is

K = 1/2 (G M m R²) 1 / R

 K =  1/2 U / R

Thus, we can conclude that the kinetic energy of satellite in terms of potential energy is K =  1/2 U / R.

(B)

Now we need to obtain the period of the orbit of satellite. For that we   write Newton's second law as

G M m / r² = m a

Since,

a = v² / r

In a circular orbit the speed is constant,

v = d / t

For the longitude of the orbit is

d = 2π R

v = 2π R / T

here,

T is the orbital period of satellite.

 

Substituting the values as,

G Mm / R² = m (2πR / T)² / R

G M / R³ = 4π² / T²

T² = (4π² / G M) R³

Thus, we can conclude that the expression for the square of the orbital period is T² = (4π² / G M) R³.

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An astronaut in an inertial reference frame measures a time interval Δt between her heartbeats. What will observers in all other inertial reference fr

Answers

Answer:

It will be more than deta t

Explanation:

Because

deta t' = န deta t

But န= 1/√ (1 - v²/c²

So the observers in all the initial frames will be more than deta t

A westward-moving bicycle increased its speed from 2.0m/s to 12.0m/s in 4.0 seconds. What is the magnitude and direction of the acceleration?

Answers

Answer:

2.5 m/s^2

Explanation:

Acceleration = (Final Velocity - Initial Velocity) / TIme

Acceleration = 12 - 2 / 4

=> Acceleration = 10 /4

=> Accelration = 5/2

=> Acceleration = 2.5 m/s^2

So, Acceleration is 2.5 m/s^2

The acceleration of the bicycle which is the change in the velocity of the bike with change in time will be 2.5m/s in the Westward direction

Initial speed = 2.0 m/s Final speed = 12.0 m/s

Change in time, t = 4.0 seconds

We define acceleration thus :

Acceleration = (△velocity / △time)

Change in velocity = (12 - 2) = 10 m/s

Acceleration = 10 / 4 = 2.5 m/s²

Therefore, the acceleration of the bike will be 2.5m/s² in the West direction

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Which of the following is an SI unit

Answers

Answer:

liter is the SI unit

idk how to explain it

difference between far point and near point​

Answers

Answer:

Far point = is the farthest point where you can see the object

near point= is the nearest distance where you can see the object.

Explanation:

The far point of human eye is upto infinity & the near point is 25cm.

At what speed does a clock move if it is measured to run at a rate two-fifths the rate of a clock at rest with respect to an observer

Answers

Answer:

0.44c

Explanation:

We know that

Time interval at speed (ts)= time interval at rest(tr) / gamma

where

gamma = √[1-(v/c)²]

ts = tr / gamma

tr/ts = gamma

But

Ss/Sr = gamma

Where

Sr = clock speed at rest, Ss at speed):

So

√[1-(v/c)²] = 2/5

1 - (v/c)² = 4/25

(v/c)²= 5/25

v/c = √5 / 5

v = 0.444c

The human eye is most sensitive to 560-nm (green) light. What is the temperature of a black body that would radiates most intensely at this wavelength

Answers

Given that,

Wavelength of the human light is 560 nm

To find,

The temperature of a black body that would radiates most intensely at this wavelength.

Solution,

The relation between temperature and the wavelength is given by :

[tex]\lambda=\dfrac{c}{T}[/tex]

T is temperature

c is [tex]2.898\times 10^{-3}\ m-K[/tex]

So,

[tex]T=\dfrac{c}{\lambda}\\\\T=\dfrac{2.898\times 10^{-3}}{560\times 10^{-9}}\\\\T=5175\ K[/tex]

So, the temperature of a black body that would radiates most intensely at this wavelength is 5175 K.

Planet Tatoone is about 1.7 AU from its Sun. Approximately how long will it take for light to travel from the Sun to Tatoone in minutes? Use 3 × 108 m/s for the speed of light.

Answers

Answer:

The value is   [tex]t =  14.129 \  minutes[/tex]    

Explanation:

From the question we are told that

  The distance of planet Tatoone is  [tex]d =  1.7 \ AU  =  1.7 *1.496* 10^{11}=2.543*10^{11} \ m[/tex]

   The  speed of light is  [tex]c =  3.0*10^{8} \  m/  s[/tex]

Generally the time taken is mathematically represented as

     [tex]t =  \frac{d}{c}[/tex]

=> [tex]t =  \frac{2.543*10^{11}}{3.0*10^{8} }[/tex]

=>    [tex]t =  847.7 \  s[/tex]

Now converting to minutes

       [tex]t =  \frac{847.7}{60}[/tex]

   =>     [tex]t =  14.129 \  minutes[/tex]    

What is the acceleration of a proton moving with a speed of 7.7 m/s at right angles to a magnetic field of 1.9 T

Answers

Answer:

The acceleration of the proton is 1.403 x 10 m/s²

Explanation:

Given;

speed of proton, v = 7.7 m/s

magnitude of magnetic field, B = 1.9 T

Magnetic force of moving proton is given by;

F = qvBsinθ

Centripetal force on the moving proton is given by;

[tex]F = m(\frac{v^2}{r})\\\\F = m(a_c) \\\\a_c \ is \ the \ centripetal \ acceleration[/tex]

[tex]qvBsin\theta = ma_c\\\\ac = \frac{qvBsin(90)}{m}[/tex]

where;

q is charge of the proton = 1.602 x 10⁻¹⁹ C

m is mass of proton = 1.67 x 10⁻²⁷ kg

[tex]ac = \frac{(1.602*10^{-19})(7.7)(1.9)sin(90)}{1.67*10^{-27}}\\\\a_c = 1.403*10^{9} \ m/s^2[/tex]

Therefore, the acceleration of the proton is 1.403 x 10 m/s²

What is your hypothesis regarding difference in urine specific gravity between subjects who drank water and subjects who a drank sports drink

Answers

Answer:

Sports drink will show increase in specific gravity

While

Water will decrease in SG

Explanation:

This is because the relative density of urine will increase because of presence of ions in the sport drink unlike in water that has very little ions

Using the Bohr model what is the radius of the electron orbit in the Hydrogen atom when the electron is in the n = 10 state?

Answers

Answer:

 r₁₀ = 52.9 nm

Explanation:

In Bohr's model of the hydrogen atom, the radius of the orbitals can be written as a function of the radius of the first orbit

               rₙ = n² a₀

where ao is 0.0529 nm and is the radius of the ground state of the atom

the radius for the excited state with n = 10

        r₁₀= 10² a₀

        r₁₀ = 100 a₀

        r₁₀ = 52.9 nm

Which of these forces help protons and neutrons to stay at the center of the Atom

Answers

Strong nuclear force

A 1890 kg truck traveling north at 34 km/h turns east and accelerates to 62 km/h. (a) What is the change in the truck's kinetic energy

Answers

Answer:

2540.18 kJ

Explanation:

The change in the trucks kinetic energy is same as the net work done by the truck in covering the said distance

Given data

mass of truck m= 1890 kg

initial velocity of truck u1= 34 km/h

final velocity v1= 62 km/h

applying the kinetic energy formula we have

[tex]K.E= \frac{1}{2}mv^2[/tex]

K.E(initial)

[tex]K.E(initial)= \frac{1}{2}*1890*34^2\\\\ K.E(initial)= \frac{1}{2}*1890*1156\\\\ K.E(initial)= \frac{1}{2}*2184840\\\\ K.E(initial)= 1092420J\\\\\ K.E(initial)= 1092.4kJ[/tex]

K.E(final)

[tex]K.E(initial)= \frac{1}{2}*1890*62^2\\\\ K.E(initial)= \frac{1}{2}*1890*3844\\\\ K.E(initial)= \frac{1}{2}*7265160\\\\ K.E(initial)= 3632580J\\\\\ K.E(initial)= 3632.58kJ[/tex]

The change in K.E= K.E(final)- K.E(initial) = 3632.58-1092.4= 2540.18 kJ

the change in the truck's K.E is 2540.18 kJ

An electron from a Ti ^ + 2 hydrogen ion leaps from one orbit with radius 13.25 angstrom to another orbit with radius 2.12 angstrom. determine the energy (Joule) e produced in said transition and the wavelength (in cm)

Answers

Answer:

    E  = 0.2276 10⁻¹⁹ J ,  λ = 8.73374 10⁻⁴ cm

Explanation:

Bohr's atomic model can be used for hydrogen-type atoms, that is, they have a single electron in their last orbit, this is the case of doubly ionized Titanium.

It is much easier to work in EV units.

          r = a₀ / Z n²

          E = - 13.606 (Z² / n²)

where ao is the Bohr radius, which is the ground state orbital of hydrogen a₀ = 0.0529 nm, Z is the atomic number of titanium, and n is an integer that represents the different states of the system.

a) Let's look for the energy, for this we look for the integer numbers of these orbits

r = 13.25 A = 1.325 nm

          r = a₀ / Z   n²

         n = √(Z r / a₀)

the atomic number of titanium is Z = 22

         n = √ (22  1.325 / 0.0529)

         n = 23

r = 2.12 A = 0.212 nm

         n = √ (22  0.212 / 0.0529)

         n = 9

now we can calculate the energy of the transition

         E = 13.606 (1 / [tex]n_{f}^2[/tex] - 1 / [tex]x_{o}^2[/tex])

         E = 13.606 (1/9² - 1/23²)

         E = 13.6060 (0.010455)

         E = 0.1423 eV

Let's reduce to J

         E = 0.1423 eV (1.6 10⁻¹⁹ J / 1eV) = 0.2276 10⁻¹⁹ J

To find the wavelength of the transition, use the Planck relation

         E = h f

the relationship of frequency and speed of light

         c = λ f

  we substitute

         E = h c /λ

         λ = hc / E

        λ = 6.626 10⁻³⁴ 3 10⁸ / 0.2276 10⁻¹⁹

        λ = 8.73374 10⁻⁶ m

       λ = 8.73374 10⁻⁴ cm

Hydrogen atom number 1 is known to be in the 4f state. Hydrogen atom number 2 is in the 5d state.

Required:
a. What is the energy of the atom?
b. WHat is the magnitude of this atom's orbital angular momentum?
c. Hydrogen atom number 2 is in the 5d state. Is this atom's energy greater than, less than, or the same as that of atom 1? Explain.
d. Is the magnitude of the orbital angular momentum of atom 1 greater than, less than, or the same as that of atom 2? Explain.

Answers

Answer:

4f   E₄ = 0.85 eV,    L₄ = 4.22 10⁻³⁴ ,  

5d          E₅ = 0.544 eV ,    L5 = 5.28 10⁻³⁴

Explanation:

Let's use the Bohr model, stable the energy of the hydrogen atom

              E = -13.606 / n2

where Eo = 13.606 eV is the energy of the ground states.

a) the energy of each atom

level 4f

In this nomenclature enumeration is the number n

               E = -13606 / 42

               E₄ = 0.85 eV

level 5d

                E₅ = -13.606 / 5 2

                E₅ = 0.544 eV

b) The angular momentum is given in Boh's model

                     L = n h / 2pi

let's calculate

             

level 4f             L₄ = 4 6.63 10⁻³⁴-34 / 2 pi

                        L₄ = 4.22 10⁻³⁴

level 4d

                       L5 = 5 6.63 10-⁻³⁴ / 2pi

                       L5 = 5.28 10⁻³⁴

c) The hydrogen atom in state n = 5 has lower energy than the other state

d) Atom 1 has less angular momentum than atom 2

These spectra are from the same element. Which is an emission spectrum, which an absorption spectrum?
A. Either could be emission (or absorption), depending on the conditions with which they were made.
B. Top is absorption; bottom emission.
C. Can't tell without knowing the element.
D. Top is emission; bottom absorption.

Answers

Answer:

D. Top is emission; bottom absorption.

Explanation:

Emission and spectrum of elements are due to the element absorbing or emitting wavelength of e-m energy. Elementary particles of elements can absorb energy from a ground state to enter an excited state, creating an absorption spectrum, or they can lose energy and fall back to a lower energy state, creating an emission spectrum. A simple rule to differentiate between an emission and an absorption spectrum is that: "all absorbed wavelength is emitted, but not all emitted wavelength is absorbed."

From the image, the lines indicates wavelengths. We can see that all of the wavelengths of the bottom absorption spectrum coincides with some of the wavelength of the upper emission wavelengths.

While skiing , Sam flies down hill and hits a jump. He has a mass of 75 kg. And he leaves the jump at 18m/s what is his momentum as he leaves the jump

Answers

123.3 for the love of god this app is so dumb I just need sanders for my test lord help

What is the difference between 103.5 and 102.24 written with the correct number of significant figures?What is the difference between 103.5 and 102.24 written with the correct number of significant figures?

Answers

Answer:

1.260

Explanation:

103.5 has 4 significant figures.

102.24 has 5 significant figures.

We will need to round the answer to the least number of significant figures available (in this case, 4).

103.5 − 102.24 = 1.26 = 1.260

The difference between 103.5 and 102.24 is equal to 1.3 in the correct number of significant figures.

What are significant figures?

Significant figures can be utilized to produce numbers that can be written in the form of figures. We can determine the number of significant figures by simply counting the values starting from the first non-zero digit placed on the left.

We can calculate the number of significant digits by counting from the first non-zero figure placed on the left. The significant digits of a given number are those significant digits, which convey the meaning with respect to its accuracy.

In the case of division or multiplication or subtraction and addition, the number of significant figures must be the same as the value with the fewest significant figures.

We have to find the difference between 103.5 and 102.24:

103.5 - 102.24 = 1.26 = 1.3

The number 103.5 has one significant figure after the decimal. Therefore, the answer will be equal to 1.3.

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Mention four importance of writing the physical quantities as vectors.​

Answers

Answer:

Explanation:

Knowledge of vectors is important because many quantities used in physics are vectors. If you try to add together vector quantities without taking into account their direction you'll get results that are incorrect.

Some of the key vector quantities in physics: force, displacement, velocity, and acceleration.

An example of the importance of vector addition could be the following:

Two cars are involved in a collision. At the time of the collision car A was travelling at 40 mph, car B was travelling at 60 mph. Until I tell you in which directions the cars were travelling you don't know how serious the collision was.

The cars could have been travelling in the same direction, in which case car B crashed into the back of car A, and the relative velocity between them was 20 mph. Or the cars could have been travelling in opposite directions, in which case it was a head on collision with a relative velocity between the cars of 100 mph!

Vector is defined as a quantity having direction as well as magnitude, especially as determining the position of one point in space relative to another

What is vector quantity?

Vector is defined as a quantity having direction as well as magnitude, especially as determining the position of one point in space relative to another

Knowledge of vectors is important because many quantities used in physics are vectors. If you try to add together vector quantities without taking into account their direction you'll get results that are incorrect.

Some of the key vector quantities in physics: force, displacement, velocity, and acceleration.

An example of the importance of vector addition could be the following:

Two cars are involved in a collision. At the time of the collision car A was travelling at 40 mph, car B was travelling at 60 mph. Until I tell you in which directions the cars were travelling you don't know how serious the collision was.

The cars could have been travelling in the same direction, in which case car B crashed into the back of car A, and the relative velocity between them was 20 mph. Or the cars could have been travelling in opposite directions, in which case it was a head on collision with a relative velocity between the cars of 100 mph!

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The system is immersed in an environment with a constant high temperature T. What would be the energy expectation value of the system

Answers

Answer:

The energy value is expected to rise steadily until it is equal to a value that depends on the temperature T of the environment.

Explanation:

If a system is immersed into an environment with a constant high temperature, the temperature of the system will also rise until it comes to equilibrium with the temperature of the environment. When this happens, the energy expectation value of the system will now be dependent on the temperature of the environment. This means that the energy of the system will be a function of the temperature of the environment.

This means that

E = f(T)

where E is the energy value of the system

T is the temperature of the environment.

Convert 200in/10s into m/s (1m = 39.37in)

Answers

5.08




hope you got it right !

Physical Science questions that I need HELP ON

Answers

Answer:

7a. CO2 => carbon dioxide

b. H2O => water

8. The mass of carbon dioxide, CO2 plus the mass of water, H2O is equal to the mass of sugar, C6H12O6 plus the mass of oxygen, O2.

Explanation:

7. Selecting the names of the reactant.

6CO2 + 6H2O —> C6H12O6 + 6O2

From the above equation, the reactants are: CO2 and H2O

Thus, the names of the reactants are:

a. CO2 => carbon dioxide

b. H2O => water

8. Determination of masses of the CO2, H2O, C6H12O6 and O2 from the balanced equation. This can be obtained as follow:

6CO2 + 6H2O —> C6H12O6 + 6O2

Molar mass of CO2 = 12 + (2x16) = 44 g/mol

Mass of CO2 from the balanced equation = 6 x 44 = 264 g

Molar mass of H2O = (2x1) + 16 = 18 g/mol

Mass of H2O from the balanced equation = 6 x 18 = 108 g

Molar mass of C6H12O6 = (12x6) + (12x1) + (16x6) = 72 + 12 + 96 = 180 g/mol

Mass of C6H12O6 from the balanced equation = 1 x 180 = 180 g

Molar mass of O2 = 16x2 = 32 g/mol

Mass of O2 from the balanced equation = 6 x 32 = 192 g

Summary:

Mass of Reactant:

CO2 = 264 g

H2O = 108 g

Total = 372 g

Mass of Product:

C6H12O6 = 180 g

O2 = 192 g

Total = 372 g

From the above calculations,

The mass of carbon dioxide, CO2 plus the mass of water, H2O is equal to the mass of sugar, C6H12O6 plus the mass of oxygen, O2.

What is the difference between
Dobereiner's triads and Newland's octaves​

Answers

Answer:

Newlands law of octave was the first logically basis on the atomic weight. Demerits of dobereiner's triads system: - This system fails because it does not hold good for all the elements discovered till date time. It is limited to only few elements.

Explanation:

which formula is used to calculate average velocity?

Answers

The answer is:

the first one

The formula  to calculate average velocity is a) V (average ) = x(f) - x(i) /t(f) - t(i)

What is average velocity ?

Average velocity is a vector quantity . It is defied as the change in displacement  over a time interval .

Average velocity can be calculated as

Average velocity  = change in displacement / change in time travel

correct answer is a) V (average ) = x(f) - x(i) /t(f) - t(i)

where

x(f) = final position

x(i) = initial position

t(f) = final time

t(i) = initial time

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A point charge Q moves on the x-axis in the positive direction with a speed of A point P is on the y-axis at The magnetic field produced at the point P, as the charge moves through the origin, is equal to What is the charge Q?

Answers

Answer: q = -52.5 μC

Explanation:

The complete question is given thus;

A point charge Q moves on the x-axis in the positive direction with a speed of 280 m/s. A point P is on the y-axis at y=+70mm. The magnetic field produced at the point P, as the charge moves through the origin, is equal to -0.30uTk. What is the charge Q? (uo=4pi x 10^-7 T m/A).

SOLVING:

from the given parameters we can solve this problem.

Given that the

Speed = 280 m/s

y = 70mm

B =  -30 * 10⁻⁶T

Using the equation for magnetic field we have;

Β = μqv*r / 4πr²

making q (charge) the subject of formula we have that;

q  = B * 4 *πr² / μqv*r

substituting the values gives us

q = (-0.3*10⁻⁶Tk * 4π * 0.07²) / (4π*10⁻⁷ * 280 ) = - [14.7 * 10⁻¹⁰k / 2.8 * 10⁻⁵ k ]

q = -52.5 μC

cheers i hope this helped !!!

A 500-kilogram sports car accelerates uniformly from rest, reaching a speed of 30 meters per second in 6 seconds. During the 6 seconds, the car has traveled a distance of:_______
(A) 15 m
(B) 30 m
(C) 60 m
(D) 90 m
(E) 180 m

Answers

Answer:

90 m

Explanation:

Given that

Mass of the car, m = 500 kg

Initial speed of the car, u = 0 m/s

Final speed of the car, v = 30 m/s

Time taken to travel, t = 6 s

average speed v = (30 + 0) / 2 = 15

We are going to be using the most very basic equations to solve this.

speed can be defined as the ratio of distance with respect to time.

v = d/t, Where

v = speed.

d = distance travelled and

t = time taken

if we invert this, we can get that

d = v.t

distance is multiplication of speed and time. We will be using the average speed we calculated above, so

Distance travelled in 6 s,

d = 15 * 6

d = 90 m.

therefore, the distance travelled by the car in this 6 s is 90 m

Consider a conducting rod of length 34 cm moving along a pair of rails, and a magnetic field pointing perpendicular to the plane of the rails.

Required:
At what speed (in m/s) must the sliding rod move to produce an emf of 0.75V in a 1.75T field?

Answers

Answer:

v = 1.26 m/s

Explanation:

Given that,

Length of the conducting rods = 34 cm = 0.34 m

Magnetic field, B = 1.75 T

Induced emf is 0.75 V

we need to find the speed with which it slides. Due to the motion of the rod an emf is induced in it which is given by :

[tex]\epsilon=Blv[/tex]

v is the speed of rod

[tex]v=\dfrac{\epsilon}{Bl}\\\\v=\dfrac{0.75}{1.75\times 0.34}\\\\v=1.26\ m/s[/tex]

So, the speed of the sliding rod is 1.26 m/s.

A 19.5-cm-diameter loop of wire is initially oriented perpendicular to a 1.8-T magnetic field. The loop is rotated so that its plane is parallel to the field direction in 0.22 s .

Required:
What is the average induced emf in the loop?

Answers

Given that,

Diameter of the loop, d = 19.5 cm

Magnetic field, B = 1.8 T

The loop is rotated so that its plane is parallel to the field direction in 0.22 s. We need to find the average induced emf in the loop.

When it is placed perpendicular to the magnetic field, angle between Area vector and Magnetic Field will be 0. Flus is BA.

When it is rotated so that its plane is parallel to the field direction, angle between Area vector and Magnetic Field will be 90. Flus is 0.

The induced emf is given by :

[tex]\epsilon=\dfrac{-d\phi}{dt}\\\\\epsilon=\dfrac{BA}{t}\\\\\epsilon=\dfrac{1.8\times \pi \times (19.5/2)^2}{0.22}\\\\\epsilon=2443.48\ V[/tex]

So, the average induced emf in the loop is 2443.48 volts.

the heaviest weight ever lifted by a human ear is 51.7kg. how many pounds is this?

Answers

Answer:

hey!

Your answer will be EXACTLY 113.97899 Pounds

Explanation:

BUT IF YOU ROUND THIS UP TO THE WHOLE NUMBER etc IT WILL BECOME 114 POUNDS!

Hope This Helped!

itsMATT04

The velocity time graph of a car shown below a) Calculate the magnitude of displacement of the car in 40 seconds. b) During which part of the journey was the car accelerating? c) Calculate the magnitude of average velocity of the car.

Answers

Answer:

a) 0 metres

b) From time 0 s to 10 s , the car was accelerated. Its velocity accelerated from 0m/s to 20 m/s

c) 20 m/s

Explanation:

a) Formula of displacement= velocity x time

time=40 s

velocity =0 m/s

∴ displacement= 0 x 40 = 0 m

Magnitude of displacement is 0 m

b) The increase in velocity shows that there has been acceleration.

c) The average velocity of the car is =[tex]\frac{0+40}{2\\}[/tex]   {initial velocity + final velocity}

                                                            =[tex]\frac{40}{2}[/tex]

                                                             =20

Therefore, the magnitude of the average velocity  of the car is 20 m/s

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