The graphs of f(x) = 3x − 2 and g(x) = 2(1.2)x are shown here. Select the table that correctly shows the most accurate approximate value of x for f(x) = g(x).

Answer:

Step-by-step explanation:

$63.03 money

[tex]\begin{cases} x = -4\implies &x+4=0\\ x=-5\implies &x+5=0\\ x = 0\implies &x=0\\ x=\frac{1}{3}\implies &x -\frac{1}{3}=0\\ &3\left( x -\frac{1}{3} \right)=3(0)\\ &3x-1=0 \end{cases} \\\\[-0.35em] ~\dotfill\\\\ (x+4)(x+5)(x)(3x-1)=\stackrel{\textit{original equation}}{0} \\\\\\ (x^2+9x+20)(x)(3x-1)=y\implies (x^3+9x^2+20x)(3x-1)=y \\\\\\ (3x^4+27x^3+60x^2)+(-x^3-9x^2-20x)=y[/tex]

[tex]3x^4+27x^3+60x^2-x^3-9x^2-20x=y \\\\[-0.35em] ~\dotfill\\\\ ~\hfill 3x^4+26x^3+51x^2-20x=y~\hfill[/tex]

9514 1404 393

Answer:

  no solution

Step-by-step explanation:

The solutions to the equation are ...

  tan(θ/7) +√3 = 0

  tan(θ/7) = -√3

  θ/7 = arctan(-√3) +nπ . . . . . . . for integer n

  θ = 7(-π/3 +nπ) = 7π(n -1/3)

For n=0, θ = -7π/3 -- not in the required interval.

For n=1, θ = 14π/3 -- not in the required interval.

There are no solutions in the required interval.

Profit, revenue and cost are related, and can be calculated from one another.

The cost function is given as:

[tex]\mathbf{C(x) =30x + 150}[/tex]

The revenue function is given as:

[tex]\mathbf{R(x) =-0.5(x -90)^2 + 4050}[/tex]

(a) Calculate the profit function

This is calculated using:

[tex]\mathbf{P(x) = R(x) - C(x)}[/tex]

So, we have:

[tex]\mathbf{P(x) =-0.5(x -90)^2 + 4050 - 30x - 150}[/tex]

Evaluate like terms

[tex]\mathbf{P(x) =-0.5(x -90)^2 - 30x + 3900}[/tex]

(b) The domain of the profit function

When profit is 0 or less, then it becomes no profit.

Hence, the domain of the profit function is x > 0

(c) The profit for 60 and 70 items

Substitute 60 and 70 for x in P(x)

[tex]\mathbf{P(60) =-0.5(60 -90)^2 - 30 \times 60 + 3900}[/tex]

[tex]\mathbf{P(60) =1650}[/tex]

The profit when producing 60 items is 1650

[tex]\mathbf{P(70) =-0.5(70 -90)^2 - 30 \times 70 + 3900}[/tex]

[tex]\mathbf{P(70) = 1500}[/tex]

The profit when producing 70 items is 1600

(d) Why producing 10 more units less profit

When a function reaches the optimal value, the value of the function begins to reduce.

This means that, producing 10 more units takes the profit function beyond its maximum point.

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Answer: 14 cm

Step-by-step explanation: A right triangle is an isosceles triangle.

Answer:

2 1/4

Step-by-step explanation:

1. 4

2. 6

3. 10

4. 30

5. 48

6. 55

7. 68

8. 148

9. 102

10. 38

Would appreciate brainly <3

Answer:

Step-by-step explanation:

Use the half angle formulas

sin(θ/2) = ±√((1 - cosθ)/2)

sin(θ/2) = ±√((1 - (3/5))/2)

sin(θ/2) = ±√((2/5)/2)

sin(θ/2) = ±√(1/5)

knowing θ is in the 4th quadrant, θ/2 will be in the second quadrant where sines are positive.

sin(θ/2) = +√(1/5) = √0.2

Answer:

30 pages/min

Step-by-step explanation:

Answer:

y - 6 = -3 ( x - 7)

Step-by-step explanation:

Use one of the points.

m is the slope

Y - Y1 = m(X - X1)

y - 6 = -3(x - 7)

y - 6 = -3x + 21

y - 6 + 3x - 21 = 0

y - 27 + 3x = 0

3x + y - 27 = 0

Answer:

(-4;5)

Step-by-step explanation:

Replace x and y by each of the possible solution until the equation is true. here it is true for (-4 ; 5), because:

3 * (-4) - 2 * 5 = -12 - 10 = -22

Answer:

a= -5

b=5

c=6

substitue each value as x

Answer:

Starting position of mine shaft is = 10m above ground

but,

it moves in opposite direction so it travels the distance (-350 m ) below the ground.

Total distance covered by mine shaft = 10m - (-350m)

= 10 + 350

= 360m

Now, taken to cover a distance of 6m by it = 1 minute

Time taken to cover a distance of 1m by it = \frac{1}{6\ }\min

Therefore, tie taken to a cover a distance of 360m = \frac{1}{6}\times\ 360\ =\ 60\ \min\ \

60 minutes = 1 hour

thus, in one hour the mine shraft reaches = 350 below the ground

Step-by-step explanation:

Answer:

2

Step-by-step explanation:

Answer:

D

Step-by-step explaination:

Answer:

The answer would be 19

Step-by-step explanation:

Using pythagoras theorem

15+6= 21

a^2+b^2= c^2

In this scenario,

c^2-a^2= b^2

Meaning it would be 21^2+8^2

= 377

Square root of 377 would be 19.416

?= 19.416

The missing side length of the right angle triangle is 20

Pythagoras theorem States that the square of the longest side of a triangle is equal to the sum of the square of the opposite side and no square of the adjacent side.

BC² = AB² + CA²

(15 + 6)² = x² + 8²

21² = x² + 8²

21² - 8² = x²

441 - 64 = x²

377 = x²

x = √377

x = 19.41648783894759891856148511263886343

Approximately to the nearest whole number

= 20

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Answer: equals Z

Step-by-step explanation:

simple you do y divided by mass energy

Step-by-step explanation:

subject arts and architecture what primary

Answer:

9 mm

Step-by-step explanation:

90*0.1=9

Answer:

Accrued expenses are those liabilities that have built up over time and are due to be paid. Accrued expenses are considered to be current liabilities because the payment is usually due within one year of the date of the transaction. Accounts payable are current liabilities that will be paid in the near future.

Answer:

Wages expense, Interest expense

Step-by-step explanation:

Answer:

x = 2.83163

Step-by-step explanation:

Have a nice day!

and if you have questions on how I found it please ask.

Answer: Here you go

Explanation:

Raduis is 2.5cm

Diameter 5cm

Circumference 15.70796cm or 16 rounded up because 2 times pie time 2.5 because 2.5 is the radius which if you calculate is 15.7 because 2 x 3.1415 x 2.5 = 15.7

Answer:

7/15

Step-by-step explanation:

2/15 + 5/15 = 7/15

Hoped this helped.

Answer:

O = 16.7 degrees

A = 73.3 degrees

Step-by-step explanation:

used a triangle calculator

Answer:

Equation 2 represents the greatest value of x!

Step-by-step explanation:

Let's solve each equation for x.

Equation 1; x = 4.1 (about)

Equation 2: x = 5 (about)

Equation 3: x = 4 (exact)

Equation 4: x = 3 (exact)

Hope this helps. :)

The fence around the edge of the garden is 17.86 m long.

The fence around the edge of the garden is the perimeter of the quarter circle. That is the length of the arc plus the two radii.

Since the radius is 5 units long, its length r = 5 m.

The length of the arc L = rθ where r = radius of quarter circle = 5 m and θ = angle subtended by the arc in radians = π/2 (90°)

So, the length of the fence L' = L + r + r

L' = L + 2r

L' = rθ + 2r

L' = r(θ + 2)

Substituting the values of the varaibles into the equation, we have

L' = r(θ + 2)

L' = 5 m(π/2 + 2)

L' = 5 m(1.571 + 2)

L' = 5 m × 3.571

L' = 17.855 m

L' ≅ 17.86 m

So, the fence around the edge of the garden is 17.86 m long.

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Answer:

maybe 13

Step-by-step explanation:

Answer:

explain it again

Step-by-step explanation:

i don't understand

Answer:

-10,-100,-8,-7,-2,-4,-5,-20,-6,-3,-7