Answer:
[tex]base = 8 ft\\height =28 ft\\[/tex]
Step-by-step explanation:
let base be x ft. then the height is 3x+4
[tex]Area=\frac{1}{2} \times x \times (3x+4)=112\\3x^{2} +4x=224\\3x^{2} +4x-224=0\\x=8, x=-9.33 (no sol. as length can not be negative)\\ x=8\\base = 8 ft\\height =3(8)+4=28 ft\\[/tex]
Answer:
base = 8 , height = 28
Step-by-step explanation:
Let base be = b
Given:
height is 3times base = 3b
Also 4 feet more than 3 times base = 3b + 4
Area = 112 square feet
[tex]area = \frac{1}{2} \times base \times height\\\\112 = \frac{1}{2} \times b \times (3b+ 4)\\\\224 = b(3b+4)\\\\224 = 3b^2 + 4b\\\\3b^2 + 4b - 224 = 0\\\\[/tex]
The quadratic equation with a = 3 , x = 4 , c = -224
Therefore ,
[tex]b = \frac{-x \pm \sqrt{x^2 - 4ac}}{2a}\\\\[/tex]
[tex]b= \frac{-4 \pm \sqrt{4^2 - (4 \times 3 \imes -224)}}{2 \times 3}\\\\b= \frac{-4 \pm \sqrt{16 + 2688}}{6}\\\\b= \frac{-4 \pm \sqrt{2704}}{6}\\\\b= \frac{-4 \pm52 }{6}\\\\b = \frac{-4 + 52}{6} , \ b = \frac{-4 -52}{6}\\\\b = \frac{48}{6} , \ b = -\frac{56}{6}[/tex]
Since base can't be negative base = 8 ft
Therefore , height = 3b + 4 = 3(8) + 4 = 24 + 4 = 28
Given the vectors u= <2, 1> and v= <5, 4>, determine the components of a vector represented by 2u - 3v
A.) <14, 15>
B.) <-6, -9>
C.) <-11, -10>
D.) <19, 14>
Answer:
C.) <-11, -10>
Step-by-step explanation:
Let's define how to work with vectors.
For two vectors:
V = <a, b>
W = <c, d>
The product of a scalar k and a vector is given by:
k*V = k*<a, b> = <k*a, k*b>
And the sum (or difference) of two vectors is given by:
V ± W = <a, b> ± <c, d> = <a ± c, b ± d>
Now that we know this, we can solve the problem.
Here we have the vectors:
u = <2, 1>
v = <5, 4>
then:
2u - 3*v = 2*<2, 1> - 3*<5, 4>
= <2*2, 2*1> - <3*5, 3*4>
= <4, 2> - <15, 12>
= <4 - 15, 2 - 12>
= < -11, -10>
Then the correct option is C.
For an outdoor concert by the city orchestra, concert organizers estimate that 19,000 people will attend if it is not raining. If it is raining, concert organizers estimate that 4000 people will
attend. On the day of the concert, meteorologists predict a 60% chance of rain. Determine the expected number of people who will attend this concert.
It is expected that people will attend the concert.
Answer:
Hope it helps you stay safe<3The Coast Starlight Amtrak train runs from Seattle to Los Angeles. The mean travel time from one stop to the next on the Coast Starlight is 129 mins, with a standard deviation of 113 minutes. The mean distance traveled from one stop to the next is 108 miles with a standard deviation of 99 miles. The correlation between travel time and distance is 0.636.
Required:
a. Write the equation of the regression line from predicting travel time.
b. Interpret the slope and the intercept in this context.
c. Calculate R2 of the regression line for predicting travel time from distance traveled for the Coast Starlight, and interpret R2 in the context of the application.
Solution :
a).
Given :
R = 0.636, [tex]$S_x = 99$[/tex], [tex]$S_y=113, M_x=108, M_y=129$[/tex]
Here R = correlation between the two variables
[tex]$S_x , S_y$[/tex] = sample standard deviations of the distance and travel time between the two train stops, respectively.
[tex]$M_x, M_y$[/tex] = means of the distance and travel between two train stops respectively.
The slope of the regression line is given by :
Regression line, [tex]b_1[/tex] [tex]$=R \times \left(\frac{S_y}{S_x}\right)$[/tex]
[tex]$=0.636 \times \left(\frac{113}{99}\right)$[/tex]
= 0.726
Therefore, the slope of the regression line [tex]b_1[/tex] is 0.726
The equation of the regression line is given by :
[tex]$\overline {y} = b_0+b_1 \overline x$[/tex]
The regression line also has to pass through the two means. That is, it has to pass through points (108, 129). Substituting these values in the equation of the regression line, we can get the value of the line y-intercept.
The y-intercept of the regression line [tex]$b_0$[/tex] is given by :
[tex]$b_0=M_y-(b_1 \times M_x)$[/tex]
= 129 - (0.726 x 108)
= 50.592
Therefore, the equation of the line is :
Travel time = 20.592 + 0.726 x distance
b).[tex]\text{ The slope of the line predicts that it will require 0.726 minutes}[/tex] for each additional mile travelled.
The intercept of the line, [tex]$b_0$[/tex] = 0.529 can be seen as the time when the distance travelled is zero. It does not make much sense in this context because it seems we have travelled zero distance in 50.529 minutes, but we could interpret it as that the wait time after which we start travelling and calculating the distance travelled and the additional time required per mile. Or we could view the intercept value as the time it takes to walk to the train station before we board the train. So this is a fixed quantity that will be added to travel time. It all depends on the interpretation.
c). [tex]$R^2=0.404$[/tex]
This means that the model accounts for around 40.4% variation in the travel time.
Lines DE and AB intersect at point C.
What is the value of x?
А.
|(2x + 2)
с
(5x + 3)
Given:
Lines DE and AB intersect at point C.
To find:
The value of x.
Solution:
In the given figure it is clear that the angles and are lie on a straight line AB.
[Linear pair]
Subtract 5 from both sides.
Divide both sides by 7.
Therefore, the correct option is B.
[tex] {x}^{2} + 2x = 0[/tex]
Answer:
[tex]\textbf{Hello!}[/tex]
[tex]\Longrightarrow2^2+2z=0[/tex]
[tex]\Longrightarrow x_{1,\:2}=\frac{-2\pm \sqrt{2^2-4\cdot \:1\cdot \:0}}{2\cdot \:1}[/tex]
[tex]\Longrightarrow \sqrt{2^2-4\cdot \:1\cdot \:0}[/tex]
[tex]\Longrightarrow =\sqrt{2^2-0}[/tex]
[tex]\Longrightarrow =\sqrt{2^2}[/tex]
[tex]\Longrightarrow=2[/tex]
[tex]\Longrightarrow x_{1,\:2}=\frac{-2\pm \:2}{2\cdot \:1}[/tex]
[tex]\Longrightarrow x_1=\frac{-2+2}{2\cdot \:1},\:x_2=\frac{-2-2}{2\cdot \:1}[/tex]
[tex]\Longrightarrow\frac{-2+2}{2\cdot \:1}[/tex]
[tex]\Longrightarrow =\frac{0}{2\cdot \:1}[/tex]
[tex]\Longrightarrow =\frac{0}{2}[/tex]
[tex]=0[/tex]
[tex]\Longrightarrow\frac{-2-2}{2\cdot \:1}[/tex]
[tex]\Longrightarrow =\frac{-4}{2\cdot \:1}[/tex]
[tex]\Longrightarrow =\frac{-4}{2}[/tex]
[tex]\Longrightarrow =-\frac{4}{2}[/tex]
[tex]=-2[/tex]
[tex]x=0,\:x=-2\Longleftarrow[/tex]
[tex]\underline{HOPE ~IT~HELPS}[/tex]
Find the perimeter of the figure below, in feet.(Note: diagram is NOT to scale)
What is the equation, in point-slope form, of the line that
is perpendicular to the given line and passes through the
point (-4,-3)?
Answer:
The equation of the line is [tex]y + 3 = m(x + 4)[/tex], in which m is found as such [tex]am = -1[/tex], considering a the slope of the given line.
Step-by-step explanation:
Equation of a line:
The equation of a line, in point-slope form, is given by:
[tex]y - y_0 = m(x - x_0)[/tex]
In which m is the slope and the point is [tex](x_0,y_0)[/tex]
Perpendicular lines:
If two lines are perpendicular, the multiplication of their slopes is -1.
Passes through the point (-4,-3)
This means that [tex]x_0 = -4, y_0 = -3[/tex]
So
[tex]y - y_0 = m(x - x_0)[/tex]
[tex]y - (-3) = m(x - (-4))[/tex]
[tex]y + 3 = m(x + 4)[/tex]
The equation of the line is [tex]y + 3 = m(x + 4)[/tex], in which m is found as such [tex]am = -1[/tex], considering a the slope of the given line.
HELP!! FAST!!
Which represents a recursion function?
A. Xn = f(Xn)
B. Xn = f(X0)
C. Xn = f(a1)
D. Xn = f(Xn-1)
(Picture added for more info)
Answer: Choice D
[tex]x_n = f(x_{n-1})[/tex]
This basically says "the nth term is found by computing math, aka evaluating some function, based on the (n-1)th term".
As an example, we could have a function that simply squares the input
Let's say we started at 5. It squares to 25 which in turns squares to 625, and so on. Each new term is based on the old term. Namely, we squared the old n-1 term to get the new nth term.
6) Find the difference of (4x - 5) and (6x + 8)
Answer:
[tex]-2x- 13[/tex]
Step-by-step explanation:
Hi there!
[tex](4x - 5)-(6x + 8)[/tex]
Open up the parentheses
[tex]4x - 5-6x - 8[/tex]
Combine like terms
[tex]4x -6x- 5 - 8\\-2x- 13[/tex]
I hope this helps!
Answer:
- 2 - 13
Step-by-step explanation:
( 4 x - 5 ) - ( 6 x + 8 )
= 4 x - 5 - 6 x + 8
Arranging like terms together
= 4 x - 6 x - 5 - 8
= - 2 x - 13
I need help I’ll give u brainlest
Answer:
1000
Step-by-step explanation:
Volume = 10 * 10 * 10 = 1000
Answer:
[tex]Volume = 1000[/tex]
Step-by-step explanation:
Formula to find volume of cube:
[tex]Volume=a^{3}[/tex]
[tex]Volume = 10^{3}[/tex]
[tex]Volume = 10*10*10[/tex]
[tex]Volume = 1,000[/tex]
hope this helps.....
PLS HELP ME ILL GIVE BRAINLIEST FOR THE 2 QUESTIONSSS
Answer:
can you turn up your brightness i can barely see it
Step-by-step explanation:
What is the area of the irregular polygon shown below?
6
6
4.1
6
6
10
A. 121.5 sq. units
B. 108 sq. units
C. 56 sq. units
O D. 216 sq. units
The area of the irregular polygon is 121.5 units squared.
How to find the area of an irregular polygon?
The irregular polygon can be divided into a rectangle and a pentagon.
Therefore, the area is the sum of the area of the pentagon and the rectangle.
Therefore,
area of the rectangle = 6 × 10 = 60 units²
area of the pentagon = 1/ 2 × perimeter × apothem
area of the pentagon = 1 / 2 × 30 × 4.1
area of the pentagon = 123 / 2
area of the pentagon = 61.5 units²
Therefore,
area of the irregular polygon = 61.5 + 60 = 121.5 units²
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How many lakhs are there in 4 million?
Now,
1 million = 10 lakhs
4 millions = 10 * 4
= 40 lakhs
There are 40 lakhs in 4 millions.
I hope it's help you...
Mark me as brainliest...
Answer: There are 40 lakhs in 4 million.
Step-by-step explanation:
A lakh is 1,00,000. We can divide 4 million by 1,00,000 to get our answer.
[tex]\frac{4,000,000}{1,00,000}[/tex]
The 5 zeros on the 4 million and on 1,00.000 cancel each other out giving us
[tex]\frac{40}{1} \\40[/tex]
Find the length of the missing side. Leave your answer in simplest radical form.
Hyp = 15yd
Leg = 13yd
Leg = X
Answer:
The other side is 7.48 yards.
Step-by-step explanation:
Given that,
Hypotenuse = 15 yards
One leg = 13 yards
We need to find the length of the other leg. We can use the Pythagoras theorem to find it such that,
[tex]H^2=b^2+h^2[/tex]
Where
h is other leg
Put all the values,
[tex]h=\sqrt{H^2-b^2} \\\\h=\sqrt{(15)^2-(13)^2} \\\\h=7.48\ yd[/tex]
So, the other side is 7.48 yards.
In a regression analysis involving 30 observations, the following estimated regressionequation was obtained.y^ =17.6+3.8x 1 −2.3x 2 +7.6x 3 +2.7x 4For this estimated regression equation SST = 1805 and SSR = 1760. a. At \alpha =α= .05, test the significance of the relationship among the variables.Suppose variables x 1 and x 4 are dropped from the model and the following estimatedregression equation is obtained.y^ =11.1−3.6x 2 +8.1x 3For this model SST = 1805 and SSR = 1705.b. Compute SSE(x 1 ,x 2 ,x 3 ,x 4 )c. Compute SSE (x2 ,x3 ) d. Use an F test and a .05 level of significance to determine whether x1 and x4 contribute significantly to the model.
Answer:
(a) There is a significant relationship between y and [tex]x_1, x_2, x_3, x_4[/tex]
(b) [tex]SSE_{(x_1 ,x_2 ,x_3 ,x_4) }= 45[/tex]
(c) [tex]SSE_{(x_2,x_3)} = 100[/tex]
(d) [tex]x_1[/tex] and [tex]x_4[/tex] are significant
Step-by-step explanation:
Given
[tex]y = 17.6+3.8x_1 - 2.3x_2 +7.6x_3 +2.7x_4[/tex] --- estimated regression equation
[tex]n = 30[/tex]
[tex]p = 4[/tex] --- independent variables i.e. x1 to x4
[tex]SSR = 1760[/tex]
[tex]SST = 1805[/tex]
[tex]\alpha = 0.05[/tex]
Solving (a): Test of significance
We have:
[tex]H_o :[/tex] There is no significant relationship between y and [tex]x_1, x_2, x_3, x_4[/tex]
[tex]H_a :[/tex] There is a significant relationship between y and [tex]x_1, x_2, x_3, x_4[/tex]
First, we calculate the t-score using:
[tex]t = \frac{SSR}{p} \div \frac{SST - SSR}{n - p - 1}[/tex]
[tex]t = \frac{1760}{4} \div \frac{1805- 1760}{30 - 4 - 1}[/tex]
[tex]t = 440 \div \frac{45}{25}[/tex]
[tex]t = 440 \div 1.8[/tex]
[tex]t = 244.44[/tex]
Next, we calculate the p value from the t score
Where:
[tex]df = n - p - 1[/tex]
[tex]df = 30 -4 - 1=25[/tex]
The p value when [tex]t = 244.44[/tex] and [tex]df = 25[/tex] is:
[tex]p =0[/tex]
So:
[tex]p < \alpha[/tex] i.e. [tex]0 < 0.05[/tex]
Solving (b): [tex]SSE(x_1 ,x_2 ,x_3 ,x_4)[/tex]
To calculate SSE, we use:
[tex]SSE = SST - SSR[/tex]
Given that:
[tex]SSR = 1760[/tex] ----------- [tex](x_1 ,x_2 ,x_3 ,x_4)[/tex]
[tex]SST = 1805[/tex]
So:
[tex]SSE_{(x_1 ,x_2 ,x_3 ,x_4)} = 1805 - 1760[/tex]
[tex]SSE_{(x_1 ,x_2 ,x_3 ,x_4) }= 45[/tex]
Solving (c): [tex]SSE(x_2 ,x_3)[/tex]
To calculate SSE, we use:
[tex]SSE = SST - SSR[/tex]
Given that:
[tex]SSR = 1705[/tex] ----------- [tex](x_2 ,x_3)[/tex]
[tex]SST = 1805[/tex]
So:
[tex]SSE_{(x_2,x_3)} = 1805 - 1705[/tex]
[tex]SSE_{(x_2,x_3)} = 100[/tex]
Solving (d): F test of significance
The null and alternate hypothesis are:
We have:
[tex]H_o :[/tex] [tex]x_1[/tex] and [tex]x_4[/tex] are not significant
[tex]H_a :[/tex] [tex]x_1[/tex] and [tex]x_4[/tex] are significant
For this model:
[tex]y =11.1 -3.6x_2+8.1x_3[/tex]
[tex]SSE_{(x_2,x_3)} = 100[/tex]
[tex]SST = 1805[/tex]
[tex]SSR_{(x_2 ,x_3)} = 1705[/tex]
[tex]SSE_{(x_1 ,x_2 ,x_3 ,x_4) }= 45[/tex]
[tex]p_{(x_2,x_3)} = 2[/tex]
[tex]\alpha = 0.05[/tex]
Calculate the t-score
[tex]t = \frac{SSE_{(x_2,x_3)}-SSE_{(x_1,x_2,x_3,x_4)}}{p_{(x_2,x_3)}} \div \frac{SSE_{(x_1,x_2,x_3,x_4)}}{n - p - 1}[/tex]
[tex]t = \frac{100-45}{2} \div \frac{45}{30 - 4 - 1}[/tex]
[tex]t = \frac{55}{2} \div \frac{45}{25}[/tex]
[tex]t = 27.5 \div 1.8[/tex]
[tex]t = 15.28[/tex]
Next, we calculate the p value from the t score
Where:
[tex]df = n - p - 1[/tex]
[tex]df = 30 -4 - 1=25[/tex]
The p value when [tex]t = 15.28[/tex] and [tex]df = 25[/tex] is:
[tex]p =0[/tex]
So:
[tex]p < \alpha[/tex] i.e. [tex]0 < 0.05[/tex]
Hence, we reject the null hypothesis
find the 11th term of the series
8,14,20,26.......
Answer:
a11 = 8+(11-1)6
a11 = 8+54
a11=68
hopefully this is correct
Step-by-step explanation:
Choose the correct Set-builder form for the following set written in Roster form: { − 2 , − 1 , 0 , 1 , 2 }
Step-by-step explanation:
{x:x is an integer where x>-3 and x<3}
Which of the following coordinates exists on the line y = 2x + 4?
A. (2, 4)
B. (1, 5)
C. (-3, -2)
D. (-1, 3)
Help me pls I don’t know how to do this
Answer:
[tex]radius=6.68cm[/tex]
Step-by-step explanation:
Formula to find radius:
[tex]r=\frac{C}{2\pi }[/tex]
[tex]r=42/2\pi[/tex]
[tex]r=42/2(3.14)[/tex]
[tex]r=6.68cm[/tex]
hope this helps......
Simplify (5 square root 2 - 1 ) ^2
Answer:
576
Step-by-step explanation:
5 square root 2 is 25
25 minus 1 is 24
24 square root 2 is 576
Answer:
25
Step-by-step explanation:
[tex](5\sqrt{(2-1)} ^{2}[/tex]
[tex](5\sqrt{1}) ^{2}[/tex]
Center(1/2+1/3) Radius=2/3
Answer:
[tex]{ \bf{ {x}^{2} + {y}^{2} - \frac{1}{2} x - \frac{1}{3} y}} - \frac{1}{12} = 0[/tex]
Which relationship is always true for the angles x,y and z of triangle ABC
Answer:
B. y + z = x
Step-by-step explanation:
x is an exterior angle of the triangle.
y and z are the opposite angles opposite the exterior angle.
The exterior angle theorem of a triangle states that the measure of an exterior angle equals the measure of the sum of the two angles opposite the exterior angle.
Thus:
y + z = x
A movie theater sells matinee tickets for $6 each and has a capacity of 100 people. The function M(x) = 6x represents the amount of money the movie theater makes from ticket sales,
where x is the number of customers. What would be the most appropriate domain for the function? (1 point)
Whole numbers less than or equal to 100
Whole numbers that are multiples of 6
All real numbers
All whole numbers
Answer:
A. Whole numbers less than or equal to 100
Step-by-step explanation:
The domain is the set of x numbers that can be plugged in to a certain equation.
Since the capacity of this movie theater is 100, x can be between 0 and 100, inclusive.
Answer choice A makes sense because whole numbers are definitionally positive integers and this choice caps out at 100.
A department store, on average, has daily sales of $21,000. The standard deviation of sales is $3600. On Tuesday, the store sold $16,230 worth of goods. Find Tuesday's z score. What is the percentile rank of sales for this day
Answer:
Tuesday's z-score was of -1.325.
The percentile rank of sales for this day was the 9.25th percentile.
Step-by-step explanation:
Z-score:
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
A department store, on average, has daily sales of $21,000. The standard deviation of sales is $3600.
This means that [tex]\mu = 21000, \sigma = 3600[/tex]
On Tuesday, the store sold $16,230 worth of goods. Find Tuesday's z score.
This is Z when X = 16230. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{16230 - 21000}{3600}[/tex]
[tex]Z = -1.325[/tex]
Tuesday's z-score was of -1.325.
What is the percentile rank of sales for this day
This is the p-value of Z = -1.325.
Looking at the z-table, this is of 0.0925, and thus:
The percentile rank of sales for this day was the 9.25th percentile.
In grade 6, there are 40 students. There are 8 girls, find the percentage of the boys?
Answer:
[tex]40 - 8 = 32 \\ \frac{32}{40} \times 100 \\ = 80\%[/tex]
a scalene triangle has angles of 53 degree and 69 degree .what is the measure of it third angles?
Answer:
x+53+69=180
x+122=180
x=180-122
x=58
What does X equal ????
A study of 133 investmen managers revealed the following make an inference about the population of all investment managers concerning the average return expected on equities over the next 12 months for equities was 11.2%.
21% selected health care as the sector most likely to lead the market in the next 12 months.
When asked to estimate how long it would take for technology and telecom stocks to resume sustainable growth, the managers’ average response was 2.5 years.
a. Cite two descriptive statistics.
b. Make an inference about the population of all investment managers concerning the average return expected on equities over the next 12 months.
c. Make an inference about the length of time it will take for technology and telecom stocks to resume sustainable growth.
Answer:
(A.)
21% selected health care as the sector most likely to lead the market in the next 12 months.
47% of managers classified themselves as bullish or very bullish on the stock market.
(B.)
The average return expected on equities over the next 12 months for equities was 11.2% for the population of investment managers.
(C.)
The length of time it will take for technology and telecom stocks to resume sustainable growth is estimated to be about 2.5 years by investment managers.
Step-by-step explanation:
Descriptive statistics gives a quantitative evaluation of particular scenario or information.
Here, the percentage of people who selected health care to lead the market in the next 12 months and the the percentage of managers who classified themselves as bullish or very bullish are examples of descriptive statistics.
The inference Given in the problem is about all investment managers, which is the population mean.
And the lengtb of time it will take for technology and telecom stocks to resume sustainable growth is estimated to be about 2.5 years by investment managers.
Jill calls a plumber to her house to fix the leaking faucets . The plumber charges a one-time fee of $50 plus an additional $35 per hour of labor. What are the independent and dependent variables
Answer:
independent=$50
dependent=$35X
Step-by-step explanation:
50 is the independent variable because it doesn't change.
35X is the dependent variable because it does change.
In this scenario, the independent variable is the number of hours of labor and dependent variable is the total cost.
The independent variable is the number of hours. It is the variable that we can control or change.
The dependent variable is the total cost charged by the plumber.
It depends on the number of hours of labor and is determined by the plumber's fee structure, which includes a one-time fee of $50 plus $35 per hour of labor.
The total cost is calculated based on the number of hours of labor, making it the dependent variable in this situation.
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Công ty X nhập khẩu trực tiếp 500 bếp hồng ngoại từ công ty Sunhouse có giá mua trên hóa đơn là 50 USD / cái. Thuế suất thuế nhập khẩu là 5%, thuế suất thuế GTGT hàng nhập khẩu là 10%. Hàng về kho đủ, tiền chưa thanh toán cho người bán. Biết tỷ giá giao dịch thực tế mua 23.100 VNĐ / USD, bán 23.200 VNĐ / USD, Tỷ giá tính thuế của hải quan là 23.500 VNĐ / USD. Kế toán ghi bút toán thuế GTGT hàng nhập khẩu?