The image below shows four points on the orbit of a comet around the Sun.
At which point does the comet have the most gravitational potential energy?
A. Point B
B. Point A
C. Point C
D. Point D

The Image Below Shows Four Points On The Orbit Of A Comet Around The Sun.At Which Point Does The Comet

Answers

Answer 1

The comet will have the most gravitational potential energy at : ( B ) Point A

Given that the gravitational potential energy between two bodies is expressed as

Ux = - GMm / d ------ ( 1 )

where :

G = gravitational constant

M = mass of larger body ( sun )

m = mass of comet

d = distance between the bodies

Therefore the greater the distance ( d ) between the bodies the less negative the potential gravitational energy the smaller body will possess. from the image attached below, the point on the orbit that is farthest from the sun is Point A

Hence we can conclude that the comet will have the most gravitational potential energy at : ( B ) Point A

Learn more about gravitational potential energy : https://brainly.com/question/15849218

Answer 2

Answer: its letter c

Explanation:


Related Questions

A golfer hits her tee-shot due north towards the fairway. Her shot has an initial velocity of 60 m/s. A 15 m/s wind is blowing in a northwesterly direction (45 degrees west of North). Considering the initial velocity of the ball and the velocity of wind, what will be the resultant velocity (m/s) and the resultant direction of the golf ball assuming no other forces are acting on the ball

Answers

Answer:

[tex]c=71.4m/s[/tex]

[tex]\theta=8.54\textdegree[/tex]

Explanation:

From the question we are told that

Initial velocity of 60 m/s

Wind speed [tex]V_w= 15 m/s \angle 45 \textdegree[/tex]

Generally Resolving vector mathematically

  [tex]sin(45\textdegree)15=10.6\\cos(45\textdegree)15=10.6[/tex]

Generally the equation Pythagoras theorem is given mathematically by

[tex]c^2=a^2+b^2[/tex]

[tex]c^2=10.6^2 +(10.6+60)^2[/tex]

[tex]c=\sqrt{10.6^2 +(10.6+60)^2}[/tex]

Therefore Resultant velocity (m/s)

[tex]c=71.4m/s[/tex]

b)Resultant direction

Generally the equation for solving Resultant direction

[tex]\theta=tan^-1(\frac{y}{x})[/tex]

Therefore

[tex]\theta=tan^-1(\frac{10.6}{70.6})[/tex]

[tex]\theta=8.54\textdegree[/tex]

Allen and Jason are chucking a speaker around. On one particular throw, Allen throws the speaker, which is playing a pure tone of frequency f, at a speed of 10 m/s directly towards Jason, but his aim is a bit off. As a result, Jason runs forward towards the speaker at a speed of 6 m/s before catching it. Then, the frequency that Jason hears while running can be written as (m/n)f Hz, where m and n are relatively prime positive integers. Compute m n.

Answers

Answer:

Explanation:

We shall apply Doppler's effect of sound .

speaker is the source , Jason is the observer . Source is moving at 10 m /s , observer is moving at  6 m/s .

apparent frequency = [tex]f_o\times\frac{V+v_o}{ V-v_s}[/tex]

V is velocity of sound , v₀ is velocity of observer and v_s is velocity of source and f_o is real frequency of source .

Here V = 340 m/s , v₀ is 6 m/s , v_s is 10 m/s . f_o = f

apparent frequency =  [tex]f\times \frac{340+6}{340-10}[/tex]

= [tex]f\times \frac{346}{330}[/tex]

So m = 346 , n = 330 .

An energy source forces a constant current of 2A to flow through a light bulbfilament for twenty seconds. If 4.6 kJ is given off in the form of light and heatenergy, calculate the voltage drop across the bulb.

Answers

Answer:

The voltage drop across the bulb is 115 V

Explanation:

The voltage drop equation is given by:

[tex]V=\frac{\Delta W}{\Delta q}[/tex]

Where:

ΔW is the total work done (4.6kJ)

Δq is the total charge

We need to use the definition of electric current to find Δq

[tex]I=\frac{\Delta q}{\Delta t}[/tex]

Where:

I is the current (2 A)

Δt is the time (20 s)

[tex]2=\frac{\Delta q}{20}[/tex]

[tex]q=40 C[/tex]

Then, we can put this value of charge in the voltage equation.

[tex]V=\frac{4600}{40}=115 V[/tex]

Therefore, the voltage drop across the bulb is 115 V.

I hope it helps you!

How much force is needed to move a 12 kg mass 10 m/s?? FEMA

Answers

Answer:

F=ma

=12×10

120 N.........

Answer:

F = 120 N [Newtons]

Explanation:

F = 120N

If the speed is 10m/s² [an acceleration], and the mass is 12 kg [kilograms].

F [Force] = ma [mass × acceleration].

F = 10 × 12 = 120.

It cannot be a velocity because time is not given.

Momentum would be the velocity times mass. p = mv.

Sarah is a forensic what is her job to do

Answers

Answer:

She takes pictures and analyzes DNA samples

A 5 kg ball was hit with 1523 J of energy how fast is it going?

a. 304.6 m/s
ь. 39 m/s
C 609.2 m/s
d. 1.218.4 m/s

Answers

Answer:

the answer is a 304.6m/s

Explanation:

1,523 / 5 equals 304.6

a 500g model rocket with a weight of 4.90 N is launched straight up. The small rocket burns for 5s and has a steady thrust of 20N. What maximum altitude does the rocket reach

Answers

Answer:

The maximum height reached by the rocket at the given time is 377.5 m.

Explanation:

Given;

mass of the rocket, m = 500 g = 0.5 kg

weight of the rocket, W = 4.9 N

Applied force or thrust of the rocket, F = 20 N

time of the rocket motion, t = 5 s

Apply Newton's second law of motion;

Applied force = Weight of the rock + Upward force of the rocket

F = W + ma

where;

a is the upward acceleration of the rock

[tex]a = \frac{F-W}{m} \\\\a = \frac{20 - 4.9}{0.5} \\\\a = 30.2 \ m/s^2[/tex]

The maximum height reached by the rock during the given time is calculated as;

h = ut + ¹/₂at²

h = 0 + ¹/₂at²

h = ¹/₂at²

h =  ¹/₂ (30.2)(5)²

h = 377.5 m

Therefore, the maximum height reached by the rocket at the given time is 377.5 m.

Interesting fact about the rib

Answers

Answer:

YOU CAN SNEEZE YOUR WAY TO A RIB FRACTURE.

Explanation:

A piece of putty and a tennis ball with the same mass are thrown against a wall with the same velocity. Which object experiences a greater force from the wall or are the forces equal

Answers

Answer:

Explanation:

Firstly, we have to define momentum.

Momentum is define as the product of mass and velocity.

That is P = mass×velocity

Also considering the third law of motion which states that: For every action, there is equal and opposite reaction.

Moreso, considering the 2nd law of motion which states that the rate of change in the momentum of a body is equal to the applied force and takes place in the direction of the applied force.

Now, applying P = mass×velocity

They both have same mass and velocity definitely, they will both experience same momentum.

Also from the question, the both share same velocity hence, the will both hit the wall with same velocity meaning the will both feel the same impact from the wall as well. Hence the third law of motion proves this right.

what is phase voltage of star connected three phase system in balanced loa is 240 the line voltage​

Answers

Answer:

Explanation:   the Star Connection, the similar ends (either start or finish) of the three windings are connected to a common point called star or neutral point. The three-line conductors run from the remaining three free terminals called line conductor

If two connected points objects pass through the same set of three points, the shapes created by each will be identical, regardless of the order in which each object was plotted. True

Answers

Answer:

This is false

Explanation:

This is why the answer to this question is false. If these types of objects (2 points connected) should pass through same sets of 3 points, irrespective of the order that each object was plotted, we will not get identical shapes created.

The shape that is going to be created will be dependent on the pattern/order that was involved in the plotting. If it was identical, then we will have identical shapes. But if the order during plotting is different then we will have different shapes created.

Thank you!

Two floors in a building are separated by 4.1 m. People move between the two floors on a set of stairs. (a) Determine the change in potential energy of a 3.0 kg backpack carried up the stairs. (b) Determine the change in potential energy of a person with weight 650 N that descends the stairs.

Answers

Answer:

a) The change in potential energy of a 3.0 kilograms backpack carried up the stairs.

b) The change in potential energy of a persona with weight 650 newtons that descends the stairs is -2665 joules.

Explanation:

Let consider the bottom of the first floor in a building as the zero reference ([tex]z = 0\,m[/tex]). The change in potential energy experimented by a particle ([tex]\Delta U_{g}[/tex]), measured in joules, is:

[tex]\Delta U_{g} = m\cdot g\cdot (z_{f}-z_{o})[/tex] (1)

Where:

[tex]m[/tex] - Mass, measured in kilograms.

[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.

[tex]z_{o}[/tex], [tex]z_{f}[/tex] - Initial and final height with respect to zero reference, measured in meters.

Please notice that [tex]m\cdot g[/tex] is the weight of the particle, measured in newtons.

a) If we know that [tex]m = 3\,kg[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex], [tex]z_{o} = 0\,m[/tex] and [tex]z_{f} = 4.1\,m[/tex], then the change in potential energy is:

[tex]\Delta U_{g} = (3\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (4.1\,m-0\,m)[/tex]

[tex]\Delta U_{g} = 120.626\,J[/tex]

The change in potential energy of a 3.0 kilograms backpack carried up the stairs.

b) If we know that [tex]m\cdot g = 650\,N[/tex], [tex]z_{o} = 4.1\,m[/tex] and [tex]z_{f} = 0\,m[/tex], then the change in potential energy is:

[tex]\Delta U_{g} = (650\,N)\cdot (0\,m-4.1\,m)[/tex]

[tex]\Delta U_{g} = -2665\,J[/tex]

The change in potential energy of a persona with weight 650 newtons that descends the stairs is -2665 joules.

At a certain elevation, the pilot of a balloon has a mass of 120 lb and a weight of 119 lbf. What is the local acceleration of gravity, in ft/s2, at that elevation

Answers

Answer:

31.905 ft/s²

Explanation:

Given that

Mass of the pilot, m = 120 lb

Weight of the pilot, w = 119 lbf

Acceleration due to gravity, g = 32.05 ft/s²

Local acceleration of gravity of found by using the relation

Weight in lbf = Mass in lb * (local acceleration/32.174 lbft/s²)

119 = 120 * a/32. 174

119 * 32.174 = 120a

a = 3828.706 / 120

a = 31.905 ft/s²

Therefore, the local acceleration due to gravity at that elevation is 31.905 ft/s²

If it took you 5 seconds to move a rock 15 meters using a force of 150 Newtons, how much power did you need to use?
500 joules/sec
45 joules/sec
4,500 joules
450 joules/sec

Answers

Answer:

Given that:

Time taken = 5 seconds

Distance = 15 meters

Force = 150 Newtons

Power = ?

Recall that power is the rate of work done per unit time

i.e Power = work / time

(since work is a product of force and distance, then

power = (force x distance)/ time

Power = (150 Newtons x 15 m) / 5 s

Power = 2250 / 5

Power = 450 joules per second

Answer:

450 joules/sec

Explanation:

150 x 15 = 2,250

2,250 / 5 = 450

                = 450 joules/sec

Which process is defined as breaking down rocks into smaller pieces without changing the rocks' compositions

Answers

Answer:

mechanical weathering

Explanation:

Answer:

Mechanical weathering is responsible for the composition of a rock

Explanation:

The answer is (D)

You yell into a canyon. You hear the echo in 3 seconds. How long did the sound of your voice travel before bouncing off a cliff?

Answers

Answer:

The sound travelled 516 meters before bouncing off a cliff.

Explanation:

The sound is an example of mechanical wave, which means that it needs a medium to propagate itself at constant speed. The time needed to hear the echo is equal to twice the height of the canyon divided by the velocity of sound. In addition, the speed of sound through the air at a temperature of 20 ºC is approximately 344 meters per second. Then, the height of the canyon can be derived from the following kinematic formula:

[tex]2\cdot h = v\cdot t[/tex] (1)

Where:

[tex]h[/tex] - Height, measured in meters.

[tex]v[/tex] - Velocity of sound, measured in meters per second.

[tex]t[/tex] - Time, measured in seconds.

If we know that  [tex]v = 344\,\frac{m}{s}[/tex] and [tex]t = 3\,s[/tex], then the height of the canyon is:

[tex]h = \frac{v\cdot t}{2}[/tex]

[tex]h = \frac{\left(344\,\frac{m}{s} \right)\cdot (3\,s)}{2}[/tex]

[tex]h = 516\,m[/tex]

The sound travelled 516 meters before bouncing off a cliff.

An automobile has a mass of 1500 kg. What is the minimum uncertainty in the velocity (in miles per hour) when its center of mass is located with an uncertainty no greater than 1 cm

Answers

Answer:

[tex]\triangle v=1.57*10^-^3^5miles/hour[/tex]

Explanation:

From the question we are told that

Mass of of automobile M= 1500 kg

Generally the equation of the uncertainty principle is  given by

[tex]\triangle p=\frac{h}{ \triangle x}[/tex]

[tex]\triangle p=\frac{1.054*10^-^3^4}{ 10^-^2}[/tex]

[tex]\triangle p=1.054*10^-^3^2[/tex]

Generally the uncertainty in velocity is mathematically given by

[tex]\triangle v=\frac{\traingle p}{m}[/tex]

[tex]\triangle v=\frac{1.054*10^-^3^2}{1500}[/tex]

[tex]\triangle v=7*10^-^3^6m/s[/tex]

Therefore the minimum uncertainty in the velocity (in miles per hour)

[tex]\triangle v=7*10^-^3^6*\frac{3600}{1609.3}[/tex]

[tex]\triangle v=1.57*10^-^3^5miles/hour[/tex]

What kind of injury would most likely come from an unfortunate slide into home in a baseball game?

erosion

macule

crust

bullae

Answers

macule i do believe.

As positively charged sodium ions enter the axon, _______ flow(s) out to repolarize part of the axon

a. potassium ions

b. a neural impulse

c. the action potential

d. glial cells

Answers

Voltage-gated sodium channels at the part of the axon closest to the cell body activate, thanks to the recently depolarized cell body. This lets positively charged sodium ions flow into the negatively charged axon, and depolarize the surrounding axon.

As positively charged sodium ions enter the axon, potassium ions flow out to repolarize part of the axon.

At the beginning of an action potential of cell membrane, the sodium ion gates open and sodium ions flows into the cell.  This process is called depolarization. Due to rapid influx of sodium ion, the channel is eventually closed.

The potassium channels are then activated in a process called repolarization. This process occurs when the potassium channels open and allow potassium ions to flow out of the cell.

To maintain the cell membrane potential, cells are kept at low concentration of sodium ions and high concentration of potassium ions.

Thus, as positively charged sodium ions enter the axon, potassium ions flow out to repolarize part of the axon.

Learn more here: https://brainly.com/question/7778945

A capacitor is connected to an AC generator. As the generator's frequency is increased, what happens to the current in the capacitor

Answers

Answer:

The current increases.

Explanation:

A capacitor can be defined as an electronic component used in electrical circuits to store charge temporarily.

A capacitor is connected to an AC generator. As the generator's frequency is increased, the current in the capacitor increases as well.

This ultimately implies that, when a capacitor is connected to an AC generator, the frequency of the circuit is directly proportional to the amount of current flowing through it.

2. A gas with a constant pressure of 270 kPa does 36,000 J of work as it expands.
What was the change in volume of the gas?
a) 0.13 meters cubed
b) 0.24 meters cubed
c) 0.33 meters cubed
d) 0.46 meters cubed

Answers

c sorry if wrong ,,,

Convert 41.3 kilocalories into joules.

Answers

Answer:172799.2

Explanation:

Determine the magnitude of the resultant force FR=F1+F2FR=F1+F2. Assume that F1F1F_1 = 235 lblb and F2F2F_2 = 350 lb

Answers

Answer:

585lb

Explanation:

Given the formula for calculating the magnitude of the resultant force as;

[tex]F_R = F_1 + F_2[/tex]

Given

[tex]F_1 = 235 lb \ and \ F_2 = 350 lb\\F_R = 235lb + 350lb\\F_R = 585lb\\[/tex]

Hence the magnitude of the resultant force is 585lb

Which of the following is Not One of the four Assumptions of kinetic theory?
A. All matter is composed of tiny particles
B. These particles are in constant random motions
C. The particles move in a choreograph path and do not collide
D. The amount of energy that the particles this on this collision is negligible

Answers

Answer:

I Believe it is

Option C (The particles move in a choreograph path and do not collide)

Explanation:

Hope this Helps! :)

If an object was observed to orbit the Sun once every half of a year, what would be this object's average distance from the Sun according to Kepler's third law?
A. 0.63 au

B. 0.25 au

C. 0.79 au

D. 0.71 au

Answers

It’s B. I think, because it’s 0.25

Three liters (3000 cm3) of oil is spilled onto a smooth lake. If the oil spreads out uniformly until it makes a circular oil slick just one molecule thick, with adjacent molecules just touching, estimate the diameter of the oil slick. Assume the oil molecules are round with a diameter of 2 x 10-10 m.

Answers

Answer:

4.38 km

Explanation:

Volume of oil slick, V = Area of oil slick, A × thickness of 1 molecule, d'

Since the oil slick spreads out in a circular area, it has the area of a circle.

So, V = πd²/4 × d'

d² = 4V/πd'

d = 2√(V/πd') where d = diameter of oil slick.

Since V = 3000 cm³ = 3000 × 10⁻⁶ m³ = 3 × 10⁻³ m³ and d' = 2 × 10⁻¹⁰ m

So, d = 2√(3 × 10⁻³ m³/(π × 2 × 10⁻¹⁰ m))

= 2√(3 × 10⁻³ m³/(6.283 × 10⁻¹⁰ m))

= 2√(0.477 × 10⁷ m²) = 2√(4.775 × 10⁶ m²)

=  2 × 2.19 × 10³ m

= 4.38 × 10³ m

= 4.38 km

Who invented gravity

Answers

Answer: joe

Explanation:

Answer:

Sir Isaac Newton

Explanation:

Sir Isaac Newton was an English mathematician and mathematician and physicist who lived from 1642-1727. The legend is that Newton discovered Gravity when he saw a falling apple while thinking about the forces of nature.

what relationship must exist between an applied force and the velocity of a moving obkect if uniform circular motion is to result

Answers

Answer:

See explanation

Explanation:

The centripetal force keeps an object moving in a circular orbit at constant velocity. The velocity of an object undergoing uniform motion is always tangential to the circle while the centripetal force is directed towards the center of the circle.

This now implies that the direction of the force acting on a body undergoing circular motion at constant velocity is perpendicular to the direction in which the object is being displaced.

Two identical carts are free to move along a straight frictionless track. At time t1, cart X is moving at 2.0 m/s when it collides with and sticks to cart Y, which is initially at rest. Draw the graphs that best shows the velocity of cart X before and after the collision?

Answers

Answer:

Explanation:

Using the law of conservation of momentum;

[tex]m_1 u_1+m_2u_2 = m_1v_1+m_2v_2[/tex]

here;

There is a need for conservation of the total momentum that occurred before and after the collision.

So;

[tex]m_1[/tex] = mass of cart X

[tex]m_2[/tex] = mas 9f cart Y

[tex]u_1[/tex] = velocity of cart X (before collision)

[tex]u_2[/tex] = velocity of cart Y (before collision)

[tex]v_1[/tex] = velocity of cart X (after collision)

[tex]v_2[/tex] = velocity of cart Y (after collision)

So;

[tex]m(u_1+0) =(m_1v+m_2)v[/tex]

because the mass is identical and v represents the velocity of both carts.

Now;

[tex]u_1[/tex] = 2 m/s

[tex]u_2[/tex] = 0 ( at rest)

m(2) = (2m)v

v = 1 m/s

Thus, we can see from the graphical image attached below that the velocity of X reduces to 1 m/s after collision with cart Y.

why is red light used in photographic dark rooms​

Answers

Photographic paper reacts to light to produce the image taken by a camera and stored on film. Darkrooms used red lighting to allow photographers to control light carefully, so that light-sensitive photographic paper would not become overexposed and ruin the pictures during the developing process.

Answer:

Photographic paper reacts to light to produce the image taken by a camera and stored on film.

Explanation:

Darkrooms used red lighting to allow photographers to control light carefully so that light-sensitive photographic paper would not become overexposed and ruin the pictures during the developing process.

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