The length of the rectangle is 10.4cm. the perimeter of the rectangle is 28cm. calculate the area of the rectangle.

Using sampling concepts, it is found that:

a) The best method is: 25 adult residents are randomly selected from the city;

b) The estimate is that 11,536 adults voted in the election.

It is a common statistics practice, when we want to study something from a population, we find a sample of this population, which is a group containing elements of a population. A sample has to be representative of the population, that is, it has to involve all segments of the population.

In this problem, the sample will be representative if all adults, no matter if senior or not, homeowners or not are represented, hence the best method is:

25 adult residents are randomly selected from the city;

The estimate of the number of adults that voted is:

14/25 x 20,600 = 11,536.

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The best explanation for why the rotation is isometric is "The rectangle did not change shape or size". Hence the second option is the right choice.

There are four main categories of transformations:

A stiff transformation known as an isometry maintains perimeter and area while also preserving length and angle measurements. In other words, there is congruence between the preimage and the image. Translations, reflections, and rotations are therefore isometric, but dilations are not since the image and preimage are comparable, rather than congruent figures.

The transformation in the question will be isometric when the preimage of the rectangle before 360° rotation, will be congruent to the image after the rotation.

The congruency is best described by the option "The rectangle did not change shape or size", as that is the basis of congruency.

Thus, the best explanation for why the rotation is isometric is "The rectangle did not change shape or size". Hence the second option is the right choice.

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The provided question is incomplete. For the complete question, refer to the attachment.

[tex] {\qquad\qquad\huge\underline{{\sf Answer}}} [/tex]

Here we go ~

[tex]\qquad \sf  \dashrightarrow \: (f + g)(x)[/tex]

[tex]\qquad \sf  \dashrightarrow \: f(x) + g(x)[/tex]

[tex]\qquad \sf  \dashrightarrow \: (4 {x}^{2} - 5x) + (3 {x}^{2} + 6x - 4)[/tex]

[tex]\qquad \sf  \dashrightarrow \: 7 {x}^{2} + x - 4[/tex]

Answer:

Step-by-step explanation:

If the lines are parallel, it means that the slopes are the same.  To write an equation in the slope intercept form, we need the slope and the y-intercept.  We are given the slope.  We need to find the y-intercept.  We can use the slope and the point to help us.  The point is written in the form (x,y).  In this case the point is (2,4) so we will use 2 for x and 4 for y.

y = mx + b  Plug in what we know

4 = -4(2) + b  b is what we are looking for.  It is the y-intercept

4 = -8 + b  Now add 8 to both sides

12 = b

Now we can write the equation:

y = -4x +12

The value of du becomes 4 by integration.

According to the statement

we have given a two statement which are u - 4x and  u = x + 1.

And we have to find the value of du by the use of integration.

An Integral assigns numbers to functions in a way that describes the data.

So,

From u  - 4x

here du becomes by derivative

du - 4dx/du

du = 4dx/du.  -(1)

And in u = x + 1.

here du becomes

du = dx/du  -(2)

by comparing both terms from equation (1) and (2) we get the value of du

du = 4.

the value of du is 4.

So, The value of du becomes 4 by integration.

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The five-number summary are as follows:

The five-number summary is a set descriptive statistics which consist of the minimum, maximum, median, upper quartile, and lower quartile of a data distribution.

Therefore,

Given:

58, 60, 65, 67, 68, 72, 79, 79, 80, 81, 82, 86, 86, 87

Therefore,

Minimum = 58

Lower quartile(Q₁) = 67

Median = 79 + 79 / 2 = 79

Upper quartile(Q₃) = 82

Maximum = 87

Interquartile range = Q₃ - Q₁ = 82 - 67 = 15

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By applying Pythagorean theorem, we have proven that the point (-1/2, -√3/2) lies on the unit circle.

In Trigonometry, an angle with a magnitude of -120° is found in the third quarter and as such, both x and y would be negative. Also, we would calculate the reference angle for θ in third quarter as follows:

Reference angle = 180 - θ

Reference angle = 180 - 120

Reference angle = 60°.

For the coordinates, we have:

sin(-120) = -sin(60) = -1/2.

cos(-120) = -cos(60) = -√3/2.

By applying Pythagorean theorem, we have:

z² = x² + y²

z = √((-1/2)² + (-√3/2)²)

z = √(1/4 + 3/4)

z = √1

z = 1.

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Answer:

[tex]\frac{32\pi }{9}[/tex] or [tex]11.17[/tex]

Step-by-step explanation:

[tex]2\pi 8(\frac{80}{360} )[/tex]

[tex]=16\pi (\frac{80}{360} )[/tex]

[tex]=16\pi (\frac{2}{9})[/tex]

[tex]=\frac{32\pi }{9}[/tex]

[tex]\huge\text{Hey there!}[/tex]

[tex]\huge\textbf{Assuming the equation is:}[/tex]

[tex]\mathsf{(12.3)^2 - (0.246 \div 3)}[/tex]

[tex]\huge\textbf{If so, let's start simplifying it:}[/tex]

[tex]\mathsf{(12.3)^2 - (0.246 \div 3)}[/tex]

[tex]\mathsf{= (12.3\times 12.3) - (0.246 \div 3)}[/tex]

[tex]\mathsf{= (151.29) - (0.246 \div 3)}[/tex]

[tex]\mathsf{= 151.29 - 0.246 \div3}[/tex]

[tex]\mathsf{= 151.29 - 0.082}[/tex]

[tex]\mathsf{= 151.208}[/tex]

[tex]\huge\textbf{Therefore, your answer should be:}[/tex]

[tex]\large\boxed{\mathsf{Exactly \rightarrow} \frak{\ 151.208\ } \& \textsf{ Corrected to two significant figures}\rightarrow \frak{150 \ or \ 151}}\large\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

Due to its subject-specific classification, ink color in pens is a qualitative variable.

Consequently, option (C) is the appropriate choice.

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Based on the graph of the function (F(x) = log6x), the following facts are true:

A graph is a type of chart that is used to graphically represent data on both the horizontal and vertical lines of a Cartesian coordinate i.e x-axis and y-axis.

By critically observing the graph of the function (F(x) = log6x) attached in the image below, we can infer and logically deduce that its domain and range include all real numbers that are greater than 0 (x > 0).

This ultimately implies that, the following facts are true:

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Complete Question:

Which facts are true for the graph of the function below? Check all that apply. F(x) = log6 x

A. It is increasing.

B. The range is y > 0.

C. The x-intercept is (1, 0).

D. It is decreasing.

E. The y-intercept is (0, 6).

F. The domain is x > 6.

Answer:

300 dollars

Step-by-step explanation:

Note that:

{Peter's revenue on Monday: 150 dollars

Peter's revenue on Tuesday: 100 dollars

Peter's revenue on Wednesday: 50 dollars}

---------------------------------------------------------------

In this problem, we need to find how much is Peter's revenue so far (total).

We need to use addition to determine how much Peter's revenue is in total.

So, add 150, 100, and 50.

We get 150 + 100 + 50 = 300

Finally, Peter's revenue in total is 300 dollars.

Answer:

$300

Step-by-step explanation:

add 150+100+50

=300

Answer:

bvjh

Step-by-step explanation:

bn

Answer:

abscissa of A = -3

ordinate of B = -6

A+B = -3+(-6)= -3-6=

-9

Answer:

Step-by-step explanation:

hello :

1)

the equation is : f(x)= a(x+1)(x-2)  because : x- ints of -1 and 2  means :

f(-1)=0 and f(2)=0

calculate : a   given f(4)=10

so :  a(4+1)(4-2)=10

10a =10   so : a = 1

the equation is : f(x)= (x+1)(x-2)

2) and 3) same method but   * y int of -3* meanes : f(0)= - 3

Answer:

see explanation

Step-by-step explanation:

- 3 | 5x + 6 | + 1 ≥ 6

First step : subtract 1 from both sides

- 3 | 5x + 6 | ≥ 5

For the square with side length n, the diagonal measures:

[tex]d = \sqrt{2} *n[/tex]

The sidelength of the square is n, and we want to get the length of the diagonal d.

Notice that the diagonal is the hypotenuse of a right triangle whose catheti measure n.

Then we can use the Pythagorean theorem, which says that the square of the hypotenuse is equal to the sum of the squares of the cathetus;

[tex]d^2 = n^2 + n^2\\\\d^2 = 2n^2\\\\d = \sqrt{2n^2} \\\\d = \sqrt{2}*n[/tex]

That is the length of the diagonal.

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Answer:

7

Step-by-step explanation:

1, 1, 2, 4, 7, 8, 10, 15, 20

median = 7

The correct option regarding whether the equation x² = y² is a function is:

No, since if you solve the equation for x, then [tex]x = \pm y[/tex]

In a function, each value of x can be associated with only one value of y.

In this problem, the equation is:

[tex]x^2 = y^2[/tex]

Then:

[tex]x = \pm \sqrt{y^2}[/tex]

[tex]x = \pm \sqrt{y}[/tex]

x is associated with two values, [tex]-\sqrt{y}[/tex] and [tex]\sqrt{y}[/tex], hence it is not a function.

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Answer:

Vertex - (2, -1)

Axis of Symmetry - x = 2

X intercept - (3,0) (1, 0)

Y intercept (0, 3)

Domain - (negative infinity, positive infinity)

Range - [-1, infinity)

Step-by-step explanation:

I graphed with desmos and found it.

The  sum of the links of the two parallel sides is 5cm

The formula for calculating the area of a trapezoid is expressed as:

A = 0.5(a+b)h

where

h is the height of the trapezoid

a+b is the sum of the sides

Substitute

20 = 0.5(a+b)8

40 = 8(a+b)

a+b = 40/8

a+b = 5cm

Hence the  sum of the links of the two parallel sides is 5cm

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Using the law of cosines, it is found that the distance across the lake is of 978.5 feet.

The law of cosines states that we can find the angle C of a triangle as follows:

[tex]c^2 = a^2 + b^2 - 2ab\cos{C}[/tex]

in which:

In this problem, the parameters are:

a = 800, b = 900, C = 70º.

Hence the distance across the lake is c, found as follows:

[tex]c^2 = a^2 + b^2 - 2ab\cos{C}[/tex]

c² = 800² + 900² - 2(800)(900)cos(70º)

c² = 957491

[tex]c = \sqrt{957491}[/tex]

c = 978.5.

The distance across the lake is of 978.5 feet.

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It takes Jay, Elle and Kay to work individually for 70 minutes, 105 minutes and 52.5 minutes respectively

A ratio can sometimes be regarded as fraction. While rate has something to do with time.

Given that Jay and Kay can pack the shelves in one aisle of the supermarket in 30 minutes. Kay and Elle take 35 minutes to do the same job. When Jay and Elle work together, the job takes 42 minutes.

Let

The interpretation of the question go thus;

1/J + 1/K = 1/30 ........ (1)

1/K + 1/E = 1/35 .........(2)

1/J + 1/E = 1/42 .........(3)

Make 1/J and 1/E the subject of formula in equation 1 and 2 respectively and substitute them in equation 3

1/J = 1/30 - 1/K  ........ (4)

1/E = 1/35 - 1/K  .........(5)

1/30 - 1/K + 1/35 - 1/K = 1/42

Collect the like terms

- 1/K - 1/K = 1/42 - 1/30 - 1/35

-2/K = (35 - 49 - 42)/1470

-2/K = -56/1470

1/K = 28/1470

Reciprocate both sides

K = 1470/28

K = 52.5 minutes.

Substitute K in both equation 4 and 5

1/J = 1/30 - 28/1470

1/J = (49 - 28)/1470

1/J = 21/1470

Reciprocate both sides

J = 1470/21

J = 70 minutes

1/E = 1/35 - 28/1470

1/E = (42 - 28)/1470

1/E = 14/1470

Reciprocate both sides

E = 1470/14

E = 105 minutes

Therefore, it takes Jay, Elle and Kay to work individually for 70 minutes, 105 minutes and 52.5 minutes respectively

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This is considered as decision making under risk.

Decision Making Under Risk

A circumstance in which the implications of the chosen course of action and the likelihood that it will occur are understood is referred to as decision-making under risk . For instance, the lottery selection tasks are frequently employed to examine the nature of decision-making in risky situations.

We make the assumption that there are two or more choices and that each alternative's characteristics are explicitly specified. For each attribute, the CV (coefficient of variation) is configured in case of such decision under risks. And, since in the given question, decision maker is supposed to consider several possible outcomes for each alternative, each with a given probability of occurrence. Thus the decision made will be decision under risk.

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Answer:

X-19

Step-by-step explanation:

First you need to distribute the three into the numbers in the parenthesis,

(3 * x) + (3  * -5) - (2x + 4)

That then turns into,

3x - 15 - (2x + 4)

but we aren't done distributing yet, because the second set of parenthesis has a negative sign in front of it we also have to distribute that. (this is because the negative sign is really just -1)

3x - 15 + (-1 * 2x) + (-1 * 4)

that turns into,

3x - 15 - 2x -4

from here all we have to do is add like terms,

(3x - 2x) + (-15 + -4)

and that leaves us with: 1x -19 or x-19

Hope that helped :))  

The line plot shown C in the figure is correct.

Given that the recorded lengths of ribbon pieces which is used in project is [tex]11\frac{1}{4},11\frac{1}{4},10\frac{3}{4},10\frac{1}{2},10\frac{7}{8},10\frac{5}{8},9\frac{7}{8},11\frac{1}{4}[/tex].

Frequency refers to the number of times an event or  value occurs. A frequency table is a table that lists items and shows how many times those items occurred.

A line plot displays the data using a no. line.

Firstly, we will fimd the frequency of each value

Values                               Frequency

9 (7/8)                                        1

10(4/8)=10(1/2)                           1

10(5/8)                                       1

10(6/8)=10(3/4)                          1

10(7/8)                                       1

11(2/8)=11(1/4)                             3

Option A is incorrect because 11(2/8) has no data values in the line plot (i.e. frequency = 0)

Option B is incorrect because 11(2/8) has no data values in the line plot (i.e. frequency = 0)

Option C is correct because the frequency distribution of the data is represented correctly in the line plot.

Option D is incorrect because 11(2/8) has 2 data values in the line plot (i.e., frequency = 2)

Hence, the line plot which correct shows the data is third line plot.

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Answer:

In total she got $555 so we have to divide that to see how much she got per hour.

Step-by-step explanation:

y/x=?

$555/15= $37

Now how much money multiplied by how many hours

$37 X 15 = $555

I hope this helps, if you need any more information just comment!

Have an Amazing Day!!!

Question 11

1) [tex]\overline{BA} \cong \overline{FA}[/tex], [tex]\angle 1 \cong \angle 2[/tex] (given)

2) [tex]\angle A \cong \angle A[/tex] (reflexive property)

3) [tex]\triangle AEB \cong \triangle ACF[/tex] (ASA)

4) [tex]\overline{AC} \cong \overline{AE}[/tex] (CPCTC)

Question 12

1) Isosceles [tex]\triangle ACD[/tex] with [tex]\overline{AC} \cong \overline{AD}[/tex], [tex]\overline{BC} \cong \overline{ED}[/tex] (given)

2) [tex]\angle ACD \cong \angle ADC[/tex] (angles opposite congruent sides in a triangle are congruent)

3) [tex]\angle ACB[/tex] and [tex]\angle ACD[/tex] are supplementary. [tex]\angle ADC[/tex] and [tex]\angle ADE[/tex] are supplementary (angles that form a linear pair are supplementary)

4) [tex]\angle ACB \cong \angle ADE[/tex] (supplements of congruent angles are congruent)

5) [tex]\triangle ABC \cong \triangle AED[/tex] (SAS)

6) [tex]\overline{AB} \cong \overline{AE}[/tex] (CPCTC)

7) [tex]\triangle ABE[/tex] is an isosceles triangle (a triangle with two congruent sides is isosceles)

Note: I changed the names of the segments in Question 11 because of the word filter.