The drama club has 72 members. 1/4 of the drama club members are in 5th grade and the rest of the members are in 6th grade. How many drama club members are in 6th grade?

answer choices
72

54

18

3

Answer:

66 inches

Step-by-step explanation:

77→ 14

X→12

In the proportion

a/b=c/d

the product of the means equals the product of the extremes. That is,

ad=bc.

So,

77 * 12 = X * 14

x = (77 X 12) / 14 = 66

In the diagram, AC is a diameter of circle O. If the slope of BC is -1/2, then the slope of AB is 2.

What is the diameter of the circle?

The diameter of a circle is the length of the line starting from one point on a circle to another point and passing through the center of the circle. It is equal to twice the radius of the circle.

We have that,

ABC is a right triangle

so,

AB is perpendicular to BC

we know that

If two lines are perpendicular, then the product of their slopes is equal to -1.

so,

m1 * m2 = -1

in this problem

mAB * mBC =-1

solve for mAB

mAB = -1 / mBC

mAB = -1 / -1/2

mAB = 2

therefore, In the diagram, AC is a diameter of circle O. If the slope of BC is -1/2, then the slope of AB is 2.

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Complete Question:

In the diagram, AC is the diameter of circle O. If the slope of BC is -1/2, what is the slope of AB?

An expression for the volume of a rectangular prism with length 7.5 ft, width w ft, and height 4.2 ft is 31.5w ft³.

Therefore the answer is 31.5 ft³.

The volume of a rectangular prism can be found by multiplying its length, width, and height. So, for a rectangular prism with length 7.5 ft, width w ft, and height 4.2 ft, the volume can be expressed as:

V = 7.5 * w * 4.2

V = 31.5 w ft³

So, the expression for the volume of this rectangular prism is 7.5 * w * 4.2, that is 31.5 w cubic feet.

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Answer:LxW

Step-by-step explanation:

Length x width

Yes, 6xy² is the greatest common factor of 12xy², 36x²y², and 42 xy⁴. The Greatest common factor is the highest common factor of all the given numbers.

We can find the greatest common factor by applying the prime factorization method. There are two steps involved to find the highest common factor.

Step 1

The factors of the numbers are

Factors of 12 are 1,2,3,4,6,12

Factors of 36 are 1,2,3,4,6,9,12,18,36

Factors of 42 are 1,2,3,6,7,14,21,42

The common factor for 12,36,42 are 1,2,3,6

Therefore, the greatest common factor for 12,36,42 is 6.

Step 2

We have to find the common factors for the variable parts x¹,y²,x²,y²,x¹,y⁴

The factor for x¹ is x itself.

The factors for y² is y⋅y

The factors for x² are x⋅x

The factors for y² are y⋅y

The factor for x¹ is x itself.

The factors for y⁴ are y⋅y⋅y⋅y

Hence, the common factors for the variables

x¹,y²,x²,y²,x¹,y⁴ are x⋅y⋅y

The GCF for the variable part is xy².

Now, multiply the GCF of the numerical part i.e.6 and the GCF of the variable part i.e. xy².

Therefore, it comes out to be 6xy².

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(5, 1, -3, 5.8, -11,)

Step-by-step explanation:

basically rage is y value. and domain is x value. so in this question the domain value are given so since domain is the value of x you have to substitute the number into the x. then you get the range. the answer are (5, 1, -3, 5.8, -11,)

The number of subs in the order is 8 or 9

Let's call the number of subs in the order "x".

Since the cost of 3 subs is $20, the cost per sub is $20 / 3 = $6.67.

And since the cost of 4 subs is $26, the cost per sub is $26 / 4 = $6.50.

So the cost per sub is between $6.50 and $6.67.

If the total cost is $56, then the cost per sub must be $56 / x.

So:

x = 56/6.5 or x = 56/6.67

Evalutate

x = 8.6 or x = 8.4

Approximate

x = 9 or 8

Hence, the subs is 8 to 9

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The decimal number that lies between 0.7 and 0.8, has three digits to the right of the decimal point, and whose sum of the digits is 24 is 7.98.

A decimal number is a number that has a fractional part represented by a decimal point. The digits to the right of the decimal point represent values that are smaller than 1.

In this problem, we are given that the decimal number has three digits to the right of the decimal point and that its sum of the digits is 24. Let's call the decimal number x. We can write an equation to represent the sum of the digits:

x = a + b/10 + c/100

Where a, b, and c are the digits of x.

We know that 0.7 < x < 0.8 and that the sum of the digits of x is 24, so we can write two more equations:

0.7 < a + b/10 + c/100 < 0.8

a + b + c = 24

By solving these three equations, we can find the decimal number x.

We know that a must be 7 because 0.7 < x < 0.8, so a = 7. We also know that b + c = 24 - 7 = 17. Now we need to find two digits b and c such that b + c = 17 and b/10 + c/100 is between 0 and 0.1.

The largest value of b that still satisfies this condition is 9. This means that

=> c = 17 - 9 = 8.

Therefore, the decimal number

=> x = 7 + 9/10 + 8/100 = 7.98.

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The surface area of the cube of side length 0.125 inches is given as follows:

S = 0.09375 in².

The surface area for a cube of side length a is given by the equation presented as follows:

S = 6a².

The side length in this problem has the value given as follows:

a = 1/8 = 0.125 in.

Hence the surface area of the cube is calculated as follows:

S = 6(0.125)²

S = 0.09375 in².

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Answer:  To find the ratio of the length of the shorter stick to the length of the longer stick, we need to divide the length of the shorter stick by the length of the longer stick:

11 inches ÷ 14 inches = 11/14

So, the ratio of the length of the shorter stick to the length of the longer stick is 11/14.

Step-by-step explanation:

Answer:

$ 31.45

Step-by-step explanation:

15% = 0.15 x 37 = 5.55$ off the original price so 31.45$ is the final price for the tee shirt. Give brainlist please

Sale price for the given shirt will be $32.

According to question given are-

Percentage of the reduction rate of the shirt is = 15%

Reduction Percentage refers to the percentage rate at which the Initial Per Certificate Entitlement will diminish daily, assuming that the daily rate will be calculated as the annual rate given in the Final Terms divided by 365 and applied as necessary.

Actual cost of the shirt is = $37.

decreased rate "Reduced rate" refers to a contribution rate that is lower than the standard rate required by State law, while "standard rate" refers to the rate used to compute variances from that rate.

So, accordingly Reduction rate = (Actual rate X Reduction Percentage)/100

Reduction = (37×15)/100 = Rs 5.55$ ≅ 5$

So the sale price = 37−5 = 32$

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1/4 of the flour was used for the muffins and 5/6 of the remaining flour was used for the cake.

Let's call the total amount of flour in the bag "x".

The amount used for the muffins is 1/4 of the total bag, or x/4.

The amount used for the cupcakes is twice as much as for the muffins, or 2 * x/4 = x/2.

The amount used for the muffins was 3 times as much as for the cupcakes, so 3 * x/2 = 3x/2 grams of flour were used for muffins.

The amount used for the cake was 256.5 grams more than the muffins, so x/4 + 256.5 = 3x/2.

Solving for x, we find that x = 2048 grams.

So, 1/4 of the flour was used for the muffins, or 2048 * 1/4 = 512 grams.

And 5/6 of the remaining flour was used for the cake, or (2048 - 512) * 5/6 = 1024 grams.

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Step-by-step explanation:

Domain: The domain of the function is all real numbers.

Range: The range of the function is all real numbers less than or equal to 8. To see this, note that the leading coefficient of the polynomial is negative (-x^3), so the function approaches negative infinity as x approaches positive or negative infinity. The largest y-value the function can attain is 8, which occurs at x = 2.

Relative maxima and minima: To find the relative maxima and minima, we find the critical points of the function, which are the values of x that satisfy f'(x) = 0 or f'(x) does not exist. The first derivative of the function f(x) is given by:

f'(x) = -3x^2 + 16x - 15

Solving f'(x) = 0, we get:

-3x^2 + 16x - 15 = 0

x = 1, 5

We also need to determine the concavity of the function near each critical point to determine whether each is a relative maximum or minimum. To do this, we find the second derivative of the function and evaluate its sign at each critical point. The second derivative of f(x) is given by:

f''(x) = -6x + 16

Since f''(x) is always negative, the function is concave down and therefore has a relative maximum at x = 1 and a relative minimum at x = 5.

End behavior: The leading term of the function is -x^3, which means the function approaches negative infinity as x approaches negative infinity and positive infinity as x approaches positive infinity. The end behavior of the function is therefore negative infinity as x approaches negative infinity and positive infinity as x approaches positive infinity.

Increasing and decreasing intervals: To find the increasing and decreasing intervals of the function, we find the critical points and the sign of f'(x) in the intervals between the critical points.

f'(x) = -3x^2 + 16x - 15

Since f'(x) is negative for x < 1 and positive for x > 1, the function is decreasing for x < 1 and increasing for x > 1. Similarly, since f'(x) is positive for x < 5 and negative for x > 5, the function is increasing for x < 5 and decreasing for x > 5. So, the increasing intervals are (negative infinity, 1) and (1, 5) and the decreasing intervals are (5, positive infinity).

The area of rectangle from the given vertices is 90 squared units

The area of a rectangle is the product of its length and width. If a rectangle has length "l" and width "w", its area can be calculated as:

A = l * w

where A is the area and l and w are the length and width of the rectangle, respectively.

The area of a rectangle can be calculated as the product of its length and width. Given the vertices, the length of the rectangle is 14 - 4 = 10 units, and its width is 2 - (-7) = 9 units. Hence, the area of the rectangle is 10 * 9 = 90 square units.

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The correct Option for this question is option C i.e. x= 4tan34°. The other options which are given in the question are incorrect.

The Right angled triangle along with the base angle of 34°. The base is equal to 4.

θ= 34°

To find the value of x which is equal to the perpendicular of the right-angled triangle

According to the trigonometric ratio

tanθ = Perpendicular ÷ base

According to the above formula

tan 34 = x ÷ 4

Now, we have to multiply each side by 4.

x= 4× tan34° which means x= 4tan34°

tan 34° = 0.6745

x= 4× 0.6745

X=2.70

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The number can be broken apart from the factor 42 using the place value as 40 + 2 here 4 is in the tens place and 4 is in the one's place.

A number is a mathematical entity that can be used to count, measure, or name things. For example, 1, 2, 56, etc. are the numbers.

It is given that:

The number is 42.

As we know,

The arithmetic operation can be defined as the operation in which we do the addition of numbers, subtraction, multiplication, and division. It has a basic four operators that is +, -, ×, and ÷.

So, We get;

⇒ 42 = 40 + 2

⇒ 42 = 4 × 10 + 2 × 1

Thus, The number can be broken apart from the factor 42 using the place value as 40 + 2 here 4 is in the tens place and 4 is in the one's place.

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Answer:

5.196103885259%

Step-by-step explanation:

Negative values detected. All input values threated as percentages (e.g. an input of 0.1 is threated as 0.1%, -10 is threated as -10%).

The linear program has an optimal solution of 28.5 at (A, B) = (2, 5) when the right-hand side for constraint 1 is 10. If the right-hand side is increased to 11, the optimal solution remains 28.5 at the same point.

The dual value for constraint 1 stays the same as long as the right-hand side stays within the range 8.4 to 11. The value of the optimal solution will increase by 0.5 for every unit increase in the right-hand side of constraint 2 as long as the right-hand side is within the range 23 to 27.

a) To find the new optimal solution, we need to graph the feasible region and find the new corner points. After the change, the first constraint becomes 1A + 1B ≤ 11. The other two constraints remain the same. The corner points can be found by substituting the bounds of each variable into the constraints and solving for the other variable. The feasible region can then be graphed, and the maximum of the objective function can be found at one of the corner points.

The new corner points are (0,0), (0,9), (6,0), and (2,5). The feasible region can be graphed as a triangle with these corner points. The maximum of the objective function 3A + 2B occurs at the point (2,5), where the value of the objective function is 28.5.

b) The value of the objective function at the optimal solution is 28.5, at (A, B) = (2, 5).

c) The right-hand side range information for constraint 1 tells us that if the right-hand side is increased from 10 to 11, the dual value will remain the same (since the allowable increase is 2.6 and the right-hand side only increases by 1). The range for constraint 1 is 8.4 to 11. As long as the right-hand side stays within this range, the dual value of 2.6 is applicable.

d) The dual value for constraint 2 is 0.5. Using this dual value and the right-hand side range information, we can conclude that the value of the optimal solution will increase by 0.5 for every unit increase in the right-hand side of constraint 2 as long as the right-hand side is within the range 23 to 27.

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Complete question:

Consider the following linear program.

Max 3A + 2B s.t.

1A + 1B ≤ 10

3A + 1B ≤ 27

1A + 2B ≤ 18

A, B ≥ 0

The value of the optimal solution is 28.5. Suppose that the right-hand side for constraint 1 is increased from 10 to 11.

(a) Use the graphical solution procedure to find the new optimal solution.

What is the value of the objective function at the optimal solution?

(blank) at (A, B) =

Use the solution to part (a) to determine the dual value for constraint 1.

(c) The computer solution for the linear program provides the following right-hand side range information

. Constraint RHS Value Allowable Increase Allowable Decrease

1 10.00000 2.60000 1.00000

2 27.00000 3.00000 13.00000

3 18.00000 Infinite 6.50000

What does the right-hand side range information for constraint 1 tell you about the dual value for constraint 1?

The range for constraint 1 is (blank) to (blank) . As long as the right-hand side stays (within/outside) this range, the dual value of (blank) is applicable.

(d) The dual value for constraint 2 is 0.5. Using this dual value and the right-hand side range information in part (c), what conclusion can be drawn about the effect of changes to the right-hand side of constraint 2?

The value of the optimal solution will increase by (blank) for every unit increase in the right-hand side of constraint 2 as long as the right-hand side is (within/outside) the range (blank) to (blank).

Answer:

600

Step-by-step explanation:

She had -350 then ended with 250

First you get -350 to 0... that's by adding 350.

Then getting from 0 to 250, you add 250

Now we add 350 and 250 to get a total of 600

The intensity of the transmitted light, [tex]I_{t}[/tex], is equal to half of the original intensity, [tex]I_{0}[/tex].

Given θ = 45° and cosθ = [tex]\sqrt\frac{I_{t} }{I_{0} }[/tex]

When polarized light with intensity [tex]I_{0}[/tex] strikes a polarized filter with its axis at an angle θ with the vertical, the intensity of the transmitted light, [tex]I_{t}[/tex], depends on the angle θ and the original intensity [tex]I_{0}[/tex]. The relationship between [tex]I_{t}[/tex] and [tex]I_{0}[/tex] is described by the equation cosθ = [tex]\sqrt\frac{I_{t} }{I_{0} }[/tex].

If θ = 45°, then the equation θ can be simplified to cos 45° =[tex]\sqrt\frac{I_{t} }{I_{0} }[/tex].

The cosine of 45° is equal to [tex]\frac{1}{\sqrt{2} }[/tex], so we have:

[tex]\frac{1}{\sqrt{2} }=\sqrt\frac{I_{t} }{I_{0} }[/tex]

On Squaring both sides, we have:

[tex]\frac{1}{{2} }=\frac{I_{t} }{I_{0} }[/tex]

Multiplying both sides by [tex]I_{0}[/tex], we have:

[tex]I_{t}=\frac{I_{0} }{2}[/tex]

Therefore, if θ = 45°, the intensity of the transmitted light, [tex]I_{t}[/tex], is equal to half of the original intensity, [tex]I_{0}[/tex].

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Answer:

I think BC

Step-by-step explanation:

Answer:

To solve the polynomial (g^2 + 9g + 18 = 0) using the X or Box method, you need to factor the polynomial into two binomials. To do this, you need to find two numbers that multiply to 18 and add up to 9. The two numbers are 6 and 3, so the polynomial can be factored as:

g^2 + 9g + 18 = (g + 6)(g + 3) = 0

To find the solutions, you set each factor equal to 0 and solve for g:

g + 6 = 0, so g = -6

g + 3 = 0, so g = -3

The solutions to the polynomial are g = -6 and g = -3.

Step-by-step explanation:

The fraction of the area of the triangle that would be shaded in stage 7 is equal to 2,187/16,384.

No, there isn't a stage when the fraction of area shaded would be equal to 0.

In Mathematics, a fraction simply refers to a numerical quantity which is not expressed as a whole number. This ultimately implies that, a fraction is simply a part of a whole number.

Next, we would determine the area of the triangle that would be shaded in stage 2 is as follows;

Fraction of the area = 3/4 × 3/4 = 9/16.

The area of the triangle that would be shaded in stage 3 is as follows;

Fraction of the area = 3/4 × 3/4 × 3/4 = 27/64.

The area of the triangle that would be shaded in stage 4 is as follows;

Fraction of the area = 3/4 × 3/4 × 3/4 × 3/4 = 81/256.

Therefore, the area of the triangle that would be shaded in stage 7 is as follows;

Fraction of the area = 3/4 × 3/4 × 3/4 × 3/4 × 3/4 × 3/4 × 3/4 = 2,187/16,384.

In this context, we can reasonably infer and logically deduce that there isn't a stage when the fraction of area shaded in this triangle would be equal to zero (0) because there is a linear relationship between the shaded and unshaded area.

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Answer:

Step 2

Step-by-step explanation:

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/\ Explantion hope it help...

Answer:

933500

Step-by-step explanation:

You move the decimal over 5 spaces to the right

Answer:

a) 83.75% or 84% rounded to the nearest percent.

b) 84%

Step-by-step explanation:

[tex]\frac{64+85+92+94}{4}[/tex] = 83.75  changed to a percent and rounded to the nearest percent would be 84%

.15(.88) + .10(.76) + .75(.84) = .838 changed to a percent and rounded to the nearest percent would be 84%

Answer:

see below

Step-by-step explanation:

We are here given that weight of an object having mass of 5kg is 450N .

As we know that,

Weight = mass * acceleration due to gravity (g)

So that ,

450N = g * 5kg

g = 450/5 m/s²

g = 90m/s²

Again in second case,

147N = g' * 50kg

g' = 147/50 m/s²

g' = 29.4 m/s²

since here g ≠ g'

Therefore,

mass and weight are not promotional in this case. This may be due to the fact that the acceleration due to gravitational force of each celestial object is different and weights may have been measured on different planets.

And the constant of proportionality is g ( acceleration due to the gravitational force) .

And we are done!