Answer:
(52) rescued.
(53) ears
(54) mission
(55) consisted
Step-by-step explanation:
The solving to this question
This is a simple harmonic motion exercise. The proof that the resultant force on the particle, at time t, is -225 Newtons is indicated below.
What is the proof that the resultant force on the particle, at time t, is -225x newtons?Note that we have been given the following:
Mass = 9kg,
Y = 45 N
ζ = 0.4 m
Then, Y/ζ = 45N/0.4m
= 112.5 N/m
Hence, the spring constant =
K = 112. 5N/m
From this point we can resolve the Amplitude (A):
Amplitude is given as:
A = CB - PB
= 0.6 - 0.5
A = 0.1m
I) So because one spring is elongated by x and the other is compressed by x, Hence, the spring force is:
F[tex]_{net}[/tex] = - Kₓ - Kₓ
= - 2Kₓ
= -2 x 112.5 x* X
F[tex]_{net}[/tex] = -225x Newton ..........Lets call this expression 1
From equation 1 above, we know that
Ma = -225x
a = (-225/m) x
⇒ a ∝ - x,
Hence, the motion is is simple harmonic in nature.
The time period, T = 2 π√m/K[tex]_{eq}[/tex]
Where, K[tex]_{eq}[/tex] = 2K
= 2π√(9/225)
= 2π * 3/15
= 2(22/7) * (3/15)
= 1.25714285714; thus
T ≈ 1.26 secs...............lets call this expression 2
What is the speed of the particle when it is 0.05 meters from C?Note that Angular Frequency is = 2π/T
= 2π/1.26
= 4.9866550057
ω = 4.99 rad/s
Since the velocity at any point x from the mean position is given by
V = ω √ (A² - x²); hence
V = 4.99 √[(0.1)² - (0.05)²
V = 4.99 x 0.0866
V = 0.432134
V ≈ 0.432..........Lets call this expression 3
What is the expression of x in terms of t?Along the x-axis, A simple harmonic motion can be depicted as:
x = A sin (ωt + Ф) ..........lets call this expression 4
where, Ф = Phase constant
At t = 0; x = A
A = A sinФ
⇒ SinФ = 1
⇒ Ф = π/2
Expression 4 becomes:
x = A sin (ωt + π/2)
Inserting the values of ω and A, we have
x = 0.1 sin (4.99t + π/2).........Lets call this expression 5a
or x = 0.1 cos (4.99t).......Lets call this expression 5b
Hence,
Sin(π/2 + Ф) = CosФ
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True or false? The graph represents a function.
5
O A. True
O B. False
Find the value of x in each case. Show your work with proper statements and notation. P belongs to line MQ
Answer:
x = 14
Step-by-step explanation:
PMN forms a triangle and the sum of interior angles in a triangle is equal to 180 therefore we can use the following equation to find the value of x
32 + 64 + 6x = 180 add like terms
96 + 6x = 180 subtract 96 from both sides
6x = 84 divide both sides by 6
x = 14
Es LOGICA PROPOSICIONAL, me pueden ayudar porfavor?
[tex]\begin{array}{c|c|c|c} p & q & \neg q & p \land \neg q \\ T & T & F & F \\ T & F & T & T \\ F & T & F & F \\ F & F & T & F \end{array}[/tex]
[tex]\begin{array}{c|c|c|c} t & s & \neg t & \neg t \implies s \\ T & T & F & T \\ T & F & F & T \\ F & T & T & T \\ F & F & T & F \end{array}[/tex]
[tex]\begin{array}{c|c|c}p\land \neg q & \neg t \implies s & (p \land \neg q) \implies (\neg t \implies s) \\T & T & T \\ T & F & F \\ F & T & T \\ F & F & T \end{array}[/tex]
The given logical statement is false when [tex]p\land\neg q[/tex] and [tex]\neg t\implies s[/tex] are true and false, respectively.
[tex]p\land\neq g[/tex] is true when [tex]p[/tex] is true and [tex]q[/tex] is false[tex]\neg t \implies s[/tex] is false when both [tex]t[/tex] and [tex]s[/tex] are falseYou have a $10,000, you must choose between Gamble A and Gamble B. Gamble A will cost $5,000. If you win, you will get $15,000, but if you lose, you will get nothing. On the other hand, Gamble B will cost $10,000 that will give $30,000 if you win, otherwise get nothing if lost. You are risk averse, and your preference for wealth (W) is specified by the relationship U(W)= √W. Probability of wining is 0.4 and losing is 0.7. Which gamble will you choose and why?
3 to 2 if there are 120 children who like pizza, how many total
Answer:
320
Step-by-step explanation:
Is the 3 to 2 part to part? Out of every 5 people, 3 prefer pizza and 2 do not. We can us this to set up a proportion.
3/5 = 120/x The 3 represent the part that like pizza over the whole of 5. The second ratio is showing the actual number of people that liked pizza over the total number of people.
What would be multiply 3 by to get 120? 40. So, we will multiply 5 times 40 to get the total number of people. 5 x 40 = 200
Compute the requested operating costs as indicated, based on the preceding table and the following information.
Car: six-cylinder compact
Year driven: second
Miles driven: 14,000
The insurance cost for second year is $
.
The insurance cost for the second year from the information given will be $476.
How to calculate the insurance cost?The insurance cost for the second year will be:
= $14000 × 0.034
= $476
Therefore, the insurance cost for the second year will be $476
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The insurance cost for the second year from the information given will be $476.
How to calculate the insurance cost?
The insurance cost for the second year will be:
= $14000 × 0.034
= $476
Therefore, the insurance cost for the second year will be $476
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Give the name (monomial,
binomial, trinomial etc.) and
degree of the polynomial.
√29x6
Name? [? ]
Degree? [
I need help with the slope
Answer:
1/5 :D
Step-by-step explanation:
Lets pick 2 point on the graph :)
We need this to find the slope!
Lets use (-5,1) and (0,2) :)
First we subtract the y coordinates! :)
2 - 1 = 1
Then we subtract the x coordinates!
0 - (-5) = 5
Now we divide!
1/5
Our answer is 1/5!
Have an amazing day!!
Please rate and mark brainliest!!
Answer:
first choice : 1/5
Step-by-step explanation:
need 2 points
one point is (0,2)
another is (5,3)
slope formula is
y2 - y1 / x2 - x1
3 - 2 / 5 - 0
1/5
Your local pizza store sells medium pizzas for $6.79 each, and breadsticks for $2.49 per order.
For a party, you decide to order 4 pizzas and 2 orders of breadsticks. There is a $3 delivery fee, and a 9.4% sales tax will be added to the total. What will be the total bill after tax?
The total bill after tax is $38.44.
What is the total bill?The first step is to determine the total cost of 4 pizzas and 2 orders of breadsticks: (4 x $6.79) + (2 x 2.49) = $32.14
Now, determine the total cost after delivery fee has been added : $3 + $32.14 = $35.14
Now determine the total cost after tax : (1.094) x $35.14 = $38.44
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The total bill after tax of 9.4% is $38.44.
It worthy of note that the sales tax of 9.4% is a percentage of the total purchase bills prior to tax computation, it is the tax due on purchases which is an added percentage of the sales price
total cost of 4 pizzas= $6.79 *4
total cost of 4 pizzas=$27.16
total cost of 2 orders of breadsticks=$2.49*2
total cost of 2 orders of breadsticks=$4.98
total cost of purchase prior to adding delivery cost=$27.16+$4.98
total cost of purchase prior to adding delivery cost=$32.14
total cost of purchase after delivery cost=$32.14+$3
total cost of purchase after delivery cost=$35.14
total cost inclusive of 9.4% sales tax=$35.14*(1+9.4%)
total cost inclusive of 9.4% sales tax=$35.14*1.094
total cost inclusive of 9.4% sales tax=$38.44
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A pie with a temperature of 140∘F is taken out of the oven and placed on a windowsill to cool. Its temperature as a function of t minutes is given by
T(t)=68e−0.0174t+72
How long, to the closest minute, will it take for the pie to cool to 80∘F?
The time taken to the closest minutes for the pie to cool to 80∘F is 123 minutes
TemperatureT(t) = 68e^−0.0174t + 72
80 = 68e^−0.0174t + 72
80 - 72 = 68e^−0.0174t
8 = 68e^−0.0174t
e^−0.0174t = 8/68
e^−0.0174t = 0.11764705882352
take natural log of both sidesln e (−0.0174t) = ln (0.11764705882352)
1 × −0.0174t = -2.1400661634962708
-0.0174t = -2.1400661634962708
divide both sides by -0.0174t = -2.1400661634962708 / -0.0174
t = 122.9923
Approximately,
t = 123 minutes
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90. Find 33.3% of 81.
35 Please help with this question.
The critical values are 0.622, 0.707, 0.789 and 0.834
How to determine the critical values?The sample size is given as:
n = 8
Calculate the degrees of freedom using
df = n - 2
So, we have:
df = 8 - 2
df = 6
Using the table of values of critical values, we have:
Critical values = 0.622, 0.707, 0.789 and 0.834
By comparing the critical values and the linear correlation coefficient, we can conclude that there is no significant linear correlation.
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correct the error 4⁴- 4³=4¹
The error is that
[tex] {x}^{y} - {x}^{z} \neq {x}^{y - z} [/tex]
Instead, it should be 4⁴ - 4³ = 256 - 64 = 192.
Given triangle ABC, which equation could be used to find the measure of angle C?
Please HELPP ONLY A FEW MINUTES TO TURN IN
Okay, it's very simple, to solve this triangle you need to understand what the other angles are. We know that angle A is 90º, as it is represented as a square.
We now need to solve for angle B. angle B can be solved for by
Sin (x) = Opposite / Hypotenuse = 3 / 3√5 = 2.24ish
sin(x) = 2.24
x = [tex]sin^{-1}[/tex](2.24)
Use sin.
Answer:
Step-by-step explanation:
what's the answer
Hello there I need help with this question pls help me I'll mark it as a brain list and give extra 50 points if you answer with an explanation and it MUST be correct
Answer:
iTS 6 2/3 OPTION 2.
Step-by-step explanation:
Because Area = L*B
SO L = A/b
L= 65/3 * 4/13(reciprocal and multiply)
L=20/3 = 6 2/3
Answer:
So answer is 6 2/3
because Look carefully
Area =length× width
length=Area÷ width
so
[tex]21 \frac{2}{3} \div 3 \frac{1}{4} = 6 \frac{2}{3} [/tex]
The point A (-5, -2) is reflected over the line y=-1, and then is reflected over the line x= 3.
The coordinates of A exist (11, 0).
How to estimate the coordinates of A?Let, the point A (-5, -2) exists reflected over the line y = -1, and then stand reflected over the line x = 3.
The distance between the y value exists -1 - (-2)= 1
We move 1 unit beyond the line y = -1
After reflection over the line y = -1 the coordinates of A becomes (-5, 1-1) is (-5, 0)
It exists reflected over the line x = 3
The distance between -5 and 3 exists 3 - (-5) = 8
We move 8 units out from the line x = 3
The Point (-5, 0) becomes (3 + 8, 0) exists (11, 0).
Therefore, the coordinates of A exist (11, 0).
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The complete question:
The point A (-5, -2) is reflected over the line y = -1, and then is reflected over the line x = 3. What are the coordinates of A.
Suppose that X-N (2,6) is a normal distribution with mean 2 and standard deviation 6. What value of x has a z-score of three?
The value of x has a z-score of three is 20
How to determine the value of x?The given parameters are:
Mean = 2
Standard deviation = 6
z = 3
The z-score is calculated as:
[tex]z = \frac{x - \mu}{\sigma}[/tex]
So, we have:
[tex]3 = \frac{x -2}{6}[/tex]
Multiply through by 6
18 = x - 2
Add 2 to both sides
x = 20
Hence, the value of x has a z-score of three is 20
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at the movie theatre, child admission is $6.10 and adult admission is $9.70. On Monday , 146 tickets were sold for a total sales of $1074.20.HOw many adult tickets were sold that day ?
Answer:
51
Step-by-step explanation:
Let c be the number of child tickets sold.
Let a be the number of adult tickets sold.
From the information given from the question, we can deduce:
6.10c + 9.70a = 1074.20 - Equation 1
c + a = 146 - Equation 2
From here, we can use the substitution method in solving simultaneous equations to find a and c. We will use Equation 2 as the base.
c = 146 - a - Equation 2A
We will then substitute equation 2A into Equation 1 to find a.
6.10(146-a) + 9.70a = 1074.20
890.6 - 6.10a + 9.70a = 1074.20
890.6 + 3.6a = 1074.20
3.6a = 1074.20 - 890.6
3.6a = 183.6
a = [tex]\frac{183.6}{3.6}[/tex]
a = 51
Therefore we know that 51 adult tickets were sold that day.
After that you can substitute a into equation 2 to find c.
Find the z a/2 critical value needed to construct a confidence interval with level .The critical value for the confidence level 90% is.......
( round to two decimal places )
Using the z-distribution, the critical value for a confidence level of 90% is of Z = 1.65.
What is the critical value for a 90% confidence interval using the z-distribution?In this problem, we have a 90% confidence level, hence[tex]\alpha = 0.9[/tex], z is the value of Z that has a p-value of [tex]\frac{1+0.9}{2} = 0.95[/tex], so the critical value is z = 1.65.
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The equation y=123.1(1.065)* models the number of college students (in thousands) who studied abroad each year from 1998 through 2013. In this equation, y is the
number of students from a certain country studying abroad (in thousands) and x represents the number of years after 1998.
a. Estimate the number of students studying abroad in 2003.
b. Assuming this equation continues to be valid in the future, use this equation to predict the number of students studying abroad in 2018.
The estimate of the number of students studying abroad in 2003 is 169 and the estimate of the number of students studying abroad in 2018 is 433
a. Estimate the number of students studying abroad in 2003.The function is given as:
y = 123(1.065)^x
Where x represents years from 1998 to 2013
2003 is 5 years from 1998.
This means that
x = 5
Substitute the known values in the above equation
y = 123(1.065)^5
Evaluate the exponent
y = 123 * 1.37008666342
Evaluate the product
y = 168.520659601
Approximate
y = 169
Hence, the estimate of the number of students studying abroad in 2003 is 169
b. Assuming this equation continues to be valid in the future, use this equation to predict the number of students studying abroad in 2018.2018 is 20 years from 1998.
This means that
x = 20
Substitute the known values in the above equation
y = 123(1.065)^20
Evaluate the exponent
y = 123 * 3.52364506352
Evaluate the product
y = 433.408342813
Approximate
y = 433
Hence, the estimate of the number of students studying abroad in 2018 is 433
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Select the correct answer from each drop-down menu.
What structural element of the paragraph is the underlined sentence, and how does it connect ideas in the text?
The underlined sentence
1.the thesis statement for the text
2.the conclusion of the text
3.a piece of evidence for the texts argument
4.a piece of reasoning in the text
It connects ideas in the text by
1.making the main claim of the text
describing why the information provided matters to readers
3. relating a fact or story that demonstrates the texts argument
4. suggesting how a specific example relates to the broader argument
The underlined sentence in the text simply functions as; the conclusion of the text and connects ideas in the text, by making the main claim of the text describing why the information provided matters to readers.
What is the function of the underlined text in the passage?The underlined text in the passage functions as the conclusion to the passage in which case, the information intended to be conveyed is that on the occasion that, regular feeding, good housing, occasional gentle corrections and kindness are in place, there'd be no need for such a cat to steal.
Therefore, the structural element of the paragraph in the underlined sentence, and how it connect ideas in the text is; by making the main claim of the text
describing why the information provided matters to readers.
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What is the simplified form of the quantity of x plus 6, all over the quantity of x plus 4 + the quantity of x minus 3, all over 3 ? (2 points) the quantity of x squared plus 3x minus 18, all over 3 times the quantity of x plus 4 the quantity of x squared plus 4x plus 6, all over the quantity of x plus 7 the quantity of x squared plus 3x minus 18, all over the quantity x plus 7 the quantity of x squared plus 4x plus 6, all over 3 times the quantity of x plus 4
The simplified expression of the given equation is [tex]\frac{x^{2} + 4x + 6}{3x + 12}[/tex]
There are three basic steps for addition or subtraction of two fractions
Step 1: Make sure the bottom numbers (the denominators) are the sameStep 2: Add the top numbers (the numerators), put that answer over the denominatorStep 3: Simplify the fraction (if possible)The given expression :- [tex]\frac{x+6}{x+4} +\frac{x-3}{3}[/tex]
Taking LCM or making the denominators same we get,
= {3(x+6) + (x-3)(x+4)}/3(x+4)
= {3x + 18 + x² +x -12}/3(x+4)
={x² + 4x + 6}/3x + 12
= [tex]\frac{x^{2} + 4x + 6}{3x + 12}[/tex]
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Answer:
i believe its B
Step-by-step explanation:
After defeating the fire breathing dragon, the knight decides
to celebrate his victory with a celebratory goblet made out of Dragon Alloy #17, which is 36% gold, 9% silver, and 55% magic steel. The dwarves have Dragon Alloy #11, which is 36% gold, 28% magic steel, and the rest silver. They also have Dragon Alloy #15, which is 36% gold and 64% magic steel. How many grams of each
alloy should the dwarves combine to get 1 kg of Dragon Alloy #17?
250 grams of dragon alloy #11 and 750 grams of dragon alloy #35 is needed to make 1000 grams (1 kg) of Dragon alloy #17.
What is an equation?An equation is an expression that shows the relationship between two or more numbers and variables.
Let x represent the amount of alloy #11 and y represent the amount of alloy #15, hence:
(0.36x) + (y * 0.36) = 1(0.36) (1)
Also:
0.28x + 0.64y = 1(0.55) (2)
From both equations:
x = 0.25, y = 0.75
250 grams of dragon alloy #11 and 750 grams of dragon alloy #35 is needed to make 1000 grams (1 kg) of Dragon alloy #17.
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If someone could help me with this problem
The equation of the given Absolute Value Function is; y = |-2x + 4|
How to interpret Linear Graphs?We can see that the given graph is a Linear graph but since it is V-shaped, we can say that it is a graph of an absolute value function.
Now, from the graph we see that;
At x = 0, y = 4
At x = 1, y = 2
At x = 2, y = 0
At x = 3, y = -2
At x = 4, y = 0
At x = 5, y = 2
We can see that the y-intercept is at y = 4.
Slope between two consecutive points is;
(2 - 4)/(1 - 0) = -2
Equation is; y = -2x + 4
Now, this is an absolute value function and as such we will write it as;
y = |-2x + 4|
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someone please help me on this question
i need detailed step by step explaination with reasoning
[tex] \qquad \qquad \bf \huge\star \: \: \large{ \underline{Answer} } \huge \: \: \star[/tex]
Correct option - C[tex]\textsf{ \underline{\underline{Steps to solve the problem} }:}[/tex]
Area left for flowers = Area of flower garden - Area of bird bath.
Area of flower garden [ rectangle ] :
[tex]\qquad❖ \: \sf \:length \times width[/tex]
[tex]\qquad❖ \: \sf \:3 \times 2[/tex]
[tex]\qquad❖ \: \sf \: 6\: \: {m}^{2} [/tex]
Area of bird bath [ Circle ] :
[tex]\qquad❖ \: \sf \: \pi{r}^{2} [/tex]
[tex]\qquad❖ \: \sf \:3.14 \times ( \frac{1}{2} ) {}^{2} [/tex]
[tex]\qquad❖ \: \sf \:3.14 \times \frac{1}{4} [/tex]
[tex]\qquad❖ \: \sf \:0.785 \: \: m {}^{2} [/tex]
Area left for flowers :
[tex]\qquad❖ \: \sf \:6 - 0.785[/tex]
[tex]\qquad❖ \: \sf \:5.215 \: \: m {}^{2} [/tex]
[tex]\qquad❖ \: \sf \: \approx5.22 \: \: m {}^{2} [/tex]
[tex] \qquad \large \sf {Conclusion} : [/tex]
Correct option - Cselect the correct answer which graph is defined by f(x)= |x^2 -x-2|
The graph of the absolute value function can be seen below.
How to get the graph of f(x)?Here we have the absolute value function:
[tex]f(x) = |x^2 - x -2|[/tex]
Notice that the argument of the absolute value function is a quadratic equation, then the graph of the function f(x) will be the graph of the quadratic equation, but such that the part below the horizontal axis is reflected.
Then the graph of the function is the one you can see below:
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The variable y varies directly as x. When x = 20, y = 12. What is the value of ywhen x = 15?
The value of y at x =15 is 9.
What is Direct Variation?Two variables are said to be in Direct Variation when increasing one variable the other also increases.
The direct variation is represented by
y ∝ x
y = kx
where k is the proportionality constant
the value of y =12 , x = 20
12 = k * 20
12/20 = k
k = 0.6
The equation becomes
y = 0.6 x
The value of y at x = 15 is
y = 0.6 * 15
y =9
Therefore, the value of y at x =15 is 9.
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How many triangles are created in the following situation:
m/A=35°, a = 12,b=16
1 triangle
2 triangles
3 triangles
no triangle
Answer:
Step-by-step explanation:
3 things of triangle are given.
2 sides + 1 angle
so, possible triangles = 1 ans
write equation that has base of 3 stretched vertically by factor of 2/3 reflected in y axis, asymptote of y=2 and passes through point (0,3,5)
The exponential equation is [tex]y = \frac23(3)^{-x+0.74} + 2[/tex]
How to determine the equation?An exponential function is represented as:
[tex]y = b^x[/tex]
The base is 3.
So, we have:
[tex]y = 3^x[/tex]
It is stretched vertically by 2/3.
So, we have:
[tex]y = \frac23(3)^x[/tex]
When reflected over the y-axis, we have:
[tex]y = \frac23(3)^{-x}[/tex]
An asymptote of y = 2, makes the function becomes
[tex]y = \frac23(3)^{-x} + 2[/tex]
Lastly, it passes through the point (0, 3.5).
So, we have:
[tex]y = \frac23(3)^{-x+h} + 2[/tex]
This gives
[tex]3.5 = \frac23(3)^{-0+h} + 2[/tex]
[tex]3.5 = \frac23(3)^{h} + 2[/tex]
Subtract 2 from both sides
[tex]1.5 = \frac23(3)^{h}[/tex]
Multiply by 3/2
[tex]2.25 = (3)^{h}[/tex]
Take the logarithm of both sides
log(2.25) = h * log(3)
Solve for h
h = 0.74
Substitute h = 0.74 in [tex]y = \frac23(3)^{-x+h} + 2[/tex]
[tex]y = \frac23(3)^{-x+0.74} + 2[/tex]
Hence, the exponential equation is [tex]y = \frac23(3)^{-x+0.74} + 2[/tex]
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