Answer:
Given: a projectile of initial launch velocity(V) and launch angle ∅ and no air resistance. At the maximum height, the projectile would have a zero contribution of speed from the vertical component(Vy) Therefore, if we say Vx=Vcos∅ is the only speed the projectile has at the instant of maximum height then we can replace Vx with 1/5V and write 1/5V=Vcos∅. Solving for the the launch angle ∅, gives Inverse Cos(1/5)=78.5 degrees.
A chemist is studying an unknown substance and could break the substance into its elemental components only by using chemical means. Based on this observation, how should the unknown substance be classified?
A. impure substance
B. solution
C. mixture
D. pure substance
The answer is D
I took the quiz lol
what are the three examples that show relation between pressure and area in daily life.
Answer: The area of the edge of a knife's blade is extremely small.
Syringes are used to take blood for blood tests.
When air is sucked out of a drinking straw, the air pressure inside if decreases and the atmospheric pressure outside forces the liquid to go inside the straw.
Explanation:
If a train is moving south at 50 m/s and a person is running SOUTH on the train at 5 m/s, what is the velocity of the person as seen by someone not moving (watching the train going by)
A-45 m/s North
B-50 m/s South
C-55 m/s North
D-100 m/s South
The velocity of the person as seen by someone not moving (watching the train going by) will be 55 m/s South. I can therefore conclude that none of the option given is correct.
Given that a train is moving south at 50 m/s and a person is running SOUTH on the train at 5 m/s.
That means the person is running relatively to the velocity of the train. Since the train and the person are moving in the same direction, the relative velocity seen by an observer watching the train going will be the addition of both the train and the person in the direction of the train.
That is,
Relative velocity = 50 + 5
Relative velocity = 55 m/s South.
Therefore, the velocity of the person as seen by someone not moving (watching the train going by) will be 55 m/s South.
I can therefore conclude that none of the option given is correct.
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why do air waves move faster than earthquake waves?
Answer:
P-waves and S-waves are body waves that propagate through the planet. P-waves travel 60% faster than S-waves on average because the interior of the Earth does not react the same way to both of them. ... The energy is thus less easily transmitted through the medium, and S-waves are slower.
Explanation:
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PLEASE ANSWER NEED HELP!!!!!!!! PLEASE THE CORRECT ANSWER!!!!!!
Zhiyu wants to start an exercise program. He knows that he should talk to his doctor, but he cannot get an appointment for several weeks. He does not have any health conditions. What is the BEST advice for Zhiyu?
A.
All exercise needs to be medically supervised, so he must wait.
B.
There is always a risk of injury, so he needs professional advice before he starts.
C.
He can start slowly with low impact activity like walking or light weightlifting.
D.
He should do whatever he feels like; his body will let him know if he overdoes it.
PLEASE NO LINKS OR I WILL REPORT YOU
Answer:
c
Explanation:
a gas increases in pressure from 2.00 atm to 6.00 atm at a constant volume of 1.00 m3 and then expands at constant pressure to a volume of 3.00 m3 before returning to its initial state as shown in the figure below. how much work is done in one cycle?
The work done on the given gas in one cycle is -405.3 kJ.
The given parameters;
initial pressure of the gas, P₁ = 2 atmfinal pressure of the gas, P₂ = 6 atminitial volume of the gas, V₁ = 1 m³final volume of the gas, V₂ = 3 m³Convert the pressure to Pascal (N/m²);
1 atm = 101325
The work done in one cycle is the area of the triangle and it is calculated as follows
[tex]Area = \frac{1}{2} \times base \times height\\\\Area = \frac{1}{2} \times (3 \ m^3\ -\ 1 \ m^3)\times (6 \ atm \ - \ 2 \ atm)\\\\Area = 4 \ atm -m^3\\\\Area = 4 \ atm -m^3 \ \times \frac{101325 \ Pa}{1 \ atm} \\\\Area = 405,300 \ m^3.Pa\\\\Area = 405,300 \ m^3. (N/m^2)\\\\Area = 405,300 \ Nm\\\\Area = 405,300 \ J\\\\Area = 405.3 \ kJ[/tex]
the net work done on the gas = - 405.3 kJ
Thus, the work done on the given gas in one cycle is -405.3 kJ.
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What electromagnetic wave is used in nuclear research and mineral exploration?.
The electromagnetic wave used in nuclear research and mineral exploration are gamma rays.
Electromagnetic waves refer to those rays that are found in the electromagnetic spectrum. They are collectively called light. Electromagnetic waves are used for different purposes.
Gamma rays are useful in nuclear research especially in identifying decaying radionuclides. Also, gamma rays are used for geologic mapping, mineral exploration, and identification of environmental contamination.
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During a collision, a 63.9-kilogram driver of a car moving at 24 m/s is brought to rest by an inflating airbag in 1.2 seconds. What is the magnitude of the force exerted on the driver by the airbag?
Hi there!
We can use impulse for this situation:
I = Δp = mΔv
Impulse = Force × time, so:
I = 63.9(24) = 1533.6 Ns
Find force by dividing by time:
I/t = 1533.6/1.2 = 1278 N
what tool had allowed scientists to learn about the characteristics of eaths layers???
Answer:
seismic waves
Explanation:
i think thats the answer
Tommy does 45 Joules of work to push the pencil over 3 meter. How much force did he use?
Answer:
Work = Force × Distance
Therefore Force = Work/Distance
= 45 joules/3 metres
= 15 newton
Explanation:
Answer:
15
Explanation:
15
A campfire is a good example of all three types of heat transfer. The molecules of the fire touching the pot and heating it up is __________________. The air above the fire heating up, becoming less dense and rising is an example of _________________. All around the campfire you can feel the waves of heat because of _____________.
someone throws a rubber ball vertically upward from the roof of a building 8.2m in height. the ball rises, then falls.it just misses the edge of the roof, and strikes the ground.if the ball is in the air for 6.2s, what was its initial velocity?(disregard air resistance. a=-g=-10m/s²
Answer:
H = V t - 1/2 g t^2 V and g are in different directions
-8.2 = V * 6.2 - 1/2 * 10 * 6.2*2 = 6.2 V - 192.2
V = 184 / 6.2 = 29.7 m/s
Check: find time for ball to return to zero height
0 = 29.7 T - 5 T^2
T = 29.7 / 5 = 5.94 sec
The ball must have fallen 8.2 m in (6.2 - 5.94) sec = .26 sec
S = 29.7 * .26 + 5 * .26^2 = 8.1
what do u guys think of my drawing?
Answer: yess sirrrrrrrr
Explanation:
Answer:
oou I like it! u did a good job ^^
when a viscous fluid flows in a tube, its velocity is __________.
pls pls pls help i need to know the correct answer and why it’s correct, thanks in advance
What is the relationship between power, work, and time?
A
As the amount of time increases,
power and work both increase.
B
As the amount of time increases,
power and work both decrease.
С
As the amount of time increases,
power increases and work is not affected. D. As the amount of time increases power decreases and work is not affected.
Answer:
it's ans is D because all three are wrong
Can u plz help me with my hw
Answer:
1) 4 x 25m = 100m
2) 0 because after 4 lengths, he's back at the starting block.
3) speed is distance over time so speed here is 100m/125s = 0.8m/s
4) ...
5) 100m / 1.25m/s = 80s
6.a) 100m / 0.5m/s = 200s
7.b) ... can't draw this now..
What is the amount of charge when 13.5a is flowing for 2 1/2 hours
Answer:
Quick Answer:
a. 8.9Ω
b. 1.2×104 C
Explanation:
Answer:
Answer provided in explanation
Explanation:
a girl on a bridge throws a rock straight down at -12.5 m/s. it hits the ground 38.4 m below. How much time did it take?
The acceleration of both the rocks is only due to the gravitational force acting on them. Even though the speed of thrown rock would be greater than that of dropped rock, the acceleration of both the rocks would be g downwards.
Answer:
1.80
Explanation:
38.4=-12.5(a)-1/2(-9.80)(a)^2
a= acceleration
^2 is the exponent
NO LINKS! What are the definitions of initial horizontal velocity and initial vertical velocity? Please help! This like is my 20th time asking this question because many people have been scamming me...
Answer:
answer
Explanation:
The initial horizontal velocity canbe determined by measuring the diameter of the ball and dividing by the time that it takes for the ball to move across the photogate. That is Vo = d/t.
When Vertical velocity refers to the speed of an object's movement in a vertical direction.
an astronomer looking out into space will observe that
Answer:
The farther out a galaxy is from Earth, the faster it is moving away.
Explanation:
True or False: Objects fall at a constant speed.
Answer:
Explanation:
true
How to find density of a gas.
Answer:
Subtract the mass of the cylinder from the mass of the cylinder when it contains gasoline. This is the mass of the gasoline. Divide this figure by the volume, 100 ml, to get the density.
What is the ideal temperature for a lithium-ion battery?.
Answer:
16 to 25 degrees f
Explanation:
Calculate torque using angular momentum
Answer:
The equation net τ=ΔLΔt net τ = Δ L Δ t gives the relationship between torque and the angular momentum produced.
A car starts from rest and accelerates at 2.5m/s^2 for 2s. What is the final velocity of the car
Answer:
5m/s ez
Explanation:
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Where does the energy released in a nuclear decay reaction come from
A. Electrons
B. Chemical bonds
C. Positrons
D. The binding energy of the nucleus
A ball is fired from a cannon at point 1 and follows the trajectory shown in the figure below. Air
resistance may be neglected. Five possible vectors are also shown in the figure; the letter E represents
the zero vector.
D
E:
C
B
a
Which vector best represents the ball's velocity at position 2?
Which vector best represents the ball's acceleration at point 2?
Which vector best represents the ball's velocity at position 3?
Which vector best represents the ball's acceleration at point 3?
du
b)
A
d)
In trajectory, acceleration vector is not the same with the velocity vector but it depends on the change in velocity. The acceleration path is perpendicular to the velocity vector path. The Correct answers are:
a.) D
b.) B
c.) C
d.) A
A Vector is a quantity that has both magnitude and direction.
Given that a ball is fired from a cannon at point 1 and follows the trajectory shown in the figure.
a.) The vector best represents the ball's velocity at position 2 is D
b.) The vector best represents the ball's acceleration at point 2 is B
c.) Which vector best represents the ball's velocity at position 3 = C
d.) Which vector best represents the ball's acceleration at point = A
In trajectory, acceleration vector is not the same with the velocity vector but depends on the change in velocity. The acceleration path is perpendicular to the velocity vector path.
At point 3, since the ball path is parabolic, the velocity at that point is not equal to zero but will tend to take a horizontal path.
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How to calculate angular velocity.
Answer:
Answer below
Explanation:
We can rearrange this statement to get the angular velocity equation: = r v / |r|2, where all of these variables are vectors and |r| is the radius's absolute value. The angular velocity is really a pseudovector with a direction perpendicular to the plane of rotational movement.
The rotating movement of bodies is described by angular velocity. It determines how quickly they rotate around a central point. Rotations may be divided into two categories. The first explains the motion of an object's centre of mass around a certain point in space, which is referred to as an origin. Planets orbiting the Sun, for example, or an automobile exiting a roadway are two instances.
The first angular velocity equation is similar to the linear velocity equation: = (2 - 1) / t = / t, where 1 and 2 are two values of angles on a circle, and is the difference between them. t is the time it takes for the angle to shift. As you can see, there is a ratio of the positional change in a period for normal velocity, but we utilise angle instead of distance here. Definition of angular velocity using linear velocity The second angular velocity formula, v = r, may be obtained from the linear velocity and radius relationship using the cross product.
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A car traveling at 35.6m/s crashes into a concert barrier and comes to a stop in 0.35 seconds. Calculate the average force applied to the 75kg driver.A 3.2kg steel ball traveling at 4.1m/s strikes a second ball of a mass 2.3kg Initially at rest. Calculate the velocity of the second ball when the first one continues traveling in the same direction with a speed of 1.5m/s2 balls of putty are shot towards one another. Ball 1 has a mass of 4.3kg and is moving at 18.6m/s . Ball 2 has a mass of 5.8kg and is moving at 9.5m/s. They collide and stick together. Calculate their final combine velocity.I really appreciate those attempting the problems. I do know the answers but I’m unaware of the steps to get there. Please include all formulas in your response and steps so I can learn and understand.Check your answer:7629N3.6m/s2.46m/sThank you all!
The force on the driver is 7629 N. The velocity of the second ball is 3.6 m/s. The combined velocity of the balls is 13.37 m/s.
We have to find the acceleration using;
v = u - at
v = final velocity = 0 m/s
u = initial velocity = 35.6m/s
a = acceleration = ?
t = time = 0.35 s
u = at
a = u/t = 35.6m/s / 0.35 s
a = 101.7 ms-2
The force on the driver = 75kg × 101.7 ms-2 = 7629 N
Using the principle of conservation of momentum;
Momentum before collision = momentum after collision
m1u1 +m2u2 = m1v1 + m2v2
Hence
(3.2 × 4.1) + 0 = (3.2 × 1.5) + 2.3v2
13.12 = 4.8 + 2.3v2
13.12 - 4.8 = 2.3v2
v2 = 13.12 - 4.8/2.3
v2 = 3.6 m/s
Using the principle of conservation of linear momentum;
m1u1 + m2u2 = m1v1 + m2v2
(4.3 × 18.6) + (5.8 × 9.5) = (4.3 + 5.8) v
v = 79.98 + 55.1/10.1
v = 13.37 m/s
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in terms of the wavelength of the sound wave, about how far below the open end of the resonance tube is the first resonant position?
The first resonant position below the open end of the resonance tube is; one-quarter of the wavelength
In the event of the first resonant position in a resonance tube, there will be a maximum air displacement which is only one antinode right at the open end where the motion is constrained.
However, there will be no displacement at the closed end which means another one node right at the closed end where air is halted.
This means that the standing wave will have one-quarter of the wavelength in the test tube.
Thus;
L = ¼λ
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