1. The electromagnetic spectrum is the range of all types of radiation.
a. index of refraction
b. EM
c. laser
Answer:
EM
Explanation:
The index of refraction is a special property that shows how light travels through different medias. It does not concern itself with the spectrum, only what it will do to that spectrum under laboratory conditions.
Laser light is a very narrow concentrated light form. It is not the entire spectrum, but only a very small part of it.
The answer you want is EM Electromagnetic Radiation
A woman pushes a car with a force of 400 N for a distance of 15m. How much work has she done?
Answer:
the work done by the woman is 6,000 J
Explanation:
Given;
force applied by the woman, F = 400 N
distance moved by the woman, d = 15 m
The work done by the woman is calculated as follows;
W = F x d
W = 400 N x 15 m
W = 6000 Nm = 6,000 J
Therefore, the work done by the woman is 6,000 J
I need help with this someone help me?
what is the car's average velocity
Answer:
vận tốc bằng quãng đường chia thời gian
Explanation:
v=s/t
What is the current in the 60.0 resistor
Answer:
Option (c)
Explanation:
According to question,
R= 60 ohm
V=120 V
Current can be calculated as :
[tex]I=\frac{V}{R}[/tex]
Where,
I is current
V is voltage
R is resistance
[tex]I=\frac{120}{60} \\I=2 A[/tex]
Current is flowing across 60 ohm will be 2.0 A
Therefore, option c is correct
a car travelled at 50km/hr for 3 hours, how far did the car travel
Answer:
The answer answer is 150 km
Answer:
Explanation:
Distance =Speed×time
Speed=50km/hr
Time=3hours
Hence the Distance will be(50km/hr×3hours)
The answer is 150km
Charge is distributed uniformly throughout the volume of an infinitely long solid Cylinder of radius R what is the electric field when r < Select one : O a . Zero O b . E = / 2 € d . E = pr / 2 € O e . E = / 2 €
Solution :
Let us consider the Gaussian surface that is in the form of a cylinder having a radius of r and a length of A which is [tex]$\text{coaxial with the charged cylinder}$[/tex].
The charged enclosed by the cylinder is given by,
[tex]$q=\rho V$[/tex] (here, V = [tex]$\pi r^2l$[/tex] is the volume of the cylinder)
[tex]$=\pi r^2lp$[/tex]
If [tex]$\rho$[/tex] is positive, then the electric field lines moves in the radial outward direction and is normal to Gaussian surface which is distributed uniformly.
Therefore, total flux through Gaussian cylinder is :
[tex]$\phi=EA_{cyl}$[/tex]
[tex]$=E(2\pi rl)$[/tex]
Now using Gauss' law, we get
[tex]$2\pi \epsilon_0rlE = \pi r^2lp$[/tex]
or [tex]$E=\frac{\rho r}{2 \epsilon_0}$[/tex]
Therefore, the electric field is [tex]$E=\frac{\rho r}{2 \epsilon_0}$[/tex]
Hence, option (d) is correct.
A body of mass 5 kg moving with velocity 10m/s attains a velocity of 30m/s in 20 seconds, after applying the force. The amount of force applied will be:
a 10N
b 20N
c 5N
d 15N
Answer↷
c) 5N
➦I hope it seemed helpful to you!
A 1500 kg truck travelling north at 60 km/hr collides with a 1200 kg car moving east at 15km/hr. If the two cars remain locked together after impact, with what velocity do they move immediately after the collision.
Answer:
33.33j+6.67i km/hr
Explanation:
From the law of conservation of momentum,
Applying,
mu+m'u' = V(m+m')............... Equation 1
Where m = mass of the truck, m' = mass of the car, u = initial velocity of the truck, u' = initial velocity of the car, V = Final velocity.
Note: let j represent the north, and i represent the east
From the question,
Given: m = 1500 kg, u = 60j, m' = 1200 kg, u' = 15i
Substitute these values into equation 1
1500*60j+1200*15i = V(1500+1200)
90000j+18000i = 2700V
V = (90000j+18000i)/2700
V = 33.33j+6.67i km/hr
What happens when a negatively charged object A is brought near a neutral object B?
A.
Object B gets a negative charge.
Ο
O o
B.Object B gets a positive charge.
O C.
Object B stays neutral but becomes polarized.
D.
Object A gets a positive charge.
O
E.
Object A loses all its charge.
Reset
Next
Answer:
A.
Explanation:Object b will get a negative charge .
¿Qué juegos se practicaban en esa Época? ¿Qué nombre tenían los juegos? ¿En qué consistía cada uno de los juegos? ¿Cómo se iniciaba y finalizaba el juego?
La respuesta correcta para esta pregunta abierta es la siguiente.
A pesar de que se te olvidó especificar el país al que te refieres y a la fecha específica para saber de qué época estás hablando, te podemos ayudar comentando lo siguiente.
¿Qué juegos se practicaban en esa Época?
Anterior al surgimiento de la era digital y la era de los "gammers," los niños y la juventud en general salían a la calle o al parque a realizar diferentes actividades físicas y recreativas. Había juegos de ronda, juegos deportivos, juegos de destreza, y juegos de mesa.
¿Qué nombre tenían los juegos?
Había juegos que se llamaba "Doña Blanca," "La Roña," "Lobo estás ahí," "Las escondidas," "canicas," el yoyo," "el trompo," "el burro castigado," "las cebollitas," "el látigo," además de las "cascaritas" que eran juegos de soccer o futbol americano en las calles y con equipos formados por tus amigos.
¿En qué consistía cada uno de los juegos?
Si jugabas canicas, tenías que golpear una canica con otra para desplazarla y llevarla a cierto lugar. O tenías que meterla en agujeros.
Si jugabas, "Doña Blanca," formabas un círculo entrelazado de las manos. Mientras cantabas la canción de Doña Blanca, alguien que estaba afuera del círculo trataba de romperlo, tratando de soltar algunas de las manos entrelazadas.
La verdad era sumamente divertido, creativo, te reías, mucho, y lo mejor de todo era que hacías ejercicio y no te quedabas sentado todo el día frente a una pantalla de computadora.
In the picture below, a car hits a wall. Using what you know about Newton’s Third Law, which is true?
The force of the wall on the car and the car on the wall are equal
The force of the wall on the car is greatest
The force of the car on the wall is greatest
There is not enough information to tell
Answer:
A...................................
The force of the wall on the car and the car on the wall are equal is true about Newton’s Third Law. Option A is the correct answer.
According to Newton's Third Law of Motion, for every action, there is an equal and opposite reaction. This means that if the car hits the wall, there will be a force exerted by the car on the wall, and an equal and opposite force exerted by the wall on the car. Option A is the correct answer.
The forces involved in the interaction between the car and the wall are equal in magnitude but opposite in direction, as dictated by Newton's Third Law. Newton's Third Law of Motion states that for every action, there is an equal and opposite reaction. This means that when an object exerts a force on another object, the second object exerts a force of equal magnitude but in the opposite direction on the first object.
Learn more about Newton here:
https://brainly.com/question/28171613
#SPJ2
The complete question is, "In the picture below, a car hits a wall. Using what you know about Newton’s Third Law, which is true?
a. The force of the wall on the car and the car on the wall are equal
b. The force of the wall on the car is greatest
c. The force of the car on the wall is greatest
d. There is not enough information to tell"
Please answer !!!A company wants to install a sensor to monitor the light level in the offices of their buildings. The sensor contains an LDR which has a resistance of 10kohlms in daylight and 100kohlms in the dark . The choice of resistor in the circuit is between one of 25kohlms and 1 megaohlm. The input p.d to the sensing circuit of 12 v . State and explain which resistor is the best choice for the circuit in light and dark which each of the resistors . You could put your calculations in a table .
Answer:
Explanation:
The sensor contains an LDR which has a resistance of 10kohlms in daylight and 100kohlms in the dark.
If the resistor in the circuit is 1 megaohlm, the total resistance in daylight and darkness will be 1.01 megaohms and 1.1 megaohlms.
The percentage difference = (1.1-1.01)/1.1*100% = 8.18%
If the resistor in the circuit is 25 kohlm, the total resistance in daylight and darkness will be 35 kohms and 125 kohlms.
The percentage difference = (125-35)/125*100% = 72%
With the input p.d to the sensing circuit fixed at 12 v, the sensing current will change according to the total resistance. A 72% difference is much more detectable. So the 25 kohm resistor is the better choice.
Answer:
Explanation:
V=IR
I=12/(R of resistor + R of LDR)
R of LDR = 10kohm in light and = 100kohm in dark
R1 = 25kohm
R2 = 1Mohm
solve 4 current
light dark
R1 12/(25+10)=0.343mA 12/(25+100)=0.096mA
R2 12/(1000+10)=0.012mA 12/(1000+100)=0.011mA
so R1 is better as its easier 2 tell its light or dark
Un hombre de pie puede ejercer la misma fuerza con sus piernas tanto en la tierra como en la luna. Sabemos que la masa del hombre es la misma en la Tierra y en la Luna. También sabemos que F=m x a (masa x aceleración, corresponde a la 2° Ley de Newton), es verdad tanto en la Tierra y la Luna. ¿Será el hombre capaz de saltar más alto en la Luna que en la Tierra? ¿Por qué o por qué no?
Answer:
The height jumped by the person on the moon is 6 times the height jumped by the person on earth.
Explanation:
As we know that the acceleration due to gravity on moon is 1/6 of the acceleration due to gravity on earth.
So, it is false.
Let the mass of man is m and the gravity on moon is g' = g/6.
Let the height jumped on earth is h and the height jumped on moon is h'.
So,
m x g' x h' = m x g x h
g/6 x h' = g x h
h' = 6 h
So, the height jumped by the person is 6 times the height jumped by the person on earth.
to produce a magnetic field, what does an electromagnet require?
Explanation:
hope it helps
pls mark me as brainliest thanks❤
how does an atom change if all of its electons are removed
a. the atom’s volume increases
b. the atom’s mass increases
c. the atom becomes positively charged
d. the atom becomes negatively charged
Answer:
c
Explanation:
Have a nice day
answer is c
(c)
Explanation:
is (c)
it is c
1. Which of the following is the most active in the Philippines?
a. Arayat
b. Hibok-Hibok
c. Kanlaon
d. Mayon
2. Which of the following theories states that the Earth's outer layer is broken into large slowly moving pieces?
a. Big Bang Theory b. Gravitational Theory c. Plate Tectonics Theory d. Theory of Relativity
3. Which type of plate boundaries where two plates are moving away from each other?
a Convergent b. Divergent
c. Fault d. Transform
4. Which of the following refers to the pattern of movement that forms when warm material rises, and eventually sinks
when it cools down.
a. Convection cell
b. Fault
c. Heat
d. Mantle
5. Which of the following forms of electromagnetic wave has the LONGEST wavelength range?
a. microwave
b. radio wave
c. ultraviolet
d. x-ray
6. Which of the following electromagnetic waves has the SHORTEST wavelength range?
a. infrared
b. ultraviolet
c. visible light
7. Which kind of wave is use in night vision goggles?
a. microwave
b. gamma ray
c. infrared
d. visible light
8. The image you see in a plane mirror is called a
image because it is not a real, physical object.
a imaginary
b. physical
c. reflected
d. virtual
9. Which of the following structures of the male reproductive system is responsible in producing sperm cells?
a penis
b. prostate gli
c. scrotum
d. testis
10. The movement of individuals into an area
d immigration
d. X-ray
Answer:
1 d
2c
3b
4a
5b
6 I think the answer is x-ray
7c
8d
10d( Immigration)
How does Newton's third law explain how a rocket is launched upward?
Answer:
At lift-off, hot burning gas is pushed downwards by the rocket motors. The hot gas pushes back on the rocket in an upwards direction. When this upwards push, or thrust, exceeds the weight of the rocket, the forces acting on the rocket are unbalanced and the rocket accelerates upwards
Explanation:
Answer:
A. Gases from burning fuel are pushed out of the bottom of the rocket, and these gases push back on the rocket with an equal amount of force.
Explanation:
A educação física, enquanto componente curricular da educação básica. Qual a tarefa que educação física?? Alguem me ajuda por fvr ??
Answer:
como assim qual a tarefa que educação física? se você me explicar melhor eu consigo te responder !!
Explanation:
pleaase help me i don't know this !!!
Answer:
coefficient=1.09N/m×g
coefficient=1.09N/0.413g×10m/s square
coefficient=1.09N/4.13N
coefficent=0.263
f= uK
here f is force, u is cofficient of friction , k is normal force
k = mg
f = umg
1.09 = u × 0.41 × 10
u = 1.09 ÷ 4.1
u = 0.26
what is the speed of a wave with a wavelength of 3.0 m and a period of 0.40 s?
Difference between cold and warm blooded animal.
Answer:
Cold blooded animals are those animals that cannot regulate their body temperature and their temperature keeps changing according to their environment. ... Warm blooded animals are the animals that have a constant body temperature and can easily adapt to extreme temperatures as they can regulate their body temperature.
A car and a large are moving with the same velocity. Which of the two is more difficult to
slow down? Why?
(Serious Answers Please)
Whichever object has more mass will need more energy to slow it down.
We don't know the mass of the car or the mass of the large.
None of this has anything to do with "difficult". We don't know what's difficult for you, and we don't know the SI unit of "difficult".
When the interval between the stimuli decreases, _______.
A. a second action potential is generated until the interval reaches the absolute refractory period
B. a second action potential is generated regardless of the stimulus and the interval
C. a second action potential is generated until the interval reaches the relative refractory period
D. a second action potential is generated as long as the stimulus is above threshold
Answer:
The correct option is A. a second action potential is generated until the interval reaches the absolute refractory period.
Explanation:
The inter-stimulus interval (ISI) is the temporal interval between two successive stimuli, measured from the offset of the first stimulus to the commencement of the second.
A cell's refractory period is the time during which it is unable to replicate an action potential. Therefore, the absolute refractory period is the amount of time it takes for a second action potential to be initiated, regardless of how large a stimulus is applied repeatedly.
A second action potential is generated when the gap between the stimuli decreases until the interval reaches the absolute refractory period.
Therefore, the correct option is A. a second action potential is generated until the interval reaches the absolute refractory period.
That is, when the interval between the stimuli decreases, a second action potential is generated until the interval reaches the absolute refractory period.
HELPPPPPPPP!!!!! PLZZZ
Answer:
1- 31.25
2-?
3-?
Explanation:
The chart shows data for four moving objects. Which object has the greatest acceleration?
Answer:
Y
Explanation:
Acceleration = (v-u)/t
W = (29-11)/6 = 3
X = (34-10)/12 = 2
Y = (40-12)/7 = 4
Z = (28-20)/8 = 1
So the answer is Y = 4.
Hope this will help. Please mark me brainliest.
what is the difference between torque and the moment of a force
Answer:
Torque Of a Force: If The Force has tendency or Bends The Body about Longitudinal axis of the Body it is Torque. Moment Of a Force :If Force has Tendency to or Rotates the Body about Transverse asis the Body It is Moment .
Explanation:
7) List three (3) automobile safety features currently used to minimize the risk of injury to its passengers. Relate these
safety features to your egg drop design.
In the 4 X 100M relay, how long is the acceleration zone..
a) 20M
b) 30M
c) 40M
d) 100M
Answer:it’s 400 meters
Explanation:
I need this now
On the planet Xenos, an astronaut observes that a 2.0 m long pendulum has a period of 2.2 s.
What is the free-fall acceleration on Xenos? *
Answer:
[tex]g=16.31\ m/s^2[/tex]
Explanation:
Given that,
The length of the pendulum, l = 2 m
The period of the pendulum, T = 2.2 s
The formula for the time period of a pendulum is given by :
[tex]T=2\pi \sqrt{\dfrac{l}{g}}[/tex]
or
[tex]T^2=4\pi ^2\dfrac{l}{g}\\\\g=\dfrac{4\pi ^2l}{T^2}\\\\g=\dfrac{4\pi ^2\times 2}{(2.2)^2}\\\\g=16.31\ m/s^2[/tex]
So, the free fall acceleration is [tex]16.31\ m/s^2[/tex].