The lines represented by the equations y=-2x-6 and 2y+x=-16 are

Answer:

Consider a big number 3,400,000. To convert this number into scientific notation:

Place a decimal by counting the steps to the left until the coefficient of the number is between 1 and 9.

Count the number of steps moved. This will be the power of the base 10.

In this case, the coefficient is 3.4 and the 6 steps are moved.

Multiply the coefficient by 106,

Therefore, the answer is 3. 4 x 10 6

Step-by-step explanation:

Answer:

y=x + 6

Step-by-step explanation:

G1=G2

so G2 =1

y-3 /x+3 =1/1

y-3 = x +3

y=x + 6

Answer: the height of a triangle can be determined in many different ways depending on whether it's a right triangle, isosceles triangle (a triangle with two equal sides), or equilateral triangle.

Step-by-step explanation:

Step-by-step explanation:

The formula for the Area of a triangle is A = (1/2)bh where b is the base an h is the height. Since the triangle is a right triangle, the base and height are the two shorter sides

Answer:

Figure a) 2

Figure B) 4

Figure c) 5

Step-by-step explanation:

Answer: A: has 1 line B has 2 and 3 has 5

Step-by-step explanation:

Answer:

4 hours · Speed = 50 mph · distance = time x speed · Time = 200 / 50 = 4 hours.

Step-by-step explanation:

Answer:

6

Step-by-step explanation:

The LCM of 6 and 2 is 6.

The value of f.ds = 20π.

The quantity of electric or magnetic field lines that flow across a surface in a specific period of time is known as flux. Field lines offer a way to visualise the size and direction of the field under study.

Given:

f = <3xy²,3x²y,z³>

Using Divergence Theorem

P= 3xy²

Q= 3x²y

R = z³

So, dP/ dx= 3y²

dQ/ dy = 3x²

dQ/ dz = 3z²

So, [tex]\int\limits\int\limits\int\limits dV[/tex]= [tex]\int\limits\int\limits\int\limits (dP/ dx + dQ/dy+ dR/dz)[/tex]

= [tex]\int\limits\int\limits\int\limits[/tex] (3y² + 3x² + 3z²)

= [tex]\int\limits\int\limits\int\limits[/tex] 3 (y² + x² + z²)

Since the radius is 5.

= [tex]\int\limits\int\limits\int\limits[/tex] 3(5)

= 15 [tex]\int\limits\int\limits\int\limits[/tex] dV

= 15 (4/3)π

= 20π

Learn more about flux here:

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#SPJ5

Answer:

36

Step-by-step explanation:

A) -3

B) 5

C) -2

D)-6

i have to write 20 characters so sisiasskklsa

Answer:

a) -3

b)5

c)-2

d)-6

Step-by-step explanation:

4 - 7 =-3

4 is positive and 7 is negative

a positive minus a negative is equal to a negative

3 is negative and 8 is positive, but 8 is bigger than 3, so take the sign of the bigger number which is 8.

c) is the same as question b

same signs rule

a negative + a negative is = to negative

positive and a positive is = to a positive

a negative +/_ a positive = a negative

Answer:

2 - n

Step-by-step explanation:

2 decreased by n means n less than 2.

Answer:

Write each phrase as an algebraic expression. Phrase, Expression. nine increased by a number x, 9 + x. fourteen decreased by a number p, 14

Step-by-step explanation:

2-n       Plz mark brainliest if correct

AB=EF

ABEF=ABF+AEF

NOW CONTINUES THE SOLUTION

Answer:

y=3x +4

Step-by-step explanation:

your y intercept is 4, go 3 down 1 across and that is the slope.

Answer:

4x+9y-27=0

compare and fill em

hope it helps

Answer:

2

Step-by-step explanation:

y=1y

x=1x

so the answer will be 2.

may be

hope to help!!!

La solution:

625 cm^2.

Explication étape par étape:

Si la forme est rectangulaire, elle aura la plus grande superficie possible quand la longueur équivaut à la largeur. Pour avoir un périmètre de 100 cm, cela signifie que chaque côté doit faire 25 cm.

La superficie serait alors de 25 cm x 25 cm = 625 cm^2.

Lin should aim the ball at 7.8 feet away from point  B

From the question (see attachment), we have the following equivalent ratios:

[tex]AB : BE = DC :CE[/tex]

This is so because triangles ABE and DCE are similar triangles.

Such that:

[tex]BE + CE = 20[/tex]

[tex]AB = 16[/tex]

[tex]DC = 16 + 9 = 25[/tex]

So, we have:

[tex]AB : BE = DC :CE[/tex]

[tex]16 : BE = 25: CE[/tex]

Make CE the subject in [tex]BE + CE = 20[/tex]

[tex]CE=20 - BE[/tex]

Substitute 20 - BE for CE in [tex]16 : BE = 25: CE[/tex]

[tex]16 : BE = 25: 20 - BE[/tex]

Express as ratio

[tex]\frac{16 }{ BE} = \frac{25}{ 20 - BE}[/tex]

Cross multiply

[tex]16(20 - BE) = 25BE[/tex]

Open bracket

[tex]320 - 16BE = 25BE[/tex]

Collect like terms

[tex]25BE + 16BE = 320[/tex]

[tex]41BE = 320[/tex]

Divide both sides by 41

[tex]BE = 7.8[/tex]

Hence, she should aim at 7.8 feet away from point  B

Read more about similar triangles at:

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Answer:You want to make a bank shot. Sketch the path of the cue ball so it will bounce off of the bottom side and knock the yellow stripe 9 ball into the top middle pocket.

Step-by-step explanation:

Answer:

9√10

Step-by-step explanation:

3√15 x 6  = √90

3√90 = 3 x √9 x √10

3 √90 = 3 x 3 √10 = 9√10

Given that:

CI = ₹408

years = 2 years

Rate of interest = 4%

A = P{1+(R/100)}^

A-P = p{1+(R/100)}^n - P

I = P[1+(R/100)}^n - 1]

408 = P[{1+(4/100)²} - 1]

= P[{1+(1/25)²} - 1]

= P[(26/25)² - 1]

= P[(676/625) - 1]

= P[(676-625)/625]

408 = P(51/625)

P = 408*(625/51)

= 8*625 = 5000

Sum = 5000

Simple Interest (I) = (P*R)/100

= 5000*2*(4/100)

= 50*2*4 = 400

From the given above options, option (a) ₹400 is your correct answer.

I am doing fine thanks bro.

Answer:

Step-by-step explanation:

11)  y = -1x - 2

12)  y = -(3/2)x + 3

13)  y = 3x - 2

14)  y = (3/4)x + 1

15)  y = (1/2)x + 1

16)  y = -(2/5)x

17)  y = 7x + 2

18)  y = (4/3)x - 4

Attached graph for 19 and 20

Answer: the y intercept form is y= 4x-1

Step-by-step explanation: let me know if you need to know how I got it

The accurate statements are:

The given parameters are:

[tex]n = 12[/tex] --- number of parts

[tex]r = 10[/tex] --- the radius

(a) The central angle

Between points 1 and 3, there are 2 sections, each of which has a measure of 30 degrees.

So, the measure of the two sections is:

[tex]\theta = 30^o \times 2[/tex]

[tex]\theta = 60^o[/tex]

Hence, (a) is false

(b) The circumference

This is calculated using:

[tex]C = 2\pi r[/tex]

So, we have:

[tex]C = 2 \times 3.14\times 10[/tex]

[tex]C = 62.8[/tex]

Hence, (b) is true

(c) The measure of the minor arc

Between points 12 and 4, there are 4 sections, each of which has a measure of 30 degrees.

So, the measure of the four sections is:

[tex]\theta = 30^o \times 4[/tex]

[tex]\theta = 120^o[/tex]

Hence, (c) is true

(d) The length of the major arc

Between points 3 and 10, there are 7 sections, each of which has a measure of 30 degrees.

So, the measure of the seven sections is:

[tex]\theta = 30^o \times 7[/tex]

[tex]\theta = 210^o[/tex]

The length of the arc is:

[tex]L = \frac{\theta}{360} \times 2\pi r[/tex]

So, we have:

[tex]L = \frac{210}{360} \times 2 \times 3.14 \times 10[/tex]

[tex]L = \frac{13188}{360}[/tex]

[tex]L = 36.3[/tex]

Hence, (d) is false

(e) The length of the minor arc

There is only one section between points 6 and 7

So, the measure of the section is:

[tex]\theta = 30^o[/tex]

The length of the arc is:

[tex]L = \frac{\theta}{360} \times 2\pi r[/tex]

So, we have:

[tex]L = \frac{30}{360} \times 2 \times 3.14 \times 10[/tex]

[tex]L = \frac{1884}{360}[/tex]

[tex]L = 5.2[/tex]

Hence, (e) is true

Read more about segments and arcs at:

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Answer:

-B

-C

-E

Step-by-step explanation:

just took the test...

I got them right

Step-by-step explanation:

We have that

[tex](x + \frac{1}{x} ) {}^{2} = 3[/tex]

We are trying to find the number value so that we can apply in the later equation.

Qe first simplify.

Remeber that

[tex](a + b) {}^{2} = a {}^{2} + 2ab + {b}^{2} [/tex]

Also remeber that

[tex] \frac{1}{x} = {x}^{ - 1} [/tex]

so

[tex](x + x {}^{ - 1} ) {}^{2} = {x}^{2} + 2x {}^{0} + {x}^{ - 2} = 3[/tex]

We then simply remeber that x^0=1 so

[tex] {x}^{2} + 2 + \frac{1}{ {x}^{2} } = 3[/tex]

Multiply both sides by x^2.

[tex] {x}^{4} + 2 {x}^{2} + 1 = 3 {x}^{2} [/tex]

Subtract both sides by 3x^2

[tex] {x}^{4} - {x}^{2} + 1 = 0[/tex]

Notice that x^4= (x^2)^2.

So our reformed equation is

[tex]( {x}^{2} ) {}^{2} - {x}^{2} + 1 = 0[/tex]

Let a variable , w equal x^2. This means that we subsitute variable, w in for x^2.

[tex]w {}^{2} - w + 1 = 0[/tex]

Now we use the quadratic formula

[tex] w = \frac{ - b + \sqrt{b {}^{2} - 4ac } }{2a} [/tex]

and

[tex]w = - b - \frac { \sqrt{b {}^{2} - 4ac } }{2a} [/tex]

Let a=1 b=-1 and c=1.

[tex]w = \frac{1 + \sqrt{1 - 4(1)} }{2} [/tex]

[tex]w = \frac{1 - \sqrt{1 - 4} }{2} [/tex]

Now, we get

[tex]w = \frac{1}{2} + \frac{i \sqrt{3} }{2} [/tex]

and

[tex]w = \frac{1}{2} - \frac{ i\sqrt{3} }{2} [/tex]

Now since we set both of these to the x^2 we solve for x.

and

[tex] {x}^{2} = \frac{1}{2} + \frac{i \sqrt{3} }{2} [/tex]

and

[tex] {x}^{2} = \frac{1}{2} - \frac{i \sqrt{3} }{2} [/tex]

We can represent both of these as complex number in the form of a+bi. Next we can convert this into trig form which is

[tex] {x}^{2} = 1( \cos(60) + i \: \sin(60) [/tex]

and

[tex] {x}^{2} = 1( \cos(300) + i \: sin(300))[/tex]

Next we take the sqr root of 1 which is 1, and divide the degree by two.

[tex] {x} = 1( \cos(30) + i \: sin \: 30)[/tex]

and

[tex]x = 1( \cos(150) + i \: sin(150)[/tex]

We are asked for the 2nd root so just add 180 degrees to this and we have

[tex]x = 1 \cos(210) + i \: sin \: 210)[/tex]

and

[tex]x = 1( \cos(330) + i \: sin(330)[/tex]

which both simplified to

[tex]x = - \frac{ \sqrt{3} }{2} - \frac{1}{2} i[/tex]

and

[tex]x = \frac{ \sqrt{3} }{2} - \frac{1}{2} i[/tex]

Now we must find

x^18+x^12+x^6+1.

We just use demovire Theorem. Which is a complex number raised to the nth root is

[tex] {r}^{n} (cos(nx) + i \: sin(nx)[/tex]

So let plug in our first root.

[tex]1( \cos(330 \times 18)) + i \: sin \: (330 \times 18))) + 1( \cos(12 \times 330)) + i \: sin(12 \times 330) + 1( \cos(6 \times 330) + i \: sin(6 \times 330))) + 1[/tex]

To save time we multiply the angle and use rules of terminals angle and we get

[tex]1( \cos(180) + i \sin(180) ) + 1( \cos(0) + i \: sin \:( 0) + 1( \cos(180) + i \: sin(180) + 1[/tex]

And we get

[tex] - 1 + 1 + - 1 + 1 = 0[/tex]

So one of the answer is x=0

And the other, let see

[tex]1 \cos(210 \times 18) + i \: \sin(210 \times 18) + 1 \: cos(210 \times 12) + i \: sin(210 \times 12) + 1 \cos(210 \times 6) + \:i sin(210 \times 6) + 1[/tex]

[tex] \cos(180) + i \: sin(180) + 1 \cos(0) + i\sin(0) +1( \cos(0) + i \sin(0) + 1[/tex]

We get

[tex] - 1 + 1 + 1 + 1 = 2[/tex]

So our answer are 2.

So the answer to the second part is

0 and 2.

Answer:

An isosceles triangle has two side lengths the same and one different.

Step-by-step explanation:

Answer:

The answer would be -12, I'm not to sure what simplify means

Answer:

Step-by-step explanation:

i think it true if right mark me as brainiest and thank

Answer:

Step-by-step explanation:

The median is the line segment connecting the vertex with the midpoint of the opposite side.

The midpoint has coordinates:

Use the distance formula to find the distance between points (2, 7) and (1, 2):

Step-by-step explanation:

the formula for the length of a median based on the 3 side lengths is

m = sqrt(2AB² + 2AC² - BC²)/2

where BC is the side opposite of the indicated vertex.

let's say

A = (2, 7)

B = (-3, 3)

C = (5, 1)

AB² = (2 - -3)² + (7 - 3)² = 5² + 4² = 25 + 16 = 41

AC² = (2 - 5)² + (7 - 1)² = (-3)² + 6² = 9 + 36 = 45

BC² = (-3 - 5)² + (3 - 1)² = (-8)² + 2² = 64 + 4 = 68

m = sqrt(2×41 + 2×45 - 68)/2 = sqrt(82+90-68)/2 =

= sqrt(104)/2 = sqrt(104/4) = sqrt(26) =

= 5.099019514...