The graph of y = 5x2 is

Answer:

Through observation, a=2, b=1 or vice versa .

Step-by-step explanation:

If a=2 and b=1

a² +b²=?

2² +1² =4+1=5

a²+b²=5

Answer:

The required answers are 80.8, 79,and g(42) > f(42).

Part A:

To determine the test average for the math class after completing test 2, we need to evaluate the function f(x) at x=2. That is,

[tex]$$f(2) = 0.9(2) + 79 = 80.8$$[/tex]

Therefore, the test average for the math class after completing test 2 is 80.8.

Part B:

To determine the test average for the science class after completing test 2, we need to find the equation of the linear function g(x) that passes through the given points (1,78) and (2,79). The slope of the line passing through these points is

[tex]$m=\frac{y_2-y_1}{x_2-x_1}=\frac{79-78}{2-1}=1$$[/tex]

We can use the point-slope form of a line to find the equation of the line passing through the point (1,78) with slope m=1. That is,

[tex]$$y-78 = 1(x-1)$$[/tex]

Simplifying, we get

y = x + 77

Therefore, the test average for the science class after completing test 2 is

g(2) = 2 + 77 = 79

Part C:

To determine which class had a higher average after completing test 42, we need to evaluate f(42) and g(42) and compare the results. We have

[tex]$$f(42) = 0.9(42) + 79 = 117.8$$[/tex]

To find (42), we need to extend the linear function g(x) beyond the given data points by assuming that the function is linear and continues with the same slope m=1. That is,

g(x) = x + 77

for all [tex]$x\geq 1$[/tex]. Therefore,

[tex]$$g(42) = 42 + 77 = 119$$[/tex]

Since g(42) > f(42), we conclude that the science class had a higher average after completing test 42.

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Answer: B)

Step-by-step explanation:

a. Coefficient of .x³in (1 + .x)⁶ is 20. b. Coefficient of .x³ in (2.x - 3)⁶ is -540. c. Coefficient of .x³ in (x + 1)²⁰ + (x - 1)²⁰ is zero. d. Coefficient of .x³ y³ in (.x + 1)⁴ is 4.

a. To find the coefficient of .x³ in the expansion of (1 + .x)⁶, we can use the binomial theorem. The coefficient of .x³ is given by the expression 6C₃(1)³(.x)³, where 6C₃ is the number of ways to choose three items from a set of six items. Evaluating this expression gives us:

6C₃(1)³(.x)³ = (6!)/(3!3!)(1³)(.x)³ = 20(.x)³

Therefore, the coefficient of .x³ in (1 + .x)⁶ is 20.

b. Similarly, we can use the binomial theorem to find the coefficient of .x³ in the expansion of (2.x - 3)⁶. The coefficient of .x³ is given by the expression 6C₃(2.x)³(-3)⁶, which simplifies to:

6C₃(2³)(.x)³(-3)⁶ = 6C₃(8)(.x)³(729)

The value of 6C₃ is 20, so we have:

20(8)(.x)³(729) = 116,640(.x)³

Therefore, the coefficient of .x³ in (2.x - 3)⁶ is -116,640.

c. In the expansion of (x + 1)²⁰ and (x - 1)²⁰, each term will be of the form (xⁿ)(1)⁽²⁰⁻ⁿ⁾ and (xⁿ)(-1)⁽²⁰⁻ⁿ⁾, respectively, where n is an even integer between 0 and 20. Since the powers of x are even, the only term that can contain .x³ is the term where n = 6, which is (x⁶)(1⁽¹⁴⁾) and (x⁶)(-1⁽¹⁴⁾) in the two expansions. Adding these two terms together gives us:

(x⁶)(1⁽¹⁴⁾ - 1⁽¹⁴⁾) = 0

Therefore, the coefficient of .x³ in (x + 1)²⁰ + (x - 1)²⁰ is zero.

d. To find the coefficient of .x³ y³ in (.x + 1)⁴, we can use the binomial theorem once again. The coefficient of .x³ y³ is given by the expression 4C₁(1³)(.x)³(y)¹, which simplifies to:

4C₁(1³)(.x)³(y)¹ = 4(.x)³(y)

Therefore, the coefficient of .x³ y³ in (.x + 1)⁴ is 4.

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Here's the completed table and the graph:

x  h(x)

-90°  1.0

-75°  -0.5

-60°  -1.0

-45° -0.0

-30° 1.0

-15° 0.5

0° 1.0

15° 0.5

30° -0.0

45° -1.0

60° -0.5

75° 1.0

90° 1.0

In mathematics, a function is a relation between a set of inputs and a set of possible outputs, with the property that each input is related to exactly one output. Functions are often represented as a set of ordered pairs, where the first element of each pair is an input and the second element is the corresponding output. Functions are a fundamental concept in many areas of mathematics and have many real-world applications, including in science, engineering, and economics.

Here,

To calculate the values of h(c) in the table, we plug in the given values of x into the function h(c) = cos 2x and evaluate. For example, to find h(c) when x = -75°:

h(c) = cos 2x

h(c) = cos 2(-75°) (substitute -75° for x)

h(c) = cos (-150°) (simplify using the double angle identity)

h(c) = -0.5 (evaluate using the unit circle or a calculator)

We repeat this process for each value of x to fill out the table.

To graph the function h(x) = cos 2x, we plot each point from the table on the given system of axes. The x-axis represents the angle x in degrees, and the y-axis represents the value of h(x) = cos 2x. We then connect the points with a smooth curve to obtain the graph.

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Answer:

The correct answer is (b+2)

Step-by-step explanation:

(3b-7) + (-2b+9)

3b-7-2b+9

3b-2b+9-7

b+2 Ans

Answer:

b+2 is the answer of this expression.

Step-by-step explanation:

(3b-7) and (-2b+9)

3b+(-2b) + (-7+9)

(3b-2b) + 2

b+2

Step 1: Calculate the total volume of the desired 5% alcohol solution.

910 mL = 0.0910 L

Step 2: Calculate the amount of 5% alcohol solution needed.

(0.0910 L) * (0.05) = 0.00455 L

Step 3: Calculate the amount of pure water needed.

(0.0910 L) - (0.00455 L) = 0.08645 L

Step 4: Calculate the amount of 65% alcohol mixture required.

(0.00455 L) / (0.65) = 0.007 L

Step 5: Calculate the amount of pure water in the 65% alcohol mixture.

(0.007 L) * (1 - 0.65) = 0.00245 L

Step 6: Calculate the total amount of pure water required.

(0.08645 L) + (0.00245 L) = 0.0889 L

To obtain the desired 910 mL of 5% alcohol solution, you will need 0.007 L of 65% alcohol mixture and 0.0889 L of pure water.

The 1,262 students who received a merit scholarship, the amount they received varied per student and totaled an average of $3,458 ($454). That amount is 78.2% of the full tuition cost of $4,400.

Merit is a term used to describe the quality of something or someone that makes them worthy of recognition or respect. It is an indicator of worthiness and is usually based on a person's ability, effort, or accomplishments. Merit is often used when evaluating an individual or a group for a promotion, hiring, or award. Merit is subjective, as different people have different standards for what merits recognition.

Therefore, 21.8% of the students who received a merit scholarship did not receive enough to cover full tuition. Therefore, the percentage of students who received a merit scholarship and did not receive enough to cover full tuition is 21%.

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Answer:

D. -1/2

Step-by-step explanation:

slope = rise/run = 1/-2 = -1/2

Answer:

Step-by-step explanation:

1st find v solving 3v + 1 = 7

3v + 1 = 7

3v = 7 - 1

3v = 6

v = 6 : 3

v = 2

v + 8 =

replace v with 2

2 + 8 = 10

Answer:

10

Step-by-step explanation:

Solve for the value of the variable, v, in the given equation of 3v + 1 = 7, by isolating the variable. Do the opposite of PEMDAS.

PEMDAS is the order of operations, and stands for:

Parenthesis

Exponents (& Roots)

Multiplications

Divisions

Additions

Subtractions

~

First, subtract 1 from both sides of the equation:

[tex]3v + 1 = 7\\3v + 1 (-1) = 7 (-1)\\3v = 7 - 1\\3v = 6[/tex]

Next, divide 3 from both sides of the equation:

[tex]3v = 6\\\frac{3v}{3} = \frac{6}{3} \\v = \frac{6}{3} \\v = 2[/tex]

Then, plug in 2 for v in the first given expression:

[tex]v + 8\\=(2) + 8\\=10[/tex]

10 is your answer for v + 8 when 3v + 1 = 7.

~

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The position of the mass at any time t is given by u(t) = -1/2 cos(2√2 t) + sin(2√2 t) + 1/2 sin(4t) - 1/2 cos(4t), and the first four times at which the velocity of the mass is zero, excluding t = 0, are t = 0.0567, 0.283, 0.510, and 0.736.

To solve this problem, we need to use Newton's second law of motion which states that the force acting on an object is equal to its mass times its acceleration. In this case, the force acting on the mass is the sum of the force due to gravity and the external force, and the acceleration is given by the second derivative of the displacement.

Using Hooke's law, the force due to the spring is proportional to the displacement u of the mass from its equilibrium position, with a proportionality constant k

F_spring = -k u

where k is the spring constant. Since the mass is pulled down 6 in. from its equilibrium position, the initial displacement is u(0) = -0.5 ft. The spring stretches 24 in. under a weight of 8 lb, so the spring constant is

k = F_spring / u = (8 lb) / (2 ft) = 4 lb/ft

The force due to gravity is

F_gravity = m g

where m is the mass of the object and g is the acceleration due to gravity. The mass is given in pounds, so we need to convert it to slugs:

m = 8 lb / (32.2 ft/s^2) = 0.248 slugs

Thus, the force due to gravity is

F_gravity = (0.248 slugs) (32 ft/s^2) = 7.94 lb

The equation of motion for the displacement u(t) is

m u''(t) = F_gravity + F_spring + F_external

where F_external = 4 sin 4t lb is the external force. Substituting the expressions for these forces and dividing by m, we get

u''(t) + 8 u(t) = 2 sin 4t

This is a homogeneous linear second-order differential equation with constant coefficients, which can be solved by finding the roots of the characteristic equation:

r^2 + 8 = 0

The roots are r = ±2i√2. The general solution of the differential equation is then

u(t) = c1 cos(2√2 t) + c2 sin(2√2 t) + u_p(t)

where u_p(t) is a particular solution of the nonhomogeneous equation. Since the right-hand side of the equation is a sinusoidal function with frequency 4/π, we can guess a particular solution of the form

u_p(t) = A sin(4t) + B cos(4t)

Substituting this into the equation and equating coefficients, we get

16 A - 16 B + 8 A = 2, or A = 1/2

-16 A - 16 B + 8 B = 0, or B = -1/2

Therefore, the particular solution is

u_p(t) = 1/2 sin(4t) - 1/2 cos(4t)

The general solution is then

u(t) = c1 cos(2√2 t) + c2 sin(2√2 t) + 1/2 sin(4t) - 1/2 cos(4t)

We can use the initial conditions u(0) = -0.5 and u'(0) = 0 to determine the values of c1 and c2

u(0) = c1 + 1/2 = -0.5, or c1 = -1/2

u'(0) = -2√2 c1 + 2√2 c2 - 2 = 0, or c2 = 1

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The given question is incomplete, the complete question is:

A mass that weighs 8 lb stretches a spring 24 in. The system is acted on by an external force of 4 sin 4t. If the mass is pulled down 6 in. and then released, determine the position of the mass at any time t. (Use g = 32 ft/s2 for the acceleration due to gravity. Let u(t), measured positive downward, denote the displacement in feet of the mass from its equilibrium position at time t seconds.)

u(t) = 1/2sin(4t)+1/2cos(4t)-2tcos(4)

Determine the first four times at which the velocity of the mass is zero. (Exclude t = 0 as trivial.)

On Wednesday, there is a higher (0.7395) likelihood that both managers will be accessible than on Monday (0.7216).

The study of random occurrences and their results falls under the category of probability, which is a subfield of mathematics. A number between 0 and 1, where 0 denotes an impossibility and 1 denotes a certainty, is used to express the likelihood of an event happening. By dividing the number of favourable outcomes by the total number of potential outcomes, the probability of an occurrence is determined. It is used in many fields, including statistics, finance, engineering, and science, to generate predictions and inform decision-making.

given

We must calculate the product of the odds of each manager being available on a given day in order to determine the day with the highest likelihood that both managers will be available.

The likelihood that both managers will be accessible on Monday is 0.82 x 0.88, or 0.7216.

The likelihood that both managers will be accessible on Wednesday is 0.87 x 0.85 = 0.7395.

Therefore, the solution is option C: Wednesday. On Wednesday, there is a higher (0.7395) likelihood that both managers will be accessible than on Monday (0.7216).

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Step-by-step explanation:

Here is ONE way

sum of exterior angles of a polygon = 360 °

  there are 5 , se each EXTERIOR angle = 360/5 = 72 °

     the EXT angles are SUPPLEMENTARY with the interior angles

          ext + int = 180°

            72 + int = 180°      INTERIOR angle = 108 °

For a limit expression to be solved using L'Hospital's rule, the expression must be in the form of 0/0 or infinity/infinity, and the derivatives of the numerator and denominator must exist and approach a finite limit or infinity/negative infinity at the point of evaluation.

L'Hospital's rule applies to limit expressions of the form 0/0 or infinity/infinity. Specifically, if we have a limit expression of form f(x)/g(x), where f(x) and g(x) both approach 0 or infinity as x approaches a certain value, then L'Hospital's rule may be applied to find the limit of the expression.

It is important to note that L'Hospital's rule can only be applied if the limit of the derivative of f(x) divided by the derivative of g(x) exists and is finite, or if the limit of the derivative of f(x) divided by the derivative of g(x) approaches infinity or negative infinity.

Therefore, for a limit expression to be solved using L'Hospital's rule, the expression must be in the form of 0/0 or infinity/infinity, and the derivatives of the numerator and denominator must exist and approach a finite limit or infinity/negative infinity at the point of evaluation.

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By using rational zeros theorem, we find that there are no real zeros of the polynomial function f(x) = x^3 - x^2 - 37x - 35, so we cannot factor f(x) over the real numbers.

To find the real zeros of the polynomial function f(x) = x^3 - x^2 - 37x - 35, we can use the rational zeros theorem, which states that any rational zeros of the function must have the form p/q, where p is a factor of the constant term (-35) and q is a factor of the leading coefficient (1).

The possible rational zeros of f are therefore ±1, ±5, ±7, ±35. We can then test each of these values using synthetic division or long division to see if they are zeros of the function. After testing all of the possible rational zeros, we find that none of them are actually zeros of the function.

Therefore, we can conclude that there are no real zeros of the function f(x) = x^3 - x^2 - 37x - 35.

However, we could factor it into linear and quadratic factors with complex coefficients using the complex zeros of f(x). But since the problem only asks for factoring over the real numbers, we can conclude that the factored form of f(x) is:

f(x) = x^3 - x^2 - 37x - 35 (cannot be factored over the real numbers)

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The value of the probability of selecting a blue marble from the bag is 1/3

The probability of selecting a blue marble can be found by dividing the number of blue marbles by the total number of marbles in the bag.

From the given information, we know that there are 4 blue marbles out of a total of 12 marbles in the bag.

Therefore, the probability of selecting a blue marble is:

Probability of selecting a blue marble = Number of blue marbles / Total number of marbles

This gives

Probability of selecting a blue marble = 4/12

Simplifying the fraction by dividing both the numerator and denominator by 4, we get:

Probability of selecting a blue marble = 1/3

So, the probability of selecting a blue marble from the bag is 1/3 or 0.33 as a decimal.

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Answer:

No

She needs 3/80 cup more

Step-by-step explanation:

She needs 3/8 cup plus 3/5 cup.

3/8 + 3/5 = 15/40 + 24/40 = 39/40

She has 15/16 cup

15/16

39/40 = 78/80

15/16 = 75/80

She has 75/80 cup and needs 78/80 cup.

She does not have enough sugar.

78/80 - 75/80 = 3/80

She needs 3/80 cup more.

The required number of boxes that the truck contain is 70 small boxes and 55 large boxes.

In mathematics, the operation and interpretation of a function to make it simple or easier to grasp is known as simplifying, and the process is known as simplification.

Given that, Number of large boxes weigh 45 pounds each, and the small boxes weigh 35 pounds each. There are 125 boxes in all, the truck is carrying a total of 4925 pounds

Let the number of large boxes will be l and the number of small boxed be s,

According to the question,

l + s = 125

l = 125 - s - - - - - (1)

Again,

45l + 35s = 4925

put 1 in the above equation,

45[125 - s] + 35s = 4925

5625 - 45s + 35s = 4925

10s = 700

s = 70

Now,

l = 125 - 70

l = 55

Thus, the required number of boxes that the truck contain is 70 small boxes and 55 large boxes.

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The sample mean X is an unbiased estimator for θ.

To find a suitable statistic as an unbiased estimator for θ, we need to find a function of sample Y, YS, ..., Yn whose expected value is equal to θ.

X = (Y + YS + ... + Yn) / n

To show that X is unbiased, we need to calculate its expected value and show that is equal to θ:

E[X] = E[(Y + YS + ... + Yn) / n]

= (1/n) E[Y + YS + ... + Yn]

= (1/n) [E[Y] + E[YS] + ... + E[Yn]]

= (1/n) [nθ] (by the given density function)

= θ

Therefore, sample mean X is an unbiased estimator for θ.

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Without the table indicating the stated premium rates and applicable discounts, the monthly property insurance cannot be computed. Hence, on the assumption that the rate is 2.5% and the discount applicable is 7.5% the premium per month will come to $152.24

The simple definition of Property Insurance is, it is an insurance policy that covers a policyholder for the structure of a building and its contents against stated or agreed perils.

Given (based on assumption) that the applicable annual rate is 2.5%

and that:

Hence annual premium will be:

= (67,000 + 12000) * (2.5/100) * 0.925

Annual Premium Payable = $1,826.89.............A

Recall that we are asked to derive the monthly Insurance premium.

This is thus given as: Answer in A/12

→  1,826.89/12

= $152.24

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This can be simplified to 19/100, which is equivalent to 6/31 or approximately 0.19 or 19%. The answer is: 6 over 31.

what is probability?

Probability is a measure of the likelihood of an event occurring. It is a number between 0 and 1, where 0 indicates that an event is impossible, and 1 indicates that an event is certain. Probability can be expressed as a fraction, decimal, or percentage.

The question asks for the experimental probability of drawing a 3, 5, or 7 from a deck of cards, given the frequency table provided.

The frequency table tells us how many times each card was drawn out of a total of 100 draws.

To calculate the frequency of drawing a 3, 5, or 7, we add the frequencies of these cards: 4 (for 3) + 6 (for 5) + 6 (for 7) = 16. Note that we do not include the frequencies of any other cards.

To calculate the probability of drawing a 3, 5, or 7, we divide the frequency of these cards (16) by the total number of draws (100): 16/100 = 0.16. This means that in our experiment, we drew a 3, 5, or 7 approximately 16% of the time.

The total number of draws is 100, and the frequency of cards 3, 5, and 7 is 7+6+6=19.

Therefore, the experimental probability of drawing a 3, 5, or 7 is:

19/100 = 0.19

This can be simplified to 19/100, which is equivalent to 6/31 or approximately 0.19 or 19%.

Therefore, the answer is: 6 over 31.

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There are 20 students who wrestle and 20 students who play basketball, for a total of 40 students altogether.

What is read-draw-write process?

The Read-Draw-Write process is a problem-solving strategy that can be used to help students organize their thoughts and work systematically through a problem. It involves three steps:

Read the problem: Students should carefully read and understand the problem they are trying to solve.

Draw a diagram or picture: Students should create a visual representation of the problem to help them better understand it and identify any relationships between the different parts of the problem.

Write an equation or statement: Students should use the information from the problem to write an equation or statement that represents the relationships between the different parts of the problem.

To solve the problem using the Read-Draw-Write process:

Read:

There are as many students who wrestle as students who play basketball

There are 20 students who play basketball

Draw:

Let "wrestle" represent the number of students who wrestle

Let "B Ball" represent the number of students who play basketball

Write:

We know that "wrestle" = "B Ball"

We also know that "B Ball" = 20

So we can substitute "B Ball" with 20 in the first equation:

wrestle = B Ball

wrestle = 20

Therefore, there are 20 students who wrestle and 20 students who play basketball, for a total of 40 students altogether.

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-3y+7x ≥ -3y-14

solving linear inequalities

To solve the inequality, we need to isolate the variable, x. First, we can simplify the expression by adding 3y to both sides:

-3y + 7x ≥ -3y - 14 + 3y

Simplifying the right side, we get:

-3y + 7x ≥ -14

Next, we can isolate x by subtracting 3y from both sides:

-3y + 7x - 3y ≥ -14 - 3y

Simplifying the left side, we get:

4x ≥ -14 - 3y

Finally, we can isolate x by dividing both sides by 4:

x ≥ (-14 - 3y) / 4

Therefore, the solution to the inequality is:

x ≥ (-14 - 3y) / 4

Note that the inequality sign remains the same because we did not multiply or divide by a negative number.

ChatGPT

Answer:

1/16

Step-by-step explanation:

1/8 is left

1/2 of 1/8 = 1/16

Answer :

Step-by-step explanation to problem:

2/3 * 3 = 2

we do 2/3 times 3 because $3 is for 1 pound and here we only need 2/3 of a pound

$2

Correct Answer = D

Rounding to the nearest billion, the new estimated value of the trust funds in 2038 would be $2 billion.

A trust fund is a financial arrangement where one party (the trustor or settlor) gives assets to another party (the trustee) to manage on behalf of a third party (the beneficiary). The trustee holds and invests the assets of the trust in accordance with the terms and instructions set out in the trust agreement. Trust funds can be established for a variety of purposes, including estate planning, charitable giving, or providing for the financial needs of a beneficiary who may be too young or incapacitated to manage their own finances.

Assuming an original starting value of $4 trillion in 2033 and a rate of decline that is 10% greater than the originally estimated 7.6% rate, the new rate of decline would be 7.6% + (10% * 7.6%) = 8.36%.

To calculate the new estimated value of the trust funds in 2038, we can use the formula:

Value in 2038 = Starting Value * (1 - Rate of Decline)ⁿ

Plugging in the values, we get:

Value in 2038 = $4 trillion * (1 - 0.0836)⁵

Value in 2038 = $4 trillion * 0.6002

Value in 2038 = $2.401 trillion

Rounding to the nearest billion, the new estimated value of the trust funds in 2038 would be $2 billion.

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