The function h(x)= 12x^8+ 49 is an even function. Which transformation of h(x) would result una function that is neither even or odd?

The Function H(x)= 12x^8+ 49 Is An Even Function. Which Transformation Of H(x) Would Result Una Function

Answers

Answer 1

Answer:

- reflecting over x -axis

Step-by-step explanation:

Given equation

[tex]$ h(x) = 12x^8 +49 $[/tex]

Now, [tex]$ h(-x) = 12(-x)^8 +49 $[/tex]

                   = [tex]$ - 12x^8 +49 $[/tex]

Therefore, h(x) ≠ h(-x) ≠ -h(-x)

So, the function is neither odd nor even.

Therefore, reflecting the equation over x - axis would result a function that in neither even nor odd.

Answer 2

Answer:

Reflecting over x axis


Related Questions

PLEASE HURRY add n to the product of 7 and 5

Answers

Answer:

[See Below]

Step-by-step explanation:

Multiply 7 by 5.

*35

Now add n to it.

*35 + n

What's the answer to this question I need help I don't understand it

Answers

Greetings from Brasil...

Making the division

(X⁵ + 2X⁴ - 7X² - 19X + 15) ÷ (X² + 2X + 5)

we get

X³ - 5X + 3

Answer:

x³ − 5x + 3

Step-by-step explanation:

To solve with long division:

Start by dividing the highest terms:

x⁵ / x² = x³

This becomes the first term of the quotient.  Multiply by the divisor:

x³ (x² + 2x + 5) = x⁵ + 2x⁴ + 5x³

Subtract from the first three terms of dividend:

(x⁵ + 2x⁴ + 0x³) − (x⁵ + 2x⁴ + 5x³) = -5x³

Drop down the next two terms and repeat the process.

To use the "box" method:

Each square in the box is the product of the term at the top of the column and the term at the end of the row.  Also, squares diagonal of each other must add up to the term outside the box.

Look at the first diagonal.  There is only one square, so that must be x⁵.  Knowing this, we can say that x³ must be at the top of the column.  We can fill in the rest of the column (2x⁴ and 5x³).

Repeat this process until all squares are filled in.

Use​ Newton's method to find an approximate solution of ln(x)=10-x. Start with x_0 =9 and find x_2 .

Answers

Answer:

x₂ = 7.9156

Step-by-step explanation:

Given the function  ln(x)=10-x with initial value x₀ = 9, we are to find the second approximation value x₂ using the Newton's method. According to Newtons method xₙ₊₁ = xₙ -  f(xₙ)/f'(xₙ)

If f(x) = ln(x)+x-10

f'(x) = 1/x + 1

f(9) = ln9+9-10

f(9) = ln9- 1

f(9) = 2.1972 - 1

f(9) = 1.1972

f'(9) = 1/9 + 1

f'(9) = 10/9

f'(9) = 1.1111

x₁ = x₀ -  f(x₀)/f'(x₀)

x₁ = 9 -  1.1972/1.1111

x₁  = 9 - 1.0775

x₁  = 7.9225

x₂ = x₁ -  f(x₁)/f'(x₁)

x₂ = 7.9225 -  f(7.9225)/f'(7.9225)

f(7.9225) = ln7.9225 + 7.9225 -10

f(7.9225) = 2.0697 + 7.9225 -10

f(7.9225) = 0.0078

f'(7.9225) = 1/7.9225 + 1

f'(7.9225) = 0.1262+1

f'(7.9225) = 1.1262

x₂ = 7.9225 - 0.0078/1.1262

x₂ = 7.9225 - 0.006926

x₂ = 7.9156

Hence the approximate value of x₂ is 7.9156

A newsletter publisher believes that above 41A% of their readers own a personal computer. Is there sufficient evidence at the 0.100.10 level to substantiate the publisher's claim?

Answers

Complete Question

A newsletter publisher believes that above 41% of their readers own a personal computer. Is there sufficient evidence at the 0.10 level to substantiate the publisher's claim?

State the null and alternative hypotheses for the above scenario.

Answer:

The null hypothesis is  [tex]H_o : p \le 0.41[/tex]

The  alternative hypothesis  [tex]H_1 : p> 0.41[/tex]

Step-by-step explanation:

From the question we are told that

      The population proportion is [tex]p = 0.41[/tex]

        The level of significance is  [tex]\alpha = 0.10[/tex]

The null hypothesis is  [tex]H_o : p \le 0.41[/tex]

The  alternative hypothesis  [tex]H_1 : p> 0.41[/tex]

         

Find the value of x.

Answers

Step-by-step explanation:

3x-12 + 6 = 14

3x-12 = 14 - 6

3x = 8 + 12

x= 20 ÷ 3

x = 6.7

Internal Angle Bisector Theoram:

Interior Angle Bisector Theorem : The angle bisector of an angle of a triangle divides the opposite side internally in the ratio of the sides containing the angle.

[tex] \Large{ \boxed{ \bf{ \color{limegreen}{Solution:}}}}[/tex]

Here, We can see that angle bisector of an angle is dividing the opposite side.

And,

From here, we can say that the ratio of side being divided is same as the ratio of sides containing this angle.

So, we can write it as,

➝ 14 : 21 = 6 : 3x - 12

Prdouct of means = Product of extremes

➝ 21 × 6 = 14(3x -12)

➝ 126 = 14(3x - 12)

➝ 9 = 3x - 12

Flipping it,

➝ 3x - 12 = 9

➝ 3x = 21

➝ x = 7

☘️ So, Value of x is [tex]\boxed{\sf{x = 7}}[/tex]

━━━━━━━━━━━━━━━━━━━━

If (x+12y)/x=19 find (144x^2 +24xy + y^2) /y^2

Answers

Answer:

81

Step-by-step explanation:

Given:

(x+12y)/x=19

Simplifying:

x+ 12y = 19x  12y=18x x/y = 2/3

Finding the value of:

(144x^2 +24xy + y^2) /y^2 = 144 (x/y)^2 + 24 (x/y) + 1 =

Substituting x/y with 2/3:

144 (2/3)^2 + 24 (2/3) + 1 = 144 (4/9) + 16 + 1 = 64 + 16 + 1 = 81

Answer is 81

Choose two statements that are true for this expression.
4x^3 – 7x^2 – 30/y + 15
A. There are four terms.
B. There are three terms. 30
C. The term is a ratio.
D. The entire expression is a difference.​

Answers

Answer:

A. There are four terms.

C. The term [tex]\frac{30}{y}[/tex] is a ratio.

Step-by-step explanation:

The expression given is the sum of four components: a third order monomial ([tex]4\cdot x^{3}[/tex]), a second order monomial ([tex]-7\cdot x^{2}[/tex]), a zero order monomial ([tex]15[/tex]) and a ratio ([tex]\frac{30}{y}[/tex]). There are a sum and two differences. Hence, the correct answers are:

A. There are four terms.

C. The term [tex]\frac{30}{y}[/tex] is a ratio.

Answer:

there are 4 terms

the term 30/y is a ratio

Step-by-step explanation:

got it right on my quiz

Which of the following is not a 3-D shape? A. quadrilateral B. cube C. sphere D. prism

Answers

Answer:

A.

Step-by-step explanation:

A quadrilateral is simply a shape with 4 sides, therefore it does not HAVE to be 3-D.

Answer:

Quadrilateral.

Step-by-step explanation:

A quadrilateral is a 2d shape not 3d.

HURRY! QUICK! SHOW WORK THANKS Write the simplified polynomials that represent the perimeter and area for the rectangle.

Length: (x-5) ft

Width: (3x-10) ft

Perimeter =

Area =

Answers

P = 2(x - 5) + 2(3x - 10)
P = 2x - 10 + 6x - 20
P = 8x - 30

A = (x - 5)(3x - 10)
A = 3x^2 - 10x - 15x + 50
A = 3x^2 - 25x + 50

Answer:

Perimeter = (8x-30)

Area=(X-5)(3x-10)

Step-by-step explanation:

Perimeter equation for solving is this

2(X-5+3x-10)=p

it is length plus width twice which will equal the perimeter

solving this out

2(4x-15)=p

8x-30=p

area equation for solving this is

(x-5)(3x-10)=a

I don’t know how to solve this one out but i hope the setup helps!

The sum of two numbers, x and y, is 12. The difference of four times the larger number and two
times the smaller number is 18. Whích system of equations should you use to find the two
numbers?
O
A X-y=12
4x - 2y = 18
O B x + y = 12
X-y= 18
C x+y=12
2x - 4y = 18
D x + y = 12
4% - 2y = 18

Answers

Answer:

D

Step-by-step explanation:

"Sum" indicates that we add the two variables so we can eliminate option A because that has x - y = 12 not x + y = 12. We can eliminate option B because the second equation should be 4x - 2y = 18, not x - y = 18. For that same reason, we can eliminate C because the coefficients are swapped. I will assume that in option D, the second equation is 4x - 2y = 18. Since we have eliminated everything else, the answer is D.

Identify the type of conic section given by the polar equation below. Also give the equation of its directrix (in rectangular coordinates is fine.)
r = 8/4+ cos θ.

Answers

Answer:

x = ±8

Step-by-step explanation:

A conic section with a focus at the origin, a directrix of x = ±p where p is a positive real number and positive eccentricity (e) has a polar equation:

[tex]r=\frac{ep}{1 \pm e*cos\theta}\\ \\[/tex]

From the question, the polar equation of the circle is:

[tex]r=\frac{8}{4+cos\theta}[/tex]

We have to make the equation to be in the form of [tex]r=\frac{ep}{1 \pm e*cos\theta}\\ \\[/tex]. Therefore:

[tex]r=\frac{8}{4+cos\theta}\\\\Multiply \ through\ numerator\ and\ denminator\ by\ \frac{1}{4}\\\\ r=\frac{8*\frac{1}{4} }{(4+cos\theta)*\frac{1}{4} }\\\\r=\frac{2}{4*\frac{1}{4} +cos\theta*\frac{1}{4}}\\ \\r=\frac{\frac{1}{4}*8}{1+\frac{1}{4}cos\theta}[/tex]

This means that the eccentricity (e) = 1/4 and the equation of the directrix is x = ±8

A die is thrown. Describe the following events: (i) A: a number less than 7 (ii) B: a number greater than 7 (iii) C: a multiple of 3 (iv) D: a number less than 4. (v) E: an even number greater than 4 (vi) F: a number not less than 3 (vii) find A× (B∩ E), A ∩B, B ∪ C, E ∩ F∩ D. Answer this if u want to be marked as the brainliest!

Answers

A: The probability of a number rolling less than 7 is 100% or 1 because a dice only has numbers 1,2,3,4,5, and 6. 1,2,3,4,5, and 6 are all less than 7 so you are guaranteed to roll a number less than 7.

B: The probability of a number rolling more than 7 is 0% or 0 because a dice only has numbers 1,2,3,4,5, and 6. 1,2,3,4,5, and 6 are all less than 7 so it's not possible to roll a number more than 7.

C: The probability of a number rolling to be a multiple of three is 33.33(repeating)% or 1/3. Out of 1,2,3,4,5, and 6, the multiples of 3 are, 3 and 6. 3 and 6 is two numbers out of six numbers. 2 out of 6 simplifies to 1 out of 3.

D: The probability of a number rolling to be less than 4 is 50% of 1/2. Out of the numbers, 1,2,3,4,5, and 6, only 1,2, and 3 are less than 4. 1,2, and 3 is three numbers out of six numbers. 3 out of 6 simplifies to 1 out of 2.

E: The probability of a number rolling to be an even number greater than 4 is 0.166(repeating) or 1/6. Out of the numbers, 1,2,3,4,5, and 6, 2,4, and 6 are even numbers. Out of 2,4, and 6, only 6 is greater than 4. 4 is one number out of 1,2,3,4,5, and 6 (six numbers).

F: The probability of a number rolling to be a number not less than 3 is 50% or 1/2. "Not less than" actually means greater than. In the numbers, 1,2,3,4,5, and 6, only 4,5, and 6 are greater than 3. 4,5, and 6 are three numbers. 3 out of 6 simplifies to 1 out of 2.

I don't really know the answer to the last question but anyways I hope this helped! ♡

❀ Have a good day! ❀

Find the mode. Select the correct choice below​ and, if​ necessary, fill in the answer box to complete your choice. A. The​ mode(s) is(are) nothing. ​(Type an integer or a decimal. Do not round. Use a comma to separate answers as​ needed.) B. There is no mode.

Answers

Answer:

The question is not complete, but I found a possible match:

Find the (a) mean, (b) median, (c) mode, and (d) midrange for the data and then (e) answer the given question. Listed below are the jersey numbers of 11 players randomly selected from the roster of a championship sports team. What do the results tell us?

86 4 85 83 9 51 24 34 28 43

Find the mode. Select the correct choice below​ and, if​ necessary, fill in the answer box to complete your choice.

A. The​ mode(s) is(are) nothing. ​(Type an integer or a decimal. Do not round. Use a comma to separate answers as​ needed.)

B. There is no mode.

Answer:

The correct answer is:

There is no mode (B.)

Step-by-step explanation:

b. The mode of data is the number that repeats the most number of times. The number that occurs most frequently. on the list of the distribution, 86 4 8 5 83 9 51 24 34 28 43, every number occurs just once, hence, there is no mode for the distribution.

a. To calculate the Mean

[tex]Mean: \frac{Sum\ of\ terms}{number\ of\ players}\\ Mean = \frac{86\ +\ 4\ +\ 8\ +\ 5\ +\ 83\ +\ 9\ +\ 51\ +\ 24\ +\ 34\ +\ 28\ +\ 43}{11}\\Mean= 34.09[/tex]

c. To calculate the median:

Median is  the mid-way term of the distribution, but first, we have to arrange the terms in ascending order (descending order can also be used)

4, 5, 8, 9, 24, 28, 34, 43, 51, 63, 86

To find the median, count the numbers equally from the left- and right-hand sides to the middle, the remaining number becomes the median. In this case, the median = 28

d. Midrange:

The midrange is the number mid-way between the greatest and smallest number in a data set. To find the midrange, we will add the smallest (4) and largest number (86), and divide by 2:

Midrange = (4 + 86) ÷ 2

Midrange = 90 ÷ 2 = 45

e. what do the results tell us:

Since only 11 of the jersey numbers were in the sample, the statistics cannot give any meaningful results

a jogger runs at an average speed of six miles per hour. At that rate, how far will the jogger travel in one and one half hours?​

Answers

Answer:

9 miles

Step-by-step explanation:

Hour = 6 miles

Half an hour = 3

6 + 3 = 9

In a recent year, 32.3% of all registered doctors were female. If there were 46,300 female registered doctors that year, what was the total number of
registered doctors?
Round your answer to the nearest whole number.

Answers

Answer:

  143,344

Step-by-step explanation:

Let d represent the total number of registered doctors. The given relation is ...

  0.323d = 46,300

Dividing by the coefficient of d, we get ...

  d = 46,300/0.323 ≈ 143,343.7

The total number of registered doctors was about 143,344.

Sketch the region enclosed by the given curves. Decide whether to integrate with respect to x or y. Draw a typical approximating rectangle.

2x + y2 = 48, x = y

Find the area of the region.

Answers

Answer: A = 58

Step-by-step explanation: The sketched region enclosed by the curves and the approximating rectangle are shown in the attachment.

From the sketches, the area will be integrated with respect to y.

To calculate the integral, first determine the limits, which will be the points where both curves meet.

In respect to y:

[tex]2x+y^{2} = 48[/tex]

[tex]2x= 48- y^{2}[/tex]

[tex]x= 24 - \frac{y^{2}}{2}[/tex]

Finding limits:

[tex]y= 24 - \frac{y^{2}}{2}[/tex]

[tex]24 - \frac{y^{2}}{2}-y=0[/tex]

Multiply by 2 to facilitate calculations:

[tex]48 - y^{2}-2y=0[/tex]

Resolving quadratic equation:

[tex]y=\frac{-2+\sqrt{2^{2}+192} }{2}[/tex]

y = 6 and y = -8

Then, integral to calculate area will be with limits -8<y<6:

[tex]A = \int {24-\frac{y^{2}}{2}-y } \, dy[/tex]

[tex]A = 24y - \frac{y^{3}}{6}-\frac{y^{2}}{2}[/tex]

[tex]A = 24.6 - \frac{6^{3}}{6}-\frac{6^{2}}{2}-[24.(-8) - \frac{(-8)^{3}}{6}-\frac{(-8)^{2}}{2}][/tex]

A = 58

The area of the enclosed region is 58 square units.

4.72x10^10 Please I need help fast

Answers

Answer:

The answer is 47200000000

Can someone please explain this to me? I’m really confused on how to find the limit with the piecewise function.

Answers

Answer:   2

Step-by-step explanation:

You only need to evaluate at the limit point.

f(x) = 4 - x  ; x ≠ 2

Consider the solution if x = 2 (because the limit is x → 2)

                                          f(2) = 4 - (2)

                                                =   2

We know that f(x) = 0  ; x = 2

                                         f(2) = 0

but we are looking for the y- value it approaches - not the y-value it is.

Look at the graph.  You will see that as x gets closer and closer to 2, the y-value gets closer and closer to 2.  This is the limit.

Eddie treated his sister to lunch while visiting her in Manchester, Their lunch cost $20, and the
sales tax in Manchester is 15%, If Eddie left a 15% tip on the $20, how much in total did he pay?
Sul

Answers

Answer:

Eddie spent $26 total

Step-by-step explanation:

15% of 20 is 3

He paid 15% tax which is $3

He also tipped 15% of the $20 which he paid for lunch so another $3

3+3+20= $26

Use technology and a​ t-test to test the claim about the population mean at the given level of significance using the given sample statistics. Assume the population is normally distributed. ​Claim: ​;     Sample​ statistics: ​, s​, n What are the null and alternative​ hypotheses? Choose the correct answer below. A. H0​: HA​: B. H0​: HA​: C. H0​: HA​: D. H0​: HA​:

Answers

Complete question is;

Use technology and a t-test to test the claim about the population mean μ at the given level of significance α using the given sample statistics. Assume the population is normally distributed.

Claim: μ > 71; α = 0.05

Sample statistics:

¯x = 73.9, s = 3.7, n = 25

A) What are the null and alternative hypotheses?

Choose the correct answer below.

A. H0:μ = 71 ; HA:μ ≠ 71

B. H0:μ ≤ 71; HA:μ > 71

C. H0: μ ≥ 71; HA: μ < 71

D. H0: μ ≠ 71; HA: μ = 71

B) What is the value of the standardized test statistic? The standardized test statistic is (Round to two decimal places as needed.)

C) What is the P-value of the test statistic? P-value = Round to three decimal places as needed.)

D) Decide whether to reject or fail to reject the null hypothesis.

Answer:

A) Option B - Alternative hypothesis: HA: μ > 71

Null hypothesis: H0: μ ≤ 71

B) t = -7.54

C) p-value = 0.000

D) we reject the null hypothesis

Step-by-step explanation:

A) We are told that the claim is: μ > 71. Thus, due to the sign, the alternative hypothesis would be the claim. So;

Alternative hypothesis: HA: μ > 71

Null hypothesis: H0: μ ≤ 71

B)Formula for standardized test statistic with a t-test is;

t = (¯x - μ)/√(s/n)

Plugging in the relevant values, we have;

t = (71 - 73.9)/√(3.7/25)

t = -7.54

C) From online p-value from t-score calculator attached using t = -7.54, n = 25, significance level = 0.05, DF = 25 - 1 = 24 and a one - tailed test, we have;

p-value = 0.00001 ≈ 0.000

D) The p-value of 0.000 is less than the significance value of 0.05,thus we will reject the null hypothesis

What is the range of the function f(x) = -|3x + 3|?

Answers

Answer:

The range of the function [tex]f(x) = -|3\cdot x+3|[/tex] is every positive real numbers plus zero.

Step-by-step explanation:

According to definition of the absolute value, the range of absolute value covers positive real numbers or zero. A linear function is a continuous function, which means the existence of an image for every element from domain. The negative sign transforms the original range to all negative real numbers plus zero.

Hence, the range of the function [tex]f(x) = -|3\cdot x+3|[/tex] is every positive real numbers plus zero.

Solve the equation V2 + 4 + 12 = 3-
a.
330
-733
d. 753
b. -776
Please select the best answer from the choices provided

Answers

Answer:

d

Step-by-step explanation:

trust

Answer:

x = -733

Step-by-step explanation:

[tex]\sqrt[3]{x+4}[/tex] + 12 = 3

[tex]\sqrt[3]{x+4}[/tex]  = -9 (cube both sides)

x + 4 = -729

x = -733

The long-distance calls made by the employees of a company are normally distributed with a mean of 6.3 minutes and a standard deviation of 2.2 minutes. Find the probability that a call a. lasts between 5 and 10 minutes. b. lasts more than 7 minutes. c. lasts less than 4 minutes.

Answers

Answer: a. 0.6759    b. 0.3752    c. 0.1480

Step-by-step explanation:

Given : The long-distance calls made by the employees of a company are normally distributed with a mean of 6.3 minutes and a standard deviation of 2.2 minutes

i.e. [tex]\mu = 6.3[/tex] minutes

[tex]\sigma=2.2[/tex] minutes

Let x be the long-distance call length.

a. The probability that a call lasts between 5 and 10 minutes will be :-

[tex]P(5<X<10)=P(\dfrac{5-6.3}{2.2}<\dfrac{X-\mu}{\sigma}>\dfrac{10-6.3}{2.2})\\\\=P(-0.59<Z<1.68)\ \ \ \ [z=\dfrac{X-\mu}{\sigma}]\\\\=P(z<1.68)-(1-P(z<0.59))\\\\=0.9535-(1-0.7224)\ \ \ \ [\text{by z-table}]\\\\=0.6759[/tex]

b. The probability that a call lasts more than 7 minutes. :

[tex]P(X>7)=P(\dfrac{X-\mu}{\sigma}>\dfrac{7-6.3}{2.2})\\\\=P(Z>0.318)\ \ \ \ [z=\dfrac{X-\mu}{\sigma}]\\\\=1-P(Z<0.318)\\\\=1-0.6248\ \ \ \ [\text{by z-table}]\\\\=0.3752[/tex]

c. The probability that a call lasts more than 4 minutes. :

[tex]P(X<4)=P(\dfrac{X-\mu}{\sigma}<\dfrac{4-6.3}{2.2})\\\\=P(Z<-1.045)\ \ \ \ [z=\dfrac{X-\mu}{\sigma}]\\\\=1-P(Z<1.045)\\\\=1-0.8520 \ \ \ [\text{by z-table}]\\\\=0.1480[/tex]

Write the decimal as a fraction or a mixed number. Write your answer in simplest form. 0.2

Answers

Answer:

[tex] \frac{1}{5} [/tex]

Step-by-step explanation:

[tex]0.2 \times \frac{10}{10} = \frac{2}{10} = \frac{1}{5} [/tex]

This number can't be written as a mixed number since it is proper fraction.

It's numerator is less than it's denominator.

Hope this helps ;) ❤❤❤

When air expands adiabatically (without gaining or losing heat), its pressure P and volume V are related by the equation
PV^1.4=C
where C is a constant. Suppose that at a certain instant the volume is 610 cubic centimeters and the pressure is 89 kPa and is decreasing at a rate of 10 kPa/minute. At what rate in cubic centimeters per minute is the volume increasing at this instant?

Answers

Answer:

48.96 cm³/min

Step-by-step explanation:

We are given;

Relationship between pressure P and volume V; PV^(1.4) = C

Volume;V = 610 m³

Pressure; P = 89 KPa

Rate of decreasing pressure; dP/dt = -10 kPa/minute.

We want to find the rate at which the volume is increasing at that instance, thus, its means we need to find dV/dt

So, we will differentiate the relationship equation of P and V given.

Thus, we have;

[V^(1.4)(dP/dt)] + d(V^(1.4))/dt = dC/dt

Differentiating this gives us;

[(dP/dt) × (V^(1.4))] + [1.4 × P × V^(0.4) × (dV/dt)] = 0

Plugging in the relevant values, we have;

(-10 × 610^(1.4)) + (1.4 × 89 × 610^(0.4) × (dV/dt)) = 0

This gives;

-79334.44155 + 1620.5035(dV/dt) = 0

Rearranging, we have;

1620.5035(dV/dt) = 79334.44155

Divide both sides by 1620.5035 to give;

dV/dt = 79334.44155/1620.5035

dV/dt = 48.96 cm³/min

what is the angle of the triangle below?

Answers

It is 45 degrees with us the last one

16y — 13= —157 solve for y

Answers

the answer is y= -24
y= 9

-16y-13=-157
You first want to get the y by itself on one side
So you do:
-16y= -157+13
(since you moved -13 to the other side it becomes positive) then you do
-16y= -144 (when you do -157+13 you get -144)
Then divide -144 by -16
y= -144/-16
So finally, you get:
y= 9


all the factors of 6

Answers

Answer:

1, 2, 3 and 6.

Step-by-step explanation:

Factors of 6 are 1, 2, 3 and 6.

Find the absolute minimum and absolute maximum values of f on the given interval. f(t) = t 25 − t2 , [−1, 5]

Answers

Answer: Absolute minimum: f(-1) = -2[tex]\sqrt{6}[/tex]

              Absolute maximum: f([tex]\sqrt{12.5}[/tex]) = 12.5

Step-by-step explanation: To determine minimum and maximum values in a function, take the first derivative of it and then calculate the points this new function equals 0:

f(t) = [tex]t\sqrt{25-t^{2}}[/tex]

f'(t) = [tex]1.\sqrt{25-t^{2}}+\frac{t}{2}.(25-t^{2})^{-1/2}(-2t)[/tex]

f'(t) = [tex]\sqrt{25-t^{2}} -\frac{t^{2}}{\sqrt{25-t^{2}} }[/tex]

f'(t) = [tex]\frac{25-2t^{2}}{\sqrt{25-t^{2}} }[/tex] = 0

For this function to be zero, only denominator must be zero:

[tex]25-2t^{2} = 0[/tex]

t = ±[tex]\sqrt{2.5}[/tex]

[tex]\sqrt{25-t^{2}}[/tex] ≠ 0

t = ± 5

Now, evaluate critical points in the given interval.

t = [tex]-\sqrt{2.5}[/tex] and t = - 5 don't exist in the given interval, so their f(x) don't count.

f(t) = [tex]t\sqrt{25-t^{2}}[/tex]

f(-1) = [tex]-1\sqrt{25-(-1)^{2}}[/tex]

f(-1) = [tex]-\sqrt{24}[/tex]

f(-1) = [tex]-2\sqrt{6}[/tex]

f([tex]\sqrt{12.5}[/tex]) = [tex]\sqrt{12.5} \sqrt{25-(\sqrt{12.5} )^{2}}[/tex]

f([tex]\sqrt{12.5}[/tex]) = 12.5

f(5) = [tex]5\sqrt{25-5^{2}}[/tex]

f(5) = 0

Therefore, absolute maximum is f([tex]\sqrt{12.5}[/tex]) = 12.5 and absolute minimum is

f(-1) = [tex]-2\sqrt{6}[/tex].

What is the slope of the line in the graph?

Answers

Answer:

i believe it is 1

Step-by-step explanation:

Answer:

the slope is 1

Step-by-step explanation:

rise/run

1/1 = 1

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