A jet stream is a fast-flowing, narrow air current found in the upper levels of the Earth's atmosphere. It is formed due to differences in air temperature and pressure, and it can have a significant impact on the weather and climate.
Jet streams are formed as a result of the movement of air from warm to cold regions.
The Great Red Spot (GRS) on Jupiter is a long-lived, high-pressure storm that has been observed for over 300 years. Scientists believe that the stability and longevity of the GRS can be attributed to several factors, including:
Jupiter's massive size and rotation: Jupiter is much larger and rotates much faster than Earth, which creates a strong and stable jet stream that helps to maintain the storm's structure.Jupiter's deep and warm atmosphere: The atmosphere of Jupiter is much deeper and warmer than Earth's, which helps to maintain the heat and energy needed to sustain the storm.The absence of land masses: Unlike Earth, Jupiter does not have any land masses to disrupt the storm, which helps to maintain its stability.Upwelling of deep atmospheric gases: The GRS is believed to be associated with a deep, upwelling of gases from Jupiter's interior, which provides a continuous source of energy and stability to the storm.To know more about jet streams refer to:
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When a soccer ball is rolling along a grassy field, it does not continue moving forever. What force is acting upon it to change its state?.
The force that acting upon it to change its state is a ball's movement is able to stop because of an unbalanced force that affects the ball's motion. The unbalanced force is called friction.
In the term of physics, Friction generally can be defined as a type of force that limits motion between two surfaces that are in contact. causing the force to be unbalanced. Friction usually occurs between the grass and the ball. Frictional force generally can be defined as the force that occurs as a result of the contact of two surfaces due to the displacement of one or both of these objects. There are several examples of friction, Examples of frictional forces such as Pencil and paper friction while writing.
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show that if the tatallinear momentum of a system of particles is zero, angular momentum
Given: [tex]\\$\sum_{i} \boldsymbol{p}_{i}=0$.[/tex] Angular momentum: [tex]\\$$\boldsymbol{J}=\sum_{i} \boldsymbol{r}_{i} \times \boldsymbol{p}_{i}$$[/tex]
A new system of axes: [tex]\\$\boldsymbol{r}_{i}^{\prime}=\boldsymbol{r}_{i}+\boldsymbol{R}$,[/tex] where [tex]$d \boldsymbol{R} / d t=0$[/tex] because we are effecting an instantaneous shift in the axes. Hence, [tex]\\$\boldsymbol{p}_{i}^{\prime}=\boldsymbol{p}_{i}$,[/tex] and
[tex]$$\begin{aligned}\boldsymbol{J}^{\prime} & =\sum_{i} \boldsymbol{r}_{i}^{\prime} \times \boldsymbol{p}_{i}, \\& =\sum_{i}\left(\boldsymbol{r}_{i}+\boldsymbol{R}\right) \times \boldsymbol{p}_{i}, \\& =\sum_{i}\left(\boldsymbol{r}_{i} \times \boldsymbol{p}_{i}+\boldsymbol{R} \times \boldsymbol{p}_{i}\right), \\& =\boldsymbol{J}+\left(\boldsymbol{R} \times \sum_{i} \boldsymbol{p}_{i}\right), \\& =\boldsymbol{J} .\end{aligned}$$[/tex]
A property known as angular momentum describes the rotational inertia of an object or system of objects when they are moving about an axis that may or may not pass through them. The Earth has spin angular momentum from its daily rotation around its axis and orbital angular momentum from its yearly revolution around the Sun.
An accurate explanation of angular momentum necessitates the identification of both a magnitude and a direction because it is a vector quantity. An orbiting object's angular momentum is proportional to its linear momentum, which is the sum of its mass m and linear velocity v, times the perpendicular distance r from the center of rotation to a line drawn parallel to its instantaneous motion and passing through the center of gravity of the object, or simply mvr.
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Q) Angular momentum : Show that if the total linear momentum of a system of particles is zero, the angular momentum of the system is the same about all origins.
A parallel plate, air filled capacitor, has plates of area 0.80 m^2 and a separation of 0.040 mm. (a) Find the capacitance. (b) If a voltage of 25 volts is applied to the capacitor, what is the magnitude of the charge on each plate? (c) What is the energy stored in the capacitor? Now the plates are filled with strontium titanate having a dielectric constant of 310 and a dielectric strength of 8.0 kV/mm. (d) What is the new value of capacitance? (e) For a voltage of 25 V, what is the charge on each plate? (f) What is the energy stored in the capacitor now? (f) What is the maximum voltage that can be placed across the capacitor?
(a) Capacitance is = 1.10 x 10^-9 C (b) Magnitude is 2.75 x 10^-7 (c) Energy stored is 3.13 x 10^-6 J (d) New Capacitance is 2.95 x 10^-8 C (e) Charge on each plate is 7.38 x 10^-7 C (f) Energy is 3.70 x 10^-6 J (g) Max. voltage is 8.17 KV.
(a) The capacitance C of a parallel plate capacitor is given by the formula:
C = ε0 x A / d
where ε0 is the vacuum permittivity (8.854 x 10^-12 F/m), A is the area of the plates (0.80 m^2), and d is the separation between the plates (0.040 mm = 0.040 x 10^-3 m).
C = 8.854 x 10^-12 F/m x 0.80 m^2 / (0.040 x 10^-3 m) = 1.10 x 10^-9 F
So, the capacitance of the capacitor is 1.10 x 10^-9 F.
(b) The charge on each plate Q can be found using the formula:
Q = C x V
where V is the voltage applied to the capacitor (25 V).
Q = 1.10 x 10^-9 F x 25 V
= 2.75 x 10^-7 C
So, the magnitude of the charge on each plate is 2.75 x 10^-7 C.
(c) The energy stored in the capacitor can be calculated using the formula:
Energy = (1/2) x C x V^2
Energy = (1/2) x 1.10 x 10^-9 F x 25 V^2
= 3.13 x 10^-6 J
So, the energy stored in the capacitor is 3.13 x 10^-6 J.
(d) The new value of capacitance can be calculated using the formula:
C = εr x ε0 x A / d
where εr is the relative permittivity (310).
C = 310 x 8.854 x 10^-12 F/m x 0.80 m^2 / (0.040 x 10^-3 m)
= 2.95 x 10^-8 F
So, the new value of capacitance is 2.95 x 10^-8 F.
(e) For a voltage of 25 V, the charge on each plate can be found using the formula:
Q = C x V
Q = 2.95 x 10^-8 F x 25 V = 7.38 x 10^-7 C
So, the charge on each plate is 7.38 x 10^-7 C.
(f) The energy stored in the capacitor can be calculated using the formula:
Energy = (1/2) x C x V^2
Energy = (1/2) x 2.95 x 10^-8 F x 25 V^2
= 3.70 x 10^-6 J
So, the energy stored in the capacitor is 3.70 x 10^-6 J.
(g) The maximum voltage that can be placed across the capacitor can be calculated using the formula:
Vmax = d x ε x E / ε0
where ε is the dielectric constant (310), E is the electric field strength (8.0 kV/mm), and d is the separation between the plates (0.040 mm = 0.040 x 10^-3 m).
Vmax = 0.040 x 10^-3 m x 310 x 8.0 kV/mm / (8.854 x 10^-12 F/m)
= 8.17 kV
So, the maximum voltage that can be placed across the capacitor is 8.17 kV.
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Let the polar coordinates of the point (x,y) be (r,θ). Determine the polar coordinates for the points (a) (−x,y), (b) (−2x,−2y), and (c) (3x,−3y).
Answer: a. (-x, y) = (r, 90° + θ) , b. (−2x, −2y) = (2r, 180° + θ) , c. (3x, −3y) = (3r, 360°- θ)
What are Polar Coordinates?
Suppose we have a point O on the plane called the origin, let's say the axis through that point - x Axis – Called the polar axis.
Then the polar coordinates (r,θ) describes a point at an angle θ to the x-axis and a distance of r units from the origin. The θ value can be specified in degrees or radians.
The conversion from Cartesian to Polar is:
[tex]r= [x2 + y2]^{1/2}[/tex] and θ = tan-1 y/x
a] P = ( - x, y) is a point in the 2nd quadrant.
So, therefore, (-x, y) = (r, 90° + θ)
b] P = (-2x, -2y) is in the 3rd quadrant
=> R' = [(-2x)2 + (-2y)2] = 2R
therefore, (−2x, −2y) = (2r, 180° + θ)
c] P = (3x, - 3y)
Similarly, R' = 3R
and since this point is in the 4th quadrant (3x, −3y) = (3r, 360°- θ)
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The polar coordinates for the points a. (-x, y) = (r, 90° + θ) , b. (−2x, −2y) = (2r, 180° + θ) , c. (3x, −3y) = (3r, 360°- θ)
What are Polar Coordinates?
Polar coordinates are a two-dimensional coordinate system in which each point on a plane is determined by a distance from a reference point (the pole) and an angle from a reference direction. It is most commonly used to plot points on a two-dimensional graph.
Suppose we have a point O on the plane called the origin, let's say the axis through that point - x Axis – Called the polar axis.
Then the polar coordinates (r,θ) describes a point at an angle θ to the x-axis and a distance of r units from the origin. The θ value can be specified in degrees or radians.
The conversion from Cartesian to Polar is:
[tex]r = [x2+y2]^{1/2}[/tex] and θ = tan-1 y/x
a] P = ( - x, y) is a point in the 2nd quadrant.
So, therefore, (-x, y) = (r, 90° + θ)
b] P = (-2x, -2y) is in the 3rd quadrant
=> R' = [(-2x)2 + (-2y)2] = 2R
therefore, (−2x, −2y) = (2r, 180° + θ)
c] P = (3x, - 3y)
Similarly, R' = 3R
and since this point is in the 4th quadrant (3x, −3y) = (3r, 360°- θ)
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gauss’s law is useful for calculating electric fields that are____
Gauss’s law is useful for calculating electric fields that are uniform.A closed surface (GS) can be easily find along which the electric field is uniform.
In material science and electromagnetism, Gauss' regulation, otherwise called Gauss' transition hypothesis, (or once in a while essentially called Gauss' hypothesis) is a regulation relating the dissemination of electric charge to the subsequent electric field. In its basic structure, it expresses that the transition of the electric field out of an erratic shut surface is relative to the electric charge encased by the surface, regardless of how that charge is disseminated. Despite the fact that the law alone is lacking to decide the electric field across a surface encasing any charge dissemination, this might be conceivable in situations where evenness commands consistency of the field. Where no such evenness exists, Gauss' regulation can be utilized in its differential structure, which expresses that the dissimilarity of the electric field is corresponding to the neighborhood thickness of charge.
The law was first[1] figured out by Joseph-Louis Lagrange in 1773,[2] followed via Carl Friedrich Gauss in 1835,[3] both with regards to the fascination of ellipsoids. It is one of Maxwell's four conditions, which frames the premise of old style electrodynamics.[note 1] Gauss' regulation can be utilized to infer Coulomb's law,[4] as well as the other way around.
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determine the magnitude of the resultant force if f1 = 300 n and f2 = 460 n .
We must find the vector sum of f1 and f2 to calculate the magnitude of the resulting force. We may utilize the Pythagorean theorem to do this: Force produced = (f12 + f22) .
in the blanks: Resultant force = (548.47 N) = (3002 + 4602) = (90000 + 211600) = (301600) As a result, the resulting force is 548.47 N. To determine the size of the resulting force, compute the vector sum of the two forces f1 and f2. The Pythagorean theorem may be used to compute the magnitude of the resulting force: R = √(f1^2 + f2^2) R = √(300^2 + 460^2) R = √(90000 + 211600) R = √(301600) R = 550 N As a result, the magnitude of the resulting force is 550 N. We must find the vector sum of f1 and f2 to calculate the magnitude of the resulting force. We may utilize the Pythagorean theorem to do this: Force produced.
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how much energy in joules does a 10-hp motor deliver in 20 minutes.
P = 10 hp = 7460 W
W = pt = 7460 × 30 × 60 J = 13.43\times { 10 }^{ 6 } J horsepower.
Just what does one horsepower mean?
horsepower, or the rate at which work is done, is the standard unit of power. According to the British Imperial System, a horsepower is equivalent to 33,000 foot-pounds of work per minute, or the force required to elevate a mass of 33,000 pounds one foot in a minute.
What makes it one horsepower?
In an effort to describe the strength of steam engines, inventor James Watt coined the term "horsepower" in the 1700s. He observed horses carefully and averaged their power output per minute.
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ector has a magnitude 5.00 and points in a direction 60.0° clockwise from the negative y axis. what are the x and y components of vector .
The x and y components of vector A are directed along negative X and Y axes respectively having magnitudes 4.330 and 2.5 units respectively.
Let the vector be taken as A.
Magnitude of the vector A = |A| = 5 units
We are aware that the positive X-axis and the negative Y-axis form a 270° anti-clockwise angle.
θ = Angle of vector A with positive X-axis = (270° - 60°) = 210°
So, x component of vector A = A x = |A| × cos 210° = |A| × cos (180° + 30°) = |A| × (- cos 30°) = 5 × (-0.866) = -4.330
And, y component of vector A = Ay = |A| × sin 210° = |A| × sin (180° + 30°) = |A| × (- sin 30°) = 5 × (-0.5) = -2.5
Thus, Ax and Ay both are negative relative to positive X and Y axes respectively. So, the x and y components of vector A are directed along negative X and Y axes respectively with magnitudes 4.330 and 2.5 units respectively.
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A cell has an emf of 4.0 V and an internal resistance of 2.0 Ω. The ideal voltmeter reads 3.2V. What is the resistance of R? A. 0.8Ω
B. 2.0Ω
C. 4.0Ω D. 8.0Ω
The resistance of R a cell has an emf of 4.0 V and an internal resistance of 2.0 Ω is 0.8 Ω.
This can be calculated using Ohm's law, which states that the voltage (V) across a resistor is equal to the current (I) multiplied by the resistance (R): V = I x R. Since the ideal voltmeter reads 3.2V, rearranging and solving for R gives R = V/I = 3.2V/4.0A = 0.8Ω. Ohm's law states that the voltage (V) across a resistor is equal to the current (I) multiplied by the resistance (R): V = I x R. This means that if you know the voltage and the resistance, then you can calculate the current, and vice versa. Ohm's law is a fundamental law in electrical engineering and is used to calculate resistance, current, and voltage in electrical circuits.
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An object has a mass of 60 kg. It decelerates from 50 m/s to 20 m/s when a resultant force of 300 n acts on it. For how long does the force act?.
Answer:
To calculate for how long the force of 300 N acts on the object with a mass of 60 kg, you need to calculate the work done by the force using the equation W = F × d, where W is the work done, F is the force and d is the displacement. In this case, the displacement is the difference in velocities (50 m/s - 20 m/s), which is 30 m/s. Therefore, the work done is 300 N × 30 m/s = 9000 Nm. To calculate the time that the force acts, divide the work done by the force: 9000 Nm ÷ 300 N = 30 s. Therefore, the force of 300 N acts on the object for 30 seconds.
For 6 seconds, the force acts on the object.
Speed: The distance traveled by an object per unit time is defined as its speed. Speed is a scalar quantity because it has no direction and only magnitude. The SI unit is meter/second.
Given the following parameters:
F =300N is the resultant force acting on the object.
Object mass: M = 60 kg
As a result,
the object decelerates: a = F/m = 300 N /60kg = 5 m/s2.
Now read
The object's initial speed is u = 50 m/s.
The object's final speed is v = 20 m/s.
Decides the object's speed = u - v = 50 m/s - 20 m/s = 30 m/s.
The deceleration formula is:
deceleration = Decrees in object speed/time taken
Time taken = Decrees in object speed/deceleration
= 30/5 s
= 6s.
As a result, the force acts for 6 seconds.
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How to convert 70 kilograms to pounds?
To convert 70 kilograms to pounds, you must multiply 70 by 2.2046. This is because there are 2.2046 pounds in 1 kilogram.
What is pound ?
Pound is the unit of measurement for weight and mass in the Imperial system of measurement. It is a unit of mass equal to 16 ounces or 0.45 kilograms. It is often used in the United States for measuring the weight of products. Pound is also used in other countries like the United Kingdom, Canada, and Australia. It is denoted by the symbol "lb". Pound is also used to measure force, where it is equal to a mass of one pound multiplied by the acceleration due to gravity, which is 9.8 m/s2.
Therefore, 70 kilograms is equal to 154.323 pounds.
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determine the maximum weight of the crate so that the tension developed in any cable does not exceed 600 lb
To determine the maximum weight of the crate so that the tension developed in any cable does not exceed 600 lb, you need to calculate the tension in each cable and make sure it does not exceed 600 lb.
This can be done by calculating the force between the crate and each cable, and then dividing by the total number of cables. For example, if the force between the crate and a single cable is 1200 lb, then the maximum weight of the crate should be 600 lb.
Therefore, if you are using multiple cables, you may be able to increase the maximum weight of the crate by distributing the weight among the cables. Additionally, the distance between the load and the attachment points of the cables affects the tension in each cable as well.
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When determining the density of the unknown metal, the flask was filled less than one quarter way with the metal instead of halfway. When determining the volume of the flask, the student did not fill the flask completely with water and left approximately 1 ml or air at the top of the flask prior to weighting it. What will be the effect on the measured density of the unknown liquid and the unknown solid?
Density is an important property of a material that helps to identify it. In determining the density of an unknown metal, the volume of the metal and the volume of the flask it occupies play a crucial role. Inaccuracies in measuring these parameters can cause errors in the calculated density. In this scenario, two such inaccuracies have been mentioned - less than one quarter of the metal was filled in the flask and the flask was not completely filled with water when determining its volume. In this text, we will discuss the effects of these inaccuracies on the measured density of the unknown liquid and solid.
Effects on Measured Density:
Less than one quarter of metal in the flask:
When the flask was filled less than one quarter with the metal, it means that the volume occupied by the metal in the flask is smaller than what it should have been. This leads to an overestimation of the density of the metal as the numerator in the density equation (mass) remains the same while the denominator (volume) is smaller. This error will be proportional to the extent of the deviation from one quarter - the greater the deviation, the greater the error in the calculated density.
Flask not completely filled with water:
When determining the volume of the flask, it is important to fill it completely with water. The presence of air at the top of the flask results in an underestimation of its volume, leading to an overestimation of the density of the unknown metal. This is because the numerator in the density equation (mass) remains the same, while the denominator (volume) is smaller. The error will be proportional to the volume of the air present in the flask.
In conclusion, these inaccuracies in measuring the volume of the metal and the flask will result in errors in the calculated density of the unknown metal. To minimize these errors, it is important to follow standard procedures when determining density, including filling the flask halfway with the metal and completely with water when measuring its volume.
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compare the accelerations determined for the acceleration vs time and velocity vs time graphs. calculate their percent difference and discuss. use extra pages if necessary
Finding the area of a velocity-versus-time graph will reveal the displacement because velocity is equal to the product of the displacement and the time. Finding the area of a graph of acceleration vs. time will give you the change in velocity because acceleration is equal to the velocity change divided by the time.
As the word constant denotes steadiness, the graph of velocity vs. time for constant acceleration shows that the acceleration is constant throughout the motion; however, we can determine the change in velocity of a body for a given period by calculating the slope of the plotted curve on the V-T graph. If an item experiences this kind of acceleration, the graph that is drawn will have a linear slope, and these curves are used to calculate only variable velocity.
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Which of the electric field line drawings are incorrect for point charges?
Positive charges cause lines to radiate outward symmetrically from a point charge. The electric field lines should be getting closer to the charge because it is negative.
It is impossible to consider electric field lines as continuous curves. Electric field lines always point away from a positive charge and towards a negative point. In reality, electric fields start with positive charges and end with negative charges. Field lines never cross one another, too. Positive charge always causes electric lines of force to diverge; conversely, negative charge causes them to converge. If there is no charge present at a given spot, the electric field there is continuous. If there is charge there, the field is also discontinuous.
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any substance that occupies space and has a mass is defined as______
Any object with mass and space-occupying properties is referred to as Anything with mass and space is considered matter.
Does energy own mass or take up space?Both mass and space are occupied by matter. Electromagnetic energy, such as heat, electricity, and other types, has no measured mass and cannot be confined in a volume. Energy can be transformed into matter and vice versa. Energy and matter can frequently be found together.
Does air have mass or space?Air has substance, or mass, therefore it is not merely empty space. The molecules in air move all the time. Air being attracted by Earth's gravity and given weight since it has mass. It exerts pressure because it is heavy and indeed the air are continually rubbing against objects.
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How much is 2 liters in cups?
In cups, 2 litres equals 8.45351 cups. To get an approximate answer, multiply the volume value by 4.227.
What is the conversion processof litres to cups?
The liter-to-cup conversion factor is 4.2267528198649, which means that 1 litre equals 4.2267528198649 cups:
1 L = 4.2267528198649 cup
To convert 2 litres to cups, multiply 2 by the conversion factor to get the volume amount from litres to cups. To calculate the result, we can also use a simple proportion:
1 L → 4.2267528198649 cup
2 L → V(cup)
To get the volume V in cups, solve the following proportion:
V(cup) = 2 L × 4.2267528198649 cup
V(cup) = 8.4535056397299 cup
As a final result of this,
2 L → 8.4535056397299 cup
We calculate that 2 litres equal 8.4535056397299 cups:
2 liters = 8.4535056397299 cups
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when we add a displacement vector to another displacement vector, the result is:
University Physics A displacement vector is also a vector quantity as well as the total of all vector quantities given a vector. Therefore, the effect of adding two displacement vectors is another displacement.
The displacement vector can be located in what way?Written as d = (x2 - x1)i + (y2 - y1)j, the displacement vector d from P1 to P2 can be understood. The displacement, denoted by the symbol d, consists of (x2 - x1) units in the x-direction and (y2 - y1) units in the y-direction. d = (((x2 - x1)2 + (y2 - y1)2)12 represents the displacement's magnitude. The Pythagorean theorem leads to this.
The reason why displacement is a vector
A physical quantity with both directions and magnitude is referred to as a vector quantity. The fact that displacement has both a magnitude and a direction makes it a vector quantity.
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a series circuit with a resistor has a voltage drop of 10 v and a current of 5 ma. if the resistance and voltage are doubled, what is the value of the current through the circuit?
In a series circuit current is directly proportional to the voltage and inversely proportional to the resistance so if we double the values of voltage and resistance the current should be same.
Series circuit is the circuit where all the components are connected in a single path for the current flow. In series circuit the total resistance is equal to the sum of all the resistance and total voltage drop is equal to the sum of all the voltage drops across the resistors. According to the Ohm’s law voltage across a conductor is directly proportional to the current flowing through it. I=V/R where I is current, V is voltage and R is resistance.
In the given question V = 10 v, I = 5 ma R=?
From Ohm’s law I=V/R 5 =10/R
R= 10/5 = 2
If we double the value of voltage and resistance the current=?
V=20v, R= 4 then I=?
I=V/R =20/4 = 5ma.
The current remains same.
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A 1-kg ball moving horizontally to the right at 3 m/s strikes a wall and rebounds, moving horizontally to the left at the same speed. What is the magnitude of the change in momentum of the ball?.
The magnitude of the change in momentum of the 1-kg ball is 6 kg-m/s.
This is because momentum is a vector quantity, and the change in momentum is equal to the difference between the initial and final momentum.
In this case, the initial momentum is 3 kg-m/s to the right, and the final momentum is 3 kg-m/s to the left. Therefore, the change in momentum is 6 kg-m/s.
Momentum is an important concept in physics, and it is useful for understanding the behavior of objects in motion. Momentum is a vector quantity, meaning it has both a magnitude and a direction.
Momentum is defined as the product of an object's mass and its velocity. The magnitude of the momentum of an object is equal to the product of its mass and its speed.
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a manometer attached to a pressurized nitrogen tank reads 28 inches of mercury. if the atmospheric pressure is 14.4 psia, what is the absolute pressure in the tank? multiple choice question. 29.1 psia 28.2 psia 13.8 psia 14.4 psia -0.3 psia
A manometer attached to a pressurized nitrogen tank reads 28 inches of mercury. if the atmospheric pressure is 14.4 psia, the absolute pressure in the tank is 28.2 psia.
The atmospheric pressure is 14.4 psia, and the manometer reading is 28 inches of mercury. The difference in pressure between the atmosphere and the pressure in the tank is equal to the difference in height between the liquid levels in the manometer tubes.
1 inch of mercury is equal to approximately 0.491 psia, so 28 inches of mercury is equivalent to:
28 inches * 0.491 psia/inch = 13.788 psia
Therefore, the absolute pressure in the tank is:
14.4 psia + 13.788 psia = 28.188 psia
So, the correct answer is 28.2 psia.
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a 1-kg ball that is traveling at 12.0 m/s collides head-on with a 3-kg ball moving in the opposite direction at a speed of 2.0 m/s. the 1-kg ball bounces backward at 9.0 m/s after the collision. find the speed of the second ball after the collision. (check definitions for options)
Velocity of first ball is -28m/s , and velocity of second ball is -4m/s.
What is Velocity?
Velocity is a vector quantity that describes the rate of change of an object's position. It is equal to the displacement of an object divided by the time interval over which the displacement occurred. Velocity has both magnitude and direction, and its units are typically meters per second (m/s). The velocity of an object can change over time due to acceleration, and if an object is moving in a circular path, it also has a component of velocity perpendicular to its direction of motion, known as centripetal velocity.
Given : Coefficient of restitution
[tex]$e=\dfrac{2}{3}$Velocity of mass[/tex]
[tex]$$1 \mathrm{~kg}$ after the collision is given by \\\\$V_1=\dfrac{\left(m_1-e m_2\right) u_1+(1+e) m_2 u_2}{m_1+m_2}$\\Or $\quad V_1=\dfrac{\left(1-\frac{2}{3} \times 2\right) \times 12+\left(1+\frac{2}{3}\right) \times 2 \times(-24)}{1+2}=-28 \mathrm{~m} / \mathrm{s}$\\[/tex]
[tex]Velocity of mass $2 \mathrm{~kg}$ after the collision is given by \\$V_2=\dfrac{\left(m-e m_1\right) u_2+(1+e) m_1 u_1}{m_1+m_2}$\\Or $\quad V_2=\dfrac{\left(2-\frac{2}{3} \times 1\right) \times(-24)+\left(1+\frac{2}{3}\right) \times 1 \times(12)}{1+2}=-4 \mathrm{~m} / \mathrm{s}$[/tex]
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what percentage of mass is electrons in carbon-12
The percentage of mass is electrons in carbon-12 is 50, 02%.
What is an atomic mass unit?Every element's atomic mass is expressed in terms of the atomic mass unit (AMU or amu). The AMU expresses both the atomic masses and the molecular masses and is commonly referred to as the dalton (Da) or unified atomic mass unit (u). AMU is explained as being one-twelfth the mass of a carbon-12 atom (12C). A carbon-12 atom's mass is precisely 1/12 of an atomic mass unit. The nucleus of an atom of carbon-12 contains six neutrons and six protons. It's written as a.m.u or u. (unified). Atomic masses are expressed using this unit of mass. The average of the neutron rest mass and the proton rest mass is 1 a.m.u. The carbon-12 atom contains 6 protons, neutrons, and electrons. The mass proportion of neutrons is therefore equal to: 6x1.0087/(6x1.0087+6x1.0073+6x5.4858x10^-4)=0.50021110822=50,021110822%.
Solution: 50, 02%.
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the loss of an electrical signal over distance as it travels along a conductor due to resistance is referred to as:
The loss of an electrical signal over distance as it travels along a conductor due to resistance is referred to as voltage drop. Thus, the correct option is B.
What is Voltage drop?Voltage drop is the decrease of the electric potential along the path of a current which is flowing in an electric circuit. Voltage drops in the internal resistance of the source of an electric circuit, across the conductors, across contacts, and across the connectors of an electric circuit are all undesirable because some of the energy supplied to it is dissipated.
Voltage drop of the circuit with conductors can be determined by multiplying the current flowing through the electric circuit with the total resistance of the circuit conductors of the electric circuit:
VD = I x R
where, VD = Voltage Drop,
I = Electric current,
R = Resistance.
Therefore, the correct option is B.
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Your question is incomplete, most probably the complete question is:
The loss of an electrical signal over distance as it travels along a conductor
due to resistance is referred to as:
A) its root mean square
B) voltage drop
C) the ampacity rating
D) a ground and bonding system
Determine the order of the given differential equation and state whether the equation is linear or nonlinear.
According to the question, given differential equation: y + y' = 0.
What is differential equation ?A differential equation is a mathematical equation that relates some function with its derivatives. It is a way to describe how a function changes over time in terms of its rate of change. Differential equations are used to solve a variety of real-world problems, from predicting weather patterns to describing the motion of planets in the solar system. They are also used to model physical systems such as electrical circuits and mechanical systems.
The order of the given differential equation is 1, and it is a linear equation. This is because the equation is linear in the highest derivative, which is y'. There are no other derivatives or nonlinear terms present in the equation.
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what is the magnitude and direction of the force exerted on a charge by a 250 n/c electric field that points due east?
The magnitude of the force exerted by a 250 n/C electric field that points due east is 250 N. The direction of the force is due east.
Calculation:
Force = Electric Field Strength x Charge
F = E x q
F = (250 n/C) x (1 C)
F = 250 N
What is electric field?
Electric field is a physical force field that is created by an electric charge, such as an electron, and exerts a force on other electrically charged objects in its vicinity. Electric fields are the fundamental forces that underlie electricity and magnetism and are responsible for the attraction and repulsion of electrically charged particles.
Therefore, The magnitude of the force exerted by a 250 n/C electric field that points due east is 250 N. The direction of the force is due east.
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find the lagrange point between a 2×1024 kg planet and its 1×1022 kg moon. the planet and moon are 6×108 m away from each other.
The lagrange point between a 2×1024 kg planet and its 1×1022 kg moon can be calculated using formula
x = d (mE - [tex]\sqrt{mEmM}[/tex])
________________ = 6×10⁸ ([tex]\sqrt{2×10²⁴ - 1×10²⁴}[/tex] ) / 2 * 10^24 - 1* 10 ^22
mE - mM
So, putting this formula together we get x = (3.844×108m)(0.9).
A line connecting two objects (often planets or stars) is said to have a Lagrange point when the gravitational pull of each object is equal to the other and there is no net gravitational force acting on the item in the middle. Find the Lagrange point between Earth and its moon to demonstrate this concept. Because Earth is so much heavier than the moon, we naturally anticipate that it will be closer to the moon.
Before inserting numbers, we'll complete the most of the work in algebra. We will then have a formula that we can use for other systems as a result.
Initially, the gravitational force between the Earth and a mass m object is calculated, along with the equivalent force owing to the moon.
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(15 points)what is the ratio of the momentum of a particle with a rest mass mo and kinetic energy ekin to the momentum of a photon of eγ = hv (i.e. pp/pγ), for both
The momentum of a particle with rest mass mo and kinetic energy E_kin is given by the equation:
p = sqrt( (mo^2 * c^2) + (2 * mo * c^2 * E_kin / c^2) )
where c is the speed of light.
The momentum of a photon with energy E_γ is given by the equation:
p_γ = E_γ / c
The ratio of the two momenta is:
p / p_γ = sqrt( (mo^2 * c^2) + (2 * mo * c^2 * E_kin / c^2) ) / (E_γ / c)
= sqrt( (mo^2 * c^2) + (2 * mo * c^2 * E_kin / c^2) ) * c / E_γ
= sqrt( (mo^2 * c^4) + (2 * mo * c^2 * E_kin) ) / E_γ
Note that as the particle approaches the speed of light, its momentum approaches infinity, while the momentum of the photon remains constant.
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what was the approximate net change from april 30 to may 1? express that net charge as a monetary amount and as a percent to the nearest tenth
The $3,528 will be paid in full if it is collected on May 4. Credit sales are listed as accounts receivable, which is a component of short-term assets, on the balance sheet.
Credit sales are contracts that provide that the entire loan balance will be repaid at a later time. The customer does not pay the whole amount due in cash at the time of the sale, in which case the transaction is a credit sale. What is a credit sales entry? To record the sale of goods on credit, a journal entry known as a credit sales item is used in accounting. The entry is created by debiting the Accounts Receivable account and crediting the Sales account. Briefing: .02 x 3600 = 72 3600-72 = $3,528. Financial analysts can comprehend the relative size of one financial statement account to another using accounting ratios.
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Y = 4sin (1000πt/λ + 0. 5x), where y and x are in cm and t is in second. Calculate the;
(i) wavelength (ii) speed and (iii) frequency ; of the wave. [π = 3. 14]
(i) The wavelength of y = 4 sin (1000πt/λ + 0. 5x), where y and x are in cm and t is in second = 12.56 m
(ii) The speed of the wave = 6280 ./s
(iii) The frequency of the wave = 500 Hz
The wave function y(x,t) = A sin(ωt−Kx), the equation itself can be used to read the amplitude, which equals A. The angular frequency can be used to calculate the wave's period.
A = 4
ω = 1000π
k = 0.5
Hence,
(i) The wavelength:
λ = 2π / k
= 2π / 0.5
= 12.56 m
(i) The speed of the wave:
v = f λ
= (500 Hz x 12.56m)
= 6280 m/s
(iii) The frequency of the wave:
f = ω / 2π
= (1000π) / 2π
= 500 Hz
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