The leg lengths of a right triangle are 14 in and 26 in. What is the length of the missing side?

Answer:

256x^8

Step-by-step explanation:

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22 + 22 x r = 30

22 x r = 30 - 22

r = 8 : 22

r = +36,36%

r = increase rate

Answer:

Step-by-step explanation:

Anything going from lower left to upper right is a positive slope.

The lines are not easily seen. My best estimate is that one point is (2,5)

Use the two points you are sure of.

(0,-1) and (1,2)

Givens

Formula

m = (y2 - y1)/(x2 - x1)

Solution

m = (2 - - 1) / (1 - 0)

m = 3/1

m = 3

Answer:

Step-by-step explanation:

congruent sides

Answer:

soIve the congcreunt sides

Step-by-step explanation:

then ask ur parents

Answer:

The quotient of these numbers is 1.7 × 10⁴

Scientifically in the notion, these would be the correct numbers.

The quotient of the given numbers is 1.7×10⁴.

Scientific notation is a method for expressing a given quantity as a number having significant digits necessary for a specified degree of accuracy, multiplied by 10 to the appropriate power such as 1.56×10⁷.

The given numbers are 7.14×10⁷ and 4.2×10³.

Here, quotient = 7.14×10⁷ ÷ 4.2×10³

= 1.7×10⁴

Therefore, the quotient of the given numbers is 1.7×10⁴.

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Answer:

1996

Step-by-step explanation:

because the line chart started st 1996

The value of the hypotenuse y will be equal to y = 2.8 inches.

The volume of the prism is equal to the product of the area of its base and the height of the prism.

[tex]\rm V=Area \ of\ triangular \ base\times Height \ of \ prism[/tex]

The volume oif the prism is =4 cubic inches

Height of the prism = x inches

Base of the right angle isosceles triangle will be =x inches

The hypotenuse is given = y

Now

[tex]\rm V=\dfrac{1}{2}\times Base\times Height \times height \ of \ prism[/tex]

[tex]V=\dfrac{1}{2} \times x \times x \times x[/tex]

[tex]x^3=8[/tex]

[tex]x=2[/tex]

Now by pythagorus theorem

[tex]y^2=h^2+b^2[/tex]

[tex]y^2=x^2+x^2[/tex]

[tex]y^2=2x^2=2\times 2^2[/tex]

[tex]y=2\sqrt{2}=2.82[/tex]

Thus the value of the hypotenuse y will be equal to y = 2.8 inches.

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Answer:

2.8 INCHES

Step-by-step explanation:

Answer:

Choice a 10 cm

Step-by-step explanation:

Volume of a sphere; 4/3 x 3.14(r^3)

Since we dont know the radius aka r, we can put in the different values until we get what we are looking for :)

!!!used an online calculator for this!!!

Choice a: 4188.79

Choice b: 50965.01

Choice c: 38792.39

Choice d: 5575.2

Since none of the answers are coming out as 4846.59, I would go with the closest one, choice a.

I really hope this helps!!

Please rate!!

Have a wonderful day!!

Answer:

59.319

Step-by-step explanation:

V=a3=3.93≈59.319

Answer: A, TRUST ME!

Step-by-step explanation:

Answer:

945 in²

Step-by-step explanation:

The scale factor of two figures is k.

The scale factor of their surface areas is k².

The scale factor of their volumes is k³.

1024 in² / 576 in² = 16/9 = k²

k = √(16/9) = 4/3

k³ = (4/3)³

k³ = 64/27

2240 in³ × 27/64 = 945 in²

Answer:

I would choose the $400 raise

Step-by-step explanation:

Well 15% of 2000 would be $300 dollar raise so i would choose the $400 dollar raise instead of the $300 raise because I get more money.

If it was a 10% raise you would get $200 dollar raise

If it was 8% raise you would get $160 dollar raise

And if it was a 5% raise you would get a $100 dollar raise

The length of arc of the given circle, to the nearest hundreth, is: 2.41 units.

Length of arc = ∅/360 × 2πr, where the radius of the circle is r, and the reference angle is ∅.

We are given the following:

Radius (r) = 3 units

Reference angle (∅) = 46°

Plug in the values into the length of arc formula:

Length of arc = 46/360 × 2π(3)

Length of arc = 2.41 units.

Therefore, the length of arc of the given circle, to the nearest hundreth, is: 2.41 units.

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Answer:

Step-by-step explanation:

Refer to the definition of a function. I'll just give you a layman's definition to be concise.

For something to be a function, there needs to be exactly 1 output for every input. You cannot have a case where you input 1 value, and get 2 or more values as an output.

In math we call all the possible input values the domain, and we call all the possible output values the range.

Let's take a look at each situation on your worksheet.

1. Is a function. This is because only one arrow stems from each input value. There are cases where the different input values give the same output, sure, but each input returns 1 discrete thing, not an array of things.

(Think of it this way, if i had a machine that could answer any question I had with yes, no or maybe. I wouldn't want the machine to give me "yes and maybe" or "yes and no" as the result when I ask it a question. That doesn't make sense and I would think the machine is broken. What could happen, is that I ask the machine different questions, and for those different questions, it gave me the same answer, like "yes" and "yes" respectively. in that case, it would be acceptable, because it isn't contradicting itself for any individual question.)

2. Not a function. There are 2 different output values for b.

(Refer back to my machine analogy. The "machine" in this question is contradicting itself. I gave the machine one input, and the machine is telling me, "it's this and actually it's this other thing too")

3. Is a function for the same reasons as 1.

4. Isn't a function.

(It's basically telling you, the machine reads -6 as -4, but it also reads -6 as 0, and also 2. And it also tells you the machine reads -4 as -3, but it also reads it as 8. Again, the machine should only read 1 input in 1 way and not contradict itself. )

Answer:

h = 24 cm

Step-by-step explanation:

Let [tex]x[/tex] = height of ΔCBD

Let [tex]h[/tex] = height of ΔABE

As ΔABE ~ ΔCBD then AE : CD = [tex]h[/tex] : [tex]x[/tex]

Given:

[tex]\implies 20 : 10 = h : x[/tex]

[tex]\implies \dfrac{20}{10}=\dfrac{h}{x}[/tex]

Cross multiply:

[tex]\implies 20x=10h[/tex]

Simplify:

[tex]\implies 2x=h[/tex]

As we are told that [tex]x+h=36 \ \sf cm[/tex]

[tex]\implies h=36-x[/tex]

Equate the two equations for [tex]h[/tex] and solve for [tex]x[/tex]:

[tex]\implies 2x=36-x[/tex]

[tex]\implies 3x=36[/tex]

[tex]\implies x=12[/tex]

Since [tex]h=2x[/tex] then

[tex]\implies h=2 \cdot 12[/tex]

[tex]\implies h=24 \ \sf cm[/tex]

Answer:

The states of the variables must be equal to the equations of the whole equation, There is no relative extreme in this equation, so its derivative y = 10

Step-by-step explanation:

[tex]y = 600 + 10x = f(x) = 600 + 10x[/tex]

[tex]y = 10[/tex]

Answer:

25.1

Step-by-step explanation:

for perimeter you just add them all together

Answer:

that's 4 and 7 .............

Answer:

Answer:

Step-by-step explanation:

Isolate the term of x and y from one side of the equation.

3x+y=8 and 6x+2y=10

x=8-y/3

Solve.

Rewrite the problem down.

6*8-y/3+2y=10

Then, solve.

16=10

Therefore, the final answer is no solution.

I hope this helps you! Let me know if my answer is wrong or not.

Answer:

Side A is 4

Step-by-step explanation:

Answer:

A.4

Step-by-step explanation:

a = √(c² - b²)

a= √(5² -3b²)=4

Answer: 10.62 irrational

Step-by-step explanation: You can divide 69.15 by 5.25 which equals 74.4 then divide by 7 which equals 10.62

Answer:

Step-by-step explanation:

k (a+b) = k*a + k*b

so

7 (4-x) = 7*4 + 7*(-x) = 28 - 7x

Using an exponential function, it is found that the amounts deposited at the end of each month are given by:

An increasing exponential function is modeled by:

[tex]A(t) = A(0)(1 - r)^t[/tex]

In which:

In this problem, we have that A(0) = 100, r = 0.1, hence the equation for the amount deposited after t months is:

[tex]A(t) = 100(1.1)^t[/tex]

Then, for each of the first four months:

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The average squared distance between the points is their variance

The average squared distance is 8/3

The given parameters are:

R={(x,y): 0<=x<=2, 0<=y<=2}

The point = (2,2).

f(x,y) = (x-2)² + (y-2)²

The squared distance is calculated as:

D² = f(x,y) = (x-2)² + (y-2)²

Where the area (A) is:

A = xy

Substitute the maximum values of x and y in A = xy

A = 2 * 2

A = 4

The minimum values of x and y are 0.

So, the limits for the integrals are 0 to 2

The integral becomes

[tex]D\² = \int \int (x-2)\² + (y-2)\² dx dy[/tex]

Expand

[tex]D\² = \int \int x\² -4x + 4 + (y-2)\² dx dy[/tex]

Evaluate the inner integral with respect to x from 0 to 2

[tex]D\² = \int \frac 13x^3 -2x^2 + 4x + x(y-2)\² |\limits^2_0 dy[/tex]

Expand

[tex]D\² = \int [\frac 13(2)^3 -2(2)^2 + 4(2) + (2)(y-2)\²] dy[/tex]

Simplify

[tex]D\² = \int \frac 83 + (2)(y-2)\² dy[/tex]

Expand

[tex]D\² = \int \frac 83 + 2y^2-8y + 8 \ dy[/tex]

Evaluate the integral with respect to y from 0 to 2

[tex]D\² = [\frac 83y + \frac 23y^3- 4y^2 + 8y ]|\limits^2_0[/tex]

Expand

[tex]D\² = \frac 83*2 + \frac 23*2^3- 4*2^2 + 8*2[/tex]

D² = 32/3

The average squared distance (AD²) is calculated as:

AD² = D²/A

So, we have:

AD² = 32/3 [tex]\div[/tex] 4

Evaluate the quotient

AD² = 32/12

Simplify

AD² = 8/3

Hence, the average squared distance is 8/3

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The average squared distance between the points of R = {(x,y): 0<=x<= h, 0<=y<=k } is 8/3.

How do determine the average squared distance?

From the given parameters R = {(x,y): 0<=x<= h, 0<=y<=k }

The squared distance from point (h, k) is calculated as

D² = f(x,y) = (x-2)² + (y-2)²

Where the area (A) will be

A = xy

Substitute the maximum values of x and y

A = 2 × 2 = 4

The minimum values of x and y are 0.

So, The integral becomes

[tex]D^{2} = \int \int(x-2)^2 +(y-2)^2 dx dy\\\\D^{2} = \int \int\limits^2_0 (x)^2 -4x + 4+(y-2)^2 dx dy\\\\D^{2} = \int1/3(x)^3-2x^{2} +4x + 4+x(y-2)^2 dy\\\\D^{2} = \int8/3+2y^{2} -8y +8 dy[/tex]

[tex]D^2 = {8/3y +2/3y^2 -4y^2+8y[/tex]

By expanding we get,

D^2 = 32/3

The average squared distance (AD²) is calculated as:

AD² = D²/A

AD² = 32/3  4

AD² = 32/12

AD² = 8/3

Hence, the average squared distance is 8/3

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a = 2, b = -18, c = 40

[tex]Given:\ Polynomial\ f(x)=ax^2+bx+c\ has\ zoroes\ 4\ aud\ 5[/tex]

[tex]and\ f(-1)=60[/tex]

[tex]Tofind:\ a,\ b,\ c[/tex]

[tex]Solution:\ As\ 4\ and\ 5\ are\ zeroes\ so\ f(4)=f(5)=0[/tex]

[tex]f(4)=a(4)^2+b(4)+c=0\Rightarrow16a+4b+c=0-(1)[/tex]

[tex]f(5)=a(5)^2+b(5)+c=0\Rightarrow25a+5b+c=0[/tex]

[tex]f(-1)=a(-1)^2+b(-1)+c=60\Rightarrowa-b+c=60-(3)[/tex]

[tex]subtracting\ (1)\ from\ (2)[/tex]

[tex]25a+5b+c-(16a+4b+c)=0\Rightarrow9a+b=0\Rightarrowb=-9a[/tex]

[tex]subtracting\ (3)\ from(2):[/tex]

[tex]25a+5b+c-(a-b+c)=0-60\Rightarrow24a+6b=-60[/tex]

[tex]putting\ b=-9a[/tex]

[tex]24a+6(-9a)=-60\Rightarrow24a-54a=-60\Rightarrow-30a=-60[/tex]

[tex]a=\frac{-60}{-30}=2[/tex] [tex]\Rightarrow[/tex] [tex]a=2[/tex]

[tex]b=-9a=-9\times2=-18[/tex]

[tex]c=-a+b\neq60=-2-18+60=-20+60=40[/tex]

I hope this helps you

:)

Answer:

please rate and mark as brainlest.

Step-by-step explanation:

(i) 1/20

(ii)

a.708.22

b.8635.4

c.147.392

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Answer:

60 cm

Step-by-step explanation:

The perimeter of a polygon means adding up all the side lengths.

In this case, we need to add up 13, 12, 8, 8, and 19

Adding all of these gets us 60

Answer:

5x/1/2 = 1x



answer  1.12 <3


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Step-by-step explanation: