The diagram shows AFGH. Which term describes point J? G A. Centroid B. Circumcenter C. Orthocenter D. Incenter​

Answers

Answer 1

answer is a-circumcenter

Answer 2

The term that describes point J is Centroid.

What is a triangle?

A triangle is a 2-D figure with three sides and three angles.

The sum of the angles is 180 degrees.

We can have an obtuse triangle, an acute triangle, or a right triangle.

We have,

Centroid:

The centroid is the point where the three medians of a triangle intersect.

A median is a line segment that connects a vertex of a triangle to the midpoint of the opposite side.

The centroid is also the center of mass of a triangle, and it is located two-thirds of the way along each median from the vertex to the midpoint of the opposite side.

Now,

From the figure,

We see that,

J is the point where the three medians of a triangle intersect.

Thus,

The term that describes point J is Centroid.

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The Diagram Shows AFGH. Which Term Describes Point J? G A. Centroid B. Circumcenter C. Orthocenter D.

Related Questions

For this question I am sure the answer is 81% as you divide 45 and 55. However, it is stating my answer is incorrect even though I put 0.81% as well. Did I round wrong or is the answer wrong completely?

Answers

Answer:

it says round to the nearest 10th so it wouldn't be 81, it would be 81.8%

12.10.4 Test (CST): Income and Budgeting
Question 12 of 25
What is the y-intercept of the line passing through the point 5.-6) with a
slope of - 1/7?
A.47/7
B.37/7
C.-37/7
D.-47/7

Answers

Answer:

C.-37/7

Step-by-step explanation:

Given the following data;

Points (x, y) = (5, -6)

Slope, m = -1/7

Mathematically, the equation of a straight line is given by the formula;

y = mx + c

Where;

m is the slope.

x and y are the points

c is the intercept.

To find the y-intercept of the line, we would use the following formula;

y - y1 = m(x - x1)

y - (-6) = -⅐(x - 5)

y + 6 = -⅐x + 5/7

y = -⅐x + (5/7 - 6)

y = -⅐x - 37/7 = mx + c

Therefore, y-intercept (c) = -37/7

(Right angle) Trigonometry
please help!

Answers

Answer:

A = 41.4°

Step-by-step explanation:

Reference angle = A

Length of Adjacent side = 6

Length of Hypotenuse = 8

Apply the trigonometric function, CAH.

Cos A = Adj/Hyp

Substitute

[tex] Cos(A) = \frac{6}{8} [/tex]

[tex] A = Cos^{-1}(\frac{6}{8}) [/tex]

A = 41.4° (approximated to the nearest tenth)

Show that the set of nonsingluar 2 by 2 matrices is not a vector space. Show also that the set of singular 2 by 2 matrices is not a vector space.

Answers

Answer:

a) 2 nonsingular 2 by 2  matrices are not closed when added together hence it is not a vector space( i.e. their sum = singular and not nonsingular )

b) 2 singular 2 by 2 matrices is not  closed under addition, hence they are not a vector space. ( i.e. their sum = nonsingular )

Step-by-step explanation:

a) Prove that nonsingular 2 by 2 matrices is not a vector space

2 nonsingular matrices are not closed when added together hence it is not a vector space ( i.e. their sum = singular and not nonsingular )

vector A = [tex]\left[\begin{array}{ccc}1&0\\0&1\\\end{array}\right][/tex]    +  vector B =  [tex]\left[\begin{array}{ccc}0&1\\1&0\\\end{array}\right][/tex] = [tex]\left[\begin{array}{ccc}1&1\\1&1\\\end{array}\right][/tex] ( singular vector )

b) Prove that singular 2 by 2 matrices is not a vector space

2 singular 2 by 2 matrices is not  closed under addition, hence they are not a vector space. ( i.e. their sum = nonsingular )

Vector C = [tex]\left[\begin{array}{ccc}1&0\\0&0\\\end{array}\right][/tex]  + vector D = [tex]\left[\begin{array}{ccc}0&0\\0&1\\\end{array}\right][/tex] = [tex]\left[\begin{array}{ccc}1&0\\0&1\\\end{array}\right][/tex] ( nonsingular vector )

Last question! Please show work. Really need to get this done in 1 hour

Answers

Answer:

x = 1, y = 2 , z = 3

Step-by-step explanation:

[tex]6x\:+\:2y\:-4z\:=\:-2 \ \ \ \ \ \ \ \ \ -----( 1 ) \:\\\\-3x-4y\:+2z\:=\:-5 \ \ \ \ \ \ ------( 2 ) \:\\\\4x-\:6y\:+3z\:=\:1 \ \ \ \ \ \ \ \ \ \ \ \ ------- ( 3 ) \\\\( 2 ) \times 2=> -6x -8y + 4z = -10 \ \ \ \ \ \ \ -----( 4)[/tex]

Now add ( 1 ) and  (4)

[tex]6x +2y -4z = - 2\\\\-6x-8y - 4z = -10\\\\=>0x -6y + 0 = - 12\\\\-6y = -12[/tex]

y = 2

Now multiply ( 1 ) by  2 and (3) by 3

[tex](1) \times 2 => 12x + 4y -8z = -4\\\\(3) \times 3 => 12x -18y +9z = 3\\\\Subtract \ the \ equation : ( 1) - ( 3) => 0x +22y -17z = -7[/tex] ------ ( 5 )

Substitute y = 2 in ( 5 ) :

[tex]22(2) - 17z = - 7\\\\ 44 - 17z = - 7\\\\ -17z = - 7 - 44\\\\ -17z = -51\\\\[/tex]

z = 3

Substitute z = 3 and y = 2 in ( 1 ) :

[tex]6x + 2y - 4z = - 2\\\\6x + 2( 2) -4( 3) = -2\\\\6x + 4 - 12 = -2\\\\6x - 8 = - 2\\\\6x = - 2 + 8 \\\\6x = 6\\[/tex]

x = 1

find the simultaneous equation for:
4x+3y=7
2x+5y=7​

Answers

Answer:

x = 1 and y = 1

Step-by-step explanation:

You can eliminate x first to get the value of y which is 1 and then replace it in one of the equations.

In a class of 40 students, 2/5
of the total number of students like to study English and 3/5
of the

total students like to study Mathematics.
a) How many students like to study English?
b)How many students like to study Mathematics?

Answers

Hi I am really good at math so I think this answer will be 6/8

An expression is shown below:

3(m + 5 + 9m)

Part A: Write two expressions that are equivalent to the given expression. (3 points)

Part B: Show that one of your expressions in Part A is equivalent to the given expression using algebraic properties. Explain which properties you used. (4 points)

Part C: Show that your other expression from Part A is equivalent to the given expression by substituting a number for m. (3 points)

Answers

The answers are as follows part A = 30m+15  part B =3m+15+27m

and partC = 30m+15

What is an expression?

Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition,substraction, multiplication and division.

Part A:- Two expressions that are equivalent to the given expressions are:-

3m   +   15   +   27m

30m  +   15

Part B:  Show that one of your expressions in Part A is equivalent to the given expression using algebraic properties.

3  (  m   +   5    +   9m   )

Open the bracket by multiplying 3 by what is in the bracket

3m   +   15   +   27m

Part C: Show that your other expression from Part A is equivalent to the given expression by substituting a number for m.

3   (  m    +   5   +   9m  )

Open the bracket by multiplying 3 by what is in the bracket

3m    +    15    +     27m

Collect like terms together

3m    +     27m  +   15

=   30m   +    15

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The half life of Co-60 is 5.20 years. How many milligrams of a 1.00mg sample remains after 6.55 years

Answers

Answer:

For cobalt-60, which has a half-life of 5.27 years, 50% remains after 5.27 years (one half-life), 25% remains after 10.54 years (two half-lives), 12.5% remains after 15.81 years (three half-lives), and so on.

Step-by-step explanation:

You can figue out the rest.

In which number is the value of the 9 ten
times the value of the number nine in the number 920

Answers

Answer:

9 hundreds that is the answer

(a+b)²=hihihihihihihihiihihihi

Answers

Answer:

(a+b)²=a²+b²+2ab

Step-by-step explanation:

The square of sum of two terms is equal to the squared plus squared plus times product of and . In mathematics, the plus whole squared algebraic identity is called in three ways. The square of sum of two terms identity.

Find the net change in the value of the function between the given inputs.
h(t) = t2 + 9; from −4 to 7

Answers

The answer should be from 1 to 23

4. The electrical resistance of a wire varies inversely as the square of its radius. If the resistance is 0.80 ohm when the radius is 0.4cm. Find the resistance whom the radius is 0.7cm.​

Answers

9514 1404 393

Answer:

  0.261 ohm

Step-by-step explanation:

If the radius increases by a factor of 0.7/0.4= 7/4, the square of this factor is (7/4)^2 = 49/16. The inverse of this square is 16/49, which is the factor by which the resistance changed.

The resistance of the larger wire is ...

  (16/49)(0.80 ohm) ≈ 0.261 ohm

The actual length is 1.53 km
scale 10 cm to 1 km. find the length on drawing.​

Answers

Answer: 15.3 cm

Step-by-step explanation:

The actual length of the line in question is 1.53km.

The scale is 10 cm to 1 km.

You can therefore use direct proportion to solve this.

Assume the length on the drawing is x:

10cm  :   1km

x cm  :   1.53 km

Cross multiply:

x = 15.3 cm

How would I solve this?

Answers

Answer:

20°

Step-by-step explanation:

perpendicular from the center on a chord of a circle always bisects the chord.

AR=BR

∴m arcAC=m arc BC=20°

Hellllllllllp! Someone help

Answers

Answer:

4. (2, 3)

5. (0, 1)

7. (-1, 2)

Step-by-step explanation:

I hope this helps! Have a nice dayy! :)

You're very close. Choices D and E are two of the three answers. The third answer is choice G (-1,2)

In short, the 3 answers are Choices D, E and G

If you plug the coordinates of the points into the inequality, you should get a true statement.

For instance, let's try the coordinates of choice G

[tex]-2x + 3y\ge 3\\\\-2(-1) + 3(2)\ge 3\\\\2 + 6\ge 3\\\\8\ge 3\\\\[/tex]

Which is true since 8 is indeed greater than 3. That verifies point G is a solution point. A similar story happens with points D and E as well.

----------

If you tried something like choice A, then,

[tex]-2x + 3y\ge 3\\\\-2*(2) + 3(-3)\ge 3\\\\-4 - 9\ge 3\\\\-13\ge 3\\\\[/tex]

Which is false because -13 is not greater than 3, and -13 is not equal to 3 either. So choice A is a non-answer. You should find that choices B, C, and F are also non-answers.

----------

The graph is below. Notice how points D, E and G are either in the blue shaded region or on the boundary. The boundary line is solid (due to the "or equal to" as part of the inequality sign), so points on the solid boundary line are part of the solution set. The graph is a quick way to visually confirm the answers. I used GeoGebra to make the graph.

So that's why the 3 answers are D, E and G.

How much is six dimes, 8 nickels, and three one-dollar bills? *

Answers

[tex]\huge\textsf{Hey there!}[/tex]

[tex]\large\textsf{Guide}\downarrow[/tex]

[tex]\large\textsf{Penny: 1 cent} \\\large\textsf{Nickel: 5 cents}\\\large\textsf{Dime: 10 cents}\\\large\textsf{Quarter: 25 cents}\\\large\textsf{Half dollar: 50 cents}\\\large\textsf{1 bill = 1 dollar}[/tex]

[tex]\large\textsf{6 dimes:}\downarrow[/tex]

[tex]\large\textsf{= 10 + 10 + 10 + 10 + 10 + 10}[/tex]

[tex]\large\textsf{= 20 + 20 + 20}[/tex]

[tex]\large\textsf{= 40 + 20}[/tex]

[tex]\large\textsf{= \bf 60}[/tex]

[tex]\large\textsf{6 dimes = \bf 60 cents}[/tex]

[tex]\large\textsf{8 nickels}[/tex]

[tex]\large\textsf{= 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5}[/tex]

[tex]\large\textsf{= 10 + 10 + 10 + 10}[/tex]

[tex]\mathsf{= 20 + 20}[/tex]

[tex]\large\textsf{= \bf 40}[/tex]

[tex]\large\textsf{8 nickels = \bf 40 cents}[/tex]

[tex]\large\textsf{3 one dollar bills}[/tex]

[tex]\large\textsf{= 1 + 1 + 1}[/tex]

[tex]\large\textsf{= 2 + 1 }[/tex]

[tex]\large\textsf{= \bf 3}[/tex]

[tex]\large\textsf{3 one dollar bills = \bf 3 dollars}[/tex]

[tex]\large\textsf{NOW LETS SOLVE FOR YOUR EQUATION}[/tex]

[tex]\large\textsf{3.00 + 0.60 + 0.40}[/tex]

[tex]\large\textsf{= 3.60 + 0.40 }[/tex]

[tex]\large\textsf{= \bf \$4}[/tex]

[tex]\boxed{\boxed{\large\textsf{Therefore, your answer is: \huge \bf \$4}}}\huge\checkmark[/tex]

[tex]\large\textsf{Good luck on your assignment and enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Rolling a fair Eight-sided die produces a uniformly distributed set of numbers between 1 and 8 with a mean of 4.5 and a standard deviation of 2.291. Assume that n eight-sided dice are rolled many times and the mean of the n outcomes is computed each time.

Required:
a. Find the mean and the standard deviation of the resulting distribution of sample means for n=36.
b. The mean of the resulting distribution of the sample means is:________

Answers

Answer:

a. The mean is 4.5 and the standard deviation is 0.3818.

b. 4.5

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 4.5 and a standard deviation of 2.291.

This means that [tex]\mu = 4.5, \sigma = 2.291[/tex]

a. Find the mean and the standard deviation of the resulting distribution of sample means for n=36.

By the Central Limit Theorem, the mean is 4.5 and the standard deviation is [tex]s = \frac{2.291}{\sqrt{36}} = 0.3818[/tex]

The mean is 4.5 and the standard deviation is 0.3818.

b. The mean of the resulting distribution of the sample means is:________

By the Central Limit Theorem, 4.5.

Share 30 000 bags of 20kg rice in the ratio 2:3:4:6 among Villages A, B, C and D in that order. (2 marks) How many bags of 20 kg rice will Villages B and C get?​

Answers

Answer:

2+3+4+6 = 15 parts

Village B gets 3 of 15 parts

3/15 * 30000 = 6000 bags

Village C gets 4 of 15 parts

4/15 * 6000 = 8000 bags

Answer:

each "share" needs "15" (2+3+4+6) "portions/bags"

2000 distributions

A-4000 bags/80000 kg

B-6000 bags/120000 kg

C-8000 bags/1680000 kg

D-12000 bags/240000 kg

Step-by-step explanation:

Find an equation for the line parallel to 3x-5y=2 with​ y-intercept (0,1/5). Write the answer in ​ slope-intercept form.

Answers

y= 3x/5 - 2/5 .i think

The Molokai Nut Company (MNC) makes four different products from macadamia nuts grown in the Hawaiian Islands: chocolate-coated whole nuts (Whole), chocolate-coated nut clusters (Cluster), chocolate-coated nut crunch bars (Crunch), and plain roasted nuts (Roasted). The company is barely able to keep up with the increasing demand for these products. However, increasing raw material prices and foreign competition are forcing MNC to watch its margins to ensure it is operating in the most efficient manner possible. To meet marketing demands for the coming week, MNC needs to produce at least 1,000 pounds of the Whole product, between 400 and 500 pounds of the Cluster product, no more than 150 pounds of the Crunch product, and no more than 200 pounds of the Roasted product. Each pound of the Whole, Cluster, Crunch, and Roasted product contains, respectively, 60%, 40%, 20%, and 100% macadamia nuts with the remaining weight made up of chocolate coating. The company has 1,100 pounds of nuts and 800 pounds of chocolate available for use in the next week. The various products are made using four different machines that hull the nuts, roast the nuts, coat the nuts in chocolate (if needed), and package the products. The following table summarizes the time required by each product on each machine. Each machine has 60 hours of time available in the coming week.

Machine Minutes Required per Pound
Whole Cluster Crunch Roasted
Hulling 1 1 1 1
Roasting 2 1.5 1 1.75
Coating 1 0.7 0.2 0
Packaging 2.5 1.6 1.25 1

The selling price and variable cost associated with each pound of product is summarized in the following table:


Per Pound Revenue and Costs
Whole Cluster Crunch Roasted
Selling Price $5.00 $4.00 $3.20 $4.50
Variable Cost $3.15 $2.60 $2.16 $3.10


Required:
a. Formulate an LP model for this problem.
b. Create a spreadsheet model for this problem, and solve it using Solver.
c. What is the optimal solution?

Answers

Answer:

Profit = Selling price - Variable cost  

Formulas:  

F2 =SUMPRODUCT(B2:E2,$B$16:$E$16) copy to F2:F12, F14  

Optimal solution: The company should produce the following quantities (in pounds) of the four varieties of nuts.  

Whole = 1000  

Cluster = 500  

Crunch = 80  

Roasted = 200  

Total profit = $ 2913.20

Step-by-step explanation:

A college admissions officer takes a simple random sample of 90 entering freshman and computes their mean mathematics sat score to be 436. assume the population standard deviation is σ = 101. Based on a 99% confidence interval for the mean mathematics SAT score, is it likely that the mean mathematics SAT score for entering freshmen class is greater than 460?

Answers

Answer:

460 is part of the confidence interval, which means that we cannot say that there is significant evidence that the mean mathematics SAT score for entering freshmen class is greater than 460

Step-by-step explanation:

We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1 - 0.99}{2} = 0.005[/tex]

Now, we have to find z in the Z-table as such z has a p-value of [tex]1 - \alpha[/tex].

That is z with a pvalue of [tex]1 - 0.005 = 0.995[/tex], so Z = 2.575.

Now, find the margin of error M as such

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.

[tex]M = 2.575\frac{101}{\sqrt{90}} = 27.4[/tex]

The lower end of the interval is the sample mean subtracted by M. So it is 436 - 27.4 = 408.6.

The upper end of the interval is the sample mean added to M. So it is 436 + 27.4 = 463.4.

460 is part of the confidence interval, which means that we cannot say that there is significant evidence that the mean mathematics SAT score for entering freshmen class is greater than 460

solution - 12. The digit in the tens place of a two-digit number is three times that in the units place. If the digits are reversed, the new number will be 36 less than the original number. Find the original number. Check your solution.​

Answers

Answer:

62

Step-by-step explanation:

t=digit in the tens place

u=digit in the units place

t=3*u

original number=t*10+u

number with reversed digits=u*10+t

u*10+t=t*10+u-36

u*10+(3*u)=(3*u)*10+u-36

10u+3u-30u-u=-36

-18u=-36

u=2

t=3*u=6

Original number = 62

Check the solution:

6=3*2 ok

26=62-36 ok

Find the simple interest on a loan of $34,500 at 6.9% interest for 11 months

Give your answer to the nearest cent

Answers

Answer:

$2182.13

Step-by-step explanation:

Simple interest (I) is calculated as

I = [tex]\frac{PRT}{100}[/tex] ( P is principal, R is rate of interest, T is time in years )

Here P = $34,500 , R = 6.9 and T = [tex]\frac{11}{12}[/tex] , then

I = [tex]\frac{34500(6.9)(\frac{11}{12}) }{100}[/tex]

  = 345 × 6.9 × [tex]\frac{11}{12}[/tex]

  = $2182.13

There are 38 Legs in a group of goat and hens. How many goats and hens are there?
1) 13 Goats , 3 hens
2) 11 goats ,3hens
3) 7 goats,3 hens
4) 8 goats,3 hens

Answers

Answer:

4)8 goats, 3 hens.

Step-by-step explanation:

8*4=32

3*2=6

32+6=38

solve the equation
[tex] \frac{1}{6 - d} = \frac{1}{d - 5} [/tex]​

Answers

Answer:

5.5

Step-by-step explanation:

[tex] \frac{1}{6 - d} = \frac{1}{d - 5} \\ \\ \therefore \: 6 - d = d - 5 \\ \\ 6 + 5 = d + d \\ \\ 11 = 2d \\ \\ d = \frac{11}{2} \\ \\ d = 5.5[/tex]

A set of numbers is shown below:

{0, 0.6, 2, 4, 6}

Which of the following shows all the numbers from the set that make the inequality 2x + 3 ≥ 7 true?

{4, 6}
{0, 0.6, 2}
{0, 0.6}
{2, 4, 6}

Answers

Answer:

{2,4,6}

Step-by-step explanation:

Hope it helps you

A tank contains 1000L of pure water. Brine that contains 0.04kg of salt per liter enters the tank at a rate of 5L/min. Also, brine that contains 0.06kg of salt per liter enters the tank at a rate of 10L/min. The solution is kept thoroughly mixed and drains from the tank at a rate of 15L/min. Answer the following questions. 1. How much salt is in the tank after t minutes

Answers

Answer:

s(t) = 160/3  ( 1 - e^(-3t / 200) )

Step-by-step explanation:

volume of pure water in tank  = 1000 L

Brine contains 0.04kg of salt/L

Inflow rate of Brine containing 0.04kg of salt/L = 5L/min

Brine containing 0.06 kg of salt/L

Inflow rate of Brine containing 0.06 kg of salt/L = 10L/min

Solution is thoroughly mixed and drains from tank at 15L/min

a) Determine the amount of salt is in the tank after t minutes

rate of salt entering = 0.2 + 0.6 = 0.8 kg/min

rate of salt leaving = s/1000 * 15

amount of salt at time (t) = s(t)

initial condition s( 0 ) = 0

ds/dt = 0.8 - 15s/1000 = 0.8 - 3s/200

200 ds/dt = ( 160 - 3s )

-200/3  In ( 160 - 3s ) = t + c

Given that ;  t = 0 , s = 0    

c =  - 200/3  In ( 160 )

∴  -200/3  In ( 160 - 3s ) = t - 200/3  In ( 160 )

- 200/3  [ In ( 60 - 3s ) - In ( 160 ) ] = t

therefore:  

In ( 160 - 3s / 160 ) = -3t/200

= ( 160 - 3s / 160 ) = e ^ (-3t/200 )

Hence amount of salt in tank after t minutes

s(t) = 160/3  ( 1 - e^(-3t / 200) )

find the area of the shape

Answers

Answer:

The area is 91 cm²

Step-by-step explanation:

The shape is a kite.

area of a kite = ½(p*q)

Where, p and q are the diagonals of the kite.

p = 13 cm

q = 7 + 7 = 14 cm

The area of the kite = ½(13 * 14)

= ½(182)

Area = 91 cm²

please helpppppppppppp

Answers

Answer:

3

Step-by-step explanation:

4.5x 2 = 9

[tex]\sqrt{9}[/tex]= 3

Other Questions
which is an irrational number 2) Cartilage is not found in a. Nose C. Bones b. Adipose tissue d. Phosphorus and potassium 1.5 in.1.5 in.8 inches tallThe tube of toothpaste shown costs $3.45. Estimate the price per cubic inch of toothpaste. Multiple Choice Re-growing a forest will:cause desertification in surrounding areas due to the trees' high water demands,increase water run-off.lead to eutrophication of nearby lakes,reduce water run-off. Select the correct answer.Read the excerpt from Theodore Dreisers My Brother Paul. What narrative point of view does Dreiser use in this excerpt from the story?I had not seen my brother in three or four days, but after I had strolled a block or two up Broadway I encountered him. I have always thought that he had kept an eye on me and had really followed me; was looking, in short, to see what I would do As usual he was most smartly and comfortably dressed. a mobile phone company changes its rental charge from $80 to per to $7.50per month.work out the percentage increase Which sentence introduces the conflict that develops the theme great expectations by Charles dickens A. I followed the candle down as I followed the candle up and she stood it in the place where we found itB. The rush of the daylight quite confounded me and made me feel as if I had been in the candlelight of the strange room many hoursC. I took the opportunity of being alone in the courtyard to look at my coarse hands and my common bootsD. I wish joe had been rather more genteelly(respectably) brought up and then I should have been so too Which of the following lines is an example of a metaphor? A. And like a thunderbolt, he falls. B. It asked for my hand.C. The girl is a speeding bullet when she runs.D. Ringed with the azure world, he stands. How many natural numbers are there between 8 and 9 ? identity two excretory products produced by plants Which of these are causes of long-term climate change? Question is in picture What sugars are composed of short chains mark all statements that are true . help ! In a writing workshop, what should you do when you don't know how to correct errors or mistakes pointed out by a peer? find the greatest number in which 60,90 and 120 are exactly divisible How do I put this into a paragraph , you get 76 points so please answer Calculus chapter7 (Transcendental Functions) Can I sue a teacher if they claim my work for themselves? 4. What are some potential benefits of growing up in aSoviet/Communistic society? What are some potentialdownsides?