The earth has a mass of 5.972 x 1024 Kg. You decide to
put the satellite in an orbit 400 Km above the surface of the earth which has a radius of 6,371 Km, so the total
distance from the center of the earth to the satellite is 6,771,000 m. What will you need the velocity of the
satellite to be to stay in orbit? Show your work

Answers

Answer 1

Answer:

Explanation:

You want the required centripetal force to equal gravity force

if m is the mass of the satellite

ma = mv²/R

a = v²/R

F = ma = GMm/R²

a = GM/R²

v²/R = GM/R²

v² = GM/R

v = √(GM/R)

v = √(6.674 x 10⁻¹¹(5.972 x 10²⁴)/6.771 x 10⁶)

v = 7.672 x 10³ m/s


Related Questions

How long does it take the second hand of a clock to move through 3.57 rad?
Answer in units of s.

Answers

Answer:

Its angular velocity is  

π

30

radians per second (about 0.105 radians/s.

Explanation:

Explanation:

Think of it like this:

There are  

2

π

radians in one complete rotation, and that takes the second hand 60 seconds to complete.

So, the rate of rotation (the angular velocity) is

2

π

/60 = pi/30 radians per second# which is about 0.105 radians per second.

To solve the problem we will first calculate the time taken by the second arm to travel 1 rad.

Time taken by the second arm to travel 1 rad

We know that the arm of the second travels 2π radians in 60 seconds. therefore, the time is taken to travel 1 rad by the second arm,

[tex]1\rm\ rad = \dfrac{60}{2\pi}[/tex]

Time taken by the second arm to travel 3.57 rad

Time taken by the second arm to travel 3.57 rad

[tex]=3.57\times \dfrac{60}{2\pi}\\\\= 34.09\rm\ sec[/tex]

Hence, the time taken by the second arm to travel 3.57 rad is 34.09 sec.

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What net force acting on a 6 kg car produces an acceleration of 6 m/s2?

Answers

Explanation:

Mass (m) = 6 kgAcceleration (a) = 6 m/s²Force (F) = ?

We know that,

• F = ma

→ F = (6 × 6) N

F = 36 N

Therefore, the net force is 36N.

Cats are groomed often by their owners to remove hair. What logical inference can be made based on this statement?

Answers

Answer:

its keeps the fur straight.....im kinda confused with the question

Explanation:


Two Blocks are connected by a massless rope over a massless,
frictionless pulley, as shown in the figure. The mass of block 2
is m2 = 10.1 kg, and the coefficient of kinetic friction
between block 2 and the incline is Mk = 0.200. The angle 0 of
the incline is 27.5º. If block 2 is moving up the incline at
constant speed, what is the mass mi of block 1?

Answers

The mass of block 1 will be 1.99 kg.The tension force is applied along the whole length of the wire, pulling energy equally on both ends.

What is tension force?

The tension force is described as the force transferred through a rope, string, or wire as it is pulled by opposing forces.

Given that,

Mass of block 1=? kg

The coefficient of the kinetic friction,μ=0.200

Now consider the weight component in the uphill direction.The weight is found as;

[tex]\rm W=m_1gsin \theta[/tex]

The force is balanced in the vertical direction as;

[tex]\rm T=F_f-W[/tex]

When the force of friction is;

[tex]\rm F_F=\mu_k N[/tex]

[tex]\rm F_f=(m_1 gcos \theta)[/tex]

Substitute the value in the vertical balanced equation;

[tex]\rm T=m_1gsin(27.5)^0-\mu_kmgcos27.5^0[/tex]

[tex]\rm T-m_2g=0\\\\T=m_2g[/tex]

[tex]\rm (10.1) g=m_1g(0.699-0.2 \times(-0.714) ) \\\\ (10.1) g=m_1g (0.699+0.1428) \\\\\ (10.1) g= m_1 \times 0.8418 \\\\ m_1 =11.99 \ kg[/tex]

Hence the mass of block 1 will be 1.99 kg.

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find the total volume of the material used to making the cylinder​

Answers

Answer:

Hey mate

Explanation:

Whereas the basic formula for the area of a rectangular shape is length × width, the basic formula for volume is length × width × height.

pls mark me as brainliest!!

A 2.98-kg object oscillates on a spring with an amplitude of 8.05 cm. Its maximum acceleration is 3.55 m/s2. Calculate the total energy.

Answers

Answer:

a = ω^2 A      formula for max acceleration (ignoring sign)

V = ω A         formula for max velocity

V^2 = ω^2 A^2 = a A   from first equation

E = 1/2 M V^2 = 1/2 * 2.98 * 3.55 * .0805 = .426 J

(kg * m/sec^2 * m = kg m^2 / sec^2 = Joule

A stone of mass m = 1.05 kg is released from a height of h = 2.1 m into a pool of water. At a time of t = 1.83 s after hitting the surface of the water, the stone's velocity has decreased by 50%.
What is the magnitude of the average force the stone experiences, in newtons, during the time t?

Answers

Answer:

Explanation:

ignoring air resistance, the kinetic energy at water impact will equal the potential energy converted

½mv² = mgh

v = √(2gh)

v = √(2(9.81)2.1) = 6.4188... m/s

after impact, an impulse will result in a change of momentum.

There is a downward impulse due to gravity equal to the weight of the stone and an upward average force due to water resistance and buoyancy force.

FΔt = mΔv

(F - mg)Δt = m(vf - vi)

(F - mg) = m(vf - vi)/Δt

F = m(vf - vi)/Δt + mg

F = m((vf - vi)/Δt + g)

F = 1.05(((½(-6.4188) - -6.4188)/ 1.83) + 9.81)

F = 12.14198...

F = 12.1 N

The magnitude of the average force the stone experiences, will be 12.1 N.

What is force?

Force is defined as the push or pulls applied to the body. Sometimes it is used to change the shape, size, and direction of the body. Force is defined as the product of mass and acceleration. Its unit is Newton.

The given data in the problem is;

m is the stone mass = 1.05 kg

The height is h, = 2.1 m i

The time is, t = 1.83 s

Velocity decreased by 50%.

From the law of conservation of energy the kinetic energy is equal to the potential energy;

[tex]\rm \frac{1}{2} mv^2 = mgh \\\\ v = \sqrt{2gh}\\\\ v = \sqrt{2 \times 9.81 \times 2.1 } \\\\ v= 64188 \ m/sec.[/tex]

From Newton's second law of motion, the impulsive force is equal to the change in momentum;

[tex]\rm F \triangle T = m \traingle v \\\\ (F - mg) = \frac{v_f-v_i}{\triangle t } \\\\ F = \frac{v_f-v_i}{\triangle t } + mg \\\\ F =m\frac{v_f-v_i}{\triangle t + g} \\\\ F= 12.14 98 \\\\ F=12.1 N[/tex]

Hence the magnitude of the average force the stone experiences, will be 12.1 N.

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A 4.0-mF capacitor initially charged to 50 V and 6.0-mF capacitor charged to 30 V are connected to each other with the positive plate of each connected to the negative plate of the other. what is the final charge of the 6.0-mF capacitor?

a. 20 mC
b. 8.0 mC
c. 10 mC
d. 12 mC
e. 230 mC

Answers

[tex]\huge\color{pink}\boxed{\colorbox{black}{Answer ☘}}[/tex]

12 mC

Explanation:

We are given that...

[tex]C_{1} = 4mF \\ V_{1} = 50v \\ C_{2} = 6mF \\ V_{2} = 30v \\ \\ we've \: to \: find \: the \: final \: charge \: on \: the \: 6mF \\capacitor \:- \\ \\ we \: know \: that ,\: \\ Q = CV \\ \\ using \: the \: formula \: \\ Q_{1} = 4 \times 50 = 200mC \\ Q_{2} = 6 \times 30 = 180mC \\ \\ total \: charge , \: Q_{1} - Q_{2} = 200 - 180 = 20mC \\ \\ let \: V \: be \: the \: final \: potential \: \\ 4V + 6V = 20mC\\ 10V = 20mC \\ V = \frac{20}{10} = 2V \\ final \: charge \: Q = CV = 6 \times 2 = 12mC[/tex]

therefore,

σptíσn ( d ) íѕ cσrrєct!

hope helpful~

~Be Brainly!

A 2.00 kg rock is dropped from the top of a 30.0 m high building. Calculate the ball’s momentum at the time that it strikes the ground.

Answers

Explanation:

We use the Theorem of conservation of mechanical energy for finding the velocity when it strikes the ground:

Ei = Ef

Ki + Ui = Kf + Uf

Ui = Kf

m g h = 1/2 m v^2

v = sqrt(2gh)

So the momentum will be:

p = mv = m * sqrt(2gh)

A dwarf planet has a mass of 0.0045 times that of the Earth and a diameter on average 0.19 times that of the Earth. What is the escape velocity of the dwarf planet? (Type in the numerical answer and unit, e.g. 10m/s)

Answers

The escape velocity of the dwarf planet is 1,721.8 m/s.

The given parameters:

Mass of the dwarf planet, m = 0.0045 MMass of the Earth = 5.98 x 10²⁴ kgDiameter of the planet, d = 0.19 DDiameter of the Earth, D = 12,742 km

The mass of the of the dwarf planet is calculated as follows;

[tex]m = 0.0045 \times 5.98 \times 10^{24} \ kg\\\\m = 2.69\times 10^{22} \ kg[/tex]

The radius of the dwarf planet is calculated as follows;

[tex]r = \frac{0.19 D}{2} \\\\r = \frac{0.19 \times 12, 742, 000}{2} \\\\r = 1,210,490 \ m[/tex]

The escape velocity of the dwarf planet is calculated as follows;

[tex]v _e = \sqrt{\frac{2GM}{r} } \\\\v_e = \sqrt{\frac{2\times 6.67 \times 10^{-11} \times 2.69 \times 10^{22}}{1,210,490}}\\\\v_e = 1,721.8 \ m/s[/tex]

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A small ball with a mass of 0.6 kg and a velocity of 12 m/s hits another ball with the same mass. The firs forward and hits a third ball with a mass of 0.2 kg. If the system is closed, what is the velocity of the third ball?

4 m/s

36 m/s

30 m/s

1.44 m/s​

Answers

I think is 30m/s I am not sure

A baseball player throws a baseball at a speed of 40 meters per second at an angle of 30 degrees. What is the velocity of projectile at 2 second?​

Answers

Answer:

The horizontal component of the velocity is the cosine of 30 degrees multiplied by 40m/s. The cosine of 30 degrees is the 0.8660 . To get the speed, multiply by 40m/s. This equals 34.64, which is approximately 35m/s.

Hope it helpss :)

Answer:35m/s

Explanation:The horizontal component of the velocity is the cosine of 30 degrees multiplied by 40m/s. The cosine of 30 degrees is the 0.8660 (check this on your Regents Reference Tables or on your calculator). To get the speed, multiply by 40m/s. This equals 34.64, which is approximately 35m/s.

4. Protons and neutrons are held together to form this _________

Answers

Answer:

strong nuclear force.

Explanation:

hope this helps you!!

True or False. When Isaac’s father was a 100 God changed his name from Abram to Abraham.

Answers

I believe this is false

a hairdryer is used for 600 seconds to dry hair. it has a 750 watt rating. how much work did the hairdryer do

Answers

The amount of work done by the hairdryer is equal to 450 Kilojoules.

Given the following data:

Time = 600 secondsPower = 750 watt

To determine the amount of work done by the hairdryer:

Mathematically, the work done by an object with respect to power and time is given by the formula:

[tex]Work\;done = power \times time[/tex]

Substituting the given parameters into the formula, we have;

[tex]Work\;done = 750 \times 600[/tex]

Work done = 450,000 Joules

Note: 1000 Joules = 1 Kilojoules.

Work done = 450 Kilojoules.

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Do you think the rider in the above figure is really in danger? What If people below were removed?

Answers

The rider will be in danger when the people below  are removed, because they initially helped to maintain equilibrium.

A system subjected to different forces is said to be in equilibrium when all the forces applied to the system are equal.

For a system subject to two opposite forces, the following exists;

If the upward force and the downward forces are equal, the system will remain in equilibrium positionIf the upward or downward force is greater than the other, the system will move in the direction of the greater force.

Thus, we can conclude that the rider will be in danger when the people below  are removed, because they initially helped to maintain equilibrium. Once these people are removed, the rider tends to move at a greater speed and possibly fall from the initial position.

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How is probability used in blood typing

Answers

Blood Type O AB

Probability 0.45 0.04

Velocity is an extensive property of a system. TRUE OR FALSE​

Answers

[tex] \: \: \: [/tex]

[tex] \pink{false}[/tex]

because velocity is neither an intensive nor extensive property

hope it helps

Answer:

False

Explanation:

I hope this helped have a great day!!!

3. Particles carrying no charge ____________

Answers

Answer:

Neutrons

Explanation:

A device is rated at 1.3kW when connected to a 120 V source. The equivalent resistance of this device in ohm is:

a- 18.3
b- 12.0
c- 11.1
d- 14.4

Answers

Answer:

D.

correct me if im wrong

brainlest plsss<333

Blaine and her sister are identical twins riding roller coasters at Kinetic Kars. They each ride the
roller coaster on their own once. Next time, they ride the roller coaster together. On which ride
do you think they have the most kinetic energy? Explain your answer using information from class
activities.

Answers

Answer:The second ride

Two 5 kg potted cacti, one in a black pot and one in a blue pot, slide down a sagging shelf in the same direction with
the same speed.
Which two equations correctly model the momentum of the two-cactus system?

Answers

Answer:

Answers A and D are the correct solution.

Explanation:

Both pots have the same mass and the same velocity vector.

the only difference between A and D is the selection of the reference frame positive direction.

The equation (A) and equation (D) correctly model the momentum of the two-cactus system.

What is momentum?

The product of a particle's mass and velocity is called momentum. Being a vector quantity, momentum possesses both magnitude and direction.

According to Isaac Newton's second equation of motion, the force applied on a particle is equal to the time rate of change of momentum.

Given that: mass of each cactus: m = 5 kg.

And they slide down a sagging shelf in the same direction with the same speed.

In equation (A), both velocities of two cacti are in positive direction whereas, in equation (B), both velocities of two cacti is in negative direction.  Hence, equation (A) and equation (D) correctly model the momentum of the two-cactus system.

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A 2N and an 6N force pull on an object to the right and a 4N force pulls on the object to the left. If the object has a mass of 0.25 kg what is its acceleration?

Answers

Answer:

[tex]16m/s^{2}[/tex]

Explanation:

Please ask if you have more questions!

Which variable mentioned in Table 2-1 is kept constant? a. amount of time spent swimming b. type of swimming stroke c. number of calories used d. the person swimming

Answers

Answer:

a. amount of time spent swimming


The average value of the load between A and B is 6.0 N. The spring has an unstretched length
increases from 4.0 cm to 6.0 cm.

Answers

The change in the length of the spring as it stretches from 4.0 cm to 6.0 cm is 2.0 cm.

The change in length of the spring can be calculated by subtracting the initial unstretched length (4.0 cm) from the final stretched length (6.0 cm).

Change in length = Final length - Initial length

Change in length = 6.0 cm - 4.0 cm

Change in length = 2.0 cm

Therefore, the change in the length of the spring as it stretches from 4.0 cm to 6.0 cm is 2.0 cm. This means the spring elongates by 2.0 cm under the applied load between points A and B.

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The complete question is:

The average value of the load between A and B is 6.0 N. The spring has an unstretched length increases from 4.0 cm to 6.0 cm. What is the change in the length of the spring as it stretches from 4.0 cm to 6.0 cm?

A. 4.0 cmB. 1.0 cmC. 2.0 cmD. 6.0 cm

An object falls through the air, gaining speed as it falls. A student claims th
new energy, and so it breaks the law of conservation of energy. Which stat
why the student is incorrect? (1 point)
Energy can be created without breaking the law of conservation
Energy is converted from other forms, not created.
O Equal and opposite amounts of other energy are also created.
O Speed is not related to energy in any way.

Answers

Answer:

Energy is converted from other forms, not created

Explanation:

The ball has a decrease in potential energy which allows the kinetic energy, and therefore speed, to  increase

Need help asap

A scientist has invented a robot to work on the seabed. According to his calculation, the armour of the robot can withstand a maximum pressure of 10⁵ Pa exerted by the sea water. If the density of the sea water is 1025 kg/m3, what is the maximum depth of the seabed that this robot can work? [Given g = 9.81 m/s2 and rho water = 1000 kg/m3] ​

Answers

Answer:

Explanation:

Well which is it ? ρ = 1000 kg/m³ or ρ = 1025 kg/m³?

Obviously the sea is salt water so we can ignore  ρ = 1000 kg/m³

1025 kg/m³(d  m)(9.81 N/kg) = 1 x 10⁵ N/m² = Pa

d = 9.9450535...

d = 10 meters

That's if we only account for the pressure due to the water. On top of that pressure would be atmospheric pressure which is about 101000 Pa

so the robot would be a hair above its pressure limit before it even got in the water.

Which law of motion uses the formula mass = force x acceleration?

Answers

Answer:

Newton's second law

Explanation:

The fundamental of a closed organ pipe is 259.6 Hz. The second harmonic of an open organ pipe has the same frequency. What is the length of the closed pipe

Answers

Answer:

A closed organ pipe is λ/4  (node-antinode) long.

λ = speed / frequency = 331.5 / 259.6 = 1.28 m

λ/4 = .319 m     length of closed pipe

An open pipe has a fundamental wavelength of A-N-A or λ/2

The second harmonic would be A-N-A-N-A   or   λ = 1.28 m for the second harmonic   331.5 / 259.6 = 1.28  (the fundamental would be 331.5 / .628

A sailcraft is stalled on a windless day. A fan is attached to the craft and blows air into the sail which bounces backward upon impact. The boat can what?

Answers

Answer:

Impulse = change in momentum w bounce

There are 2 impulses acting. Recoil of the fan going the negative direction and the impulse of the air bouncing off the sail. The greater impulse will bounce so the direction will be to the right moving the craft.

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