The face-centered cubic unit cell describing the structure of an ionic compound has an edge length of 207 pm. The lattice points of the unit cell are occupied by anions, and the cations are small enough so that the anions are in contact along the diagonal of the face of the unit cell. What is the ionic radius of the anion (in picometers)

Answers

Answer 1

Answer:

73.2 pm

Explanation:

"The anions make contact along the diagonal of the face of the unit cell, so the diagonal of the face is equal to 4 ionic anion radii. By letting r represent the ionic radius of the anion, d represent the diagonal of the face of the unit cell, and x represent the edge length, then d=4r and

d^2=x^2+x^2=  2x^2

By substituting 4r for d, the second equation becomes

(4r)^2=(2)x^2

Solving this equation for r shows that

r=(x–√2)/4

Since the edge length x is 207 pm, the ionic radius of the anion is

r= ((207 pm) X [tex]\sqrt{2}[/tex])/4=73.2 pm

Notice that the formulae used to describe atomic radii include constants with exact values. Therefore, these values do not constrain the number of significant figures."

Answer 2

The ionic radius of the anion in the FCC unit cell where anions are in contact along the diagonal of the face of the unit cell is 73.1pm.

What is ionic radius?

Ionic radius is the distance between the center of the atom and the outermost part.

As in the question it is given that anions are in contact along the diagonal of the face of the unit cell, so the length of the diagonal is represented as: d = 4r, where

r = ionic radius

Length of edge i.e. a = 207 pm (given)

Two adjacent edges and diagonal of a FCC unit cell makes a right angle triangle, by using pythagoras theorem we can write as:

a² + a² = d²

2a² = (4r)²

2a²/16 = r²

2(207)²/16 = r²

85,698/16 =  r²

0r r = 73.18 pm

Hence, 73.18 pm is the ionic radius of the anion.

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Related Questions

Plasma can be found naturally in
O water and ice.
O stars and lightning.
O wood and metal.
O comets and asteroids.

Answers

Answer:

stars and lightning. this is the answer ok

The sun and other stars consist of plasma. Plasma is also found naturally in lightning and the northern and southern lights. Human-made plasma is found in fluorescent lights, plasma TV screens and plasma spheres.

Hope it helped

The subscript represents the number of ____________ in a chemical equation.

Answers

Answer: Atoms

Good luck!


If 280.4 g of KOH react with an excess of FeCl3, how many grams of Fe(OH)3 will be produced?
FeCl3 + 3 KOH — Fe(OH)3 + 3 KCI
How many grams will be produced?

Answers

Answer:

From 00:11

Balance the Molecular Equation

From 01:35

Ions for the Complete Ionic Equation

From 03:04

Net Ionic EquationExplanation:

Which of the following is a characteristic of both the Earth and the Moon?
Fossils and fossil
fuels under the
surface
Rocky surface
covered with
landforms
Flowing water in
Oceans and rivers
Atmosphere
containing oxygen

Answers

Answer:

rocky surface covered with landforms

Explanation:

How many grams equal 4.3 x 1024 atoms of oxygen (02)?

Answers

Answer: 248.66g

Explanation:

4.3e24 / 6.23e23 = 6.9 mols O2

6.9(18.02*2)=248.66

Liquids B and C are partially miscible at 25 oC. When one starts with 1 mol of C at 25 oC and isothermally adds B a little at a time, a two-phase system first appears when a bit more than 0.125 mol of B has been added; continuing to add B, one finds the two-phase system becomes a one-phase system when a total of 3 mol of B has been added. For a system consisting of 2.5 mol of B and 2 mol of C at 25 oC, find the number of moles of B and of C present in each phase.

Answers

Answer:

[tex]0.8\overline 3[/tex] moles of A and 2.5 moles of B in the one-phase system

[tex]1.1 \overline 6[/tex] moles of A and [tex]0.1458 \overline 3[/tex] moles of B in the two-phase system

[tex]0.3541 \overline 6[/tex] moles of B remains in the system

Explanation:

The given parameters are;

The extent of miscibility of liquid B and C = Partially miscible

The number of moles of liquid B added to 1 mole of liquid A that forms a two-phase system = 0.125 mol of liquid B

The number of moles of liquid B added to 1 mole of liquid A that forms a one -phase system = 3 moles of liquid B

Whereby the system consist of 2.5 mol of B and 2 mol of C at 25°C, we have;

The 1 mole of A mixes with 3 moles of B to form a single phase solution

Therefore;

2.5 moles of B will mix with (1/3)×2.5 moles of A = 5/6 moles of A

The remaining number of moles of A in the system = 2 - 5/6 =  7/6 moles of A

Similarly, we have;

At least, 0.125 mole of B combines with 1 mole of A to form a two-phase system

7/6 moles of A will combine with 7/6 × 0.125 = 7/48 moles of B to form a two-phase system

The number of moles of B left = 0.5 - 7/48 = 17/48 = 0.3541[tex]\overline 6[/tex] moles of A

Therefore, we have;

5/6 moles of A and 2.5 moles of B in the one-phase system

7/6 moles of A and 7/48 moles of B in the two-phase system

17/48 moles of B remaining in the system

What is the atomic mass of element XX if 3.6 moles of the substance has a mass of 192 grams?

Answers

Answer:

53.3g/mol

Explanation

Moles=mass/molar mass

Molar mass= mass/moles

Molar mass= 192/3.6

= 53.3

chemical properties of elements

Answers

Answer:

Atomic number. The atomic number indicates the number of protons within the core of an atom. ...

Atomic mass. The name indicates the mass of an atom, expressed in atomic mass units (amu). ...

Electronegativity according to Pauling. let me know if you need more ;)

A gas takes
up a volume of 17 L, has a
pressure of 2.3 atm, and a temperature
of 299 K. If I raise the temperature to
350 K and lower the pressure to 1140
mmHg, what is the new volume?

Answers

Answer:

V₂ = 25.065 L

Explanation:

Given data:

Initial volume = 15L

Initial pressure = 1500 mmHg (1500/760 = 1.97 atm)

Initial temperature = 299 K

Final temperature = 350 K

Final volume = ?

Final pressure = 1050 mmHg (1050/760 = 1.38 atm)

Formula:

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

V₂ = P₁V₁ T₂/ T₁ P₂  

V₂ = 1.97 atm × 15 L × 350 K / 299 K × 1.38 atm

V₂ = 10342.5 atm .L. K / 412.62 K.atm

V₂ = 25.065 L

Elizabeth REALLY didn’t study, and she also wrote the formula for dicarbon tetrafluoride as “C2F5”. Describe why her answer is incorrect.

Answers

Answer:

correct formula: C2F4

Explanation:

tetra means 4. There are 2 C and 4 F in dicarbon tetrafluoride.

I need help with like 35 questions anyone willing to help please let me know I have discord

UnknownGoddxss#2795

Please I only have like 5 hours to complete this

Answers

Answer and Explanation:

The molar mass of a substance is all of the weights from the elements combined.

So, we have the elements

CU, S, and [tex]O_{4}[/tex]

CU has a mass is 65

S mass is 32

O has a mass of 16, but there's 4 atoms of O, so we do 16 times 4, which is 64.

Now we add.

65 + 32 + 64 is 161.

So, the answer is 160, or answer choice A.

#teamtrees #PAW (Plant And Water)

Fill in the blanks. 3NH3

Answers

Answer:

3, 9, 3

Explanation:

The coefficient of 3 tells us that there are three molecules (the chemical unit of NH3). Each molecule of ammonia (NH3) is made up of 1 atom of nitrogen bonded to 3 atoms of hydrogen.

Since there are three molecules, we have three times the amount of atoms there are in one molecule.

3 x 1 = 3 nitrogen

3 x 3 = 9 hydrogen

1) Calculate the percent composition of each element in ammonia (NH).

Answers

Answer:

[tex]\% N=82.2\% \\\\\% H=17.8\%[/tex]

Explanation:

Hello there!

In this case, since ammonia is NH₃, we can see nitrogen weights 14.01 g/mol and hydrogen 3.03 g/mol as there is one only nitrogen atom and three hydrogen atoms; thus, the total mass is 17.04 g/mol. In such a way, the percent composition of each element turns out to be:

[tex]\% N=\frac{14.01}{17.04}*100\%=82.2\% \\\\\% H=\frac{3.03}{17.04}*100\%=17.8\%[/tex]

Best regards!

Astronauts go to live on the International Space Station for a period of ________ month(s). A one B three C six D nine

Answers

Answer:

The answer is C. six months

Explanation:

I hope this helps you bestie:))

Balance the chemical equation
C2H6+O2 = CO2 +H2O

Answers

c26886
........................

(b) The student collects the H2(g) produced by the reaction and measures its volume over water at 298 K after carefully
equalizing the water levels inside and outside the gas-collection tube, as shown in the diagram below. The volume is
measured to be 45.6 mL. The atmospheric pressure in the lab is measured as 765 torr, and the equilibrium vapor pressure
of water at 298 K is 24 torr,
45
46
Gas
Water
Calculate the following.
() The number of moles of h2 produced in the reaction

Answers

Answer:

The pressure of  H₂(g) = 741 torr

Explanation:

Given that:

The atmospheric pressure measured in the lab  = 765 torr

The vapor pressure of water = 24 torr

By applying Dalton's Law of Partial Pressure :

Making The Pressure inside the tube due to the H₂(g) the subject of the formula :

we have:

= (765 -24) torr

= 741 torr

According to ideal gas law and Dalton's law of partial pressure, 0.0136 moles of hydrogen are produced in the reaction.

What is ideal gas law?

The ideal gas law is a equation which is applicable in a hypothetical state of an ideal gas.It is a combination of Boyle's law, Charle's law,Avogadro's law and Gay-Lussac's law . It is given as, PV=nRT where R= gas constant whose value is 8.314.The law has several limitations.It is applicable to ideal gases which have hypothetical existence.Law was proposed by Benoit Paul Emile Clapeyron.

In the given problem, according to Dalton's law of partial pressure, pressure =765-24=741 torr

Substituting the given values in the ideal gas equation, n=PV/RT

n=741×45.6×10[tex]^-3[/tex]/8.314×298=0.0136 moles.

Thus 0.0136 moles of hydrogen are produced in the reaction.

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Cool air can hold less water vapor than warm air. Apply this fact to explain why clouds and precipitation form on the windward side of the mountain.​

Answers

The pressure is directly proportional to temperature (when the pressure decrease the temperature decrease too). Because the air parcel expands so the molecules will not interact with each other as much.

The energy of the particles does not change but the fact that the particles are more spaced out means the parcel is cooler.

so now, the warmer a parcel of air the more water vapor it can hold. so, if a parcel of air cools it's ability to hold water vapor drops and if it drops to a low enough point that is when the water vapor will condense and turn back into liquid water. This is how clouds and precipitation form on the the windward side of the mountain.

Clouds and precipitation form on the windward side of the mountain due to change in temperature and pressure.

What is the relation between pressure and temperature?

Temperature of any substance is directly proportional to the pressure of that substance.

If the temperature of the wind increases so that winds get warmer and at the same time pressure of gas also increases, due to which particles will go far from each other. After this warm air rises up and cools down will condenses to form clouds, after this precipitate will falls on the windward side of the mountain.

Hence due to temperature and pressure precipitate will form on the windward side of the mountain.​

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Can u please help me name which one it is

Answers

i think it’s D.
sorry if it’s wrong

Answer:

I think it is C

Explanation:

Question 2 (1 point)
(02.01 LC)
Which scientist proposed the model of an atom as a solid sphere? (1 point)

John Dalton

Niels Bohr

Ernest Rutherford

William Crookes

Answers

Answer:

John Dalton

Explanation:

Both John Dalton and Democritus thought that the atom was an indivisible sphere until J.J. Thompson came out with the plum pudding model. Hope I helped!

Who among, Amit and Saaketh, is correct? Explain.​

Answers

Answer:

What is their question answers exactly? I won't be able to explain who is correct.

Explanation:

Answer:

Not a lot to draw from this question if im going to be honest

Explanation

plz help :(
In a high-pressure system,
a.
air molecules are far apart and pressing on Earth’s surface.
b.
air molecules are far apart and rising away from Earth’s surface.
c.
air molecules are close together and pressing on Earth’s surface.
d.
air molecules are close together and rising away from Earth’s surface.

Answers

Answer:

c.

air molecules are close together and pressing on Earth’s surface.

Explanation:

i hope this helps!

Pls someone help rn!! Pls pls

Answers

Answer:

A. Mass = 61kg, weight on moon = 97.8N

Explanation:

To calculate the weight (force) from Mass of a body, the following formula is used:

W = mg

Where;

W = weight (Newtons)

m = mass (kg)

g = acceleration due to gravity (9.8m/s²)

According to this question, a scale shows that I weigh 600N on Earth, the mass on Earth can be calculated thus:

Using W = mg

m = W/g

m = 600/9.8

m = 61.2

m = 61kg

However, this mass on Earth will weigh differently on the Moon because gravity in the moon is 1.6 N/kg. The weight of the 61kg on the Moon is:

W(moon) = mass × gravity

W = 61 × 1.6

W = 97.6 N

Therefore, Mass = 61kg, weight on moon = 97.8N

help please guys i need it

Answers

Answer:

Amplitude

Explanation:

Hope I helped :)

Sulfur
how many electron shells in 4th shell?

Answers

Answer:

16 electrons in a sulfur atom. Looking at the picture, you can see there are two electrons in shell one, eight in shell two, and six in shell three.

Explanation:

What is the mass of 0.063x10^-4 moles of aluminum sulphate ?

Answers

Answer:

The mass of 0.063*10⁻⁴ moles of aluminum sulphate  is 2.15*10⁻³ grams.

Explanation:

Aluminum sulfate Al₂(SO₄)₃ has a molar mass of 342.15 g/mol.

Molar mass is the amount of mass that a substance contains in one mole of a substance, which can be an element or a compound.

So in this case you can apply the following rule of three: if 342.15 grams are present in 1 mole of aluminum sulfate, how much mass is present in 0.063*10⁻⁴ moles of the compound?

[tex]mass of aluminum sulphate=\frac{0.063*10^{-4}moles*342.15 grams }{1 mole}[/tex]

mass of aluminum sulphate= 2.15*10⁻³ grams

The mass of 0.063*10⁻⁴ moles of aluminum sulphate  is 2.15*10⁻³ grams.

Which postmortem parameter is fixed by 8 hours?

1)cloudiness of the eyes

2)rigor mortis

3)livor mortis

4)putrefaction

Answers

The postmortem cooling or algor mortis gets fixed by 8- 10 hours after death. The temperature of the body after death can be used to determine the time since death.

what is derived from sheep and goats that is used in break fluid

A bones and horns
B Fats and Fattys acids
C Manure
D Wool and Lanolin

Answers

the answer is A I took the test

Yes it is a just make sure tho

Which set of coefficients will correctly balance the following skeleton equation?
Fe + Cl2 →FeCl3

Answers

Answer:

2Fe + 3Cl2 → 2FeCl3

Explanation:

what is the mass of 1.25 L of ammonia gas at STP

Answers

Answer:

mass 1.25 Liters NH₃(gas) = 0.949 grams (3 sig-figs)

Explanation:

At STP (Standard Temperature-Pressure conditions => 0°C(=273K) and 1atm pressure,  1 mole any gas will occupy 22.4 Liters.

So, given 1.25 Liters ammonia gas at STP, convert to moles then multiply by formula wt. (17g/mole gives mass of NH₃.

moles NH₃(gas) = 1.25L NH₃(gas)/22.4L NH₄(gas)· NH₃(gas)mole⁻¹ = 0.0558 mole NH₃(gas).  

Converting to grams NH₃(gas) = 0.0558 mole NH₃(gas) x 17 g·mol⁻¹ = 0.949 grams NH₃(gas).

After you set up your apparatus for the second part of the experiment, your group begins to add the textbooks on top of the plunger. It appears that the plunger continues to drop with every added book and does not return to its original place after the books are removed. What possible sources of error could be given for this experimental outcome? Be specific and give at least two reasons.

Answers

The possible sources of error that could be given for this experimental outcome is the change in the density of the air.

What is an experiment?

An experiment simply means the procedure that is carried out in order to refute a particular hypothesis. It should be noted that experiments are important to provide insights into the cause and effect of a particular situation.

In this situation, with every added book, the volume of that air column will reduce. It is just important that the temperature should remain constant when the gas compression is taking place.

Another source of error is the assumption of moles that was assumed was constant during the experiment. In this scenario, it's possible that some gas could have escaped while the compression was taking place.

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